Long-low iterations / matrix forcing Alan Dow 1 and Saharon Shelah 2 - - PowerPoint PPT Presentation

long low iterations matrix forcing
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Long-low iterations / matrix forcing Alan Dow 1 and Saharon Shelah 2 - - PowerPoint PPT Presentation

Long-low iterations / matrix forcing Alan Dow 1 and Saharon Shelah 2 1 University of North Carolina Charlotte 2 this paper initiated at Fields Oct 2012 see forthcoming F1222 Forcing at Fields Goal we want to force a model of t < h = < s


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Long-low iterations / matrix forcing

Alan Dow 1 and Saharon Shelah2

1University of North Carolina Charlotte 2this paper initiated at Fields Oct 2012

see forthcoming F1222

Forcing at Fields

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Goal

we want to force a model of t < h = κ < s = λ and see where we can put b

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Goal

we want to force a model of t < h = κ < s = λ and see where we can put b

Definition

We can define h as the minimum cardinal for which there is a sequence Iξ : ξ ∈ h of ⊂∗-dense ideals on P(ω) with empty intersection (or maybe intersection equal to [ω]<ℵ0)

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basic poset definitions

Hechler H is the standard order on (s, g) ∈ ω<ω↑ × ωω↑ adds dominating real

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basic poset definitions

Hechler H is the standard order on (s, g) ∈ ω<ω↑ × ωω↑ adds dominating real ccc Mathias/Prikry (w, U) ∈ Q(U) = [ω]<ω × U since U ∈ ω∗ it adds unsplit W ≺∗ U

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basic poset definitions

Hechler H is the standard order on (s, g) ∈ ω<ω↑ × ωω↑ adds dominating real ccc Mathias/Prikry (w, U) ∈ Q(U) = [ω]<ω × U since U ∈ ω∗ it adds unsplit W ≺∗ U Booth/Solovay for sfip Y ⊂ [ω]ω, also Q(Y) (w, Y) ∈ [ω]<ω × [Y]<ω adds a generic pseudointersection W to the family Y

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basic poset definitions

Hechler H is the standard order on (s, g) ∈ ω<ω↑ × ωω↑ adds dominating real ccc Mathias/Prikry (w, U) ∈ Q(U) = [ω]<ω × U since U ∈ ω∗ it adds unsplit W ≺∗ U Booth/Solovay for sfip Y ⊂ [ω]ω, also Q(Y) (w, Y) ∈ [ω]<ω × [Y]<ω adds a generic pseudointersection W to the family Y Shelah: the forcing QBould with countable support to first get b = ω1 < s = ω2

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basic poset definitions

Hechler H is the standard order on (s, g) ∈ ω<ω↑ × ωω↑ adds dominating real ccc Mathias/Prikry (w, U) ∈ Q(U) = [ω]<ω × U since U ∈ ω∗ it adds unsplit W ≺∗ U Booth/Solovay for sfip Y ⊂ [ω]ω, also Q(Y) (w, Y) ∈ [ω]<ω × [Y]<ω adds a generic pseudointersection W to the family Y Shelah: the forcing QBould with countable support to first get b = ω1 < s = ω2 family of special ccc subposets of QBould: we’ll call Q207 first used by Fischer-Steprans

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Brief history

Proposition

Baumgartner-Dordal [1985] obtain h ≤ s < b with Hechler but h will be ω1 because of Cohens

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Brief history

Proposition

Baumgartner-Dordal [1985] obtain h ≤ s < b with Hechler but h will be ω1 because of Cohens to raise h (or even keep h large) we have to be constantly adding pseudointersections (probably also raising t), but how to also keep it small?

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Brief history

Proposition

Baumgartner-Dordal [1985] obtain h ≤ s < b with Hechler but h will be ω1 because of Cohens to raise h (or even keep h large) we have to be constantly adding pseudointersections (probably also raising t), but how to also keep it small?

Proposition

Blass-Shelah [1987] introduce matrix-iterations TBI (named by Brendle 2011?) but actually short-tall; to obtain a model of ω1 < u < d using special ccc Mathias (generalized Kunen)

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Brief history

Proposition

Baumgartner-Dordal [1985] obtain h ≤ s < b with Hechler but h will be ω1 because of Cohens to raise h (or even keep h large) we have to be constantly adding pseudointersections (probably also raising t), but how to also keep it small?

Proposition

Blass-Shelah [1987] introduce matrix-iterations TBI (named by Brendle 2011?) but actually short-tall; to obtain a model of ω1 < u < d using special ccc Mathias (generalized Kunen)

Proposition

Shelah [1983] in Boulder proceedings introduced QBould to

  • btain ω1 = b < s = a.
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still brief history

Proposition

Fischer-Steprans [2008] could raise b by using Cohen forcing to define ccc subposets of QBould, and obtain b = κ < κ+ = s

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still brief history

Proposition

Fischer-Steprans [2008] could raise b by using Cohen forcing to define ccc subposets of QBould, and obtain b = κ < κ+ = s

Proposition

Brendle-Fischer [2011] using long-low matrix and Blass-Shelah ccc Mathias could get unrestricted ω1 < b = a = κ < s = λ

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still brief history

Proposition

Fischer-Steprans [2008] could raise b by using Cohen forcing to define ccc subposets of QBould, and obtain b = κ < κ+ = s

Proposition

Brendle-Fischer [2011] using long-low matrix and Blass-Shelah ccc Mathias could get unrestricted ω1 < b = a = κ < s = λ

Notes

It was shown in Brendle-Raghavan [2014] that QBould can be factored as countably closed * ccc Mathias (similar to Fischer-Steprans but still limits to κ+). Brendle delivered a beautiful workshop on matrix forcing at Czech WS 2010.

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a matrix iteration P(α, γ), Q(α, γ) : γ ≤ µ , α < λ

in case you don’t know what a matrix looks like

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properties required of P equal PP(α, i) : i ≤ κ, α ≤ γ

Let β < α ≤ γ and j < i < κ κ uncountable

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properties required of P equal PP(α, i) : i ≤ κ, α ≤ γ

Let β < α ≤ γ and j < i < κ κ uncountable

  • 1. as we go up, we have complete subposets

P(α, j) <c P(α, i) this is key but subtle

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properties required of P equal PP(α, i) : i ≤ κ, α ≤ γ

Let β < α ≤ γ and j < i < κ κ uncountable

  • 1. as we go up, we have complete subposets

P(α, j) <c P(α, i) this is key but subtle

  • 2. but not “needed” for limit:

j<i Pα,j is just a subset of P(α, i)

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properties required of P equal PP(α, i) : i ≤ κ, α ≤ γ

Let β < α ≤ γ and j < i < κ κ uncountable

  • 1. as we go up, we have complete subposets

P(α, j) <c P(α, i) this is key but subtle

  • 2. but not “needed” for limit:

j<i Pα,j is just a subset of P(α, i)

  • 3. as we go horizontally we iterate:

? P(β, j) ∗ Q(β, j) = P(β + 1, j) and also

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properties required of P equal PP(α, i) : i ≤ κ, α ≤ γ

Let β < α ≤ γ and j < i < κ κ uncountable

  • 1. as we go up, we have complete subposets

P(α, j) <c P(α, i) this is key but subtle

  • 2. but not “needed” for limit:

j<i Pα,j is just a subset of P(α, i)

  • 3. as we go horizontally we iterate:

? P(β, j) ∗ Q(β, j) = P(β + 1, j) and also

  • 4. limit α implies

P(α, i) = {P(β, i) : β < α} i.e. FS

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properties required of P equal PP(α, i) : i ≤ κ, α ≤ γ

Let β < α ≤ γ and j < i < κ κ uncountable

  • 1. as we go up, we have complete subposets

P(α, j) <c P(α, i) this is key but subtle

  • 2. but not “needed” for limit:

j<i Pα,j is just a subset of P(α, i)

  • 3. as we go horizontally we iterate:

? P(β, j) ∗ Q(β, j) = P(β + 1, j) and also

  • 4. limit α implies

P(α, i) = {P(β, i) : β < α} i.e. FS

  • 5. for i = κ, P(α, κ) = {P(α, i) : i < κ}
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properties required of P equal PP(α, i) : i ≤ κ, α ≤ γ

Let β < α ≤ γ and j < i < κ κ uncountable

  • 1. as we go up, we have complete subposets

P(α, j) <c P(α, i) this is key but subtle

  • 2. but not “needed” for limit:

j<i Pα,j is just a subset of P(α, i)

  • 3. as we go horizontally we iterate:

? P(β, j) ∗ Q(β, j) = P(β + 1, j) and also

  • 4. limit α implies

P(α, i) = {P(β, i) : β < α} i.e. FS

  • 5. for i = κ, P(α, κ) = {P(α, i) : i < κ}

All posets will be ccc, and so if ˙ Y is a P(λ, κ)-name of a subset

  • f ω, there are (α, i) ∈ λ × κ so that

˙ Y is a P(α, i)-name.

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properties required of P equal PP(α, i) : i ≤ κ, α ≤ γ

Let β < α ≤ γ and j < i < κ κ uncountable

  • 1. as we go up, we have complete subposets

P(α, j) <c P(α, i) this is key but subtle

  • 2. but not “needed” for limit:

j<i Pα,j is just a subset of P(α, i)

  • 3. as we go horizontally we iterate:

? P(β, j) ∗ Q(β, j) = P(β + 1, j) and also

  • 4. limit α implies

P(α, i) = {P(β, i) : β < α} i.e. FS

  • 5. for i = κ, P(α, κ) = {P(α, i) : i < κ}

All posets will be ccc, and so if ˙ Y is a P(λ, κ)-name of a subset

  • f ω, there are (α, i) ∈ λ × κ so that

˙ Y is a P(α, i)-name. This means ˙ Y won’t know about even P(0, i + 1) and so gives us a chance to keep a cardinal invariant small

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illustrative examples

Let us look at two examples where P(0, i) is FSj≤iHj adding H0

i : i < κ

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illustrative examples

Let us look at two examples where P(0, i) is FSj≤iHj adding H0

i : i < κ

iterate Hechler up every column

If, for all α > 0 and i, ˙ Q(α, i) is

  • j<i ˙

Q(α, j)

  • ∗ H

up each column, iteratively add Hechler reals then we get a model of b = κ < d = λ (and h = ω1)

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illustrative examples

Let us look at two examples where P(0, i) is FSj≤iHj adding H0

i : i < κ

iterate Hechler up every column

If, for all α > 0 and i, ˙ Q(α, i) is

  • j<i ˙

Q(α, j)

  • ∗ H

up each column, iteratively add Hechler reals then we get a model of b = κ < d = λ (and h = ω1)

just add one Hechler! in each column

If, for all α > 0 and i < κ ˙ Q(α, i) is H (but in V P(α,i)) i.e. ˙ Q(α, i) = [ω]<ω↑ ×

  • ωω↑ ∩ V[Gα,i]
  • then we get a model of b = λ

( P(α + 1, κ) = P(α, κ) ∗ H)

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illustrative examples

Let us look at two examples where P(0, i) is FSj≤iHj adding H0

i : i < κ

iterate Hechler up every column

If, for all α > 0 and i, ˙ Q(α, i) is

  • j<i ˙

Q(α, j)

  • ∗ H

up each column, iteratively add Hechler reals then we get a model of b = κ < d = λ (and h = ω1)

just add one Hechler! in each column

If, for all α > 0 and i < κ ˙ Q(α, i) is H (but in V P(α,i)) i.e. ˙ Q(α, i) = [ω]<ω↑ ×

  • ωω↑ ∩ V[Gα,i]
  • then we get a model of b = λ

( P(α + 1, κ) = P(α, κ) ∗ H)

remark

In first case, it is obvious that P(α, i) <c P(α, i + 1), but not so much in the second case (more on this later)

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remark

In fact, let us notice that HVα,i <c HVα,i+1, but it IS the construction of the chain {Qα,i : i < κ} that controls things. Here’s why

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remark

In fact, let us notice that HVα,i <c HVα,i+1, but it IS the construction of the chain {Qα,i : i < κ} that controls things. Here’s why

a γ-matrix Pγ extending a δ-matrix Pδ

means the obvious things (the heights must be the same)

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remark

In fact, let us notice that HVα,i <c HVα,i+1, but it IS the construction of the chain {Qα,i : i < κ} that controls things. Here’s why

a γ-matrix Pγ extending a δ-matrix Pδ

means the obvious things (the heights must be the same)

Lemma (and limits come for free)

If γ is a limit and we have an increasing sequence {Pδ : δ < γ}

  • f matrices, then the union Pγ extends canonically to a γ-matrix
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remark

In fact, let us notice that HVα,i <c HVα,i+1, but it IS the construction of the chain {Qα,i : i < κ} that controls things. Here’s why

a γ-matrix Pγ extending a δ-matrix Pδ

means the obvious things (the heights must be the same)

Lemma (and limits come for free)

If γ is a limit and we have an increasing sequence {Pδ : δ < γ}

  • f matrices, then the union Pγ extends canonically to a γ-matrix

The union,

δ<γ Pδ will be a list {P(α, i) : i ≤ κ, α < γ}. For

each i < κ, P(γ, i) must equal

δ<γ P(δ, i).

And, as needed, we have P(γ, j) <c Pγ,i ( j < i ≤ κ)

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Lemma (Brendle-Fischer)

Suppose P <c P′, and Q is a P-name and Q′ is a P′-name. For P ∗ Q <c P′ ∗ Q′, we need every P-name of a maximal antichain of Q is also forced by P′ to be a maximal antichain of Q′.

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Lemma (Brendle-Fischer)

Suppose P <c P′, and Q is a P-name and Q′ is a P′-name. For P ∗ Q <c P′ ∗ Q′, we need every P-name of a maximal antichain of Q is also forced by P′ to be a maximal antichain of Q′.

Corollary

If P <c P′, then P ∗ Q <c P′ ∗ ˇ Q.

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Lemma (Brendle-Fischer)

Suppose P <c P′, and Q is a P-name and Q′ is a P′-name. For P ∗ Q <c P′ ∗ Q′, we need every P-name of a maximal antichain of Q is also forced by P′ to be a maximal antichain of Q′.

Corollary

If P <c P′, then P ∗ Q <c P′ ∗ ˇ Q.

Corollary (for successor α < λ)

If Pα is given, and if Yα is a Pα,iα-name of a sfip family, we can let Qα,j be trivial for j < iα and let Qα,i = Q(Yα) for j ≥ iα with generic set ˙ Aα.

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Lemma (Brendle-Fischer)

Suppose P <c P′, and Q is a P-name and Q′ is a P′-name. For P ∗ Q <c P′ ∗ Q′, we need every P-name of a maximal antichain of Q is also forced by P′ to be a maximal antichain of Q′.

Corollary

If P <c P′, then P ∗ Q <c P′ ∗ ˇ Q.

Corollary (for successor α < λ)

If Pα is given, and if Yα is a Pα,iα-name of a sfip family, we can let Qα,j be trivial for j < iα and let Qα,i = Q(Yα) for j ≥ iα with generic set ˙ Aα. In this way we extend to Pα+1. With simple bookkeeping we will obtain t ≥ κ and we will let Ii = ideal{ ˙ Aα : iα = i} towards h ≤ κ.

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Lemma (Brendle-Fischer)

Suppose P <c P′, and Q is a P-name and Q′ is a P′-name. For P ∗ Q <c P′ ∗ Q′, we need every P-name of a maximal antichain of Q is also forced by P′ to be a maximal antichain of Q′.

Corollary

If P <c P′, then P ∗ Q <c P′ ∗ ˇ Q.

Corollary (for successor α < λ)

If Pα is given, and if Yα is a Pα,iα-name of a sfip family, we can let Qα,j be trivial for j < iα and let Qα,i = Q(Yα) for j ≥ iα with generic set ˙ Aα. In this way we extend to Pα+1. With simple bookkeeping we will obtain t ≥ κ and we will let Ii = ideal{ ˙ Aα : iα = i} towards h ≤ κ. With more tedious bookkeeping, Ij ⊃ Ii (for j < i)

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Proposition (Ihoda-Shelah, 1988)

If Q is (forced to be) Souslin and P <c P′, then P ∗ Q <c P′ ∗ Q

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Proposition (Ihoda-Shelah, 1988)

If Q is (forced to be) Souslin and P <c P′, then P ∗ Q <c P′ ∗ Q for example if Q = H (can also use rank)

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Proposition (Ihoda-Shelah, 1988)

If Q is (forced to be) Souslin and P <c P′, then P ∗ Q <c P′ ∗ Q for example if Q = H (can also use rank)

Corollary (for cf(α) = κ)

If Pα is given, then we can let Pα+1 be constructed with ˙ Qα,i = H for all i ≤ κ.

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Proposition (Ihoda-Shelah, 1988)

If Q is (forced to be) Souslin and P <c P′, then P ∗ Q <c P′ ∗ Q for example if Q = H (can also use rank)

Corollary (for cf(α) = κ)

If Pα is given, then we can let Pα+1 be constructed with ˙ Qα,i = H for all i ≤ κ.

Definition (fundamental Ind. Hyp.)

By induction on γ < λ, when building Pγ and setting Iγ

i = ideal ˙

Aα : α < γ, and iα = i i + 1-names we need that no Pγ,i-name is in Iγ

i

(actually just successor i) it is routine at limit γ and for successor γ using Q(Yγ)

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Proposition (Ihoda-Shelah, 1988)

If Q is (forced to be) Souslin and P <c P′, then P ∗ Q <c P′ ∗ Q for example if Q = H (can also use rank)

Corollary (for cf(α) = κ)

If Pα is given, then we can let Pα+1 be constructed with ˙ Qα,i = H for all i ≤ κ.

Definition (fundamental Ind. Hyp.)

By induction on γ < λ, when building Pγ and setting Iγ

i = ideal ˙

Aα : α < γ, and iα = i i + 1-names we need that no Pγ,i-name is in Iγ

i

(actually just successor i) it is routine at limit γ and for successor γ using Q(Yγ)

Corollary (Baumgartner-Dordal)

When cf(α) = κ and we let ˙ Qα,i = H, we preserve Ind Hyp.

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Now we discuss QBould and Q207

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Now we discuss QBould and Q207

unsplit reals

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Now we discuss QBould and Q207

unsplit reals

For other limits µ, we will, by induction on i < κ, define ˙ Qµ,i = Ci+1×2ω ∗ ˙ Qµ,i

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Now we discuss QBould and Q207

unsplit reals

For other limits µ, we will, by induction on i < κ, define ˙ Qµ,i = Ci+1×2ω ∗ ˙ Qµ,i where CI is Fn(I, 2) and it is forced that the generic for ˙ Qµ,i is unsplit over V[Pµ,i] (making Ind Hyp much harder)

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Now we discuss QBould and Q207

unsplit reals

For other limits µ, we will, by induction on i < κ, define ˙ Qµ,i = Ci+1×2ω ∗ ˙ Qµ,i where CI is Fn(I, 2) and it is forced that the generic for ˙ Qµ,i is unsplit over V[Pµ,i] (making Ind Hyp much harder) Also, we have to work to ensure that Pµ+1 "holds" and this is what ˙ Qµ,i ∈ Q207 is for.

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Now we discuss QBould and Q207

unsplit reals

For other limits µ, we will, by induction on i < κ, define ˙ Qµ,i = Ci+1×2ω ∗ ˙ Qµ,i where CI is Fn(I, 2) and it is forced that the generic for ˙ Qµ,i is unsplit over V[Pµ,i] (making Ind Hyp much harder) Also, we have to work to ensure that Pµ+1 "holds" and this is what ˙ Qµ,i ∈ Q207 is for. i.e. to take care of Pµ,j ∗ Cj+1×2ω ∗ ˙ Qµ,j <c Pµ,i ∗ Ci+1×2ω ∗ ˙ Qµ,i

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Now we discuss QBould and Q207

unsplit reals

For other limits µ, we will, by induction on i < κ, define ˙ Qµ,i = Ci+1×2ω ∗ ˙ Qµ,i where CI is Fn(I, 2) and it is forced that the generic for ˙ Qµ,i is unsplit over V[Pµ,i] (making Ind Hyp much harder) Also, we have to work to ensure that Pµ+1 "holds" and this is what ˙ Qµ,i ∈ Q207 is for. i.e. to take care of Pµ,j ∗ Cj+1×2ω ∗ ˙ Qµ,j <c Pµ,i ∗ Ci+1×2ω ∗ ˙ Qµ,i

finite working part

Elements q = (wq, T q) of QBould, like all our posets, have a finite working part w and an infinite side condition T elements r of Ci+1×2ω are also working part

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stronger Induction Hypothesis seems necessary

Before, or even if, discussing what such a (w, T) ∈ QBould looks like, I seemed to need a stronger hypothesis on Pµ in order to be able to construct ˙ Qµ,i ∈ Q207 to do the job.

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stronger Induction Hypothesis seems necessary

Before, or even if, discussing what such a (w, T) ∈ QBould looks like, I seemed to need a stronger hypothesis on Pµ in order to be able to construct ˙ Qµ,i ∈ Q207 to do the job.

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SLIDE 52

stronger Induction Hypothesis seems necessary

Before, or even if, discussing what such a (w, T) ∈ QBould looks like, I seemed to need a stronger hypothesis on Pµ in order to be able to construct ˙ Qµ,i ∈ Q207 to do the job.

Definition

Γµ

i is the set of α < µ with iα = i; and p0, . . . , pn is a Γµ i -fan if

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SLIDE 53

stronger Induction Hypothesis seems necessary

Before, or even if, discussing what such a (w, T) ∈ QBould looks like, I seemed to need a stronger hypothesis on Pµ in order to be able to construct ˙ Qµ,i ∈ Q207 to do the job.

Definition

Γµ

i is the set of α < µ with iα = i; and p0, . . . , pn is a Γµ i -fan if

  • 1. each pk ≤ p0 is in Pµ,i+1,
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SLIDE 54

stronger Induction Hypothesis seems necessary

Before, or even if, discussing what such a (w, T) ∈ QBould looks like, I seemed to need a stronger hypothesis on Pµ in order to be able to construct ˙ Qµ,i ∈ Q207 to do the job.

Definition

Γµ

i is the set of α < µ with iα = i; and p0, . . . , pn is a Γµ i -fan if

  • 1. each pk ≤ p0 is in Pµ,i+1,
  • 2. for each β /

∈ Γµ

i , the working parts of pk(β) (1 ≤ k ≤ n) are

all the same

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SLIDE 55

stronger Induction Hypothesis seems necessary

Before, or even if, discussing what such a (w, T) ∈ QBould looks like, I seemed to need a stronger hypothesis on Pµ in order to be able to construct ˙ Qµ,i ∈ Q207 to do the job.

Definition

Γµ

i is the set of α < µ with iα = i; and p0, . . . , pn is a Γµ i -fan if

  • 1. each pk ≤ p0 is in Pµ,i+1,
  • 2. for each β /

∈ Γµ

i , the working parts of pk(β) (1 ≤ k ≤ n) are

all the same

  • 3. for ξ, α both in Γµ

i and 1 ≤ j < k ≤ n, the working part of

pj(ξ) intersect the working part of pk(α) is contained in the working part of p0(ξ) intersect the working part of p0(α).

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new Ind Hyp (µ, i)

Definition

Γµ

i is the set of α < µ with iα = i; and p0, . . . , pn is a Γµ i -fan if

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new Ind Hyp (µ, i)

Definition

Γµ

i is the set of α < µ with iα = i; and p0, . . . , pn is a Γµ i -fan if

  • 1. each pk ≤ p0 is in Pµ,i+1,
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new Ind Hyp (µ, i)

Definition

Γµ

i is the set of α < µ with iα = i; and p0, . . . , pn is a Γµ i -fan if

  • 1. each pk ≤ p0 is in Pµ,i+1,
  • 2. for each β /

∈ Γµ

i , the working parts of pk(β) (1 ≤ k ≤ n) are

all the same

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new Ind Hyp (µ, i)

Definition

Γµ

i is the set of α < µ with iα = i; and p0, . . . , pn is a Γµ i -fan if

  • 1. each pk ≤ p0 is in Pµ,i+1,
  • 2. for each β /

∈ Γµ

i , the working parts of pk(β) (1 ≤ k ≤ n) are

all the same

  • 3. for ξ, α both in Γµ

i and 1 ≤ j ≤ k ≤ n, the working part of

pj(ξ) intersect the working part of pk(α) is contained in the working part of p0(ξ) intersect the working part of p0(α).

slide-60
SLIDE 60

new Ind Hyp (µ, i)

Definition

Γµ

i is the set of α < µ with iα = i; and p0, . . . , pn is a Γµ i -fan if

  • 1. each pk ≤ p0 is in Pµ,i+1,
  • 2. for each β /

∈ Γµ

i , the working parts of pk(β) (1 ≤ k ≤ n) are

all the same

  • 3. for ξ, α both in Γµ

i and 1 ≤ j ≤ k ≤ n, the working part of

pj(ξ) intersect the working part of pk(α) is contained in the working part of p0(ξ) intersect the working part of p0(α).

new Ind. Hyp. : Γµ

i -pure

For any dense set D ⊂ Pµ,i+1 and any Γµ

i -fan p0, p1, . . . , pn,

there is an extension Γµ

i -fan p0, ¯

p1, . . . , ¯ pn such that {¯ p1, . . . , ¯ pn} ⊂ D.

slide-61
SLIDE 61

this is a good Ind. Hyp.

Lemma (assume Γµ

i -pure)

By induction on µ, if ˙ Y is a Pµ,i-name and p0, p1, · · · , pn is a Γµ

i -fan, then, for 1 ≤ j, k ≤ n, integer y,

pj y ∈ ˙ Y iff pk y ∈ ˙ Y and pj ⊥ p iff pk ⊥ p for each p ∈ Pµ,i

slide-62
SLIDE 62

this is a good Ind. Hyp.

Lemma (assume Γµ

i -pure)

By induction on µ, if ˙ Y is a Pµ,i-name and p0, p1, · · · , pn is a Γµ

i -fan, then, for 1 ≤ j, k ≤ n, integer y,

pj y ∈ ˙ Y iff pk y ∈ ˙ Y and pj ⊥ p iff pk ⊥ p for each p ∈ Pµ,i

Corollary

If p0 ∈ Pµ,i and ˙ Y is a Pµ,i-name, and p0 ˙ Y ⊂ ˙ Aα ∪ m for some α ∈ Γµ

i , then p0 ˙

Y is finite. thus preserves Ind. Hyp.

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SLIDE 63

this is a good Ind. Hyp.

Lemma (assume Γµ

i -pure)

By induction on µ, if ˙ Y is a Pµ,i-name and p0, p1, · · · , pn is a Γµ

i -fan, then, for 1 ≤ j, k ≤ n, integer y,

pj y ∈ ˙ Y iff pk y ∈ ˙ Y and pj ⊥ p iff pk ⊥ p for each p ∈ Pµ,i

Corollary

If p0 ∈ Pµ,i and ˙ Y is a Pµ,i-name, and p0 ˙ Y ⊂ ˙ Aα ∪ m for some α ∈ Γµ

i , then p0 ˙

Y is finite. thus preserves Ind. Hyp.

Proof.

  • therwise
slide-64
SLIDE 64

this is a good Ind. Hyp.

Lemma (assume Γµ

i -pure)

By induction on µ, if ˙ Y is a Pµ,i-name and p0, p1, · · · , pn is a Γµ

i -fan, then, for 1 ≤ j, k ≤ n, integer y,

pj y ∈ ˙ Y iff pk y ∈ ˙ Y and pj ⊥ p iff pk ⊥ p for each p ∈ Pµ,i

Corollary

If p0 ∈ Pµ,i and ˙ Y is a Pµ,i-name, and p0 ˙ Y ⊂ ˙ Aα ∪ m for some α ∈ Γµ

i , then p0 ˙

Y is finite. thus preserves Ind. Hyp.

Proof.

  • therwise the Γµ

i -fan p0, p0, p0 has an extension fan

p0, ¯ p1, ¯ p2 with some arbitrarily large y > m such that ¯ p1 y ∈ ˙ Y.

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SLIDE 65

this is a good Ind. Hyp.

Lemma (assume Γµ

i -pure)

By induction on µ, if ˙ Y is a Pµ,i-name and p0, p1, · · · , pn is a Γµ

i -fan, then, for 1 ≤ j, k ≤ n, integer y,

pj y ∈ ˙ Y iff pk y ∈ ˙ Y and pj ⊥ p iff pk ⊥ p for each p ∈ Pµ,i

Corollary

If p0 ∈ Pµ,i and ˙ Y is a Pµ,i-name, and p0 ˙ Y ⊂ ˙ Aα ∪ m for some α ∈ Γµ

i , then p0 ˙

Y is finite. thus preserves Ind. Hyp.

Proof.

  • therwise the Γµ

i -fan p0, p0, p0 has an extension fan

p0, ¯ p1, ¯ p2 with some arbitrarily large y > m such that ¯ p1 y ∈ ˙

  • Y. But then y must be in working part of ¯

p1(α) and not in the working part of ¯ p2(α).

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SLIDE 66

this is a good Ind. Hyp.

Lemma (assume Γµ

i -pure)

By induction on µ, if ˙ Y is a Pµ,i-name and p0, p1, · · · , pn is a Γµ

i -fan, then, for 1 ≤ j, k ≤ n, integer y,

pj y ∈ ˙ Y iff pk y ∈ ˙ Y and pj ⊥ p iff pk ⊥ p for each p ∈ Pµ,i

Corollary

If p0 ∈ Pµ,i and ˙ Y is a Pµ,i-name, and p0 ˙ Y ⊂ ˙ Aα ∪ m for some α ∈ Γµ

i , then p0 ˙

Y is finite. thus preserves Ind. Hyp.

Proof.

  • therwise the Γµ

i -fan p0, p0, p0 has an extension fan

p0, ¯ p1, ¯ p2 with some arbitrarily large y > m such that ¯ p1 y ∈ ˙

  • Y. But then y must be in working part of ¯

p1(α) and not in the working part of ¯ p2(α). But then ¯ p2 y ∈ ˙ Y \ ˙ Aα.

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SLIDE 67

Hechler preserves the Ind. Hyp Γµ

i -pure

Lemma (Baumgartner-Dordal)

If D ⊂ H is dense, there is a function rkD : ω<ω↑ → ω1 such that rk(s) = 0 if there is a g with (s, g) ∈ D, and rk(s) = α > 0 if there is an ℓ such that for each n, there is an (sn, g + n) < (s, g + n) with sn ∈ ωℓ↑ and rk(sn) < α.

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SLIDE 68

Hechler preserves the Ind. Hyp Γµ

i -pure

Lemma (Baumgartner-Dordal)

If D ⊂ H is dense, there is a function rkD : ω<ω↑ → ω1 such that rk(s) = 0 if there is a g with (s, g) ∈ D, and rk(s) = α > 0 if there is an ℓ such that for each n, there is an (sn, g + n) < (s, g + n) with sn ∈ ωℓ↑ and rk(sn) < α. Suppose that Pµ (cf(µ) = κ ) satisfies Γµ

i for any i < κ.

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SLIDE 69

Hechler preserves the Ind. Hyp Γµ

i -pure

Lemma (Baumgartner-Dordal)

If D ⊂ H is dense, there is a function rkD : ω<ω↑ → ω1 such that rk(s) = 0 if there is a g with (s, g) ∈ D, and rk(s) = α > 0 if there is an ℓ such that for each n, there is an (sn, g + n) < (s, g + n) with sn ∈ ωℓ↑ and rk(sn) < α. Suppose that Pµ (cf(µ) = κ ) satisfies Γµ

i for any i < κ.

Now let ˙ D be a Pµ,i+1-name of a dense subset of H. Also, let p0, p1, . . . , pn be any Γµ

i -fan.

slide-70
SLIDE 70

Hechler preserves the Ind. Hyp Γµ

i -pure

Lemma (Baumgartner-Dordal)

If D ⊂ H is dense, there is a function rkD : ω<ω↑ → ω1 such that rk(s) = 0 if there is a g with (s, g) ∈ D, and rk(s) = α > 0 if there is an ℓ such that for each n, there is an (sn, g + n) < (s, g + n) with sn ∈ ωℓ↑ and rk(sn) < α. Suppose that Pµ (cf(µ) = κ ) satisfies Γµ

i for any i < κ.

Now let ˙ D be a Pµ,i+1-name of a dense subset of H. Also, let p0, p1, . . . , pn be any Γµ

i -fan.

For Γµ+1

i

, we have to find an extension fan p0, ¯ p1, . . . , ¯ pn so that ¯ pk ↾ µ pk(µ) ∈ ˙ D for all 1 ≤ k ≤ n.

slide-71
SLIDE 71

proof continued

We may assume that p0(µ) = (s0, ˙ g0), which means that, we can simply assume that pj(µ) = (s0, ˙ g0) for all j ≤ n

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SLIDE 72

proof continued

We may assume that p0(µ) = (s0, ˙ g0), which means that, we can simply assume that pj(µ) = (s0, ˙ g0) for all j ≤ n AND, by Γµ

i , we can assume that p1 forces a value α0 on rk ˙ D(s0), and on

the witnessing ℓ0.

slide-73
SLIDE 73

proof continued

We may assume that p0(µ) = (s0, ˙ g0), which means that, we can simply assume that pj(µ) = (s0, ˙ g0) for all j ≤ n AND, by Γµ

i , we can assume that p1 forces a value α0 on rk ˙ D(s0), and on

the witnessing ℓ0. There is an extension fan p0, ¯ p1, · · · , ¯ pn so that each ¯ pk forces a value on ˙ g0 ↾ ℓ0 and ¯ p1 picks an s1 so that each ¯ pk (s1, ˙ g0) < (s0, ˙ g0) and ¯ p1 forces that rk(s1) = α1 < α0 .

slide-74
SLIDE 74

proof continued

We may assume that p0(µ) = (s0, ˙ g0), which means that, we can simply assume that pj(µ) = (s0, ˙ g0) for all j ≤ n AND, by Γµ

i , we can assume that p1 forces a value α0 on rk ˙ D(s0), and on

the witnessing ℓ0. There is an extension fan p0, ¯ p1, · · · , ¯ pn so that each ¯ pk forces a value on ˙ g0 ↾ ℓ0 and ¯ p1 picks an s1 so that each ¯ pk (s1, ˙ g0) < (s0, ˙ g0) and ¯ p1 forces that rk(s1) = α1 < α0 . Repeat this finitely many times (as rank descends) we end up with there being a ˙ g1 such that ¯ p1 (s1, ˙ g1) ∈ ˙ D and, for all 1 ≤ k ≤ n and ¯ pk (s1, ˙ g1) < (s0, ˙ g0).

slide-75
SLIDE 75

proof continued

We may assume that p0(µ) = (s0, ˙ g0), which means that, we can simply assume that pj(µ) = (s0, ˙ g0) for all j ≤ n AND, by Γµ

i , we can assume that p1 forces a value α0 on rk ˙ D(s0), and on

the witnessing ℓ0. There is an extension fan p0, ¯ p1, · · · , ¯ pn so that each ¯ pk forces a value on ˙ g0 ↾ ℓ0 and ¯ p1 picks an s1 so that each ¯ pk (s1, ˙ g0) < (s0, ˙ g0) and ¯ p1 forces that rk(s1) = α1 < α0 . Repeat this finitely many times (as rank descends) we end up with there being a ˙ g1 such that ¯ p1 (s1, ˙ g1) ∈ ˙ D and, for all 1 ≤ k ≤ n and ¯ pk (s1, ˙ g1) < (s0, ˙ g0). Make the same steps (keep extending the fan) so that we then have an s2 and ˙ g2 so that ¯ p2 (s2, ˙ g2) ∈ ˙ D, and each ¯ pk (s2, ˙ g2) < (s1, ˙ g1) .

slide-76
SLIDE 76
  • kay, finally back to QBould

Definition (from Avraham)

h is a log-measure on a set e if h(k) = 0 for all k ∈ e and if h(e1 ∪ e2) > ℓ > 0, then one of h(e1), h(e2) is at least ℓ.

slide-77
SLIDE 77
  • kay, finally back to QBould

Definition (from Avraham)

h is a log-measure on a set e if h(k) = 0 for all k ∈ e and if h(e1 ∪ e2) > ℓ > 0, then one of h(e1), h(e2) is at least ℓ.

Definition

the log-measure (e, h) is built from the sequence (e1, h1), . . . , (en, hn) (max(ek) < min(ek+1)) if e ⊂ (e1 ∪ · · · en) and if x ⊂ e is h-positive, then there is a k such that x ∩ ek is hk-positive

slide-78
SLIDE 78

Definition

q = (wq, T q) ∈ QBould if T q = tk = (ek, hk) : k ∈ ω and max(ek) < min(ek+1) and lim inf{hk(ek) : k ∈ ω} = ∞ We let int(T) =

k int(tk) = k ek and

(w2, T2) < (w1, T1) if each t2

k is built from members of T1

and there is an ℓ such that w1 = w2 ∩ min(int(t1

ℓ )) and w2 \ w1 ⊂ int(T1) \ min(int(t1 ℓ ))

slide-79
SLIDE 79

Q207 and ℵ1-directed

slide-80
SLIDE 80

Q207 and ℵ1-directed

Definition (how to handle <c for QBould)

A subset Q ⊂ QBould is in Q207 if it is closed under finite changes, the subfamily {q ∈ Q : wq = ∅} is directed, and whenever {(wn, Tn) : n ∈ ω} is pre-dense, there is a single T such that, (∅, T) ∈ Q and for each n, there is an ℓn such that (wn, T \ ℓn) < (wn, Tn). (we made it upward absolute)

slide-81
SLIDE 81

Q207 and ℵ1-directed

Definition (how to handle <c for QBould)

A subset Q ⊂ QBould is in Q207 if it is closed under finite changes, the subfamily {q ∈ Q : wq = ∅} is directed, and whenever {(wn, Tn) : n ∈ ω} is pre-dense, there is a single T such that, (∅, T) ∈ Q and for each n, there is an ℓn such that (wn, T \ ℓn) < (wn, Tn). (we made it upward absolute)

Lemma (Fischer-Steprans partially)

If Q ∈ Q207 and P is ccc, and P Q ⊂ Q1 ∈ Q207 then Q <c P ∗ Q1. Furthermore, if Q ⊂ QBould is closed under finite changes and weakly centered, and P is ccc, then there is a P ∗ C2ω-name ˙ Q1 such that Q ⊂ ˙ Q1 ∈ Q207 and adds an unsplit real over V.

slide-82
SLIDE 82

Finishing the construction of Pλ

Lemma

Let µ < λ be a limit of cofinality =κ and assume that Pµ,i+1 is a Γµ

i -pure extension of Pµ,i. Assume further that ˙

Qµ,i is a Pµ,i ∗ C2ω-name of a member of Q207. Then there is a Pµ,i+1 ∗ C2ω+2ω-name ˙ Qµ,i+1 that is forced to be a member of Q207 and such that Pµ+1,i+1 is a Γµ+1

i

  • pure extension of Pµ+1,i.

In addition, ˙ Qµ,i+1 can be chosen so that it adds an unsplit real

  • ver the extension by Pµ,i.
slide-83
SLIDE 83

Finishing the construction of Pλ

Lemma

Let µ < λ be a limit of cofinality =κ and assume that Pµ,i+1 is a Γµ

i -pure extension of Pµ,i. Assume further that ˙

Qµ,i is a Pµ,i ∗ C2ω-name of a member of Q207. Then there is a Pµ,i+1 ∗ C2ω+2ω-name ˙ Qµ,i+1 that is forced to be a member of Q207 and such that Pµ+1,i+1 is a Γµ+1

i

  • pure extension of Pµ+1,i.

In addition, ˙ Qµ,i+1 can be chosen so that it adds an unsplit real

  • ver the extension by Pµ,i.

Remark

When handling a pre-dense {(un, Tn) : n ∈ ω} (in V[Gµ,i]) from ˙ Qµ,i, towards extending into Q207 we may not be able to do so (Cohen forcing) while keeping things Γµ,i-pure but then we Cohen force with fans as side-conditions to add to ˙ Qµ,i+1 in a Γµ

i -pure way and destroy the pre-density.

slide-84
SLIDE 84

conclusion and questions

Lemma

If we never use Hechler for α > 0, we obtain κ = t = b < λ = s

slide-85
SLIDE 85

conclusion and questions

Lemma

If we never use Hechler for α > 0, we obtain κ = t = b < λ = s

Lemma

If we do as discussed, we get κ = t = h < λ = b = s

slide-86
SLIDE 86

conclusion and questions

Lemma

If we never use Hechler for α > 0, we obtain κ = t = b < λ = s

Lemma

If we do as discussed, we get κ = t = h < λ = b = s

Corollary

There is an easy trick to lower t to ω1 (or any other value) while leaving others the same.

slide-87
SLIDE 87

conclusion and questions

Lemma

If we never use Hechler for α > 0, we obtain κ = t = b < λ = s

Lemma

If we do as discussed, we get κ = t = h < λ = b = s

Corollary

There is an easy trick to lower t to ω1 (or any other value) while leaving others the same.

Question

Is it consistent to have ω1 < h < b < s? Is it consistent to hae ω1 < h < s < b?