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Converse of Smith Theory Min Yan Hong Kong University of Science - - PowerPoint PPT Presentation

Converse of Smith Theory Min Yan Hong Kong University of Science and Technology International Workshop on Algebraic Topology SCMS, Shanghai, 2019 Joint with S. Cappell and S. Weinberger Smith Theory and Pseudo-equivalence General


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Converse of Smith Theory

Min Yan Hong Kong University of Science and Technology International Workshop on Algebraic Topology SCMS, Shanghai, 2019

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Joint with S. Cappell and S. Weinberger

◮ Smith Theory and Pseudo-equivalence ◮ General Action: Oliver ◮ Semi-Free Action: Jones

Always assume: Finite CW-complex, Finite group

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  • 1. Smith Theory

Paul Althaus Smith Fixed-Point Theorems for Periodic Transformations.

  • Amer. J. Math., 63(1):1-8, 1941.
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  • 1. Smith Theory

Paul Althaus Smith Fixed-Point Theorems for Periodic Transformations.

  • Amer. J. Math., 63(1):1-8, 1941.

Theorem G = Zpk acts on Fp-acyclic X = ⇒ X G is Fp-acyclic. ˜ H∗(X; Fp) = 0 = ⇒ ˜ H∗(X G; Fp) = 0.

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  • 1. Smith Theory

“X is Fp-acyclic = ⇒ X G is Fp-acyclic” holds for

  • 1. Smith: G = Zpk.
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  • 1. Smith Theory

“X is Fp-acyclic = ⇒ X G is Fp-acyclic” holds for

  • 1. Smith: G = Zpk.
  • 2. G is p-group.
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  • 1. Smith Theory

“X is Fp-acyclic = ⇒ X G is Fp-acyclic” holds for

  • 1. Smith: G = Zpk.
  • 2. G is p-group.
  • 3. Any G, semi-free action (Gx = G or e), and p dividing |G|.
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  • 1. Smith Theory

“X is Fp-acyclic = ⇒ X G is Fp-acyclic” holds for

  • 1. Smith: G = Zpk.
  • 2. G is p-group.
  • 3. Any G, semi-free action (Gx = G or e), and p dividing |G|.

Need to divide into two cases:

◮ Semi-free action: Smith condition must be satisfied. ◮ General action, |G| is not prime power: Smith condition needs

not be satisfied. The first was studied by Lowell Jones. The second was studied by Robert Oliver.

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  • 1. Converse of Smith

Theorem [Lowell Jones 1971] F is Zn-acyclic = ⇒ F = X Zn for a contractible X with semi-free Zn-action. Remark Zn-acyclic ⇐ ⇒ Zp-acyclic for all p|n. Theorem [Robert Oliver 1975] For any G such that |G| is not prime power, there is nG, such that F = X G for a contractible X with G-action ⇐ ⇒ χ(F) = 1 mod nG.

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  • 1. Pseudo-equivalence Extension

Definition A G-map is a pseudo-equivalence if it is a homotopy equivalence after forgetting the G-action.

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  • 1. Pseudo-equivalence Extension

Definition A G-map is a pseudo-equivalence if it is a homotopy equivalence after forgetting the G-action. f F Y

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  • 1. Pseudo-equivalence Extension

Definition A G-map is a pseudo-equivalence if it is a homotopy equivalence after forgetting the G-action. f F Y X g ≃ add G-cells

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  • 1. Pseudo-equivalence Extension

Definition A G-map is a pseudo-equivalence if it is a homotopy equivalence after forgetting the G-action. f F Y X g ≃ add G-cells Pseudo-equivalence Extension Problem Always assume: F = X G (F has trivial G-action), and adding free G-cells (semi-free), or adding non-fixed G-cells (general).

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  • 1. Pseudo-equivalence Extension

Definition A G-map is a pseudo-equivalence if it is a homotopy equivalence after forgetting the G-action. f F Y X g ≃ add G-cells Pseudo-equivalence Extension Problem Always assume: F = X G (F has trivial G-action), and adding free G-cells (semi-free), or adding non-fixed G-cells (general). Jones and Oliver: The case Y is a single point. Our problem: Y not contractible, especially π = π1Y non-trivial.

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  • 1. Pseudo-equivalence Extension

f F Y X g ≃ X G = Oliver and Petrie (1982) studied the general problem, with isotropies of X − F in a prescribed family. However, they only conclude quasi-equivalence instead of pseudo-equivalence.

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  • 1. Pseudo-equivalence Extension

f F Y X g ≃ X G = Oliver and Petrie (1982) studied the general problem, with isotropies of X − F in a prescribed family. However, they only conclude quasi-equivalence instead of pseudo-equivalence. Quasi-equivalence: π1X ∼ = π1Y and H∗(X; Z) ∼ = H∗(Y ; Z) Pseudo-equivalence: π1X ∼ = π1Y and H∗(X; Zπ) ∼ = H∗(Y ; Zπ)

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  • 1. Pseudo-equivalence Extension

f F Y X g ≃ X G = Oliver and Petrie (1982) studied the general problem, with isotropies of X − F in a prescribed family. However, they only conclude quasi-equivalence instead of pseudo-equivalence. Quasi-equivalence: π1X ∼ = π1Y and H∗(X; Z) ∼ = H∗(Y ; Z) Pseudo-equivalence: π1X ∼ = π1Y and H∗(X; Zπ) ∼ = H∗(Y ; Zπ)

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  • 2. General Action: Pseudo-equivalence Invariant

|G| is not prime power = ⇒ There is nG, χ(X G) = 1 mod nG for contractible G-space X. = ⇒ For pseudo-equiv g : X → Y , χ(X G) = χ(Y G) mod nG. = ⇒ χ(X G) mod nG is pseudo-equivalence invariant. Second = ⇒ : Apply Oliver to contractible G-space Cone(g).

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  • 2. General Action: Pseudo-equivalence Invariant

|G| is not prime power = ⇒ There is nG, χ(X G) = 1 mod nG for contractible G-space X. = ⇒ For pseudo-equiv g : X → Y , χ(X G) = χ(Y G) mod nG. = ⇒ χ(X G) mod nG is pseudo-equivalence invariant. Second = ⇒ : Apply Oliver to contractible G-space Cone(g). Remark Pseudo-equivalence has no inverse. To get equivalence relation, need zig-zaging sequence of pseudo-equivalences X ← • → • ← • → • · · · • ← • → Y χ(X G) mod nG is an invariant in this sense.

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  • 2. General Action: Main Theorem

Theorem Suppose |G| is not prime power, and Y G

1 , Y G 2 , . . . , Y G k are

components of Y G. Then there is a subgroup NY ⊂ Zk, such that f : F → Y can be extended to a pseudo-equivalence G-map g : X → Y , with X G = F, if and only if ( χ(F1) − χ(Y G

1 ), . . . , χ(Fk) − χ(Y G k ) ) ∈ NY ,

Fi = f −1(Y G

i ).

Moreover, nGZk ⊂ NY ⊂ {(ai): nG divides

  • ai}.
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  • 2. General Action: Main Theorem

Theorem Suppose |G| is not prime power, and Y G

1 , Y G 2 , . . . , Y G k are

components of Y G. Then there is a subgroup NY ⊂ Zk, such that f : F → Y can be extended to a pseudo-equivalence G-map g : X → Y , with X G = F, if and only if ( χ(F1) − χ(Y G

1 ), . . . , χ(Fk) − χ(Y G k ) ) ∈ NY ,

Fi = f −1(Y G

i ).

Moreover, nGZk ⊂ NY ⊂ {(ai): nG divides

  • ai}.

First ⊂: component-wise χ(Fi) = χ(Y G

i ) mod nG is sufficient.

Second ⊂: global χ(F) = χ(Y G) mod nG is necessary.

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  • 2. General Action: Connected Y G

NY = nGZ for k = 1, i.e., Y G is connected. Theorem Suppose |G| is not prime power, and Y G is connected. Then f : F → Y can be extended to a pseudo-equivalence G-map g : X → Y , with X G = F, if and only if χ(F) = χ(Y G) mod nG.

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  • 2. General Action: Connected Y G

NY = nGZ for k = 1, i.e., Y G is connected. Theorem Suppose |G| is not prime power, and Y G is connected. Then f : F → Y can be extended to a pseudo-equivalence G-map g : X → Y , with X G = F, if and only if χ(F) = χ(Y G) mod nG. Corollary Suppose |G| is not prime power, and Y G is non-empty and

  • connected. Then F = X G for some X pseudo-equivalent to Y (no

direct map needed) if and only if χ(F) = χ(Y G) mod nG.

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  • 2. General Action: Application

Corollary If |G| is not prime power, Y is connected, χ(Y ) = 0 mod nG, then G acts on a homotopy Y with no fixed points.

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  • 2. General Action: Application

Corollary If |G| is not prime power, Y is connected, χ(Y ) = 0 mod nG, then G acts on a homotopy Y with no fixed points. G-action on X, induces homomorphism G → Out(π), π = π1X. If the action has fixed point, then the homomorphism lifts to G → Aut(π).

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  • 2. General Action: Application

Corollary If |G| is not prime power, Y is connected, χ(Y ) = 0 mod nG, then G acts on a homotopy Y with no fixed points. G-action on X, induces homomorphism G → Out(π), π = π1X. If the action has fixed point, then the homomorphism lifts to G → Aut(π). Problem: If G → Out(π) lifts to Aut(π), does the action have fixed point?

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  • 2. General Action: Application

Corollary If |G| is not prime power, Y is connected, χ(Y ) = 0 mod nG, then G acts on a homotopy Y with no fixed points. G-action on X, induces homomorphism G → Out(π), π = π1X. If the action has fixed point, then the homomorphism lifts to G → Aut(π). Problem: If G → Out(π) lifts to Aut(π), does the action have fixed point? The corollary provides plenty of examples of G-action on homotopy Y with and without fixed points.

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  • 2. General Action: Application

Corollary If |G| is not prime power, Y is connected, χ(Y ) = 0 mod nG, then G acts on a homotopy Y with no fixed points. G-action on X, induces homomorphism G → Out(π), π = π1X. If the action has fixed point, then the homomorphism lifts to G → Aut(π). Problem: If G → Out(π) lifts to Aut(π), does the action have fixed point? The corollary provides plenty of examples of G-action on homotopy Y with and without fixed points. Theorem Suppose |G| is not prime power. Then there is an aspherical manifold M with centerless fundamental group, such that G → Out(π) lifts to Aut(π), and the action has no fixed point.

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  • 2. General Action: Proof

Need to show

  • 1. NY = {(χ(X G

i ) − χ(Y G i ))k i=1 : pseudo-equiv X → Y } is an

abelian subgroup.

  • 2. Component-wise Euler condition χ(Fi) = χ(Y G

i ) mod nG

= ⇒ pseudo-equivalence extension exists.

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  • 2. General Action: Proof

Need to show

  • 1. NY = {(χ(X G

i ) − χ(Y G i ))k i=1 : pseudo-equiv X → Y } is an

abelian subgroup.

  • 2. Component-wise Euler condition χ(Fi) = χ(Y G

i ) mod nG

= ⇒ pseudo-equivalence extension exists. The first is by general constructions, which also shows that NY is

  • functorial. The second is by the following steps:
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  • 2. General Action: Proof

Need to show

  • 1. NY = {(χ(X G

i ) − χ(Y G i ))k i=1 : pseudo-equiv X → Y } is an

abelian subgroup.

  • 2. Component-wise Euler condition χ(Fi) = χ(Y G

i ) mod nG

= ⇒ pseudo-equivalence extension exists. The first is by general constructions, which also shows that NY is

  • functorial. The second is by the following steps:

◮ Reduce to extending f : F → Y , Y connected and trivial

action.

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  • 2. General Action: Proof

Need to show

  • 1. NY = {(χ(X G

i ) − χ(Y G i ))k i=1 : pseudo-equiv X → Y } is an

abelian subgroup.

  • 2. Component-wise Euler condition χ(Fi) = χ(Y G

i ) mod nG

= ⇒ pseudo-equivalence extension exists. The first is by general constructions, which also shows that NY is

  • functorial. The second is by the following steps:

◮ Reduce to extending f : F → Y , Y connected and trivial

action.

◮ Partition of Euler number: If F = ∅ and χ(F) = χ(Y ) mod n,

then by changing F and f by homotopy, we have χ(f −1(σ)) = 1 mod n for each cell σ of Y .

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  • 2. General Action: Proof

Need to show

  • 1. NY = {(χ(X G

i ) − χ(Y G i ))k i=1 : pseudo-equiv X → Y } is an

abelian subgroup.

  • 2. Component-wise Euler condition χ(Fi) = χ(Y G

i ) mod nG

= ⇒ pseudo-equivalence extension exists. The first is by general constructions, which also shows that NY is

  • functorial. The second is by the following steps:

◮ Reduce to extending f : F → Y , Y connected and trivial

action.

◮ Partition of Euler number: If F = ∅ and χ(F) = χ(Y ) mod n,

then by changing F and f by homotopy, we have χ(f −1(σ)) = 1 mod n for each cell σ of Y .

◮ Oliver’s argument is relative, allowing induction on cells.

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  • 2. General Action: Proof

Need to show

  • 1. NY = {(χ(X G

i ) − χ(Y G i ))k i=1 : pseudo-equiv X → Y } is an

abelian subgroup.

  • 2. Component-wise Euler condition χ(Fi) = χ(Y G

i ) mod nG

= ⇒ pseudo-equivalence extension exists. The first is by general constructions, which also shows that NY is

  • functorial. The second is by the following steps:

◮ Reduce to extending f : F → Y , Y connected and trivial

action.

◮ Partition of Euler number: If F = ∅ and χ(F) = χ(Y ) mod n,

then by changing F and f by homotopy, we have χ(f −1(σ)) = 1 mod n for each cell σ of Y .

◮ Oliver’s argument is relative, allowing induction on cells. ◮ Treat F = ∅ by the special case Y = S1.

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  • 2. General Action: F = ∅ and Y = S1

Corollary If |G| is not prime power, then there is a G-space X ≃ S1, such that X G = ∅.

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  • 2. General Action: F = ∅ and Y = S1

Corollary If |G| is not prime power, then there is a G-space X ≃ S1, such that X G = ∅. Let V = ker(RG → R) ⊂ RG, and Z = unit sphere of ⊕kV .

Z

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  • 2. General Action: F = ∅ and Y = S1

Corollary If |G| is not prime power, then there is a G-space X ≃ S1, such that X G = ∅. Let V = ker(RG → R) ⊂ RG, and Z = unit sphere of ⊕kV .

Z x Gx = Sylow P

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  • 2. General Action: F = ∅ and Y = S1

Corollary If |G| is not prime power, then there is a G-space X ≃ S1, such that X G = ∅. Let V = ker(RG → R) ⊂ RG, and Z = unit sphere of ⊕kV .

D Z x Gx = Sylow P

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  • 2. General Action: F = ∅ and Y = S1

Corollary If |G| is not prime power, then there is a G-space X ≃ S1, such that X G = ∅. Let V = ker(RG → R) ⊂ RG, and Z = unit sphere of ⊕kV .

D Z x Gx = Sylow P Z ∨x D/∂D

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  • 2. General Action: F = ∅ and Y = S1

Corollary If |G| is not prime power, then there is a G-space X ≃ S1, such that X G = ∅. Let V = ker(RG → R) ⊂ RG, and Z = unit sphere of ⊕kV .

D Z x Gx = Sylow P Z ∨x D/∂D Z

We have D/∂D ∼ =P Z and G-map of degree 1 ± |G/NP| Z → Z ∨Gx G(D/∂D) → Z.

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  • 2. General Action: F = ∅ and Y = S1

Corollary If |G| is not prime power, then there is a G-space X ≃ S1, such that X G = ∅. Let V = ker(RG → R) ⊂ RG, and Z = unit sphere of ⊕kV .

D Z x Gx = Sylow P Z ∨x D/∂D Z

We have D/∂D ∼ =P Z and G-map of degree 1 ± |G/NP| Z → Z ∨Gx G(D/∂D) → Z. Repeat and modify for all Pi, get G-map φ: Z → Z of degree 1 + a1|G/NP1| + · · · + an|G/NPn| = 0.

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  • 2. General Action: F = ∅ and Y = S1

Corollary If |G| is not prime power, then there is a G-space X ≃ S1, such that X G = ∅. Let V = ker(RG → R) ⊂ RG, and Z = unit sphere of ⊕kV .

D Z x Gx = Sylow P Z ∨x D/∂D Z

We have D/∂D ∼ =P Z and G-map of degree 1 ± |G/NP| Z → Z ∨Gx G(D/∂D) → Z. Repeat and modify for all Pi, get G-map φ: Z → Z of degree 1 + a1|G/NP1| + · · · + an|G/NPn| = 0. Mapping torus X = T(φ) → S1 is ≃.

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  • 2. General Action: Local vs Global Euler

nGZk ⊂ NY ⊂ {(ai) ∈ Zk : nG divides ai}.

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  • 2. General Action: Local vs Global Euler

nGZk ⊂ NY ⊂ {(ai) ∈ Zk : nG divides ai}. NY = Zk (no Euler condition) if nG = 1. By Oliver (1975), this means G is not of the form P ⊳ H ⊳ G, |P| and |G/H| prime power, and H/P cyclic.

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  • 2. General Action: Local vs Global Euler

nGZk ⊂ NY ⊂ {(ai) ∈ Zk : nG divides ai}. NY = Zk (no Euler condition) if nG = 1. By Oliver (1975), this means G is not of the form P ⊳ H ⊳ G, |P| and |G/H| prime power, and H/P cyclic. Theorem Suppose nG = 0, which means P ⊳ G, |P| prime power, and G/P cyclic. Let Γ on ˜ Y be the lifting of G on Y . If the connected components Y G

1 , . . . , Y G k of Y G satisfy

  • 1. Induced splittings G

si

− → Γ are not π-conjugate.

  • 2. π1Y G

i

→ π1Y are injective. Then NY = nGZk.

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  • 2. General Action: Local vs Global Euler

Theorem [Oliver and Petrie 1982] Consider G = Dp, the dihedral group of order 2p (p an odd prime). Consider f : F → Y , Y simply connected. Let Y Cp

1 , . . . , Y Cp l

be connected components of Y Cp. Then f has pseudo-equivalence extension if and only if χ(F ∩ f −1(Y Cp

i

)) = χ(Y G ∩ Y Cp

i

) for all i. Y Y Dp Y Cp χ-trade off

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  • 3. Semi-free Action: Pseudo-equivalence Invariant

For semi-free action, pseudo-equivalence g : X → Y implies Smith condition H∗(X G; Fpπ) ∼ = H∗(Y G; Fpπ), p| |G|. So H∗(−G; Fpπ) is pseudo-equivalence invariant, not as easy to use as Euler number.

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  • 3. Semi-free Action: Main Theorem

Theorem (fixed target)

A map f : F → Y (no G-action) has pseudo-equivalent extension g : X → Y , with semi-free G-space X and F = X G, if and only if

  • 1. Smith: H∗(F; Fpπ) ∼

= H∗(Y ; Fpπ),

  • 2. K-theory: [C(˜

f )] ∈ ˜ K0(Z[π × G]) vanishes.

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  • 3. Semi-free Action: Main Theorem

Theorem (fixed target)

A map f : F → Y (no G-action) has pseudo-equivalent extension g : X → Y , with semi-free G-space X and F = X G, if and only if

  • 1. Smith: H∗(F; Fpπ) ∼

= H∗(Y ; Fpπ),

  • 2. K-theory: [C(˜

f )] ∈ ˜ K0(Z[π × G]) vanishes. Remark C(˜ f ) is Zπ-chain complex, regarded as Z[π × G]-chain complex by trivial G-action. Then Smith condition implies C(˜ f ) has finite Z[π × G]-projective resolution.

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  • 3. Semi-free Action: Main Theorem

Theorem (fixed target)

A map f : F → Y (no G-action) has pseudo-equivalent extension g : X → Y , with semi-free G-space X and F = X G, if and only if

  • 1. Smith: H∗(F; Fpπ) ∼

= H∗(Y ; Fpπ),

  • 2. K-theory: [C(˜

f )] ∈ ˜ K0(Z[π × G]) vanishes. Remark C(˜ f ) is Zπ-chain complex, regarded as Z[π × G]-chain complex by trivial G-action. Then Smith condition implies C(˜ f ) has finite Z[π × G]-projective resolution.

Theorem (semi-free target)

Consider G acting semi-freely on Y and f : F → Y G ⊂ Y , exists exists if and only if Smith condition is satisfied and K-theory

  • bstruction [C(˜

f )] ∈ ˜ K0(Z[Γ]) vanishes.

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  • 3. Semi-free Action: Proof

Same as Wall (1965) construction for finiteness.

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  • 3. Semi-free Action: Proof

Same as Wall (1965) construction for finiteness. Attach free G-cells to F to get isomorphism on π1 and then inductively kill Hi(f ; Zπ). Get f n : X n → Y , n > dim F, dim Y , such that Hi(f n; Zπ) = 0 for i ≤ n. Get exact sequence 0 → C∗(˜ f ) → C∗(˜ f n) → C∗−1( ˜ X n, ˜ F) → 0.

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  • 3. Semi-free Action: Proof

Same as Wall (1965) construction for finiteness. Attach free G-cells to F to get isomorphism on π1 and then inductively kill Hi(f ; Zπ). Get f n : X n → Y , n > dim F, dim Y , such that Hi(f n; Zπ) = 0 for i ≤ n. Get exact sequence 0 → C∗(˜ f ) → C∗(˜ f n) → C∗−1( ˜ X n, ˜ F) → 0. The obstruction is the “stable Z(π × G)-freeness” of Hn+1(f n; Zπ). Since C∗( ˜ X n, ˜ F) is Z(π × G)-free, the obstruction is ±[Hn+1(f n; Zπ)] = [C∗(˜ f n)] = [C∗(˜ f )] ∈ ˜ K0(Z[π × G]).

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  • 3. Semi-Free Action: Example

Y = S1, π = {ti : i ∈ Z}. F is double mapping torus T(a, b) of maps Sd → Sd of deg a, b

a b Sd F f S1

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  • 3. Semi-Free Action: Example

Y = S1, π = {ti : i ∈ Z}. F is double mapping torus T(a, b) of maps Sd → Sd of deg a, b

a b Sd F f S1

For G = Zn, we want to extend f : F = T(a, b) → Y to semi-free pseudo-equivalence.

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  • 3. Semi-Free Action: Example

Y = S1, π = {ti : i ∈ Z}. F is double mapping torus T(a, b) of maps Sd → Sd of deg a, b

a b Sd F f S1

For G = Zn, we want to extend f : F = T(a, b) → Y to semi-free pseudo-equivalence. The only non-trivial Zπ-homology of f is H = Hd(f ; Z[t, t−1]) = Z[t, t−1]/(at − b).

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  • 3. Semi-Free Action: Example

The pullback diagrams Z[Zn][t, t−1] − − − − →

Z[Zn] Σ [t, t−1]

 

  • Z[t, t−1]

− − − − → Zn[t, t−1] Z[Zn] − − − − →

Z[Zn] Σ

 

  • Z

− − − − → Zn induce ∂ between Bass-Heller-Swan decompositions

K1(Zn[t, t−1]) = K1(Zn) ⊕ K0(Zn) ⊕ NK1(Zn) ⊕ NK1(Zn) ↓ ∂ ˜ K0(Z[Zn][t, t−1]) = ˜ K0(Z[Zn]) ⊕ K−1(Z[Zn]) ⊕ NK0(Z[Zn]) ⊕ NK0(Z[Zn])

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  • 3. Semi-Free Action: Example 1

For G = Zn, n = pk, p prime, a = p, b = 1, we have H = Z[t, t−1]/(pt − 1), Smith condition satisfied.

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  • 3. Semi-Free Action: Example 1

For G = Zn, n = pk, p prime, a = p, b = 1, we have H = Z[t, t−1]/(pt − 1), Smith condition satisfied. [pt − 1] = ([p − 1], 0, 0, [(p − 1)−1p]) in K1(Zn[t, t−1]) = K1(Zn) ⊕ K0(Zn) ⊕ NK1(Zn) ⊕ NK1(Zn), goes to [H] = (0, 0, 0, ∂[(p − 1)−1p]) in ˜ K0(Z[Zn][t, t−1]) = ˜ K0(Z[Zn])⊕K−1(Z[Zn])⊕NK0(Z[Zn])⊕NK0(Z[Zn])

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  • 3. Semi-Free Action: Example 1

For G = Zn, n = pk, p prime, a = p, b = 1, we have H = Z[t, t−1]/(pt − 1), Smith condition satisfied. [pt − 1] = ([p − 1], 0, 0, [(p − 1)−1p]) in K1(Zn[t, t−1]) = K1(Zn) ⊕ K0(Zn) ⊕ NK1(Zn) ⊕ NK1(Zn), goes to [H] = (0, 0, 0, ∂[(p − 1)−1p]) in ˜ K0(Z[Zn][t, t−1]) = ˜ K0(Z[Zn])⊕K−1(Z[Zn])⊕NK0(Z[Zn])⊕NK0(Z[Zn])

◮ For k = 1, [(p − 1)−1p] ∈ NK1(Zn) already vanishes. So

pseudo-equivalence extension exists.

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SLIDE 61
  • 3. Semi-Free Action: Example 1

For G = Zn, n = pk, p prime, a = p, b = 1, we have H = Z[t, t−1]/(pt − 1), Smith condition satisfied. [pt − 1] = ([p − 1], 0, 0, [(p − 1)−1p]) in K1(Zn[t, t−1]) = K1(Zn) ⊕ K0(Zn) ⊕ NK1(Zn) ⊕ NK1(Zn), goes to [H] = (0, 0, 0, ∂[(p − 1)−1p]) in ˜ K0(Z[Zn][t, t−1]) = ˜ K0(Z[Zn])⊕K−1(Z[Zn])⊕NK0(Z[Zn])⊕NK0(Z[Zn])

◮ For k = 1, [(p − 1)−1p] ∈ NK1(Zn) already vanishes. So

pseudo-equivalence extension exists.

◮ For k > 1, ∂[(p − 1)−1p] ∈ NK0(Z[Zn]) is non-trivial. So

pseudo-equivalence extension does not exist. (still obstruction even in ANR category).

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SLIDE 62
  • 3. Semi-Free Action: Example 1

Theorem If G has element of order p2 (say G is a p-group and G = Z⊕k

p ),

then there is no semi-free G-action on homotopy S1 with T(p, 1) as fixed point.

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SLIDE 63
  • 3. Semi-Free Action: Example 2

If G = Zn, n is not prime power, then n = n1n2, with n1, n2 > 1 and coprime. Pick a, b = 1 − a satisfying (a, b) = (1, 0) mod n1, (a, b) = (0, 1) mod n2. Then H = Z[t, t−1]/(at − b) satisfies Smith condition.

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SLIDE 64
  • 3. Semi-Free Action: Example 2

If G = Zn, n is not prime power, then n = n1n2, with n1, n2 > 1 and coprime. Pick a, b = 1 − a satisfying (a, b) = (1, 0) mod n1, (a, b) = (0, 1) mod n2. Then H = Z[t, t−1]/(at − b) satisfies Smith condition. [at − b] = (0, [aZn], 0, 0) in (note Zn = aZn ⊕ bZn) K1(Zn[t, t−1]) = K1(Zn) ⊕ K0(Zn) ⊕ NK1(Zn) ⊕ NK1(Zn), goes to [H] = (0, ∂[aZn], 0, 0) in ˜ K0(Z[Zn][t, t−1]) = ˜ K0(Z[Zn])⊕K−1(Z[Zn])⊕NK0(Z[Zn])⊕NK0(Z[Zn])

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SLIDE 65
  • 3. Semi-Free Action: Example 2

If G = Zn, n is not prime power, then n = n1n2, with n1, n2 > 1 and coprime. Pick a, b = 1 − a satisfying (a, b) = (1, 0) mod n1, (a, b) = (0, 1) mod n2. Then H = Z[t, t−1]/(at − b) satisfies Smith condition. [at − b] = (0, [aZn], 0, 0) in (note Zn = aZn ⊕ bZn) K1(Zn[t, t−1]) = K1(Zn) ⊕ K0(Zn) ⊕ NK1(Zn) ⊕ NK1(Zn), goes to [H] = (0, ∂[aZn], 0, 0) in ˜ K0(Z[Zn][t, t−1]) = ˜ K0(Z[Zn])⊕K−1(Z[Zn])⊕NK0(Z[Zn])⊕NK0(Z[Zn]) No longer obstruction in ANR category!

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SLIDE 66
  • 3. Semi-Free Action: Example 2

Calculate ∂[aZn] by exact sequence ˜ K0(Z)⊕ ˜ K0(Z[ξn]) → ˜ K0(Zn) ∂ − → K−1(Z[Zn]) → K−1(Z)⊕K−1(Z[ξn]). This is (K0(Zn) = ⊕k

i=1K0(Zpmi

i ) = Zk for n = pm1

1

. . . pmk

k )

0 ⊕ finite → Zk/Z(1, . . . , 1) ∂ − → K−1(Z[Zn]) → 0 ⊕ torsionfree

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SLIDE 67
  • 3. Semi-Free Action: Example 2

Calculate ∂[aZn] by exact sequence ˜ K0(Z)⊕ ˜ K0(Z[ξn]) → ˜ K0(Zn) ∂ − → K−1(Z[Zn]) → K−1(Z)⊕K−1(Z[ξn]). This is (K0(Zn) = ⊕k

i=1K0(Zpmi

i ) = Zk for n = pm1

1

. . . pmk

k )

0 ⊕ finite → Zk/Z(1, . . . , 1) ∂ − → K−1(Z[Zn]) → 0 ⊕ torsionfree ∂ is injective. In fact ˜ K0(Zn) is a direct summand of K−1(Z[Zn]).

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SLIDE 68
  • 3. Semi-Free Action: Example 2

Calculate ∂[aZn] by exact sequence ˜ K0(Z)⊕ ˜ K0(Z[ξn]) → ˜ K0(Zn) ∂ − → K−1(Z[Zn]) → K−1(Z)⊕K−1(Z[ξn]). This is (K0(Zn) = ⊕k

i=1K0(Zpmi

i ) = Zk for n = pm1

1

. . . pmk

k )

0 ⊕ finite → Zk/Z(1, . . . , 1) ∂ − → K−1(Z[Zn]) → 0 ⊕ torsionfree ∂ is injective. In fact ˜ K0(Zn) is a direct summand of K−1(Z[Zn]). Take n1 = pm1

1 , n2 = pm2 2

. . . pmk

k

= ⇒ [aZn] = [1, 0, . . . , 0] = 0 ∈ ˜ K0(Zn) = ⇒ ∂[aZn] = 0 ∈ K−1(Z[Zn]).

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SLIDE 69
  • 3. Semi-Free Action: Summary

For G = Zn acting on homotopy circle:

◮ If n is not primer power, then we get K−1-obstruction

counterexample.

◮ If p2 divides n, then get NK0-obstruction counterexample.

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SLIDE 70

Thank You