SatoTate groups of abelian threefolds Francesc Fit e (IAS), Kiran - - PowerPoint PPT Presentation

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SatoTate groups of abelian threefolds Francesc Fit e (IAS), Kiran - - PowerPoint PPT Presentation

SatoTate groups of abelian threefolds Francesc Fit e (IAS), Kiran S. Kedlaya (UCSD), A.V. Sutherland (MIT) Arithmetic of low-dimensional abelian varieties. ICERM, 5th June 2019. Fit e, Kedlaya, Sutherland 1 / 22 SatoTate groups of


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Sato–Tate groups of abelian threefolds

Francesc Fit´ e (IAS), Kiran S. Kedlaya (UCSD), A.V. Sutherland (MIT)

Arithmetic of low-dimensional abelian varieties. ICERM, 5th June 2019.

Fit´ e, Kedlaya, Sutherland 1 / 22

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Sato–Tate groups of elliptic curves

k a number field. E/k an elliptic curve. The Sato–Tate group ST(E) is defined as:

◮ SU(2) if E does not have CM. ◮ U(1) =

u u

  • : u ∈ C, |u| = 1
  • if E has CM by M ⊆ k.

◮ NSU(2)(U(1)) if E has CM by M ⊆ k.

Note that Tr: ST(E) → [−2, 2]. Denote µ = Tr∗(µHaar).

SU(2) U(1) N(U(1))

Fit´ e, Kedlaya, Sutherland 2 / 22

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The Sato–Tate conjecture for elliptic curves

Let p be a prime of good reduction for E. The normalized Frobenius trace satisfies ap = N(p) + 1 − #E(Fp)

  • N(p)

= Tr(Frobp |Vℓ(E))

  • N(p)

∈ [−2, 2] (for p ∤ ℓ)

Sato–Tate conjecture

The sequence {ap}p is equidistributed on [−2, 2] w.r.t µ. If ST(E) = U(1) or N(U(1)): Known in full generality (Hecke, Deuring). Known if ST(E) = SU(2) and k is totally real. (Barnet-Lamb, Geraghty, Harris, Shepherd-Barron, Taylor); Known if ST(E) = SU(2) and k is a CM field

(Allen,Calegary,Caraiani,Gee,Helm,LeHung,Newton,Scholze,Taylor,Thorne).

Fit´ e, Kedlaya, Sutherland 3 / 22

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The Sato–Tate conjecture for elliptic curves

Let p be a prime of good reduction for E. The normalized Frobenius trace satisfies ap = N(p) + 1 − #E(Fp)

  • N(p)

= Tr(Frobp |Vℓ(E))

  • N(p)

∈ [−2, 2] (for p ∤ ℓ)

Sato–Tate conjecture

The sequence {ap}p is equidistributed on [−2, 2] w.r.t µ. If ST(E) = U(1) or N(U(1)): Known in full generality (Hecke, Deuring). Known if ST(E) = SU(2) and k is totally real. (Barnet-Lamb, Geraghty, Harris, Shepherd-Barron, Taylor); Known if ST(E) = SU(2) and k is a CM field

(Allen,Calegary,Caraiani,Gee,Helm,LeHung,Newton,Scholze,Taylor,Thorne).

Fit´ e, Kedlaya, Sutherland 3 / 22

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The Sato–Tate conjecture for elliptic curves

Let p be a prime of good reduction for E. The normalized Frobenius trace satisfies ap = N(p) + 1 − #E(Fp)

  • N(p)

= Tr(Frobp |Vℓ(E))

  • N(p)

∈ [−2, 2] (for p ∤ ℓ)

Sato–Tate conjecture

The sequence {ap}p is equidistributed on [−2, 2] w.r.t µ. If ST(E) = U(1) or N(U(1)): Known in full generality (Hecke, Deuring). Known if ST(E) = SU(2) and k is totally real. (Barnet-Lamb, Geraghty, Harris, Shepherd-Barron, Taylor); Known if ST(E) = SU(2) and k is a CM field

(Allen,Calegary,Caraiani,Gee,Helm,LeHung,Newton,Scholze,Taylor,Thorne).

Fit´ e, Kedlaya, Sutherland 3 / 22

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Toward the Sato–Tate group: the ℓ-adic image

Let A/k be an abelian variety of dimension g ≥ 1. Consider the ℓ-adic representation attached to A ̺A,ℓ : Gk → Autψℓ(Vℓ(A)) ≃ GSp2g(Qℓ) . Serre defines ST(A) in terms of Gℓ = ̺A,ℓ(Gk)Zar. For g ≤ 3, Banaszak and Kedlaya describe ST(A) in terms of endomorphisms. By Faltings, there is a Gk-equivariant isomorphism End(AQ) ⊗ Qℓ ≃ EndG0

ℓ(Q2g

ℓ ) .

Therefore G0

ℓ ֒

→ {γ ∈ GSp2g(Qℓ) | γαγ−1 = α for all α ∈ End(AQ)} .

Fit´ e, Kedlaya, Sutherland 4 / 22

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Toward the Sato–Tate group: the ℓ-adic image

Let A/k be an abelian variety of dimension g ≥ 1. Consider the ℓ-adic representation attached to A ̺A,ℓ : Gk → Autψℓ(Vℓ(A)) ≃ GSp2g(Qℓ) . Serre defines ST(A) in terms of Gℓ = ̺A,ℓ(Gk)Zar. For g ≤ 3, Banaszak and Kedlaya describe ST(A) in terms of endomorphisms. By Faltings, there is a Gk-equivariant isomorphism End(AQ) ⊗ Qℓ ≃ EndG0

ℓ(Q2g

ℓ ) .

Therefore G0

ℓ ֒

→ {γ ∈ GSp2g(Qℓ) | γαγ−1 = α for all α ∈ End(AQ)} .

Fit´ e, Kedlaya, Sutherland 4 / 22

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SLIDE 8

Toward the Sato–Tate group: the ℓ-adic image

Let A/k be an abelian variety of dimension g ≥ 1. Consider the ℓ-adic representation attached to A ̺A,ℓ : Gk → Autψℓ(Vℓ(A)) ≃ GSp2g(Qℓ) . Serre defines ST(A) in terms of Gℓ = ̺A,ℓ(Gk)Zar. For g ≤ 3, Banaszak and Kedlaya describe ST(A) in terms of endomorphisms. By Faltings, there is a Gk-equivariant isomorphism End(AQ) ⊗ Qℓ ≃ EndG0

ℓ(Q2g

ℓ ) .

Therefore G0

ℓ ֒

→ {γ ∈ GSp2g(Qℓ) | γαγ−1 = α for all α ∈ End(AQ)} .

Fit´ e, Kedlaya, Sutherland 4 / 22

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Toward the Sato–Tate group: the ℓ-adic image

Let A/k be an abelian variety of dimension g ≥ 1. Consider the ℓ-adic representation attached to A ̺A,ℓ : Gk → Autψℓ(Vℓ(A)) ≃ GSp2g(Qℓ) . Serre defines ST(A) in terms of Gℓ = ̺A,ℓ(Gk)Zar. For g ≤ 3, Banaszak and Kedlaya describe ST(A) in terms of endomorphisms. By Faltings, there is a Gk-equivariant isomorphism End(AQ) ⊗ Qℓ ≃ EndG0

ℓ(Q2g

ℓ ) .

Therefore G0

ℓ ֒

→ {γ ∈ GSp2g(Qℓ) | γαγ−1 = α for all α ∈ End(AQ)} .

Fit´ e, Kedlaya, Sutherland 4 / 22

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Toward the Sato–Tate group: the ℓ-adic image

Let A/k be an abelian variety of dimension g ≥ 1. Consider the ℓ-adic representation attached to A ̺A,ℓ : Gk → Autψℓ(Vℓ(A)) ≃ GSp2g(Qℓ) . Serre defines ST(A) in terms of Gℓ = ̺A,ℓ(Gk)Zar. For g ≤ 3, Banaszak and Kedlaya describe ST(A) in terms of endomorphisms. By Faltings, there is a Gk-equivariant isomorphism End(AQ) ⊗ Qℓ ≃ EndG0

ℓ(Q2g

ℓ ) .

Therefore G0

ℓ ֒

→ {γ ∈ GSp2g(Qℓ) | γαγ−1 = α for all α ∈ End(AQ)} .

Fit´ e, Kedlaya, Sutherland 4 / 22

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The twisted Lefschetz group

More accurately Gℓ ֒ →

  • σ∈Gk

{γ ∈ GSp2g(Qℓ) | γαγ−1 = σ(α) for all α ∈ End(AQ)} . For g = 4, Mumford has constructed A/k such that End(AQ) ≃ Z and Gℓ GSp2g(Qℓ) . For g ≤ 3, one has Gℓ ≃

  • σ∈Gk

{γ ∈ GSp2g(Qℓ) | γαγ−1 = σ(α) for all α ∈ End(AQ)} .

Definition

The Twisted Lefschetz group is defined as TL(A) =

  • σ∈Gk

{γ ∈ Sp2g /Q|γαγ−1 = σ(α) for all α ∈ End(AF)}.

Fit´ e, Kedlaya, Sutherland 5 / 22

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The twisted Lefschetz group

More accurately Gℓ ֒ →

  • σ∈Gk

{γ ∈ GSp2g(Qℓ) | γαγ−1 = σ(α) for all α ∈ End(AQ)} . For g = 4, Mumford has constructed A/k such that End(AQ) ≃ Z and Gℓ GSp2g(Qℓ) . For g ≤ 3, one has Gℓ ≃

  • σ∈Gk

{γ ∈ GSp2g(Qℓ) | γαγ−1 = σ(α) for all α ∈ End(AQ)} .

Definition

The Twisted Lefschetz group is defined as TL(A) =

  • σ∈Gk

{γ ∈ Sp2g /Q|γαγ−1 = σ(α) for all α ∈ End(AF)}.

Fit´ e, Kedlaya, Sutherland 5 / 22

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The twisted Lefschetz group

More accurately Gℓ ֒ →

  • σ∈Gk

{γ ∈ GSp2g(Qℓ) | γαγ−1 = σ(α) for all α ∈ End(AQ)} . For g = 4, Mumford has constructed A/k such that End(AQ) ≃ Z and Gℓ GSp2g(Qℓ) . For g ≤ 3, one has Gℓ ≃

  • σ∈Gk

{γ ∈ GSp2g(Qℓ) | γαγ−1 = σ(α) for all α ∈ End(AQ)} .

Definition

The Twisted Lefschetz group is defined as TL(A) =

  • σ∈Gk

{γ ∈ Sp2g /Q|γαγ−1 = σ(α) for all α ∈ End(AF)}.

Fit´ e, Kedlaya, Sutherland 5 / 22

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SLIDE 14

The twisted Lefschetz group

More accurately Gℓ ֒ →

  • σ∈Gk

{γ ∈ GSp2g(Qℓ) | γαγ−1 = σ(α) for all α ∈ End(AQ)} . For g = 4, Mumford has constructed A/k such that End(AQ) ≃ Z and Gℓ GSp2g(Qℓ) . For g ≤ 3, one has Gℓ ≃

  • σ∈Gk

{γ ∈ GSp2g(Qℓ) | γαγ−1 = σ(α) for all α ∈ End(AQ)} .

Definition

The Twisted Lefschetz group is defined as TL(A) =

  • σ∈Gk

{γ ∈ Sp2g /Q|γαγ−1 = σ(α) for all α ∈ End(AF)}.

Fit´ e, Kedlaya, Sutherland 5 / 22

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The Sato–Tate group when g ≤ 3

From now on, assume g ≤ 3.

Definition

ST(A) ⊆ USp(2g) is a maximal compact subgroup of TL(A) ⊗Q C. Note that ST(A)/ ST(A)0 ≃ TL(A)/ TL(A)0 ≃ Gal(F/k) . where F/k is the minimal extension such that End(AF) ≃ End(AQ). We call F the endomorphism field of A. To each prime p of good reduction for A, one can attach a conjugacy class xp ∈ X = Conj(ST(A)) s.t. Char(xp) = Char ̺A,ℓ(Frobp)

√Np

  • .

Sato–Tate conjecture for abelian varieties

The sequence {xp}p is equidistributed on X w.r.t the push forward of the Haar measure of ST(A).

Fit´ e, Kedlaya, Sutherland 6 / 22

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The Sato–Tate group when g ≤ 3

From now on, assume g ≤ 3.

Definition

ST(A) ⊆ USp(2g) is a maximal compact subgroup of TL(A) ⊗Q C. Note that ST(A)/ ST(A)0 ≃ TL(A)/ TL(A)0 ≃ Gal(F/k) . where F/k is the minimal extension such that End(AF) ≃ End(AQ). We call F the endomorphism field of A. To each prime p of good reduction for A, one can attach a conjugacy class xp ∈ X = Conj(ST(A)) s.t. Char(xp) = Char ̺A,ℓ(Frobp)

√Np

  • .

Sato–Tate conjecture for abelian varieties

The sequence {xp}p is equidistributed on X w.r.t the push forward of the Haar measure of ST(A).

Fit´ e, Kedlaya, Sutherland 6 / 22

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SLIDE 17

The Sato–Tate group when g ≤ 3

From now on, assume g ≤ 3.

Definition

ST(A) ⊆ USp(2g) is a maximal compact subgroup of TL(A) ⊗Q C. Note that ST(A)/ ST(A)0 ≃ TL(A)/ TL(A)0 ≃ Gal(F/k) . where F/k is the minimal extension such that End(AF) ≃ End(AQ). We call F the endomorphism field of A. To each prime p of good reduction for A, one can attach a conjugacy class xp ∈ X = Conj(ST(A)) s.t. Char(xp) = Char ̺A,ℓ(Frobp)

√Np

  • .

Sato–Tate conjecture for abelian varieties

The sequence {xp}p is equidistributed on X w.r.t the push forward of the Haar measure of ST(A).

Fit´ e, Kedlaya, Sutherland 6 / 22

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The Sato–Tate group when g ≤ 3

From now on, assume g ≤ 3.

Definition

ST(A) ⊆ USp(2g) is a maximal compact subgroup of TL(A) ⊗Q C. Note that ST(A)/ ST(A)0 ≃ TL(A)/ TL(A)0 ≃ Gal(F/k) . where F/k is the minimal extension such that End(AF) ≃ End(AQ). We call F the endomorphism field of A. To each prime p of good reduction for A, one can attach a conjugacy class xp ∈ X = Conj(ST(A)) s.t. Char(xp) = Char ̺A,ℓ(Frobp)

√Np

  • .

Sato–Tate conjecture for abelian varieties

The sequence {xp}p is equidistributed on X w.r.t the push forward of the Haar measure of ST(A).

Fit´ e, Kedlaya, Sutherland 6 / 22

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SLIDE 19

The Sato–Tate group when g ≤ 3

From now on, assume g ≤ 3.

Definition

ST(A) ⊆ USp(2g) is a maximal compact subgroup of TL(A) ⊗Q C. Note that ST(A)/ ST(A)0 ≃ TL(A)/ TL(A)0 ≃ Gal(F/k) . where F/k is the minimal extension such that End(AF) ≃ End(AQ). We call F the endomorphism field of A. To each prime p of good reduction for A, one can attach a conjugacy class xp ∈ X = Conj(ST(A)) s.t. Char(xp) = Char ̺A,ℓ(Frobp)

√Np

  • .

Sato–Tate conjecture for abelian varieties

The sequence {xp}p is equidistributed on X w.r.t the push forward of the Haar measure of ST(A).

Fit´ e, Kedlaya, Sutherland 6 / 22

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Sato–Tate axioms for g ≤ 3

The Sato–Tate axioms for a closed subgroup G ⊆ USp(2g) for g ≤ 3 are:

Hodge condition (ST1)

There is a homomorphism θ: U(1) → G 0 such that θ(u) has eigenvalues u and u each with multiplicity g. The image of such a θ is called a Hodge

  • circle. Moreover, the Hodge circles generate a dense subgroup of G 0.

Rationality condition (ST2)

For every connected component H ⊆ G and for every irreducible character χ: GL2g(C) → C:

  • H

χ(h)µHaar ∈ Z , where µHaar is normalized so that µHaar(G 0) = 1.

Lefschetz condition (ST3)

G 0 = {γ ∈ USp(2g)|γαγ−1 = α for all α ∈ EndG 0(C2g)} .

Fit´ e, Kedlaya, Sutherland 7 / 22

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Sato–Tate axioms for g ≤ 3

The Sato–Tate axioms for a closed subgroup G ⊆ USp(2g) for g ≤ 3 are:

Hodge condition (ST1)

There is a homomorphism θ: U(1) → G 0 such that θ(u) has eigenvalues u and u each with multiplicity g. The image of such a θ is called a Hodge

  • circle. Moreover, the Hodge circles generate a dense subgroup of G 0.

Rationality condition (ST2)

For every connected component H ⊆ G and for every irreducible character χ: GL2g(C) → C:

  • H

χ(h)µHaar ∈ Z , where µHaar is normalized so that µHaar(G 0) = 1.

Lefschetz condition (ST3)

G 0 = {γ ∈ USp(2g)|γαγ−1 = α for all α ∈ EndG 0(C2g)} .

Fit´ e, Kedlaya, Sutherland 7 / 22

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SLIDE 22

Sato–Tate axioms for g ≤ 3

The Sato–Tate axioms for a closed subgroup G ⊆ USp(2g) for g ≤ 3 are:

Hodge condition (ST1)

There is a homomorphism θ: U(1) → G 0 such that θ(u) has eigenvalues u and u each with multiplicity g. The image of such a θ is called a Hodge

  • circle. Moreover, the Hodge circles generate a dense subgroup of G 0.

Rationality condition (ST2)

For every connected component H ⊆ G and for every irreducible character χ: GL2g(C) → C:

  • H

χ(h)µHaar ∈ Z , where µHaar is normalized so that µHaar(G 0) = 1.

Lefschetz condition (ST3)

G 0 = {γ ∈ USp(2g)|γαγ−1 = α for all α ∈ EndG 0(C2g)} .

Fit´ e, Kedlaya, Sutherland 7 / 22

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SLIDE 23

Sato–Tate axioms for g ≤ 3

The Sato–Tate axioms for a closed subgroup G ⊆ USp(2g) for g ≤ 3 are:

Hodge condition (ST1)

There is a homomorphism θ: U(1) → G 0 such that θ(u) has eigenvalues u and u each with multiplicity g. The image of such a θ is called a Hodge

  • circle. Moreover, the Hodge circles generate a dense subgroup of G 0.

Rationality condition (ST2)

For every connected component H ⊆ G and for every irreducible character χ: GL2g(C) → C:

  • H

χ(h)µHaar ∈ Z , where µHaar is normalized so that µHaar(G 0) = 1.

Lefschetz condition (ST3)

G 0 = {γ ∈ USp(2g)|γαγ−1 = α for all α ∈ EndG 0(C2g)} .

Fit´ e, Kedlaya, Sutherland 7 / 22

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General remarks and dimension g = 1

Proposition

If G = ST(A) for some A/k with g ≤ 3, then G satisfies the ST axioms. Mumford–Tate conjecture

  • (ST1)

“Rationality” of Gℓ

  • (ST2)

Bicommutant property of G0

  • (ST3)

Axioms (ST1), (ST2) are expected for general g. But not (ST3)!

Remark

Up to conjugacy, 3 subgroups of USp(2) satisfy the ST axioms. All 3 occur as ST groups of elliptic curves defined over number fields. Only 2 of them occur as ST groups of elliptic curves defined over totally real fields.

Fit´ e, Kedlaya, Sutherland 8 / 22

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SLIDE 25

General remarks and dimension g = 1

Proposition

If G = ST(A) for some A/k with g ≤ 3, then G satisfies the ST axioms. Mumford–Tate conjecture

  • (ST1)

“Rationality” of Gℓ

  • (ST2)

Bicommutant property of G0

  • (ST3)

Axioms (ST1), (ST2) are expected for general g. But not (ST3)!

Remark

Up to conjugacy, 3 subgroups of USp(2) satisfy the ST axioms. All 3 occur as ST groups of elliptic curves defined over number fields. Only 2 of them occur as ST groups of elliptic curves defined over totally real fields.

Fit´ e, Kedlaya, Sutherland 8 / 22

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SLIDE 26

General remarks and dimension g = 1

Proposition

If G = ST(A) for some A/k with g ≤ 3, then G satisfies the ST axioms. Mumford–Tate conjecture

  • (ST1)

“Rationality” of Gℓ

  • (ST2)

Bicommutant property of G0

  • (ST3)

Axioms (ST1), (ST2) are expected for general g. But not (ST3)!

Remark

Up to conjugacy, 3 subgroups of USp(2) satisfy the ST axioms. All 3 occur as ST groups of elliptic curves defined over number fields. Only 2 of them occur as ST groups of elliptic curves defined over totally real fields.

Fit´ e, Kedlaya, Sutherland 8 / 22

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SLIDE 27

General remarks and dimension g = 1

Proposition

If G = ST(A) for some A/k with g ≤ 3, then G satisfies the ST axioms. Mumford–Tate conjecture

  • (ST1)

“Rationality” of Gℓ

  • (ST2)

Bicommutant property of G0

  • (ST3)

Axioms (ST1), (ST2) are expected for general g. But not (ST3)!

Remark

Up to conjugacy, 3 subgroups of USp(2) satisfy the ST axioms. All 3 occur as ST groups of elliptic curves defined over number fields. Only 2 of them occur as ST groups of elliptic curves defined over totally real fields.

Fit´ e, Kedlaya, Sutherland 8 / 22

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Sato–Tate groups for g = 2

Theorem (F.-Kedlaya-Rotger-Sutherland; 2012)

Up to conjugacy, 55 subgroups of USp(4) satisfy the ST axioms. 52 of them occur as ST groups of abelian surfaces over number fields. 35 of them occur as ST groups of abelian surfaces over totally real number fields. 34 of them occur as ST groups of abelian surfaces over Q.

Above can replace “abelian surfaces” with “Jacobians of genus 2 curves”.

Corollary

The degree of the endomorphism field of an abelian surface over a number field divides 48.

Theorem (F.-Guitart; 2016)

There exists a number field (of degree 64) over which all 52 ST groups can be realized.

Fit´ e, Kedlaya, Sutherland 9 / 22

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SLIDE 29

Sato–Tate groups for g = 2

Theorem (F.-Kedlaya-Rotger-Sutherland; 2012)

Up to conjugacy, 55 subgroups of USp(4) satisfy the ST axioms. 52 of them occur as ST groups of abelian surfaces over number fields. 35 of them occur as ST groups of abelian surfaces over totally real number fields. 34 of them occur as ST groups of abelian surfaces over Q.

Above can replace “abelian surfaces” with “Jacobians of genus 2 curves”.

Corollary

The degree of the endomorphism field of an abelian surface over a number field divides 48.

Theorem (F.-Guitart; 2016)

There exists a number field (of degree 64) over which all 52 ST groups can be realized.

Fit´ e, Kedlaya, Sutherland 9 / 22

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SLIDE 30

Sato–Tate groups for g = 2

Theorem (F.-Kedlaya-Rotger-Sutherland; 2012)

Up to conjugacy, 55 subgroups of USp(4) satisfy the ST axioms. 52 of them occur as ST groups of abelian surfaces over number fields. 35 of them occur as ST groups of abelian surfaces over totally real number fields. 34 of them occur as ST groups of abelian surfaces over Q.

Above can replace “abelian surfaces” with “Jacobians of genus 2 curves”.

Corollary

The degree of the endomorphism field of an abelian surface over a number field divides 48.

Theorem (F.-Guitart; 2016)

There exists a number field (of degree 64) over which all 52 ST groups can be realized.

Fit´ e, Kedlaya, Sutherland 9 / 22

slide-31
SLIDE 31

Sato–Tate groups for g = 2

Theorem (F.-Kedlaya-Rotger-Sutherland; 2012)

Up to conjugacy, 55 subgroups of USp(4) satisfy the ST axioms. 52 of them occur as ST groups of abelian surfaces over number fields. 35 of them occur as ST groups of abelian surfaces over totally real number fields. 34 of them occur as ST groups of abelian surfaces over Q.

Above can replace “abelian surfaces” with “Jacobians of genus 2 curves”.

Corollary

The degree of the endomorphism field of an abelian surface over a number field divides 48.

Theorem (F.-Guitart; 2016)

There exists a number field (of degree 64) over which all 52 ST groups can be realized.

Fit´ e, Kedlaya, Sutherland 9 / 22

slide-32
SLIDE 32

Sato–Tate groups for g = 2

Theorem (F.-Kedlaya-Rotger-Sutherland; 2012)

Up to conjugacy, 55 subgroups of USp(4) satisfy the ST axioms. 52 of them occur as ST groups of abelian surfaces over number fields. 35 of them occur as ST groups of abelian surfaces over totally real number fields. 34 of them occur as ST groups of abelian surfaces over Q.

Above can replace “abelian surfaces” with “Jacobians of genus 2 curves”.

Corollary

The degree of the endomorphism field of an abelian surface over a number field divides 48.

Theorem (F.-Guitart; 2016)

There exists a number field (of degree 64) over which all 52 ST groups can be realized.

Fit´ e, Kedlaya, Sutherland 9 / 22

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SLIDE 33

Sato–Tate conjecture for g = 2

Theorem (Johansson, N. Taylor; 2014-19)

For g = 2 and k totally real, the ST conjecture holds for 33 of the 35 possible ST groups. The missing cases are USp(4) and N(SU(2) × SU(2)). The case N(SU(2) × SU(2)) corresponds to an abelian surface A/k, which is either:

◮ ResL

k(E), where L/k quadratic and E/L an e.c. which is not a k-curve;

  • r

◮ absolutely simple with real multiplication not defined over k.

If k = Q, the ST conjecture holds for N(SU(2) × SU(2)) (N. Taylor).

Fit´ e, Kedlaya, Sutherland 10 / 22

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SLIDE 34

Sato–Tate conjecture for g = 2

Theorem (Johansson, N. Taylor; 2014-19)

For g = 2 and k totally real, the ST conjecture holds for 33 of the 35 possible ST groups. The missing cases are USp(4) and N(SU(2) × SU(2)). The case N(SU(2) × SU(2)) corresponds to an abelian surface A/k, which is either:

◮ ResL

k(E), where L/k quadratic and E/L an e.c. which is not a k-curve;

  • r

◮ absolutely simple with real multiplication not defined over k.

If k = Q, the ST conjecture holds for N(SU(2) × SU(2)) (N. Taylor).

Fit´ e, Kedlaya, Sutherland 10 / 22

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SLIDE 35

Sato–Tate conjecture for g = 2

Theorem (Johansson, N. Taylor; 2014-19)

For g = 2 and k totally real, the ST conjecture holds for 33 of the 35 possible ST groups. The missing cases are USp(4) and N(SU(2) × SU(2)). The case N(SU(2) × SU(2)) corresponds to an abelian surface A/k, which is either:

◮ ResL

k(E), where L/k quadratic and E/L an e.c. which is not a k-curve;

  • r

◮ absolutely simple with real multiplication not defined over k.

If k = Q, the ST conjecture holds for N(SU(2) × SU(2)) (N. Taylor).

Fit´ e, Kedlaya, Sutherland 10 / 22

slide-36
SLIDE 36

Sato–Tate conjecture for g = 2

Theorem (Johansson, N. Taylor; 2014-19)

For g = 2 and k totally real, the ST conjecture holds for 33 of the 35 possible ST groups. The missing cases are USp(4) and N(SU(2) × SU(2)). The case N(SU(2) × SU(2)) corresponds to an abelian surface A/k, which is either:

◮ ResL

k(E), where L/k quadratic and E/L an e.c. which is not a k-curve;

  • r

◮ absolutely simple with real multiplication not defined over k.

If k = Q, the ST conjecture holds for N(SU(2) × SU(2)) (N. Taylor).

Fit´ e, Kedlaya, Sutherland 10 / 22

slide-37
SLIDE 37

Sato–Tate groups for g = 3

Theorem(F.-Kedlaya-Sutherland; 2019)

Up to conjugacy, 433 subgroups of USp(6) satisfy the ST axioms. Only 410 of them occur as Sato–Tate groups of abelian threefolds

  • ver number fields.

Corollary

The degree of the endomorphism field [F : Q] of an abelian threefold over a number field divides 192, 336, or 432. This refines a previous result of Guralnick and Kedlaya, which asserts [F : Q] | 26 · 33 · 7 = Lcm(192, 336, 432) .

Fit´ e, Kedlaya, Sutherland 11 / 22

slide-38
SLIDE 38

Sato–Tate groups for g = 3

Theorem(F.-Kedlaya-Sutherland; 2019)

Up to conjugacy, 433 subgroups of USp(6) satisfy the ST axioms. Only 410 of them occur as Sato–Tate groups of abelian threefolds

  • ver number fields.

Corollary

The degree of the endomorphism field [F : Q] of an abelian threefold over a number field divides 192, 336, or 432. This refines a previous result of Guralnick and Kedlaya, which asserts [F : Q] | 26 · 33 · 7 = Lcm(192, 336, 432) .

Fit´ e, Kedlaya, Sutherland 11 / 22

slide-39
SLIDE 39

Sato–Tate groups for g = 3

Theorem(F.-Kedlaya-Sutherland; 2019)

Up to conjugacy, 433 subgroups of USp(6) satisfy the ST axioms. Only 410 of them occur as Sato–Tate groups of abelian threefolds

  • ver number fields.

Corollary

The degree of the endomorphism field [F : Q] of an abelian threefold over a number field divides 192, 336, or 432. This refines a previous result of Guralnick and Kedlaya, which asserts [F : Q] | 26 · 33 · 7 = Lcm(192, 336, 432) .

Fit´ e, Kedlaya, Sutherland 11 / 22

slide-40
SLIDE 40

Classification: identity components

(ST1) and (ST3) allow 14 possibilities for G 0 ⊆ USp(6):

USp(6) U(3) SU(2) × USp(4) U(1) × USp(4) U(1) × SU(2) × SU(2) SU(2) × U(1) × U(1) SU(2) × SU(2)2 SU(2) × U(1)2 U(1) × SU(2)2 U(1) × U(1)2 SU(2) × SU(2) × SU(2) U(1) × U(1) × U(1) SU(2)3 U(1)3

Notations:

For d ∈ {2, 3} and H ∈ {SU(2), U(1)}: Hd = {diag(u, d . . ., u) |u ∈ H }

For d ∈ {1, 3}: U(d) =

  • U(d)St

U(d)

St

  • ⊆ USp(2d)

Note in particular that SU(2) × U(1)2 ≃ U(1) × SU(2)2 .

Fit´ e, Kedlaya, Sutherland 12 / 22

slide-41
SLIDE 41

Classification: identity components

(ST1) and (ST3) allow 14 possibilities for G 0 ⊆ USp(6):

USp(6) U(3) SU(2) × USp(4) U(1) × USp(4) U(1) × SU(2) × SU(2) SU(2) × U(1) × U(1) SU(2) × SU(2)2 SU(2) × U(1)2 U(1) × SU(2)2 U(1) × U(1)2 SU(2) × SU(2) × SU(2) U(1) × U(1) × U(1) SU(2)3 U(1)3

Notations:

For d ∈ {2, 3} and H ∈ {SU(2), U(1)}: Hd = {diag(u, d . . ., u) |u ∈ H }

For d ∈ {1, 3}: U(d) =

  • U(d)St

U(d)

St

  • ⊆ USp(2d)

Note in particular that SU(2) × U(1)2 ≃ U(1) × SU(2)2 .

Fit´ e, Kedlaya, Sutherland 12 / 22

slide-42
SLIDE 42

Classification: identity components

(ST1) and (ST3) allow 14 possibilities for G 0 ⊆ USp(6):

USp(6) U(3) SU(2) × USp(4) U(1) × USp(4) U(1) × SU(2) × SU(2) SU(2) × U(1) × U(1) SU(2) × SU(2)2 SU(2) × U(1)2 U(1) × SU(2)2 U(1) × U(1)2 SU(2) × SU(2) × SU(2) U(1) × U(1) × U(1) SU(2)3 U(1)3

Notations:

For d ∈ {2, 3} and H ∈ {SU(2), U(1)}: Hd = {diag(u, d . . ., u) |u ∈ H }

For d ∈ {1, 3}: U(d) =

  • U(d)St

U(d)

St

  • ⊆ USp(2d)

Note in particular that SU(2) × U(1)2 ≃ U(1) × SU(2)2 .

Fit´ e, Kedlaya, Sutherland 12 / 22

slide-43
SLIDE 43

Classification: identity components

(ST1) and (ST3) allow 14 possibilities for G 0 ⊆ USp(6):

USp(6) U(3) SU(2) × USp(4) U(1) × USp(4) U(1) × SU(2) × SU(2) SU(2) × U(1) × U(1) SU(2) × SU(2)2 SU(2) × U(1)2 U(1) × SU(2)2 U(1) × U(1)2 SU(2) × SU(2) × SU(2) U(1) × U(1) × U(1) SU(2)3 U(1)3

Notations:

For d ∈ {2, 3} and H ∈ {SU(2), U(1)}: Hd = {diag(u, d . . ., u) |u ∈ H }

For d ∈ {1, 3}: U(d) =

  • U(d)St

U(d)

St

  • ⊆ USp(2d)

Note in particular that SU(2) × U(1)2 ≃ U(1) × SU(2)2 .

Fit´ e, Kedlaya, Sutherland 12 / 22

slide-44
SLIDE 44

Classification: From Lie groups to finite groups

General strategy to recover the possibilities for G from G 0: Compute N = NUSp(6)(G 0) and N /G 0 . Use G ⊆ USp(6) with G0 = G 0 satisfying (ST2)

  • /∼ ←

→ finite H ⊆ N/G 0 s.t. HG 0 satisfies (ST2)

  • /∼

Consider 3 cases depending on G 0:

◮ Genuine of dimension 3: G 0 ⊆ USp(6) cannot be written as

G 0 = G 0,1 × G 0,2 with G 0,1 ⊆ SU(2) and G 0,2 ⊆ USp(4) . (∗)

◮ Split case: G 0 can be written as in (*) and

N ≃ N1 × N2 , where Ni = NUSp(2i)(G 0,i) .

◮ Non-split case: G 0 can be written as in (*) and

N1 × N2 N .

Fit´ e, Kedlaya, Sutherland 13 / 22

slide-45
SLIDE 45

Classification: From Lie groups to finite groups

General strategy to recover the possibilities for G from G 0: Compute N = NUSp(6)(G 0) and N /G 0 . Use G ⊆ USp(6) with G0 = G 0 satisfying (ST2)

  • /∼ ←

→ finite H ⊆ N/G 0 s.t. HG 0 satisfies (ST2)

  • /∼

Consider 3 cases depending on G 0:

◮ Genuine of dimension 3: G 0 ⊆ USp(6) cannot be written as

G 0 = G 0,1 × G 0,2 with G 0,1 ⊆ SU(2) and G 0,2 ⊆ USp(4) . (∗)

◮ Split case: G 0 can be written as in (*) and

N ≃ N1 × N2 , where Ni = NUSp(2i)(G 0,i) .

◮ Non-split case: G 0 can be written as in (*) and

N1 × N2 N .

Fit´ e, Kedlaya, Sutherland 13 / 22

slide-46
SLIDE 46

Classification: From Lie groups to finite groups

General strategy to recover the possibilities for G from G 0: Compute N = NUSp(6)(G 0) and N /G 0 . Use G ⊆ USp(6) with G0 = G 0 satisfying (ST2)

  • /∼ ←

→ finite H ⊆ N/G 0 s.t. HG 0 satisfies (ST2)

  • /∼

Consider 3 cases depending on G 0:

◮ Genuine of dimension 3: G 0 ⊆ USp(6) cannot be written as

G 0 = G 0,1 × G 0,2 with G 0,1 ⊆ SU(2) and G 0,2 ⊆ USp(4) . (∗)

◮ Split case: G 0 can be written as in (*) and

N ≃ N1 × N2 , where Ni = NUSp(2i)(G 0,i) .

◮ Non-split case: G 0 can be written as in (*) and

N1 × N2 N .

Fit´ e, Kedlaya, Sutherland 13 / 22

slide-47
SLIDE 47

Classification: From Lie groups to finite groups

General strategy to recover the possibilities for G from G 0: Compute N = NUSp(6)(G 0) and N /G 0 . Use G ⊆ USp(6) with G0 = G 0 satisfying (ST2)

  • /∼ ←

→ finite H ⊆ N/G 0 s.t. HG 0 satisfies (ST2)

  • /∼

Consider 3 cases depending on G 0:

◮ Genuine of dimension 3: G 0 ⊆ USp(6) cannot be written as

G 0 = G 0,1 × G 0,2 with G 0,1 ⊆ SU(2) and G 0,2 ⊆ USp(4) . (∗)

◮ Split case: G 0 can be written as in (*) and

N ≃ N1 × N2 , where Ni = NUSp(2i)(G 0,i) .

◮ Non-split case: G 0 can be written as in (*) and

N1 × N2 N .

Fit´ e, Kedlaya, Sutherland 13 / 22

slide-48
SLIDE 48

Classification: From Lie groups to finite groups

General strategy to recover the possibilities for G from G 0: Compute N = NUSp(6)(G 0) and N /G 0 . Use G ⊆ USp(6) with G0 = G 0 satisfying (ST2)

  • /∼ ←

→ finite H ⊆ N/G 0 s.t. HG 0 satisfies (ST2)

  • /∼

Consider 3 cases depending on G 0:

◮ Genuine of dimension 3: G 0 ⊆ USp(6) cannot be written as

G 0 = G 0,1 × G 0,2 with G 0,1 ⊆ SU(2) and G 0,2 ⊆ USp(4) . (∗)

◮ Split case: G 0 can be written as in (*) and

N ≃ N1 × N2 , where Ni = NUSp(2i)(G 0,i) .

◮ Non-split case: G 0 can be written as in (*) and

N1 × N2 N .

Fit´ e, Kedlaya, Sutherland 13 / 22

slide-49
SLIDE 49

Classification: From Lie groups to finite groups

General strategy to recover the possibilities for G from G 0: Compute N = NUSp(6)(G 0) and N /G 0 . Use G ⊆ USp(6) with G0 = G 0 satisfying (ST2)

  • /∼ ←

→ finite H ⊆ N/G 0 s.t. HG 0 satisfies (ST2)

  • /∼

Consider 3 cases depending on G 0:

◮ Genuine of dimension 3: G 0 ⊆ USp(6) cannot be written as

G 0 = G 0,1 × G 0,2 with G 0,1 ⊆ SU(2) and G 0,2 ⊆ USp(4) . (∗)

◮ Split case: G 0 can be written as in (*) and

N ≃ N1 × N2 , where Ni = NUSp(2i)(G 0,i) .

◮ Non-split case: G 0 can be written as in (*) and

N1 × N2 N .

Fit´ e, Kedlaya, Sutherland 13 / 22

slide-50
SLIDE 50

Classification: From Lie groups to finite groups

General strategy to recover the possibilities for G from G 0: Compute N = NUSp(6)(G 0) and N /G 0 . Use G ⊆ USp(6) with G0 = G 0 satisfying (ST2)

  • /∼ ←

→ finite H ⊆ N/G 0 s.t. HG 0 satisfies (ST2)

  • /∼

Consider 3 cases depending on G 0:

◮ Genuine of dimension 3: G 0 ⊆ USp(6) cannot be written as

G 0 = G 0,1 × G 0,2 with G 0,1 ⊆ SU(2) and G 0,2 ⊆ USp(4) . (∗)

◮ Split case: G 0 can be written as in (*) and

N ≃ N1 × N2 , where Ni = NUSp(2i)(G 0,i) .

◮ Non-split case: G 0 can be written as in (*) and

N1 × N2 N .

Fit´ e, Kedlaya, Sutherland 13 / 22

slide-51
SLIDE 51

Classification: cases depending on G 0

Genuine dim. 3 cases

  • USp(6)

U(3) Split cases                              SU(2) × USp(4) U(1) × USp(4) U(1) × SU(2) × SU(2) SU(2) × U(1) × U(1) SU(2) × SU(2)2 SU(2) × U(1)2 U(1) × SU(2)2 U(1) × U(1)2 Non-split cases          SU(2) × SU(2) × SU(2) U(1) × U(1) × U(1) SU(2)3 U(1)3

Fit´ e, Kedlaya, Sutherland 14 / 22

slide-52
SLIDE 52

Classification: From G 0 to G

Genuine cases: USp(6), U(3), N(U(3)). Split cases: Since N/G 0 ≃ N1/G 0,1 × N2/G 0,2 we have A =

H ⊆ N/G 0 finite s.t. HG 0 satisfies (ST2)

  • /∼ ←

   H = H1 ×H′ H2 with Hi ⊆ Ni/G 0,i finite s.t. HiG 0,i satisfies (ST2)    /∼

The set on the right can be recovered from the ST group classifications in dimensions 1 and 2. This accounts for 211 groups. Non-split cases: G 0 N/G 0 #A SU(2) × SU(2) × SU(2) S3 4 U(1) × U(1) × U(1) (C2 × C2 × C2) ⋊ S3 33 SU(2)3 SO(3) 11 U(1)3 PSU(3) ⋊ C2 171

Fit´ e, Kedlaya, Sutherland 15 / 22

slide-53
SLIDE 53

Classification: From G 0 to G

Genuine cases: USp(6), U(3), N(U(3)). Split cases: Since N/G 0 ≃ N1/G 0,1 × N2/G 0,2 we have A =

H ⊆ N/G 0 finite s.t. HG 0 satisfies (ST2)

  • /∼ ←

   H = H1 ×H′ H2 with Hi ⊆ Ni/G 0,i finite s.t. HiG 0,i satisfies (ST2)    /∼

The set on the right can be recovered from the ST group classifications in dimensions 1 and 2. This accounts for 211 groups. Non-split cases: G 0 N/G 0 #A SU(2) × SU(2) × SU(2) S3 4 U(1) × U(1) × U(1) (C2 × C2 × C2) ⋊ S3 33 SU(2)3 SO(3) 11 U(1)3 PSU(3) ⋊ C2 171

Fit´ e, Kedlaya, Sutherland 15 / 22

slide-54
SLIDE 54

Classification: From G 0 to G

Genuine cases: USp(6), U(3), N(U(3)). Split cases: Since N/G 0 ≃ N1/G 0,1 × N2/G 0,2 we have A =

H ⊆ N/G 0 finite s.t. HG 0 satisfies (ST2)

  • /∼ ←

   H = H1 ×H′ H2 with Hi ⊆ Ni/G 0,i finite s.t. HiG 0,i satisfies (ST2)    /∼

The set on the right can be recovered from the ST group classifications in dimensions 1 and 2. This accounts for 211 groups. Non-split cases: G 0 N/G 0 #A SU(2) × SU(2) × SU(2) S3 4 U(1) × U(1) × U(1) (C2 × C2 × C2) ⋊ S3 33 SU(2)3 SO(3) 11 U(1)3 PSU(3) ⋊ C2 171

Fit´ e, Kedlaya, Sutherland 15 / 22

slide-55
SLIDE 55

Classification: From G 0 to G

Genuine cases: USp(6), U(3), N(U(3)). Split cases: Since N/G 0 ≃ N1/G 0,1 × N2/G 0,2 we have A =

H ⊆ N/G 0 finite s.t. HG 0 satisfies (ST2)

  • /∼ ←

   H = H1 ×H′ H2 with Hi ⊆ Ni/G 0,i finite s.t. HiG 0,i satisfies (ST2)    /∼

The set on the right can be recovered from the ST group classifications in dimensions 1 and 2. This accounts for 211 groups. Non-split cases: G 0 N/G 0 #A SU(2) × SU(2) × SU(2) S3 4 U(1) × U(1) × U(1) (C2 × C2 × C2) ⋊ S3 33 SU(2)3 SO(3) 11 U(1)3 PSU(3) ⋊ C2 171

Fit´ e, Kedlaya, Sutherland 15 / 22

slide-56
SLIDE 56

Classification: From G 0 to G

Genuine cases: USp(6), U(3), N(U(3)). Split cases: Since N/G 0 ≃ N1/G 0,1 × N2/G 0,2 we have A =

H ⊆ N/G 0 finite s.t. HG 0 satisfies (ST2)

  • /∼ ←

   H = H1 ×H′ H2 with Hi ⊆ Ni/G 0,i finite s.t. HiG 0,i satisfies (ST2)    /∼

The set on the right can be recovered from the ST group classifications in dimensions 1 and 2. This accounts for 211 groups. Non-split cases: G 0 N/G 0 #A SU(2) × SU(2) × SU(2) S3 4 U(1) × U(1) × U(1) (C2 × C2 × C2) ⋊ S3 33 SU(2)3 SO(3) 11 U(1)3 PSU(3) ⋊ C2 171

Fit´ e, Kedlaya, Sutherland 15 / 22

slide-57
SLIDE 57

G 0 = U(1)3: map of the proof

A =

  • finite H ⊆ PSU(3) ⋊ C2

s.t. H U(1)3 satisfies (ST2)

  • /∼
  • finite µ3 ⊆ H ⊆ SU(3)

s.t. H U(1)3 satisfies (ST2)

  • /∼
  • C2-extensions of groups

in the set on the left

  • /∼

֒ →

  • finite µ3 ⊆ H ⊆ SU(3) s.t.

H U(1)3 sat. (ST2) for Tr(∧2C6)

  • /∼

||

  • finite µ3 ⊆ H ⊆ SU(3) s.t.

| Tr(h)|2 ∈ Z for all h ∈ H

  • /∼

The above injection is seen to be a bijection a posteriori. This yields 171 = 63 + 108 groups.

Fit´ e, Kedlaya, Sutherland 16 / 22

slide-58
SLIDE 58

G 0 = U(1)3: map of the proof

A =

  • finite H ⊆ PSU(3) ⋊ C2

s.t. H U(1)3 satisfies (ST2)

  • /∼
  • finite µ3 ⊆ H ⊆ SU(3)

s.t. H U(1)3 satisfies (ST2)

  • /∼
  • C2-extensions of groups

in the set on the left

  • /∼

֒ →

  • finite µ3 ⊆ H ⊆ SU(3) s.t.

H U(1)3 sat. (ST2) for Tr(∧2C6)

  • /∼

||

  • finite µ3 ⊆ H ⊆ SU(3) s.t.

| Tr(h)|2 ∈ Z for all h ∈ H

  • /∼

The above injection is seen to be a bijection a posteriori. This yields 171 = 63 + 108 groups.

Fit´ e, Kedlaya, Sutherland 16 / 22

slide-59
SLIDE 59

G 0 = U(1)3: map of the proof

A =

  • finite H ⊆ PSU(3) ⋊ C2

s.t. H U(1)3 satisfies (ST2)

  • /∼
  • finite µ3 ⊆ H ⊆ SU(3)

s.t. H U(1)3 satisfies (ST2)

  • /∼
  • C2-extensions of groups

in the set on the left

  • /∼

֒ →

  • finite µ3 ⊆ H ⊆ SU(3) s.t.

H U(1)3 sat. (ST2) for Tr(∧2C6)

  • /∼

||

  • finite µ3 ⊆ H ⊆ SU(3) s.t.

| Tr(h)|2 ∈ Z for all h ∈ H

  • /∼

The above injection is seen to be a bijection a posteriori. This yields 171 = 63 + 108 groups.

Fit´ e, Kedlaya, Sutherland 16 / 22

slide-60
SLIDE 60

G 0 = U(1)3: map of the proof

A =

  • finite H ⊆ PSU(3) ⋊ C2

s.t. H U(1)3 satisfies (ST2)

  • /∼
  • finite µ3 ⊆ H ⊆ SU(3)

s.t. H U(1)3 satisfies (ST2)

  • /∼
  • C2-extensions of groups

in the set on the left

  • /∼

֒ →

  • finite µ3 ⊆ H ⊆ SU(3) s.t.

H U(1)3 sat. (ST2) for Tr(∧2C6)

  • /∼

||

  • finite µ3 ⊆ H ⊆ SU(3) s.t.

| Tr(h)|2 ∈ Z for all h ∈ H

  • /∼

The above injection is seen to be a bijection a posteriori. This yields 171 = 63 + 108 groups.

Fit´ e, Kedlaya, Sutherland 16 / 22

slide-61
SLIDE 61

G 0 = U(1)3: map of the proof

A =

  • finite H ⊆ PSU(3) ⋊ C2

s.t. H U(1)3 satisfies (ST2)

  • /∼
  • finite µ3 ⊆ H ⊆ SU(3)

s.t. H U(1)3 satisfies (ST2)

  • /∼
  • C2-extensions of groups

in the set on the left

  • /∼

֒ →

  • finite µ3 ⊆ H ⊆ SU(3) s.t.

H U(1)3 sat. (ST2) for Tr(∧2C6)

  • /∼

||

  • finite µ3 ⊆ H ⊆ SU(3) s.t.

| Tr(h)|2 ∈ Z for all h ∈ H

  • /∼

The above injection is seen to be a bijection a posteriori. This yields 171 = 63 + 108 groups.

Fit´ e, Kedlaya, Sutherland 16 / 22

slide-62
SLIDE 62

G 0 = U(1)3: map of the proof

A =

  • finite H ⊆ PSU(3) ⋊ C2

s.t. H U(1)3 satisfies (ST2)

  • /∼
  • finite µ3 ⊆ H ⊆ SU(3)

s.t. H U(1)3 satisfies (ST2)

  • /∼
  • C2-extensions of groups

in the set on the left

  • /∼

֒ →

  • finite µ3 ⊆ H ⊆ SU(3) s.t.

H U(1)3 sat. (ST2) for Tr(∧2C6)

  • /∼

||

  • finite µ3 ⊆ H ⊆ SU(3) s.t.

| Tr(h)|2 ∈ Z for all h ∈ H

  • /∼

The above injection is seen to be a bijection a posteriori. This yields 171 = 63 + 108 groups.

Fit´ e, Kedlaya, Sutherland 16 / 22

slide-63
SLIDE 63

G 0 = U(1)3: Ingredients of the proof

The finite µ3 ⊆ H ⊆ SU(3) were classified by Blichfeldt, Miller, and Dickson (1916). They are:

◮ Abelian groups ◮ C2-extensions of abelian groups. ◮ C3-extenions of abelian groups. ◮ S3-extensions of abelian groups. ◮ cyclic extensions of exceptional subgroups of SU(2) (2T, 2O, 2I). ◮ Exceptional subgroups of SU(3)

(projected in PSU(3) are E36 , E72 , E216 , A5, A6, E168 ≃ PSL(2, 7)).

Determining the possible orders of h ∈ H reduces to solving “a multiplicative Manin-Mumford problem”:

◮ If z1, z2, z3 ∈ µ∞ are the eigenvalues of h, then:

|z1 + z2 + z3|2 = | Tr(h)|2 ∈ Z and z1z2z3 = 1 .

◮ Even more, it must happen |zn

1 + zn 2 + zn 3 |2 ∈ Z for all n ≥ 1.

◮ One deduces that ord(h)|21, 24, 36.

Assemble elements to build groups of the shape described by the BMD classification.

Fit´ e, Kedlaya, Sutherland 17 / 22

slide-64
SLIDE 64

G 0 = U(1)3: Ingredients of the proof

The finite µ3 ⊆ H ⊆ SU(3) were classified by Blichfeldt, Miller, and Dickson (1916). They are:

◮ Abelian groups ◮ C2-extensions of abelian groups. ◮ C3-extenions of abelian groups. ◮ S3-extensions of abelian groups. ◮ cyclic extensions of exceptional subgroups of SU(2) (2T, 2O, 2I). ◮ Exceptional subgroups of SU(3)

(projected in PSU(3) are E36 , E72 , E216 , A5, A6, E168 ≃ PSL(2, 7)).

Determining the possible orders of h ∈ H reduces to solving “a multiplicative Manin-Mumford problem”:

◮ If z1, z2, z3 ∈ µ∞ are the eigenvalues of h, then:

|z1 + z2 + z3|2 = | Tr(h)|2 ∈ Z and z1z2z3 = 1 .

◮ Even more, it must happen |zn

1 + zn 2 + zn 3 |2 ∈ Z for all n ≥ 1.

◮ One deduces that ord(h)|21, 24, 36.

Assemble elements to build groups of the shape described by the BMD classification.

Fit´ e, Kedlaya, Sutherland 17 / 22

slide-65
SLIDE 65

G 0 = U(1)3: Ingredients of the proof

The finite µ3 ⊆ H ⊆ SU(3) were classified by Blichfeldt, Miller, and Dickson (1916). They are:

◮ Abelian groups ◮ C2-extensions of abelian groups. ◮ C3-extenions of abelian groups. ◮ S3-extensions of abelian groups. ◮ cyclic extensions of exceptional subgroups of SU(2) (2T, 2O, 2I). ◮ Exceptional subgroups of SU(3)

(projected in PSU(3) are E36 , E72 , E216 , A5, A6, E168 ≃ PSL(2, 7)).

Determining the possible orders of h ∈ H reduces to solving “a multiplicative Manin-Mumford problem”:

◮ If z1, z2, z3 ∈ µ∞ are the eigenvalues of h, then:

|z1 + z2 + z3|2 = | Tr(h)|2 ∈ Z and z1z2z3 = 1 .

◮ Even more, it must happen |zn

1 + zn 2 + zn 3 |2 ∈ Z for all n ≥ 1.

◮ One deduces that ord(h)|21, 24, 36.

Assemble elements to build groups of the shape described by the BMD classification.

Fit´ e, Kedlaya, Sutherland 17 / 22

slide-66
SLIDE 66

G 0 = U(1)3: Ingredients of the proof

The finite µ3 ⊆ H ⊆ SU(3) were classified by Blichfeldt, Miller, and Dickson (1916). They are:

◮ Abelian groups ◮ C2-extensions of abelian groups. ◮ C3-extenions of abelian groups. ◮ S3-extensions of abelian groups. ◮ cyclic extensions of exceptional subgroups of SU(2) (2T, 2O, 2I). ◮ Exceptional subgroups of SU(3)

(projected in PSU(3) are E36 , E72 , E216 , A5, A6, E168 ≃ PSL(2, 7)).

Determining the possible orders of h ∈ H reduces to solving “a multiplicative Manin-Mumford problem”:

◮ If z1, z2, z3 ∈ µ∞ are the eigenvalues of h, then:

|z1 + z2 + z3|2 = | Tr(h)|2 ∈ Z and z1z2z3 = 1 .

◮ Even more, it must happen |zn

1 + zn 2 + zn 3 |2 ∈ Z for all n ≥ 1.

◮ One deduces that ord(h)|21, 24, 36.

Assemble elements to build groups of the shape described by the BMD classification.

Fit´ e, Kedlaya, Sutherland 17 / 22

slide-67
SLIDE 67

G 0 = U(1)3: Ingredients of the proof

The finite µ3 ⊆ H ⊆ SU(3) were classified by Blichfeldt, Miller, and Dickson (1916). They are:

◮ Abelian groups ◮ C2-extensions of abelian groups. ◮ C3-extenions of abelian groups. ◮ S3-extensions of abelian groups. ◮ cyclic extensions of exceptional subgroups of SU(2) (2T, 2O, 2I). ◮ Exceptional subgroups of SU(3)

(projected in PSU(3) are E36 , E72 , E216 , A5, A6, E168 ≃ PSL(2, 7)).

Determining the possible orders of h ∈ H reduces to solving “a multiplicative Manin-Mumford problem”:

◮ If z1, z2, z3 ∈ µ∞ are the eigenvalues of h, then:

|z1 + z2 + z3|2 = | Tr(h)|2 ∈ Z and z1z2z3 = 1 .

◮ Even more, it must happen |zn

1 + zn 2 + zn 3 |2 ∈ Z for all n ≥ 1.

◮ One deduces that ord(h)|21, 24, 36.

Assemble elements to build groups of the shape described by the BMD classification.

Fit´ e, Kedlaya, Sutherland 17 / 22

slide-68
SLIDE 68

G 0 = U(1)3: Ingredients of the proof

The finite µ3 ⊆ H ⊆ SU(3) were classified by Blichfeldt, Miller, and Dickson (1916). They are:

◮ Abelian groups ◮ C2-extensions of abelian groups. ◮ C3-extenions of abelian groups. ◮ S3-extensions of abelian groups. ◮ cyclic extensions of exceptional subgroups of SU(2) (2T, 2O, 2I). ◮ Exceptional subgroups of SU(3)

(projected in PSU(3) are E36 , E72 , E216 , A5, A6, E168 ≃ PSL(2, 7)).

Determining the possible orders of h ∈ H reduces to solving “a multiplicative Manin-Mumford problem”:

◮ If z1, z2, z3 ∈ µ∞ are the eigenvalues of h, then:

|z1 + z2 + z3|2 = | Tr(h)|2 ∈ Z and z1z2z3 = 1 .

◮ Even more, it must happen |zn

1 + zn 2 + zn 3 |2 ∈ Z for all n ≥ 1.

◮ One deduces that ord(h)|21, 24, 36.

Assemble elements to build groups of the shape described by the BMD classification.

Fit´ e, Kedlaya, Sutherland 17 / 22

slide-69
SLIDE 69

G 0 = U(1)3: Ingredients of the proof

The finite µ3 ⊆ H ⊆ SU(3) were classified by Blichfeldt, Miller, and Dickson (1916). They are:

◮ Abelian groups ◮ C2-extensions of abelian groups. ◮ C3-extenions of abelian groups. ◮ S3-extensions of abelian groups. ◮ cyclic extensions of exceptional subgroups of SU(2) (2T, 2O, 2I). ◮ Exceptional subgroups of SU(3)

(projected in PSU(3) are E36 , E72 , E216 , A5, A6, E168 ≃ PSL(2, 7)).

Determining the possible orders of h ∈ H reduces to solving “a multiplicative Manin-Mumford problem”:

◮ If z1, z2, z3 ∈ µ∞ are the eigenvalues of h, then:

|z1 + z2 + z3|2 = | Tr(h)|2 ∈ Z and z1z2z3 = 1 .

◮ Even more, it must happen |zn

1 + zn 2 + zn 3 |2 ∈ Z for all n ≥ 1.

◮ One deduces that ord(h)|21, 24, 36.

Assemble elements to build groups of the shape described by the BMD classification.

Fit´ e, Kedlaya, Sutherland 17 / 22

slide-70
SLIDE 70

Classification: Invariants

Only 210 distinct pairs (G 0, G/G 0). Define the (i, j, k)-th moment, for i, j, k ≥ 0, as Mi,j,k(G) := dimC

  • (∧1C6)⊗i ⊗ (∧2C6)⊗j ⊗ (∧3C6)⊗kG ∈ Z≥0 .

The tuple {Mi,j,k(G)}i+j+k≤6 attains 432 values. It only conflates a pair of groups G1, G2, for which however G1/G 0

1 ≃ 54, 5 ≃ 54, 8 ≃ G2/G 0 2 .

In fact, Mi,j,k(G1) = Mi,j,k(G2) for all i, j, k ! In total, the 433 groups have 10988 connected components (4 for g = 1 and 414 for g = 2). There are 30 maximal groups. Any possible order of G/G 0 divides 192, 336, or 432.

Fit´ e, Kedlaya, Sutherland 18 / 22

slide-71
SLIDE 71

Classification: Invariants

Only 210 distinct pairs (G 0, G/G 0). Define the (i, j, k)-th moment, for i, j, k ≥ 0, as Mi,j,k(G) := dimC

  • (∧1C6)⊗i ⊗ (∧2C6)⊗j ⊗ (∧3C6)⊗kG ∈ Z≥0 .

The tuple {Mi,j,k(G)}i+j+k≤6 attains 432 values. It only conflates a pair of groups G1, G2, for which however G1/G 0

1 ≃ 54, 5 ≃ 54, 8 ≃ G2/G 0 2 .

In fact, Mi,j,k(G1) = Mi,j,k(G2) for all i, j, k ! In total, the 433 groups have 10988 connected components (4 for g = 1 and 414 for g = 2). There are 30 maximal groups. Any possible order of G/G 0 divides 192, 336, or 432.

Fit´ e, Kedlaya, Sutherland 18 / 22

slide-72
SLIDE 72

Classification: Invariants

Only 210 distinct pairs (G 0, G/G 0). Define the (i, j, k)-th moment, for i, j, k ≥ 0, as Mi,j,k(G) := dimC

  • (∧1C6)⊗i ⊗ (∧2C6)⊗j ⊗ (∧3C6)⊗kG ∈ Z≥0 .

The tuple {Mi,j,k(G)}i+j+k≤6 attains 432 values. It only conflates a pair of groups G1, G2, for which however G1/G 0

1 ≃ 54, 5 ≃ 54, 8 ≃ G2/G 0 2 .

In fact, Mi,j,k(G1) = Mi,j,k(G2) for all i, j, k ! In total, the 433 groups have 10988 connected components (4 for g = 1 and 414 for g = 2). There are 30 maximal groups. Any possible order of G/G 0 divides 192, 336, or 432.

Fit´ e, Kedlaya, Sutherland 18 / 22

slide-73
SLIDE 73

Classification: Invariants

Only 210 distinct pairs (G 0, G/G 0). Define the (i, j, k)-th moment, for i, j, k ≥ 0, as Mi,j,k(G) := dimC

  • (∧1C6)⊗i ⊗ (∧2C6)⊗j ⊗ (∧3C6)⊗kG ∈ Z≥0 .

The tuple {Mi,j,k(G)}i+j+k≤6 attains 432 values. It only conflates a pair of groups G1, G2, for which however G1/G 0

1 ≃ 54, 5 ≃ 54, 8 ≃ G2/G 0 2 .

In fact, Mi,j,k(G1) = Mi,j,k(G2) for all i, j, k ! In total, the 433 groups have 10988 connected components (4 for g = 1 and 414 for g = 2). There are 30 maximal groups. Any possible order of G/G 0 divides 192, 336, or 432.

Fit´ e, Kedlaya, Sutherland 18 / 22

slide-74
SLIDE 74

Classification: Invariants

Only 210 distinct pairs (G 0, G/G 0). Define the (i, j, k)-th moment, for i, j, k ≥ 0, as Mi,j,k(G) := dimC

  • (∧1C6)⊗i ⊗ (∧2C6)⊗j ⊗ (∧3C6)⊗kG ∈ Z≥0 .

The tuple {Mi,j,k(G)}i+j+k≤6 attains 432 values. It only conflates a pair of groups G1, G2, for which however G1/G 0

1 ≃ 54, 5 ≃ 54, 8 ≃ G2/G 0 2 .

In fact, Mi,j,k(G1) = Mi,j,k(G2) for all i, j, k ! In total, the 433 groups have 10988 connected components (4 for g = 1 and 414 for g = 2). There are 30 maximal groups. Any possible order of G/G 0 divides 192, 336, or 432.

Fit´ e, Kedlaya, Sutherland 18 / 22

slide-75
SLIDE 75

Classification: Invariants

Only 210 distinct pairs (G 0, G/G 0). Define the (i, j, k)-th moment, for i, j, k ≥ 0, as Mi,j,k(G) := dimC

  • (∧1C6)⊗i ⊗ (∧2C6)⊗j ⊗ (∧3C6)⊗kG ∈ Z≥0 .

The tuple {Mi,j,k(G)}i+j+k≤6 attains 432 values. It only conflates a pair of groups G1, G2, for which however G1/G 0

1 ≃ 54, 5 ≃ 54, 8 ≃ G2/G 0 2 .

In fact, Mi,j,k(G1) = Mi,j,k(G2) for all i, j, k ! In total, the 433 groups have 10988 connected components (4 for g = 1 and 414 for g = 2). There are 30 maximal groups. Any possible order of G/G 0 divides 192, 336, or 432.

Fit´ e, Kedlaya, Sutherland 18 / 22

slide-76
SLIDE 76

Classification: Invariants

Only 210 distinct pairs (G 0, G/G 0). Define the (i, j, k)-th moment, for i, j, k ≥ 0, as Mi,j,k(G) := dimC

  • (∧1C6)⊗i ⊗ (∧2C6)⊗j ⊗ (∧3C6)⊗kG ∈ Z≥0 .

The tuple {Mi,j,k(G)}i+j+k≤6 attains 432 values. It only conflates a pair of groups G1, G2, for which however G1/G 0

1 ≃ 54, 5 ≃ 54, 8 ≃ G2/G 0 2 .

In fact, Mi,j,k(G1) = Mi,j,k(G2) for all i, j, k ! In total, the 433 groups have 10988 connected components (4 for g = 1 and 414 for g = 2). There are 30 maximal groups. Any possible order of G/G 0 divides 192, 336, or 432.

Fit´ e, Kedlaya, Sutherland 18 / 22

slide-77
SLIDE 77

Realization

By Shimura, if A/k has CM by M, then F = M∗k. This rules out:

◮ 20 groups in the case U(1) × U(1) × U(1). ◮ 3 groups in the case SU(2) × U(1) × U(1).

This leaves 410 groups, 33 of which are maximal. It suffices to realize the maximal groups. The iso ST(A)/ ST(A)0 ≃ Gal(F/k) is compatible with base change. Given F/k′/k: ST(A)0

ST(A) Gal(F/k)

ST(Ak′)0

ST(Ak′)

  • Gal(F/k′)
  • Fit´

e, Kedlaya, Sutherland 19 / 22

slide-78
SLIDE 78

Realization

By Shimura, if A/k has CM by M, then F = M∗k. This rules out:

◮ 20 groups in the case U(1) × U(1) × U(1). ◮ 3 groups in the case SU(2) × U(1) × U(1).

This leaves 410 groups, 33 of which are maximal. It suffices to realize the maximal groups. The iso ST(A)/ ST(A)0 ≃ Gal(F/k) is compatible with base change. Given F/k′/k: ST(A)0

ST(A) Gal(F/k)

ST(Ak′)0

ST(Ak′)

  • Gal(F/k′)
  • Fit´

e, Kedlaya, Sutherland 19 / 22

slide-79
SLIDE 79

Realization

By Shimura, if A/k has CM by M, then F = M∗k. This rules out:

◮ 20 groups in the case U(1) × U(1) × U(1). ◮ 3 groups in the case SU(2) × U(1) × U(1).

This leaves 410 groups, 33 of which are maximal. It suffices to realize the maximal groups. The iso ST(A)/ ST(A)0 ≃ Gal(F/k) is compatible with base change. Given F/k′/k: ST(A)0

ST(A) Gal(F/k)

ST(Ak′)0

ST(Ak′)

  • Gal(F/k′)
  • Fit´

e, Kedlaya, Sutherland 19 / 22

slide-80
SLIDE 80

Realization

By Shimura, if A/k has CM by M, then F = M∗k. This rules out:

◮ 20 groups in the case U(1) × U(1) × U(1). ◮ 3 groups in the case SU(2) × U(1) × U(1).

This leaves 410 groups, 33 of which are maximal. It suffices to realize the maximal groups. The iso ST(A)/ ST(A)0 ≃ Gal(F/k) is compatible with base change. Given F/k′/k: ST(A)0

ST(A) Gal(F/k)

ST(Ak′)0

ST(Ak′)

  • Gal(F/k′)
  • Fit´

e, Kedlaya, Sutherland 19 / 22

slide-81
SLIDE 81

Realization

By Shimura, if A/k has CM by M, then F = M∗k. This rules out:

◮ 20 groups in the case U(1) × U(1) × U(1). ◮ 3 groups in the case SU(2) × U(1) × U(1).

This leaves 410 groups, 33 of which are maximal. It suffices to realize the maximal groups. The iso ST(A)/ ST(A)0 ≃ Gal(F/k) is compatible with base change. Given F/k′/k: ST(A)0

ST(A) Gal(F/k)

ST(Ak′)0

ST(Ak′)

  • Gal(F/k′)
  • Fit´

e, Kedlaya, Sutherland 19 / 22

slide-82
SLIDE 82

Realization of the maximal groups

Genuine cases (2 max. groups):

◮ USp(6): generic case. Eg.: y 2 = x7 − x + 1/Q. ◮ N(U(3)): Picard curves. Eg.: y 3 = x4 + x + 1/Q.

Split cases (13 max. groups): Maximality ensures the triviality of the fiber product, i.e. G ≃ G1 × G2 , where G1 and G2 are realizable in dimensions 1 and 2. Non-split cases (18 max. groups):

◮ G 0 = SU(2) × SU(2) × SU(2) (1. max. group): ResL

Q(E), where L/Q a

non-normal cubic and E/L e.c. which is not a Q-curve.

◮ G 0 = U(1) × U(1) × U(1) (3 max. groups):

Products of CM abelian varieties.

◮ G 0 = SU(2)3 (2 max. groups):

Twists of curves with many automorphisms.

Fit´ e, Kedlaya, Sutherland 20 / 22

slide-83
SLIDE 83

Realization of the maximal groups

Genuine cases (2 max. groups):

◮ USp(6): generic case. Eg.: y 2 = x7 − x + 1/Q. ◮ N(U(3)): Picard curves. Eg.: y 3 = x4 + x + 1/Q.

Split cases (13 max. groups): Maximality ensures the triviality of the fiber product, i.e. G ≃ G1 × G2 , where G1 and G2 are realizable in dimensions 1 and 2. Non-split cases (18 max. groups):

◮ G 0 = SU(2) × SU(2) × SU(2) (1. max. group): ResL

Q(E), where L/Q a

non-normal cubic and E/L e.c. which is not a Q-curve.

◮ G 0 = U(1) × U(1) × U(1) (3 max. groups):

Products of CM abelian varieties.

◮ G 0 = SU(2)3 (2 max. groups):

Twists of curves with many automorphisms.

Fit´ e, Kedlaya, Sutherland 20 / 22

slide-84
SLIDE 84

Realization of the maximal groups

Genuine cases (2 max. groups):

◮ USp(6): generic case. Eg.: y 2 = x7 − x + 1/Q. ◮ N(U(3)): Picard curves. Eg.: y 3 = x4 + x + 1/Q.

Split cases (13 max. groups): Maximality ensures the triviality of the fiber product, i.e. G ≃ G1 × G2 , where G1 and G2 are realizable in dimensions 1 and 2. Non-split cases (18 max. groups):

◮ G 0 = SU(2) × SU(2) × SU(2) (1. max. group): ResL

Q(E), where L/Q a

non-normal cubic and E/L e.c. which is not a Q-curve.

◮ G 0 = U(1) × U(1) × U(1) (3 max. groups):

Products of CM abelian varieties.

◮ G 0 = SU(2)3 (2 max. groups):

Twists of curves with many automorphisms.

Fit´ e, Kedlaya, Sutherland 20 / 22

slide-85
SLIDE 85

Realization of the maximal groups

G 0 = U(1)3 (12 max. groups):

◮ All such G satisfy

G/G 0 ֒ → GL3(OM) ⋊ Gal(M/Q) where M is a quadratic imaginary field of class number 1.

◮ Reinterpret

G/G 0 ֒ → Aut(E 3

M) ⋊ Gal(M/Q)

where E/Q is an elliptic curve with CM by OM.

◮ This gives a 1-cocycle

˜ ξ ∈ H1(G/G 0, Aut(E 3)) .

◮ There exists L/Q such that G/G 0 ≃ Gal(L/Q). ◮ Then setting

ξ : Gal(L/Q) ≃ G/G 0

˜ ξ

→ Aut(E 3) and A = (E 3)ξ one finds ST(A) ≃ G.

Fit´ e, Kedlaya, Sutherland 21 / 22

slide-86
SLIDE 86

Realization of the maximal groups

G 0 = U(1)3 (12 max. groups):

◮ All such G satisfy

G/G 0 ֒ → GL3(OM) ⋊ Gal(M/Q) where M is a quadratic imaginary field of class number 1.

◮ Reinterpret

G/G 0 ֒ → Aut(E 3

M) ⋊ Gal(M/Q)

where E/Q is an elliptic curve with CM by OM.

◮ This gives a 1-cocycle

˜ ξ ∈ H1(G/G 0, Aut(E 3)) .

◮ There exists L/Q such that G/G 0 ≃ Gal(L/Q). ◮ Then setting

ξ : Gal(L/Q) ≃ G/G 0

˜ ξ

→ Aut(E 3) and A = (E 3)ξ one finds ST(A) ≃ G.

Fit´ e, Kedlaya, Sutherland 21 / 22

slide-87
SLIDE 87

Realization of the maximal groups

G 0 = U(1)3 (12 max. groups):

◮ All such G satisfy

G/G 0 ֒ → GL3(OM) ⋊ Gal(M/Q) where M is a quadratic imaginary field of class number 1.

◮ Reinterpret

G/G 0 ֒ → Aut(E 3

M) ⋊ Gal(M/Q)

where E/Q is an elliptic curve with CM by OM.

◮ This gives a 1-cocycle

˜ ξ ∈ H1(G/G 0, Aut(E 3)) .

◮ There exists L/Q such that G/G 0 ≃ Gal(L/Q). ◮ Then setting

ξ : Gal(L/Q) ≃ G/G 0

˜ ξ

→ Aut(E 3) and A = (E 3)ξ one finds ST(A) ≃ G.

Fit´ e, Kedlaya, Sutherland 21 / 22

slide-88
SLIDE 88

Realization of the maximal groups

G 0 = U(1)3 (12 max. groups):

◮ All such G satisfy

G/G 0 ֒ → GL3(OM) ⋊ Gal(M/Q) where M is a quadratic imaginary field of class number 1.

◮ Reinterpret

G/G 0 ֒ → Aut(E 3

M) ⋊ Gal(M/Q)

where E/Q is an elliptic curve with CM by OM.

◮ This gives a 1-cocycle

˜ ξ ∈ H1(G/G 0, Aut(E 3)) .

◮ There exists L/Q such that G/G 0 ≃ Gal(L/Q). ◮ Then setting

ξ : Gal(L/Q) ≃ G/G 0

˜ ξ

→ Aut(E 3) and A = (E 3)ξ one finds ST(A) ≃ G.

Fit´ e, Kedlaya, Sutherland 21 / 22

slide-89
SLIDE 89

Realization of the maximal groups

G 0 = U(1)3 (12 max. groups):

◮ All such G satisfy

G/G 0 ֒ → GL3(OM) ⋊ Gal(M/Q) where M is a quadratic imaginary field of class number 1.

◮ Reinterpret

G/G 0 ֒ → Aut(E 3

M) ⋊ Gal(M/Q)

where E/Q is an elliptic curve with CM by OM.

◮ This gives a 1-cocycle

˜ ξ ∈ H1(G/G 0, Aut(E 3)) .

◮ There exists L/Q such that G/G 0 ≃ Gal(L/Q). ◮ Then setting

ξ : Gal(L/Q) ≃ G/G 0

˜ ξ

→ Aut(E 3) and A = (E 3)ξ one finds ST(A) ≃ G.

Fit´ e, Kedlaya, Sutherland 21 / 22

slide-90
SLIDE 90

Open questions

Realizability over totally real fields? Realizability over Q? Existence of a number field over which all 410 groups can be realized? Realizability via principally polarized abelian thereefolds? Realizability via Jacobians of genus 3 curves?

◮ Partial answer: At least 22 of the 33 maximal groups can be realized

via Jacobians... G/G 0 #(G/G 0) C with ST(Jac(C)) (C4 × C4) ⋊ S3 × C2 192 Twist of the Fermat quartic PSL(2, 7) × C2 336 Twist of the Klein quartic (C6 × C6) ⋊ S3 × C2 432 ? E216 × C2 432 ?

Fit´ e, Kedlaya, Sutherland 22 / 22