Maximally entangled mixed states with fixed marginals
Giuseppe Baio SUPA & University of Strathclyde, Glasgow, UK 51 Symposium of Mathematical Physics, Toruń, Poland
17th June 2019
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Maximally entangled mixed states with fixed marginals Giuseppe Baio - - PowerPoint PPT Presentation
Maximally entangled mixed states with fixed marginals Giuseppe Baio SUPA & University of Strathclyde, Glasgow, UK 51 Symposium of Mathematical Physics, Toru, Poland 17 th June 2019 17 th June 2019 Giuseppe Baio 51 SMP Toru 1 / 22 My
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AB) < 1: convex roof construction, e.g.:
pk,Ψk
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AB) < 1: convex roof construction, e.g.:
pk,Ψk
AB1 − 1)
AB = (I ⊗ τ) ρAB
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AB): 2
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AB): 2
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AB): 2
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AB): 2
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4 I2 ⊗ I2 + rP + 2 ,
2 = 1 2
i,j=1 |iijj|
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2
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2
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2
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2
2
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2
2
d−1
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d )
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d )
α KασK† α, extremal iff {K† αKβ}α,β=1,...,d2 is L.I.
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d )
α KασK† α, extremal iff {K† αKβ}α,β=1,...,d2 is L.I.
α = ρA
ρ(Id) = 1
αKα = ρB
αKβ ⊕ KβK† α}α,β=1,...,d2 L.I
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AB = (1 − p10 − p20) |Ψ(1) mcΨ(1) mc| + p10 |1010| + p20 |2020|
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AB = (1 − p10 − p20) |Ψ(1) mcΨ(1) mc| + p10 |1010| + p20 |2020|
AB = (1 − p10 − p12) |Ψ(2) mcΨ(2) mc| + p10 |1010| + p12 |1212|
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AB = (1 − p10 − p20) |Ψ(1) mcΨ(1) mc| + p10 |1010| + p20 |2020|
AB = (1 − p10 − p12) |Ψ(2) mcΨ(2) mc| + p10 |1010| + p12 |1212|
AB = (1 − p20 − p21) |Ψ(3) mcΨ(3) mc| + p20 |2020| + p21 |2121|
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AB = (1 − p10 − p20) |Ψ(1) mcΨ(1) mc| + p10 |1010| + p20 |2020|
AB = (1 − p10 − p12) |Ψ(2) mcΨ(2) mc| + p10 |1010| + p12 |1212|
AB = (1 − p20 − p21) |Ψ(3) mcΨ(3) mc| + p20 |2020| + p21 |2121|
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d
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d
n ⊗ B† n)
n ⊗ B† n)
n→∞ P + d ,
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2
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AB = (1 − p10 − p20) |Ψ(1) mcΨ(1) mc| + p10 |1010| + p20 |2020|
AB = (1 − p10 − p12) |Ψ(2) mcΨ(2) mc| + p10 |1010| + p12 |1212|
AB = (1 − p20 − p21) |Ψ(3) mcΨ(3) mc| + p20 |2020| + p21 |2121|
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AB = (1 − p10 − p20) |Ψ(1) mcΨ(1) mc| + p10 |1010| + p20 |2020|
AB = (1 − p10 − p12) |Ψ(2) mcΨ(2) mc| + p10 |1010| + p12 |1212|
AB = (1 − p20 − p21) |Ψ(3) mcΨ(3) mc| + p20 |2020| + p21 |2121|
3 + (1 − η)
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