Colorful simplicial depth
Zuzana Pat´ akov´ a joint work with Karim Adiprasito, Philip Brinkmann, Arnau Padrol, Pavel Pat´ ak, and Raman Sanyal ICERM 1st December, Providence
Colorful simplicial depth Zuzana Pat akov a joint work with Karim - - PowerPoint PPT Presentation
Colorful simplicial depth Zuzana Pat akov a joint work with Karim Adiprasito, Philip Brinkmann, Arnau Padrol, Pavel Pat ak, and Raman Sanyal ICERM 1st December, Providence Colorful configurations C = { C 0 , . . . , C d } :
Zuzana Pat´ akov´ a joint work with Karim Adiprasito, Philip Brinkmann, Arnau Padrol, Pavel Pat´ ak, and Raman Sanyal ICERM 1st December, Providence
⇒ (C, ϕ) is a colorful configuration
⇒ (C, ϕ) is a colorful configuration Colorful simplex
⇒ (C, ϕ) is a colorful configuration
Colorful simplex
⇒ (C, ϕ) is a colorful configuration
Colorful simplex
⇒ (C, ϕ) is a colorful configuration
Colorful simplex
⇒ (C, ϕ) is a colorful configuration
Colorful simplex
⇒ (C, ϕ) is a colorful configuration
Colorful simplex
⇒ (C, ϕ) is a colorful configuration
Not Colorful simplex
⇒ (C, ϕ) is a colorful configuration
Not Colorful simplex
Allowed
Allowed
Not Allowed
Centered
Centered
Centered
Centered
Centered
Not Centered
A colorful configuration
Hitting simplex
Another hitting simplex
= number of hitting simplices of C Deza, Huang, Stephen and Terlaky ’06
≈ higher dim analogue of median
= number of hitting simplices of C Deza, Huang, Stephen and Terlaky ’06
≈ higher dim analogue of median
= number of hitting simplices of C Deza, Huang, Stephen and Terlaky ’06
≈ higher dim analogue of median
Theorem (Colorful Carath´ eodory, B´ ar´ any ’82)
There is always at least one hitting simplex. (cdepth ≥ 1)
Conjecture (Deza, Huang, Stephen, Terlaky, ’06)
If Card C0 = Card C1 = . . . = Card Cd = d + 1, then
1 cdepth C ≥ d2 + 1 2 cdepth C ≤ 1 + dd+1
Deza et al: both bounds can be attained Lower bound: Deza et al [’06], B´ ar´ any, Matouˇ sek [’07], . . . Sarrabezolles [’15]
Theorem (Colorful Carath´ eodory, B´ ar´ any ’82)
There is always at least one hitting simplex. (cdepth ≥ 1)
Conjecture (Deza, Huang, Stephen, Terlaky, ’06)
If Card C0 = Card C1 = . . . = Card Cd = d + 1, then
1 cdepth C ≥ d2 + 1 2 cdepth C ≤ 1 + dd+1
Deza et al: both bounds can be attained Lower bound: Deza et al [’06], B´ ar´ any, Matouˇ sek [’07], . . . Sarrabezolles [’15]
Theorem (Colorful Carath´ eodory, B´ ar´ any ’82)
There is always at least one hitting simplex. (cdepth ≥ 1)
Conjecture (Deza, Huang, Stephen, Terlaky, ’06)
If Card C0 = Card C1 = . . . = Card Cd = d + 1, then
1 cdepth C ≥ d2 + 1 2 cdepth C ≤ 1 + dd+1
Deza et al: both bounds can be attained Lower bound: Deza et al [’06], B´ ar´ any, Matouˇ sek [’07], . . . Sarrabezolles [’15]
Theorem (Colorful Carath´ eodory, B´ ar´ any ’82)
There is always at least one hitting simplex. (cdepth ≥ 1)
Conjecture (Deza, Huang, Stephen, Terlaky, ’06)
If Card C0 = Card C1 = . . . = Card Cd = d + 1, then
1 cdepth C ≥ d2 + 1 2 cdepth C ≤ 1 + dd+1
Deza et al: both bounds can be attained Lower bound: Deza et al [’06], B´ ar´ any, Matouˇ sek [’07], . . . Sarrabezolles [’15]
Theorem (Colorful Carath´ eodory, B´ ar´ any ’82)
There is always at least one hitting simplex. (cdepth ≥ 1)
Conjecture (Deza, Huang, Stephen, Terlaky, ’06)
If Card C0 = Card C1 = . . . = Card Cd = d + 1, then
1 cdepth C ≥ d2 + 1 2 cdepth C ≤ 1 + dd+1
Deza et al: both bounds can be attained Lower bound: Deza et al [’06], B´ ar´ any, Matouˇ sek [’07], . . . Sarrabezolles [’15]
Theorem (Adiprasito, Brinkmann, Padrol, Pat´ ak, P, Sanyal)
cdepth C ≤ 1 +
d
Theorem (Adiprasito, Brinkmann, Padrol, Pat´ ak, P, Sanyal)
cdepth C ≤ 1 +
d
Theorem (Adiprasito, Brinkmann, Padrol, Pat´ ak, P, Sanyal)
cdepth C ≤ 1 +
d
Theorem (Adiprasito, Brinkmann, Padrol, Pat´ ak, P, Sanyal)
cdepth C ≤ 1 +
d
Theorem (Adiprasito, Brinkmann, Padrol, Pat´ ak, P, Sanyal)
cdepth C ≤ 1 +
d
Theorem (Adiprasito, Brinkmann, Padrol, Pat´ ak, P, Sanyal)
cdepth C ≤ 1 +
d
⇒ for i < d fi(A) = fi(B) ⇒ for i < d − 1
βi(B)
⇒ for i < d fi(A) = fi(B) ⇒ for i < d − 1
βi(B)
⇒ for i < d fi(A) = fi(B) ⇒ for i < d − 1
βi(B)
⇒ for i < d fi(A) = fi(B) ⇒ for i < d − 1
βi(B)
⇒ for i < d fi(A) = fi(B) ⇒ for i < d − 1
βi(B)
⇒ for i < d fi(A) = fi(B) ⇒ for i < d − 1
βi(B)
⇒ for i < d fi(A) = fi(B) ⇒ for i < d − 1
βi(B)
cdepth C = fd(A) − fd(B)
cdepth C = fd(A) − fd(B)
cdepth C = fd(A) − fd(B)
d
(−1)ifi(A) =
d
(−1)i βi(A)
cdepth C = fd(A) − fd(B)
d
(−1)ifi(A) =
d
(−1)i βi(A) ⇒ fd(A) = (−1)d d
(−1)i βi(A) + 1 −
d−1
(−1)ifi(A)
cdepth C = (−1)d d
(−1)i βi(A) + 1 −
d−1
(−1)ifi(A)
⇒ fd(A) = (−1)d d
(−1)i βi(A) + 1 −
d−1
(−1)ifi(A)
cdepth C = (−1)d d
(−1)i βi(A) + 1 −
d−1
(−1)ifi(A)
cdepth C = (−1)d d
(−1)i βi(A) + 1 −
d−1
(−1)ifi(A)
fd(B) = (−1)d d
(−1)i βi(B) + 1 −
d−1
(−1)ifi(B)
cdepth C = (−1)d d
(−1)i βi(A) + 1 −
d−1
(−1)ifi(A) −
d
(−1)i βi(B) − 1 +
d−1
(−1)ifi(B)
d
(−1)i βi(B) + 1 −
d−1
(−1)ifi(B)
cdepth C = (−1)d d
(−1)i βi(A) + 1 −
d−1
(−1)ifi(A) −
d
(−1)i βi(B) − 1 +
d−1
(−1)ifi(B)
cdepth C = (−1)d d
(−1)i βi(A)−
d−1
(−1)ifi(A) −
d
(−1)i βi(B)+
d−1
(−1)ifi(B)
cdepth C = (−1)d d
(−1)i βi(A)−
d−1
(−1)ifi(A) −
d
(−1)i βi(B)+
d−1
(−1)ifi(B)
cdepth C = (−1)d d
(−1)i βi(A)−
d−1
(−1)ifi(A) −
d
(−1)i βi(B)+
d−1
(−1)ifi(B)
cdepth C = (−1)d d
(−1)i βi(A) −
d
(−1)i βi(B)
cdepth C = (−1)d d
(−1)i βi(A) −
d
(−1)i βi(B)
cdepth C = (−1)d d
(−1)i βi(A) −
d
(−1)i βi(B)
βi(A) = βi(B)
cdepth C = (−1)d (−1)d βd(A) + (−1)d−1 βd−1(A) −(−1)d βd(B) − (−1)d−1 βd−1(B)
cdepth C = (−1)d (−1)d βd(A) + (−1)d−1 βd−1(A) −(−1)d βd(B) − (−1)d−1 βd−1(B)
cdepth C = βd(A)− βd−1(A) − βd(B) + βd−1(B)
cdepth C = βd(A)− βd−1(A) − βd(B) + βd−1(B)
cdepth C = βd(A) − 0 − βd(B) + βd−1(B)
cdepth C = βd(A) − βd(B) + βd−1(B)
cdepth C = βd(A) − βd(B) + βd−1(B)
cdepth C =
d
βd(B) + βd−1(B)
cdepth C =
d
βd(B) + βd−1(B)
cdepth C =
d
βd(B) + βd−1(B) Our main Lemma: βd−1(B) = 1
cdepth C =
d
βd(B) + 1
cdepth C =
d
βd(B) + 1 ⇒ cdepth C ≤
d
Lemma
Proof idea:
1 First show for a special configuration of points: 2 Use flips preserving
βd−1(B; Z2)
Lemma
Proof idea:
1 First show for a special configuration of points: 2 Use flips preserving
βd−1(B; Z2)
Lemma
Proof idea:
1 First show for a special configuration of points: 2 Use flips preserving
βd−1(B; Z2)
Lemma
Proof idea:
1 First show for a special configuration of points: 2 Use flips preserving
βd−1(B; Z2)
1-fan, given by normals of a triangle
1-fan, given by normals of a triangle
2-fan; halfplanes = leafs
2-fan; halfplanes = leafs
with leafs LFi
1 , LFi 2 , LFi 3
common refinement = collection of rays LF1
i1 ∩ . . . ∩ LFd−1 id−1
with leafs LFi
1 , LFi 2 , LFi 3
common refinement = collection of rays LF1
i1 ∩ . . . ∩ LFd−1 id−1
with leafs LFi
1 , LFi 2 , LFi 3
common refinement = collection of rays LF1
i1 ∩ . . . ∩ LFd−1 id−1
P1 + P2 + . . . + Pk = {p1 + p2 + . . . + pk | pi ∈ Pi} ⊆ Rd
P1 + P2 + . . . + Pk = {p1 + p2 + . . . + pk | pi ∈ Pi} ⊆ Rd
P1 + P2 + . . . + Pk = {p1 + p2 + . . . + pk | pi ∈ Pi} ⊆ Rd
P1 + P2 + . . . + Pk = {p1 + p2 + . . . + pk | pi ∈ Pi} ⊆ Rd
with leafs LFi
1 , LFi 2 , LFi 3
common refinement = collection of rays LF1
i1 ∩ . . . ∩ LFd−1 id−1
with leafs LFi
1 , LFi 2 , LFi 3
common refinement = collection of rays LF1
i1 ∩ . . . ∩ LFd−1 id−1
Minkowski sum which correspond to a Minkow. sum of facets
= hitting simplices of the associated colorful Gale transform
i=1 (|Ci| − 1) becomes 1 + 2d−1
⇒ Burton’s conjecture is true!!
Lemma : βd−1(B, Z2) = 1
hence βd−1(B) = 1.
Lemma : βd−1(B, Z2) = 1
hence βd−1(B) = 1.
Lemma : βd−1(B, Z2) = 1
hence βd−1(B) = 1.
Lemma : βd−1(B, Z2) = 1
hence βd−1(B) = 1.
Definition
Let x ∈ Ci be a point.
Definition
Let x ∈ Ci be a point. H is a flipping hyperplane for x if H = aff
any j = j′.
Definition
Let x ∈ Ci be a point. H is a flipping hyperplane for x if H = aff
any j = j′.
x
Definition
Let x ∈ Ci be a point. H is a flipping hyperplane for x if H = aff
any j = j′.
x Definition
A flip (of a colored point x): x x′ s.t. the line segment xx′ crosses at most one flipping hyperplane
Definition
Let x ∈ Ci be a point. H is a flipping hyperplane for x if H = aff
any j = j′.
x′ Definition
A flip (of a colored point x): x x′ s.t. the line segment xx′ crosses at most one flipping hyperplane
Definition
A flip is called
1 safe, if the line segment xx′ does not cross any flipping
hyperplane
x x′ x0
Definition
A flip is called
1 safe, if the line segment xx′ does not cross any flipping
hyperplane
2 mild, if the line segment xx′ does cross a flipping hyperplane
aff{0, x0, x1, . . . , xd−2} and 0 / ∈ conv{x, x′, x0, x1, . . . , xd−2}
x x′ x0 x x′ x0
Definition
A flip is called
1 safe, if the line segment xx′ does not cross any flipping
hyperplane
2 mild, if the line segment xx′ does cross a flipping hyperplane
aff{0, x0, x1, . . . , xd−2} and 0 / ∈ conv{x, x′, x0, x1, . . . , xd−2}
3 wild, otherwise
x x′ x0 x x′ x0 x x′ x0
1 a safe flip preserves B
⇒ it preserves βd−1(B)
1 a safe flip preserves B
⇒ it preserves βd−1(B) ⇒ we may assume that all the points are in general position
1 a safe flip preserves B
⇒ it preserves βd−1(B) ⇒ we may assume that all the points are in general position
2 a mild flip preserves B
⇒ it preserves βd−1(B)
1 a safe flip preserves B
⇒ it preserves βd−1(B) ⇒ we may assume that all the points are in general position
2 a mild flip preserves B
⇒ it preserves βd−1(B)
x x′
1 a safe flip preserves B
⇒ it preserves βd−1(B) ⇒ we may assume that all the points are in general position
2 a mild flip preserves B
⇒ it preserves βd−1(B)
x x′
1 a safe flip preserves B
⇒ it preserves βd−1(B) ⇒ we may assume that all the points are in general position
2 a mild flip preserves B
⇒ it preserves βd−1(B)
x x′
Wild flips do change B. B′ = simpl. complex after the flip σ0 a d-simplex present in B′ and not in B
Wild flips do change B. B′ = simpl. complex after the flip σ0 a d-simplex present in B′ and not in B
Wild flips do change B. B′ = simpl. complex after the flip σ0 a d-simplex present in B′ and not in B
Wild flips do change B. B′ = simpl. complex after the flip σ0 a d-simplex present in B′ and not in B
x x′
Wild flips do change B. B′ = simpl. complex after the flip σ0 a d-simplex present in B′ and not in B
x x′
Wild flips do change B. B′ = simpl. complex after the flip σ0 a d-simplex present in B′ and not in B
x x′
Wild flips do change B. B′ = simpl. complex after the flip σ0 a d-simplex present in B′ and not in B
x x′
Wild flips do change B. B′ = simpl. complex after the flip σ0 a d-simplex present in B′ and not in B
x x′
Wild flips do change B. B′ = simpl. complex after the flip σ0 a d-simplex present in B′ and not in B σ1, . . . , σr all d-simplices that are in B and not in B′
Wild flips do change B. B′ = simpl. complex after the flip σ0 a d-simplex present in B′ and not in B σ1, . . . , σr all d-simplices that are in B and not in B′ τ1, . . . , τs all d-simplices present in both B and B′
Wild flips do change B. B′ = simpl. complex after the flip σ0 a d-simplex present in B′ and not in B σ1, . . . , σr all d-simplices that are in B and not in B′ τ1, . . . , τs all d-simplices present in both B and B′ Since βd−1(B) = 1, every (d − 1)-cycle z in B can be expressed as z =
∂σi +
∂τj, where I ⊆ {0, 1, . . . , r} and J ⊆ {1, . . . , s}.
Wild flips do change B. B′ = simpl. complex after the flip σ0 a d-simplex present in B′ and not in B σ1, . . . , σr all d-simplices that are in B and not in B′ τ1, . . . , τs all d-simplices present in both B and B′ Since βd−1(B) = 1, every (d − 1)-cycle z in B can be expressed as z =
∂σi +
∂τj, where I ⊆ {0, 1, . . . , r} and J ⊆ {1, . . . , s}. ∂τi and ∂σ0 boundaries in B′ ⇒ ∂σ1, . . . , ∂σr generate Hd−1(B′).
Clearly ∂σ1 is not zero homologous, therefore βd−1(B′) ≥ 1. Lemma: For every k > 0, the cycle ∂σ1 + ∂σk is contained in a subcomplex C with βd−1(C) = 0.
Clearly ∂σ1 is not zero homologous, therefore βd−1(B′) ≥ 1. Lemma: For every k > 0, the cycle ∂σ1 + ∂σk is contained in a subcomplex C with βd−1(C) = 0.
Clearly ∂σ1 is not zero homologous, therefore βd−1(B′) ≥ 1. Lemma: For every k > 0, the cycle ∂σ1 + ∂σk is contained in a subcomplex C with βd−1(C) = 0.
x x′
Clearly ∂σ1 is not zero homologous, therefore βd−1(B′) ≥ 1. Lemma: For every k > 0, the cycle ∂σ1 + ∂σk is contained in a subcomplex C with βd−1(C) = 0.
x x′
Clearly ∂σ1 is not zero homologous, therefore βd−1(B′) ≥ 1. Lemma: For every k > 0, the cycle ∂σ1 + ∂σk is contained in a subcomplex C with βd−1(C) = 0.
x x′
Clearly ∂σ1 is not zero homologous, therefore βd−1(B′) ≥ 1. Lemma: For every k > 0, the cycle ∂σ1 + ∂σk is contained in a subcomplex C with βd−1(C) = 0.
x x′
⇒ all (d − 1)-cycles in C are zero homologous
Clearly ∂σ1 is not zero homologous, therefore βd−1(B′) ≥ 1. Lemma: For every k > 0, the cycle ∂σ1 + ∂σk is contained in a subcomplex C with βd−1(C) = 0.
x x′
⇒ all (d − 1)-cycles in C are zero homologous ⇒ ∂σ1 and ∂σk are homologous in B′ for all k and βd−1(B′) = 1 as claimed.
Thank you for your attention!