Algebra, geometry, and Pythagorean triples Kaloyan Slavov - - PowerPoint PPT Presentation

algebra geometry and pythagorean triples
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Algebra, geometry, and Pythagorean triples Kaloyan Slavov - - PowerPoint PPT Presentation

Algebra, geometry, and Pythagorean triples Kaloyan Slavov Department of Mathematics ETH Z urich kaloyan.slavov@math.ethz.ch February 9, 2017 1 / 8 Basics 2 , 1 , 5 , 7 2 / 8 Basics 1 2 , 1 , 5 , 7 2 7 5 2 / 8


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SLIDE 1

Algebra, geometry, and Pythagorean triples

Kaloyan Slavov Department of Mathematics ETH Z¨ urich kaloyan.slavov@math.ethz.ch February 9, 2017

1 / 8

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SLIDE 2

Basics

−2, 1, √ 5, 7

2 / 8

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SLIDE 3

Basics

−2, 1, √ 5, 7 −2 1 √ 5 7

2 / 8

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SLIDE 4

Basics

algebra geometry −2, 1, √ 5, 7 −2 1 √ 5 7

2 / 8

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SLIDE 5

Basics

algebra geometry −2, 1, √ 5, 7 −2 1 √ 5 7 (2, 1)

2 / 8

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SLIDE 6

Basics

algebra geometry −2, 1, √ 5, 7 −2 1 √ 5 7 (2, 1) x y (2, 1)

2 / 8

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SLIDE 7

Lines

algebra geometry

3 / 8

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SLIDE 8

Lines

algebra geometry x y (2, 1) (−1, 0)

3 / 8

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SLIDE 9

Lines

algebra geometry x y (2, 1) (−1, 0)

3 / 8

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SLIDE 10

Lines

algebra geometry y = x + x y (2, 1) (−1, 0)

3 / 8

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SLIDE 11

Lines

algebra geometry y =

slope

x + x y (2, 1) (−1, 0)

3 / 8

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SLIDE 12

Lines

algebra geometry y = 1 − 0 2 − (−1)

slope

x + x y (2, 1) (−1, 0)

3 / 8

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SLIDE 13

Lines

algebra geometry y = 1 3

slope

x + x y (2, 1) (−1, 0)

3 / 8

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SLIDE 14

Lines

algebra geometry y = 1 3

slope

x + 1 3 x y (2, 1) (−1, 0)

3 / 8

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SLIDE 15

Lines

algebra geometry y = 1 3

slope

x + 1 3 x y (2, 1) (−1, 0) y = 1 3x + 1 3

3 / 8

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SLIDE 16

Circles

algebra geometry

4 / 8

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SLIDE 17

Circles

algebra geometry x y 1

4 / 8

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SLIDE 18

Circles

algebra geometry x y 1 x2 + y2 = 1

4 / 8

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SLIDE 19

Circles

algebra geometry x y 1 (x, y) x y 1 x2 + y2 = 1

4 / 8

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SLIDE 20

Circles

algebra geometry x y 1 (x, y) x y 1 x2 + y2 = 1 Is

  • −1

3, 2 √ 2 3

  • n this circle?

4 / 8

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SLIDE 21

Circles

algebra geometry x y 1 (x, y) x y 1 x2 + y2 = 1 Is

  • −1

3, 2 √ 2 3

  • n this circle?

1 9 + 8 9 = 1 = ⇒ yes.

4 / 8

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SLIDE 22

Circles

algebra geometry x y 1 (x, y) x y 1 x2 + y2 = 1 Is

  • −1

3, 2 √ 2 3

  • n this circle?

1 9 + 8 9 = 1 = ⇒ yes.

4 / 8

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SLIDE 23

Pythagorean triples

N = {1, 2, 3, 4, 5, ...} positive integers

5 / 8

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SLIDE 24

Pythagorean triples

N = {1, 2, 3, 4, 5, ...} positive integers a b c

5 / 8

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SLIDE 25

Pythagorean triples

N = {1, 2, 3, 4, 5, ...} positive integers a b c

Problem

Find examples of a, b, c ∈ N such that a2 + b2 = c2.

5 / 8

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SLIDE 26

Pythagorean triples

N = {1, 2, 3, 4, 5, ...} positive integers a b c

Problem

Find examples of a, b, c ∈ N such that a2 + b2 = c2. 32 + 42 = 52

5 / 8

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SLIDE 27

Pythagorean triples

N = {1, 2, 3, 4, 5, ...} positive integers a b c

Problem

Find examples of a, b, c ∈ N such that a2 + b2 = c2. 32 + 42 = 52 62 + 82 = 102

5 / 8

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SLIDE 28

Pythagorean triples

N = {1, 2, 3, 4, 5, ...} positive integers a b c

Problem

Find examples of a, b, c ∈ N such that a2 + b2 = c2. 32 + 42 = 52 62 + 82 = 102 92 + 122 = 152

5 / 8

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SLIDE 29

Pythagorean triples

N = {1, 2, 3, 4, 5, ...} positive integers a b c

Problem

Find examples of a, b, c ∈ N such that a2 + b2 = c2. 32 + 42 = 52 62 + 82 = 102 92 + 122 = 152 . . . 3002 + 4002 = 5002

5 / 8

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SLIDE 30

Pythagorean triples

N = {1, 2, 3, 4, 5, ...} positive integers a b c

Problem

Find examples of a, b, c ∈ N such that a2 + b2 = c2. 32 + 42 = 52, 52 + 122 = 132 62 + 82 = 102 92 + 122 = 152 . . . 3002 + 4002 = 5002

5 / 8

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SLIDE 31

Pythagorean triples

N = {1, 2, 3, 4, 5, ...} positive integers a b c

Problem

Find examples of a, b, c ∈ N such that a2 + b2 = c2. 32 + 42 = 52, 52 + 122 = 132, 82 + 152 = 172, 62 + 82 = 102 92 + 122 = 152 . . . 3002 + 4002 = 5002

5 / 8

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SLIDE 32

Pythagorean triples

N = {1, 2, 3, 4, 5, ...} positive integers a b c

Problem

Find examples of a, b, c ∈ N such that a2 + b2 = c2. 32 + 42 = 52, 52 + 122 = 132, 82 + 152 = 172,

  • • •

62 + 82 = 102 92 + 122 = 152 . . . 3002 + 4002 = 5002

5 / 8

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SLIDE 33

Pythagorean triples

N = {1, 2, 3, 4, 5, ...} positive integers a b c

Problem

Find examples of a, b, c ∈ N such that a2 + b2 = c2. 32 + 42 = 52, 52 + 122 = 132, 82 + 152 = 172,

  • • •

62 + 82 = 102 92 + 122 = 152 . . . 3002 + 4002 = 5002 Non-example: 12 + 12 = ( √ 2)2

5 / 8

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SLIDE 34

Geometric interpretation

a2 + b2 = c2 a, b, c ∈ N

6 / 8

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SLIDE 35

Geometric interpretation

a2 + b2 = c2 a, b, c ∈ N ⇐ ⇒

6 / 8

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SLIDE 36

Geometric interpretation

a2 + b2 = c2 a, b, c ∈ N ⇐ ⇒ a c 2 + b c 2 = 1

6 / 8

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SLIDE 37

Geometric interpretation

a2 + b2 = c2 a, b, c ∈ N ⇐ ⇒ a c

  • x

2

+ b c

  • y

2

= 1

6 / 8

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SLIDE 38

Geometric interpretation

a2 + b2 = c2 a, b, c ∈ N ⇐ ⇒ a c

  • x

2

+ b c

  • y

2

= 1 ⇐ ⇒

6 / 8

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SLIDE 39

Geometric interpretation

a2 + b2 = c2 a, b, c ∈ N ⇐ ⇒ a c

  • x

2

+ b c

  • y

2

= 1 ⇐ ⇒ x2 + y2 = 1 x, y ∈ Q (rational)

6 / 8

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SLIDE 40

Geometric interpretation

a2 + b2 = c2 a, b, c ∈ N ⇐ ⇒ a c

  • x

2

+ b c

  • y

2

= 1 ⇐ ⇒ x2 + y2 = 1 x, y ∈ Q (rational) x y

1

6 / 8

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SLIDE 41

Geometric interpretation

a2 + b2 = c2 a, b, c ∈ N ⇐ ⇒ a c

  • x

2

+ b c

  • y

2

= 1 ⇐ ⇒ x2 + y2 = 1 x, y ∈ Q (rational)

32 + 42 = 52 ⇐ ⇒

x y

1

6 / 8

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SLIDE 42

Geometric interpretation

a2 + b2 = c2 a, b, c ∈ N ⇐ ⇒ a c

  • x

2

+ b c

  • y

2

= 1 ⇐ ⇒ x2 + y2 = 1 x, y ∈ Q (rational)

32 + 42 = 52 ⇐ ⇒ 3 5 2 + 4 5 2 = 1

x y

1

6 / 8

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SLIDE 43

Geometric interpretation

a2 + b2 = c2 a, b, c ∈ N ⇐ ⇒ a c

  • x

2

+ b c

  • y

2

= 1 ⇐ ⇒ x2 + y2 = 1 x, y ∈ Q (rational)

32 + 42 = 52 ⇐ ⇒ 3 5 2 + 4 5 2 = 1

x y

1

( 3

5, 4 5)

6 / 8

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SLIDE 44

Geometric interpretation

a2 + b2 = c2 a, b, c ∈ N ⇐ ⇒ a c

  • x

2

+ b c

  • y

2

= 1 ⇐ ⇒ x2 + y2 = 1 x, y ∈ Q (rational)

32 + 42 = 52 ⇐ ⇒ 3 5 2 + 4 5 2 = 1 52 + 122 = 132 ⇐ ⇒

x y

1

( 3

5, 4 5)

6 / 8

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SLIDE 45

Geometric interpretation

a2 + b2 = c2 a, b, c ∈ N ⇐ ⇒ a c

  • x

2

+ b c

  • y

2

= 1 ⇐ ⇒ x2 + y2 = 1 x, y ∈ Q (rational)

32 + 42 = 52 ⇐ ⇒ 3 5 2 + 4 5 2 = 1 52 + 122 = 132 ⇐ ⇒ 5 13 2 + 12 13 2 = 1

x y

1

( 3

5, 4 5)

6 / 8

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SLIDE 46

Geometric interpretation

a2 + b2 = c2 a, b, c ∈ N ⇐ ⇒ a c

  • x

2

+ b c

  • y

2

= 1 ⇐ ⇒ x2 + y2 = 1 x, y ∈ Q (rational)

32 + 42 = 52 ⇐ ⇒ 3 5 2 + 4 5 2 = 1 52 + 122 = 132 ⇐ ⇒ 5 13 2 + 12 13 2 = 1

x y

1

( 3

5, 4 5)

( 5

13, 12 13)

6 / 8

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SLIDE 47

Geometric interpretation

a2 + b2 = c2 a, b, c ∈ N ⇐ ⇒ a c

  • x

2

+ b c

  • y

2

= 1 ⇐ ⇒ x2 + y2 = 1 x, y ∈ Q (rational)

32 + 42 = 52 ⇐ ⇒ 3 5 2 + 4 5 2 = 1 52 + 122 = 132 ⇐ ⇒ 5 13 2 + 12 13 2 = 1 152 + 82 = 172 ⇐ ⇒

x y

1

( 3

5, 4 5)

( 5

13, 12 13)

6 / 8

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SLIDE 48

Geometric interpretation

a2 + b2 = c2 a, b, c ∈ N ⇐ ⇒ a c

  • x

2

+ b c

  • y

2

= 1 ⇐ ⇒ x2 + y2 = 1 x, y ∈ Q (rational)

32 + 42 = 52 ⇐ ⇒ 3 5 2 + 4 5 2 = 1 52 + 122 = 132 ⇐ ⇒ 5 13 2 + 12 13 2 = 1 152 + 82 = 172 ⇐ ⇒ 15 17 2 + 8 17 2 = 1

x y

1

( 3

5, 4 5)

( 5

13, 12 13)

6 / 8

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SLIDE 49

Geometric interpretation

a2 + b2 = c2 a, b, c ∈ N ⇐ ⇒ a c

  • x

2

+ b c

  • y

2

= 1 ⇐ ⇒ x2 + y2 = 1 x, y ∈ Q (rational)

32 + 42 = 52 ⇐ ⇒ 3 5 2 + 4 5 2 = 1 52 + 122 = 132 ⇐ ⇒ 5 13 2 + 12 13 2 = 1 152 + 82 = 172 ⇐ ⇒ 15 17 2 + 8 17 2 = 1

x y

1

( 3

5, 4 5)

( 5

13, 12 13)

( 15

17, 8 17)

6 / 8

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SLIDE 50

Geometric interpretation

a2 + b2 = c2 a, b, c ∈ N ⇐ ⇒ a c

  • x

2

+ b c

  • y

2

= 1 ⇐ ⇒ x2 + y2 = 1 x, y ∈ Q (rational)

32 + 42 = 52 ⇐ ⇒ 3 5 2 + 4 5 2 = 1 52 + 122 = 132 ⇐ ⇒ 5 13 2 + 12 13 2 = 1 152 + 82 = 172 ⇐ ⇒ 15 17 2 + 8 17 2 = 1

Problem

Find examples of x, y ∈ Q such that x2 + y2 = 1. x y

1

( 3

5, 4 5)

( 5

13, 12 13)

( 15

17, 8 17)

6 / 8

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SLIDE 51

Hunting rational points

x y

1

7 / 8

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SLIDE 52

Hunting rational points

x y

1

( 3

5, 4 5)

7 / 8

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SLIDE 53

Hunting rational points

x y

1

( 3

5, 4 5)

( 5

13, 12 13)

7 / 8

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SLIDE 54

Hunting rational points

x y

1

( 3

5, 4 5)

( 5

13, 12 13)

( 15

17, 8 17)

7 / 8

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SLIDE 55

Hunting rational points

x y

1

(−1, 0)

( 3

5, 4 5)

( 5

13, 12 13)

( 15

17, 8 17)

7 / 8

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SLIDE 56

Hunting rational points

x y

1

(−1, 0)

( 3

5, 4 5)

( 5

13, 12 13)

( 15

17, 8 17)

7 / 8

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SLIDE 57

Hunting rational points

x y

1

(−1, 0)

( 3

5, 4 5)

slope m =

( 5

13, 12 13)

( 15

17, 8 17)

7 / 8

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SLIDE 58

Hunting rational points

x y

1

(−1, 0)

( 3

5, 4 5)

slope m =

4 5 − 0 3 5 + 1

( 5

13, 12 13)

( 15

17, 8 17)

7 / 8

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SLIDE 59

Hunting rational points

x y

1

(−1, 0)

( 3

5, 4 5)

slope m =

4 5 − 0 3 5 + 1 = 1

2

( 5

13, 12 13)

( 15

17, 8 17)

7 / 8

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SLIDE 60

Hunting rational points

x y

1

(−1, 0)

( 3

5, 4 5)

slope m =

4 5 − 0 3 5 + 1 = 1

2

( 5

13, 12 13)

( 15

17, 8 17)

7 / 8

slide-61
SLIDE 61

Hunting rational points

x y

1

(−1, 0)

( 3

5, 4 5)

slope m =

4 5 − 0 3 5 + 1 = 1

2

( 5

13, 12 13)

slope m =

( 15

17, 8 17)

7 / 8

slide-62
SLIDE 62

Hunting rational points

x y

1

(−1, 0)

( 3

5, 4 5)

slope m =

4 5 − 0 3 5 + 1 = 1

2

( 5

13, 12 13)

slope m =

12 13 − 0 5 13 + 1

( 15

17, 8 17)

7 / 8

slide-63
SLIDE 63

Hunting rational points

x y

1

(−1, 0)

( 3

5, 4 5)

slope m =

4 5 − 0 3 5 + 1 = 1

2

( 5

13, 12 13)

slope m =

12 13 − 0 5 13 + 1= 2

3

( 15

17, 8 17)

7 / 8

slide-64
SLIDE 64

Hunting rational points

x y

1

(−1, 0)

( 3

5, 4 5)

slope m =

4 5 − 0 3 5 + 1 = 1

2

( 5

13, 12 13)

slope m =

12 13 − 0 5 13 + 1= 2

3

( 15

17, 8 17)

7 / 8

slide-65
SLIDE 65

Hunting rational points

x y

1

(−1, 0)

( 3

5, 4 5)

slope m =

4 5 − 0 3 5 + 1 = 1

2

( 5

13, 12 13)

slope m =

12 13 − 0 5 13 + 1= 2

3

( 15

17, 8 17)

slope m =

7 / 8

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SLIDE 66

Hunting rational points

x y

1

(−1, 0)

( 3

5, 4 5)

slope m =

4 5 − 0 3 5 + 1 = 1

2

( 5

13, 12 13)

slope m =

12 13 − 0 5 13 + 1= 2

3

( 15

17, 8 17)

slope m = (rational!)

7 / 8

slide-67
SLIDE 67

Hunting rational points

x y

1

(−1, 0)

( 3

5, 4 5)

slope m =

4 5 − 0 3 5 + 1 = 1

2

( 5

13, 12 13)

slope m =

12 13 − 0 5 13 + 1= 2

3

( 15

17, 8 17)

slope m = 1 4 (rational!)

7 / 8

slide-68
SLIDE 68

Hunting rational points

x y

1

(−1, 0)

( 3

5, 4 5)

slope m =

4 5 − 0 3 5 + 1 = 1

2

( 5

13, 12 13)

slope m =

12 13 − 0 5 13 + 1= 2

3

( 15

17, 8 17)

slope m = 1 4 (rational!) slope m = 1 10 (try!)

7 / 8

slide-69
SLIDE 69

Hunting rational points

x y

1

(−1, 0)

( 3

5, 4 5)

slope m =

4 5 − 0 3 5 + 1 = 1

2

( 5

13, 12 13)

slope m =

12 13 − 0 5 13 + 1= 2

3

( 15

17, 8 17)

slope m = 1 4 (rational!) slope m = 1 10 (try!)

7 / 8

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SLIDE 70

The computation

x y

1

(−1, 0) slope m =

1 10

8 / 8

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SLIDE 71

The computation

x y

1

(−1, 0) slope m =

1 10

y =x +

8 / 8

slide-72
SLIDE 72

The computation

x y

1

(−1, 0) slope m =

1 10

y = 1 10 x +

8 / 8

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SLIDE 73

The computation

x y

1

(−1, 0) slope m =

1 10

y = 1 10 x + 1 10

8 / 8

slide-74
SLIDE 74

The computation

x y

1

(−1, 0) slope m =

1 10

y = 1 10 x + 1 10 (x, 1

10x + 1 10)

8 / 8

slide-75
SLIDE 75

The computation

x y

1

(−1, 0) slope m =

1 10

y = 1 10 x + 1 10 (x, 1

10x + 1 10)

x2 + y2 = 1

8 / 8

slide-76
SLIDE 76

The computation

x y

1

(−1, 0) slope m =

1 10

y = 1 10 x + 1 10 (x, 1

10x + 1 10)

x2 + y2 = 1 Solve: x2 + 1 10x + 1 10 2 = 1

8 / 8

slide-77
SLIDE 77

The computation

x y

1

(−1, 0) slope m =

1 10

y = 1 10 x + 1 10 (x, 1

10x + 1 10)

x2 + y2 = 1 Solve: x2 + 1 10x + 1 10 2 = 1 ⇐ ⇒

8 / 8

slide-78
SLIDE 78

The computation

x y

1

(−1, 0) slope m =

1 10

y = 1 10 x + 1 10 (x, 1

10x + 1 10)

x2 + y2 = 1 Solve: x2 + 1 10x + 1 10 2 = 1 ⇐ ⇒ 101x2 + 2x − 99 = 0

8 / 8

slide-79
SLIDE 79

The computation

x y

1

(−1, 0) slope m =

1 10

y = 1 10 x + 1 10 (x, 1

10x + 1 10)

x2 + y2 = 1 Solve: x2 + 1 10x + 1 10 2 = 1 ⇐ ⇒ 101x2 + 2x − 99 = 0 x1 = −1

8 / 8

slide-80
SLIDE 80

The computation

x y

1

(−1, 0) slope m =

1 10

y = 1 10 x + 1 10 (x, 1

10x + 1 10)

x2 + y2 = 1 Solve: x2 + 1 10x + 1 10 2 = 1 ⇐ ⇒ 101x2 + 2x − 99 = 0 x1 = −1 x1x2 = − 99 101 Vieta’s formula

8 / 8

slide-81
SLIDE 81

The computation

x y

1

(−1, 0) slope m =

1 10

y = 1 10 x + 1 10 (x, 1

10x + 1 10)

x2 + y2 = 1 Solve: x2 + 1 10x + 1 10 2 = 1 ⇐ ⇒ 101x2 + 2x − 99 = 0 x1 = −1 x1x2 = − 99 101 Vieta’s formula = ⇒ x2 = 99 101

8 / 8

slide-82
SLIDE 82

The computation

x y

1

(−1, 0) slope m =

1 10

y = 1 10 x + 1 10 (x, 1

10x + 1 10)

x2 + y2 = 1 Solve: x2 + 1 10x + 1 10 2 = 1 ⇐ ⇒ 101x2 + 2x − 99 = 0 99

101,

  • x1 = −1

x1x2 = − 99 101 Vieta’s formula = ⇒ x2 = 99 101

8 / 8

slide-83
SLIDE 83

The computation

x y

1

(−1, 0) slope m =

1 10

y = 1 10 x + 1 10 (x, 1

10x + 1 10)

x2 + y2 = 1 Solve: x2 + 1 10x + 1 10 2 = 1 ⇐ ⇒ 101x2 + 2x − 99 = 0 99

101,

  • x1 = −1

x1x2 = − 99 101 Vieta’s formula = ⇒ x2 = 99 101, y2 = 20 101

8 / 8

slide-84
SLIDE 84

The computation

x y

1

(−1, 0) slope m =

1 10

y = 1 10 x + 1 10 (x, 1

10x + 1 10)

x2 + y2 = 1 Solve: x2 + 1 10x + 1 10 2 = 1 ⇐ ⇒ 101x2 + 2x − 99 = 0 99

101, 20 101

  • x1 = −1

x1x2 = − 99 101 Vieta’s formula = ⇒ x2 = 99 101, y2 = 20 101

8 / 8

slide-85
SLIDE 85

The computation

x y

1

(−1, 0) slope m =

1 10

y = 1 10 x + 1 10 (x, 1

10x + 1 10)

x2 + y2 = 1 Solve: x2 + 1 10x + 1 10 2 = 1 ⇐ ⇒ 101x2 + 2x − 99 = 0 99

101, 20 101

  • x1 = −1

x1x2 = − 99 101 Vieta’s formula = ⇒ x2 = 99 101, y2 = 20 101 Check: 99 101 2 + 20 101 2 = 1

8 / 8

slide-86
SLIDE 86

The computation

x y

1

(−1, 0) slope m =

1 10

y = 1 10 x + 1 10 (x, 1

10x + 1 10)

x2 + y2 = 1 Solve: x2 + 1 10x + 1 10 2 = 1 ⇐ ⇒ 101x2 + 2x − 99 = 0 99

101, 20 101

  • x1 = −1

x1x2 = − 99 101 Vieta’s formula = ⇒ x2 = 99 101, y2 = 20 101 Check: 99 101 2 + 20 101 2 = 1 ⇐ ⇒

8 / 8

slide-87
SLIDE 87

The computation

x y

1

(−1, 0) slope m =

1 10

y = 1 10 x + 1 10 (x, 1

10x + 1 10)

x2 + y2 = 1 Solve: x2 + 1 10x + 1 10 2 = 1 ⇐ ⇒ 101x2 + 2x − 99 = 0 99

101, 20 101

  • x1 = −1

x1x2 = − 99 101 Vieta’s formula = ⇒ x2 = 99 101, y2 = 20 101 Check: 99 101 2 + 20 101 2 = 1 ⇐ ⇒ 992 + 202 = 1012

8 / 8