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Bilateral Market Power & Bargaining
Johan Stennek
Bilateral Market Power & Bargaining Johan Stennek 1 Dont need - - PowerPoint PPT Presentation
Bilateral Market Power & Bargaining Johan Stennek 1 Dont need to know appendixes in lecture notes Bilateral Market Power Example: Food Retailing Food Retailing Food retailers are huge !
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Johan Stennek
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! The!world’s!largest!food!retailers!in!2003! Company! Food!Sales!
(US$mn)!
Wal$Mart( 121(566( Carrefour( 77(330( Ahold( 72(414( Tesco( 40(907( Kroger( 39(320( Rewe( 36(483( Aldi( 36(189( Ito$Yokado( 35(812( Metro(Group(ITM( 34(700(
(
½ Swedish GDP
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Tabell&1a.&Dagligvarukedjornas&andel&av&den&svenska&marknaden& Kedja& Butiker& (antal)& Butiksyta& (kvm)& Omsättning& (miljarder&kr)& Axfood& 803&
(24%)&
625&855&
(18%)&
34,6&&&&&&&&&
(18%)&
Bergendahls& 229&
(7%)&
328&196&
(10%)&
13,6&
(7%)&
Coop& 730&
(22%)&
983&255&
(29%)&
41,4&
(21%)&
ICA& 1&379&
(41%)&
1&240&602&
(36%)&
96,6&
(50%)&
Lidl& 146&
(4%)&
170&767&
(5%)&
5,2&&&&&&&&&
(3%)&
Netto& 105&
(3%)&
70&603&
(2%)&
3,0&
(2%)&
&
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Retailer( Market(Share(
(CC#Table#5:3,#p.#44)#
Price(
(CC#Table#5,#p.#435)#
Tesco# 24.6# 100.0# Sainsbury# 20.7# 101.6# Asda# 13.4# 102.3# Somerfield# 8.5# 103.0# Safeway# 12.5# 103.1# Morrison# 4.3# 104.6# Iceland# 0.1# 105.3# Waitrose# 3.3# 109.4# Booth# 0.1# 109.5# Netto# 0.5# 110.1# Budgens# 0.4# 111.1#
#
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– One Seller: MC(q) = inverse supply if price taker – One Buyer: MV(q)
= inverse demand if price taker q € MC(q) MV(q)
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q € MC(q) MV(q) q* S*
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q € MC(q) MV(q) q* S*
Efficiency from the point of view of the two firms = Same quantity as a vertically integrated firm would choose
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– But what price?
– Seller must cover his costs, C(q*) – Buyer must not pay more than wtp, V(q*) => Any split of S* = V(q*) – C(q*) seems reasonable
q € MC(q) MV(q) q* S*
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– If someone demands “too much” – The other side will reject and make a counter-offer
– Haggling could go on forever – Gains from trade delayed
– Both sides have incentive to be reasonable – Party with less aversion to delay has strategic advantage
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– Efficient quantity: q* – Walrasian price: pw – Maximum bilateral surplus: S* q € MC(q) MV(q) q* pw S*
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– Contract must specify both price and quantity, (p, q) – Q: Why? – Otherwise inefficiency (If p > pw then q < q*) q € MC(q) MV(q) q* pw S*
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– One party, say seller, gets to propose a contract (p, q) – Other party, say buyer, can accept or reject
– If (p, q) accepted, it is implemented – Otherwise game ends without agreement
– Buyer: V(q) – p q if agreement, zero otherwise – Seller: p q – C(q) if agreement, zero otherwise
– Backwards induction
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– Buyer accepts proposed contract (p, q) iff V(q) – p q ≥ 0
– Seller: maxp,q p q – C(q) such that V(q) – p q ≥ 0
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max p,q p q – C(q) st : V(q) – p q ≥ 0
Must set p such that: p ⋅q = V(q)
maxq V(q) – C(q)
Must set q such that: MV q
( ) = MC(q)
Seller takes whole surplus Efficient quanHty
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– Unique equilibrium – There is agreement – Efficient quantity – Proposer takes the whole (maximal) surplus
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– Always efficient quantity – Surplus = 1 – Player S gets share πS – Player B gets share πB = 1 – πS
– πS = 1 – πB = 0
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– For B: €1 in period 2 is equally good as €δB in period 1 – Where δB, δS < 1 are discount factors
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– B proposes – S accepts or rejects
– S proposes – B accepts or rejects
π B
T ,π S T
( )
π B
T −1,π S T −1
( )
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– B accepts iff: – S proposes:
– S accepts iff: – B proposes:
– S willing to reduce his share to get an early agreement – Both players get part of surplus – B’s share determined by S’s impatience. If S very patient πS≈1
π B
T ≥ 0
π B
T = 0
π S
T = 1
π S
T −1 ≥ δSπ S T
= δS < 1 π B
T −1 = 1− δS > 0
π S
T −1 = δS
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– Large number of periods, T – Buyer and seller take turns to make offer – Common discount factor δ = δB = δS – Subgame perfect equilibrium (ie start analysis in last period)
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Time Bidder πB πS Resp. T S ? ? ?
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Time Bidder πB πS Resp. T S 1 yes
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Time Bidder πB πS Resp. T S 1 yes T-1 B ? ? ?
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Time Bidder πB πS Resp. T S 1 yes T-1 B rest δ yes
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Time Bidder πB πS Resp. T S 1 yes T-1 B 1-δ δ yes
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Time Bidder πB πS Resp. T S 1 yes T-1 B 1-δ δ yes T-2 S ? ? ?
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Time Bidder πB πS Resp. T S 1 yes T-1 B 1-δ δ yes T-2 S δ(1-δ) rest yes
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Time Bidder πB πS Resp. T S 1 yes T-1 B 1-δ δ yes T-2 S δ(1-δ) 1-δ(1-δ) yes
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Time Bidder πB πS Resp. T S 1 yes T-1 B 1-δ δ yes T-2 S δ(1-δ) 1-δ(1-δ) yes multiply
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Time Bidder πB πS Resp. T S 1 yes T-1 B 1-δ δ yes T-2 S δ-δ2 1-δ+δ2 yes
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Time Bidder πB πS Resp. T S 1 yes T-1 B 1-δ δ yes T-2 S δ-δ2 1-δ+δ2 yes T-3 B ? ? ?
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Time Bidder πB πS Resp. T S 1 yes T-1 B 1-δ δ yes T-2 S δ-δ2 1-δ+δ2 yes T-3 B rest δ(1-δ+δ2) yes
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Time Bidder πB πS Resp. T S 1 yes T-1 B 1-δ δ yes T-2 S δ-δ2 1-δ+δ2 yes T-3 B 1-δ(1-δ+δ2) δ(1-δ+δ2) yes
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Time Bidder πB πS Resp. T S 1 yes T-1 B 1-δ δ yes T-2 S δ-δ2 1-δ+δ2 yes T-3 B 1-δ+δ2-δ3 δ-δ2+δ3 yes
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Time Bidder πB πS Resp. T S 1 yes T-1 B 1-δ δ yes T-2 S δ-δ2 1-δ+δ2 yes T-3 B 1-δ+δ2-δ3 δ-δ2+δ3 yes T-4 S δ(1-δ+δ2-δ3) rest yes
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Time Bidder πB πS Resp. T S 1 yes T-1 B 1-δ δ yes T-2 S δ-δ2 1-δ+δ2 yes T-3 B 1-δ+δ2-δ3 δ-δ2+δ3 yes T-4 S δ(1-δ+δ2-δ3) 1-δ(1-δ+δ2-δ3) yes
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Time Bidder πB πS Resp. T S 1 yes T-1 B 1-δ δ yes T-2 S δ-δ2 1-δ+δ2 yes T-3 B 1-δ+δ2-δ3 δ-δ2+δ3 yes T-4 S δ-δ2+δ3-δ4 1-δ+δ2-δ3+δ4 yes
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Time Bidder πB πS Resp. T S 1 yes T-1 B 1-δ δ yes T-2 S δ-δ2 1-δ+δ2 yes T-3 B 1-δ+δ2-δ3 δ-δ2+δ3 yes T-4 S δ-δ2+δ3-δ4 1-δ+δ2-δ3+δ4 yes … …
… …
… 1 S
δ-δ2+δ3-δ4+…-δT-1 1-δ+δ2-δ3+δ4-…+δT-1
yes
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Time Bidder πB πS Resp. T S 1 yes T-1 B 1-δ δ yes T-2 S δ-δ2 1-δ+δ2 yes T-3 B 1-δ+δ2-δ3 δ-δ2+δ3 yes T-4 S δ-δ2+δ3-δ4 1-δ+δ2-δ3+δ4 yes … …
… …
… 1 S
δ-δ2+δ3-δ4+…-δT-1 1-δ+δ2-δ3+δ4-…+δT-1
yes
π B = δ − δ 2 + δ 3 − δ 4 + ...− δ T −1 π S = 1− δ + δ 2 − δ 3 + δ 4 − ...+ δ T −1
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Geometric series π B = δ − δ 2 + δ 3 − δ 4 + ...− δ T −1 π S = 1− δ + δ 2 − δ 3 + δ 4 − ...+ δ T −1
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S's share π S = 1− δ + δ 2 − δ 3 + δ 4 − ...+ δ T −1
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S's share π S = 1− δ + δ 2 − δ 3 + δ 4 − ...+ δ T −1 Multiply δπ S = δ − δ 2 + δ 3 − δ 4 + δ 5 − ...+ δ T
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S's share π S = 1− δ + δ 2 − δ 3 + δ 4 − ...+ δ T −1 Multiply δπ S = δ − δ 2 + δ 3 − δ 4 + δ 5 − ...+ δ T Add π S + δπ S = 1+ δ T
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S's share π S = 1− δ + δ 2 − δ 3 + δ 4 − ...+ δ T −1 Multiply δπ S = δ − δ 2 + δ 3 − δ 4 + δ 5 − ...+ δ T Add π S + δπ S = 1+ δ T Solve π S = 1+ δ T 1+ δ
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Equilibrium shares with T periods π S = 1 1+ δ 1+ δ T
( )
π B = δ 1+ δ 1− δ T −1
( )
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Equilibrium shares with T periods π S = 1 1+ δ 1+ δ T
( )
π B = δ 1+ δ 1− δ T −1
( )
S has advantage of making last bid 1+ δ T > 1− δ T −1 To confirm this, solve model where
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Equilibrium shares with T periods π S = 1 1+ δ 1+ δ T
( )
π B = δ 1+ δ 1− δ T −1
( )
S has advantage of making last bid 1+ δ T > 1− δ T −1 Disappears if T very large
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Equilibrium shares with T ≈ ∞ periods π S = 1 1+ δ π B = δ 1+ δ S has advantage of making first bid 1 1+ δ > δ 1+ δ To confirm this, solve model where
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Equilibrium shares with T ≈ ∞ periods π S = 1 1+ δ π B = δ 1+ δ S has advantage of making first bid 1 1+ δ > δ 1+ δ To confirm this, solve model where
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Equilibrium shares with T ≈ ∞ periods π S = 1 1+ δ π B = δ 1+ δ S has advantage of making first bid 1 1+ δ > δ 1+ δ First bidder’s advantage disappears if δ ≈ 1
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Equilibrium shares with T ≈ ∞ periods and very patient players (δ ≈ 1) π S = 1 2 π B = 1 2
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Equilibrium shares with T ≈ ∞ periods and different discount factors π S = 1− δB 1− δSδB π B = 1− δS 1− δSδB δB (Easy to show using same method as above)
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– ri = continous-time discount factor – Δ = length of time period
– – Using l’Hopital’s rule
δi = e−r
iΔ
π S = 1− δ B 1− δSδ B ≈ rB r
S + rB
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– Exists unique equilibrium (SPE) – There is agreement – Agreement is immediate – Efficient agreement (here: quantity) – Split of surplus (price) determined by relative patience
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ΠS = ΠB p ⋅q − C q
( ) = V q ( ) − p ⋅q
2 ⋅ p ⋅q = V q
( ) + C q ( )
p = 1 2 V q
( )
q + C q
( )
q ⎡ ⎣ ⎢ ⎤ ⎦ ⎥
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ΠS = ΠB p ⋅q − C q
( ) = V q ( ) − p ⋅q
2 ⋅ p ⋅q = V q
( ) + C q ( )
p = 1 2 V q
( )
q + C q
( )
q ⎡ ⎣ ⎢ ⎤ ⎦ ⎥
Retailer’s average revenues
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ΠS = ΠB p ⋅q − C q
( ) = V q ( ) − p ⋅q
2 ⋅ p ⋅q = V q
( ) + C q ( )
p = 1 2 V q
( )
q + C q
( )
q ⎡ ⎣ ⎢ ⎤ ⎦ ⎥
Manufacturer’s average costs
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ΠS = ΠB p ⋅q − C q
( ) = V q ( ) − p ⋅q
2 ⋅ p ⋅q = V q
( ) + C q ( )
p = 1 2 V q
( )
q + C q
( )
q ⎡ ⎣ ⎢ ⎤ ⎦ ⎥
The firms share the Retailer’s revenues and the Manufacturer’s costs equally
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– Intuitive – But tedious
– Less intuitive – But easier to find the same outcome
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1. Describe bargaining situation 2. Define Nash product 3. Maximize Nash product
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1. Who are the two players? 2. What contracts can they agree upon? 3. What payoff would they get from every possible contract? 4. What payoff do they have before agreement? 5. What is their relative patience (= bargaining power)
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– Players: Manufacturer and Retailer – Contracts: (T, q) – Payoffs:
– Payoff if there is no agreement (while negotiating)
– Same patience => same bargaining power
! π R = 0 ! π M = 0
π R T,q
π M T,q
T = total price for q units.
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N T,q
π R ⎡ ⎣ ⎤ ⎦ ⋅ π M T,q
π M ⎡ ⎣ ⎤ ⎦
Retailer’s profit from contract Manufacturer’s profit from contract
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N T,q
π R ⎡ ⎣ ⎤ ⎦ ⋅ π M T,q
π M ⎡ ⎣ ⎤ ⎦
Retailer’s extra profit from contract Manufacturer’s extra profit from contract
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N T,q
π R ⎡ ⎣ ⎤ ⎦ ⋅ π M T,q
π M ⎡ ⎣ ⎤ ⎦
Nash product
Depends on contract
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N T,q
π R ⎡ ⎣ ⎤ ⎦ ⋅ π M T,q
π M ⎡ ⎣ ⎤ ⎦
Claim: The contract (T, q) maximizing N is the same contract that the parties would agree upon in an extensive form bargaining game!
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N T,q
( ) = π R T,q ( ) − !
π R ⎡ ⎣ ⎤ ⎦ ⋅ π M T,q
( ) − !
π M ⎡ ⎣ ⎤ ⎦ N T,q
( ) = V q ( ) − T
⎡ ⎣ ⎤ ⎦ ⋅ T − C q
( )
⎡ ⎣ ⎤ ⎦
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N T,q
( ) = V q ( ) − T
⎡ ⎣ ⎤ ⎦ ⋅ T − C q
( )
⎡ ⎣ ⎤ ⎦ ∂N ∂T = − T − C q
( )
⎡ ⎣ ⎤ ⎦ + V q
( ) − T
⎡ ⎣ ⎤ ⎦ = 0 ⇒ T = 1
2 V q
( ) + C q ( )
⎡ ⎣ ⎤ ⎦ ⇒ p = 1
2
V q
( )
q + C q
( )
q ⎡ ⎣ ⎢ ⎤ ⎦ ⎥
Equal profits = Equal split of surplus
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N T,q
( ) = V q ( ) − T
⎡ ⎣ ⎤ ⎦ ⋅ T − C q
( )
⎡ ⎣ ⎤ ⎦ ∂N ∂T = − T − C q
( )
⎡ ⎣ ⎤ ⎦ + V q
( ) − T
⎡ ⎣ ⎤ ⎦ = 0 ⇒ T = 1
2 V q
( ) + C q ( )
⎡ ⎣ ⎤ ⎦ ⇒ p = 1
2
V q
( )
q + C q
( )
q ⎡ ⎣ ⎢ ⎤ ⎦ ⎥
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N T,q
( ) = V q ( ) − T
⎡ ⎣ ⎤ ⎦ ⋅ T − C q
( )
⎡ ⎣ ⎤ ⎦ ∂N ∂T = − T − C q
( )
⎡ ⎣ ⎤ ⎦ + V q
( ) − T
⎡ ⎣ ⎤ ⎦ = 0 ⇒ T = 1
2 V q
( ) + C q ( )
⎡ ⎣ ⎤ ⎦ ⇒ p = 1
2
V q
( )
q + C q
( )
q ⎡ ⎣ ⎢ ⎤ ⎦ ⎥
Convert to price per unit.
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N T,q
( ) = V q ( ) − T
⎡ ⎣ ⎤ ⎦ ⋅ T − C q
( )
⎡ ⎣ ⎤ ⎦ ∂N ∂T = − T − C q
( )
⎡ ⎣ ⎤ ⎦ + V q
( ) − T
⎡ ⎣ ⎤ ⎦ = 0 ∂N ∂q = V ' q
( )⋅ T − C q ( )
⎡ ⎣ ⎤ ⎦ − C' q
( )⋅ V q ( ) − T
⎡ ⎣ ⎤ ⎦ = 0 ⇒ V ' q
( ) = C' q ( )
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N T,q
( ) = V q ( ) − T
⎡ ⎣ ⎤ ⎦ ⋅ T − C q
( )
⎡ ⎣ ⎤ ⎦ ∂N ∂T = − T − C q
( )
⎡ ⎣ ⎤ ⎦ + V q
( ) − T
⎡ ⎣ ⎤ ⎦ = 0 ∂N ∂q = V ' q
( )⋅ T − C q ( )
⎡ ⎣ ⎤ ⎦ − C' q
( )⋅ V q ( ) − T
⎡ ⎣ ⎤ ⎦ = 0 ⇒ V ' q
( ) = C' q ( )
Efficiency
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– Maximizing Nash product is easy way to find equilibrium – Efficient quantity – Price splits surplus equally
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N T,q
π R ⎡ ⎣ ⎤ ⎦
β ⋅ π M T,q
π M ⎡ ⎣ ⎤ ⎦
1−β
Exponents determined by relative patience
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Manufacturer Retailer 1 Retailer 2 Consumers Consumers
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Manufacturer Retailer 1 Retailer 2 Consumers Consumers
π1 T1,q1
( ) = V q1 ( ) − T1
π 2 T2,q2
( ) = V q2 ( ) − T2
Retailers independent
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Manufacturer Retailer 1 Retailer 2 Consumers Consumers
π1 T1,q1
( ) = V q1 ( ) − T1
π 2 T2,q2
( ) = V q2 ( ) − T2
π M T1,T2,q1,q2
( ) = T1 + T2 − C q1 + q2 ( )
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– Contracts: (T1, q1)
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– Contracts: (T1, q1) – Payoffs:
π1 T1,q1
π M T1,T2,q1,q2
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– Contracts: (T1, q1) – Payoffs:
– Payoff if no agreement
! π1 = 0 ! π M = T2 − C q2
( )
π1 T1,q1
π M T1,T2,q1,q2
Manufacturer only supplies
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– Contracts: (T1, q1) – Payoffs:
– Payoff while negotiating
– Same patience => same bargaining power
! π1 = 0 ! π M = T2 − C q2
( )
π1 T1,q1
π M T1,T2,q1,q2
Manufacturer only supplies
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N T1,q1
( ) = π R T1,q1 ( ) − !
π R ⎡ ⎣ ⎤ ⎦ ⋅ π M T1,T2,q1,q2
( ) − !
π M ⎡ ⎣ ⎤ ⎦ N T1,q1
( ) = V q1 ( ) − T1
⎡ ⎣ ⎤ ⎦ ⋅ T1 + T2 − C q1 + q2
( )
{ } − T2 − C q2
( )
{ }
⎡ ⎣ ⎤ ⎦ N T1,q1
( ) = V q1 ( ) − T1
⎡ ⎣ ⎤ ⎦ ⋅ T1 − C q1 + q2
( ) − C q2 ( )
{ }
⎡ ⎣ ⎤ ⎦
Incremental cost
96
N T1,q1
( ) = π R T1,q1 ( ) − !
π R ⎡ ⎣ ⎤ ⎦ ⋅ π M T1,T2,q1,q2
( ) − !
π M ⎡ ⎣ ⎤ ⎦ N T1,q1
( ) = V q1 ( ) − T1
⎡ ⎣ ⎤ ⎦ ⋅ T1 + T2 − C q1 + q2
( )
{ } − T2 − C q2
( )
{ }
⎡ ⎣ ⎤ ⎦ N T1,q1
( ) = V q1 ( ) − T1
⎡ ⎣ ⎤ ⎦ ⋅ T1 − C q1 + q2
( ) − C q2 ( )
{ }
⎡ ⎣ ⎤ ⎦
Incremental cost
97
N T1,q1
( ) = π R T1,q1 ( ) − !
π R ⎡ ⎣ ⎤ ⎦ ⋅ π M T1,T2,q1,q2
( ) − !
π M ⎡ ⎣ ⎤ ⎦ N T1,q1
( ) = V q1 ( ) − T1
⎡ ⎣ ⎤ ⎦ ⋅ T1 + T2 − C q1 + q2
( )
{ } − T2 − C q2
( )
{ }
⎡ ⎣ ⎤ ⎦ N T1,q1
( ) = V q1 ( ) − T1
⎡ ⎣ ⎤ ⎦ ⋅ T1 − C q1 + q2
( ) − C q2 ( )
{ }
⎡ ⎣ ⎤ ⎦
Incremental cost
98
N T1,q1
( ) = π R T1,q1 ( ) − !
π R ⎡ ⎣ ⎤ ⎦ ⋅ π M T1,T2,q1,q2
( ) − !
π M ⎡ ⎣ ⎤ ⎦ N T1,q1
( ) = V q1 ( ) − T1
⎡ ⎣ ⎤ ⎦ ⋅ T1 + T2 − C q1 + q2
( )
{ } − T2 − C q2
( )
{ }
⎡ ⎣ ⎤ ⎦ N T1,q1
( ) = V q1 ( ) − T1
⎡ ⎣ ⎤ ⎦ ⋅ T1 − C q1 + q2
( ) − C q2 ( )
{ }
⎡ ⎣ ⎤ ⎦
Incremental cost
99
N T1,q1
( ) = V q1 ( ) − T1
⎡ ⎣ ⎤ ⎦ ⋅ T1 − C q1 + q2
( ) − C q2 ( )
{ }
⎡ ⎣ ⎤ ⎦ ∂N ∂T1 = T1 − C q1 + q2
( ) − C q2 ( )
{ }
⎡ ⎣ ⎤ ⎦ − V q1
( ) − T1
⎡ ⎣ ⎤ ⎦ = 0 ⇒ T1 = 1
2 V q1
( ) + C q1 + q2 ( ) − C q2 ( )
{ }
⎡ ⎣ ⎤ ⎦ ⇒ p1 = 1
2
V q1
( )
q1 + C q1 + q2
( ) − C q2 ( )
q1 ⎡ ⎣ ⎢ ⎤ ⎦ ⎥
Average incremental cost
100
p1 = 1
2 6 + C q1 + q2
( )− C q2 ( )
q1 ⎡ ⎣ ⎢ ⎤ ⎦ ⎥
Example
1 2 3 4 5 6 7 8 9 10 10 1 2 3 4 5 6 7 8 9
Quantity € MC(q) MV(q)
Average incremental cost
101
1 2 3 4 5 6 7 8 9 10 10 1 2 3 4 5 6 7 8 9
Quantity €
MC(q) MV(q)
Incremental Cost
Units sold to other firm
Retailer 1
buys 4 units
Example
p1 = 1
2 6 + C q1 + q2
( )− C q2 ( )
q1 ⎡ ⎣ ⎢ ⎤ ⎦ ⎥ = 1
2 6 + 16
4 ⎡ ⎣ ⎢ ⎤ ⎦ ⎥ = 5
102
103
1 2 3 4 5 6 7 8 9 10 10 1 2 3 4 5 6 7 8 9
Quantity € MC(q) MV(q)
Incremental Cost
Units sold to other firm
Retailer 2
buys 2 units
1 2 3 4 5 6 7 8 9 10 10 1 2 3 4 5 6 7 8 9
Quantity € MC(q) MV(q)
Incremental Cost
Units sold to other firm
Retailer 1
buys 4 units
104
1 2 3 4 5 6 7 8 9 10 10 1 2 3 4 5 6 7 8 9
Quantity € MC(q) MV(q)
Incremental Cost
Units sold to other firm
Retailer 2
buys 2 units
1 2 3 4 5 6 7 8 9 10 10 1 2 3 4 5 6 7 8 9
Quantity € MC(q) MV(q)
Incremental Cost
Units sold to other firm
Retailer 1
buys 4 units
105
1 2 3 4 5 6 7 8 9 10 10 1 2 3 4 5 6 7 8 9
Quantity € MC(q) MV(q)
Incremental Cost
Units sold to other firm
Retailer 2
buys 2 units
1 2 3 4 5 6 7 8 9 10 10 1 2 3 4 5 6 7 8 9
Quantity € MC(q) MV(q)
Incremental Cost
Units sold to other firm
Retailer 1
buys 4 units
p1 = 1
2 6 + C q1 + q2
( )− C q2 ( )
q1 ⎡ ⎣ ⎢ ⎤ ⎦ ⎥ = 1
2 6 + 1 2 ⋅36 − 1 2 ⋅4
4 ⎡ ⎣ ⎢ ⎤ ⎦ ⎥ = 1
2 6 + 16
4 ⎡ ⎣ ⎢ ⎤ ⎦ ⎥ = 5
p2 = 1
2 6 + C q1 + q2
( )− C q1 ( )
q1 ⎡ ⎣ ⎢ ⎤ ⎦ ⎥ = 1
2 6 + 1 2 ⋅36 − 1 2 ⋅16
2 ⎡ ⎣ ⎢ ⎤ ⎦ ⎥ = 1
2 6 + 10
2 ⎡ ⎣ ⎢ ⎤ ⎦ ⎥ = 5.5
106
N T1,q1
( ) = V q1 ( ) − T1
⎡ ⎣ ⎤ ⎦ ⋅ T1 − C q1 + q2
( ) − C q2 ( )
{ }
⎡ ⎣ ⎤ ⎦ ∂N ∂q1 = V ' q1
( )⋅ T1 − C q1 + q2 ( ) − C q2 ( )
{ }
⎡ ⎣ ⎤ ⎦ + C' q1 + q2
( )⋅ V q1 ( ) − T1
⎡ ⎣ ⎤ ⎦ = 0 ⇒ V ' q1
( ) = C' q1 + q2 ( )
Bilateral Efficiency
107
V ' q1
( ) = C' q1 + q2 ( )
V ' q2
( ) = C' q1 + q2 ( )
⎫ ⎬ ⎪ ⎪ ⎭ ⎪ ⎪ ⇒ V ' q1
( ) = V ' q2 ( )
Bilateral efficiency 1 Bilateral efficiency 2
108
V ' q1
( ) = C' q1 + q2 ( )
V ' q2
( ) = C' q1 + q2 ( )
⎫ ⎬ ⎪ ⎪ ⎭ ⎪ ⎪ ⇒ V ' q1
( ) = V ' q2 ( )
Overall market efficiency
109
– Prices of homogenous goods may differ
– Market with bilateral market power may be efficient