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Friday, 4 th January 2013 WIND AND EARTHQUAKE LOAD ON THE VERTICAL - PowerPoint PPT Presentation

Friday, 4 th January 2013 WIND AND EARTHQUAKE LOAD ON THE VERTICAL PRESSURE VESSEL FOR OIL SEPARATOR USING GRAPHICAL- BASED SOFTWARE Name : Aji Abdillah Kharisma Student Number : 20409191 Department : Mechanical


  1. Friday, 4 th January 2013 WIND AND EARTHQUAKE LOAD ON THE VERTICAL PRESSURE VESSEL FOR OIL SEPARATOR USING GRAPHICAL- BASED SOFTWARE Name : Aji Abdillah Kharisma Student Number : 20409191 Department : Mechanical Engineering Advisor : Dr. C. Prapti Mahandari, ST, M.Eng

  2. Friday, 4 th January 2013 Outline INTRODUCTION RESEARCH METHOD RESULT AND DISSCUSSION CONCLUSION

  3. Friday, 4 th January 2013 Introduction Vertical Separator and its function Mechanical design of a Oil Separator Pressure Vessel

  4. Friday, 4 th January 2013 Introduction Designing a pressure vessel involves numerous calculations. Many software as a tool for designing a pressure vessel are available A pressure vessel has been design using a Graphical-Based Software is PV Elite 2010

  5. Friday, 4 th January 2013 Introduction Objective of The Research • To determine the safety factor of the pressure vessel design on the earthquake and wind load inputs. • To determine the result of the calculation of greatest bending and design stability which occur on the wind load input. • To determine the result of the calculation of greatest bending and the stress allowance on the design due to the earthquake load input.

  6. Friday, 4 th January 2013 Research Methods A pressure vessel has been design using Standar Code ASME VIII Divison 1. Analysis was conducted on the Wind and Earthquake Load Design of The Oil Separator Pressure Vessel. Wind and Earthquake Load on The Oil Separator Design using Standar ASCE 7-98 Criteria of the stability and design of a acceptable on The Wind and Earthquake Load Design. Output are presented as they were generated.

  7. Friday, 4 th January 2013 Research Methods Flow chart input Wind Load

  8. Friday, 4 th January 2013 Research Methods Flowchart Input Eartquake Load

  9. Friday, 4 th January 2013 Result and Discussion Wind Bending : 20971.9 N.m

  10. Friday, 4 th January 2013 Result and Discussion From To Wind Bending (N-m) 10 to 20 20971.9 20 t0 30 17735.5 30 to 40 13736.8 40 to 50 9151.17 50 to 60 9145.94 60 to 70 5291.80 70 to 80 2467.08 80 to 90 705.858

  11. Friday, 4 th January 2013 Result and Discussion • Effective Height [z] • `Basic Wind Pressure, Imperial Units [qz]: = Centroid Hgt. + Vessel Base Elevation = 0.00256 * Kz * Kzt * Kd * I * Vr(mph)² = 0.657 + 0.000 = 0.657 m = 0.00256 * 0.849 * 1.000 * 0.950 * 1.000 * (25.054 )² = 2.156 ft. Imperial Units = 1.296 psf [0.062 ] kPa • `Force on the first element [F]: • Compute [Kz] = qz * Gh * Cf * WindArea Because z (2.156 ft.) < 15 ft. = 0.062 * 0.889 * 0.617 * 5.007 = 2.01 * ( 15 / Zg ) 2 / Alpha = 170.221 N = 2.01 * ( 15 / 900.000 ) 2 / 9.500 = 0.849 • As there is No Hill Present: [Kzt] K1 = 0, K2 = 0, K3 = 0 • Topographical Factor [Kzt] = ( 1 + K1 * K2 * K3 )² = ( 1 + 0.000 * 0.000 * 0.000 )² = 1.0000

  12. Friday, 4 th January 2013 Result and Discussion Earthquake Bending : 797398. N-m

  13. Friday, 4 th January 2013 Result and Discussion From To Earthquake Bending (N-m) 10 to 20 797398. 20 to 30 687538 30 to 40 545604. 40 to 50 379911. 50 to 60 379721. 60 to 70 233727. 70 to 80 116016. 80 to 90 34922.1

  14. Friday, 4 th January 2013 Result and Discussion Earthquake Load Input : The Coefficient Cu from Table 9.5.3.3 is 1.300 • Fa 1.000 Check the Min. Value of T which is the Smaller of Cu*Ta • and T, [T]: Fv 1.400 = Min. Value of (1.300 * 0.398 , 1/6.699 ) • Ss 1.00 = 0.1493 per 9.5.3.3 • S1 0.400 • Moment Reduction Factor Tau : 1.000 Compute the Seismic Response Coefficient Cs per • Force Modification Factor R : 3.000 9.5.3.2.1, [Cs]: • = Sds / ( R / I ) Importance Factor : 1.000 = 0.667 / ( 3.00 / 1.00 ) = 0.2222 • Site Class : C Check the Maximum value of Cs per eqn. 9.5.3.2.1-2 : • Sms = Fa * Ss = 1.000 * 1.000 = 1.000 = Sd1 / ( ( R / I ) * T ) • Sm1 = Fv * S1 = 1.400 * 0.400 = 0.560 = 0.373 / ( ( 3.00 / 1.00 ) * 0.149 ) = 0.8336 • Sds = 2/3 * Sms = 2/3 * 1.000 = 0.667 Check the Minimum value of Cs per eqn. 9.5.3.2.1-3: • Sd1 = 2/3 * Sm1 = 2/3 * 0.560 = 0.373 = 0.044 * 1.00 * 0.667 = 0.0293 • Check the Period (1/Frequency) from 9.5.3.3-1 Compute the Total Base Shear V = Cs * Total Weight, = Ct * hn 3/4 where Ct = 0.020 and hn = total [V]: Vessel Height [Ta]: = 0.2222 * 474627.4 = 105472.76 N = 0.020 * 16.4221 3/4 = 0.398 seconds

  15. Friday, 4 th January 2013 Conclusion The wind bending which occurs in the oil separator design is 20971.9 N-m. The earthquake bending in the oil separator on the earthquake load design is 797398 N-m • W/LDr 2 > 25 criterion, the value is 0.10005+05 > 25. This condition fulfills the requirement of occurring vibration. • Vc > 22.3515 m/s criterion, The value is 38.4 m/s > 22.3512 m/s. This condition in the pressure vessel design is stable. It is not necessary to reanalyze. • Dynamic deflection criterion of the design due to either wind or earthquake loads. If < 6 or 100 ft, in the unit SI < 30.48 m (the design is approved). If 0.00116 m < 0.1524 m (the design is approved in the dynamic deflection condition). • Pm < SE = 11.19 N/ mm 2 < 120.65 N/mm 2 • Pb > Pm = 180.98 N/mm 2 > 11.19 N/mm 2 • PL = Pm+Qm< 1.5 SE = 22.34 N/mm 2 < 180.98 N/mm 2

  16. Friday, 4 th January 2013 Thank You

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