- Prof. Girish Kumar
Antenna Fundamentals Prof. Girish Kumar Electrical Engineering - - PowerPoint PPT Presentation
Antenna Fundamentals Prof. Girish Kumar Electrical Engineering - - PowerPoint PPT Presentation
Antenna Fundamentals Prof. Girish Kumar Electrical Engineering Department, IIT Bombay gkumar@ee.iitb.ac.in (022) 2576 7436 3-D Radiation Pattern of Antenna ` Isotropic Radiation Pattern Omni-Directional Radiation Directional Radiation
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3-D Radiation Pattern of Antenna
Omni-Directional Radiation Pattern of Ξ»/2 Dipole Antenna D = 1.64 = 2.1dB Isotropic Radiation Pattern D = 1 = 0dB Directional Radiation Pattern
- f Microstrip Antenna Array
D = 500 = 27dB
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2-D Radiation Pattern of Antenna
Back Lobe Minor Lobes (HPBW) (FNBW)
y x
Major Lobe Side Lobe
z
Beamwidth between first nulls (FNBW) ~ 2.25 x HPBW (Half Power Beamwidth) Side Lobe Level (SLL) < 20 dB for satellite and high power applications Front to Back Ratio (F/B) > 20 dB
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Directivity of Antenna
- U
m
- U
DU ο½
Directivity of an antenna is the ratio of radiation density in the direction of maximum radiation to the radiation density averaged over all the directions.
πΈ = πmax P
π ππ
4π = 4π πmax ππ ππ = 4π πmax πmax π»π΅ = 4π π»π΅ πΈ β 4π ππΉππΌ πΈ = maximum radiation intensity average radiation intensity = πmax π0 [where, ΞΈE, ΞΈH are in radian [where, Ξ©Ais beam solid angle π»π΅ = 1 πΊ(π, π)|max
2π π
πΊ(π, π)sinπππππ where, F ΞΈ, Ο β |EΞΈ
- (ΞΈ, Ο)|2 + |EΟ
- (ΞΈ, Ο)|2
Example: For Infinitesimal Dipole
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Directivity and Gain of Antenna
Gain = Ξ· D
Directivity of Large Antenna
Practice Problem: Find the gain in dB of a parabolic reflector antenna at 15 GHz having diameter of 1m. Assume efficiency is 0.6. What will be its gain at 36 GHz? Hint: Aperture Area of parabolic reflector antenna = Ο r2
where, ΞΈE, ΞΈH are in degree πΈ = 32400 ππΉππΌ
where Ξ· is Efficiency of Antenna Directivity is proportional to the Effective Aperture Area of Antenna
41253
E H
D ο± ο± ο½ Directivity of Small Antenna
Polarization of Antenna
Orientation of radiated electric field vector in the main beam of the antenna
Wave is Linearly Polarized Wave is Circularly Polarized Wave is Elliptically Polarized
πΉ = πππΉπcosππ’ + πππΉπcos(ππ’ + π½
πΉπ πΉπ πΉπ πΉπ πΉπ πΉπ
π·ππ‘π 3: π½= Β± π/2 and Eπβ πΉπ π·ππ‘π 2: π½= Β± π/2 and Eπ= πΉπ π·ππ‘π 1: π½=0 or π
Axial Ratio of Antenna
Axial Ratio Bandwidth:
Frequency range over which AR < 3 dB
Axial Ratio Plot of Circularly Polarized MSA Bandwidth for AR < 3dB = 380MHz (13%)
, circular polarization
, elliptical polarization , linear polarization
AR = 1 1<AR<β AR = β
Axial Ratio(AR) = Major Axis of Polarization Minor Axis of Polarization
Input Impedance and VSWR of Antenna
Input Impedance
RA represents power loss from the antenna and XA gives the power stored in the near field
- f
the antenna
A r L
R R R ο½ ο«
r r r A r L
R R e R R R ο½ ο½ ο«
Radiation Efficiency
A A
Z Z Z Z ο ο ο½ ο«
max min
1 V VSWR V 1 ο« ο ο½ ο½ ο ο
Reflection Coefficient and VSWR
Practice Problem: Calculate Reflection Coefficient and VSWR for impedance ZA= 10, 30, 50,100Ξ©
ππ΅ = ππ΅ + πππ΅
Example: If antenna impedance , calculate Ξ and VSWR.
Input Impedance Plot on Smith Chart
ππ΅= (20+j30)π» π₯ = 20 + π30 β 50 20 + π30 + 50 β β0.2 + 0.52j = 0.56β 112Β° ππ΅ = 20π» + π30π», Z0= 50π» π₯ = ππ΅ β π0 ππ΅ + π0 VSWR = 1 + |π₯| 1 β |π₯| VSWR =
1+0.56 1β0.56 β3.55
ππ΅πππ π = ππ΅ π0 = 20 + π30 50 = 0.4 + π0.6
π₯ = 0.56β 112Β°
VSWR = 3.55
Normalized Input Impedance Plot
- n Smith Chart gives Ξ and VSWR
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Microstrip Antenna at 5.8 GHz
Return loss Plot BW for Ξ β€ 10 dB is 85MHz (1.5%) Input Impedance Plot on Smith Chart normalized with 50 ohm MSA design at 5.8GHz with RT Duroid 5880 Substrate height =0.8mm
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Microstrip Antenna Radiation Pattern and Gain
Antenna Gain Plot BW for 1dB Gain Variation = 126MHz Radiation Pattern HPBW( H-plane) = 88Β° HPBW( E-plane) = 80Β° Antenna Efficiency Plot
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Microstrip Antenna Array β Millimeter Wave
8x8 EMCP MSA Array at millimeter wave Gain Plot
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Radiation Pattern of 8x8 MSA Array
Side Lobe Level Main Beam Cross Polar
Cartesian Plot Polar Plot
HPBW= 8.8Β°, FNBW=20Β° πΊππΆπ πΌππΆπ β 2.27 D = 32400 8.8Β°x8.8Β° β 413 = 26.1dB whereas, the simulated directivity is 25.8dB
Link Budget
Receiving antenna Transmitting antenna
r
Transmitter Receiver
Aet Aer
Friis Transmission Equation
Power Density
π
π = π ππ΅ππ = π π’π»π π΅ππ
4ππ 2 Watt π
π = π π’π»π’
4ππ 2 Watt π2 π»π’ = 4ππ΅ππ’ π2
π
π = π π’ π»π’π»π
π 4ππ
2
Watt
Example: A GSM1800 cell tower antenna is transmitting 20W of power in the
frequency range of 1840 to 1845MHz. The gain of the antenna is 17dB. Find the power density at a distance of (a) 50m and (b) 300m in the direction of maximum radiation. Power density: (a) r = 50m (b) r = 300m
Power Density
Pd = P
tGt
4Οr2 Watt m2 Pd = 20 x 50 4Ο x 502 = 31.8m W m2 Pd = 20 x 50 4Ο x 3002 = 0.88m W m2 π»π’ = 17ππΆ = 50
RF Radiation Hazards and Solutions
- Prof. Girish Kumar
IIT Bombay Tel: (022) 2576 7436 gkumar@ee.iitb.ac.in prof.gkumar@gmail.com
People living within 50 to 300 meter radius are in the high radiation zone (dark blue) and are more prone to ill-effects of electromagnetic radiation
Radiation Pattern of a Cell Tower Antenna
People living at < 50m are in extremely high radiation zone
Power varies by 1/RΒ², where R = Distance from tower
Primary Lobe Secondary Lobes Very High High Medium Low
ICNIRP Guidelines β Adopted by India till Aug. 31, 2012
According to ICNIRP, for general public exposure, safe power density = f/200 for frequency range of 400-2,000 MHz. So for GSM900, safe power density is 900/200 = 4.5W/m2, which is for 6 min period as mentioned in Note no. 3.
Country Milliwatt / mΒ² Watt / mΒ² INDIA (adopted ICNIRP) 4500 4.5 (f/200) INDIA (Adopted 1/10th of ICNIRP on Sep. 1, 2012) 450 0.45 (f/2000) AUSTRALIA (New South Wales proposed) 0.01 0.00001 AUSTRIA (Salzburg city) 1 0.001 BELGIUM 45 to 1125 0.045 to 1.125 BELGIUM (Luxembourg) 24 0.024 BIO-INITIATIVE REPORT (Outdoor) 1 0.001 BIO-INITIATIVE REPORT (Indoor) 0.1 0.0001 CANADA (Toronto Board of Health - proposed) 100 0.1 CHINA 400 0.4 FRANCE (Paris) 100 0.1 GERMANY (ECOLOG 1998 - Precautionary Recommendation) 90 0.09 GERMANY (BUND 2007 - Precautionary Recommendation) 0.1 0.0001 ITALY 100 0.1 NEW ZELAND (Aukland) 500 0.5 POLAND 100 0.1 RUSSIA 100 0.1 SWITZERLAND (Apartments, Schools, Hospitals, Offices & Playgrounds) 42 0.042 USA (Implementation is strict)* 3000 3 (f/300) Final Recommendations Indoor - include apartments, schools, hospitals, offices & playgrounds. 0.1 0.0001 Outdoor - where people spend few minutes a day. 10 0.01
EMF Radiation Standards for GSM900
*USA - FCC Guidelines OET56: Power transmitted is 0.5 to 1 W in the Urban Area
Guidelines of the Austrian Medical Association
Adopted on 3rd March 2012 in Vienna
Page 18 - Complete manual can be downloaded from -
http://docs.blackberry.com/en/smartphone_users/deliverables/11261/BlackBerry_Bold_9700_Smartphone-US.pdf
Warning from Blackberry
WHO: Cell Phones can Increase Cancer Risk
International Agency for Research on Cancer (IARC), a part of WHO designates cell phones as βPossible Human Carcinogenβ [Class 2B] Found evidence of increase in glioma and acoustic neuroma brain cancer for mobile phone
βAre cell phones injurious to your healthβ by
- Prof. Girish Kumar
- Sep. 2011.
SUGGESTED SOLUTIONS
Antennas on Cell tower transmit in the frequency range of:
- 869 - 890 MHz (CDMA)
- 935 - 960 MHz (GSM900)
- 1805 β 1880 MHz (GSM1800)
- 2110 β 2170 MHz (3G)
- 2300 β 2400 MHz (4G)*
- 2400 β 2500 MHz (Wi-Fi, Bluetooth)
http://www.wifiinschools.com/
This website is dedicated to help the public realize that wireless internet, or WiFi, emits radiation that causes a myriad of serious health effects, including damage to DNA, cancer, and infertility.
Cell Tower Antenna Radiation
Malignant Brain Tumors vs. Cumulative Use
- L. Hardell, M. Carlberg, Mobile phone and cordless phone use and the risk for glioma β Analysis of pooled
case-control studies in Sweden, 1997β2003 and 2007β2009, Pathophysiology (Oct. 2014) 4000 hours = approx. 1 hour use for 11 years
- r
less than 6 months
- f 24 hours
exposure to 100 mW/mΒ²