axial vectors and transversal short distance constraints
play

Axial vectors and transversal short-distance constraints Martin - PowerPoint PPT Presentation

Axial vectors and transversal short-distance constraints Martin Hoferichter Institute for Nuclear Theory University of Washington Third Plenary Workshop of the Muon g 2 Theory Initiative INT Workshop on Hadronic contributions to ( g 2 )


  1. Axial vectors and transversal short-distance constraints Martin Hoferichter Institute for Nuclear Theory University of Washington Third Plenary Workshop of the Muon g − 2 Theory Initiative INT Workshop on Hadronic contributions to ( g − 2 ) µ Seattle, September 12, 2019 M. Hoferichter (Institute for Nuclear Theory) Axials and transversal SDCs Seattle, September 12, 2019 1

  2. Motivation Short-distance constraints for mixed region: OPE, VVA anomaly Melnikov, Vainshtein 2004 Mapping onto BTT see my talk from Mainz meeting Longitudinal constraints: ˆ Π 1–3 , related to pseudoscalar poles see talk by L. Laub Transversal constraints: all other ˆ Π i Status of the axial vectors a 1 ( 1260 ) , f 1 ( 1285 ) , f ′ 1 ( 1420 ) a 1 + f 1 + f ′ MV = 22 × 10 − 11 (used to saturate transversal SDCs) � Large in MV: a 1 µ � Jegerlehner 2017 : MV model violates Landau–Yang theorem a 1 + f 1 + f ′ 1 � J = 8 × 10 − 11 ֒ → introduces antisymmetrization by hand ⇒ a µ � f 1 + f ′ � PV = 6 × 10 − 11 1 Pauk, Vanderhaeghen 2014 : Lagrangian model, a µ � This talk: BTT decomposition for axials Mapping of MV model onto BTT ֒ → clarify Landau–Yang, explain why MV number is so large M. Hoferichter (Institute for Nuclear Theory) Axials and transversal SDCs Seattle, September 12, 2019 2

  3. Axial vectors: matrix element Decomposition of A → γ ∗ γ ∗ amplitude � γ ∗ ( q 1 , λ 1 ) γ ∗ ( q 2 , λ 2 ) | A ( p , λ A ) � = i ( 2 π ) 4 δ ( 4 ) ( q 1 + q 2 − p ) e 2 ǫ λ 1 ∗ ǫ λ 2 ∗ ǫ λ A α M µνα ( q 1 , q 2 ) µ ν 3 i M µνα ( q 1 , q 2 ) = � T µνα F i ( q 2 1 , q 2 2 ) m 2 i A i = 1 → three form factors F i ( q 2 1 , q 2 ֒ 2 ) Lorentz structures from BTT recipe T µνα = ǫ µνβγ q 1 β q 2 γ ( q α 1 − q α 2 ) 1 T µνα = ǫ ανβγ q 1 β q 2 γ q µ 1 + ǫ αµνβ q 2 β q 2 2 1 T µνα = ǫ αµβγ q 1 β q 2 γ q ν 2 + ǫ αµνβ q 1 β q 2 2 3 Crossing properties � = − T µνα � = − T µνα � T µνα � T µνα C 12 C 12 1 1 2 3 F 1 ( q 2 1 , q 2 2 ) = −F 1 ( q 2 2 , q 2 F 2 ( q 2 1 , q 2 2 ) = −F 3 ( q 2 2 , q 2 1 ) 1 ) F 1 ( 0 , 0 ) = 0 F 2 ( 0 , 0 ) = −F 3 ( 0 , 0 ) M. Hoferichter (Institute for Nuclear Theory) Axials and transversal SDCs Seattle, September 12, 2019 3

  4. Axial vectors: phenomenology Landau–Yang in action: 2 ) = λ ( m 2 A , q 2 1 , q 2 2 ) − q 2 1 ( m 2 A − q 2 1 + q 2 2 ) − q 2 2 ( m 2 A + q 2 1 − q 2 2 ) 2 ) 2 ) H ++ ( q 2 1 , q 2 F 1 ( q 2 1 , q 2 F 2 ( q 2 1 , q 2 F 3 ( q 2 1 , q 2 2 ) 2 m 3 2 m 3 2 m 3 A A A q 2 1 , q 2 → 0 for 2 → 0 Equivalent two-photon photon width m 2 L γ T ) = πα 2 m A 1 � 2 ˜ A � � Γ γγ = lim 2 Γ( A → γ ∗ � F 2 ( 0 , 0 ) q 2 12 q 2 1 → 0 1 Experimental input from e + e − → e + e − f 1 ( ′ ) L3 2002, 2007 ˜ ˜ Γ γγ ( f 1 ) = 3 . 5 ( 8 ) keV Γ γγ ( f ′ 1 ) BR ( f ′ 1 → KK π ) = 3 . 2 ( 9 ) keV Λ D ( f ′ Λ D ( f 1 ) = 1 . 04 ( 8 ) GeV 1 ) = 0 . 93 ( 8 ) GeV assuming Schuler et al. 1998 � − 2 F 2 ( − Q 2 , 0 ) 1 + Q 2 � F 1 ( − Q 2 , 0 ) = 0 = Λ 2 F 2 ( 0 , 0 ) D M. Hoferichter (Institute for Nuclear Theory) Axials and transversal SDCs Seattle, September 12, 2019 4

  5. Axial vectors: mixing and SU ( 3 ) Mixing of f 1 and f ′ 1        f 0  f 1  cos θ A sin θ A  = 1   f 8 f ′ − sin θ A cos θ A 1 1 Mixing angle ˜ = m f 1 Γ γγ ( f 1 ) θ 0 = arcsin 1 cot 2 ( θ A − θ 0 ) θ A = 62 ( 5 ) ◦ ˜ Γ γγ ( f ′ 1 ) m f ′ 3 1 Assume SU ( 3 ) symmetry for axial nonet φ √ √ Tr ( Q 2 φ ) = 1 � � 6 f 0 3 f 8 3 a 1 + 2 1 + 1 9 ˜ ˜ Γ γγ ( f ′ Γ γγ ( f 1 ) m a 1 1 ) m a 1 ˜ Γ γγ ( a 1 ) = = = 2 . 1 keV 3 cos 2 ( θ A − θ 0 ) 3 sin 2 ( θ A − θ 0 ) m f 1 m f ′ 1 M. Hoferichter (Institute for Nuclear Theory) Axials and transversal SDCs Seattle, September 12, 2019 5

  6. BTT projection of MV constraints MV constraint for q 2 3 ≪ q 2 1 ∼ q 2 2 , ˆ q = ( q 1 − q 2 ) / 2 ˆ Π 1 = 2 w L ( q 2 q 2 ) 3 ) f (ˆ Π 5 = ˆ ˆ Π 6 = w T ( q 2 q 2 ) 3 ) f (ˆ 1 Π 10 = ˆ ˆ Π 14 = − ˆ Π 17 = − ˆ Π 39 = − ˆ Π 50 = − ˆ w T ( q 2 q 2 ) 3 ) f (ˆ Π 51 = q 1 · q 2 ˆ Π i = 0 i ∈ { 2 , 3 , 4 , 7 , 8 , 9 , 11 , 13 , 16 , 54 } where 1 1 C 3 = 1 1 2 � q 2 ) = − C 2 f (ˆ a = − C 8 = √ C 0 = √ 2 π 2 ˆ q 2 18 π 2 ˆ q 2 6 6 3 3 6 a = 0 , 3 , 8 Non-renormalization theorems and anomaly condition in chiral limit Vainshtein 2003, Czarnecki et al. 2003, Knecht et al. 2004, . . . w L ( q 2 ) = 2 w T ( q 2 ) = 6 q 2 Transversal relation receives non-perturbative corrections M. Hoferichter (Institute for Nuclear Theory) Axials and transversal SDCs Seattle, September 12, 2019 6

  7. Matching onto MV model Saturate transversal constraint from axial exchange, drop longitudinal amplitudes q 2 ˆ 8 1 � � C 2 a w T ( q 2 φ A ( q 2 1 , q 2 2 ) F A 2 ( q 2 3 ) = 3 , 0 ) q 2 ˆ m 4 q 2 3 − m 2 A A a = 0 , 3 , 8 A = a 1 , f 1 , f ′ 1 Λ 4 φ A ( q 2 1 , q 2 2 ) = F A 2 ( q 2 1 , q 2 2 ) + F A 2 ( q 2 2 , q 2 1 ) = 2 F A A 2 ( 0 , 0 ) (Λ 2 A − q 2 1 )(Λ 2 A − q 2 2 ) Conclusions F 2 ( q 2 1 , q 2 2 ) = −F 3 ( q 2 2 , q 2 1 ) , but φ ( q 2 1 , q 2 2 ) indeed symmetric ֒ → additional antisymmetrization in Jegerlehner 2017 incorrect q 4 and F 2 ( q 2 Scaling matches for φ ( q 2 1 , q 2 2 ) ∼ 1 / ˆ 3 , 0 ) → F 2 ( 0 , 0 ) � Λ A ˜ � 4 Λ A = 0 . 77 GeV Γ γγ ( A ) ? � C 2 � 1 = 9 = 9 = 0 . 04 a πα 2 m A m A a = 0 , 3 , 8 A = a 1 , f 1 , f ′ 1 ֒ → axial vectors with VMD not enough to saturate constraint , need Λ A ∼ 1 . 7 GeV M. Hoferichter (Institute for Nuclear Theory) Axials and transversal SDCs Seattle, September 12, 2019 7

  8. Consequences Original MV estimates for different mixing scenarios | MV = ( 5 . 7 + 15 . 6 + 0 . 8 ) × 10 − 11 = 22 × 10 − 11 a ideal µ | MV = ( 5 . 7 + 1 . 9 + 9 . 7 ) × 10 − 11 = 17 × 10 − 11 a octet/singlet µ Comparison in BTT Model only well defined in OPE limit, need to pick kinematics in ˆ Π 4–6 ֒ → key difference to pseudoscalar poles, which are already the proper residues Axial propagators modified to enforce w L ( q 2 ) = 2 w T ( q 2 ) at O ( 1 / q 4 ) ֒ → depends on mixing scheme not only for axials, but also for pseudoscalars For VMD find similar numbers as MV Increasing the VMD scale to correct ˜ Γ γγ decreases a axials by about a factor 3 µ M. Hoferichter (Institute for Nuclear Theory) Axials and transversal SDCs Seattle, September 12, 2019 8

  9. Conclusions MV model does not violate the Landau–Yang theorem , the critical combination of axial form factors is indeed symmetric MV model implies significantly too large two-photon widths ˜ Γ γγ Changing the VMD scale in the model to fix the widths decreases a axials µ All existing estimates for axial vectors are based on Lagrangian assumptions ֒ → need to isolate the residues and study the sum rules Transversal OPE constraint will be helpful for the mixed regions , just as the longitudinal one for the pseudoscalars M. Hoferichter (Institute for Nuclear Theory) Axials and transversal SDCs Seattle, September 12, 2019 9

  10. Outlook: matching to the quark loop 20 Λ = ∞ Red: longitudinal ˆ Π 1–3 , blue: transversal, Λ = 1 GeV 15 Λ = 1 . 35 GeV a µ × 10 11 black: all 10 Integration region θ ( Q 1 − Q min ) θ ( Q 2 − Q min ) θ ( Q 3 − Q min ) 5 Q 2 3 + θ ( Q 1 − Q min ) θ ( Q 2 − Q min ) θ ( Q min − Q 3 ) Q 2 3 + Λ 2 0 1 1.5 2 2.5 3 + crossed Q min [GeV] Regge implementation of longitudinal SDCs see talk by L. Laub µ + ∆ a η ′ ∆ a η ∼ C 2 0 + C 2 µ 8 a LSDC � ∆ a P µ ∼ 12 × 10 − 11 = 3 = µ ∆ a π 0 C 2 µ 3 P = π 0 ,η,η ′ Naive matching to the quark loop for scale Λ ∼ Q min ∼ 1 . 35 GeV → would imply transversal SDCs a TSDC ∼ 4 × 10 − 11 ֒ µ But: axials resonances close to this scale M. Hoferichter (Institute for Nuclear Theory) Axials and transversal SDCs Seattle, September 12, 2019 10

  11. Encore: the charm loop Perturbative QCD quark loops with PDG masses a c -loop = 3 . 1 × 10 − 11 a b -loop = 2 × 10 − 13 a t -loop = 2 × 10 − 15 µ µ µ ֒ → charm loop borderline relevant What about non-perturbative effects ? Lowest-lying c ¯ c resonance: the η c ( 1 S ) m η c ( 1 S ) = 2 . 9839 ( 5 ) GeV Γ( η c ( 1 S ) → γγ ) = 5 . 0 ( 4 ) keV Should couple to J / Ψ , since BR ( J / Ψ → η c ( 1 S ) γ ) = 1 . 7 ( 4 )% significant VMD with Λ = m J / Ψ gives see talk by P . Roig at Mainz meeting a η c ( 1 S ) = 0 . 8 × 10 − 11 µ To avoid double counting take this as the error estimate a c -quark = 3 ( 1 ) × 10 − 11 µ M. Hoferichter (Institute for Nuclear Theory) Axials and transversal SDCs Seattle, September 12, 2019 11

Download Presentation
Download Policy: The content available on the website is offered to you 'AS IS' for your personal information and use only. It cannot be commercialized, licensed, or distributed on other websites without prior consent from the author. To download a presentation, simply click this link. If you encounter any difficulties during the download process, it's possible that the publisher has removed the file from their server.

Recommend


More recommend