table of contents
play

Table of Contents Why DNA Computing? The Structure of DNA DNA - PDF document

Table of Contents Why DNA Computing? The Structure of DNA DNA Computing Operations on DNA Molecules Reading DNA Example of a Molecular Computer Information Processing with DNA Molecules Christian Jacob Why DNA Computing?


  1. Table of Contents Æ Why DNA Computing? Æ The Structure of DNA DNA Computing Æ Operations on DNA Molecules Æ Reading DNA Æ Example of a Molecular Computer Information Processing with DNA Molecules Christian Jacob Why DNA Computing? Challenges of DNA Computing Æ From silico to carbon. Æ Biochemical techniques are not yet From microchips to DNA molecules. sufficiently sophisticated or accurate. Æ Limits to miniaturization with current Æ Compare Charles Babbage´s „Analytical Engine“ (1810-1820) computer technologies. Æ Information processing capabilities of organic molecules ... Æ replace digital switching primitives, Æ enable new computing paradigms. Still: Why DNA Computing? Key Features of DNA Computing Æ Massive parallelism of DNA strands Æ Further reasons to investigate DNA computing: Æ high density of information storage Æ support for standard computation Æ ease of constructing many copies Æ better understanding of how nature Æ Watson-Crick complementarity computes Æ new data structures (molecules) Æ feature provided „for free“ Æ new operations Æ universal twin shuffle language l cut, paste, adjoin, insert, delete, ... Æ new computability models.

  2. Table of Contents The Structure of DNA Æ Why DNA Computing? Æ DNA is a polymer („large“ molecule). Æ The Structure of DNA Æ DNA is strung together from monomers („small“ mols.): deoxyribonucleotides. Æ Operations on DNA Molecules Æ Reading DNA Æ DNA = Deoxyribo Nucleic Acid Æ Example of a Molecular Computer Æ DNA supports two key functions for life: Æ coding for the production of proteins, Æ self-replication. Structure of a DNA Monomer Chemical Structure of a Nucleotide Æ Each deoxyribonucleotide consists of three components: Æ a sugar — deoxyribose Æ five carbon atoms: 1´ to 5´ Æ hydroxyl group (OH) attached to 3´ carbon Æ a phosphate group Æ a nitrogenous base. Linking of Nucleotides Structure of a DNA Monomer (2) Æ DNA nucleotides differ only by their Æ The DNA monomers can link in two ways: bases (B): Æ Phosphodiester bond Æ Hydrogen bond Æ purines Æ Adenine A Æ Guanine G Æ pyrimidines Æ Cytosine C Æ Thymine T

  3. Linking of Nucleotides Linking of Nucleotides Phosphodiester Bond Phosphodiester Bond Æ The 5´-phosphate group of one nucleotide is joined with the 3´-hydroxyl group of the other Æ strong (covalent) bond Æ directionality: 5´—3´ or 3´—5´ Linking of Nucleotides Linking of Nucleotides Hydrogen Bond Hydrogen Bond Æ The base of one nucleotide interacts with the base of another Æ base pairing (weak bond) l A — T (2 hydrogen bonds) l C — G (3 hydrogen bonds) Æ Watson-Crick complementarity l James D. Watson l Francis H. C. Crick l deduced double-helix structure of DNA in 1953 l Nobel Prize (1962) DNA Double Helix Table of Contents Æ Longer streches keep the double Æ Why DNA Computing? strands together through the Æ The Structure of DNA cumulative effect (the sum) of hydrogen bonds. Æ Operations on DNA Molecules Æ Reading DNA Æ Dense packing: l Bacteria: DNA molecule is 10,000 times Æ Example of a Molecular Computer longer than the host cell l Eucaryotes: „hierarchical“ packing

  4. Operations on DNA Molecules Separating and Fusing DNA Strands Æ Separating and fusing DNA strands Æ Denaturation: separating the single strands without breaking them Æ Lengthening of DNA Æ weaker hydrogen than phosphodiester Æ Shortening DNA bonding Æ Cutting DNA Æ heat DNA (85° - 90° C) Æ Multiplying DNA Æ Renaturation: Æ slowly cooling down Æ annealing of matching, separated strands Enzymes Lengthening DNA Machinery for Nucleotide Manipulation Æ Enzymes are proteins that catalyze Æ DNA polymerase enzymes chemical reactions. add nucleotides to a DNA molecule Æ Enzymes speed up chemical reactions Æ Requirements: extremely efficiently (speedup: 1012) Æ single-stranded template Æ Enzymes are very specific. Æ primer, Æ Nature has created a multitude of l bonded to the template enzymes that are useful in processing l 3´-hydroxyl end available for DNA. extension l Note: Terminal transferase needs no primer. Shortening DNA Shortening DNA Æ DNA nucleases are enzymes Æ DNA nucleases are enzymes that degrade DNA. that degrade DNA. Æ DNA exonucleases Æ DNA exonucleases l cleave (remove) nucleotides one at l cleave (remove) nucleotides one at a time from the ends of the strands a time from the ends of the strands l Example: Exonuclease III l Example: Bal31 3´-nuclease removes nucleotides from both degrading in 3´-5´direction strands

  5. Cutting DNA Multiplying DNA Æ DNA nucleases are enzymes Æ Amplification of a „small“ amount of a specific that degrade DNA. DNA fragment, lost in a huge amount of other pieces. Æ DNA endonucleases Æ „Needle in a haystack“ l destroy internal phosphodiester bonds Æ Solution: PCR = Polymerase Chain Reaction l Example: S1 cuts only single strands or within Æ devised by Karl Mullis in 1985 single strand sections Æ Nobel Prize Æ Restriction endonucleases Æ a very efficient molecular Xerox machine l much more specific l cut only double strands l at a specific set of sites (EcoRI) PCR PCR Step 0: Initialization Step 1: Denaturation Æ Start with a solution containing Æ Solution heated close to boiling the following ingredients: temperature. l the target DNA molecule Æ Hydrogen bonds between the l primers double strands are separated (synthetic oligonucleotides), into single strand molecules. complementary to the terminal sections l polymerase, heat resistant l nucleotides PCR PCR Step 2: Priming Step 3: Extension Æ The solution is cooled down (to Æ The solution is heated again (to about 55° C). about 72° C). Æ Primers anneal to their Æ A polymerase will extend the complementary borders. primers, using nucleotides available in the solution. Æ Two complete strands of the target DNA molecule are produced.

  6. PCR Table of Contents Efficient Xeroxing: 2n copies after n steps Æ Why DNA Computing? Æ The Structure of DNA Step 1 Æ Operations on DNA Molecules Step 2 Æ Reading DNA Æ Example of a Molecular Computer Step 3 Step 4 Step 5 Measuring the Length of DNA Molecules Schematic representation of gel electrophoresis Gel Electrophoresis Radioactive marker Æ DNA molecules are negatively charged. Æ Placed in an electric field, they will move towards the positive electrode. Æ The negative charge is proportional to the length of the DNA molecule. Ethidium bromide marker Æ The force needed to move the molecule is proportional to its length. Æ A gel makes the molecules move at different speeds. Æ DNA molecules are invisible, and must be marked (ethidium bromide, radioactive) Sequencing a DNA Molecule Sequencing — Part 1 Æ Sequencing: Æ Objective Æ reading the exact sequence of nucleotides Æ We want to sequence a single stranded molecule comprising a given DNA molecule � . Æ based on Æ Preparation l the polymerase action of extending a primed single Æ We extend � at the 3´ end by a short (20 bp) stranded template sequence � , which will act as the W-C complement l nucleotide analogues for the primer compl ( � ). l chemically modified l Usually, the primer is labelled (radioactively, or marked l e.g., replace 3´-hydroxyl group (3´-OH) by 3´- fluorescently) hydrogen atom (3´-H) Æ This results in a molecule � ´= 3´- �� . l dideoxynucleotides: - ddA, ddT, ddC, ddG l Sanger method, dideoxy enzymatic method

  7. Sequencing — Part 2 Reaction in Tube A Æ 4 tubes are prepared: Æ The polymerase enzyme l Tube A, Tube T, Tube C, Tube G extends the primer of � ´, using l Each of them contains the nucleotides present in l � molecules Tube A: l primers, compl ( � ) ddA, A, T, C, G. l polymerase Æ using only A, T, C, G: l nucleotides A, T, C, and G. l � ´ is extended to the full duplex. l Tube A contains a limited amount of ddA. l Tube T contains a limited amount of ddT. Æ using ddA rather than A: l Tube C contains a limited amount of ddC. l complementing will end at the l Tube G contains a limited amount of ddG. position of the ddA nucleotide. Resulting Sequences in Tubes Final Reading of the Strands Æ Tube A: Æ Tube C: Æ We read: Æ TCATGCACTGCG Æ TCATGCACTGCG Gel Æ T Æ TC Æ TCA electrophoresis: Æ TC Æ TCATGC Æ TCA Æ TCATGCA Æ TCATGCAC Æ TCAT Æ TCATG Æ TCATGCACTGC Æ Tube T: Æ Tube A: Æ TCATGC Æ Tube C: Æ TCATGCACTGCG Æ TCATGCA TCATGCACTGCG l TCATGCACTGCG Æ Tube G: l Æ TCATGCAC TCA l TC Æ T l Æ TCATGCACTGCG l TCATGC TCATGCA Æ TCATGCACT l Æ TCAT l TCATGCAC Æ TCATG Æ TCATGCACTG Æ Tube T: l TCATGCACTGC Æ TCATGCACT Æ TCATGCACTGC Æ TCATGCACTG TCATGCACTGCG l Æ TCATGCACTGCG Æ Tube G: T l l TCATGCACTGCG TCAT l l TCATG TCATGCACT l l TCATGCACTG Table of Contents Adleman´s Experiment Æ Why DNA Computing? Æ In 1994 Leonard M. Adleman showed how to solve the Hamilton Path Problem, using DNA Æ The Structure of DNA computation. Æ Operations on DNA Molecules Æ Reading DNA Æ Hamiltonian Path Problem: Æ Let G be a directed graph with designated input Æ Example of a Molecular Computer and output vertices, vin and vout. Æ Find a (Hamiltonian) path from vin to vout that involves every vertex in G exactly once.

Download Presentation
Download Policy: The content available on the website is offered to you 'AS IS' for your personal information and use only. It cannot be commercialized, licensed, or distributed on other websites without prior consent from the author. To download a presentation, simply click this link. If you encounter any difficulties during the download process, it's possible that the publisher has removed the file from their server.

Recommend


More recommend