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Sequential properties of measures Piotr BorodulinNadzieja (Wroc - PowerPoint PPT Presentation

Preliminaries Problems An example Sequential properties of measures Piotr BorodulinNadzieja (Wroc law) Winterschool 2011, Hejnice joint work with Omar Selim (Norwich) Piotr BorodulinNadzieja (Wroc law) Sequential properties of


  1. Preliminaries Problems An example Sequential properties of measures Piotr Borodulin–Nadzieja (Wroc� law) Winterschool 2011, Hejnice joint work with Omar Selim (Norwich) Piotr Borodulin–Nadzieja (Wroc� law) Sequential properties of measures

  2. Preliminaries Problems An example Space of probability measures Notation K - a (Hausdorff) compact space; N = { 1 , 2 , . . . } ; P ( K ) - space of probability Borel measures on K . Weak* convergence A sequence ( µ n ) from P ( K ) is weak ∗ convergent to µ if � � f d µ n → f d µ K K for each continuous f : K → R . Piotr Borodulin–Nadzieja (Wroc� law) Sequential properties of measures

  3. Preliminaries Problems An example Space of probability measures Notation K - a (Hausdorff) compact space; N = { 1 , 2 , . . . } ; P ( K ) - space of probability Borel measures on K . Weak* convergence A sequence ( µ n ) from P ( K ) is weak ∗ convergent to µ if � � f d µ n → f d µ K K for each continuous f : K → R . Piotr Borodulin–Nadzieja (Wroc� law) Sequential properties of measures

  4. Preliminaries Problems An example Weak* convergence in 0-dim spaces Weak* convergence A sequence ( µ n ) from P ( K ) is weak ∗ convergent to µ if � � f d µ n → f d µ K K for each continuous f : K → R . Remark If K is zero–dimensional, then µ n converges weakly to µ if and only if µ n ( A ) → µ ( A ) for every clopen subset A ⊆ K . Piotr Borodulin–Nadzieja (Wroc� law) Sequential properties of measures

  5. Preliminaries Problems An example Levels of complexity in P(K) Sequential closures h : K → h [ K ] ⊆ P ( K ) defined by h ( x ) = δ x is a homeomorphism; S 0 ( K ) = conv ( { δ x : x ∈ K } ); let S 1 ( K ) be the weak ∗ –sequential closure of S 0 ( K ); generally: let S α ( K ) be the weak ∗ –sequential closure of � β<α S β ( K ); S ( K ) = S ω 1 ( K ). Piotr Borodulin–Nadzieja (Wroc� law) Sequential properties of measures

  6. Preliminaries Problems An example Levels of complexity in P(K) Sequential closures h : K → h [ K ] ⊆ P ( K ) defined by h ( x ) = δ x is a homeomorphism; S 0 ( K ) = conv ( { δ x : x ∈ K } ); let S 1 ( K ) be the weak ∗ –sequential closure of S 0 ( K ); generally: let S α ( K ) be the weak ∗ –sequential closure of � β<α S β ( K ); S ( K ) = S ω 1 ( K ). Piotr Borodulin–Nadzieja (Wroc� law) Sequential properties of measures

  7. Preliminaries Problems An example Levels of complexity in P(K) Sequential closures h : K → h [ K ] ⊆ P ( K ) defined by h ( x ) = δ x is a homeomorphism; S 0 ( K ) = conv ( { δ x : x ∈ K } ); let S 1 ( K ) be the weak ∗ –sequential closure of S 0 ( K ); generally: let S α ( K ) be the weak ∗ –sequential closure of � β<α S β ( K ); S ( K ) = S ω 1 ( K ). Piotr Borodulin–Nadzieja (Wroc� law) Sequential properties of measures

  8. Preliminaries Problems An example Levels of complexity in P(K) Sequential closures h : K → h [ K ] ⊆ P ( K ) defined by h ( x ) = δ x is a homeomorphism; S 0 ( K ) = conv ( { δ x : x ∈ K } ); let S 1 ( K ) be the weak ∗ –sequential closure of S 0 ( K ); generally: let S α ( K ) be the weak ∗ –sequential closure of � β<α S β ( K ); S ( K ) = S ω 1 ( K ). Piotr Borodulin–Nadzieja (Wroc� law) Sequential properties of measures

  9. Preliminaries Problems An example A measure outside the sequential closure Remark If µ ∈ S ( K ), then it has a separable carrier, i.e. a closed set F ⊆ K with µ ( F ) = 1 (not necessarily the support). Corollary Let R = Bor ([0 , 1]) / Null be the measure algebra and let R be its Stone space. Then the standard measure λ on R is in P ( R ) but not in S ( R ). Piotr Borodulin–Nadzieja (Wroc� law) Sequential properties of measures

  10. Preliminaries Problems An example A measure outside the sequential closure Remark If µ ∈ S ( K ), then it has a separable carrier, i.e. a closed set F ⊆ K with µ ( F ) = 1 (not necessarily the support). Corollary Let R = Bor ([0 , 1]) / Null be the measure algebra and let R be its Stone space. Then the standard measure λ on R is in P ( R ) but not in S ( R ). Piotr Borodulin–Nadzieja (Wroc� law) Sequential properties of measures

  11. Preliminaries Problems An example Uniform distribution Fact A measure µ is in S 1 ( K ) if and only if it has a uniformly distributed sequence. Theorems Many spaces K have property: P ( K ) = S 1 ( K ). E.g. scattered spaces; metric spaces; 2 ω 1 [Losert, 79]; 2 c [Fremlin, 00’s]. Piotr Borodulin–Nadzieja (Wroc� law) Sequential properties of measures

  12. Preliminaries Problems An example Uniform distribution Fact A measure µ is in S 1 ( K ) if and only if it has a uniformly distributed sequence. Theorems Many spaces K have property: P ( K ) = S 1 ( K ). E.g. scattered spaces; metric spaces; 2 ω 1 [Losert, 79]; 2 c [Fremlin, 00’s]. Piotr Borodulin–Nadzieja (Wroc� law) Sequential properties of measures

  13. Preliminaries Problems An example Problems Theorem (Plebanek, PBN) If K is Koppelberg compact, then P ( K ) = S ( K ). Problem 1 Is there a space K such that S 1 ( K ) � = S ( K )? Problem 2 Is there a space K such that S 1 ( K ) � = S ( K ) = P ( K )? Piotr Borodulin–Nadzieja (Wroc� law) Sequential properties of measures

  14. Preliminaries Problems An example Problems Theorem (Plebanek, PBN) If K is Koppelberg compact, then P ( K ) = S ( K ). Problem 1 Is there a space K such that S 1 ( K ) � = S ( K )? Problem 2 Is there a space K such that S 1 ( K ) � = S ( K ) = P ( K )? Piotr Borodulin–Nadzieja (Wroc� law) Sequential properties of measures

  15. Preliminaries Problems An example Problems Theorem (Plebanek, PBN) If K is Koppelberg compact, then P ( K ) = S ( K ). Problem 1 Is there a space K such that S 1 ( K ) � = S ( K )? Problem 2 Is there a space K such that S 1 ( K ) � = S ( K ) = P ( K )? Piotr Borodulin–Nadzieja (Wroc� law) Sequential properties of measures

  16. Preliminaries Problems An example Asymptotic density Asymptotic density function We say that A ⊆ N has a density if the limit | A ∩ { 1 , 2 , . . . , n }| lim = d ( A ) n n →∞ exists. Density and weak ∗ convergence If every element of a Boolean algebra A ⊆ P ( N ) has a density, then for µ defined on the Stone space K of A by µ ( � A ) = d ( A ) for each A ∈ A we have δ 1 ( A ) + . . . + δ n ( A ) µ ( � A ) = lim . n n →∞ Piotr Borodulin–Nadzieja (Wroc� law) Sequential properties of measures

  17. Preliminaries Problems An example Asymptotic density Asymptotic density function We say that A ⊆ N has a density if the limit | A ∩ { 1 , 2 , . . . , n }| lim = d ( A ) n n →∞ exists. Density and weak ∗ convergence If every element of a Boolean algebra A ⊆ P ( N ) has a density, then for µ defined on the Stone space K of A by µ ( � A ) = d ( A ) for each A ∈ A we have δ 1 ( A ) + . . . + δ n ( A ) µ ( � A ) = lim . n n →∞ Piotr Borodulin–Nadzieja (Wroc� law) Sequential properties of measures

  18. Preliminaries Problems An example Asymptotic density Density and weak* convergence If every element of a Boolean algebra A ⊆ P ( N ) has a density, then for µ defined on the Stone space K of A by µ ( � A ) = d ( A ) for each A ∈ A we have δ 1 ( A ) + . . . + δ n ( A ) µ ( � A ) = lim . n n →∞ Corollary µ ∈ S 1 ( N ) ⊆ S 1 ( K ) . Piotr Borodulin–Nadzieja (Wroc� law) Sequential properties of measures

  19. Preliminaries Problems An example Asymptotic density Density and weak* convergence If every element of a Boolean algebra A ⊆ P ( N ) has a density, then for µ defined on the Stone space K of A by µ ( � A ) = d ( A ) for each A ∈ A we have δ 1 ( A ) + . . . + δ n ( A ) µ ( � A ) = lim . n n →∞ Corollary µ ∈ S 1 ( N ) ⊆ S 1 ( K ) . Piotr Borodulin–Nadzieja (Wroc� law) Sequential properties of measures

  20. Preliminaries Problems An example Asymptotic density Density and weak* convergence If every element of a Boolean algebra A ⊆ P ( N ) has a density, then for µ defined on the Stone space K of A by µ ( � A ) = d ( A ) for each A ∈ A we have δ 1 ( A ) + . . . + δ n ( A ) µ ( � A ) = lim . n n →∞ Corollary µ ∈ S 1 ( N ) ⊆ S 1 ( K ) . Piotr Borodulin–Nadzieja (Wroc� law) Sequential properties of measures

  21. Preliminaries Problems An example Limit of densities Relative density Fix a sequence ( B n ) n ∈ N of infinite and pairwise disjoint subsets of N such that � n B n = N . Let n ∈ N . Enumerate B n = { b 1 < b 2 < . . . } . For A ⊆ B n let d n ( A ) = d ( { i : b i ∈ A } ) . Limit of densities Let d ′ ( A ) = lim n →∞ d n ( A ) provided this limit exist. If each element A of a Boolean algebra A ⊆ P ( N ) is such that d ′ ( A ) exists, then µ ∈ P ( Stone ( A )) defined by µ ( � A ) = d ′ ( A ) is in S 2 ( N ) Piotr Borodulin–Nadzieja (Wroc� law) Sequential properties of measures

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