A Rumpke Public Outreach Program
F I R E L O G I S T I C S A N D M AT H E D U C AT I O N
F I R E L O G I S T I C S A N D M AT H E D U C AT I O N A Rumpke - - PowerPoint PPT Presentation
F I R E L O G I S T I C S A N D M AT H E D U C AT I O N A Rumpke Public Outreach Program Welcome Welcome & & I ntroductions I ntroductions I dentify emergency exits I dentify emergency exits to all participants. to all
A Rumpke Public Outreach Program
F I R E L O G I S T I C S A N D M AT H E D U C AT I O N
I dentify emergency exits I dentify emergency exits to all participants. to all participants. I dentify location of I dentify location of restroom facilities. restroom facilities. Cover any other Cover any other related site information. related site information.
What will we accomplish today! What will we accomplish today!
What we do in the Fire Service! What we do in the Fire Service!
Why Numbers?
– How much water we need. – The amount of water we are flowing. – The truck pressure required to meet our flow requirements. – The time we have flowed water and the total gallons used. – How to adjust for elevation, plus or minus.
types:
– Smooth bore – straight stream, no adjustment or settings. – Variable stream – choice of straight stream
type based on fire location and size.
– Not enough pressure can prevent an effective fire attack or get the firefighters burned. – Too much pressure can injure the firefighters from excessive nozzle force.
at the nozzle.
equals success:
– Applying the correct numbers into the formulas predicts a successful and manageable nozzle pressure. – This allows the firefighters to move the hose line in a building to successfully attack and extinguish the fire.
Elevation Pressure Gain & Loss Elevation Pressure Gain & Loss
Pressure Loss: Aerial Piped Pressure Loss: Aerial Piped Waterway Waterway
Pump Discharge Pressure: Pump Discharge Pressure: Fog Nozzle Fog Nozzle
Pressure Loss: Four Hoselines Pressure Loss: Four Hoselines (Unequal Lengths) (Unequal Lengths)
Common Hose Sizes Common Hose Sizes
Common Common Nozzle
Nozzle Diameters
Diameters
Friction Loss Coefficient Friction Loss Coefficient Single Hoselines Single Hoselines
Variables for Calculating Variables for Calculating Total Pressure Loss Total Pressure Loss
Volume of water flowing per minute;
Length & diameter of the hoseline;
Any major appliances attached to hoseline; hoseline;
Pressure loss or gain created by elevation; elevation;
Appliance Pressure Loss Appliance Pressure Loss
0 psi friction loss for flows less than 350 gpm; than 350 gpm;
10 psi friction loss for flows greater than 350 gpm; greater than 350 gpm;
25 psi friction loss in all master stream appliances. stream appliances.
Types of Appliances
Student Activity 1 Student Activity 1
FL = CQ FL = CQ2
2 L
L
Where: Where:
FL = Friction loss in psi FL = Friction loss in psi C = Friction loss coefficient C = Friction loss coefficient Q = Flow rate in hundreds of Q = Flow rate in hundreds of gpm gpm (Flow (Flow ÷ ÷ 100) 100) L = Hose length in hundreds of L = Hose length in hundreds of feet (Length feet (Length÷ ÷ 100) 100)
1.
I f 150 gpm is flowing from a nozzle, what is the a nozzle, what is the friction loss for 200 feet of friction loss for 200 feet of 2 2-
inch hose?
Please write your answer on the Please write your answer on the student worksheet as we student worksheet as we work through the problem. work through the problem.
Problem 1 Problem 1
FL = CQ FL = CQ2
2L
L (Q= 150 (Q= 150÷ ÷ 100) (L= 200 100) (L= 200÷ ÷ 100) 100) FL = 8 FL = 8 × × 1.5 1.5 2
2 ×
× 2 2 FL = 8 FL = 8 × × 2.25 2.25 × × 2 2 FL = 18 FL = 18 × × 2 2 FL = 36 psi FL = 36 psi
2.
I f 400 gpm is flowing from a nozzle, what is the from a nozzle, what is the friction loss for 300 feet friction loss for 300 feet
inch hose?
Please write your answer Please write your answer
as we work through the as we work through the problem. problem.
Problem 2 Problem 2
FL = CQ FL = CQ2
2L
L (Q= 400 (Q= 400÷ ÷ 100) (L= 300 100) (L= 300÷ ÷ 100) 100) FL = 0.2 FL = 0.2 × × 4 4 2
2 ×
× 3 3 FL = 0.2 FL = 0.2 × × 16 16 × × 3 3 FL = 3.2 FL = 3.2 × × 3 3 FL = 9.6 or 10 psi FL = 9.6 or 10 psi
3.
I f 200 gpm is flowing from a nozzle, what is the a nozzle, what is the friction loss for 150 feet of friction loss for 150 feet of 2 2-
inch hose?
Please write your answer on the Please write your answer on the student worksheet as we work student worksheet as we work through the problem. through the problem.
Problem 3 Problem 3
FL = CQ FL = CQ2
2L
L (Q= 200 (Q= 200÷ ÷ 100) (L= 150 100) (L= 150÷ ÷ 100) 100) FL = 8 FL = 8 × × 2 2 2
2 ×
× 1.5 1.5 FL = 8 FL = 8 × × 4 4 × × 1.5 1.5 FL = 32 FL = 32 × × 1.5 1.5 FL = 48 psi FL = 48 psi
Student Activity 2 Student Activity 2
EP = 0.5 EP = 0.5 × × H H
Where: Where: EP = Elevation Pressure in psi EP = Elevation Pressure in psi 0.5 = A constant 0.5 = A constant H = Height in feet H = Height in feet
EP = 5 EP = 5 × × (No. Stories (No. Stories – – 1) 1)
Where: Where: Pressure in psi EP = Elevation Pressure in psi EP = Elevation 5 = A constant 5 = A constant
12 12 th
th floor of a structure fire is
floor of a structure fire is connected to the building connected to the building’ ’s s standpipe system. standpipe system. What is the elevation pressure What is the elevation pressure at the base of the standpipe at the base of the standpipe system? system? Please write your answer on the student Please write your answer on the student worksheet as we work through the worksheet as we work through the problem. problem.
Problem 4 Problem 4
EP = 5 EP = 5 × × (No. Stories (No. Stories – – 1) 1) EP = 5 EP = 5 × × 11 11 EP = 55 EP = 55
5.
What would be the elevation pressure loss at the pump pressure loss at the pump for a pumper at the bottom for a pumper at the bottom
foot hill supplying a hoseline at the top of the hoseline at the top of the hill? hill? Please write your answer on the student Please write your answer on the student worksheet as we work through the worksheet as we work through the problem. problem.
Problem 5 Problem 5
EP = 0.5 EP = 0.5 × × H H EP = 0.5H EP = 0.5H EP = 0.5 EP = 0.5 × × 250 250 EP = 125 EP = 125
6. 6. What would be the What would be the elevation pressure gain at elevation pressure gain at the pump for a pumper the pump for a pumper atop of a 150 atop of a 150-
foot hill supplying a hoseline at supplying a hoseline at the base of the hill? the base of the hill? Please write your answer on the student Please write your answer on the student worksheet as we work through the worksheet as we work through the problem. problem.
Problem 6 Problem 6
EP = 0.5 EP = 0.5 × × H H EP = 0.5H EP = 0.5H EP = 0.5 EP = 0.5 × × 150 150 EP = 75 EP = 75
Calculating Total Pressure Calculating Total Pressure Loss in Single Hoseline Loss in Single Hoseline Layouts Layouts
Student Activity 3 Student Activity 3
TPL = FL TPL = FL ± ± EP EP
Where: Where: FL = Friction loss FL = Friction loss ± ± = Add (+ ) or Subtract ( = Add (+ ) or Subtract ( – –) ) EP = Elevation pressure in psi EP = Elevation pressure in psi
FL = CQ FL = CQ2
2L
L EP = 5 EP = 5 × × (No. Stories (No. Stories – – 1) 1) EP = 0.5H EP = 0.5H
7.
A pumper is supplying 150-
feet of 1¾ ¾ -
inch hose with 150 gpm flowing. What is 150 gpm flowing. What is the total pressure loss in the the total pressure loss in the hose assembly? hose assembly? Please write your answer on the student Please write your answer on the student worksheet as we work through the worksheet as we work through the problem. problem.
Problem 7 Problem 7
TPL = FL TPL = FL ± ± EP EP TPL = 52.3 TPL = 52.3 ± ± 0 FL = 52.3 = 15.5 FL = 52.3 = 15.5 × × 1.5 1.5 2
2 ×
× 1.5 1.5 TPL = 52.3 or 52 TPL = 52.3 or 52
8.
Using the information from Problem 7, what is the total Problem 7, what is the total pressure loss if the fire pressure loss if the fire situation is located on the situation is located on the 4th floor of a building? 4th floor of a building? Please write your answer on the student Please write your answer on the student worksheet as we work through the worksheet as we work through the problem. problem.
Problem 8 Problem 8
TPL = FL TPL = FL ± ± EP EP TPL = 52.3 TPL = 52.3 ± ± 15 15 FL = 52.3 = 15.5 FL = 52.3 = 15.5 × × 1.5 1.5 2
2 ×
× 1.5 1.5 EP = 15 = 5 x 3 EP = 15 = 5 x 3 TPL = 67.3 or 67 TPL = 67.3 or 67
We We’ ’re ready to apply the math to move some re ready to apply the math to move some water! water!
A Rumpke Public Outreach Program
F I R E L O G I S T I C S A N D M AT H E D U C AT I O N
Closing Comments
I hope this course was: I hope this course was: I nteresting I nteresting Challenging Challenging Fun; and Fun; and Applied math in a different and helpful Applied math in a different and helpful perspective! perspective!
A Rumpke Public Outreach Program
F I R E L O G I S T I C S A N D M AT H E D U C AT I O N