Seriesrlciuits order Second transient response - - PowerPoint PPT Presentation

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Seriesrlciuits order Second transient response - - PowerPoint PPT Presentation

Seriesrlciuits order Second transient response current-voltagerelations.hr# capaoi.r.IE#=cdI 1- i - v Component symbol relation R = in Resistor a- Who . R Or + - Or I terrors L did Inductor K = + q - dt R L - m -


slide-1
SLIDE 1

Seriesrlciuits

Second

  • rder

transient

response

slide-2
SLIDE 2

current-voltagerelations.hr#

Component

symbol

i - v

relation

1-

R

Resistor

a-Who

Or

= in . R + Or
  • I

capaoi.r.IE#=cdI

Inductor

terrors

K

= L did + q
  • dt
slide-3
SLIDE 3 R L
  • m-mm
+ |

¥

  • v. =
a

KVL

: i R t

k

+ Vc =
  • v. =L dd÷
= L dat

i

= c daff

⇒ [

i

Ctsdt

=

Ck

acct)

= I #idt

t

Vo

  • i. R t
L dat + I #idt

t

Vo =
slide-4
SLIDE 4

Differentiate

with

respect

to '

t

' .
  • i. R t
L dat + I ft '

i dt

t

Vo =
  • R
. di + L

d- i dt

at

+ I i =

Divide

by

' L '

da÷+Ed÷+ziT

slide-5
SLIDE 5

SOLVE

Differential

ddI÷

+

Eddie

+ Ici =
  • equation
St Assume

ict )

=

ke

then

ddI

=

Ks

' est

and

ddt

= Ks est

Ks
  • est

t Ry

Ks est t t k est = O

5-ies-tc-fcheghauE.int?

slide-6
SLIDE 6

Sot

'

: s't Res t # = o s =
  • Eh

±

LC

=

=
  • iz

±

Fixate:&:Ygeae

  • T

c

  • r complex

Define

Wo = Resonant

frequency

Cracks )

÷÷±=¥÷÷÷÷¥z

X

=

R

  • 2L
=

attenuation

constant
slide-7
SLIDE 7 S .
  • d If

L>wo→Rootsarereal0VsEyRsDAMmPED

te

x=wo→Roa%segre;da¥atmFE¥

te

×<wo→RjgaEGmek×UN?7?amPED

*

slide-8
SLIDE 8

DampedFreqnenoy#

B

  • frequency
  • f

damped

  • scillations

f

  • FF

radians

"

h

"

4

Per resonant

attenuation second

frequency

constant

=2T(frequency

in Herty) .