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Holmgren theorems for the Radon transform Jan Boman, Stockholm - - PowerPoint PPT Presentation
Holmgren theorems for the Radon transform Jan Boman, Stockholm - - PowerPoint PPT Presentation
Holmgren theorems for the Radon transform Jan Boman, Stockholm University MIPT, September 14, 2016 Holmgrens uniqueness theorem (1901): Unique continuation across a non-characteristic hypersurface for (distribution) solutions of general
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H¨
- rmander’s proof of Holmgren’s theorem
Part 1. Microlocal regularity theorem for solutions of PDE:s with analytic coefficients: WFA(f) ⊂ WFA(Pf) ∪ char(P), where char(P) = {(x, ξ); ppr(x, ξ) = 0}.
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H¨
- rmander’s proof of Holmgren’s theorem
Part 1. Microlocal regularity theorem for solutions of PDE:s with analytic coefficients: WFA(f) ⊂ WFA(Pf) ∪ char(P), where char(P) = {(x, ξ); ppr(x, ξ) = 0}. In particular, if P(x, D)f = 0, then WFA(f) ⊂ char(P).
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H¨
- rmander’s proof of Holmgren’s theorem, cont.
Part 2. Unique continuation theorem for distributions satisfying an analytic wave front condition (microlocally real analytic distributions):
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H¨
- rmander’s proof of Holmgren’s theorem, cont.
Part 2. Unique continuation theorem for distributions satisfying an analytic wave front condition (microlocally real analytic distributions): Let S be a C2 hypersurface in Rn. Assume that f = 0 on one side of S near x0 ∈ S, and that (x0, ξ0) / ∈ WFA(f), where ξ0 is conormal to S at x0. S ξ0 x0 f = 0 Then f = 0 in some neighborhood of x0.
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The wave front set
ξ0 x0 Γ (x0, ξ0) / ∈ WF(f) if and only if ∃ ψ ∈ C∞
c
with ψ(x0) = 0 and open cone Γ ∋ ξ0 such that | ψf(ξ)| ≤ Cm(1 + |ξ|)−m, m = 1, 2, . . . , ξ ∈ Γ.
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The analytic wave front set
ξ0 x0 Γ U (x0, ξ0) / ∈ WFA(f) ⇐ ⇒ ∃ψm ∈ C∞
c (U), ψm = 1 in U0 ∋ x0 and open cone Γ ∋ ξ0 such that
| ψmf(ξ)| ≤ (Cm)k (1 + |ξ|)k , k ≤ m, m = 1, 2, . . . , ξ ∈ Γ.
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The analytic wave front set
ξ0 x0 Γ U (x0, ξ0) / ∈ WFA(f) ⇐ ⇒ ∃ψm ∈ C∞
c (U), ψm = 1 in U0 ∋ x0 and open cone Γ ∋ ξ0 such that
| ψmf(ξ)| ≤ (Cm)k (1 + |ξ|)k , k ≤ m, m = 1, 2, . . . , ξ ∈ Γ. Equivalent concept was defined for hyperfunctions with completely different methods (Sato, Kawai, Kashiwara, etc.)
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Properties of the wave front set
If ϕ ∈ C∞, then WF(ϕf) ⊂ WF(f) .
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Properties of the wave front set
If ϕ ∈ C∞, then WF(ϕf) ⊂ WF(f) . Similarly If ϕ is real analytic, then WFA(ϕf) ⊂ WFA(f) .
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Properties of the wave front set
If ϕ ∈ C∞, then WF(ϕf) ⊂ WF(f) . Similarly If ϕ is real analytic, then WFA(ϕf) ⊂ WFA(f) . If x′ → f(x′, xn) is compactly supported and (x, ±en) / ∈ WF(f) for all x then xn →
- Rn−1 f(x′, xn)dx′
is C∞. supp f x′ xn
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Another unique continuation theorem for microlocally real analytic distributions
Theorem 1 (B. 1992). Let S be a real analytic submanifold of Rn and let f be a continuous function such that (x, ξ) / ∈ WFA(f) for every x ∈ S and ξ conormal to S at x. S ξ
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Another unique continuation theorem for microlocally real analytic distributions
Theorem 1 (B. 1992). Let S be a real analytic submanifold of Rn and let f be a continuous function such that (x, ξ) / ∈ WFA(f) for every x ∈ S and ξ conormal to S at x. S ξ Assume moreover that f is flat along S in the sense that f(x) = O
- dist(x, S)m
for every m as dist(x, S) → 0. Then f = 0 in some neighborhood of S.
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Another unique continuation theorem for microlocally real analytic distributions
Theorem 1 (B. 1992). Let S be a real analytic submanifold of Rn and let f be a continuous function such that (x, ξ) / ∈ WFA(f) for every x ∈ S and ξ conormal to S at x. S ξ Assume moreover that f is flat along S in the sense that f(x) = O
- dist(x, S)m
for every m as dist(x, S) → 0. Then f = 0 in some neighborhood of S. Notation: N∗(S) = {(x, ξ); x ∈ S and ξ conormal to S at x}.
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Theorem (B. 1992). Let S be a real analytic submanifold of Rn and let f be a continuous function such that (x, ξ) / ∈ WFA(f) for every (x, ξ) ∈ N∗(S). Here N∗(S) = {(x, ξ); x ∈ S and ξ conormal to S at x}. Assume moreover that f is flat along S in the sense that f(x) = O
- dist(x, L0)m
for every m as dist(x, L0) → 0. Then f = 0 in some neighborhood of S. Remark 1. If S is a hypersurface, then the flatness assumption is weaker than in H¨
- rmander’s theorem, but the wave front assumption
is stronger.
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Theorem (B. 1992). Let S be a real analytic submanifold of Rn and let f be a continuous function such that (x, ξ) / ∈ WFA(f) for every (x, ξ) ∈ N∗(S). Here N∗(S) = {(x, ξ); x ∈ S and ξ conormal to S at x}. Assume moreover that f is flat along S in the sense that f(x) = O
- dist(x, L0)m
for every m as dist(x, L0) → 0. Then f = 0 in some neighborhood of S. Remark 1. If S is a hypersurface, then the flatness assumption is weaker than in H¨
- rmander’s theorem, but the wave front assumption
is stronger. Remark 2. The submanifold S can have arbitrary dimension.
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We don’t need to assume that f is continuous, because we can formulate the flatness condition for an arbitrary distribution satisfying the wave front condition.
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We don’t need to assume that f is continuous, because we can formulate the flatness condition for an arbitrary distribution satisfying the wave front condition. Theorem (B. 1992). Let S be a real analytic submanifold of Rn and let f be a distribution, defined in some neighborhood of S, such that (x, ξ) / ∈ WFA(f) for every (x, ξ) ∈ N∗(S). Assume moreover that f is flat along S in the sense that the restriction ∂αf
- S vanishes on S for every derivative of f.
Then f = 0 in some neighborhood of S.
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We don’t need to assume that f is continuous, because we can formulate the flatness condition for an arbitrary distribution satisfying the wave front condition. Theorem (B. 1992). Let S be a real analytic submanifold of Rn and let f be a distribution, defined in some neighborhood of S, such that (x, ξ) / ∈ WFA(f) for every (x, ξ) ∈ N∗(S). Assume moreover that f is flat along S in the sense that the restriction ∂αf
- S vanishes on S for every derivative of f.
Then f = 0 in some neighborhood of S. Note that the restrictions are well defined because of the wave front condition.
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We don’t need to assume that f is continuous, because we can formulate the flatness condition for an arbitrary distribution satisfying the wave front condition. Theorem (B. 1992). Let S be a real analytic submanifold of Rn and let f be a distribution, defined in some neighborhood of S, such that (x, ξ) / ∈ WFA(f) for every (x, ξ) ∈ N∗(S). Assume moreover that f is flat along S in the sense that the restriction ∂αf
- S vanishes on S for every derivative of f.
Then f = 0 in some neighborhood of S. Note that the restrictions are well defined because of the wave front condition. Remark 3. The theorem is not true for hyperfunctions (M. Sato).
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A non-standard initial value problem for the wave equation.
Assume a wave motion is known with infinite precision at one point for all times. Is the wave motion uniquely determined?
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A non-standard initial value problem for the wave equation.
Assume a wave motion is known with infinite precision at one point for all times. Is the wave motion uniquely determined? More precisely, assume a solution u(x, t) of the wave equation is known together with all its x-derivatives at one point x0 for all values
- f t.
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A non-standard initial value problem for the wave equation.
Assume a wave motion is known with infinite precision at one point for all times. Is the wave motion uniquely determined? More precisely, assume a solution u(x, t) of the wave equation is known together with all its x-derivatives at one point x0 for all values
- f t. Is u(x, t) uniquely determined?
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A non-standard initial value problem for the wave equation.
Assume a wave motion is known with infinite precision at one point for all times. Is the wave motion uniquely determined? More precisely, assume a solution u(x, t) of the wave equation is known together with all its x-derivatives at one point x0 for all values
- f t. Is u(x, t) uniquely determined?
The answer is YES. To prove this, let S be the line in space-time S = {(x0, t); t ∈ R}. The assumption is that ∂α
x u(x0, t) = 0
for all α and t, so the flatness condition is fulfilled.
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A non-standard initial value problem for the wave equation.
Assume a wave motion is known with infinite precision at one point for all times. Is the wave motion uniquely determined? More precisely, assume a solution u(x, t) of the wave equation is known together with all its x-derivatives at one point x0 for all values
- f t. Is u(x, t) uniquely determined?
The answer is YES. To prove this, let S be the line in space-time S = {(x0, t); t ∈ R}. The assumption is that ∂α
x u(x0, t) = 0
for all α and t, so the flatness condition is fulfilled. What about the wave front condition?
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x t S
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The conormals (x0, ξ) of S have the form ξ = (ξ1, ξ2, ξ3, 0), if n = 3.
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The conormals (x0, ξ) of S have the form ξ = (ξ1, ξ2, ξ3, 0), if n = 3. But none of those is characteristic for the wave equation.
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The conormals (x0, ξ) of S have the form ξ = (ξ1, ξ2, ξ3, 0), if n = 3. But none of those is characteristic for the wave equation. Because the characteristic directions for the wave equation with wave speed 1 are (ξ1, ξ2, ξ3, ±|ξ|). By the microlocal regularity theorem WFA(u) ⊂ char(P), where P is the wave operator.
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The conormals (x0, ξ) of S have the form ξ = (ξ1, ξ2, ξ3, 0), if n = 3. But none of those is characteristic for the wave equation. Because the characteristic directions for the wave equation with wave speed 1 are (ξ1, ξ2, ξ3, ±|ξ|). By the microlocal regularity theorem WFA(u) ⊂ char(P), where P is the wave operator. Hence (x, ξ) / ∈ WFA(f) for every (x, ξ) ∈ N∗(S).
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The conormals (x0, ξ) of S have the form ξ = (ξ1, ξ2, ξ3, 0), if n = 3. But none of those is characteristic for the wave equation. Because the characteristic directions for the wave equation with wave speed 1 are (ξ1, ξ2, ξ3, ±|ξ|). By the microlocal regularity theorem WFA(u) ⊂ char(P), where P is the wave operator. Hence (x, ξ) / ∈ WFA(f) for every (x, ξ) ∈ N∗(S). Thus the assumptions of Theorem 1 are fulfilled, so we can conclude u = 0 in some neighborhood of S.
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The conormals (x0, ξ) of S have the form ξ = (ξ1, ξ2, ξ3, 0), if n = 3. But none of those is characteristic for the wave equation. Because the characteristic directions for the wave equation with wave speed 1 are (ξ1, ξ2, ξ3, ±|ξ|). By the microlocal regularity theorem WFA(u) ⊂ char(P), where P is the wave operator. Hence (x, ξ) / ∈ WFA(f) for every (x, ξ) ∈ N∗(S). Thus the assumptions of Theorem 1 are fulfilled, so we can conclude u = 0 in some neighborhood of S. But then we can fill the space-time with a family on non-characteristic surfaces, starting from a cylindrical surface around (finite parts of) S. Hence u(x, t) = 0 for all (x, t).
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The conormals (x0, ξ) of S have the form ξ = (ξ1, ξ2, ξ3, 0), if n = 3. But none of those is characteristic for the wave equation. Because the characteristic directions for the wave equation with wave speed 1 are (ξ1, ξ2, ξ3, ±|ξ|). By the microlocal regularity theorem WFA(u) ⊂ char(P), where P is the wave operator. Hence (x, ξ) / ∈ WFA(f) for every (x, ξ) ∈ N∗(S). Thus the assumptions of Theorem 1 are fulfilled, so we can conclude u = 0 in some neighborhood of S. But then we can fill the space-time with a family on non-characteristic surfaces, starting from a cylindrical surface around (finite parts of) S. Hence u(x, t) = 0 for all (x, t). This argument can be applied to wave equations with variable analytic
- coefficients. This was done by Lebeau 1999.
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The Radon transform
For continuous f, decaying sufficiently fast at infinity, define Rf(L) =
- L
f ds, L hyperplane in Rn, where ds is area measure on L.
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The Radon transform
For continuous f, decaying sufficiently fast at infinity, define Rf(L) =
- L
f ds, L hyperplane in Rn, where ds is area measure on L. Weighted Radon transform: Define Rρf(L) =
- L
f(x)ρ(L, x)ds, L hyperplane in Rn, where ρ(L, x) is a smooth, positive function defined for all pairs (L, x) where x ∈ L.
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Helgason’s support theorem
Theorem (1965). Let K ⊂ Rn be compact and convex. Assume that f is continuous and that Rf(L) = 0 for all hyperplanes L that do not intersect K. K L
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Helgason’s support theorem
Theorem (1965). Let K ⊂ Rn be compact and convex. Assume that f is continuous and that Rf(L) = 0 for all hyperplanes L that do not intersect K. K L Assume moreover that f(x) = O(|x|−m) as |x| → ∞ for all m.
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Helgason’s support theorem
Theorem (1965). Let K ⊂ Rn be compact and convex. Assume that f is continuous and that Rf(L) = 0 for all hyperplanes L that do not intersect K. K L Assume moreover that f(x) = O(|x|−m) as |x| → ∞ for all m. Then f = 0 in the complement of K.
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Microlocal regularity theorem for R
If Rf(L) = 0 for all L in some neighborhood of L0, then (x, ξ) / ∈ WFA(f) for all x ∈ L0 and ξ conormal to L0.
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Microlocal regularity theorem for R
If Rf(L) = 0 for all L in some neighborhood of L0, then (x, ξ) / ∈ WFA(f) for all x ∈ L0 and ξ conormal to L0. In other words N∗(L0) ∩ WFA(f) = ∅. L0 ξ
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Microlocal regularity theorem for R
If Rf(L) = 0 for all L in some neighborhood of L0, then (x, ξ) / ∈ WFA(f) for all x ∈ L0 and ξ conormal to L0. In other words N∗(L0) ∩ WFA(f) = ∅. L0 ξ More generally WFA(f) ⊂ Λ−1 WFA(Rf)
- ,
where Λ is a 1 − 1 map (x, ξ) → (L, η) from T ∗(Rn) to T ∗(Hn). (Hn is the manifold of hyperplanes in Rn. )
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Microlocal regularity theorem for R
If Rf(L) = 0 for all L in some neighborhood of L0, then (x, ξ) / ∈ WFA(f) for all x ∈ L0 and ξ conormal to L0. In other words N∗(L0) ∩ WFA(f) = ∅. L0 ξ More generally WFA(f) ⊂ Λ−1 WFA(Rf)
- ,
where Λ is a 1 − 1 map (x, ξ) → (L, η) from T ∗(Rn) to T ∗(Hn). (Hn is the manifold of hyperplanes in Rn. ) Combined with H¨
- rmander’s theorem this proves the support theorem
for the special case when f is assumed to have compact support.
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Microlocal regularity theorem for R
If Rf(L) = 0 for all L in some neighborhood of L0, then (x, ξ) / ∈ WFA(f) for all x ∈ L0 and ξ conormal to L0. In other words N∗(L0) ∩ WFA(f) = ∅. L0 ξ More generally WFA(f) ⊂ Λ−1 WFA(Rf)
- ,
where Λ is a 1 − 1 map (x, ξ) → (L, η) from T ∗(Rn) to T ∗(Hn). (Hn is the manifold of hyperplanes in Rn. ) Combined with H¨
- rmander’s theorem this proves the support theorem
for the special case when f is assumed to have compact support. These assertions are also true for Rρ, if (L, x) → ρ(L, x) is real analytic an positive. (B. and Quinto 1987.)
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K L
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Factorable mappings
L x
- x
- L
− → φ ↓f ↓ f Consider imbedding Rn ⊂ Pn, and let x → φ(x) = x be a projective transformation.
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Factorable mappings
L x
- x
- L
− → φ ↓f ↓ f Consider imbedding Rn ⊂ Pn, and let x → φ(x) = x be a projective
- transformation. Then
R f( L) =
- L
- f(
x) ds =
- L
f(x)J(L, x)ds = J0(L)
- L
f(x)J1(x)ds, because the Jacobian J(L, x) factors J(L, x) = J0(L)J1(x), where J0(L) and J1(L) are positive and real analytic.
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Factorable mappings
L x
- x
- L
− → φ ↓f ↓ f Consider imbedding Rn ⊂ Pn, and let x → φ(x) = x be a projective
- transformation. Then
R f( L) =
- L
- f(
x) ds =
- L
f(x)J(L, x)ds = J0(L)
- L
f(x)J1(x)ds, because the Jacobian J(L, x) factors J(L, x) = J0(L)J1(x), where J0(L) and J1(L) are positive and real analytic. See Reconstructive integral geometry by V. Palamodov, Section 3.1: Factorable mappings.
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An extension of Helgason’s theorem
Assume again that f is rapidly decaying and that Rf(L) = 0 for all L that do not intersect K.
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An extension of Helgason’s theorem
Assume again that f is rapidly decaying and that Rf(L) = 0 for all L that do not intersect K. Make a projective transformation that takes the hyperplane at infinity to a hyperplane L0.
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An extension of Helgason’s theorem
Assume again that f is rapidly decaying and that Rf(L) = 0 for all L that do not intersect K. Make a projective transformation that takes the hyperplane at infinity to a hyperplane L0. Since R(J1 f) = 0 for all L in a neighborhood of L0, we know that (x, ξ) / ∈ WFA(J1 f) for all x ∈ L0 and ξ conormal to L0,
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An extension of Helgason’s theorem
Assume again that f is rapidly decaying and that Rf(L) = 0 for all L that do not intersect K. Make a projective transformation that takes the hyperplane at infinity to a hyperplane L0. Since R(J1 f) = 0 for all L in a neighborhood of L0, we know that (x, ξ) / ∈ WFA(J1 f) for all x ∈ L0 and ξ conormal to L0, and hence (x, ξ) / ∈ WFA( f) for all x ∈ L0 and ξ conormal to L0.
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An extension of Helgason’s theorem
Assume again that f is rapidly decaying and that Rf(L) = 0 for all L that do not intersect K. Make a projective transformation that takes the hyperplane at infinity to a hyperplane L0. Since R(J1 f) = 0 for all L in a neighborhood of L0, we know that (x, ξ) / ∈ WFA(J1 f) for all x ∈ L0 and ξ conormal to L0, and hence (x, ξ) / ∈ WFA( f) for all x ∈ L0 and ξ conormal to L0. K L0
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An extension of Helgason’s theorem, cont.
(x, ξ) / ∈ WFA( f) for all x ∈ L0 and ξ conormal to L0.
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An extension of Helgason’s theorem, cont.
(x, ξ) / ∈ WFA( f) for all x ∈ L0 and ξ conormal to L0. By the decay assumption we know also that f decays fast as x approaches L0:
- f(x) = O
- dist(x, L0)m
for every m as dist(x, L0) → 0, Hence Theorem 1 implies that f must vanish in some neighborhood of L0.
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An extension of Helgason’s theorem, cont.
(x, ξ) / ∈ WFA( f) for all x ∈ L0 and ξ conormal to L0. By the decay assumption we know also that f decays fast as x approaches L0:
- f(x) = O
- dist(x, L0)m
for every m as dist(x, L0) → 0, Hence Theorem 1 implies that f must vanish in some neighborhood of
- L0. So our original function f must vanish in some neighborhood of
the plane at infinity, which menas that it must have compact support. And then we know that it must vanish in the complement of K. K L0
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All of those arguments are valid for weighted Radon transforms Rρ with real analytic weight functions ρ(L, x), provided that the extension of ρ(L, x) to Pn∗ × Pn is real analytic and positive everywhere, that is, also at the hyperplane at infinity.
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In this argument I did not use the fact that my unique continuation theorem is local. In fact it implies more.
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In this argument I did not use the fact that my unique continuation theorem is local. In fact it implies more. Now let L0 be the plane at infinity and S a subset of the plane at infinity.
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In this argument I did not use the fact that my unique continuation theorem is local. In fact it implies more. Now let L0 be the plane at infinity and S a subset of the plane at
- infinity. That f is flat at S then means that f decays in certain
directions.
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In this argument I did not use the fact that my unique continuation theorem is local. In fact it implies more. Now let L0 be the plane at infinity and S a subset of the plane at
- infinity. That f is flat at S then means that f decays in certain
directions.
- Proposition. Assume Rf(L) = 0 for all L that do not intersect K
and that there is an open cone C ⊂ Rn and f(x) = O(|x|−m) for all m as |x| → ∞ for x ∈ C. Then f = 0 in the set
- x∈K
- x + C ∪ (−C)
- .
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I denote this set by shK(C), the shadow of C (if identified with the corresponding subset of the plane at infinity) with respect to K. K shK(C) shK(C) C
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Assume Rf(L) = 0 for all L that do not intersect K and that f(x) is rapidly decaying as x approaches a subset S of the hyperplane L0: f(x) = O
- dist(x, S)m
for every m as dist(x, S) → 0. K L0 S By Theorem 1 it follows that f = 0 in some neighborhood of S.
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And then we can continue by means of a family of “non-characteristic” surfaces: S L0 K
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Also on the other side of S: S L0 K
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Note that the points of shK(S) are the points that cannot be seen from K, if S serves as a screen and light rays are allowed to go in just one
- f the directions along the geodesics in P n.
S L0 K shK(S) shK(S)
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Let me repeat: All of those arguments are valid for weighted Radon transforms Rρ with real analytic weight functions ρ(L, x), provided that the extension of ρ(L, x) to Pn∗ × Pn is real analytic and positive everywhere, that is, also at the hyperplane at infinity.
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Unique continuation of CR functions
Let M be a real analytic submanifold of Cn. A function on M is called a CR function if for every x ∈ M it satisfies the Cauchy-Riemann equations with respect to all complex directions in Tx(M). Let S ⊂ M be a real analytic submanifold of M.
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Unique continuation of CR functions
Let M be a real analytic submanifold of Cn. A function on M is called a CR function if for every x ∈ M it satisfies the Cauchy-Riemann equations with respect to all complex directions in Tx(M). Let S ⊂ M be a real analytic submanifold of M. For x ∈ M we have two subspaces of the tangent space Tx(M): Tx(S), the tangent space to S, and Ax(M), the maximal complex-analytic subspace of Tx(M)
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Unique continuation of CR functions
Let M be a real analytic submanifold of Cn. A function on M is called a CR function if for every x ∈ M it satisfies the Cauchy-Riemann equations with respect to all complex directions in Tx(M). Let S ⊂ M be a real analytic submanifold of M. For x ∈ M we have two subspaces of the tangent space Tx(M): Tx(S), the tangent space to S, and Ax(M), the maximal complex-analytic subspace of Tx(M) Theorem (Baouendi and Tr` eves 1988). Let f be a CR function on M and assume that f vanishes together with all its derivatives on the real analytic submanifold S ⊂ M. Assume moreover that for every point x ∈ S the subspaces Ax(M) and Tx(S) span Tx(M). Then f must vanish in some neighborhood of S.
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Proof.
For a subspace N of Tx(M) we denote by N⊥ the set of its conormals in T ∗
x(M). Then
the subspaces Ax(M) and Tx(S) span Tx(M) is equivalent to Ax(M)⊥ ∩ Tx(S)⊥ = ∅.
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Proof.
For a subspace N of Tx(M) we denote by N⊥ the set of its conormals in T ∗
x(M). Then
the subspaces Ax(M) and Tx(S) span Tx(M) is equivalent to Ax(M)⊥ ∩ Tx(S)⊥ = ∅. But Tx(S)⊥ is equal to N∗
x(S) by definition.
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Proof.
For a subspace N of Tx(M) we denote by N⊥ the set of its conormals in T ∗
x(M). Then
the subspaces Ax(M) and Tx(S) span Tx(M) is equivalent to Ax(M)⊥ ∩ Tx(S)⊥ = ∅. But Tx(S)⊥ is equal to N∗
x(S) by definition.
And the fact that f is a CR function on M implies that WFA(f) ⊂ Ax(M)⊥.
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Proof.
For a subspace N of Tx(M) we denote by N⊥ the set of its conormals in T ∗
x(M). Then
the subspaces Ax(M) and Tx(S) span Tx(M) is equivalent to Ax(M)⊥ ∩ Tx(S)⊥ = ∅. But Tx(S)⊥ is equal to N∗
x(S) by definition.
And the fact that f is a CR function on M implies that WFA(f) ⊂ Ax(M)⊥. Hence WFA(f) ∩ N∗(S) = ∅, so the assumptions of Theorem 1 are fulfilled and the assertion follows.
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Proof of Theorem 1
Let us consider the case when f is continuous and S is a hypersurface, which we may assume to be {(x′, 0); |x′| < γ} for some γ > 0.
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Proof of Theorem 1
Let us consider the case when f is continuous and S is a hypersurface, which we may assume to be {(x′, 0); |x′| < γ} for some γ > 0. The assumptions are (write en = (0, . . . , 0, 1)) (x, ±en) / ∈ WFA(f) for every x = (x′, 0) ∈ S, and f(x′, xn) = O(xm
n )
as xn → 0 for (x′, 0) ∈ S and every m.
SLIDE 77
Proof of Theorem 1
Let us consider the case when f is continuous and S is a hypersurface, which we may assume to be {(x′, 0); |x′| < γ} for some γ > 0. The assumptions are (write en = (0, . . . , 0, 1)) (x, ±en) / ∈ WFA(f) for every x = (x′, 0) ∈ S, and f(x′, xn) = O(xm
n )
as xn → 0 for (x′, 0) ∈ S and every m. We have to prove that f = 0 in some neighborhood of the origin.
SLIDE 78
Proof of Theorem 1
Let us consider the case when f is continuous and S is a hypersurface, which we may assume to be {(x′, 0); |x′| < γ} for some γ > 0. The assumptions are (write en = (0, . . . , 0, 1)) (x, ±en) / ∈ WFA(f) for every x = (x′, 0) ∈ S, and f(x′, xn) = O(xm
n )
as xn → 0 for (x′, 0) ∈ S and every m. We have to prove that f = 0 in some neighborhood of the origin. Since (0, ±en) / ∈ WFA(f) we can choose ψm ∈ C∞ such that supp ψm is contained in a neighborhood U of the origin, ψm = 1 in a smaller neighborhood U0 of the origin, and ε > 0, such that | ψmf(ξ)| ≤ (Cm)k(1 + |ξ|)−k, k ≤ m, |ξ′| < ε|ξn|, for all m.
SLIDE 79
It turns out that it is better to choose ψm so that ψm tends to and arbitrary test function ϕ ∈ C∞
c (U0) with convergence in the topology
- f C∞
c . One can show that this is possible.
SLIDE 80
It turns out that it is better to choose ψm so that ψm tends to and arbitrary test function ϕ ∈ C∞
c (U0) with convergence in the topology
- f C∞
c . One can show that this is possible.
Consider hm(xn) =
- Rn−1 ψm(x′, xn)f(x′, xn)dx′,
which now depends on ϕ.
SLIDE 81
It turns out that it is better to choose ψm so that ψm tends to and arbitrary test function ϕ ∈ C∞
c (U0) with convergence in the topology
- f C∞
c . One can show that this is possible.
Consider hm(xn) =
- Rn−1 ψm(x′, xn)f(x′, xn)dx′,
which now depends on ϕ. The Fourier transforms of hm satisfies
- hm(ξn) =
ψmf(0, ξn).
SLIDE 82
It turns out that it is better to choose ψm so that ψm tends to and arbitrary test function ϕ ∈ C∞
c (U0) with convergence in the topology
- f C∞
c . One can show that this is possible.
Consider hm(xn) =
- Rn−1 ψm(x′, xn)f(x′, xn)dx′,
which now depends on ϕ. The Fourier transforms of hm satisfies
- hm(ξn) =
ψmf(0, ξn). There are good bounds for derivatives of hm, because sup |∂khm| ≤
- |ξk
n
hm(ξn)|dξn =
- |ξk
n
ψmf(0, ξn)|dξn ≤
- |ξn|k
(Cm)k+2 (1 + |ξn|)k+2 dξn ≤ 4(Cm)k+2 for k + 2 ≤ m. (1)
SLIDE 83
It turns out that it is better to choose ψm so that ψm tends to and arbitrary test function ϕ ∈ C∞
c (U0) with convergence in the topology
- f C∞
c . One can show that this is possible.
Consider hm(xn) =
- Rn−1 ψm(x′, xn)f(x′, xn)dx′,
which now depends on ϕ. The Fourier transforms of hm satisfies
- hm(ξn) =
ψmf(0, ξn). There are good bounds for derivatives of hm, because sup |∂khm| ≤
- |ξk
n
hm(ξn)|dξn =
- |ξk
n
ψmf(0, ξn)|dξn ≤
- |ξn|k
(Cm)k+2 (1 + |ξn|)k+2 dξn ≤ 4(Cm)k+2 for k + 2 ≤ m. (1) One can show that the constant C can be chosen independent of ϕ.
SLIDE 84
Since hm is flat at xn = 0 and its derivatives satisfy (1), Taylor’s formula gives |hm(xn)| ≤ δm−2 (m − 2)! sup |∂m−2hm| ≤ δm−2 (m − 2)!4(Cm)m ≤ 4C2e2m2(Ceδ)m−2, |xn| < δ. Hence lim
m→∞ hm(xn) = 0,
if |xn| < δ < 1/Ce. But hm(xn) tends to h(xn) =
- Rn−1 ϕ(x′, xn)f(x′, xn)dx′,
as m → ∞, hence h(xn) = 0, if |xn| < δ < 1/Ce.
SLIDE 85
Since hm is flat at xn = 0 and its derivatives satisfy (1), Taylor’s formula gives |hm(xn)| ≤ δm−2 (m − 2)! sup |∂m−2hm| ≤ δm−2 (m − 2)!4(Cm)m ≤ 4C2e2m2(Ceδ)m−2, |xn| < δ. Hence lim
m→∞ hm(xn) = 0,
if |xn| < δ < 1/Ce. But hm(xn) tends to h(xn) =
- Rn−1 ϕ(x′, xn)f(x′, xn)dx′,
as m → ∞, hence h(xn) = 0, if |xn| < δ < 1/Ce. Since this is true for all ϕ, we can conclude that f(x′, xn) = 0 for (x′, xn) ∈ U0 and |xn| < δ, which completes the proof.
SLIDE 86
Construction of ψm
- Lemma. For every m there exists φm ∈ C∞
c (R), even, with
supp φm ⊂ [−1, 1],
- φm(x)dx = 1, and
(2)
- |∂kφm(x)|dx ≤ (2m)k,
k ≤ m.
SLIDE 87
Construction of ψm
- Lemma. For every m there exists φm ∈ C∞
c (R), even, with
supp φm ⊂ [−1, 1],
- φm(x)dx = 1, and
(2)
- |∂kφm(x)|dx ≤ (2m)k,
k ≤ m.
- Proof. Take θ(x) in C∞, even, with supp θ ⊂ [−1, 1], θ(x) ≥ 0, and
- θ(x)dx = 1. We can find θ(x) so that
- |θ′(x)|dx ≤ 2.
SLIDE 88
Construction of ψm
- Lemma. For every m there exists φm ∈ C∞
c (R), even, with
supp φm ⊂ [−1, 1],
- φm(x)dx = 1, and
(2)
- |∂kφm(x)|dx ≤ (2m)k,
k ≤ m.
- Proof. Take θ(x) in C∞, even, with supp θ ⊂ [−1, 1], θ(x) ≥ 0, and
- θ(x)dx = 1. We can find θ(x) so that
- |θ′(x)|dx ≤ 2. Choose
φm(x) = mθ(mx) ∗ mθ(mx) ∗ . . . ∗ mθ(mx) (m factors).
SLIDE 89
Construction of ψm
- Lemma. For every m there exists φm ∈ C∞
c (R), even, with
supp φm ⊂ [−1, 1],
- φm(x)dx = 1, and
(2)
- |∂kφm(x)|dx ≤ (2m)k,
k ≤ m.
- Proof. Take θ(x) in C∞, even, with supp θ ⊂ [−1, 1], θ(x) ≥ 0, and
- θ(x)dx = 1. We can find θ(x) so that
- |θ′(x)|dx ≤ 2. Choose
φm(x) = mθ(mx) ∗ mθ(mx) ∗ . . . ∗ mθ(mx) (m factors). Then supp φm ⊂ [−1, 1] and
- φm(x)dx = 1.
SLIDE 90
Construction of ψm
- Lemma. For every m there exists φm ∈ C∞
c (R), even, with
supp φm ⊂ [−1, 1],
- φm(x)dx = 1, and
(2)
- |∂kφm(x)|dx ≤ (2m)k,
k ≤ m.
- Proof. Take θ(x) in C∞, even, with supp θ ⊂ [−1, 1], θ(x) ≥ 0, and
- θ(x)dx = 1. We can find θ(x) so that
- |θ′(x)|dx ≤ 2. Choose
φm(x) = mθ(mx) ∗ mθ(mx) ∗ . . . ∗ mθ(mx) (m factors). Then supp φm ⊂ [−1, 1] and
- φm(x)dx = 1. Moreover, if k ≤ m
∂kφm(x) = m2θ′(mx) ∗ . . . ∗ m2θ′(mx)
- k factors
∗ . . . ∗ mθ(mx). This proves (2).
SLIDE 91
Construction of ψm, cont.
- Lemma. The functions φm satisfy
φm → δ0 in distribution sense, hence (3) ψm = φm ∗ ϕ → ϕ in C∞
c
.
SLIDE 92
Construction of ψm, cont.
- Lemma. The functions φm satisfy
φm → δ0 in distribution sense, hence (3) ψm = φm ∗ ϕ → ϕ in C∞
c
. Proof sketch. Since
- θ(x)dx = 1, θ(x) ≥ 0, and θ(x) is even
- θ(ξ) = 1 − c ξ2 + . . .
as ξ → 0, for some c > 0.
SLIDE 93
Construction of ψm, cont.
- Lemma. The functions φm satisfy
φm → δ0 in distribution sense, hence (3) ψm = φm ∗ ϕ → ϕ in C∞
c
. Proof sketch. Since
- θ(x)dx = 1, θ(x) ≥ 0, and θ(x) is even
- θ(ξ) = 1 − c ξ2 + . . .
as ξ → 0, for some c > 0. Hence
- φm(ξ) =
θ(ξ/m)m =
- 1 − c ξ2
m2 + . . . m → 1 as |ξ| → ∞ uniformly on bounded sets. Since φm is uniformly bounded (in fact | φm| ≤ 1) this proves (3).
SLIDE 94
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