Four classes of verbal subgroups Olga Macedonska Silesian - - PowerPoint PPT Presentation

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Four classes of verbal subgroups Olga Macedonska Silesian - - PowerPoint PPT Presentation

Four classes of verbal subgroups Olga Macedonska Silesian University of Technology, Poland St.Andrews 2013 Let F be a free group of rank n > 1, and F be a semigroup on a set of free generators. Let F be a free group of rank n > 1, and F be


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Four classes of verbal subgroups

Olga Macedonska

Silesian University of Technology, Poland

St.Andrews 2013

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Let F be a free group of rank n > 1, and F be a semigroup on a set of free generators.

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Let F be a free group of rank n > 1, and F be a semigroup on a set of free generators. A law u ≡ v is called positive if u, v ∈ F.

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Let F be a free group of rank n > 1, and F be a semigroup on a set of free generators. A law u ≡ v is called positive if u, v ∈ F. By V we denote a verbal subgroup in F. Every word in V is a law in the variety var(F/V ).

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Let F be a free group of rank n > 1, and F be a semigroup on a set of free generators. A law u ≡ v is called positive if u, v ∈ F. By V we denote a verbal subgroup in F. Every word in V is a law in the variety var(F/V ). Proposition The set of verbal subgroups in F forms a lattice. If V1, V2 are verbal then V1V2 and V1 ∩ V2 are the verbal subgroups.

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Let F be a free group of rank n > 1, and F be a semigroup on a set of free generators. A law u ≡ v is called positive if u, v ∈ F. By V we denote a verbal subgroup in F. Every word in V is a law in the variety var(F/V ). Proposition The set of verbal subgroups in F forms a lattice. If V1, V2 are verbal then V1V2 and V1 ∩ V2 are the verbal subgroups. The examples of verbal subgroups: ˆ F e, γc(F).

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Let F be a free group of rank n > 1, and F be a semigroup on a set of free generators. A law u ≡ v is called positive if u, v ∈ F. By V we denote a verbal subgroup in F. Every word in V is a law in the variety var(F/V ). Proposition The set of verbal subgroups in F forms a lattice. If V1, V2 are verbal then V1V2 and V1 ∩ V2 are the verbal subgroups. The examples of verbal subgroups: ˆ F e, γc(F). Definition V is called VN-verbal if F/V is virtually nilpotent.

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Let F be a free group of rank n > 1, and F be a semigroup on a set of free generators. A law u ≡ v is called positive if u, v ∈ F. By V we denote a verbal subgroup in F. Every word in V is a law in the variety var(F/V ). Proposition The set of verbal subgroups in F forms a lattice. If V1, V2 are verbal then V1V2 and V1 ∩ V2 are the verbal subgroups. The examples of verbal subgroups: ˆ F e, γc(F). Definition V is called VN-verbal if F/V is virtually nilpotent. So a verbal subgroup V is VN-verbal iff it contains γc( ˆ F e).

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Theorem VN-verbal subgroups in F form a sublattice in the lattice of all subgroups in F.

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Theorem VN-verbal subgroups in F form a sublattice in the lattice of all subgroups in F. Proof

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Theorem VN-verbal subgroups in F form a sublattice in the lattice of all subgroups in F. Proof Let V1 ⊇ γc( ˆ F k), V2 ⊇ γd( ˆ F ℓ).

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Theorem VN-verbal subgroups in F form a sublattice in the lattice of all subgroups in F. Proof Let V1 ⊇ γc( ˆ F k), V2 ⊇ γd( ˆ F ℓ). V1V2 ⊇ γm( ˆ F e), m = min(c, d), e = gcd(k, ℓ).

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Theorem VN-verbal subgroups in F form a sublattice in the lattice of all subgroups in F. Proof Let V1 ⊇ γc( ˆ F k), V2 ⊇ γd( ˆ F ℓ). V1V2 ⊇ γm( ˆ F e), m = min(c, d), e = gcd(k, ℓ). V1 ∩ V2 ⊇ γm( ˆ F e), m = max(c, d), e = lcm(k, ℓ).

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VN-property

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VN-property

We say that V has VN-property if V is VN-verbal.

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VN-property

We say that V has VN-property if V is VN-verbal. VN-verbal subgroups have the following 3 properties:

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VN-property

We say that V has VN-property if V is VN-verbal. VN-verbal subgroups have the following 3 properties: F/V satisfies a positive law, (A. Maltsev)

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VN-property

We say that V has VN-property if V is VN-verbal. VN-verbal subgroups have the following 3 properties: P-property: F/V satisfies a positive law, (A. Maltsev)

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VN-property

We say that V has VN-property if V is VN-verbal. VN-verbal subgroups have the following 3 properties: P-property: F/V satisfies a positive law, (A. Maltsev) (F/V )′ is finitely generated, (S. Rosset)

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VN-property

We say that V has VN-property if V is VN-verbal. VN-verbal subgroups have the following 3 properties: P-property: F/V satisfies a positive law, (A. Maltsev) R-property: (F/V )′ is finitely generated, (S. Rosset)

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VN-property

We say that V has VN-property if V is VN-verbal. VN-verbal subgroups have the following 3 properties: P-property: F/V satisfies a positive law, (A. Maltsev) R-property: (F/V )′ is finitely generated, (S. Rosset) V F ′′(F ′)p for all prime p. (A. Maltsev)

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VN-property

We say that V has VN-property if V is VN-verbal. VN-verbal subgroups have the following 3 properties: P-property: F/V satisfies a positive law, (A. Maltsev) R-property: (F/V )′ is finitely generated, (S. Rosset) M-property: V F ′′(F ′)p for all prime p. (A. Maltsev)

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VN-property

We say that V has VN-property if V is VN-verbal. VN-verbal subgroups have the following 3 properties: P-property: F/V satisfies a positive law, (A. Maltsev) R-property: (F/V )′ is finitely generated, (S. Rosset) M-property: V F ′′(F ′)p for all prime p. (A. Maltsev) The last is equivalent to var(F/V ) ApA for all prime p.

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VN-property

We say that V has VN-property if V is VN-verbal. VN-verbal subgroups have the following 3 properties: P-property: F/V satisfies a positive law, (A. Maltsev) R-property: (F/V )′ is finitely generated, (S. Rosset) M-property: V F ′′(F ′)p for all prime p. (A. Maltsev) The last is equivalent to var(F/V ) ApA for all prime p. We introduce the following subsets of verbal subgroups in F:

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VN-property

We say that V has VN-property if V is VN-verbal. VN-verbal subgroups have the following 3 properties: P-property: F/V satisfies a positive law, (A. Maltsev) R-property: (F/V )′ is finitely generated, (S. Rosset) M-property: V F ′′(F ′)p for all prime p. (A. Maltsev) The last is equivalent to var(F/V ) ApA for all prime p. We introduce the following subsets of verbal subgroups in F:

  • VN−verbal
  • ⊆ {P−verbal} ⊆
  • R−verbal
  • M−verbal
  • .
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VN-property

We say that V has VN-property if V is VN-verbal. VN-verbal subgroups have the following 3 properties: P-property: F/V satisfies a positive law, (A. Maltsev) R-property: (F/V )′ is finitely generated, (S. Rosset) M-property: V F ′′(F ′)p for all prime p. (A. Maltsev) The last is equivalent to var(F/V ) ApA for all prime p. We introduce the following subsets of verbal subgroups in F:

  • VN−verbal
  • ⊆ {P−verbal} ⊆
  • R−verbal
  • M−verbal
  • .
  • VN−varieties
  • ⊆{P−varieties}⊆
  • R−varieties
  • M−varieties
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VN-property

We say that V has VN-property if V is VN-verbal. VN-verbal subgroups have the following 3 properties: P-property: F/V satisfies a positive law, (A. Maltsev) R-property: (F/V )′ is finitely generated, (S. Rosset) M-property: V F ′′(F ′)p for all prime p. (A. Maltsev) The last is equivalent to var(F/V ) ApA for all prime p. We introduce the following subsets of verbal subgroups in F:

  • VN−verbal
  • ⊆ {P−verbal} ⊆
  • R−verbal
  • M−verbal
  • .
  • VN−varieties
  • ⊆{P−varieties}⊆
  • R−varieties
  • M−varieties
  • VN−laws

{P−laws} ⊆

  • R−laws
  • M−laws
  • .
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P-verbal subgroups

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P-verbal subgroups

V is P-verbal iff F/V satisfies a binary balanced positive law u(x, y) ≡ v(x, y).

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P-verbal subgroups

V is P-verbal iff F/V satisfies a binary balanced positive law u(x, y) ≡ v(x, y). V is P-verbal iff V ∩ FF−1 = 1.

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P-verbal subgroups

V is P-verbal iff F/V satisfies a binary balanced positive law u(x, y) ≡ v(x, y). V is P-verbal iff V ∩ FF−1 = 1. By A. Maltsev, VN-verbal subgroup is P-verbal.

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P-verbal subgroups

V is P-verbal iff F/V satisfies a binary balanced positive law u(x, y) ≡ v(x, y). V is P-verbal iff V ∩ FF−1 = 1. By A. Maltsev, VN-verbal subgroup is P-verbal.

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P-verbal subgroups

V is P-verbal iff F/V satisfies a binary balanced positive law u(x, y) ≡ v(x, y). V is P-verbal iff V ∩ FF−1 = 1. By A. Maltsev, VN-verbal subgroup is P-verbal. The inclusion is proper: there are infinite Burnside groups and examples by A. Yu. Ol’shanskii and A. Storozhev.

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Theorem The set of P-verbal subgroups forms a sublattice in the lattice of all subgroups in F.

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Theorem The set of P-verbal subgroups forms a sublattice in the lattice of all subgroups in F. Proof

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Theorem The set of P-verbal subgroups forms a sublattice in the lattice of all subgroups in F. Proof Let V1 and V2 be the P-verbal subgroups, providing positive laws a(x, y) ≡ b(x, y) and u(x, y) ≡ v(x, y).

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Theorem The set of P-verbal subgroups forms a sublattice in the lattice of all subgroups in F. Proof Let V1 and V2 be the P-verbal subgroups, providing positive laws a(x, y) ≡ b(x, y) and u(x, y) ≡ v(x, y). We can assume that the law a(x, y) ≡ b(x, y) is balanced.

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Theorem The set of P-verbal subgroups forms a sublattice in the lattice of all subgroups in F. Proof Let V1 and V2 be the P-verbal subgroups, providing positive laws a(x, y) ≡ b(x, y) and u(x, y) ≡ v(x, y). We can assume that the law a(x, y) ≡ b(x, y) is balanced. The join V1V2 provides each of these laws.

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Theorem The set of P-verbal subgroups forms a sublattice in the lattice of all subgroups in F. Proof Let V1 and V2 be the P-verbal subgroups, providing positive laws a(x, y) ≡ b(x, y) and u(x, y) ≡ v(x, y). We can assume that the law a(x, y) ≡ b(x, y) is balanced. The join V1V2 provides each of these laws. The intersection V1 ∩ V2 provides the positive law

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Theorem The set of P-verbal subgroups forms a sublattice in the lattice of all subgroups in F. Proof Let V1 and V2 be the P-verbal subgroups, providing positive laws a(x, y) ≡ b(x, y) and u(x, y) ≡ v(x, y). We can assume that the law a(x, y) ≡ b(x, y) is balanced. The join V1V2 provides each of these laws. The intersection V1 ∩ V2 provides the positive law a (u(x, y), v(x, y)) ≡ b (u(x, y), v(x, y)) ,

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Theorem The set of P-verbal subgroups forms a sublattice in the lattice of all subgroups in F. Proof Let V1 and V2 be the P-verbal subgroups, providing positive laws a(x, y) ≡ b(x, y) and u(x, y) ≡ v(x, y). We can assume that the law a(x, y) ≡ b(x, y) is balanced. The join V1V2 provides each of these laws. The intersection V1 ∩ V2 provides the positive law a (u(x, y), v(x, y)) ≡ b (u(x, y), v(x, y)) , because modV2 it has is a(u, u) ≡ b(u, u) and hence uk ≡ uk.

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R-verbal subgroups

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R-property of V says that (F/V )′ is finitely generated (for n < ∞)

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R-property of V says that (F/V )′ is finitely generated (for n < ∞)

Criterion for R-verbal subgroups

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R-property of V says that (F/V )′ is finitely generated (for n < ∞)

Criterion for R-verbal subgroups

Theorem ( R-law) V is R-verbal iff ∃m ∈ N, such that F/V satisfies a law [x, my] ≡ u(x, y),

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R-property of V says that (F/V )′ is finitely generated (for n < ∞)

Criterion for R-verbal subgroups

Theorem ( R-law) V is R-verbal iff ∃m ∈ N, such that F/V satisfies a law [x, my] ≡ u(x, y), u(x, y) ∈ x, [x, y], [x, 2y], ...[x, m−1y] . Proof is long.

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[x, my] ≡ u(x, y), u(x, y) ∈ x, [x, y], [x, 2y], ...[x, m−1y] .

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[x, my] ≡ u(x, y), u(x, y) ∈ x, [x, y], [x, 2y], ...[x, m−1y] .

By means of the above criterion we can prove:

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[x, my] ≡ u(x, y), u(x, y) ∈ x, [x, y], [x, 2y], ...[x, m−1y] .

By means of the above criterion we can prove: Theorem The set of R-verbal subgroups forms a sublattice in the lattice of all subgroups in F.

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[x, my] ≡ u(x, y), u(x, y) ∈ x, [x, y], [x, 2y], ...[x, m−1y] .

By means of the above criterion we can prove: Theorem The set of R-verbal subgroups forms a sublattice in the lattice of all subgroups in F. Proof is long.

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V is R-verbal if (F/V )′ is finitely generated (for n < ∞)

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V is R-verbal if (F/V )′ is finitely generated (for n < ∞)

By S.Rosset, P-verbal subgroups are R-verbal.

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V is R-verbal if (F/V )′ is finitely generated (for n < ∞)

By S.Rosset, P-verbal subgroups are R-verbal.

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V is R-verbal if (F/V )′ is finitely generated (for n < ∞)

By S.Rosset, P-verbal subgroups are R-verbal. Note that n-Engel laws define R-verbal subgroups.

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V is R-verbal if (F/V )′ is finitely generated (for n < ∞)

By S.Rosset, P-verbal subgroups are R-verbal. Note that n-Engel laws define R-verbal subgroups. Will the n-Engel laws prove that the inclusion is proper?

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M-verbal subgroups

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V is M-verbal if ∀p, V F ′′(F ′)p i.e. var(F/V ) ApA.

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V is M-verbal if ∀p, V F ′′(F ′)p i.e. var(F/V ) ApA.

M-verbal subgroups

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V is M-verbal if ∀p, V F ′′(F ′)p i.e. var(F/V ) ApA.

M-verbal subgroups

V is called M-verbal because a law which is not satisfied in any of ApA is called Milnoridentity (F.Point 1996).

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V is M-verbal if ∀p, V F ′′(F ′)p i.e. var(F/V ) ApA.

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V is M-verbal if ∀p, V F ′′(F ′)p i.e. var(F/V ) ApA.

Theorem A verbal subgroup V is M-verbal if and only if

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V is M-verbal if ∀p, V F ′′(F ′)p i.e. var(F/V ) ApA.

Theorem A verbal subgroup V is M-verbal if and only if (∗) VF ′′ ∩ FF−1 = 1.

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V is M-verbal if ∀p, V F ′′(F ′)p i.e. var(F/V ) ApA.

Theorem A verbal subgroup V is M-verbal if and only if (∗) VF ′′ ∩ FF−1 = 1. Proof If V ⊆ F ′′(F ′)p, then V F ′′ ⊆ F ′′(F ′)p and by (*)

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V is M-verbal if ∀p, V F ′′(F ′)p i.e. var(F/V ) ApA.

Theorem A verbal subgroup V is M-verbal if and only if (∗) VF ′′ ∩ FF−1 = 1. Proof If V ⊆ F ′′(F ′)p, then V F ′′ ⊆ F ′′(F ′)p and by (*) F ′′(F ′)p ∩ FF−1 = 1. The contradiction.

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V is M-verbal if ∀p, V F ′′(F ′)p i.e. var(F/V ) ApA.

Theorem A verbal subgroup V is M-verbal if and only if (∗) VF ′′ ∩ FF−1 = 1. Proof If V ⊆ F ′′(F ′)p, then V F ′′ ⊆ F ′′(F ′)p and by (*) F ′′(F ′)p ∩ FF−1 = 1. The contradiction. Conversely, if V F ′′(F ′)p, then VF ′′ F ′′(F ′)p,

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V is M-verbal if ∀p, V F ′′(F ′)p i.e. var(F/V ) ApA.

Theorem A verbal subgroup V is M-verbal if and only if (∗) VF ′′ ∩ FF−1 = 1. Proof If V ⊆ F ′′(F ′)p, then V F ′′ ⊆ F ′′(F ′)p and by (*) F ′′(F ′)p ∩ FF−1 = 1. The contradiction. Conversely, if V F ′′(F ′)p, then VF ′′ F ′′(F ′)p, Then var(F/VF ′′) ApA, and

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V is M-verbal if ∀p, V F ′′(F ′)p i.e. var(F/V ) ApA.

Theorem A verbal subgroup V is M-verbal if and only if (∗) VF ′′ ∩ FF−1 = 1. Proof If V ⊆ F ′′(F ′)p, then V F ′′ ⊆ F ′′(F ′)p and by (*) F ′′(F ′)p ∩ FF−1 = 1. The contradiction. Conversely, if V F ′′(F ′)p, then VF ′′ F ′′(F ′)p, Then var(F/VF ′′) ApA, and by result of J. Groves F/VF ′′ is virtually nilpotent.

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V is M-verbal if ∀p, V F ′′(F ′)p i.e. var(F/V ) ApA.

Theorem A verbal subgroup V is M-verbal if and only if (∗) VF ′′ ∩ FF−1 = 1. Proof If V ⊆ F ′′(F ′)p, then V F ′′ ⊆ F ′′(F ′)p and by (*) F ′′(F ′)p ∩ FF−1 = 1. The contradiction. Conversely, if V F ′′(F ′)p, then VF ′′ F ′′(F ′)p, Then var(F/VF ′′) ApA, and by result of J. Groves F/VF ′′ is virtually nilpotent. Hence F/VF ′′ satisfies a positive law, which implies (*).

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V is M-verbal if ∀p, V F ′′(F ′)p i.e. var(F/V ) ApA.

By means of the criterion VF ′′ ∩ FF−1 = 1 we can prove:

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V is M-verbal if ∀p, V F ′′(F ′)p i.e. var(F/V ) ApA.

By means of the criterion VF ′′ ∩ FF−1 = 1 we can prove: Theorem The set of M-verbal subgroups forms a sublattice in the lattice of all subgroups in F.

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V is M-verbal if ∀p, V F ′′(F ′)p i.e. var(F/V ) ApA.

By means of the criterion VF ′′ ∩ FF−1 = 1 we can prove: Theorem The set of M-verbal subgroups forms a sublattice in the lattice of all subgroups in F. Proof is long.

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V is M-verbal if ∀p, V F ′′(F ′)p i.e. var(F/V ) ApA.

Since (F/F ′′(F ′)p)′ is infinitely generated, it does not satisfy an R-law.

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V is M-verbal if ∀p, V F ′′(F ′)p i.e. var(F/V ) ApA.

Since (F/F ′′(F ′)p)′ is infinitely generated, it does not satisfy an R-law. So, if V is R-verbal then V F ′′(F ′)p, Hence R-verbal subgroups are M-verbal.

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V is M-verbal if ∀p, V F ′′(F ′)p i.e. var(F/V ) ApA.

Since (F/F ′′(F ′)p)′ is infinitely generated, it does not satisfy an R-law. So, if V is R-verbal then V F ′′(F ′)p, Hence R-verbal subgroups are M-verbal.

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V is M-verbal if ∀p, V F ′′(F ′)p i.e. var(F/V ) ApA.

Since (F/F ′′(F ′)p)′ is infinitely generated, it does not satisfy an R-law. So, if V is R-verbal then V F ′′(F ′)p, Hence R-verbal subgroups are M-verbal. We know that M-verbal subgroup need not be P-verbal.

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V is M-verbal if ∀p, V F ′′(F ′)p i.e. var(F/V ) ApA.

Since (F/F ′′(F ′)p)′ is infinitely generated, it does not satisfy an R-law. So, if V is R-verbal then V F ′′(F ′)p, Hence R-verbal subgroups are M-verbal. We know that M-verbal subgroup need not be P-verbal. Questions What are R-verbal subgroups which are not P-verbal.

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V is M-verbal if ∀p, V F ′′(F ′)p i.e. var(F/V ) ApA.

Since (F/F ′′(F ′)p)′ is infinitely generated, it does not satisfy an R-law. So, if V is R-verbal then V F ′′(F ′)p, Hence R-verbal subgroups are M-verbal. We know that M-verbal subgroup need not be P-verbal. Questions What are R-verbal subgroups which are not P-verbal. What are M-verbal subgroups which are not R-verbal.

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THANK YOU FOR ATTENTION

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