Image Processing 12. Photometric Stereo Aleix M. Martinez - - PDF document

image processing 12 photometric stereo
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Image Processing 12. Photometric Stereo Aleix M. Martinez - - PDF document

Image Processing 12. Photometric Stereo Aleix M. Martinez aleix@ece.osu.edu Illumination A 3D object illuminated with a light source. ^ n ^ s a Intensity at image point I(u,v) (u,v) T . 1 Photometric Stereo = I ( x , y ) kB


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SLIDE 1

1 Image Processing

  • 12. Photometric Stereo

Aleix M. Martinez aleix@ece.osu.edu

Illumination

^ n ^ s a

I(u,v) A 3D object illuminated with a light source. Intensity at image point (u,v)T.

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SLIDE 2

2 Photometric Stereo

( )

i i i

y x y x y x k y x kB y x I V g S N × = × = = ) , ( ) , ( ) , ( ) , ( ) , ( r

Dealing with shadows

I1

2(x,y)

I2

2(x,y)

.. In

2(x,y)

æ è ç ç ç ç ö ø ÷ ÷ ÷ ÷ = I1(x,y) .. I2(x,y) .. .. .. .. .. .. In(x,y) æ è ç ç ç ç ö ø ÷ ÷ ÷ ÷ V

1 T

V2

T

.. Vn

T

æ è ç ç ç ç ö ø ÷ ÷ ÷ ÷ g(x,y)

Known Known Known Unknown

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SLIDE 3

3 Recovering normal and reflectance

  • Given sufficient sources, we can solve the previous

equation (most likely need a least squares solution) for g(x, y)

  • Recall that N(x, y) is the unit normal.
  • This means that r(x,y) is the magnitude of g(x, y).
  • This yields a check

– If the magnitude of g(x, y) is greater than 1, there’s a problem

  • And N(x, y) = g(x, y) / r(x,y)

Example Recovered reflectance

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SLIDE 4

4 Recovered normal field

Surface recovered by integration

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SLIDE 5

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