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Semifinite Generalized Quadrangles G. Eric Moorhouse Department of - - PowerPoint PPT Presentation

Semifinite Generalized Quadrangles G. Eric Moorhouse Department of Mathematics University of Wyoming RMAC Seminar10 October 2014 G. Eric Moorhouse Semifinite Generalized Quadrangles Generalized Quadrangles A generalized quadrangle (GQ) is


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SLIDE 1

Semifinite Generalized Quadrangles

  • G. Eric Moorhouse

Department of Mathematics University of Wyoming

RMAC Seminar—10 October 2014

  • G. Eric Moorhouse

Semifinite Generalized Quadrangles

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SLIDE 2

Generalized Quadrangles

A generalized quadrangle (GQ) is a point-line incidence structure in which every non-incident point-line pair (P, ℓ) has exactly one line through P meeting ℓ: We assume every point is on more than two lines; and every line has more than 2 points.

  • G. Eric Moorhouse

Semifinite Generalized Quadrangles

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SLIDE 3

Semifinite Generalized Quadrangles

We say the GQ is semifinite if it has infinitely many points and lines, but the number of points on each line (always the same number) is k <∞. (Open question: Can this happen?) There is no semifinite GQ with line size k =3 (Cameron, 1981 . . . one paragraph). There is no semifinite GQ with line size k =4 (Brouwer, 1991 . . . three pages). There is no semifinite GQ with line size k =5 (Cherlin, 2005 . . . seven pages of model theory). Nothing is known for line size k 6. Experts differ on whether semifinite GQ’s may exist at all.

  • G. Eric Moorhouse

Semifinite Generalized Quadrangles

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SLIDE 4

Semifinite Generalized Quadrangles

We say the GQ is semifinite if it has infinitely many points and lines, but the number of points on each line (always the same number) is k <∞. (Open question: Can this happen?) There is no semifinite GQ with line size k =3 (Cameron, 1981 . . . one paragraph). There is no semifinite GQ with line size k =4 (Brouwer, 1991 . . . three pages). There is no semifinite GQ with line size k =5 (Cherlin, 2005 . . . seven pages of model theory). Nothing is known for line size k 6. Experts differ on whether semifinite GQ’s may exist at all.

  • G. Eric Moorhouse

Semifinite Generalized Quadrangles

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SLIDE 5

Semifinite Generalized Quadrangles

We say the GQ is semifinite if it has infinitely many points and lines, but the number of points on each line (always the same number) is k <∞. (Open question: Can this happen?) There is no semifinite GQ with line size k =3 (Cameron, 1981 . . . one paragraph). There is no semifinite GQ with line size k =4 (Brouwer, 1991 . . . three pages). There is no semifinite GQ with line size k =5 (Cherlin, 2005 . . . seven pages of model theory). Nothing is known for line size k 6. Experts differ on whether semifinite GQ’s may exist at all.

  • G. Eric Moorhouse

Semifinite Generalized Quadrangles

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SLIDE 6

Semifinite Generalized Quadrangles

We say the GQ is semifinite if it has infinitely many points and lines, but the number of points on each line (always the same number) is k <∞. (Open question: Can this happen?) There is no semifinite GQ with line size k =3 (Cameron, 1981 . . . one paragraph). There is no semifinite GQ with line size k =4 (Brouwer, 1991 . . . three pages). There is no semifinite GQ with line size k =5 (Cherlin, 2005 . . . seven pages of model theory). Nothing is known for line size k 6. Experts differ on whether semifinite GQ’s may exist at all.

  • G. Eric Moorhouse

Semifinite Generalized Quadrangles

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SLIDE 7

Semifinite Generalized Quadrangles

We say the GQ is semifinite if it has infinitely many points and lines, but the number of points on each line (always the same number) is k <∞. (Open question: Can this happen?) There is no semifinite GQ with line size k =3 (Cameron, 1981 . . . one paragraph). There is no semifinite GQ with line size k =4 (Brouwer, 1991 . . . three pages). There is no semifinite GQ with line size k =5 (Cherlin, 2005 . . . seven pages of model theory). Nothing is known for line size k 6. Experts differ on whether semifinite GQ’s may exist at all.

  • G. Eric Moorhouse

Semifinite Generalized Quadrangles

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SLIDE 8

First-Order Axioms for Generalized Quadrangles

P(x), L(x): unary predicates I(x, y): binary predicate

1

(∀x)(P(x) ↔ ¬L(x))

2

(∀x)(∀y)

  • I(x, y) → (P(x) ∧ L(y))
  • 3

(∀p)(∀ℓ)

  • (P(p)∧L(ℓ)) → (∃q)(∃m)(I(p, m)∧I(q, m)∧I(q, ℓ)
  • 4

(∀p1)(∀p2)(∀ℓ1)(∀ℓ2)

  • (I(p1, ℓ1)∧I(p1, ℓ2)∧I(p2, ℓ1)∧I(p2, ℓ2)) → (p1=p2∧ℓ1=ℓ2)
  • 5

(∀p1)(∀p2)(∀p3)(∀ℓ1)(∀ℓ2)(∀ℓ3)

  • (I(p1, ℓ1) ∧ I(p1, ℓ2) ∧

I(p2, ℓ2) ∧ I(p2, ℓ3) ∧ I(p3, ℓ3) ∧ I(p3, ℓ1)) → (p1=p2 ∧ p1=p3 ∧ p2=p3 ∧ ℓ1=ℓ2 ∧ ℓ1=ℓ3 ∧ ℓ2=ℓ3)

  • 6

(∃p1)(∃p2)(∃p3)(∃ℓ) (I(p1, ℓ) ∧ I(p2, ℓ) ∧ I(p3, ℓ) ∧ p1=p2 ∧ p1=p3 ∧ p2=p3

  • 7

similarly, each point is on at least 3 lines

  • G. Eric Moorhouse

Semifinite Generalized Quadrangles

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SLIDE 9

First-Order Axioms for Generalized Quadrangles

P(x), L(x): unary predicates I(x, y): binary predicate

1

(∀x)(P(x) ↔ ¬L(x))

2

(∀x)(∀y)

  • I(x, y) → (P(x) ∧ L(y))
  • 3

(∀p)(∀ℓ)

  • (P(p)∧L(ℓ)) → (∃q)(∃m)(I(p, m)∧I(q, m)∧I(q, ℓ)
  • 4

(∀p1)(∀p2)(∀ℓ1)(∀ℓ2)

  • (I(p1, ℓ1)∧I(p1, ℓ2)∧I(p2, ℓ1)∧I(p2, ℓ2)) → (p1=p2∧ℓ1=ℓ2)
  • 5

(∀p1)(∀p2)(∀p3)(∀ℓ1)(∀ℓ2)(∀ℓ3)

  • (I(p1, ℓ1) ∧ I(p1, ℓ2) ∧

I(p2, ℓ2) ∧ I(p2, ℓ3) ∧ I(p3, ℓ3) ∧ I(p3, ℓ1)) → (p1=p2 ∧ p1=p3 ∧ p2=p3 ∧ ℓ1=ℓ2 ∧ ℓ1=ℓ3 ∧ ℓ2=ℓ3)

  • 6

(∃p1)(∃p2)(∃p3)(∃ℓ) (I(p1, ℓ) ∧ I(p2, ℓ) ∧ I(p3, ℓ) ∧ p1=p2 ∧ p1=p3 ∧ p2=p3

  • 7

similarly, each point is on at least 3 lines

  • G. Eric Moorhouse

Semifinite Generalized Quadrangles

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SLIDE 10

First-Order Axioms for Generalized Quadrangles

P(x), L(x): unary predicates I(x, y): binary predicate

1

(∀x)(P(x) ↔ ¬L(x))

2

(∀x)(∀y)

  • I(x, y) → (P(x) ∧ L(y))
  • 3

(∀p)(∀ℓ)

  • (P(p)∧L(ℓ)) → (∃q)(∃m)(I(p, m)∧I(q, m)∧I(q, ℓ)
  • 4

(∀p1)(∀p2)(∀ℓ1)(∀ℓ2)

  • (I(p1, ℓ1)∧I(p1, ℓ2)∧I(p2, ℓ1)∧I(p2, ℓ2)) → (p1=p2∧ℓ1=ℓ2)
  • 5

(∀p1)(∀p2)(∀p3)(∀ℓ1)(∀ℓ2)(∀ℓ3)

  • (I(p1, ℓ1) ∧ I(p1, ℓ2) ∧

I(p2, ℓ2) ∧ I(p2, ℓ3) ∧ I(p3, ℓ3) ∧ I(p3, ℓ1)) → (p1=p2 ∧ p1=p3 ∧ p2=p3 ∧ ℓ1=ℓ2 ∧ ℓ1=ℓ3 ∧ ℓ2=ℓ3)

  • 6

(∃p1)(∃p2)(∃p3)(∃ℓ) (I(p1, ℓ) ∧ I(p2, ℓ) ∧ I(p3, ℓ) ∧ p1=p2 ∧ p1=p3 ∧ p2=p3

  • 7

similarly, each point is on at least 3 lines

  • G. Eric Moorhouse

Semifinite Generalized Quadrangles

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SLIDE 11

First-Order Axioms for Generalized Quadrangles

P(x), L(x): unary predicates I(x, y): binary predicate

1

(∀x)(P(x) ↔ ¬L(x))

2

(∀x)(∀y)

  • I(x, y) → (P(x) ∧ L(y))
  • 3

(∀p)(∀ℓ)

  • (P(p)∧L(ℓ)) → (∃q)(∃m)(I(p, m)∧I(q, m)∧I(q, ℓ)
  • 4

(∀p1)(∀p2)(∀ℓ1)(∀ℓ2)

  • (I(p1, ℓ1)∧I(p1, ℓ2)∧I(p2, ℓ1)∧I(p2, ℓ2)) → (p1=p2∧ℓ1=ℓ2)
  • 5

(∀p1)(∀p2)(∀p3)(∀ℓ1)(∀ℓ2)(∀ℓ3)

  • (I(p1, ℓ1) ∧ I(p1, ℓ2) ∧

I(p2, ℓ2) ∧ I(p2, ℓ3) ∧ I(p3, ℓ3) ∧ I(p3, ℓ1)) → (p1=p2 ∧ p1=p3 ∧ p2=p3 ∧ ℓ1=ℓ2 ∧ ℓ1=ℓ3 ∧ ℓ2=ℓ3)

  • 6

(∃p1)(∃p2)(∃p3)(∃ℓ) (I(p1, ℓ) ∧ I(p2, ℓ) ∧ I(p3, ℓ) ∧ p1=p2 ∧ p1=p3 ∧ p2=p3

  • 7

similarly, each point is on at least 3 lines

  • G. Eric Moorhouse

Semifinite Generalized Quadrangles

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SLIDE 12

First-Order Axioms for Generalized Quadrangles

To say that the line size is 3, add an axiom

  • (∀p1)(∀p2)(∀p3)(∀p4)(∀ℓ)
  • (I(p1, ℓ) ∧ I(p2, ℓ) ∧ I(p3, ℓ) ∧ I(p4, ℓ))

→ (p1=p2 ∨ p1=p3 ∨ p1=p4 ∨ p2=p3 ∨ p2=p4 ∨ p3=p4) To say that there are infinitely many points and lines, add an infinite list of axioms

  • (∃x1)(∃x2)(x1=x2)
  • (∃x1)(∃x2)(∃x3)(x1=x2 ∨ x1=x3 ∨ x2=x3)
  • etc.
  • G. Eric Moorhouse

Semifinite Generalized Quadrangles

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SLIDE 13

First-Order Axioms for Generalized Quadrangles

To say that the line size is 3, add an axiom

  • (∀p1)(∀p2)(∀p3)(∀p4)(∀ℓ)
  • (I(p1, ℓ) ∧ I(p2, ℓ) ∧ I(p3, ℓ) ∧ I(p4, ℓ))

→ (p1=p2 ∨ p1=p3 ∨ p1=p4 ∨ p2=p3 ∨ p2=p4 ∨ p3=p4) To say that there are infinitely many points and lines, add an infinite list of axioms

  • (∃x1)(∃x2)(x1=x2)
  • (∃x1)(∃x2)(∃x3)(x1=x2 ∨ x1=x3 ∨ x2=x3)
  • etc.
  • G. Eric Moorhouse

Semifinite Generalized Quadrangles

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SLIDE 14

Model Theory as a Convenient Crutch

Proofs by model-theoretic methods are sometimes shorter or more natural than alternative proofs obtained by other means. Concern may be expressed over the liberal use of the axiom of choice (AC) in model theory. But often, proofs obtained by these methods can be rewritten so as to obtain more ‘constructive’ proofs not requiring AC. The model-theoretic language often serves as a convenience rather than as a necessity. Its use is similar to proofs in discrete mathematics that appeal to R or to C, where typically a finite extension of Q suffices.

  • G. Eric Moorhouse

Semifinite Generalized Quadrangles

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SLIDE 15

Model Theory as a Convenient Crutch

Proofs by model-theoretic methods are sometimes shorter or more natural than alternative proofs obtained by other means. Concern may be expressed over the liberal use of the axiom of choice (AC) in model theory. But often, proofs obtained by these methods can be rewritten so as to obtain more ‘constructive’ proofs not requiring AC. The model-theoretic language often serves as a convenience rather than as a necessity. Its use is similar to proofs in discrete mathematics that appeal to R or to C, where typically a finite extension of Q suffices.

  • G. Eric Moorhouse

Semifinite Generalized Quadrangles

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SLIDE 16

Model Theory as a Convenient Crutch

Proofs by model-theoretic methods are sometimes shorter or more natural than alternative proofs obtained by other means. Concern may be expressed over the liberal use of the axiom of choice (AC) in model theory. But often, proofs obtained by these methods can be rewritten so as to obtain more ‘constructive’ proofs not requiring AC. The model-theoretic language often serves as a convenience rather than as a necessity. Its use is similar to proofs in discrete mathematics that appeal to R or to C, where typically a finite extension of Q suffices.

  • G. Eric Moorhouse

Semifinite Generalized Quadrangles

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SLIDE 17

Order Indiscernibles

Let T be a theory (say, a set of axioms) having a model M with underlying set M. (We write M T.) An indexed family of distinct elements mj ∈ M (for j ∈ Q) consists of order indiscernibles if for every propositional formula φ(x1, . . . , xr), and every pair of increasing sequences j1<j2< · · · <jr, k1<k2< · · · <kr in Q, we have φ(mj1, mj2, . . . , mjr ) holds in M iff φ(mk1, mk2, . . . , mkr ) holds in M, i.e. M

  • φ(mj1, mj2, . . . , mjr ) ↔ φ(mk1, mk2, . . . , mkr )
  • .

For example, in C, any countably infinite algebraically independent subset consists of order indiscernibles (but in this case an arbitrary ordering can be used).

  • G. Eric Moorhouse

Semifinite Generalized Quadrangles

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SLIDE 18

Order Indiscernibles

Let T be a theory (say, a set of axioms) having a model M with underlying set M. (We write M T.) An indexed family of distinct elements mj ∈ M (for j ∈ Q) consists of order indiscernibles if for every propositional formula φ(x1, . . . , xr), and every pair of increasing sequences j1<j2< · · · <jr, k1<k2< · · · <kr in Q, we have φ(mj1, mj2, . . . , mjr ) holds in M iff φ(mk1, mk2, . . . , mkr ) holds in M, i.e. M

  • φ(mj1, mj2, . . . , mjr ) ↔ φ(mk1, mk2, . . . , mkr )
  • .

For example, in C, any countably infinite algebraically independent subset consists of order indiscernibles (but in this case an arbitrary ordering can be used).

  • G. Eric Moorhouse

Semifinite Generalized Quadrangles

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SLIDE 19

Order Indiscernibles

Let T be a theory (say, a set of axioms) having a model M with underlying set M. (We write M T.) An indexed family of distinct elements mj ∈ M (for j ∈ Q) consists of order indiscernibles if for every propositional formula φ(x1, . . . , xr), and every pair of increasing sequences j1<j2< · · · <jr, k1<k2< · · · <kr in Q, we have φ(mj1, mj2, . . . , mjr ) holds in M iff φ(mk1, mk2, . . . , mkr ) holds in M, i.e. M

  • φ(mj1, mj2, . . . , mjr ) ↔ φ(mk1, mk2, . . . , mkr )
  • .

For example, in C, any countably infinite algebraically independent subset consists of order indiscernibles (but in this case an arbitrary ordering can be used).

  • G. Eric Moorhouse

Semifinite Generalized Quadrangles

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SLIDE 20

Another Example of Order Indiscernibles

A more enlightening example is the theory of dense linear

  • rders without endpoints. This has a single binary predicate

R(x, y) written as x<y, with axioms

1

(∀x)(∀y)(∀z)

  • (x<y ∧ y<z) → x<z
  • 2

(∀x)(∀y)(x=y ∨ x<y ∨ y<x)

3

(∀x)(∀y)

  • x<y → ¬(x=y ∨ y<x)
  • 4

(∀x)(∀z)

  • x<z → (∃y)(x<y ∧ y<z)
  • 5

(∀x)(∃y)(x<y)

6

(∀x)(∃y)(y<x) For examples, (R, <) and (Q, <) are models. In both cases, Q is a set of order indiscernibles.

  • G. Eric Moorhouse

Semifinite Generalized Quadrangles

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SLIDE 21

Another Example of Order Indiscernibles

A more enlightening example is the theory of dense linear

  • rders without endpoints. This has a single binary predicate

R(x, y) written as x<y, with axioms

1

(∀x)(∀y)(∀z)

  • (x<y ∧ y<z) → x<z
  • 2

(∀x)(∀y)(x=y ∨ x<y ∨ y<x)

3

(∀x)(∀y)

  • x<y → ¬(x=y ∨ y<x)
  • 4

(∀x)(∀z)

  • x<z → (∃y)(x<y ∧ y<z)
  • 5

(∀x)(∃y)(x<y)

6

(∀x)(∃y)(y<x) For examples, (R, <) and (Q, <) are models. In both cases, Q is a set of order indiscernibles.

  • G. Eric Moorhouse

Semifinite Generalized Quadrangles

slide-22
SLIDE 22

Another Example of Order Indiscernibles

A more enlightening example is the theory of dense linear

  • rders without endpoints. This has a single binary predicate

R(x, y) written as x<y, with axioms

1

(∀x)(∀y)(∀z)

  • (x<y ∧ y<z) → x<z
  • 2

(∀x)(∀y)(x=y ∨ x<y ∨ y<x)

3

(∀x)(∀y)

  • x<y → ¬(x=y ∨ y<x)
  • 4

(∀x)(∀z)

  • x<z → (∃y)(x<y ∧ y<z)
  • 5

(∀x)(∃y)(x<y)

6

(∀x)(∃y)(y<x) For examples, (R, <) and (Q, <) are models. In both cases, Q is a set of order indiscernibles.

  • G. Eric Moorhouse

Semifinite Generalized Quadrangles

slide-23
SLIDE 23

Another Example of Order Indiscernibles

A more enlightening example is the theory of dense linear

  • rders without endpoints. This has a single binary predicate

R(x, y) written as x<y, with axioms

1

(∀x)(∀y)(∀z)

  • (x<y ∧ y<z) → x<z
  • 2

(∀x)(∀y)(x=y ∨ x<y ∨ y<x)

3

(∀x)(∀y)

  • x<y → ¬(x=y ∨ y<x)
  • 4

(∀x)(∀z)

  • x<z → (∃y)(x<y ∧ y<z)
  • 5

(∀x)(∃y)(x<y)

6

(∀x)(∃y)(y<x) For examples, (R, <) and (Q, <) are models. In both cases, Q is a set of order indiscernibles.

  • G. Eric Moorhouse

Semifinite Generalized Quadrangles

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SLIDE 24

Order Indiscernibles and Group Actions

Let Aut(Q, <) be the group of all order-preserving permutations (a highly homogeneous permutation group—transitive on subsets of size n for each n 1). This group accounts for the fact that the entire set Q consists of

  • rder indiscernibles in (Q, <).

More generally: Given an indexed family of distinct elements S = {mj : j ∈ Q} ⊆ M, the group Aut(Q, <) permutes S naturally (acting on subscripts). If every g ∈ Aut(Q, <) extends to an automorphism of M, then S consists of order indiscernibles. The converse fails; there exist sets of order indiscernibles in structures with no automorphisms. However, it is usually possible to pretend that sets of order indiscernibles are subsets S ⊆ M with (Aut M)S ∼ = Aut(Q, <) acting naturally on subscripts.

  • G. Eric Moorhouse

Semifinite Generalized Quadrangles

slide-25
SLIDE 25

Order Indiscernibles and Group Actions

Let Aut(Q, <) be the group of all order-preserving permutations (a highly homogeneous permutation group—transitive on subsets of size n for each n 1). This group accounts for the fact that the entire set Q consists of

  • rder indiscernibles in (Q, <).

More generally: Given an indexed family of distinct elements S = {mj : j ∈ Q} ⊆ M, the group Aut(Q, <) permutes S naturally (acting on subscripts). If every g ∈ Aut(Q, <) extends to an automorphism of M, then S consists of order indiscernibles. The converse fails; there exist sets of order indiscernibles in structures with no automorphisms. However, it is usually possible to pretend that sets of order indiscernibles are subsets S ⊆ M with (Aut M)S ∼ = Aut(Q, <) acting naturally on subscripts.

  • G. Eric Moorhouse

Semifinite Generalized Quadrangles

slide-26
SLIDE 26

Order Indiscernibles and Group Actions

Let Aut(Q, <) be the group of all order-preserving permutations (a highly homogeneous permutation group—transitive on subsets of size n for each n 1). This group accounts for the fact that the entire set Q consists of

  • rder indiscernibles in (Q, <).

More generally: Given an indexed family of distinct elements S = {mj : j ∈ Q} ⊆ M, the group Aut(Q, <) permutes S naturally (acting on subscripts). If every g ∈ Aut(Q, <) extends to an automorphism of M, then S consists of order indiscernibles. The converse fails; there exist sets of order indiscernibles in structures with no automorphisms. However, it is usually possible to pretend that sets of order indiscernibles are subsets S ⊆ M with (Aut M)S ∼ = Aut(Q, <) acting naturally on subscripts.

  • G. Eric Moorhouse

Semifinite Generalized Quadrangles

slide-27
SLIDE 27

Order Indiscernibles and Group Actions

Let Aut(Q, <) be the group of all order-preserving permutations (a highly homogeneous permutation group—transitive on subsets of size n for each n 1). This group accounts for the fact that the entire set Q consists of

  • rder indiscernibles in (Q, <).

More generally: Given an indexed family of distinct elements S = {mj : j ∈ Q} ⊆ M, the group Aut(Q, <) permutes S naturally (acting on subscripts). If every g ∈ Aut(Q, <) extends to an automorphism of M, then S consists of order indiscernibles. The converse fails; there exist sets of order indiscernibles in structures with no automorphisms. However, it is usually possible to pretend that sets of order indiscernibles are subsets S ⊆ M with (Aut M)S ∼ = Aut(Q, <) acting naturally on subscripts.

  • G. Eric Moorhouse

Semifinite Generalized Quadrangles

slide-28
SLIDE 28

Order Indiscernibles and Group Actions

Let Aut(Q, <) be the group of all order-preserving permutations (a highly homogeneous permutation group—transitive on subsets of size n for each n 1). This group accounts for the fact that the entire set Q consists of

  • rder indiscernibles in (Q, <).

More generally: Given an indexed family of distinct elements S = {mj : j ∈ Q} ⊆ M, the group Aut(Q, <) permutes S naturally (acting on subscripts). If every g ∈ Aut(Q, <) extends to an automorphism of M, then S consists of order indiscernibles. The converse fails; there exist sets of order indiscernibles in structures with no automorphisms. However, it is usually possible to pretend that sets of order indiscernibles are subsets S ⊆ M with (Aut M)S ∼ = Aut(Q, <) acting naturally on subscripts.

  • G. Eric Moorhouse

Semifinite Generalized Quadrangles

slide-29
SLIDE 29

Existence of Order Indiscernibles

Theorem If a theory T has some infinite model, then T has a model containing a set of order indiscernibles. For example, if there exists a semifinite GQ, then there exists a semifinite GQ containing a set of order indiscernibles. This set must consist of (i) a partial spread (i.e. set of mutually disjoint lines), or (ii) a set of lines through a single point, or (iii) a cap (i.e. a set of points, no two on the same line). We may assume that case (i) occurs: a partial spread of order indiscernible lines.

  • G. Eric Moorhouse

Semifinite Generalized Quadrangles

slide-30
SLIDE 30

Existence of Order Indiscernibles

Theorem If a theory T has some infinite model, then T has a model containing a set of order indiscernibles. For example, if there exists a semifinite GQ, then there exists a semifinite GQ containing a set of order indiscernibles. This set must consist of (i) a partial spread (i.e. set of mutually disjoint lines), or (ii) a set of lines through a single point, or (iii) a cap (i.e. a set of points, no two on the same line). We may assume that case (i) occurs: a partial spread of order indiscernible lines.

  • G. Eric Moorhouse

Semifinite Generalized Quadrangles

slide-31
SLIDE 31

Existence of Order Indiscernibles

Theorem If a theory T has some infinite model, then T has a model containing a set of order indiscernibles. For example, if there exists a semifinite GQ, then there exists a semifinite GQ containing a set of order indiscernibles. This set must consist of (i) a partial spread (i.e. set of mutually disjoint lines), or (ii) a set of lines through a single point, or (iii) a cap (i.e. a set of points, no two on the same line). We may assume that case (i) occurs: a partial spread of order indiscernible lines.

  • G. Eric Moorhouse

Semifinite Generalized Quadrangles

slide-32
SLIDE 32

Partial Spread of Order Indiscernible Lines

Henceforth let Q be a semifinite GQ with k per line, and let {ℓa : a ∈ Q} be a partial spread consisting of order indiscernible

  • lines. Every pair of lines ℓa, ℓb (a<b) has exactly k transversals.

But: Lemma No three lines of our partial spread have a common transversal. Proof: Suppose ℓa, ℓb, ℓc have a common transversal where a<b<c. By indiscernibility, ℓa, ℓb, ℓd have a common transversal whenever a<b<d. However, there are only k common transversals to ℓa and ℓb, each with only k points, a contradiction.

  • G. Eric Moorhouse

Semifinite Generalized Quadrangles

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SLIDE 33

Partial Spread of Order Indiscernible Lines

Henceforth let Q be a semifinite GQ with k per line, and let {ℓa : a ∈ Q} be a partial spread consisting of order indiscernible

  • lines. Every pair of lines ℓa, ℓb (a<b) has exactly k transversals.

But: Lemma No three lines of our partial spread have a common transversal. Proof: Suppose ℓa, ℓb, ℓc have a common transversal where a<b<c. By indiscernibility, ℓa, ℓb, ℓd have a common transversal whenever a<b<d. However, there are only k common transversals to ℓa and ℓb, each with only k points, a contradiction.

  • G. Eric Moorhouse

Semifinite Generalized Quadrangles

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SLIDE 34

Partial Spread of Order Indiscernible Lines

Henceforth let Q be a semifinite GQ with k per line, and let {ℓa : a ∈ Q} be a partial spread consisting of order indiscernible

  • lines. Every pair of lines ℓa, ℓb (a<b) has exactly k transversals.

But: Lemma No three lines of our partial spread have a common transversal. Proof: Suppose ℓa, ℓb, ℓc have a common transversal where a<b<c. By indiscernibility, ℓa, ℓb, ℓd have a common transversal whenever a<b<d. However, there are only k common transversals to ℓa and ℓb, each with only k points, a contradiction.

  • G. Eric Moorhouse

Semifinite Generalized Quadrangles

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SLIDE 35

Partial Spread of Order Indiscernible Lines

Label the points of ℓ0 as 1, 2, . . . , k. Using transversals, this induces a labeling of the points of each line ℓ disjoint from ℓ0: Whenever ℓ0, ℓ, m are mutually disjoint lines, transversals induce a permutation σ = σ(ℓ, m) ∈ Sk: Lemma The number of fixed points of σ(ℓ, m) ∈ Sk equals the number

  • f common transversals of ℓ0, ℓ, m.
  • G. Eric Moorhouse

Semifinite Generalized Quadrangles

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SLIDE 36

Partial Spread of Order Indiscernible Lines

Label the points of ℓ0 as 1, 2, . . . , k. Using transversals, this induces a labeling of the points of each line ℓ disjoint from ℓ0: Whenever ℓ0, ℓ, m are mutually disjoint lines, transversals induce a permutation σ = σ(ℓ, m) ∈ Sk: Lemma The number of fixed points of σ(ℓ, m) ∈ Sk equals the number

  • f common transversals of ℓ0, ℓ, m.
  • G. Eric Moorhouse

Semifinite Generalized Quadrangles

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SLIDE 37

Partial Spread of Order Indiscernible Lines

Label the points of ℓ0 as 1, 2, . . . , k. Using transversals, this induces a labeling of the points of each line ℓ disjoint from ℓ0: Whenever ℓ0, ℓ, m are mutually disjoint lines, transversals induce a permutation σ = σ(ℓ, m) ∈ Sk: Lemma The number of fixed points of σ(ℓ, m) ∈ Sk equals the number

  • f common transversals of ℓ0, ℓ, m.
  • G. Eric Moorhouse

Semifinite Generalized Quadrangles

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SLIDE 38

Partial Spread of Order Indiscernible Lines

A similar argument shows Lemma Suppose ℓ0, ℓ, m, n are mutually disjoint lines. Then the number

  • f fixed points of σ(ℓ, m)σ(m, n)σ(n, ℓ) ∈ Sk equals the number
  • f common transversals of ℓ, m, n.
  • G. Eric Moorhouse

Semifinite Generalized Quadrangles

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SLIDE 39

Partial Spread of Order Indiscernible Lines

Since ℓ0, ℓ1, ℓ2 have no common transversals, the permutation σ = σ(ℓ1, ℓ2) is fixed-point-free. Moreover by indiscernibility, σ(ℓa, ℓb) = σ whenever 0<a<b. Lemma Without loss of generality, σ = (12) σ where σ is a fixed-point-free permutation of 3, 4, . . . , k. Proof: WLOG 1σ = 2. Now {ma : a ∈ Q ∩ (0, 1)} is a partial spread of order indiscernible lines with σ(ma, mb) = (12)( · · · ) whenever 0<a<b<1.

  • G. Eric Moorhouse

Semifinite Generalized Quadrangles

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SLIDE 40

Partial Spread of Order Indiscernible Lines

Since ℓ0, ℓ1, ℓ2 have no common transversals, the permutation σ = σ(ℓ1, ℓ2) is fixed-point-free. Moreover by indiscernibility, σ(ℓa, ℓb) = σ whenever 0<a<b. Lemma Without loss of generality, σ = (12) σ where σ is a fixed-point-free permutation of 3, 4, . . . , k. Proof: WLOG 1σ = 2. Now {ma : a ∈ Q ∩ (0, 1)} is a partial spread of order indiscernible lines with σ(ma, mb) = (12)( · · · ) whenever 0<a<b<1.

  • G. Eric Moorhouse

Semifinite Generalized Quadrangles

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SLIDE 41

Partial Spread of Order Indiscernible Lines

Since ℓ0, ℓ1, ℓ2 have no common transversals, the permutation σ = σ(ℓ1, ℓ2) is fixed-point-free. Moreover by indiscernibility, σ(ℓa, ℓb) = σ whenever 0<a<b. Lemma Without loss of generality, σ = (12) σ where σ is a fixed-point-free permutation of 3, 4, . . . , k. Proof: WLOG 1σ = 2. Now {ma : a ∈ Q ∩ (0, 1)} is a partial spread of order indiscernible lines with σ(ma, mb) = (12)( · · · ) whenever 0<a<b<1.

  • G. Eric Moorhouse

Semifinite Generalized Quadrangles

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SLIDE 42

Partial Spread of Order Indiscernible Lines

Since ℓ0, ℓ1, ℓ2 have no common transversals, the permutation σ = σ(ℓ1, ℓ2) is fixed-point-free. Moreover by indiscernibility, σ(ℓa, ℓb) = σ whenever 0<a<b. Lemma Without loss of generality, σ = (12) σ where σ is a fixed-point-free permutation of 3, 4, . . . , k. Corollary Semifinite GQ’s of line size k =3 do not exist. Next suppose k = 4. . .

  • G. Eric Moorhouse

Semifinite Generalized Quadrangles

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SLIDE 43

Partial Spread of Order Indiscernible Lines

Since ℓ0, ℓ1, ℓ2 have no common transversals, the permutation σ = σ(ℓ1, ℓ2) is fixed-point-free. Moreover by indiscernibility, σ(ℓa, ℓb) = σ whenever 0<a<b. Lemma Without loss of generality, σ = (12) σ where σ is a fixed-point-free permutation of 3, 4, . . . , k. Corollary Semifinite GQ’s of line size k =3 do not exist. Next suppose k = 4. . .

  • G. Eric Moorhouse

Semifinite Generalized Quadrangles

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SLIDE 44

Semifinite GQ’s of line size k=4 do not exist

Suppose k = 4. WLOG σ = (12)(34). σ(ℓ, m) = (1234) σ(m, n) = (1342) σ(n, ℓ) = (12)(34) So σ(ℓ, m)σ(m, n)σ(n, ℓ) = (123), which has one fixed point. Thus ℓ, m, n have a common transversal. This cannot happen, so Corollary Semifinite GQ’s of line size k=4 do not exist.

  • G. Eric Moorhouse

Semifinite Generalized Quadrangles

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SLIDE 45

Semifinite GQ’s of line size k=4 do not exist

Suppose k = 4. WLOG σ = (12)(34). σ(ℓ, m) = (1234) σ(m, n) = (1342) σ(n, ℓ) = (12)(34) So σ(ℓ, m)σ(m, n)σ(n, ℓ) = (123), which has one fixed point. Thus ℓ, m, n have a common transversal. This cannot happen, so Corollary Semifinite GQ’s of line size k=4 do not exist.

  • G. Eric Moorhouse

Semifinite Generalized Quadrangles

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SLIDE 46

Semifinite GQ’s of line size k=4 do not exist

Suppose k = 4. WLOG σ = (12)(34). σ(ℓ, m) = (1234) σ(m, n) = (1342) σ(n, ℓ) = (12)(34) So σ(ℓ, m)σ(m, n)σ(n, ℓ) = (123), which has one fixed point. Thus ℓ, m, n have a common transversal. This cannot happen, so Corollary Semifinite GQ’s of line size k=4 do not exist.

  • G. Eric Moorhouse

Semifinite Generalized Quadrangles

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SLIDE 47

GQ’s and Model Theory

Cherlin applied techniques of model theory to the study of GQ’s.

Model Theory GQ’s

However, the study of GQ’s is also applied to model theory. GQ’s arise in the investigation of the Cherlin-Zil’ber Conjecture,

  • ne of the leading open problems in model theory.
  • G. Eric Moorhouse

Semifinite Generalized Quadrangles

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SLIDE 48

General References

P . J. Cameron

  • D. Marker
  • Y. I. Manin
  • G. Eric Moorhouse

Semifinite Generalized Quadrangles

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SLIDE 49