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The Alon-Tarsi Conjecture G. Eric Moorhouse Department of Mathematics University of Wyoming 5 Dec 2008 / RMAC Seminar G. Eric Moorhouse The Alon-Tarsi Conjecture Latin Squares A Latin square of order n is an n n array in which each of the


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The Alon-Tarsi Conjecture

  • G. Eric Moorhouse

Department of Mathematics University of Wyoming

5 Dec 2008 / RMAC Seminar

  • G. Eric Moorhouse

The Alon-Tarsi Conjecture

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Latin Squares

A Latin square of order n is an n × n array in which each of the symbols 1, 2, . . ., n occurs once in each row and in each

  • column. Denote LS(n) = {Latin squares of order n}.

L ∈ LS(n) is row-even (or row-odd) according as sgn(σ1σ2 · · ·σn) = +1 or −1, resp., where σ1, σ2, . . ., σn ∈ Sn are the rows of L. Similarly column-even, column-odd. L is even or odd according to its sign: sgn(L) = sgn(σ1σ2 · · ·σnτ1τ2 · · ·τn) where σi ∈ Sn are the columns, and τj ∈ Sn are the rows, of L. ELS(n) = {even Latin squares of order n} OLS(n) = {odd Latin squares of order n}

  • G. Eric Moorhouse

The Alon-Tarsi Conjecture

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Latin Squares

A Latin square of order n is an n × n array in which each of the symbols 1, 2, . . ., n occurs once in each row and in each

  • column. Denote LS(n) = {Latin squares of order n}.

L ∈ LS(n) is row-even (or row-odd) according as sgn(σ1σ2 · · ·σn) = +1 or −1, resp., where σ1, σ2, . . ., σn ∈ Sn are the rows of L. Similarly column-even, column-odd. L is even or odd according to its sign: sgn(L) = sgn(σ1σ2 · · ·σnτ1τ2 · · ·τn) where σi ∈ Sn are the columns, and τj ∈ Sn are the rows, of L. ELS(n) = {even Latin squares of order n} OLS(n) = {odd Latin squares of order n}

  • G. Eric Moorhouse

The Alon-Tarsi Conjecture

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Latin Squares

A Latin square of order n is an n × n array in which each of the symbols 1, 2, . . ., n occurs once in each row and in each

  • column. Denote LS(n) = {Latin squares of order n}.

L ∈ LS(n) is row-even (or row-odd) according as sgn(σ1σ2 · · ·σn) = +1 or −1, resp., where σ1, σ2, . . ., σn ∈ Sn are the rows of L. Similarly column-even, column-odd. L is even or odd according to its sign: sgn(L) = sgn(σ1σ2 · · ·σnτ1τ2 · · ·τn) where σi ∈ Sn are the columns, and τj ∈ Sn are the rows, of L. ELS(n) = {even Latin squares of order n} OLS(n) = {odd Latin squares of order n}

  • G. Eric Moorhouse

The Alon-Tarsi Conjecture

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Latin Squares

A Latin square of order n is an n × n array in which each of the symbols 1, 2, . . ., n occurs once in each row and in each

  • column. Denote LS(n) = {Latin squares of order n}.

L ∈ LS(n) is row-even (or row-odd) according as sgn(σ1σ2 · · ·σn) = +1 or −1, resp., where σ1, σ2, . . ., σn ∈ Sn are the rows of L. Similarly column-even, column-odd. L is even or odd according to its sign: sgn(L) = sgn(σ1σ2 · · ·σnτ1τ2 · · ·τn) where σi ∈ Sn are the columns, and τj ∈ Sn are the rows, of L. ELS(n) = {even Latin squares of order n} OLS(n) = {odd Latin squares of order n}

  • G. Eric Moorhouse

The Alon-Tarsi Conjecture

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Latin Squares

A Latin square of order n is an n × n array in which each of the symbols 1, 2, . . ., n occurs once in each row and in each

  • column. Denote LS(n) = {Latin squares of order n}.

L ∈ LS(n) is row-even (or row-odd) according as sgn(σ1σ2 · · ·σn) = +1 or −1, resp., where σ1, σ2, . . ., σn ∈ Sn are the rows of L. Similarly column-even, column-odd. L is even or odd according to its sign: sgn(L) = sgn(σ1σ2 · · ·σnτ1τ2 · · ·τn) where σi ∈ Sn are the columns, and τj ∈ Sn are the rows, of L. ELS(n) = {even Latin squares of order n} OLS(n) = {odd Latin squares of order n}

  • G. Eric Moorhouse

The Alon-Tarsi Conjecture

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Latin Squares

A Latin square of order n is an n × n array in which each of the symbols 1, 2, . . ., n occurs once in each row and in each

  • column. Denote LS(n) = {Latin squares of order n}.

L ∈ LS(n) is row-even (or row-odd) according as sgn(σ1σ2 · · ·σn) = +1 or −1, resp., where σ1, σ2, . . ., σn ∈ Sn are the rows of L. Similarly column-even, column-odd. L is even or odd according to its sign: sgn(L) = sgn(σ1σ2 · · ·σnτ1τ2 · · ·τn) where σi ∈ Sn are the columns, and τj ∈ Sn are the rows, of L. ELS(n) = {even Latin squares of order n} OLS(n) = {odd Latin squares of order n}

  • G. Eric Moorhouse

The Alon-Tarsi Conjecture

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Latin Squares

Example: L =    1 2 3 3 1 2 2 3 1    is row-even, column-odd, and sgn(L) = −1 (L is odd).

  • G. Eric Moorhouse

The Alon-Tarsi Conjecture

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Latin Squares

Example: L =    1 2 3 3 1 2 2 3 1    is row-even, column-odd, and sgn(L) = −1 (L is odd).

  • G. Eric Moorhouse

The Alon-Tarsi Conjecture

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Latin Squares

Example: L =    1 2 3 3 1 2 2 3 1    is row-even, column-odd, and sgn(L) = −1 (L is odd).

  • G. Eric Moorhouse

The Alon-Tarsi Conjecture

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Alon-Tarsi Conjecture

n |ELS(n)| |OLS(n)| 1 1 2 2 3 6 6 4 576 5 80640 80640 6 505958400 306892800 7 30739709952000 30739709952000 8 55019078005712486400 53756954453370470400 Conjecture (Alon and Tarsi, 1986) For even n 2, we have |ELS(n)| = |OLS(n)|. Equivalently, there are unequal numbers of row-even and row-odd Latin squares. N.B. There is also an apparently unrelated Alon-Tarsi Basis Conjecture.

  • G. Eric Moorhouse

The Alon-Tarsi Conjecture

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Alon-Tarsi Conjecture

n |ELS(n)| |OLS(n)| 1 1 2 2 3 6 6 4 576 5 80640 80640 6 505958400 306892800 7 30739709952000 30739709952000 8 55019078005712486400 53756954453370470400 Conjecture (Alon and Tarsi, 1986) For even n 2, we have |ELS(n)| = |OLS(n)|. Equivalently, there are unequal numbers of row-even and row-odd Latin squares. N.B. There is also an apparently unrelated Alon-Tarsi Basis Conjecture.

  • G. Eric Moorhouse

The Alon-Tarsi Conjecture

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Alon-Tarsi Conjecture

n |ELS(n)| |OLS(n)| 1 1 2 2 3 6 6 4 576 5 80640 80640 6 505958400 306892800 7 30739709952000 30739709952000 8 55019078005712486400 53756954453370470400 Conjecture (Alon and Tarsi, 1986) For even n 2, we have |ELS(n)| = |OLS(n)|. Equivalently, there are unequal numbers of row-even and row-odd Latin squares. N.B. There is also an apparently unrelated Alon-Tarsi Basis Conjecture.

  • G. Eric Moorhouse

The Alon-Tarsi Conjecture

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Alon-Tarsi Conjecture

n |ELS(n)| |OLS(n)| 1 1 2 2 3 6 6 4 576 5 80640 80640 6 505958400 306892800 7 30739709952000 30739709952000 8 55019078005712486400 53756954453370470400 Conjecture (Alon and Tarsi, 1986) For even n 2, we have |ELS(n)| = |OLS(n)|. Equivalently, there are unequal numbers of row-even and row-odd Latin squares. N.B. There is also an apparently unrelated Alon-Tarsi Basis Conjecture.

  • G. Eric Moorhouse

The Alon-Tarsi Conjecture

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Extended Alon-Tarsi Conjecture

FDLS(n) = {Latin squares of order n with 1’s on main diagonal} FDELS(n) = {even Latin squares of order n with 1’s on main diagonal} FDOLS(n) = {odd Latin squares of order n with 1’s on main diagonal} AT(n) = |FDELS(n)| − |FDOLS(n)| (n − 1)! n 1 2 3 4 5 6 7 AT(n) 1 −1 4 −24 2304 368640 6210846720

  • G. Eric Moorhouse

The Alon-Tarsi Conjecture

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Extended Alon-Tarsi Conjecture

FDLS(n) = {Latin squares of order n with 1’s on main diagonal} FDELS(n) = {even Latin squares of order n with 1’s on main diagonal} FDOLS(n) = {odd Latin squares of order n with 1’s on main diagonal} AT(n) = |FDELS(n)| − |FDOLS(n)| (n − 1)! n 1 2 3 4 5 6 7 AT(n) 1 −1 4 −24 2304 368640 6210846720

  • G. Eric Moorhouse

The Alon-Tarsi Conjecture

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Extended Alon-Tarsi Conjecture

FDLS(n) = {Latin squares of order n with 1’s on main diagonal} FDELS(n) = {even Latin squares of order n with 1’s on main diagonal} FDOLS(n) = {odd Latin squares of order n with 1’s on main diagonal} AT(n) = |FDELS(n)| − |FDOLS(n)| (n − 1)! n 1 2 3 4 5 6 7 AT(n) 1 −1 4 −24 2304 368640 6210846720

  • G. Eric Moorhouse

The Alon-Tarsi Conjecture

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Extended Alon-Tarsi Conjecture

FDLS(n) = {Latin squares of order n with 1’s on main diagonal} FDELS(n) = {even Latin squares of order n with 1’s on main diagonal} FDOLS(n) = {odd Latin squares of order n with 1’s on main diagonal} AT(n) = |FDELS(n)| − |FDOLS(n)| (n − 1)! |ELS(n)|−|OLS(n)| =    n!(n−1)!AT(n), for even n > 1; 0, for odd n > 1; 1, for n = 1. Extended Alon-Tarsi Conjecture (Zappa, 1997) For every n 1, we have AT(n) = 0.

  • G. Eric Moorhouse

The Alon-Tarsi Conjecture

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Extended Alon-Tarsi Conjecture

FDLS(n) = {Latin squares of order n with 1’s on main diagonal} FDELS(n) = {even Latin squares of order n with 1’s on main diagonal} FDOLS(n) = {odd Latin squares of order n with 1’s on main diagonal} AT(n) = |FDELS(n)| − |FDOLS(n)| (n − 1)! |ELS(n)|−|OLS(n)| =    n!(n−1)!AT(n), for even n > 1; 0, for odd n > 1; 1, for n = 1. Extended Alon-Tarsi Conjecture (Zappa, 1997) For every n 1, we have AT(n) = 0.

  • G. Eric Moorhouse

The Alon-Tarsi Conjecture

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Rota’s Basis Conjecture

Conjecture (Rota, 1992) Let B1 = {v11 , v12 , . . . , v1n }, B2 = {v21 , v22 , . . . , v2n }, . . . . . . ... . . . Bn = {vn1 , vn2 , . . . , vnn } be bases for an n-dimensional vector space V. Then the vectors in each row can be permuted in such a way that the columns also form a set of n bases for V. Rota has also conjectured a generalization to matroids of rank n, which has been verified only for n = 3.

  • G. Eric Moorhouse

The Alon-Tarsi Conjecture

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Rota’s Basis Conjecture

Conjecture (Rota, 1992) Let B1 = {v11 , v12 , . . . , v1n }, B2 = {v21 , v22 , . . . , v2n }, . . . . . . ... . . . Bn = {vn1 , vn2 , . . . , vnn } be bases for an n-dimensional vector space V. Then the vectors in each row can be permuted in such a way that the columns also form a set of n bases for V. Rota has also conjectured a generalization to matroids of rank n, which has been verified only for n = 3.

  • G. Eric Moorhouse

The Alon-Tarsi Conjecture

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Rota’s Basis Conjecture

Theorem (Huang and Rota (1992)) Let n ≥ 2 be even, and let F be a field of characteristic zero. If |ELS(n)| = |OLS(n)|, then Rota’s conjecture holds for F n. Proof uses bracket algebras. Theorem (Onn (1997)) Let n ≥ 2 be even, and let F be a field whose characteristic does not divide |ELS(n)| − |OLS(n)|. Then Rota’s conjecture holds for F n. Self-contained proof using a determinantal identity.

  • G. Eric Moorhouse

The Alon-Tarsi Conjecture

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Rota’s Basis Conjecture

Theorem (Huang and Rota (1992)) Let n ≥ 2 be even, and let F be a field of characteristic zero. If |ELS(n)| = |OLS(n)|, then Rota’s conjecture holds for F n. Proof uses bracket algebras. Theorem (Onn (1997)) Let n ≥ 2 be even, and let F be a field whose characteristic does not divide |ELS(n)| − |OLS(n)|. Then Rota’s conjecture holds for F n. Self-contained proof using a determinantal identity.

  • G. Eric Moorhouse

The Alon-Tarsi Conjecture

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Kahn’s Conjecture

Conjecture (Kahn, 1991) Let V be an n-dimensional vector space, and consider an n × n array of bases Bij for V. Then we may choose vij ∈ Bij such that the n × n array of vectors vij has a basis for V in every row and column. This generalizes both the Alon-Tarsi Conjecture and Rota’s Basis Conjecture. Apparently the generalization to matroids of rank n is also open.

  • G. Eric Moorhouse

The Alon-Tarsi Conjecture

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Kahn’s Conjecture

Conjecture (Kahn, 1991) Let V be an n-dimensional vector space, and consider an n × n array of bases Bij for V. Then we may choose vij ∈ Bij such that the n × n array of vectors vij has a basis for V in every row and column. This generalizes both the Alon-Tarsi Conjecture and Rota’s Basis Conjecture. Apparently the generalization to matroids of rank n is also open.

  • G. Eric Moorhouse

The Alon-Tarsi Conjecture

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Dinitz’ Problem

Conjecture (Dinitz, 1979) Given an n × n array of sets Sij of cardinality |Sij| = n, there exists a partial Latin square L of order n (i.e. no repeated symbols in any row or column) such that Lij ∈ Sij . {1, 2, 3} {1, 3, 4} {2, 3, 4} {1, 3, 5} {2, 3, 5} {2, 3, 4} {1, 3, 5} {2, 4, 5} {2, 3, 5} Proved by Galvin (1995) using results of Janssen (1993). Janssen had solved the problem affirmatively for (n − 1) × n partial Latin rectangles, using work of Alon and Tarsi. Alon and Tarsi (1986) had showed that their conjecture for even n, implies Dinitz’ Conjecture.

  • G. Eric Moorhouse

The Alon-Tarsi Conjecture

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Dinitz’ Problem

Conjecture (Dinitz, 1979) Given an n × n array of sets Sij of cardinality |Sij| = n, there exists a partial Latin square L of order n (i.e. no repeated symbols in any row or column) such that Lij ∈ Sij . {1, 2, 3} {1, 3, 4} {2, 3, 4} {1, 3, 5} {2, 3, 5} {2, 3, 4} {1, 3, 5} {2, 4, 5} {2, 3, 5} Proved by Galvin (1995) using results of Janssen (1993). Janssen had solved the problem affirmatively for (n − 1) × n partial Latin rectangles, using work of Alon and Tarsi. Alon and Tarsi (1986) had showed that their conjecture for even n, implies Dinitz’ Conjecture.

  • G. Eric Moorhouse

The Alon-Tarsi Conjecture

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Dinitz’ Problem

Conjecture (Dinitz, 1979) Given an n × n array of sets Sij of cardinality |Sij| = n, there exists a partial Latin square L of order n (i.e. no repeated symbols in any row or column) such that Lij ∈ Sij . {1, 2, 3} {1, 3, 4} {2, 3, 4} {1, 3, 5} {2, 3, 5} {2, 3, 4} {1, 3, 5} {2, 4, 5} {2, 3, 5} Proved by Galvin (1995) using results of Janssen (1993). Janssen had solved the problem affirmatively for (n − 1) × n partial Latin rectangles, using work of Alon and Tarsi. Alon and Tarsi (1986) had showed that their conjecture for even n, implies Dinitz’ Conjecture.

  • G. Eric Moorhouse

The Alon-Tarsi Conjecture

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List Colouring Conjecture

The edge chromatic number χ′(Γ) of a graph Γ is the minimum number of colours in a proper colouring of the edges

  • f Γ (i.e. no two edges of the

same colour meeting at a vertex). The list edge chromatic number ch′(Γ) is the minimum number k such that for every assignment of k-sets to the edges of Γ, there is a proper edge-colouring of Γ, with each edge colour chosen from the corresponding set. Clearly ch′(Γ) χ′(Γ). Conjecture (predates 1995; attribution unclear) ch′(Γ) = χ′(Γ). The Dinitz Conjecture regards the special case of a complete bipartite graph: ch′(Kn,n) = n = χ(Kn,n).

  • G. Eric Moorhouse

The Alon-Tarsi Conjecture

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List Colouring Conjecture

The edge chromatic number χ′(Γ) of a graph Γ is the minimum number of colours in a proper colouring of the edges

  • f Γ (i.e. no two edges of the

same colour meeting at a vertex). The list edge chromatic number ch′(Γ) is the minimum number k such that for every assignment of k-sets to the edges of Γ, there is a proper edge-colouring of Γ, with each edge colour chosen from the corresponding set. Clearly ch′(Γ) χ′(Γ). Conjecture (predates 1995; attribution unclear) ch′(Γ) = χ′(Γ). The Dinitz Conjecture regards the special case of a complete bipartite graph: ch′(Kn,n) = n = χ(Kn,n).

  • G. Eric Moorhouse

The Alon-Tarsi Conjecture

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List Colouring Conjecture

The edge chromatic number χ′(Γ) of a graph Γ is the minimum number of colours in a proper colouring of the edges

  • f Γ (i.e. no two edges of the

same colour meeting at a vertex). The list edge chromatic number ch′(Γ) is the minimum number k such that for every assignment of k-sets to the edges of Γ, there is a proper edge-colouring of Γ, with each edge colour chosen from the corresponding set. Clearly ch′(Γ) χ′(Γ). Conjecture (predates 1995; attribution unclear) ch′(Γ) = χ′(Γ). The Dinitz Conjecture regards the special case of a complete bipartite graph: ch′(Kn,n) = n = χ(Kn,n).

  • G. Eric Moorhouse

The Alon-Tarsi Conjecture

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List Colouring Conjecture

The edge chromatic number χ′(Γ) of a graph Γ is the minimum number of colours in a proper colouring of the edges

  • f Γ (i.e. no two edges of the

same colour meeting at a vertex). The list edge chromatic number ch′(Γ) is the minimum number k such that for every assignment of k-sets to the edges of Γ, there is a proper edge-colouring of Γ, with each edge colour chosen from the corresponding set. Clearly ch′(Γ) χ′(Γ). Conjecture (predates 1995; attribution unclear) ch′(Γ) = χ′(Γ). The Dinitz Conjecture regards the special case of a complete bipartite graph: ch′(Kn,n) = n = χ(Kn,n).

  • G. Eric Moorhouse

The Alon-Tarsi Conjecture

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Tensors (“Hypermatrices”)

An r-tensor of dimension n (and rank r) is an

r

  • n × n × · · · × n

array of scalars M =

  • mi1, i2, ..., ir
  • ,

1 i1, i2, . . ., ir n. Its Cayley “hyperdeterminant” is det(M) =

  • σ2,σ3,...,σr∈Sn

sgn(σ2σ3 · · ·σr)m1,σ2(1),σ3(1),··· ,σ2(1) ×m2,σ2(2),σ3(2),··· ,σ2(2) · · ·mn,σ2(n),σ3(n),··· ,σ2(n) .

  • G. Eric Moorhouse

The Alon-Tarsi Conjecture

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Tensors (“Hypermatrices”)

An r-tensor of dimension n (and rank r) is an

r

  • n × n × · · · × n

array of scalars M =

  • mi1, i2, ..., ir
  • ,

1 i1, i2, . . ., ir n. Its Cayley “hyperdeterminant” is det(M) =

  • σ2,σ3,...,σr∈Sn

sgn(σ2σ3 · · ·σr)m1,σ2(1),σ3(1),··· ,σ2(1) ×m2,σ2(2),σ3(2),··· ,σ2(2) · · ·mn,σ2(n),σ3(n),··· ,σ2(n) .

  • G. Eric Moorhouse

The Alon-Tarsi Conjecture

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Levi-Civita Tensor (“Determinant tensor”)

Ei1,i2,...,in =      0, if two of i1, i2, . . ., in coincide; sgn(σ), if (i1, i2, . . ., in) is a permutation σ of (1, 2, . . ., n). n! det E = |ELS(n)| − |OLS(n)| Theorem (Zappa, 1997) (i) If n 2 is even, then AT(n) 0. (ii) If n is even and AT(n) = 0, then AT(2n) = 0. (iii) If n is odd and AT(n)AT(n+1) = 0, then AT(2n) = 0.

  • G. Eric Moorhouse

The Alon-Tarsi Conjecture

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Levi-Civita Tensor (“Determinant tensor”)

Ei1,i2,...,in =      0, if two of i1, i2, . . ., in coincide; sgn(σ), if (i1, i2, . . ., in) is a permutation σ of (1, 2, . . ., n). n! det E = |ELS(n)| − |OLS(n)| Theorem (Zappa, 1997) (i) If n 2 is even, then AT(n) 0. (ii) If n is even and AT(n) = 0, then AT(2n) = 0. (iii) If n is odd and AT(n)AT(n+1) = 0, then AT(2n) = 0.

  • G. Eric Moorhouse

The Alon-Tarsi Conjecture

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Levi-Civita Tensor (“Determinant tensor”)

Ei1,i2,...,in =      0, if two of i1, i2, . . ., in coincide; sgn(σ), if (i1, i2, . . ., in) is a permutation σ of (1, 2, . . ., n). n! det E = |ELS(n)| − |OLS(n)| Theorem (Zappa, 1997) (i) If n 2 is even, then AT(n) 0. (ii) If n is even and AT(n) = 0, then AT(2n) = 0. (iii) If n is odd and AT(n)AT(n+1) = 0, then AT(2n) = 0.

  • G. Eric Moorhouse

The Alon-Tarsi Conjecture

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Levi-Civita Tensor (“Determinant tensor”)

Ei1,i2,...,in =      0, if two of i1, i2, . . ., in coincide; sgn(σ), if (i1, i2, . . ., in) is a permutation σ of (1, 2, . . ., n). n! det E = |ELS(n)| − |OLS(n)| Theorem (Zappa, 1997) (i) If n 2 is even, then AT(n) 0. (ii) If n is even and AT(n) = 0, then AT(2n) = 0. (iii) If n is odd and AT(n)AT(n+1) = 0, then AT(2n) = 0.

  • G. Eric Moorhouse

The Alon-Tarsi Conjecture

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Levi-Civita Tensor (“Determinant tensor”)

Ei1,i2,...,in =      0, if two of i1, i2, . . ., in coincide; sgn(σ), if (i1, i2, . . ., in) is a permutation σ of (1, 2, . . ., n). n! det E = |ELS(n)| − |OLS(n)| Theorem (Zappa, 1997) (i) If n 2 is even, then AT(n) 0. (ii) If n is even and AT(n) = 0, then AT(2n) = 0. (iii) If n is odd and AT(n)AT(n+1) = 0, then AT(2n) = 0.

  • G. Eric Moorhouse

The Alon-Tarsi Conjecture

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Drisko’s results

Theorem (Drisko (1997)) Let p be an odd prime. Then |ELS(p+1)| − |OLS(p+1)| ≡ (−1)(p+1)/2p2 mod p3. Theorem (Drisko (1998)) Let p be an odd prime. Then AT(p) ≡ (−1)(p−1)/2 mod p. Combining with Zappa’s results gives Corollary The Extended Alon-Tarsi Conjecture holds for n = 2rp, whenever r 0 and p is an odd prime.

  • G. Eric Moorhouse

The Alon-Tarsi Conjecture

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Drisko’s results

Theorem (Drisko (1997)) Let p be an odd prime. Then |ELS(p+1)| − |OLS(p+1)| ≡ (−1)(p+1)/2p2 mod p3. Theorem (Drisko (1998)) Let p be an odd prime. Then AT(p) ≡ (−1)(p−1)/2 mod p. Combining with Zappa’s results gives Corollary The Extended Alon-Tarsi Conjecture holds for n = 2rp, whenever r 0 and p is an odd prime.

  • G. Eric Moorhouse

The Alon-Tarsi Conjecture

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SLIDE 43

Drisko’s results

Theorem (Drisko (1997)) Let p be an odd prime. Then |ELS(p+1)| − |OLS(p+1)| ≡ (−1)(p+1)/2p2 mod p3. Theorem (Drisko (1998)) Let p be an odd prime. Then AT(p) ≡ (−1)(p−1)/2 mod p. Combining with Zappa’s results gives Corollary The Extended Alon-Tarsi Conjecture holds for n = 2rp, whenever r 0 and p is an odd prime.

  • G. Eric Moorhouse

The Alon-Tarsi Conjecture

slide-44
SLIDE 44

Drisko’s results

Theorem (Drisko (1998)) Let p be an odd prime. Then AT(p) ≡ (−1)(p−1)/2 mod p. Idea of proof: Let C be a p × p permutation matrix representing a p-cycle. Consider the group G of order p acting on FDLS(p), the set of Latin squares of order p with 1’s on the main diagonal, generated by L → C−1LC. Note that the action of G on FDLS(p) preserves signs, hence preserving the sum

  • L∈LS(p)

sgn(L) = |FDELS(p)| − |FDOLS(p)| = (p − 1)!|AT(p)|. Fixed points of G are circulant matrices having sign (−1)(p+1)/2. All remaining orbits are regular.

  • G. Eric Moorhouse

The Alon-Tarsi Conjecture

slide-45
SLIDE 45

Drisko’s results

Theorem (Drisko (1998)) Let p be an odd prime. Then AT(p) ≡ (−1)(p−1)/2 mod p. Idea of proof: Let C be a p × p permutation matrix representing a p-cycle. Consider the group G of order p acting on FDLS(p), the set of Latin squares of order p with 1’s on the main diagonal, generated by L → C−1LC. Note that the action of G on FDLS(p) preserves signs, hence preserving the sum

  • L∈LS(p)

sgn(L) = |FDELS(p)| − |FDOLS(p)| = (p − 1)!|AT(p)|. Fixed points of G are circulant matrices having sign (−1)(p+1)/2. All remaining orbits are regular.

  • G. Eric Moorhouse

The Alon-Tarsi Conjecture

slide-46
SLIDE 46

Drisko’s results

Theorem (Drisko (1998)) Let p be an odd prime. Then AT(p) ≡ (−1)(p−1)/2 mod p. Idea of proof: Let C be a p × p permutation matrix representing a p-cycle. Consider the group G of order p acting on FDLS(p), the set of Latin squares of order p with 1’s on the main diagonal, generated by L → C−1LC. Note that the action of G on FDLS(p) preserves signs, hence preserving the sum

  • L∈LS(p)

sgn(L) = |FDELS(p)| − |FDOLS(p)| = (p − 1)!|AT(p)|. Fixed points of G are circulant matrices having sign (−1)(p+1)/2. All remaining orbits are regular.

  • G. Eric Moorhouse

The Alon-Tarsi Conjecture

slide-47
SLIDE 47

Drisko’s results

Theorem (Drisko (1998)) Let p be an odd prime. Then AT(p) ≡ (−1)(p−1)/2 mod p. Idea of proof: Let C be a p × p permutation matrix representing a p-cycle. Consider the group G of order p acting on FDLS(p), the set of Latin squares of order p with 1’s on the main diagonal, generated by L → C−1LC. Note that the action of G on FDLS(p) preserves signs, hence preserving the sum

  • L∈LS(p)

sgn(L) = |FDELS(p)| − |FDOLS(p)| = (p − 1)!|AT(p)|. Fixed points of G are circulant matrices having sign (−1)(p+1)/2. All remaining orbits are regular.

  • G. Eric Moorhouse

The Alon-Tarsi Conjecture

slide-48
SLIDE 48

Drisko’s results

Theorem (Drisko (1998)) Let p be an odd prime. Then AT(p) ≡ (−1)(p−1)/2 mod p. Idea of proof: Let C be a p × p permutation matrix representing a p-cycle. Consider the group G of order p acting on FDLS(p), the set of Latin squares of order p with 1’s on the main diagonal, generated by L → C−1LC. Note that the action of G on FDLS(p) preserves signs, hence preserving the sum

  • L∈LS(p)

sgn(L) = |FDELS(p)| − |FDOLS(p)| = (p − 1)!|AT(p)|. Fixed points of G are circulant matrices having sign (−1)(p+1)/2. All remaining orbits are regular.

  • G. Eric Moorhouse

The Alon-Tarsi Conjecture

slide-49
SLIDE 49
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SLIDE 50