Introduction Results Idea of Proof Summary
Directed Polymers in Random Environment with Heavy Tails
- A. Auffinger
- O. Louidor
Courant (New York University)
Directed Polymers in Random Environment with Heavy Tails A. - - PowerPoint PPT Presentation
Introduction Results Idea of Proof Summary Directed Polymers in Random Environment with Heavy Tails A. Auffinger O. Louidor Courant (New York University) Maryland Probability Seminar, 11/16/2009 Introduction Results Idea of Proof
Introduction Results Idea of Proof Summary
Courant (New York University)
Introduction Results Idea of Proof Summary
Introduction Results Idea of Proof Summary
Introduction Results Idea of Proof Summary
Introduction Results Idea of Proof Summary
Introduction Results Idea of Proof Summary
Introduction Results Idea of Proof Summary
Introduction Results Idea of Proof Summary
n,β(s) =
n,β
Introduction Results Idea of Proof Summary
n,β(s) =
n,β
Introduction Results Idea of Proof Summary
n,β(s) =
n,β
Introduction Results Idea of Proof Summary
n,β(s(n/2)2).
Introduction Results Idea of Proof Summary
n,β(s(n/2)2).
Introduction Results Idea of Proof Summary
n,β(s(n/2)2).
Introduction Results Idea of Proof Summary
n,β(s(n/2)2).
Introduction Results Idea of Proof Summary
n,β(s(n/2)2).
Introduction Results Idea of Proof Summary
Introduction Results Idea of Proof Summary
Introduction Results Idea of Proof Summary
n,β(s(n/2)2) ∼ Cn1/2 and even s(n/2)/
n,β(s(n/2) = y) = 0.
Introduction Results Idea of Proof Summary
n,β(s(n/2)2) ∼ Cn1/2 and even s(n/2)/
n,β(s(n/2) = y) = 0.
Introduction Results Idea of Proof Summary
n,β(s∞ nζ) → 1 in P-prob.} ∈ [3/(4 + d), 3/4].
n,β(s(n/2) = y) > C.
Introduction Results Idea of Proof Summary
n,β(s∞ nζ) → 1 in P-prob.} ∈ [3/(4 + d), 3/4].
n,β(s(n/2) = y) > C.
Introduction Results Idea of Proof Summary
n,β is the δ measure on the maximal path
Introduction Results Idea of Proof Summary
n,β is the δ measure on the maximal path
Introduction Results Idea of Proof Summary
n,β is the δ measure on the maximal path
Introduction Results Idea of Proof Summary
n,β is the δ measure on the maximal path
Introduction Results Idea of Proof Summary
Introduction Results Idea of Proof Summary
Introduction Results Idea of Proof Summary
1 n ·
n
Introduction Results Idea of Proof Summary
1 n ·
n
Introduction Results Idea of Proof Summary
Introduction Results Idea of Proof Summary
n,β look like asymptotically?
Introduction Results Idea of Proof Summary
n,β look like asymptotically?
Introduction Results Idea of Proof Summary
n,β
Introduction Results Idea of Proof Summary
n,β
Introduction Results Idea of Proof Summary
n,β
Introduction Results Idea of Proof Summary
n,β
Introduction Results Idea of Proof Summary
n,β
Introduction Results Idea of Proof Summary
n be the set of functions γ : [0, n] → Rd which are 1-Lipchitz
n is:
2[(1 + x) log(1 + x) + (1 − x) log(1 − x)] .
β (γ) = βσ(γ) − E(γ)
Introduction Results Idea of Proof Summary
n be the set of functions γ : [0, n] → Rd which are 1-Lipchitz
n is:
2[(1 + x) log(1 + x) + (1 − x) log(1 − x)] .
β (γ) = βσ(γ) − E(γ)
Introduction Results Idea of Proof Summary
n be the set of functions γ : [0, n] → Rd which are 1-Lipchitz
n is:
2[(1 + x) log(1 + x) + (1 − x) log(1 − x)] .
β (γ) = βσ(γ) − E(γ)
Introduction Results Idea of Proof Summary
n,βn
n,βn∞ > δn
n,β = arg max γ∈L0
n
β (γ)
Introduction Results Idea of Proof Summary
n,βn really different from
n · γ∗ n,βn
1.
Introduction Results Idea of Proof Summary
n,βn really different from
n · γ∗ n,βn
1.
Introduction Results Idea of Proof Summary
n,βn really different from
n · γ∗ n,βn
1.
Introduction Results Idea of Proof Summary
n,βn really different from
n · γ∗ n,βn
1.
Introduction Results Idea of Proof Summary
α where Ej are i.i.d exponentials with rate 1.
Introduction Results Idea of Proof Summary
α where Ej are i.i.d exponentials with rate 1.
Introduction Results Idea of Proof Summary
α where Ej are i.i.d exponentials with rate 1.
Introduction Results Idea of Proof Summary
α where Ej are i.i.d exponentials with rate 1.
Introduction Results Idea of Proof Summary
α where Ej are i.i.d exponentials with rate 1.
Introduction Results Idea of Proof Summary
α where Ej are i.i.d exponentials with rate 1.
Introduction Results Idea of Proof Summary
α,β = arg max γ∈L0
β = arg max γ∈L0
Introduction Results Idea of Proof Summary
α,β = arg max γ∈L0
β = arg max γ∈L0
Introduction Results Idea of Proof Summary
α,β = arg max γ∈L0
β = arg max γ∈L0
Introduction Results Idea of Proof Summary
α,β = arg max γ∈L0
β = arg max γ∈L0
Introduction Results Idea of Proof Summary
α,β = arg max γ∈L0
β = arg max γ∈L0
Introduction Results Idea of Proof Summary
α,β = arg max γ∈L0
β = arg max γ∈L0
Introduction Results Idea of Proof Summary
1 n · s ⇒ γ∗ α,β
n,βn.
Introduction Results Idea of Proof Summary
1 n · s ⇒ γ∗ α,β
n,βn.
Introduction Results Idea of Proof Summary
α,β for β ∈ [0, ∞] can be coupled
α,β ≡ 0}.
2, 2) then βc = 0 a.s.
3) then βc > 0 a.s.
Introduction Results Idea of Proof Summary
α,β for β ∈ [0, ∞] can be coupled
α,β ≡ 0}.
2, 2) then βc = 0 a.s.
3) then βc > 0 a.s.
Introduction Results Idea of Proof Summary
α,β for β ∈ [0, ∞] can be coupled
α,β ≡ 0}.
2, 2) then βc = 0 a.s.
3) then βc > 0 a.s.
Introduction Results Idea of Proof Summary
α,β for β ∈ [0, ∞] can be coupled
α,β ≡ 0}.
2, 2) then βc = 0 a.s.
3) then βc > 0 a.s.
Introduction Results Idea of Proof Summary
Introduction Results Idea of Proof Summary
n, Pi n) : i = 1, . . . , n) extreme values and positions of
n, Z i n))k i=1
n2/α Ui n, 1 nPi n
i=1 ⇒ ((V i, Z i))k i=1
n ⇒ πk as n → ∞ where
n = k
nδ
n
k
Introduction Results Idea of Proof Summary
n, Pi n) : i = 1, . . . , n) extreme values and positions of
n, Z i n))k i=1
n2/α Ui n, 1 nPi n
i=1 ⇒ ((V i, Z i))k i=1
n ⇒ πk as n → ∞ where
n = k
nδ
n
k
Introduction Results Idea of Proof Summary
n, Pi n) : i = 1, . . . , n) extreme values and positions of
n, Z i n))k i=1
n2/α Ui n, 1 nPi n
i=1 ⇒ ((V i, Z i))k i=1
n ⇒ πk as n → ∞ where
n = k
nδ
n
k
Introduction Results Idea of Proof Summary
γ∈L0(πn n − πk n)(γ) → 0 as k → ∞
Introduction Results Idea of Proof Summary
γ∈L0(πn n − πk n)(γ) → 0 as k → ∞
Introduction Results Idea of Proof Summary
γ∈L0(πn n − πk n)(γ) → 0 as k → ∞
Introduction Results Idea of Proof Summary
0.
n = k i=1 Ui nδ
n
n(γ) = βnπk n(n−1 · γ). and
n(γ)
n(n−1·γ)
0.
n
n,β(γ) ∼
n − E − const)(n−1 · γ)
Introduction Results Idea of Proof Summary
0.
n = k i=1 Ui nδ
n
n(γ) = βnπk n(n−1 · γ). and
n(γ)
n(n−1·γ)
0.
n
n,β(γ) ∼
n − E − const)(n−1 · γ)
Introduction Results Idea of Proof Summary
0.
n = k i=1 Ui nδ
n
n(γ) = βnπk n(n−1 · γ). and
n(γ)
n(n−1·γ)
0.
n
n,β(γ) ∼
n − E − const)(n−1 · γ)
Introduction Results Idea of Proof Summary
n,β is exponentially concentrated around the maximizer of
n − E)(n−1 · γ) = n−1(βnσk n − E)(γ)
n,βn this maximizer. Then
n
n,βn
n,βn∞ > δn
Introduction Results Idea of Proof Summary
n,β is exponentially concentrated around the maximizer of
n − E)(n−1 · γ) = n−1(βnσk n − E)(γ)
n,βn this maximizer. Then
n
n,βn
n,βn∞ > δn
Introduction Results Idea of Proof Summary
Introduction Results Idea of Proof Summary
Introduction Results Idea of Proof Summary