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Integer factoring and compositeness witnesses Jacek Pomykaa & Maciej Radziejewski June 26, 2019 Integer factoring and compositeness witnesses 1 Objective: Factorization of a large integer n Oracles Techniques How many hard numbers are


  1. Integer factoring and compositeness witnesses Jacek Pomykała & Maciej Radziejewski June 26, 2019

  2. Integer factoring and compositeness witnesses 1 Objective: Factorization of a large integer n Oracles Techniques How many hard numbers are there? 2 Compositeness witnesses Fermat-Euclid Miller-Rabin Power difference 3 Results Using the Φ oracle Using the Dec Φ oracle Using iterated Φ oracle 4 Weaker oracles

  3. Oracles Φ computes the value of φ ( n ) for any given n Dec Φ computes the prime factorization of φ ( n ) Mul Φ computes some multiple D = O (exp((log n ) M ′ )) of φ ( n ) Dec Mul Φ computes the prime factorization of such a multiple

  4. Techniques • Factorization witnesses i.e. residues mod n wih special properties • We consider residues b = 1 , . . . , B , where B ≤ (log n ) O (1) is a parameter. • Exponent m of the group generated by { 1 , . . . , B } • because p ≡ 1 (mod m ) for primes p | n • Hensel-Berlekamp method • works if the exponent m is large enough • Sieving out small prime factors p ≤ y , where y ≤ (log n ) O (1) is a parameter • Reduction to square-free integers Cf. Pomykała, Źrałek (2012), and Źrałek (2010).

  5. How many hard numbers are there? Main task: Careful analysis how many numbers n ≤ x are hard, i.e. unfactorable with a given method.

  6. How many hard numbers are there? And why do we care? If we only know that there are o ( x ) such numbers, then they have density 0. However, it can mean many different things. E.g., there are log x ) = o ( x ) primes p ≤ x x • O ( • O ( x log log x ) = o ( x ) integers of the form n = pq ≤ x log x x M log log x ) = o ( x ) integers n ≤ x without prime factors • O ( p ≤ (log x ) M • O ( x 1 / 2 ) = o ( x ) squares n ≤ x • O ( x 1 / 3 ) = o ( x ) cubes n ≤ x

  7. How many hard numbers are there? Given an algorithm A we call n hard if A does not find the complete factorization of n ∗ -hard if A does not find any nontrivial divisor of n We count factorizable integers. We put: F ( x, A , O , t A , t O ) the number of n ≤ x that can be factored completely by A in time t A with at most t O queries to oracle O , F ∗ ( x, A , O , t A , t O ) the number of n ≤ x that either are prime, or can be nontrivially factored by A in time t A with at most t O queries to oracle O .

  8. Integer factoring and compositeness witnesses 1 Objective: Factorization of a large integer n Oracles Techniques How many hard numbers are there? 2 Compositeness witnesses Fermat-Euclid Miller-Rabin Power difference 3 Results Using the Φ oracle Using the Dec Φ oracle Using iterated Φ oracle 4 Weaker oracles

  9. Fermat-Euclid Fermat-Euclid compositeness witness A residue b such that � ord n b � gcd b − 1 , n � = 1 . r for some prime r | ord n b . • Then r is called the order of the witness. • If D is any multiple of ord n b , we can check b D/r i − 1 , n � � for i = 1 , 2 , . . . gcd • We have a witness, unless ord n b = ord p b for all p | n . • Problem: how do we know wich r to try?

  10. Miller-Rabin Miller-Rabin compositeness witness is just a Fermat-Euclid compositeness witness of order 2. Lemma Either there is a Miller-Rabin witness b ≤ B for n (square-free, without large prime divisors) or • n is “ B -exceptional”, i.e. for some Dirichlet character mod n the least non-residue is greater than B , or • n is determined by a pair of such exceptional integers

  11. Power difference Power difference compositeness witness A residue b such that 1 < gcd( b u − b uj 0 , n ) < n for some prescribed b 0 and u . • We can often find it if there are no Fermat-Euclid witnesses of a given order r ≥ 3 , but • we need to check j = 1 , . . . , r .

  12. Power difference Lemma Given r ≥ 3 , either there is a Fermat-Euclid witness b ≤ B for n (square-free, without large prime divisors) or • there is a power difference witness • n is “ B -exceptional”, i.e. for some Dirichlet character mod n the least non-residue is greater than B , or

  13. Integer factoring and compositeness witnesses 1 Objective: Factorization of a large integer n Oracles Techniques How many hard numbers are there? 2 Compositeness witnesses Fermat-Euclid Miller-Rabin Power difference 3 Results Using the Φ oracle Using the Dec Φ oracle Using iterated Φ oracle 4 Weaker oracles

  14. Using the Φ oracle Theorem We have, for arbitrary fixed M ≥ 4 , A = ( A 0 ( A 1 ) , B, y ) , and appropriate choices of B and y : x (log x ) − 6 . 5 M � � F ( x, A , Φ , t A , t Φ ) ≥ x − O M and F ∗ ( x, A , Φ , t A , t Φ ) ≥ x − O M x 1 . 34 /M � � , where t Φ = 1 and t A = O ((log x ) M +5 ) .

  15. Using the Φ oracle In other words: • the set of *-hard numbers is very thin, • the bound for hard numbers is much worse. Reason: • poor bounds for the smallest *-hard number, • related to the Vinogradov least-non-residue problem, • solved under Extended Riemann Hypothesis, • top results keep getting improved.

  16. Using the Dec Φ oracle Using the Dec Φ oracle we can compute the orders of all b = 1 , . . . , B mod n , and thus: • use Fermat-Euclid witnesses of all orders • compute the exponent m and use techniques based on it

  17. Using the Dec Φ oracle Theorem We have, for arbitrary fixed M ≥ 2 , A = ( A 0 ( A 3 ) , B, y ) , and appropriate choices of B and y : F ( x, A , Dec Φ , t A , t Dec Φ ) ≥ x M 3 (log log x ) 3 � � �� − O M x exp − 9(log( M + 2) + log log log x ) 2 and F ∗ ( x, A , Dec Φ , t A , t Dec Φ ) ≥ x − O M x 1 /M � � , where t Dec Φ = 1 and t A = O ((log x ) M +5 ) .

  18. Using the Dec Φ oracle Theorem We have, for arbitrary fixed M ≥ 2 , A = ( A 0 ( A 3 ) , B, y ) , and appropriate choices of B and y : F ( x, A , Dec Φ , t A , t Dec Φ ) ≥ x M 3 (log log x ) 3 � � �� − O M x exp − 9(log( M + 2) + log log log x ) 2 > x − O ( x/ (log x ) c ) for any fixed c and F ∗ ( x, A , Dec Φ , t A , t Dec Φ ) ≥ x − O M x 1 /M � � , where t Dec Φ = 1 and t A = O ((log x ) M +5 ) .

  19. Using iterated Φ oracle Idea: • If you try to factorize n and need the decomposition of φ ( n ) , • compute φ ( φ ( n )) , • compute φ ( φ ( φ ( n ))) , . . . • and factorize φ ( φ ( n )) , • and factorize φ ( n ) . • Then you can factorize n .

  20. Using iterated Φ oracle It is not as easy as iterating the algorithm A 0 ( A 3 ) , but we do have: Theorem For arbitrary fixed M ≥ 4 , A = ( A 4 , B, y ) , and appropriate choices of B and y : F ( x, A , Φ , t A , t Φ ) ≥ x M 3 (log log x ) 3 � � �� − O M x exp − 9(log( M + 2) + log log log x ) 2 and F ∗ ( x, A , Φ , t A , t Φ ) ≥ x − O M x 1 . 34 /M � � , where t Φ ≪ log x and t A = O ((log x ) M +5 ) .

  21. Integer factoring and compositeness witnesses 1 Objective: Factorization of a large integer n Oracles Techniques How many hard numbers are there? 2 Compositeness witnesses Fermat-Euclid Miller-Rabin Power difference 3 Results Using the Φ oracle Using the Dec Φ oracle Using iterated Φ oracle 4 Weaker oracles

  22. Reduction to square-free integers Reduction to square-free integers: • shown by S. Landau (1988), with O (log 3 n ) calls to Φ , • we do it with 0 extra calls to Φ , reusing the initial value, • we cannot do it if we replace Φ by Mul Φ . Nevertheless we can do it for square-free integers. Theorem All except O M x 1 /M � integers of the form n = pq ≤ x can be � factored using algorithm A 1 in time t A = O (log x ) M + M ′ +5 � with � one query to the oracle Mul Φ .

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