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The indep endene numb ers and the hromati numb ers of - - PowerPoint PPT Presentation
The indep endene numb ers and the hromati numb ers of random subgraphs Andrei Raigo ro dskii Moso w Institute of Physis and T ehnology Moso w, Russia A. Raigo ro dskii (MIPT) 2019 T ehran, Iran 1 / 10
n
, where c > 1 . Let d =1 1−p
. Then w.h.p.α(G(n, p)) ∼ 2 logd(np), χ(G(n, p)) ∼ n 2 logd(np).
A. Raigo ro dskii (MIPT) 2019 T ehran, Iran 2 / 10n
, where c > 1 . Let d =1 1−p
. Then w.h.p.α(G(n, p)) ∼ 2 logd(np), χ(G(n, p)) ∼ n 2 logd(np).
A general random subgraph Let n ∈ N, p ∈ [0, 1], Gn = (Vn, En)n
, where c > 1 . Let d =1 1−p
. Then w.h.p.α(G(n, p)) ∼ 2 logd(np), χ(G(n, p)) ∼ n 2 logd(np).
A general random subgraph Let n ∈ N, p ∈ [0, 1], Gn = (Vn, En)V = {x = (x1, . . . , xn) : xi ∈ {0, 1}, x1 + . . . + xn = r}, E = {{x, y} : (x, y) = s}.
A. Raigo ro dskii (MIPT) 2019 T ehran, Iran 3 / 10V = {x = (x1, . . . , xn) : xi ∈ {0, 1}, x1 + . . . + xn = r}, E = {{x, y} : (x, y) = s}.
Equivalent denition Let r, s, n ∈ N, s < r < n . Let [n] b e an n -element set, and letG(n, r, s) = (V, E)
, whereV = [n] r
E = {A, B ∈ V : |A ∩ B| = s}.
A. Raigo ro dskii (MIPT) 2019 T ehran, Iran 3 / 10V = {x = (x1, . . . , xn) : xi ∈ {0, 1}, x1 + . . . + xn = r}, E = {{x, y} : (x, y) = s}.
Equivalent denition Let r, s, n ∈ N, s < r < n . Let [n] b e an n -element set, and letG(n, r, s) = (V, E)
, whereV = [n] r
E = {A, B ∈ V : |A ∩ B| = s}.
Again, what an b e said abG(n, r, 0)
is the lassi al Kneser graph; G(n, 1, 0) is just aG(n, r, 0)
is the lassi al Kneser graph; G(n, 1, 0) is just a2 r(n) = o(n1/3)
. Let pc(n, r) = ((r + 1) log n − r log r)/n−1
r−1
P
n − 1 r − 1
2 r(n) = o(n1/3)
. Let pc(n, r) = ((r + 1) log n − r log r)/n−1
r−1
P
n − 1 r − 1
2 r(n) = o(n1/3)
. Let pc(n, r) = ((r + 1) log n − r log r)/n−1
r−1
P
n − 1 r − 1
2 r(n) = o(n1/3)
. Let pc(n, r) = ((r + 1) log n − r log r)/n−1
r−1
P
n − 1 r − 1
2 r(n) = o(n1/3)
. Let pc(n, r) = ((r + 1) log n − r log r)/n−1
r−1
P
n − 1 r − 1
2 r(n) = o(n1/3)
. Let pc(n, r) = ((r + 1) log n − r log r)/n−1
r−1
P
n − 1 r − 1
α(G1/2(n, r, s)) = Θ (α(G(n, r, s)) log n)
. A. Raigo ro dskii (MIPT) 2019 T ehran, Iran 7 / 10α(G1/2(n, r, s)) = Θ (α(G(n, r, s)) log n)
. If r = 1 , s = 0 , then w e have already ited the mu h subtler lassi al result. A. Raigo ro dskii (MIPT) 2019 T ehran, Iran 7 / 10α(G1/2(n, r, s)) = Θ (α(G(n, r, s)) log n)
. If r = 1 , s = 0 , then w e have already ited the mu h subtler lassi al result. Theo rem Let p b e an
, where c > 1 . Let d =1 1−p
. Then w.h.p. α(Gp(n, 1, 0)) ∼ 2 logd(np). A. Raigo ro dskii (MIPT) 2019 T ehran, Iran 7 / 10α(G1/2(n, r, s)) = Θ (α(G(n, r, s)) log n)
. If r = 1 , s = 0 , then w e have already ited the mu h subtler lassi al result. Theo rem Let p b e an
, where c > 1 . Let d =1 1−p
. Then w.h.p. α(Gp(n, 1, 0)) ∼ 2 logd(np). There a reα(G1/2(n, r, s)) = Θ (α(G(n, r, s)) log n)
. If r = 1 , s = 0 , then w e have already ited the mu h subtler lassi al result. Theo rem Let p b e an
, where c > 1 . Let d =1 1−p
. Then w.h.p. α(Gp(n, 1, 0)) ∼ 2 logd(np). There a reα(G1/2(n, r, s)) = Θ (α(G(n, r, s)) log n)
. If r = 1 , s = 0 , then w e have already ited the mu h subtler lassi al result. Theo rem Let p b e an
, where c > 1 . Let d =1 1−p
. Then w.h.p. α(Gp(n, 1, 0)) ∼ 2 logd(np). There a re2 − g(n)
, then fo r any xed p , χ(Gp(n, r, 0)) ∼ n − 2r + 2. A. Raigo ro dskii (MIPT) 2019 T ehran, Iran 8 / 102 − g(n)
, then fo r any xed p , χ(Gp(n, r, 0)) ∼ n − 2r + 2. Many imp rovements b y Kupavskii and b y Alishahi and Hajiabn − c1
2r−2
2r−2
n − c1
2r−2
2r−2
n − c1
2
2r−2
βn > γn
and βn = o(αn) ; 2log2 Nn = o
βn
log2 Nn = o (βn − γn)
. Then w.h.p. α(Gn, 1/2) ∼ α(Gn) . A. Raigo ro dskii (MIPT) 2019 T ehran, Iran 10 / 10