EP 228: Quantum Mechanics Lec 30: Addition of angular momentum - - PowerPoint PPT Presentation

ep 228 quantum mechanics lec 30 addition of angular
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EP 228: Quantum Mechanics Lec 30: Addition of angular momentum - - PowerPoint PPT Presentation

EP 228: Quantum Mechanics Lec 30: Addition of angular momentum Spin particle Direct product space spanned by position ket |x> and two-dimensional spin space given by |m s > Rotation operator in such a space is U R ( )


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SLIDE 1

EP 228: Quantum Mechanics Lec 30: Addition of angular momentum

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SLIDE 2

Spin ½ particle

  • Direct product space spanned by position

ket |x> and two-dimensional spin space given by |ms>

  • Rotation operator in such a space is UR(θ)
  • Here J is sum of orbital and spin
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SLIDE 3

Direct product space

  • Ang. Mom:
  • Note: [J2 , L2 ] = [J2 , S2 ] =[J2, Jz] = 0
  • Two equivalent basis for the direct product

space:

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SLIDE 4

Direct product state of two spin ½ particles

  • Ang. Mom:
  • Note: [J2 , S1

2 ] = [J2 , S2 2 ] =[J2, Jz] = 0

  • Two equivalent basis for the direct product

space:

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SLIDE 5

Angular momentum basis

  • System of two particles with angular

momentum J1 and J2 where

  • uncoupled basis states are
  • Equivalent basis : coupled basis states

involving total angular momentum

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SLIDE 6

Change of basis

  • The dimensionality of both basis are equal :

(2j1 +1) (2j2+1)

  • The matrix relating them called Clebsch-Gordan matrix
  • The matrix elements are called Clebsch-Gordan (CG)

coefficients

  • CG coeffts is non-zero when m= m1 + m2
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SLIDE 7

CG coeffts

  • Maximum value for mmax is j1 + j2
  • For this max m, jmax = j1 + j2
  • We put CG coefft for the such a state as 1
  • Consider
  • We can obtain this in two ways(degeneracy=2)
  • The above m value suggest two possible values

for j : (j1 + j2 ) , (j1 + j2 -1). Proceeding this way, we can determine m values such that mmin = -j1 - j2