DECAY RATE OF DEGENERATE CONVECTION DIFFUSION EQUATIONS Christian - - PowerPoint PPT Presentation

decay rate of degenerate convection diffusion equations
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DECAY RATE OF DEGENERATE CONVECTION DIFFUSION EQUATIONS Christian - - PowerPoint PPT Presentation

DECAY RATE OF DEGENERATE CONVECTION DIFFUSION EQUATIONS Christian Klingenberg Mathematics Dept., Wrzburg University, Germany joint work with: Ujjwal Koley, Wrzburg Univ., Germany Yunguang Lu, Hangzhou Normal Univ., China where is


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DECAY RATE OF DEGENERATE CONVECTION DIFFUSION EQUATIONS

Christian Klingenberg

Mathematics Dept., Würzburg University, Germany

joint work with:

Ujjwal Koley, Würzburg Univ., Germany

Yunguang Lu,

Hangzhou Normal Univ.,

China

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where is Würzburg?

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ut = uxx

As you all know, for the heat equation in one space dimension for an initial value probem with compact support

u(x, t) →

with decay rate 1

√ t

as t → ∞

you can read it off the explicit solution formula: pointwise

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Consider the large time behaviour of the initial value problem

  • f the inviscid Burgers equation

periodic

= u0(x).

u(x, t) → ¯ u

= u0(x). compactly supported

u(x, t) →

with decay rate 1

√ t

with decay rate

1 t

as t → ∞ as t → ∞

ut + (u2)x = 0 u(x, 0) = u0(x)

L1(R)

illustrating the effect of “energy dissipation” via the shock waves

  • r

u0(x) ∈ L1(R)

m e a n v a l u e

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3.6 Shock speed

33

_f

x

t

Figure 3.11. N wave solution to Burgers' equation.

XI

X, + Ax

Figure 3.12. Region of integration for shock speed calculation.

N-wave solution to Burgers equation

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moving on to the viscous Burgers equation with compactly supported initial data

u(x, t) →

with decay rate 1

√ t

as t → ∞

pointwise this can be seen this with help of the Cole-Hopf transformation resulting in here two time decay mechanisms are at play:

  • dissipation from the parabolic term
  • “dissipation” from “within” the shocks coming from the nonlinear flux

joining forces to the same decay rate

ut + (u2)x = νuxx

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the large time decay rate depending on exponent q:

ku(t)kL∞  K∞t−1/2

ku(t)kL∞  K∞t−1/q

( ut + (uq)x = uxx, ( 0) = ( )

consider a viscous conservation law with a non-Burgers flux for q > 2 for 1 < q < 2

What happens if we use a more general flux but keep strictly positive diffusion?

for u0(x) ∈ L1(R)

case q = 2 is the viscous Burgers equation

faster than 1

√ t

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the last result also holds true without viscosity

ut + uq

x = 0

for 1 < q < 2

for u0(x) ∈ L1(R)

we obtain 1

tq decay in L1(R)

so this large time decay rate is faster than 1

√ t

  • Ph. Laurencot 1998
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lets first look at the modified heat equation

ut = (um)xx,

gives a large time decay rate:

ku(t)kL∞  C∞t−1/(m+1)

here depends on m and initial data

 C∞

How does this work if we use degenerate diffusion?

for u0(x) ∈ L1(R)

for m = 1 this is the heat equation result

m ∈ N

say m=2

ut = (u2)xx

slower than

1 √ t

u(x, 0) = u0(x) ≥ 0

u(x, t) decays like 1 t

1 3

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( ut + (uq)x = uxx, ( 0) = ( )

ut = (um)xx,

for q 2 for 1 < q < 2

1 tq

1 tm+1

1 √ t

m ∈ N

summary: let us combine both degenerate diffusion and non-Burgers fluxes

faster slower

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We shall consider a scalar equation of the type

ut + F(u, x, t)x + H(u, x, t) = G(u)xx,

where G(u) may lead to a degenerate elliptic operator Thus the solutions are not smooth, they are weak solutions.

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  • ur technique requires manipulating with the solutions as if they were

smooth we deal with degenerary of the parabolic term by considering a regularisation of type

g(u) ≥ 0

this gives uniform parabolicity

  • ne can get regularity estimates of the solution independent of epsilon

ut + f(u)x = ((g(u) + ✏)ux)x

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For

ut + F(u, x, t)x + H(u, x, t) = G(u)xx,

we identify conditions on F, H and G for which we obtain large time behaviour of the form This includes all the above cases and includes new one’s. G(u) may be pointwise degenerate

||u(x, t)||L∞ ≤ C √ t

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  • ur strategy
  • find bounds for u of the type
  • then obtain time decay for u

ux < M(u, x, t)

u(x, t) ≤ C √ t

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ux ≤ f2(u, x, t),

consider solution to where the coefficients of the PDE satisfy we conclude that the solution satisfies

ut + F(u, x, t)x + H(u, x, t) = (g(u)ux)x

(x, t) ∈ R × (0, T)

  • ur result in more detail:

F(u, x, t) = F1(u, x, t) + F2(u, x, t),

(F1)uu ≥ 0, (F1)xu ≥ 0, (F1)xx ≥ 0, f2 ≥ 0, (f2)t ≥ 0, Huf2 − (f2)uH ≥ 0, (f2)u(F1)x − (F1)u(f2)x ≤ 0.

f2(u, x, t) := F2(u, x, t) g(u)

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now suppose the solution to where the conditions on the previous in particular satisfy we can conclude

pointwise

ut + F(u, x, t)x + H(u, x, t) = (g(u)ux)x

ux ≤ M t

u(x, t) ≤ M √ t

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sketch of the proof 1.) gradient decay:

ux ≤ f2(u, x, t),

here the bound is a combination of the coefficients of the PDE.

v = ux − f2(u, x, t)

set assume that at initial time this is negative and then proceed to show that

vt < 0

this uses properties of the PDE plus the assumptions on the coefficients we made

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2.) obtain a particular gradient decay of the solution in time: for our PDE we introduce the new variable we get an evolution for w

wx < const.

Hence

  • r

wt − w tα + F(w, x)x + H(w, x) = wxx

applying our result in part 1.) to this equation we conclude

w = ut

wx = uxt ≤ C

because f2 ≤ const.

ux(x, t) ≤ C t

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3.) form this time decay of the gradient conclude decay of solution

u(x, t) ≤ M √ t

α

we use the fact that we are in one space dimension

d put A = u(x0, t).

M = Z

R

u(x, t) dx ≥ Z Atα x tα dx = tαA2 2 ,

fix t and x0

integrating gives which implies

u(x, t) ≥ 1 √ t(x − x1) for 0 ≤ x − x1 ≤ At

x1 = x0 − At

ux(x, t) ≤ C t

( we know )

pos.

  • pos. in the inetrval (x1, x0)
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Now we consider time decay of the solution to porous media type equations with degenerate diffusion in higher space dimensions

ut = ∆um +

N

X

i=1

fi(u)xi − S(u),

u(x, 0) = u0(x1, x2, · · · , xN) ≥ 0.

non-negative initial data Because of parabolic degeneracy the solution may fail to be smooth. So we perturb both the initial data to be strictly positive

  • n uε ≥ ε.

nt of , on

and also the equation to be strictly parabolic. One can get uniform bounds on the solution independent of .

≥ ε. , on

This allows us to manipulate the equation.

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we can prove bounds on the gradient of the solution

0 < α ≤ 1

under certain assumptions on the coefficients of this PDE ut = ∆um +

N

X

i=1

fi(u)xi − S(u), An example for which this holds true is

ut = ∆um +

u(x, 0) ≥ 0

(u2)xi ≤ M (1 + t)

α 2

any α ≥ 1

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the proof consists of long calculations the idea is to do several changes of variables

v = un

4.5) vt = nun1∆(um) + X

i

f 0

i(u)vxi − nun1S(u)

which gives an evolution of v

first change of variables:

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w = 1 2

N

X

i=1

v2

xi

(4.8) wt = 2h0(v)(∆v)w + h(v)∆w − X

i,j

h(v)v2

xixj

+ 2m(m − n) n v(mn1)/n X

i

vxiwxi + 4m(m − n)(m − n − 1) n2 v(m2n1)/nw2 + X

j

f 0

j(u)wxj +

X

j

f 00

j (u)

nun1 vxjw − 2(n − 1)S(u) u w − 2S0(u)w.

then set which gives an evolution of w

next change of variables

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θ = (w − 1 tα )

then set which gives an evolution of θ = (

(4.11) θt + ( 1 tα )t ≤ 2h0(v)(∆v)θ + h(v)∆θ − cmv(m2n1)/n 1 t2α + 2m(m − n) n v(mn1)/n X

i

vxiθxi + 4m(m − n)(m − n − 1) n2 v(m2n1)/nθ2

applying the maximum principle and our assumptions gives the desired gradient bound on u

next change of variables

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lets summarize:

ut + F(u, x, t)x + H(u, x, t) = (g(u)ux)x

for degenerate convection diffusion equations in one space dimension we identified a certain class for which we can obtain time decay for several space dimensions

ut = ∆um +

N

X

i=1

fi(u)xi − S(u),

we identified equations for which we can show time decay of the derivative

(uxi)2 ≤ M tα

u(x, t) ≤ M √ t

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Thank you for your attention!

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here are examples of the type of equations for which we can show time decay of this type

ut + (u2 + u2 + 1 t )x = uxx

ut + (u3)x = (u2)xx