Transferring imaginaries
How to eliminate imaginaries in p-adic fields Silvain Rideau (joint work with E. Hrushovski and B. Martin)
Paris 11, École Normale Supérieure
April 3, 2013
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Transferring imaginaries How to eliminate imaginaries in p-adic - - PowerPoint PPT Presentation
Transferring imaginaries How to eliminate imaginaries in p-adic fields Silvain Rideau (joint work with E. Hrushovski and B. Martin) Paris 11, cole Normale Suprieure April 3, 2013 1 / 35 Contents Imaginaries Valued fields Imaginary
Paris 11, École Normale Supérieure
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▸ A non-example : infinite sets, ▸ An example : algebraically closed fields.
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▸ For any definable equivalence relation E on a product of L-sorts
▸ In Meq, SE is interpreted as ∏i Si(M)/E(M) and fE as the canonical
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▸ For any definable equivalence relation E on a product of L-sorts
▸ In Meq, SE is interpreted as ∏i Si(M)/E(M) and fE as the canonical
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▸ We usually add a point ∞ to Γ to denote v(0), greater than any other
▸ The set O = {x ∈ K ∣ v(x) ≥ 0} is a ring, called the valuation ring of K. ▸ It has a unique maximal ideal M = {x ∈ K ∣ v(x) > 0}. ▸ The residue field O /M will be denoted k. ▸ We will also be considering the group RV ∶= K⋆/(1 + M).
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▸ Let p be a prime number, then we can define the p-adic valuation on
▸ We will denote by Qp, the field of p-adic numbers, the completion of
▸ We will denote by ACVF the theory of algebraically closed valued
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▸ We can give an alternative definition of these sorts, for example
▸ The geometric language LG is composed of the sorts K, Sn and Tn for
▸ S1 can be identified with Γ and ρ1 with v, ▸ T1 can be identified with RV, ▸ The set of balls (open and closed, possibly with infinite radius) B can
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alg be its algebraic closure (both fields are
▸ Let a ∈ K, the function f ∶ x ↦ √x − a can be defined in K but not in
alg, ▸ However, the 1-to-2 correspondance F = {(x,y) ∣ y2 = x − a} is
alg, ▸ F is the Zariski closure of the graph of f and f(x) can be defined (in K)
▸ In fact, f can be coded by the code of F in K alg (which is K).
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▸ Let ̃
▸ Let ̃
▸ Let T be a L-theory such that ̃
▸ Let A ⊆ ̃
L(A) for the (quantifier-free) ̃
▸ Let A ⊆ Meq, we will write dcleq L (A) for the Leq-definable closure in
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▸ The theory ̃
▸ The theory T will be either :
alg.
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▸ The set consisting of all the sorts is dominant. ▸ The set of “real” sorts (i.e. the original sorts from M) are dominant in
▸ In a valued field in the geometric language, the sort K is dominant.
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L (M1c) ∩ M ⊆ acl̃ L(M1c).
L(A)≼M.
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L(M), there exists a tuple e′ ∈ M such that for all σ ∈ Aut(̃
L(M)). Such a lattice has a basis in some
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L(A) that contains
▸ If r and s have the same p-germ, then for any c ⊧ p, r(c) = s(c), ▸ “Having the same p-germ” is an equivalence relation on A-definable
▸ If p is a definable type and we only consider the germs of a family of
▸ In any case, if p is Aut(̃
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L (A) ∩ M and c ∈ dom(M)1, there exists an
L(̃
L(AB) such that any
pr iff σ fixes almost every εi.
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L (A) ∩ M and c ∈ dom(M), acleq L (Ac) ∩ M = dcleq L (Ac) ∩ M.
L (c) and
L (c)) has an invariant extension.
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L (A)) be a decreasing sequence
L (A)),b ⊂ P}.
▸ If A = acleq L (A), any c ∈ K(M)1 is generic over A in
▸ P is said to be strict if the sequence bi does not have a smallest
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L (A)), then : ▸ If there exists a ball a ∈ B(dcleq L (A)) such that a ⊂ P, then qP∣A is
▸ If not, qP∣A is complete.
L (K(A)) then the proposition follows from quantifier
0 and for any c ⊧ qP∣A
0 such that c ≡A c′.
L (∅).
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L (A)), then : ▸ If there exists a ball a ∈ B(dcleq L (A)) such that a ⊂ P, then qP∣A is
▸ If not, qP∣A is complete.
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L (A)) and γ be the radius of b. We define the following map
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L (A)) and γ be the radius of b. We define the following map
▸ If there exists a ball a ∈ B(dcleq L (A)) such that a ⊂ b, then qb∣A is
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L (A)) and γ be the radius of b. We define the following map
▸ If there exists a ball a ∈ B(dcleq L (A)) such that a ⊂ b, then qb∣A is
▸ If not, qb∣A is complete.
L (A)-points is a complete type, but that is surprisingly
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L (A) and c ∈ K(M)1:
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L (A) ∩ M and c ∈ dom(M)1, there exists an
L(̃
L(AB) such that any
pr iff σ fixes almost every εi.
▸ If P is a closed ball, then ̃
▸ If P is strict, take εi to be the germ of r on the ACVF-generic of bi.
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alg over Q eliminates
alg over Q eliminates
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