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Gauss composition and integral arithmetic invariant theory David - - PowerPoint PPT Presentation

Gauss composition and integral arithmetic invariant theory David Zureick-Brown (Emory University) Anton Gerschenko (Google) Connections in Number Theory Fall Southeastern Sectional Meeting University of North Carolina at Greensboro,


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Gauss composition and integral arithmetic invariant theory

David Zureick-Brown (Emory University) Anton Gerschenko (Google) Connections in Number Theory Fall Southeastern Sectional Meeting University of North Carolina at Greensboro, Greensboro, NC Nov 8, 2014

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Sums of Squares

Recall (p prime)

p = x2 + y2 if and only if p = 1 mod 4 or p = 2.

For products

(x2 + y2)(z2 + w2) = (xz + yw)2 + (xw − yz)2

David Zureick-Brown (Emory University) Gauss composition and integral AIT Nov 8, 2014 2 / 26

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Sums of Squares

Recall (p prime)

p = x2 + dy2 if and only if [more complicated condition].

Example

p = x2 + 2y2 for some x, y ∈ Z if and only if p = 2 or p = 1, 3 mod 8.

Example

p = x2 + 3y2 for some x, y ∈ Z if and only if p = 3 or p = 1 mod 3.

David Zureick-Brown (Emory University) Gauss composition and integral AIT Nov 8, 2014 3 / 26

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Sums of Squares

Recall (p prime)

p = x2 + dy2 if and only if [more complicated condition].

For products

(x2 + dy2)(z2 + dw2) = (xz + dyw)2 + d(xw − yz)2

David Zureick-Brown (Emory University) Gauss composition and integral AIT Nov 8, 2014 4 / 26

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Integers represented by a quadratic form

General quadratic forms (initiated by Lagrange)

Q(x, y) ∈ Z[x, y]2

Recall (p prime)

p = Q(x, y) for some x, y ∈ Z if and only if [more complicated condition].

Composition law?

Q(x, y)Q(z, w) = Q(a, b)

David Zureick-Brown (Emory University) Gauss composition and integral AIT Nov 8, 2014 5 / 26

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Sums of Squares (Euler’s conjecture)

Example

p = x2 + 14y2 for some x, y ∈ Z if and only if −14

p

  • = −1 and

(z2 + 1)2 = 8 has a solution mod p.

Example

p = 2x2 + 7y2 for some x, y ∈ Z if and only if −14

p

  • = −1 and

(z2 + 1)2 − 8 factors into two irreducible quadratics mod p.

David Zureick-Brown (Emory University) Gauss composition and integral AIT Nov 8, 2014 6 / 26

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Integers represented by a quadratic form (equivalence)

Equivalence of forms

1 Q(x, y) ∈ Z[x, y]2 2 M ∈ SL2(Z), QM(x, y) := Q(ax + by, cx + dy) 3 n ∈ Z is represented by Q iff it is represented by QM. 4 Reduced forms: |b| ≤ a ≤ c and b ≥ 0 if a = c or a = |b|.

Example

29x2 + 82xy + 58y2 ∼ x2 + y2.

David Zureick-Brown (Emory University) Gauss composition and integral AIT Nov 8, 2014 7 / 26

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Gauss composition

Theorem (Gauss composition)

The reduced, non-degenerate positive definite forms of discriminant −D form a finite abelian group, isomorphic to the class group of Q( √ −D).

Example (D = −56)

x2 + 14y2, 2x2 + 7y2, 3x2 ± 2xy + 5y2

Remark

1 Gauss’s proof was long and complicated; difficult to compute with. 2 Later reformulated by Dirichlet. 3 Much later reformulated by Bhargava. David Zureick-Brown (Emory University) Gauss composition and integral AIT Nov 8, 2014 8 / 26

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Bhargava cubes

a b d c e f h g

  • David Zureick-Brown (Emory University)

Gauss composition and integral AIT Nov 8, 2014 9 / 26

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Bhargava cubes

a b d c e f h g

  • 1 a, b, d, c, e, f , h, g ∈ Z,

2 Cube is really an element of Z2 ⊗ Z2 ⊗ Z2, with a natural SL2(Z)3

action

David Zureick-Brown (Emory University) Gauss composition and integral AIT Nov 8, 2014 10 / 26

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Gauss composition via Bhargava cubes

a b d c e f h g

  • Q1(x, y) := −Det

a b

d c

  • x −

e f

h g

  • y
  • David Zureick-Brown (Emory University)

Gauss composition and integral AIT Nov 8, 2014 11 / 26

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Gauss composition via Bhargava cubes

a b d c e f h g

  • Qi(x, y) := −Det (Mix − Niy)

David Zureick-Brown (Emory University) Gauss composition and integral AIT Nov 8, 2014 12 / 26

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Gauss composition via Bhargava cubes

a b d c e f h g

  • Qi(x, y) := −Det (Mix − Niy)

David Zureick-Brown (Emory University) Gauss composition and integral AIT Nov 8, 2014 13 / 26

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Bhargava’s theorem

a b d c e f h g

  • Qi(x, y) := −Det (Mix − Niy)

Theorem (Bhargava)

Q1(x, y) + Q2(x, y) + Q3(x, y) = 0

David Zureick-Brown (Emory University) Gauss composition and integral AIT Nov 8, 2014 14 / 26

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Lots of parameterizations

Example

binary cubic forms ↔ cubic fields pairs (ternary, quadratic) forms ↔ quartic fields quadruples of quinary ↔ quintic fields alternating bilinear forms binary quartic forms ↔

2-Selmer elements of Elliptic curves

Remark

1 14 more (Bhargava) 2 many more (Bhargava-Ho) David Zureick-Brown (Emory University) Gauss composition and integral AIT Nov 8, 2014 15 / 26

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Representation theoretic framework

Space of forms

1 The space V of binary quadratic forms is 3-dimensional vector space

(resp. R-module).

2 V = Sym2 C2

Representations

SL2(C) Sym2 C2 SL2(R) Sym2 R2 SL2(Z) Sym2 Z2 etc..

Invariants

1

C-Invariants: two non-zero forms f , g are C equivalent iff ∆(f ) = ∆(g).

2

Z-Invariants: ∆(f ) = ∆(g) ⇒ Z equivalence.

David Zureick-Brown (Emory University) Gauss composition and integral AIT Nov 8, 2014 16 / 26

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Representation theoretic framework

Invariants

1

C-Invariants: two non-zero forms f , g are C equivalent iff ∆(f ) = ∆(g).

2

Z-Invariants: ∆(f ) = ∆(g) ⇒ Z equivalence.

Example (D = −14 · 4)

x2 + 14y2 is not equivalent to 2x2 + 7y2.

Fundamental object of study

1 SL2(Z)-orbits of an SL2(Q)-orbit David Zureick-Brown (Emory University) Gauss composition and integral AIT Nov 8, 2014 17 / 26

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General representation theoretic framework

Framework

1 V = free R module 2 G V 3 R → R′ ring extension 4 v ∈ V (R)

Goal

Understand the G(R)-orbits of the G(R′)-orbit of v

David Zureick-Brown (Emory University) Gauss composition and integral AIT Nov 8, 2014 18 / 26

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Arithmetic invariant theory

“Is every group a cohomology group H1

´ et(Spec Z, ResO/ZGm)

David Zureick-Brown (Emory University) Gauss composition and integral AIT Nov 8, 2014 19 / 26

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Arithmetic invariant theory

“Is every group a cohomology group

  • r a Manjul shaped

asteroid that fell from the sky?” – Jordan Ellenberg H1

´ et(Spec Z, ResO/ZGm)

David Zureick-Brown (Emory University) Gauss composition and integral AIT Nov 8, 2014 19 / 26

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Arithmetic invariant theory

“Is every group a cohomology group

  • r a Manjul shaped

asteroid that fell from the sky?” – Jordan Ellenberg H1

´ et(Spec Z, ResO/ZGm)

David Zureick-Brown (Emory University) Gauss composition and integral AIT Nov 8, 2014 19 / 26

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Bhargava–Gross–Wang

Setup

1 f , g ∈ V (Q) 2 M ∈ G(Q) s.t. g = M · f 3 σ ∈ Gal(Q/Q) 4 Then g = Mσ · f , so f = M−1Mσ · f , i.e. M−1Mσ ∈ Stabf

Cohomological framework

The map Gal(Q/Q) → Stabf ; σ → M−1Mσ is a cocycle, and gives an element of H1(Gal(Q/Q), Stabf ).

David Zureick-Brown (Emory University) Gauss composition and integral AIT Nov 8, 2014 20 / 26

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Integral arithmetic invariant theory

Remark

1 AIT only works for fields; can’t recover Gauss composition 2 Analogue of Galois cohomology is ´

etale cohomology.

David Zureick-Brown (Emory University) Gauss composition and integral AIT Nov 8, 2014 21 / 26

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Integral arithmetic invariant theory – setup

Setup

1 S any base (e.g. Z); 2 G/S any group scheme (not necessarily smooth, or even flat); 3 X (usually a vector space); 4 G X an action.

Example (“Gauss”)

G = SL2,Z, acting on X = Sym2 A2

Z

David Zureick-Brown (Emory University) Gauss composition and integral AIT Nov 8, 2014 22 / 26

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Main Theorem

Theorem (Giraud; Geraschenko-ZB)

Let v ∈ X(S). Then there is a functorial long exact sequence (of groups and pointed sets) 0 → Stabv(S) → G(S)

g→g·v

− − − − → Orbitv(S) → H1(S, Stabv) → H1(S, G). If Stabv is commutative, then Orbitv(S)/G(S) ∼ = ker

  • H1(S, Stabv) → H1(S, G)
  • is a group.

Remark

The image Orbitv(S)/G(S) of X(S) is the set of G(S) equivalence classes

  • f v′ ∈ Orbitv(S) in the same local orbit as v.

David Zureick-Brown (Emory University) Gauss composition and integral AIT Nov 8, 2014 23 / 26

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Example: Gauss composition revisited

Example (“Gauss”)

G = SL2,Z acts on X = Sym2 A2

Z; Stabv is a non-split torus (thus commutative).

Let f ∈ X(Z) be a primitive (non-zero mod all p) integral quadratic form. 0 → Stabv(Z) → SL2(Z)

g→g·f

− − − − → Orbitf (Z) → H1(Z, Stabv) → H1(Z, SL2).

Remark

1 H1(Z, SL2) = 0 (this is Hilbert’s theorem 90). 2 Orbitf (Z)/ SL2(Z) = integral equivalence classes of primitive forms with

the same discriminantn.

3

H1(Z, Stabv) ∼ = Orbitf (Z)/ SL2(Z).

4

H1(Z, Stabv) ∼ = Pic Z[(∆f + √∆f )/2] = Cl Q[√∆f ].

David Zureick-Brown (Emory University) Gauss composition and integral AIT Nov 8, 2014 24 / 26

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Example: Gauss composition (non-primitive)

Remark

1 If f ∈ Z2 is not primitive, then Stabf is not flat over Spec Z. 2 (Easiest way to not be flat: dim Stabf ,Fp is not constant.) 3 Our machinery does not care; and recovers Gauss composition for

non-primitive forms.

David Zureick-Brown (Emory University) Gauss composition and integral AIT Nov 8, 2014 25 / 26

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Still to come

More applications wanted.

1 We’re currently iterating through the known literature, deriving

paramaterizations where possible.

2 E.g. Delone–Faddeev (ternary cubic forms vs cubic rings): stabilizer is

a finite flat group scheme.

3 Future predictive power, especially of degenerate objects/orbits. David Zureick-Brown (Emory University) Gauss composition and integral AIT Nov 8, 2014 26 / 26