Last time d N = [ b (1 N/k ) d ] N N = 0 or N = k (1 d/b ) = - - PowerPoint PPT Presentation

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Last time d N = [ b (1 N/k ) d ] N N = 0 or N = k (1 d/b ) = - - PowerPoint PPT Presentation

Last time d N = [ b (1 N/k ) d ] N N = 0 or N = k (1 d/b ) = k (1 1 /R 0 ) d t d N = [ b d (1 + N/k )] N N = 0 or N = k ( b/d 1) = k ( R 0 1) d t d N = rN (1 N/K ) N = 0 or N = K d t


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SLIDE 1

Last time

dN dt = [b(1 − N/k) − d]N ¯ N = 0

  • r

¯ N = k(1 − d/b) = k(1 − 1/R0) dN dt = [b − d(1 + N/k)]N ¯ N = 0

  • r

¯ N = k(b/d − 1) = k(R0 − 1) dN dt = rN(1 − N/K) ¯ N = 0

  • r

¯ N = K

Figures taken from NRC Handelsblad 11 Dec 2010 (left) and Wikipedia (right).

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SLIDE 2

Theoretical Biology 2016 Chapter 3 Lotka Volterra model

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SLIDE 3

Suppose measurements for the prey

(a)

mouse density R p.c. mouse birth rate b

(b)

mouse density R p.c. mouse death rate d

(c)

mouse density R mice eaten per owl dR dt = [bf(R) − d − aN]R where f(R) = 1 − R/k with maximum birth rate b, death rate d, and a predation term aRN.

y=b(1-R/k) y=aR

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SLIDE 4

Suppose measurements for the prey

(a)

mouse density R p.c. mouse birth rate b

(b)

mouse density R p.c. mouse death rate d

(c)

mouse density R mice eaten per owl dR dt = [bf(R) − d − aN]R where f(R) = 1 − R/k with maximum birth rate b, death rate d, and a predation term aRN.

y=b(1-R/k) y=aR

tumor cells tumor cells tumor cells tumor cell division rate tumor cell death rate cells killed per killer cell

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SLIDE 5

Measurements for the predator

where 1/δ is the expected owl life span

(d)

mice eaten per owl p.c. owl birth rate

(e)

  • wl density N
  • wl death rate

δ

dN dt = [caR − δ]N aR y=caR

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SLIDE 6

Measurements for the predator

where 1/δ is the expected killer cell life span

(d)

mice eaten per owl p.c. owl birth rate

(e)

  • wl density N
  • wl death rate

δ

dN dt = [caR − δ]N aR y=caR

killer cells killer cell death rate tumor cells seen per killer cell killer cell division rate

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SLIDE 7

dR dt = [bf(R) − d − aN]R where f(R) = 1 − R/k with maximum birth rate b, death rate d, and a predation term aRN. In the abscence of predators the carrying capacity is: ¯ R = k(1 − d/b) = k(1 − 1/R0) = K Number of predators: dN dt = [caR − δ]N where 1/δ is the expected life-span.

32

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SLIDE 8

Steady states

Setting dR/dt = dN/dt = 0 yields R = 0 and N = 1 a [b(1 − R/k) − d] N = 0 and R = δ ca Trivial: ( ¯ R, ¯ N) = (0, 0) and ( ¯ R, ¯ N) = (K, 0). Non-trivial: ¯ N = 1 a

b

  • 1 −

δ cak

− d

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SLIDE 9

Nullclines in phase space

(a)

R N

δ ca

K

b−d a (b)

R

δ ca

K dR dt = [b(1 − R/k) − d − aN]R and dN dt = [caR − δ]N

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SLIDE 10

LV-model typically written with logistic growth

(a)

R N

δ ca

K

b−d a (b)

R

δ ca

K dR dt = [b(1 − R/k) − d − aN]R and dN dt = [caR − δ]N

r/a

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SLIDE 11

(a)

R N

δ ca

K

b−d a (b)

R

δ ca

K dR dt = [b(1 − R/k) − d − aN]R and dN dt = [caR − δ]N

r/a What happens if we feed the prey?

Increasing K in (b):

  • 1. increases the prey density
  • 2. increases the predator density
  • 3. increases the prey density until predators can survive
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SLIDE 12

What happens if we feed the prey?

(a)

R N

δ ca

K

b−d a (b)

R

δ ca

K dR dt = [b(1 − R/k) − d − aN]R and dN dt = [caR − δ]N

dR dt = [r(1 − R/K) − aN]R and dN dt = [caR − δ]N

r/a K

K

By feeding the prey we get predators

  • 3. increases the

prey density until predators can survive

K

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SLIDE 13

(a)

R N

δ ca

K

b−d a (b)

R

δ ca

K dR dt = [b(1 − R/k) − d − aN]R and dN dt = [caR − δ]N

r/a What happens if we feed the prey?

Increasing K in (a):

  • 1. increases the prey density and keeps predators the same
  • 2. increases the predator density and keeps prey the same
  • 3. increases both populations
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SLIDE 14

What happens if we feed the prey?

(a)

R N

δ ca

K

b−d a (b)

R

δ ca

K dR dt = [b(1 − R/k) − d − aN]R and dN dt = [caR − δ]N

dR dt = [r(1 − R/K) − aN]R and dN dt = [caR − δ]N

r/a K K

By feeding the prey we get more predators

  • 2. increases the

predator density and keeps prey the same

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SLIDE 15

Example: bacterial food chain

← Prey alone ← Prey with predator ← Predator

(b): The effect of nutrients on the density of prey (a): The same for prey (a: open circles) and a predator (a: closed circles). From: Kaunzinger et al. Nature 1998.

Serratia marcescens Serratia marcescens Colpidium striatium

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SLIDE 16

(a)

R N

δ ca

K

b−d a (b)

R

δ ca

K dR dt = [b(1 − R/k) − d − aN]R and dN dt = [caR − δ]N

dR dt = [r(1 − R/K) − aN]R and dN dt = [caR − δ]N

r/a What happens if we change a?

Prey: tumor cells Predator: killer cells a: drug changing the killing rate

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SLIDE 17

1 0.5 R 1 0.5 N

Changing the predation rate a changes both

1 0.5 R 1 0.5 N

dR dt = rR(1 − R/K) − aRN , dN dt = caRN − dN .

R = d ca

N N R K K

r a

R = d ca

r a

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SLIDE 18

1 0.5 R 1 0.5 N

Decreasing the predation rate increases the predator

1 0.5 b 3 1.5 N

dR dt = rR(1 − R/K) − aRN , dN dt = caRN − dN .

N N a R

R = d ca

r a

Predators with larger a have higher fitness R0

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SLIDE 19

Fitness R0

For the prey R0 = b/d For the predator R0 = caR

δ

which is not a constant. Take the best possible circumstances, i.e., R = K and let R0 = caK

δ .

The prey equilibrium is at R = δ

ca or at R = K R0

This implies that a predator with an R0 = 2 is expected to halve its prey population.

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SLIDE 20

Lotka Volterra model is very general

Predator-prey & host-parasite models Seals in the Waddensea infected by virus Hepatocytes infected by hepatitis Cancer cells removed by killer cells Economics: interactions industries

dR dt = [r(1 − R/K) − aN]R and dN dt = [caR − δ]N

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SLIDE 21

Lotka Volterra model is very general

Many models use the Lotka Volterra equations

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SLIDE 22

1 0.5 R 1 0.5 N

Increasing the killing rate decreases the killers

1 0.5 b 3 1.5 N

dR dt = rR(1 − R/K) − aRN , dN dt = caRN − dN .

N N a R

R = d ca

r a

Tumor Killer cells

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SLIDE 23

For example the SARS epidemic

dI dt = [β − δ]I

dt − with R0 = 3, and β = 1.5 and δ = 0.5 per week

dS dt = rS(1 − S/K) − βSI and dI dt = βSI − δI

4 8 12 16 20 24 28 32 36 40 44 48 52

Time in weeks

10 10

1

10

2

10

3

10

4

10

5

10

6

10

7

10

8

10

9

10

10

Number of people

Susceptibles Infected (Lotka Volterra) Infected (I’=(β−δ)I

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SLIDE 24

Alternative: prey maintained by source

σ

dR dt = s − dN − aRN dN dt = [caR − δ]N K = s d

R N

predator remains:

δ ca

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SLIDE 25

Several Lotka Volterra like models

Lotka-Volterra model (with birth and death rates): dR dt = [b(1 − R/k) − d − aN]R and dN dt = [caR − δ]N Lotka-Volterra model (with logistic growth): dR dt = [r(1 − R/K) − aN]R and dN dt = [caR − δ]N Resource maintained by a source: dR dt = s − dR − aNR and dN dt = [caR − δ]N Lotka-Volterra competition equations: dN1 dt = r1N1(1 − N1/K1 − N2/c1) and dN2 dt = r2N2(1 − N2/K2 − N1/c2)

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SLIDE 26

History from Wikipedia

The Lotka–Volterra predator–prey model was proposed by Alfred J. Lotka “in the theory of autocatalytic chemical reactions” in 1910. This was effectively the logistic equation, originally derived by Pierre François Verhulst. In 1920 Lotka extended the model to "organic systems" using a plant species and a herbivorous animal species as an example, and in 1925 he utilised it to analyse predator- prey interactions in his book on biomathematics arriving at the equations that we know today. Vito Volterra, who made a statistical analysis of fish catches in the Adriatic independently investigated the equations in 1926.