water wave analysis with nonlinear fourier transforms
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Water wave analysis with nonlinear Fourier transforms Peter Prins p.j.prins@tudelft.nl 7 September 2018 This project has received funding from the European Research Council (ERC) under the European Unions Horizon 2020 research and


  1. Water wave analysis with nonlinear Fourier transforms Peter Prins p.j.prins@tudelft.nl 7 September 2018 This project has received funding from the European Research Council (ERC) under the European Union’s Horizon 2020 research and innovation programme (grant agreement No 716669). 1

  2. Nonlinear water waves “ I was observing the motion of a boat which was rapidly drawn along a narrow channel by a pair of horses, when the boat suddenly stopped - not so the mass of water in the channel which it had put in motion; it accumulated round the prow of the vessel in a state of violent agitation, then suddenly leaving it behind, rolled forward with great velocity, assuming the form of a large solitary elevation , a rounded, smooth and well-defined heap of water, which continued its course along the channel apparently without change of form or diminution of speed . I followed it on horseback, and overtook it still rolling on at a rate of some eight or nine miles an hour, preserving its original figure some thirty feet long and a foot to a foot and a half in height. Its height gradually diminished, and after a chase of one or two miles I lost it in the windings of the channel. Such, in the month of August 1834, was my first chance interview with that singular and beautiful phenomenon which I have called the Wave of Translation. “ John Scott Russell (1808-1882) 2

  3. https://youtu.be/w-oDnvbV8mY 3

  4. https://youtu.be/D14QuUL8x60?t=51s 4

  5. Wave equations • Water surface elevation: u = u ( x, t ) • Linear wave equation: u tt − u xx = 0 • Korteweg-De Vries equation (KdV): − u t + 6 uu x + u xxx = 0 • Many other non-linear wave equations exist. 5

  6. Why a Fourier transform? Hard calculations u(t) y(t) ☹ Inverse Fourier Fourier Transform Transform Easy calculations " 6

  7. Why a Fourier transform? d t + ↵ 2 d 2 u y ( t ) = ↵ 0 u ( t ) + ↵ 1 d u d t 2 =: ( ↵ 0 + ↵ 1 � t + ↵ 2 � tt ) u ( t ) | {z } | K M v i = � i v i K exp( j ! 0 t ) = H ( j ! 0 )exp( j ! 0 t ) Z ∞ X w = c i v i u ( t ) = U ( j ! ) exp( j ! t ) d ! −∞ i Z ∞ X y ( t ) = Ku ( t ) = U ( j ! ) K exp( j ! t ) d ! y = M w = c i M v i −∞ i Z ∞ X = U ( j ! ) H ( j ! ) exp( j ! t ) d ! = c i � i v i | {z } −∞ Y ( j ω ) i 7

  8. ➡ ⬆ Solitons overtaking: No superposition Source: http://lie.math.brocku.ca/~sanco /solitons/kdv_solitons.php Adapted from: https://carretero.sdsu.edu/ teaching/M-639/lectures/ nonlinear_waves.html 8

  9. Lax pair � u t + 6 uu x + u xxx = 0 ⇕ − L t + LA − AL = 0 − − A := 4 � xxx + 6 u � x + 3 u x L := � xx + u • A and L are linear operators. • The eigenvalues of L are constant in time iff u(x,t) satisfies the KdV equation. 9

  10. Schrödinger eigenvalue problem • The Non-linear Fourier transform of an input u(x,t0) w.r.t. the KdV equation, is the eigenvalue problem of L. " • It can be shown that " – All are real. λ – All <0 are an eigenvalue (cf. ordinary λ " Fourier transform) – Some isolated >0 may be eigenvalues (cf. λ matrix eigenvalues) 10

  11. Schrödinger eigenvalue problem � � δ xx + u ( x ) w ( x ) = λ w ( x ) � � w xx ( x ) = λ − u ( x ) w ( x ) " # " # " # d w ( x ) 0 1 w ( x ) = · w x ( x ) λ − u ( x ) 0 w x ( x ) d x d d x w ( x ) = A ( x ) w ( x ) � ¯ � d x w ( x ) = ¯ d A w ( x ) ⇒ w ( x ) = exp · w (0) A x 11

  12. Staircase approximation 1 0.8 u(x,t 0 ) 0.6 0.4 0.2 0 -6 -4 -2 0 2 4 6 x u i := u ( x i ) ¯ " # 0 1 ¯ A i = λ − ¯ u i 0 � � � ¯ � � ¯ � � ¯ � � � x D + ε / 2 , λ = exp A D ( λ ) · ε · · · exp A 2 ( λ ) · ε · exp A 1 ( λ ) · ε x 1 − ε / 2 , λ w · w | {z } | {z } | {z } G D ( λ ) G 2 ( λ ) G 1 ( λ ) 12

  13. Computational complexity • D gridpoints in x => (D-1) matrix " multiplications. λ • D gridpoints in => Repeat the calculation D times. • Hence complexity O(D^2). • We have improved it to O(D log^2(D)), see next slide. 13

  14. Fast Nonlinear Fourier Transform = p 1 ↘ p 1 p 2 ↗ p 2 ↘ " # p 11 i ( z ) p 12 i ( z ) p 1 p 2 p 3 p 4 G i ( λ ) ≈ p 3 ↗ p 21 i ( z ) p 22 i ( z ) ↘ p 3 p 4 ↘ ↗ p · i ( z ) = c 0 + c 1 z + c 2 z 2 + . . . p 4 p z = z ( λ ) p 5 ↘ " p 5 p 6 ↗ ↗ p 6 ↘ Main benefit: No need to repeat " p 5 p 6 p 7 p 8 λ for every . We can fill out the p 7 ↗ resulting 4 polynomials for ↘ p 7 p 8 ↗ λ every value of we need. p 8 Source: Wahls, Sander, and H. Vincent Poor. "Fast numerical nonlinear Fourier transforms." IEEE Transactions on Information Theory 61.12 (2015): 14 6957-6974.

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