Lecture 3.4: Simple harmonic motion Matthew Macauley Department of - - PowerPoint PPT Presentation

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Lecture 3.4: Simple harmonic motion Matthew Macauley Department of - - PowerPoint PPT Presentation

Lecture 3.4: Simple harmonic motion Matthew Macauley Department of Mathematical Sciences Clemson University http://www.math.clemson.edu/~macaule/ Math 2080, Differential Equations M. Macauley (Clemson) Lecture 3.4: Simple harmonic motion


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Lecture 3.4: Simple harmonic motion

Matthew Macauley Department of Mathematical Sciences Clemson University http://www.math.clemson.edu/~macaule/ Math 2080, Differential Equations

  • M. Macauley (Clemson)

Lecture 3.4: Simple harmonic motion Differential Equations 1 / 5

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Introduction

Mass-spring systems

If x(t) is the displacement of a mass m on a spring, then x(t) satsifies mx′′ + 2cx′ + ω2

0x = f (t) ,

where c is the damping constant ω0 is frequency f (t) is the external driving force

  • M. Macauley (Clemson)

Lecture 3.4: Simple harmonic motion Differential Equations 2 / 5

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Harmonic motion: mx′′ + 2cx′ + ω2

0x = f (t)

Simple harmonic motion

When there is no damping or driving force, then the mass exhibits simple harmonic motion: x′′ + kx = 0 , k = ω2 > 0 .

  • M. Macauley (Clemson)

Lecture 3.4: Simple harmonic motion Differential Equations 3 / 5

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A better way to write the solution to x′′ + ω2x = 0

Big idea

Any function x(t) = a cos(ωt) + b sin(ωt) can be written as a single cosine wave x(t) = A cos(ωt − φ) = A cos

  • ω
  • t − φ

ω

  • with

Amplitude A = √ a2 + b2 Phase shift φ/ω, where “φ = tan−1(b/a).”

  • M. Macauley (Clemson)

Lecture 3.4: Simple harmonic motion Differential Equations 4 / 5

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Simple harmonic motion with an external force

Example

A 2 kg mass is suspended from a spring. The displacement of the spring once the mass is attached is 0.5 meters. If the mass is displaced 0.12m downward from equilibrium, set up and solve the initial value problem that models this.

  • M. Macauley (Clemson)

Lecture 3.4: Simple harmonic motion Differential Equations 5 / 5