Dyons and KvBLL Instantons in QCD Tin Sulejmanpa si c Work done - - PowerPoint PPT Presentation

dyons and kvbll instantons in qcd
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Dyons and KvBLL Instantons in QCD Tin Sulejmanpa si c Work done - - PowerPoint PPT Presentation

Dyons and KvBLL Instantons in QCD Tin Sulejmanpa si c Work done with E. Shuryak, F. Bruckmann and R. R odle December 12, 2012 1 / 45 Outline Instantons from dyons The fermionic zero modes The fundamental zero modes The adjoint zero


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SLIDE 1

Dyons and KvBLL Instantons in QCD

Tin Sulejmanpaˇ si´ c

Work done with E. Shuryak, F. Bruckmann and R. R¨

  • dle

December 12, 2012

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SLIDE 2

Outline

Instantons from dyons The fermionic zero modes The fundamental zero modes The adjoint zero modes The caloron zero modes at finite chemical potential Interactions of dyons Classical interactions One loop effects (Debye screening) The Fermionic zeromode Interactions Chiral symmetry breaking via dyons Some lattice observations How topology breaks chiral symmetry The three models Shift of critical coupling as a function of Nf Some comments on confinement Conclusion and outlook

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SLIDE 3

KvBLL instantons

◮ Classical self-dual solutions of Yang-Mills eq. at finite

temperature

◮ Generalizations of instantons with an additional parameter –

holonomy exp(i

  • A0dτ)

◮ When holonomy is “non-trivial”, they disassociate into static

  • bjects called dyons

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SLIDE 4

KvBLL instantons

◮ Classical self-dual solutions of Yang-Mills eq. at finite

temperature

◮ Generalizations of instantons with an additional parameter –

holonomy exp(i

  • A0dτ)

◮ When holonomy is “non-trivial”, they disassociate into static

  • bjects called dyons

A0(r → ∞) = v τ·ˆ

ω 2

– Acts like a an adjoint higgs field F 2

µν = (DiA0)2 + F 2 ij (Assuming time independent fields)

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SLIDE 5

The dyon

In the usual radial ansatz it looks as Aa

0 = H(r)ˆ

ra (1) Aa

i = A(r)ǫaij ˆ

rj (2) Imposing selfduality Fµν = 1 2ǫµνρσFρσ with boundary condition A(r → ∞) = 0 , H(r → ∞) = v One can see that functions H = −1 − vr coth(vr) r (3) A = 1 r − v sinh(vr) (4) satisfy the self duality equations, such that

  • d3x F 2 = 4πv

which gives a fractional topological charge Q = vβ

2π .

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SLIDE 6

A(r) H(r)

20 10 10 20 0.0 0.2 0.4 0.6 0.8 rv

Aa

0 = H(r)ˆ

ra Aa

i = A(r)ǫaij ˆ

rj

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SLIDE 7

The dyon

The fields look like Ei = ˆ ri r2 ˆ r · τ 2 + o(e−rv) , (5) Bi = Ei (6) Changing the gauge so that τ · ˆ r → τ 3 (which is not unique) reveals the abelian nature of the solutions, for example Ar = 0 , Aθ = o(e−vr) A0 = (v − 1 r )τ 3 2 + o(e−vr) Aϕ = tan θ

2

r τ 3 2 + o(e−vr) In this form the Dirac monopole field is evident, with the Dirac string along θ = π direction.

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SLIDE 8

The second dyon

Take v → 2πT − v and using the time dependent gauge transform U(t) = e−itπτ 3/β we get a new solution with same asymptotics A0 ∼ (v + 1/r)τ3 2 but opposite charge of magnetic and electric fields, i.e. Ei = − ˆ ri r2 τ3 2 , Bi = Ei . This configuration, however, has and action

  • F 2 = 4π(2π − vβ)

topological charge ¯ Q = 1 − vβ/(2π), so that Q + ¯ Q = 1

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SLIDE 9

The approximate higgs potential

H(r1,r2)

30 20 10 10 20 30 1 2 3 4 5 6 8 / 45

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SLIDE 10

What can we conclude?

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SLIDE 11

What can we conclude?

◮ There are two solutions which have A0 → vτ 3.

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SLIDE 12

What can we conclude?

◮ There are two solutions which have A0 → vτ 3. ◮ Their individual topological charges are Q = vβ/(2π) and

¯ Q = 1 − vβ/(2π), where v ∈ [0, πT] is an angular variable.

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SLIDE 13

What can we conclude?

◮ There are two solutions which have A0 → vτ 3. ◮ Their individual topological charges are Q = vβ/(2π) and

¯ Q = 1 − vβ/(2π), where v ∈ [0, πT] is an angular variable.

◮ The total topological charge of two objects is unity

Q + ¯ Q = 1.

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SLIDE 14

What can we conclude?

◮ There are two solutions which have A0 → vτ 3. ◮ Their individual topological charges are Q = vβ/(2π) and

¯ Q = 1 − vβ/(2π), where v ∈ [0, πT] is an angular variable.

◮ The total topological charge of two objects is unity

Q + ¯ Q = 1.

◮ These are, in fact, two parts of the same object!

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SLIDE 15

What can we conclude?

◮ There are two solutions which have A0 → vτ 3. ◮ Their individual topological charges are Q = vβ/(2π) and

¯ Q = 1 − vβ/(2π), where v ∈ [0, πT] is an angular variable.

◮ The total topological charge of two objects is unity

Q + ¯ Q = 1.

◮ These are, in fact, two parts of the same object! ◮ At v = 0 the “heavy”’ dyon, with topological charge ¯

Q reduces to Harrington-Shepard caloron of infinite size (know to be a monopole)

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SLIDE 16

What can we conclude?

◮ There are two solutions which have A0 → vτ 3. ◮ Their individual topological charges are Q = vβ/(2π) and

¯ Q = 1 − vβ/(2π), where v ∈ [0, πT] is an angular variable.

◮ The total topological charge of two objects is unity

Q + ¯ Q = 1.

◮ These are, in fact, two parts of the same object! ◮ At v = 0 the “heavy”’ dyon, with topological charge ¯

Q reduces to Harrington-Shepard caloron of infinite size (know to be a monopole)

◮ Instanton has constituents! And their “masses” (action)

depend on the holonomy parameter v.

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SLIDE 17

What can we conclude?

◮ There are two solutions which have A0 → vτ 3. ◮ Their individual topological charges are Q = vβ/(2π) and

¯ Q = 1 − vβ/(2π), where v ∈ [0, πT] is an angular variable.

◮ The total topological charge of two objects is unity

Q + ¯ Q = 1.

◮ These are, in fact, two parts of the same object! ◮ At v = 0 the “heavy”’ dyon, with topological charge ¯

Q reduces to Harrington-Shepard caloron of infinite size (know to be a monopole)

◮ Instanton has constituents! And their “masses” (action)

depend on the holonomy parameter v.

◮ Indeed Kraan and van Baal found this solution!

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SLIDE 18

The exact KvBLL Caloron

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SLIDE 19

The exact KvBLL Caloron

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SLIDE 20

The exact KvBLL Caloron

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SLIDE 21

The exact KvBLL Caloron

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SLIDE 22

The exact KvBLL Caloron

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SLIDE 23

The exact KvBLL Caloron

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SLIDE 24

The exact KvBLL Caloron

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SLIDE 25

The fermionic zero modes

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SLIDE 26

Fermionic zero modes

Now we look for the solution of Dirac equation in the background

  • f a single dyon. The result is well known from the 70s for 3D
  • theory. Writing the equation for a chiral fermion

ψα

A(r) = [(α1(r)1 + α2(r)ˆ

r · τ) ǫ]Aα e−iϕt/β , we obtain for the Dirac equation dα1(r) dr + H + 2A 2 α1 + ϕTα2 = 0 , (7) dα2(r) dr + H − 2A 2 + 2 r

  • α2 + ϕTα1 = 0 .

(8) with φ = 0 (periodic fermions for now) we can get that / Dψ = 0 results in α1(r) = const tanh(vr/2)

  • vr sinh(vr)

∼ e−vr/2 , α2(r) = 0 . But we can do better! In fact one can solve the Dirac equation with general φ.

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The solution turns out to be (Shuryak, Sulejmanpasic - Phys. Rev. D86 036001) α1,2(r, ϕ) = c χ1,2(vr)

  • vr sinh(vr)

(9a) χ1(rv) =

  • 2 ϕ

v sinh(rϕ/β) − tanh(vr/2) cosh(rϕ/β)

  • ,

(9b) χ2(rv) =

  • − 2 ϕ

v cosh(rϕ/β) + coth(vr/2) sinh(rϕ/β)

  • ,

(9c)

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SLIDE 28

5 10 15 20 r 0.4 0.2 0.2 0.4 0.6 0.8 1.0 Α1r solid, Α2r dashed

Functions α1 (solid) and α2 (dashed) for ϕ = 0 (black) to ϕ = 0.55v/β

When ϕ ≥ vβ/2 the solution

  • diverges. But since v ∈ [0, πT],

what happens to antieriodic fermions? The answer lies in the second dyon! Recall that the second dyon differs from the first by a time dependent gauge transform (in stringy gauge) exp(iπtTτ 3) Therefore the solution has to be multiplied by an anti periodic gauge transformation! This means that the solution for anti periodic fermions has the same profiles, but with v → ¯ v

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SLIDE 29

The adjoint zero modes

The Dirac equation: α′

1 + 2

r α1 − 2 v sinh(vr)β1 = ϕ β α2 , α′

2 + 2

v sinh(vr)β2 = ϕ β α1 , β′

1 −

v sinh(vr)α1 + v coth(vr)β1 = ϕ β β2 , β2 + v sinh(vr)α2 + v coth(vr)β2 = ϕ β β1 .

2 4 6 8 10 12 14 0.5 0.0 0.5 1.0

ϕ = (0, 0.2, 0.4, 0.6, 0.8, 0.9, 0.95)vβ

ψm = ˆ rmα2(r)−i(ˆ r × σ)mβ2(r)+α1(r)ˆ rm( σ · ˆ r)+((ˆ r × σ)× ˆ r)β1(r) and Ψa = ψaεeiϕt/β ε - arbitrary 2-spinor

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The adjoint zero modes

The leading order ΨM ∼ e−(v−ϕ/β)r Similarly we can construct a zero mode on top of the “heavy” dyon ΨL ∼ e−(¯

v−ϕ/β)r .

¯ v = 2π − v However there are also solutions with ϕ → ϕ − 2π ˜ ΨM ∼ e−(ϕ/β−¯

v)r

˜ ΨL ∼ e−(ϕ/β−v)r .

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The adjoint hopping

v v

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SLIDE 32

The adjoint hopping

v v

Each dyon has a zeromode

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SLIDE 33

The adjoint hopping

v v

L (heavy) dyon has a zeromode

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SLIDE 34

The adjoint hopping

v v

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SLIDE 35

Zeromodes at finite µ (with Bruckmann and R¨

  • dl)

One needs to solve ( / D + µγ0)ψ = 0 This is the same as solving the Dirac equation with Ψ = ψeµt, so µ = iϕ/β. However, since the

  • perator does not have any

Hermiticity property, it turns out that one needs to redefine the bra vector and use ψ†(−µ) instead of ψ†(µ).

1 2 3 4 0.0 0.2 0.4 0.6 0.8 rv Ψ0ΜΨ0ΜTv3

The full solution for the caloron is complicated, but will be published soon!

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SLIDE 36

Interactions of dyons

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SLIDE 37

Classical interactions

Partition function is schematically Z ∼ e− Si−

i=j Sij

where

◮ Si is the action of individual dyons or antidyons ◮ Sij is the interaction between pairs of dyons

The self dual dyons are in fact BPS states, i.e. they do not interact classically. However dyons interact with antidyons (clearly they will annihilate to zero action if they come together)

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SLIDE 38

Classical interactions

Recall that self dual dyons in SU(2) have electric and magnetic charge (++) or (−−), and that their fields are abelian outside their cores r > 1/v and r > 1/¯

  • v. It is then strange how these
  • bjects do not have any classical interaction, as naively one would

think that they attract Coulombicaly. Consider an action of two constituent dyons with actions SM = 4πv and SL = 4π¯ v where v + v ¯ =2π. Naively we would say that Stot = SM + SL + Sint(rM, rS) , where Sint = 1

2

  • d4x
  • E M

abel · E L abel + BM abel · BL abel

  • = −

8πβ | rM− rS|

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SLIDE 39

Classical interactions

Remember that the asymptotic “higgs” of L dyon A0 ∼ v + 1/rL so close to M dyon we must replace v → v + 1/d where d is the distance between the two dyons, which replaces the action SM(v) → SM(v + 1/d) Going to the stationary gauge of the L, we get that close to L dyon A0 ∼ v + 1/d, so the total action is Stot = 4π(v + 1/d)β + 4π(¯ v + 1/d)β − 8πβ d = 8π2 exactly the instanton action! (up to 1/g2 which is not written here)

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Classical interactions

The same reasoning can be applied to any combination of dyons. The self dual dyon are BPS states and they don’t interact

  • classically. For example two (++) don’t interact because their

“higgs” fields are attractive, but their abelian fields are repulsive. However for dyon-antidyon pair the situation is a bit different. In fact dyons of opposite magnetic charge and same electric attract coulombically with twice the strength, but of same magnetic charge repel with twice the strength due to the repulsive “higgs” field.

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SLIDE 41

Classical interactions

So naively

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Perturbative quantum effects

Perurbatively one has that (D.J. Gross, R.D. Pisarski and L.G. Yaffe, Rev. Mod. Phys. 53, 43 (1981).) F(v) = − ln Z(v) ∼ V3 v2¯ v2 3T(2π)2 This free energy has a minimum at v = 0 or at ¯ v = 0. If one (perturbativellt) calculates the free energy in the presence of a KvBLL instanton, one gets (Diakonov, Petrov Phys.Rev. D70 (2004) 036003 ) FKvBLL(v) = VF(v) + 2πdF ′′(v) + . . . where d is the distance between constituents. At trivial holonomy this is just the Pisarski-Yaffe term δSPY = 4 3π2ρ2T 2 , d = πρ2T which, in turn, is related to Debye screening of the electric charge at finite temperature.

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SLIDE 43

Screening

screening

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SLIDE 44

Zeromode facilitated interactions

The fermionic determinant for a dyon-antidyon pair det / D = |TD ¯

D|2Nf

We take it in zero mode basis TD ¯

D =

  • d4xψ†

¯ D /

DψD ∼ e−¯

vd/2

because ψD ∼ e−¯

vr/2. So

Veff (d) = −d Nf ¯ v 2

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SLIDE 45

The dyonic molecule

We assemble all the pieces which we know for a partition function dZmol = dZLMdZ¯

L ¯ M

m2 + |TD ¯

D|2

Λ2 Nf C(Nf ) π2rLMr¯

L ¯ MΛ4

T 2 Nf /6 e−Vscr−VL¯

L

(10)

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SLIDE 46

The dyonic molecule

stars – rLM dyon distances boxes – rL¯

L dyon distances

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SLIDE 47

The dyonic molecule

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SLIDE 48

Chiral symmetry breaking via dyons

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Some lattice observations

◮ Chiral symmetry differs for fundamental and adjoint fermions

◮ For fundamental the transition is a crossover, and the chiral

symmetry seems to go hand in hand with confinement

◮ For adjoint fermions the confinement phase transition is at

much lower temperatures then chiral symmetry breaking Tχ ≈ 8Tc.

◮ The dependence of the critical coupling βc = 6/g2 c as a

function of flavours Nf is inversely varying (larger Nf needs larger βc)

◮ Varying periodicity conditions of fermions reveals interesting

properties in the chiral condensate (Ilgenfritz, Bruckmann, Gattringer, etc.)

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SLIDE 50

The ensemble of (heavy) dyons

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SLIDE 51

The ensemble of (heavy) dyons

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Dirac operator in zero mode basis

[ / D] =                 · · · · · · T1¯

1

T1¯

2

· · · T1 ¯

N

. . . ... . . . T2¯

1

T2¯

2

· · · T2 ¯

N

. . . . . . . . . ... . . . · · · · · · TN¯

1

TN¯

2

· · · TN ¯

N

11

12

· · · T¯

1N

· · · · · · T¯

21

22

· · · T¯

2N

. . . ... . . . . . . ... . . . . . . . . . T ¯

N1

T ¯

N2

· · · T ¯

NN

· · · · · ·                

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Dirac operator with the pair ensemble

[ / D] =                 · · · · · · T1¯

1

· · · . . . ... . . . T2¯

2

· · · . . . . . . . . . ... . . . · · · · · · · · · TN ¯

N

11

· · · · · · · · · T¯

22

· · · . . . ... . . . . . . ... . . . . . . . . . · · · T ¯

NN

· · · · · ·                

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Simple example: gaussian distributed pairs

1 1 2 500 1000 1500 2000

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SLIDE 55

The dyon ensambles

We need is to generate an ensemble. We study 3 models

◮ The random dyon model RDM ◮ The random molecule model RMM ◮ The reweighed molecule model RWMM

We take that TD ¯

D = c e−Mr √ 1+Mr , and the molecules for the RMM

and RWMM are generated with the distribution dist(r) = norm × r2

  • e−Mr

√ 1 + Mr 2Nf where M is a parameter of our model, as well as Nf (although they are quite similar, so it is really one an the same parameter, so we set Nf = 2). All dimensional quantities are expressed in terms of dyon density n = N/V .

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Dirac spectrum of the random dyon model

1.0 0.5 0.0 0.5 1.0 1 2 3 4

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Dirac spectrum of the random molecule model

1.0 0.5 0.0 0.5 1.0 0.0 0.5 1.0 1.5 1.0 0.5 0.0 0.5 1.0 0.0 0.2 0.4 0.6 0.8 1.0 1.2 1.4 1.0 0.5 0.0 0.5 1.0 0.0 0.2 0.4 0.6 0.8 1.0 1.2 1.0 0.5 0.0 0.5 1.0 0.0 0.1 0.2 0.3 0.4 0.5 0.6 1.0 0.5 0.0 0.5 1.0 0.0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 1.0 0.5 0.0 0.5 1.0 0.0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 1.0 0.5 0.0 0.5 1.0 0.0 0.2 0.4 0.6 0.8 1.0 0.5 0.0 0.5 1.0 0.0 0.2 0.4 0.6 0.8 1.0 0.5 0.0 0.5 1.0 0.0 0.2 0.4 0.6 0.8 1.0 0.5 0.0 0.5 1.0 0.0 0.2 0.4 0.6 0.8 1.0 0.5 0.0 0.5 1.0 0.0 0.2 0.4 0.6 0.8 1.0 0.5 0.0 0.5 1.0 0.0 0.2 0.4 0.6 0.8

Above plots are for

M n1/3 = (1 . . . 12) π 6

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SLIDE 58

ΨΨnΒc

2 4 6 8 10 12 14 2107 4107 6107 8107 1108

6MΠn13 ΨΨnΒc

2 4 6 8 10 12 14 100 200 300 400 500

6MΠn13

Random dyon model chiral condensate as a function of M Random molecular model chiral condensate as a function of M

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Dirac spectrum of the reweighed random molecule model

1.0 0.5 0.0 0.5 1.0 0.0 0.2 0.4 0.6 0.8 1.0 0.5 0.0 0.5 1.0 0.0 0.2 0.4 0.6 0.8 1.0 1.0 0.5 0.0 0.5 1.0 0.0 0.2 0.4 0.6 0.8 1.0 0.5 0.0 0.5 1.0 0.0 0.2 0.4 0.6 0.8 1.0 0.5 0.0 0.5 1.0 0.0 0.2 0.4 0.6 0.8 1.0 0.5 0.0 0.5 1.0 0.0 0.1 0.2 0.3 0.4 0.5 0.6

Above plots are for

M n1/3 = (30 . . . 5) π 6

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SLIDE 60

ΨΨnΒc

2 4 6 8 10 12 14 100 200 300 400 500

6MΠn13

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What is M in the dyon picture?

◮ For physical, anti periodic fermions M = ¯

v/2 = 2πT−v

2

, so increasing the holonomy parameter v helps break chiral symmetry (possible connection between confinement and chiral symmetry breaking, more later)!

◮ For (anti periodic) adjoint fermions it turns out that

M = π − v (but there are more of them), so they have long tails close to v = π (confining holonomy). This explains why it is more difficult to restore chiral symmetry for adjoint fermions then for fundamental.

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SLIDE 62

Critical coupling as a function of Nf

2 4 6 8 10 12 14 16 1 2 3 4 5 6 7

  • K. Miura, M. P. Lombardo and
  • E. Pallante, arXiv:1110.3152

[hep-lat]. βc =

6 g2(Tc) as a function of Nf

From our analysis r3 nc = const. r ∼ 1 MNf where nc is critical density of dyons which nc ∼ e

− 8π2

g2 , which

means that β2

c = β1 c + (. . . ) ln r2

r1 ≈ ≈ β1

c + (. . . ) ln N1 f

N2

f

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Some works and comments on confinement

Dyons in the vacuum present a potential explanation for confinement and they have been explored by: Diakonov & Petrov, Bruckmann et al, Unsal and Poppitz, ... The main results are the following

◮ Diakonov & Petrov showed that a theory made out of only

self-dual dyons in pure gluonic theory confines

◮ Bruckmann et. al showed that a random ensemble of dyons

and antidyons of all kinds yields confinement

◮ Unsal, Poppitz et al explored the role of dyons in perturbative

regime where they force Polyakov loop to be confining.

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SLIDE 64

Large N

Why instantons cannot confine at large N! Z ∝ e−Sinst = e−N 8π

λ → 0

So pairs will be suppressed as pulling an instanton–anti-instanton pair out of the vacuum costs infinite action! However dyons carry a fractional action, and at maximally nontrivial holonomy Sdyon = 1

N Sinst. So pulling a dyon pair out of

the vacuum costs ∼ 2 × 8π

λ , i.e. they are suppressed as e−2× 8π

λ , so

at strong coupling they become quite common fluctuations!

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Conclusion

◮ Dyons in the vacuum appear as pair fluctuations of

dyon-antidyon pairs, suppressed by their action (smallness of coupling)

◮ The pairs by themselves do not break chiral symmetry, but

generate Dirac spectra with two bumps around 0 eigenvalues

◮ As the density of dyons becomes larger the gap between the

bumps closes and develops eigenvalue density at zero, breaking chiral symmetry

◮ The parameter which does this is the holonomy, and it has

qualitatively different behaviour when fermions are fundamental and adjoint, as well as when they are periodic and anti periodic

◮ Qualitative behaviour of adjoint chiral transition being pushed

to much larger temperature is natural from the point of view

  • f adjoint zero modes

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SLIDE 66

Outlook and some things not mentioned

◮ Back reaction of fermionic zero modes on the holonomy

(preference of nontrivial holonomy)

◮ Large N contributions of dyons ◮ Role of dyons at finite chemical potential ◮ Detailed interactions of dyons (string interactions) ◮ Moduli space interactions (very important!) ◮ Magnetic field and the “hairs” of topological charge ◮ Magnetic field and additional zero modes (on top of

instantons Basar, Kharazeev)

◮ Full scale simulations of the dyon ensemble (first simulations

soon by E. Shuryak and ...)

◮ Correlation functions, masses of hadrons, etc.

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