syntactic complexity of regular languages
play

Syntactic Complexity of Regular Languages Janusz Brzozowski David - PowerPoint PPT Presentation

Syntactic Complexity Languages with Special Quotients Ideals and Closed Languages Prefix-, Suffix-, and Bifix-Free Languages Star-Free Languages Conclusions Syntactic Complexity of Regular Languages Janusz Brzozowski David R. Cheriton School


  1. Syntactic Complexity Languages with Special Quotients Ideals and Closed Languages Prefix-, Suffix-, and Bifix-Free Languages Star-Free Languages Conclusions Syntactic Complexity of Regular Languages Janusz Brzozowski David R. Cheriton School of Computer Science Tallinn University of Technology Tallinn, Estonia June 13, 2011 Janusz Brzozowski Syntactic Complexity of Regular Languages

  2. Syntactic Complexity Languages with Special Quotients Ideals and Closed Languages Prefix-, Suffix-, and Bifix-Free Languages Star-Free Languages Conclusions Languages Alphabet Σ a finite set of letters Set of all words Σ ∗ free monoid generated by Σ Set of non-empty words Σ + free semigroup generated by Σ Empty word ε L ⊆ Σ ∗ Language The ε -function L ε of a regular language L � ∅ , if ε �∈ L ; L ε = { ε } , if ε ∈ L . Janusz Brzozowski Syntactic Complexity of Regular Languages

  3. Syntactic Complexity Languages with Special Quotients Ideals and Closed Languages Prefix-, Suffix-, and Bifix-Free Languages Star-Free Languages Conclusions Congruences on Σ ∗ An equivalence relation ∼ on Σ ∗ is a left congruence if x ∼ y ⇔ ux ∼ uy , for all u ∈ Σ ∗ Janusz Brzozowski Syntactic Complexity of Regular Languages

  4. Syntactic Complexity Languages with Special Quotients Ideals and Closed Languages Prefix-, Suffix-, and Bifix-Free Languages Star-Free Languages Conclusions Congruences on Σ ∗ An equivalence relation ∼ on Σ ∗ is a left congruence if x ∼ y ⇔ ux ∼ uy , for all u ∈ Σ ∗ It is a right congruence if, for all x , y ∈ Σ ∗ , x ∼ y ⇔ xv ∼ yv , for all v ∈ Σ ∗ Janusz Brzozowski Syntactic Complexity of Regular Languages

  5. Syntactic Complexity Languages with Special Quotients Ideals and Closed Languages Prefix-, Suffix-, and Bifix-Free Languages Star-Free Languages Conclusions Congruences on Σ ∗ An equivalence relation ∼ on Σ ∗ is a left congruence if x ∼ y ⇔ ux ∼ uy , for all u ∈ Σ ∗ It is a right congruence if, for all x , y ∈ Σ ∗ , x ∼ y ⇔ xv ∼ yv , for all v ∈ Σ ∗ It is a congruence if it is both a left and a right congruence, or x ∼ y ⇔ uxv ∼ uyv , for all u , v ∈ Σ ∗ Janusz Brzozowski Syntactic Complexity of Regular Languages

  6. Syntactic Complexity Languages with Special Quotients Ideals and Closed Languages Prefix-, Suffix-, and Bifix-Free Languages Star-Free Languages Conclusions Nerode Congruence on Σ ∗ x ∼ L y if and only if xv ∈ L ⇔ yv ∈ L , for all v ∈ Σ ∗ Janusz Brzozowski Syntactic Complexity of Regular Languages

  7. Syntactic Complexity Languages with Special Quotients Ideals and Closed Languages Prefix-, Suffix-, and Bifix-Free Languages Star-Free Languages Conclusions Nerode Congruence on Σ ∗ x ∼ L y if and only if xv ∈ L ⇔ yv ∈ L , for all v ∈ Σ ∗ The (left) quotient, of a language L by a word w is the language L w = { x ∈ Σ ∗ | wx ∈ L } x ∼ L y if and only if L x = L y Number of classes of ∼ L = number of quotients of L The quotient complexity of L is the number of quotients of L Janusz Brzozowski Syntactic Complexity of Regular Languages

  8. Syntactic Complexity Languages with Special Quotients Ideals and Closed Languages Prefix-, Suffix-, and Bifix-Free Languages Star-Free Languages Conclusions Nerode Congruence on Σ ∗ x ∼ L y if and only if xv ∈ L ⇔ yv ∈ L , for all v ∈ Σ ∗ The (left) quotient, of a language L by a word w is the language L w = { x ∈ Σ ∗ | wx ∈ L } x ∼ L y if and only if L x = L y Number of classes of ∼ L = number of quotients of L The quotient complexity of L is the number of quotients of L The quotient automaton of a regular language L is A = ( Q , Σ , δ, q 0 , F ), where Q = { L w | w ∈ Σ ∗ } , δ ( L w , a ) = L wa , q 0 = L ε = L , F = { L w | ε ∈ L w } . κ ( L )=quotient complexity = state complexity Janusz Brzozowski Syntactic Complexity of Regular Languages

  9. Syntactic Complexity Languages with Special Quotients Ideals and Closed Languages Prefix-, Suffix-, and Bifix-Free Languages Star-Free Languages Conclusions Myhill Congruence x ≈ L y if and only if uxv ∈ L ⇔ uyv ∈ L for all u , v ∈ Σ ∗ Janusz Brzozowski Syntactic Complexity of Regular Languages

  10. Syntactic Complexity Languages with Special Quotients Ideals and Closed Languages Prefix-, Suffix-, and Bifix-Free Languages Star-Free Languages Conclusions Myhill Congruence x ≈ L y if and only if uxv ∈ L ⇔ uyv ∈ L for all u , v ∈ Σ ∗ Also known as the syntactic congruence of L Σ + / ≈ L syntactic semigroup of L Σ ∗ / ≈ L syntactic monoid of L Syntactic complexity σ ( L ): cardinality of syntactic semigroup Janusz Brzozowski Syntactic Complexity of Regular Languages

  11. Syntactic Complexity Languages with Special Quotients Ideals and Closed Languages Prefix-, Suffix-, and Bifix-Free Languages Star-Free Languages Conclusions Myhill Congruence x ≈ L y if and only if uxv ∈ L ⇔ uyv ∈ L for all u , v ∈ Σ ∗ Also known as the syntactic congruence of L Σ + / ≈ L syntactic semigroup of L Σ ∗ / ≈ L syntactic monoid of L Syntactic complexity σ ( L ): cardinality of syntactic semigroup The transformation semigroup T L of a quotient automaton A = ( Q , Σ , δ, q 0 , F ) of L : Set of transformations of states of A by non-empty words Syntactic semigroup isomorphic to transformation semigroup Janusz Brzozowski Syntactic Complexity of Regular Languages

  12. Syntactic Complexity Languages with Special Quotients Ideals and Closed Languages Prefix-, Suffix-, and Bifix-Free Languages Star-Free Languages Conclusions Quotient Complexity vs Syntactic Complexity c a c a b , c a , b a b A 2 A 3 1 A 1 0 0 1 0 1 c b a , b c c c a , c a b b 2 2 2 b a , b , c a Figure: Automata with various syntactic complexities. Janusz Brzozowski Syntactic Complexity of Regular Languages

  13. Syntactic Complexity Languages with Special Quotients Ideals and Closed Languages Prefix-, Suffix-, and Bifix-Free Languages Star-Free Languages Conclusions Quotient Complexity vs Syntactic Complexity c a c a b , c a , b a b A 2 A 3 1 A 1 0 0 1 0 1 c b a , b c c c a , c a b b 2 2 2 b a , b , c a Figure: Automata with various syntactic complexities. σ ( L 1 ) = 3 σ ( L 2 ) = 9 σ ( L 3 ) = 27 Can we predict this? Janusz Brzozowski Syntactic Complexity of Regular Languages

  14. Syntactic Complexity Languages with Special Quotients Ideals and Closed Languages Prefix-, Suffix-, and Bifix-Free Languages Star-Free Languages Conclusions Transformations of Q = { 0 , 1 , . . ., n − 1 } � 0 � 1 · · · n − 2 n − 1 A transformation t = · · · i 0 i 1 i n − 2 i n − 1 The image of element i under transformation t is it The identity transformation maps each element to itself t contains a cycle ( i 1 , i 2 , . . . , i k ) of length k if there exist i 1 , . . . , i k such that i 1 t = i 2 , i 2 t = i 3 , . . . , i k − 1 t = i k , i k t = i 1 � i � A singular transformation, denoted by , has it = j , and j ht = h for all h � = i . For i < j , a transposition is the cycle ( i , j ) � Q � A constant transformation, , has it = j for all i . j Janusz Brzozowski Syntactic Complexity of Regular Languages

  15. Syntactic Complexity Languages with Special Quotients Ideals and Closed Languages Prefix-, Suffix-, and Bifix-Free Languages Star-Free Languages Conclusions Generators Theorem (Piccard, 1935) The complete transformation monoid T Q on Q = { 0 , 1 , . . . , n − 1 } of size n n can be generated by any cyclic permutation of n elements together with a transposition and a “returning” � n − 1 � transformation r = . In particular, T n can be generated by 0 � n − 1 � c = (0 , 1 , . . . , n − 1) , t = (0 , 1) and r = . 0 Janusz Brzozowski Syntactic Complexity of Regular Languages

  16. Syntactic Complexity Languages with Special Quotients Ideals and Closed Languages Prefix-, Suffix-, and Bifix-Free Languages Star-Free Languages Conclusions Generators Theorem (Piccard, 1935) The complete transformation monoid T Q on Q = { 0 , 1 , . . . , n − 1 } of size n n can be generated by any cyclic permutation of n elements together with a transposition and a “returning” � n − 1 � transformation r = . In particular, T n can be generated by 0 � n − 1 � c = (0 , 1 , . . . , n − 1) , t = (0 , 1) and r = . 0 Proposition For any language L with κ ( L ) = n > 1 , we have n − 1 ≤ σ ( L ) ≤ n n . Each state > 0 reached from the initial state, so at least n − 1 If Σ = { a } and L = a n − 1 a ∗ , then κ ( L ) = n , and σ ( L ) = n − 1 Janusz Brzozowski Syntactic Complexity of Regular Languages

  17. Syntactic Complexity Languages with Special Quotients Ideals and Closed Languages Prefix-, Suffix-, and Bifix-Free Languages Star-Free Languages Conclusions Special Quotients, κ ( L ) = n If one of the quotients of L is ∅ (respectively, { ε } , Σ ∗ , Σ + ), then we say that L has ∅ (respectively, { ε } , Σ ∗ , Σ + ). Janusz Brzozowski Syntactic Complexity of Regular Languages

  18. Syntactic Complexity Languages with Special Quotients Ideals and Closed Languages Prefix-, Suffix-, and Bifix-Free Languages Star-Free Languages Conclusions Special Quotients, κ ( L ) = n If one of the quotients of L is ∅ (respectively, { ε } , Σ ∗ , Σ + ), then we say that L has ∅ (respectively, { ε } , Σ ∗ , Σ + ). A quotient L w of a language L is uniquely reachable (ur) if L x = L w implies that x = w . Janusz Brzozowski Syntactic Complexity of Regular Languages

Download Presentation
Download Policy: The content available on the website is offered to you 'AS IS' for your personal information and use only. It cannot be commercialized, licensed, or distributed on other websites without prior consent from the author. To download a presentation, simply click this link. If you encounter any difficulties during the download process, it's possible that the publisher has removed the file from their server.

Recommend


More recommend