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Remarks on High Reynolds Number Hydrodynamics Peter Constantin - - PowerPoint PPT Presentation

Remarks on High Reynolds Number Hydrodynamics Peter Constantin Princeton University June 2017 The equations Incompressible Navier-Stokes for u = u NS = S NS ( t ) u 0 : t u + u u u + p = f , u = 0 , The


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SLIDE 1

Remarks on High Reynolds Number Hydrodynamics

Peter Constantin

Princeton University June 2017

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SLIDE 2

The equations

Incompressible Navier-Stokes for u = uNS = SNS(t)u0: ∂tu + u · ∇u − ν∆u + ∇p = f, ∇ · u = 0,

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SLIDE 3

The equations

Incompressible Navier-Stokes for u = uNS = SNS(t)u0: ∂tu + u · ∇u − ν∆u + ∇p = f, ∇ · u = 0, and incompressible Euler for v = uE = SE(t)u0: ∂tv + v · ∇v + ∇p = f, ∇ · v = 0.

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SLIDE 4

The equations

Incompressible Navier-Stokes for u = uNS = SNS(t)u0: ∂tu + u · ∇u − ν∆u + ∇p = f, ∇ · u = 0, and incompressible Euler for v = uE = SE(t)u0: ∂tv + v · ∇v + ∇p = f, ∇ · v = 0. Boundary conditions: Navier-Stokes: u| ∂Ω = 0

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SLIDE 5

The equations

Incompressible Navier-Stokes for u = uNS = SNS(t)u0: ∂tu + u · ∇u − ν∆u + ∇p = f, ∇ · u = 0, and incompressible Euler for v = uE = SE(t)u0: ∂tv + v · ∇v + ∇p = f, ∇ · v = 0. Boundary conditions: Navier-Stokes: u| ∂Ω = 0 Euler: v| ∂Ω · n = 0

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SLIDE 6

The equations

Incompressible Navier-Stokes for u = uNS = SNS(t)u0: ∂tu + u · ∇u − ν∆u + ∇p = f, ∇ · u = 0, and incompressible Euler for v = uE = SE(t)u0: ∂tv + v · ∇v + ∇p = f, ∇ · v = 0. Boundary conditions: Navier-Stokes: u| ∂Ω = 0 Euler: v| ∂Ω · n = 0 Reynolds number Re = UL ν

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SLIDE 7

The equations

Incompressible Navier-Stokes for u = uNS = SNS(t)u0: ∂tu + u · ∇u − ν∆u + ∇p = f, ∇ · u = 0, and incompressible Euler for v = uE = SE(t)u0: ∂tv + v · ∇v + ∇p = f, ∇ · v = 0. Boundary conditions: Navier-Stokes: u| ∂Ω = 0 Euler: v| ∂Ω · n = 0 Reynolds number Re = UL ν U = LT −1, L, T length and time scales.

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SLIDE 8

The equations

Incompressible Navier-Stokes for u = uNS = SNS(t)u0: ∂tu + u · ∇u − ν∆u + ∇p = f, ∇ · u = 0, and incompressible Euler for v = uE = SE(t)u0: ∂tv + v · ∇v + ∇p = f, ∇ · v = 0. Boundary conditions: Navier-Stokes: u| ∂Ω = 0 Euler: v| ∂Ω · n = 0 Reynolds number Re = UL ν U = LT −1, L, T length and time scales. ν-kinematic viscosity.

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SLIDE 9

The equations

Incompressible Navier-Stokes for u = uNS = SNS(t)u0: ∂tu + u · ∇u − ν∆u + ∇p = f, ∇ · u = 0, and incompressible Euler for v = uE = SE(t)u0: ∂tv + v · ∇v + ∇p = f, ∇ · v = 0. Boundary conditions: Navier-Stokes: u| ∂Ω = 0 Euler: v| ∂Ω · n = 0 Reynolds number Re = UL ν U = LT −1, L, T length and time scales. ν-kinematic viscosity. Flows with the same Reynolds number = the same behavior.

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SLIDE 10

Energy dissipation

From NSE: ǫ = ν|∇u|2

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SLIDE 11

Energy dissipation

From NSE: ǫ = ν|∇u|2 u = turbulent fluctuation.

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SLIDE 12

Energy dissipation

From NSE: ǫ = ν|∇u|2 u = turbulent fluctuation. Constancy of energy dissipation per unit volume ǫ = C U3 L

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SLIDE 13

Energy dissipation

From NSE: ǫ = ν|∇u|2 u = turbulent fluctuation. Constancy of energy dissipation per unit volume ǫ = C U3 L High Reynolds numbers R ∼ 106 − 109,

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SLIDE 14

Energy dissipation

From NSE: ǫ = ν|∇u|2 u = turbulent fluctuation. Constancy of energy dissipation per unit volume ǫ = C U3 L High Reynolds numbers R ∼ 106 − 109, U = mean-square average velocity, L integral scale.

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SLIDE 15

Energy dissipation

From NSE: ǫ = ν|∇u|2 u = turbulent fluctuation. Constancy of energy dissipation per unit volume ǫ = C U3 L High Reynolds numbers R ∼ 106 − 109, U = mean-square average velocity, L integral scale. Large number of experiments, different situations, large number of numerical experiments:

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SLIDE 16

Energy dissipation

From NSE: ǫ = ν|∇u|2 u = turbulent fluctuation. Constancy of energy dissipation per unit volume ǫ = C U3 L High Reynolds numbers R ∼ 106 − 109, U = mean-square average velocity, L integral scale. Large number of experiments, different situations, large number of numerical experiments: C bounded away from zero and from infinity, C ∈ [.3, 5].

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SLIDE 17

Energy dissipation

From NSE: ǫ = ν|∇u|2 u = turbulent fluctuation. Constancy of energy dissipation per unit volume ǫ = C U3 L High Reynolds numbers R ∼ 106 − 109, U = mean-square average velocity, L integral scale. Large number of experiments, different situations, large number of numerical experiments: C bounded away from zero and from infinity, C ∈ [.3, 5]. Frisch:

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SLIDE 18

Energy dissipation

From NSE: ǫ = ν|∇u|2 u = turbulent fluctuation. Constancy of energy dissipation per unit volume ǫ = C U3 L High Reynolds numbers R ∼ 106 − 109, U = mean-square average velocity, L integral scale. Large number of experiments, different situations, large number of numerical experiments: C bounded away from zero and from infinity, C ∈ [.3, 5]. Frisch: “If, in an experiment on turbulent flow, all the control parameters are kept the same, except for the viscosity, which is lowered as much as possible, the energy dissipation per unit mass dE

dt behaves in a way

consistent with a finite positive limit”

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SLIDE 19

Energy dissipation

From NSE: ǫ = ν|∇u|2 u = turbulent fluctuation. Constancy of energy dissipation per unit volume ǫ = C U3 L High Reynolds numbers R ∼ 106 − 109, U = mean-square average velocity, L integral scale. Large number of experiments, different situations, large number of numerical experiments: C bounded away from zero and from infinity, C ∈ [.3, 5]. Frisch: “If, in an experiment on turbulent flow, all the control parameters are kept the same, except for the viscosity, which is lowered as much as possible, the energy dissipation per unit mass dE

dt behaves in a way

consistent with a finite positive limit”

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SLIDE 20

Two-thirds Law, K’41

Frisch:

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Two-thirds Law, K’41

Frisch: “In a turbulent flow at very high Reynolds number, the mean square velocity increment (δv(ℓ))2 between two points separated by a distance ℓ behaves approximately as the two-thirds power of the distance” (in the inertial range.)

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SLIDE 22

Two-thirds Law, K’41

Frisch: “In a turbulent flow at very high Reynolds number, the mean square velocity increment (δv(ℓ))2 between two points separated by a distance ℓ behaves approximately as the two-thirds power of the distance” (in the inertial range.) |u(x + ℓ) − u(x)|2 ∼ (ǫ|ℓ|)

2 3

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SLIDE 23

Two-thirds Law, K’41

Frisch: “In a turbulent flow at very high Reynolds number, the mean square velocity increment (δv(ℓ))2 between two points separated by a distance ℓ behaves approximately as the two-thirds power of the distance” (in the inertial range.) |u(x + ℓ) − u(x)|2 ∼ (ǫ|ℓ|)

2 3

|ℓ| ≥ ℓd,

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SLIDE 24

Two-thirds Law, K’41

Frisch: “In a turbulent flow at very high Reynolds number, the mean square velocity increment (δv(ℓ))2 between two points separated by a distance ℓ behaves approximately as the two-thirds power of the distance” (in the inertial range.) |u(x + ℓ) − u(x)|2 ∼ (ǫ|ℓ|)

2 3

|ℓ| ≥ ℓd, Kolmogorov spectrum

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SLIDE 25

Two-thirds Law, K’41

Frisch: “In a turbulent flow at very high Reynolds number, the mean square velocity increment (δv(ℓ))2 between two points separated by a distance ℓ behaves approximately as the two-thirds power of the distance” (in the inertial range.) |u(x + ℓ) − u(x)|2 ∼ (ǫ|ℓ|)

2 3

|ℓ| ≥ ℓd, Kolmogorov spectrum E(k) = Cǫ

2 3 k− 5 3

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SLIDE 26

Two-thirds Law, K’41

Frisch: “In a turbulent flow at very high Reynolds number, the mean square velocity increment (δv(ℓ))2 between two points separated by a distance ℓ behaves approximately as the two-thirds power of the distance” (in the inertial range.) |u(x + ℓ) − u(x)|2 ∼ (ǫ|ℓ|)

2 3

|ℓ| ≥ ℓd, Kolmogorov spectrum E(k) = Cǫ

2 3 k− 5 3

k ≤ kd,

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SLIDE 27

Two-thirds Law, K’41

Frisch: “In a turbulent flow at very high Reynolds number, the mean square velocity increment (δv(ℓ))2 between two points separated by a distance ℓ behaves approximately as the two-thirds power of the distance” (in the inertial range.) |u(x + ℓ) − u(x)|2 ∼ (ǫ|ℓ|)

2 3

|ℓ| ≥ ℓd, Kolmogorov spectrum E(k) = Cǫ

2 3 k− 5 3

k ≤ kd, kd = ν3 ǫ − 1

4

= ℓ−1

d

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SLIDE 28

Two-thirds Law, K’41

Frisch: “In a turbulent flow at very high Reynolds number, the mean square velocity increment (δv(ℓ))2 between two points separated by a distance ℓ behaves approximately as the two-thirds power of the distance” (in the inertial range.) |u(x + ℓ) − u(x)|2 ∼ (ǫ|ℓ|)

2 3

|ℓ| ≥ ℓd, Kolmogorov spectrum E(k) = Cǫ

2 3 k− 5 3

k ≤ kd, kd = ν3 ǫ − 1

4

= ℓ−1

d

Four-fifths law: homogeneous and isotropic turbulence, third order longitudinal moment: |u(x + ℓ) − u(x)|3 ∼ ǫ|ℓ|.

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SLIDE 29

Turbulence Questions

Is the energy dissipation ǫ bounded away from zero?

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SLIDE 30

Turbulence Questions

Is the energy dissipation ǫ bounded away from zero? Is the two-thirds law true?

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SLIDE 31

Turbulence Questions

Is the energy dissipation ǫ bounded away from zero? Is the two-thirds law true? four-fifths law?

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SLIDE 32

Turbulence Questions

Is the energy dissipation ǫ bounded away from zero? Is the two-thirds law true? four-fifths law? Are there high Reynolds number universal asymptotics?

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SLIDE 33

Turbulence Questions

Is the energy dissipation ǫ bounded away from zero? Is the two-thirds law true? four-fifths law? Are there high Reynolds number universal asymptotics? Structure functions: |u(x + ℓ) − u(x)|p ∼ (ǫ|ℓ|)

p 3

|ℓ| L αp = CUp |ℓ| L ζp for |ℓ| ≥ ℓd

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SLIDE 34

Turbulence Questions

Is the energy dissipation ǫ bounded away from zero? Is the two-thirds law true? four-fifths law? Are there high Reynolds number universal asymptotics? Structure functions: |u(x + ℓ) − u(x)|p ∼ (ǫ|ℓ|)

p 3

|ℓ| L αp = CUp |ℓ| L ζp for |ℓ| ≥ ℓd αp = intermittency “corrections”.

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SLIDE 35

Turbulence Questions

Is the energy dissipation ǫ bounded away from zero? Is the two-thirds law true? four-fifths law? Are there high Reynolds number universal asymptotics? Structure functions: |u(x + ℓ) − u(x)|p ∼ (ǫ|ℓ|)

p 3

|ℓ| L αp = CUp |ℓ| L ζp for |ℓ| ≥ ℓd αp = intermittency “corrections”. Known rigorously (CF): If scaling, then ζ2 ≥ 2ζ1 ≥ 2

3

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SLIDE 36

Inviscid limit

Infinite time and zero viscosity limits do not commute.

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Inviscid limit

Infinite time and zero viscosity limits do not commute. Time interval fixed. In the absence of boundaries the finite time inviscid limit leads to the initial value problem for Euler equations.

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Inviscid limit

Infinite time and zero viscosity limits do not commute. Time interval fixed. In the absence of boundaries the finite time inviscid limit leads to the initial value problem for Euler equations. Time → ∞ first, only then Reynolds number UL

ν → ∞

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SLIDE 39

Inviscid limit

Infinite time and zero viscosity limits do not commute. Time interval fixed. In the absence of boundaries the finite time inviscid limit leads to the initial value problem for Euler equations. Time → ∞ first, only then Reynolds number UL

ν → ∞

Limits: selected stationary statistical solutions.

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SLIDE 40

Inviscid limit

Infinite time and zero viscosity limits do not commute. Time interval fixed. In the absence of boundaries the finite time inviscid limit leads to the initial value problem for Euler equations. Time → ∞ first, only then Reynolds number UL

ν → ∞

Limits: selected stationary statistical solutions. µ(Φ) = lim

Re→∞ lim T→∞

1 T ˆ T Φ(SNS(t))dt

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SLIDE 41

Finite time, no boundaries

Theorem

(C, ’86) If u0 and T are fixed, but arbitrary, if the solution SE(t; u0) is smooth on [0, T] (e.g. C(0, T; Hs(T3)), s > 5/2), then there exists ν0 = ν0(u0, T) such that S(ν)(t, u0) is smooth on the same time interval for all ν ≤ ν0 and SNS(t)u0 − SE(t)u0s′ = O(ν) s′ < s.

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Finite time, no boundaries

Theorem

(C, ’86) If u0 and T are fixed, but arbitrary, if the solution SE(t; u0) is smooth on [0, T] (e.g. C(0, T; Hs(T3)), s > 5/2), then there exists ν0 = ν0(u0, T) such that S(ν)(t, u0) is smooth on the same time interval for all ν ≤ ν0 and SNS(t)u0 − SE(t)u0s′ = O(ν) s′ < s. A gap (ν0, ν1). Artificial?

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SLIDE 43

Finite time, no boundaries

Theorem

(C, ’86) If u0 and T are fixed, but arbitrary, if the solution SE(t; u0) is smooth on [0, T] (e.g. C(0, T; Hs(T3)), s > 5/2), then there exists ν0 = ν0(u0, T) such that S(ν)(t, u0) is smooth on the same time interval for all ν ≤ ν0 and SNS(t)u0 − SE(t)u0s′ = O(ν) s′ < s. A gap (ν0, ν1). Artificial? Swann’71, Kato ’72: short time. Masmoudi ’06: convergence in top Sobolev space Hs, t < T.

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SLIDE 44

Finite time, no boundaries

Theorem

(C, ’86) If u0 and T are fixed, but arbitrary, if the solution SE(t; u0) is smooth on [0, T] (e.g. C(0, T; Hs(T3)), s > 5/2), then there exists ν0 = ν0(u0, T) such that S(ν)(t, u0) is smooth on the same time interval for all ν ≤ ν0 and SNS(t)u0 − SE(t)u0s′ = O(ν) s′ < s. A gap (ν0, ν1). Artificial? Swann’71, Kato ’72: short time. Masmoudi ’06: convergence in top Sobolev space Hs, t < T. Less smooth initial data: vortex patches (∇ × u0 ∈ L∞ ∩ L1).

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SLIDE 45

Finite time, no boundaries

Theorem

(C, ’86) If u0 and T are fixed, but arbitrary, if the solution SE(t; u0) is smooth on [0, T] (e.g. C(0, T; Hs(T3)), s > 5/2), then there exists ν0 = ν0(u0, T) such that S(ν)(t, u0) is smooth on the same time interval for all ν ≤ ν0 and SNS(t)u0 − SE(t)u0s′ = O(ν) s′ < s. A gap (ν0, ν1). Artificial? Swann’71, Kato ’72: short time. Masmoudi ’06: convergence in top Sobolev space Hs, t < T. Less smooth initial data: vortex patches (∇ × u0 ∈ L∞ ∩ L1). Convergence to Euler still holds but rate deteriorates (C-Wu ’95, Abidi-Danchin ’04, Masmoudi ’06.)

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SLIDE 46

Finite time, no boundaries

Theorem

(C, ’86) If u0 and T are fixed, but arbitrary, if the solution SE(t; u0) is smooth on [0, T] (e.g. C(0, T; Hs(T3)), s > 5/2), then there exists ν0 = ν0(u0, T) such that S(ν)(t, u0) is smooth on the same time interval for all ν ≤ ν0 and SNS(t)u0 − SE(t)u0s′ = O(ν) s′ < s. A gap (ν0, ν1). Artificial? Swann’71, Kato ’72: short time. Masmoudi ’06: convergence in top Sobolev space Hs, t < T. Less smooth initial data: vortex patches (∇ × u0 ∈ L∞ ∩ L1). Convergence to Euler still holds but rate deteriorates (C-Wu ’95, Abidi-Danchin ’04, Masmoudi ’06.) Lions-DiPerna: Any L2 weak limit

  • f NSE is a dissipative solution of Euler.
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SLIDE 47

Onsager Conjecture

Somewhat related to 2/3-law, but finite time IVP for 3D Euler.

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SLIDE 48

Onsager Conjecture

Somewhat related to 2/3-law, but finite time IVP for 3D Euler. Onsager Conjecture: solutions conserve energy if smoother than C

1 3 .

For s < 1

3 there exist Cs solutions for which energy is dissipated.

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SLIDE 49

Onsager Conjecture

Somewhat related to 2/3-law, but finite time IVP for 3D Euler. Onsager Conjecture: solutions conserve energy if smoother than C

1 3 .

For s < 1

3 there exist Cs solutions for which energy is dissipated.

Eyink, C-E-Titi, Duchon-Robert, C-Cheskidov-Friedlander-Shvydkoy: first part. u ∈ L3 dt; B

1 3

∞,c(N)

  • ⇒ E(t) = const
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SLIDE 50

Onsager Conjecture

Somewhat related to 2/3-law, but finite time IVP for 3D Euler. Onsager Conjecture: solutions conserve energy if smoother than C

1 3 .

For s < 1

3 there exist Cs solutions for which energy is dissipated.

Eyink, C-E-Titi, Duchon-Robert, C-Cheskidov-Friedlander-Shvydkoy: first part. u ∈ L3 dt; B

1 3

∞,c(N)

  • ⇒ E(t) = const

Examples of wild Euler solutions: Scheffer: compactly supported in time.

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SLIDE 51

Onsager Conjecture

Somewhat related to 2/3-law, but finite time IVP for 3D Euler. Onsager Conjecture: solutions conserve energy if smoother than C

1 3 .

For s < 1

3 there exist Cs solutions for which energy is dissipated.

Eyink, C-E-Titi, Duchon-Robert, C-Cheskidov-Friedlander-Shvydkoy: first part. u ∈ L3 dt; B

1 3

∞,c(N)

  • ⇒ E(t) = const

Examples of wild Euler solutions: Scheffer: compactly supported in

  • time. Shnirelman: dissipating energy, in L∞(dt; L2).
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SLIDE 52

Onsager Conjecture

Somewhat related to 2/3-law, but finite time IVP for 3D Euler. Onsager Conjecture: solutions conserve energy if smoother than C

1 3 .

For s < 1

3 there exist Cs solutions for which energy is dissipated.

Eyink, C-E-Titi, Duchon-Robert, C-Cheskidov-Friedlander-Shvydkoy: first part. u ∈ L3 dt; B

1 3

∞,c(N)

  • ⇒ E(t) = const

Examples of wild Euler solutions: Scheffer: compactly supported in

  • time. Shnirelman: dissipating energy, in L∞(dt; L2).

DeLellis- Sz´ ekelyhidi, Cs: convex integration, h-principle (Nash, Gromov), Beltrami flows, diminishing Reynolds fluxes. s <

1 10.

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SLIDE 53

Onsager Conjecture

Somewhat related to 2/3-law, but finite time IVP for 3D Euler. Onsager Conjecture: solutions conserve energy if smoother than C

1 3 .

For s < 1

3 there exist Cs solutions for which energy is dissipated.

Eyink, C-E-Titi, Duchon-Robert, C-Cheskidov-Friedlander-Shvydkoy: first part. u ∈ L3 dt; B

1 3

∞,c(N)

  • ⇒ E(t) = const

Examples of wild Euler solutions: Scheffer: compactly supported in

  • time. Shnirelman: dissipating energy, in L∞(dt; L2).

DeLellis- Sz´ ekelyhidi, Cs: convex integration, h-principle (Nash, Gromov), Beltrami flows, diminishing Reynolds fluxes. s <

1 10.

Isett, C

1 5+ : Material (Lagrangian) derivative better behaved than time

derivative, nonlinear phases.

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SLIDE 54

Onsager Conjecture

Somewhat related to 2/3-law, but finite time IVP for 3D Euler. Onsager Conjecture: solutions conserve energy if smoother than C

1 3 .

For s < 1

3 there exist Cs solutions for which energy is dissipated.

Eyink, C-E-Titi, Duchon-Robert, C-Cheskidov-Friedlander-Shvydkoy: first part. u ∈ L3 dt; B

1 3

∞,c(N)

  • ⇒ E(t) = const

Examples of wild Euler solutions: Scheffer: compactly supported in

  • time. Shnirelman: dissipating energy, in L∞(dt; L2).

DeLellis- Sz´ ekelyhidi, Cs: convex integration, h-principle (Nash, Gromov), Beltrami flows, diminishing Reynolds fluxes. s <

1 10.

Isett, C

1 5+ : Material (Lagrangian) derivative better behaved than time

derivative, nonlinear phases. Buckmaster, De Lellis, Sz´ ekelyhidi: L1(0, T; C

1 3 ). More careful

accounting.

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SLIDE 55

Onsager Conjecture

Somewhat related to 2/3-law, but finite time IVP for 3D Euler. Onsager Conjecture: solutions conserve energy if smoother than C

1 3 .

For s < 1

3 there exist Cs solutions for which energy is dissipated.

Eyink, C-E-Titi, Duchon-Robert, C-Cheskidov-Friedlander-Shvydkoy: first part. u ∈ L3 dt; B

1 3

∞,c(N)

  • ⇒ E(t) = const

Examples of wild Euler solutions: Scheffer: compactly supported in

  • time. Shnirelman: dissipating energy, in L∞(dt; L2).

DeLellis- Sz´ ekelyhidi, Cs: convex integration, h-principle (Nash, Gromov), Beltrami flows, diminishing Reynolds fluxes. s <

1 10.

Isett, C

1 5+ : Material (Lagrangian) derivative better behaved than time

derivative, nonlinear phases. Buckmaster, De Lellis, Sz´ ekelyhidi: L1(0, T; C

1 3 ). More careful

accounting. Isett C

1 3+ : gluing, Mikado flows.

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SLIDE 56

Onsager Conjecture

Somewhat related to 2/3-law, but finite time IVP for 3D Euler. Onsager Conjecture: solutions conserve energy if smoother than C

1 3 .

For s < 1

3 there exist Cs solutions for which energy is dissipated.

Eyink, C-E-Titi, Duchon-Robert, C-Cheskidov-Friedlander-Shvydkoy: first part. u ∈ L3 dt; B

1 3

∞,c(N)

  • ⇒ E(t) = const

Examples of wild Euler solutions: Scheffer: compactly supported in

  • time. Shnirelman: dissipating energy, in L∞(dt; L2).

DeLellis- Sz´ ekelyhidi, Cs: convex integration, h-principle (Nash, Gromov), Beltrami flows, diminishing Reynolds fluxes. s <

1 10.

Isett, C

1 5+ : Material (Lagrangian) derivative better behaved than time

derivative, nonlinear phases. Buckmaster, De Lellis, Sz´ ekelyhidi: L1(0, T; C

1 3 ). More careful

accounting. Isett C

1 3+ : gluing, Mikado flows.

Buckmaster, De Lellis, Sz´ ekelyhidi, Vicol: dissipative.

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SLIDE 57

Long time, no boundaries

No results for 3d NS/Euler.

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SLIDE 58

Long time, no boundaries

No results for 3d NS/Euler. 2DNS No anomalous dissipation of energy: ∇u2

L2 bounded in time uniformly in ν.

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SLIDE 59

Long time, no boundaries

No results for 3d NS/Euler. 2DNS No anomalous dissipation of energy: ∇u2

L2 bounded in time uniformly in ν.

Vorticity: ω = ∇⊥ · u

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SLIDE 60

Long time, no boundaries

No results for 3d NS/Euler. 2DNS No anomalous dissipation of energy: ∇u2

L2 bounded in time uniformly in ν.

Vorticity: ω = ∇⊥ · u ∂tω + u · ∇ω − ν∆ω = ∇⊥ · f = g

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SLIDE 61

Long time, no boundaries

No results for 3d NS/Euler. 2DNS No anomalous dissipation of energy: ∇u2

L2 bounded in time uniformly in ν.

Vorticity: ω = ∇⊥ · u ∂tω + u · ∇ω − ν∆ω = ∇⊥ · f = g Enstrophy balance: d 2dt ˆ

R2 |ω(x, t)|2dx + ν

ˆ

R2 |∇ω(x, t)|2dx =

ˆ

R2 gωdx

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SLIDE 62

Long time, no boundaries

No results for 3d NS/Euler. 2DNS No anomalous dissipation of energy: ∇u2

L2 bounded in time uniformly in ν.

Vorticity: ω = ∇⊥ · u ∂tω + u · ∇ω − ν∆ω = ∇⊥ · f = g Enstrophy balance: d 2dt ˆ

R2 |ω(x, t)|2dx + ν

ˆ

R2 |∇ω(x, t)|2dx =

ˆ

R2 gωdx

Anomalous dissipation of enstrophy?

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SLIDE 63

Long time, no boundaries

No results for 3d NS/Euler. 2DNS No anomalous dissipation of energy: ∇u2

L2 bounded in time uniformly in ν.

Vorticity: ω = ∇⊥ · u ∂tω + u · ∇ω − ν∆ω = ∇⊥ · f = g Enstrophy balance: d 2dt ˆ

R2 |ω(x, t)|2dx + ν

ˆ

R2 |∇ω(x, t)|2dx =

ˆ

R2 gωdx

Anomalous dissipation of enstrophy? lim

ν→0 ν∇ω2 L2 = χ > 0

slide-64
SLIDE 64

Long time, no boundaries

No results for 3d NS/Euler. 2DNS No anomalous dissipation of energy: ∇u2

L2 bounded in time uniformly in ν.

Vorticity: ω = ∇⊥ · u ∂tω + u · ∇ω − ν∆ω = ∇⊥ · f = g Enstrophy balance: d 2dt ˆ

R2 |ω(x, t)|2dx + ν

ˆ

R2 |∇ω(x, t)|2dx =

ˆ

R2 gωdx

Anomalous dissipation of enstrophy? lim

ν→0 ν∇ω2 L2 = χ > 0

Kraichnan (’68): yes,

slide-65
SLIDE 65

Long time, no boundaries

No results for 3d NS/Euler. 2DNS No anomalous dissipation of energy: ∇u2

L2 bounded in time uniformly in ν.

Vorticity: ω = ∇⊥ · u ∂tω + u · ∇ω − ν∆ω = ∇⊥ · f = g Enstrophy balance: d 2dt ˆ

R2 |ω(x, t)|2dx + ν

ˆ

R2 |∇ω(x, t)|2dx =

ˆ

R2 gωdx

Anomalous dissipation of enstrophy? lim

ν→0 ν∇ω2 L2 = χ > 0

Kraichnan (’68): yes, Bernard (’00): add damping, and then no.

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SLIDE 66

Absence of anomalous dissipation

C-Ramos ’07: If you add damping ut + γu + νAu + B(u, u) = f then there is no anomalous dissipation of enstrophy: lim

ν→0 lim sup T→∞

ν T ˆ T ˆ

  • ∇ω(ν)(x, t)
  • 2

dxdt = 0

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SLIDE 67

Absence of anomalous dissipation

C-Ramos ’07: If you add damping ut + γu + νAu + B(u, u) = f then there is no anomalous dissipation of enstrophy: lim

ν→0 lim sup T→∞

ν T ˆ T ˆ

  • ∇ω(ν)(x, t)
  • 2

dxdt = 0 C-Tarfulea-Vicol ’13. No anomalous dissipation of energy in critical SQG.

slide-68
SLIDE 68

Absence of anomalous dissipation

C-Ramos ’07: If you add damping ut + γu + νAu + B(u, u) = f then there is no anomalous dissipation of enstrophy: lim

ν→0 lim sup T→∞

ν T ˆ T ˆ

  • ∇ω(ν)(x, t)
  • 2

dxdt = 0 C-Tarfulea-Vicol ’13. No anomalous dissipation of energy in critical

  • SQG. Method of proof: statistical solutions.
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SLIDE 69

Long time, undamped

Gallet-Young (’13): “Condensate” in 2D periodic, undamped forced by Kolmogorov forcing.

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SLIDE 70

Long time, undamped

Gallet-Young (’13): “Condensate” in 2D periodic, undamped forced by Kolmogorov forcing. Inverse cascade.

slide-71
SLIDE 71

Long time, undamped

Gallet-Young (’13): “Condensate” in 2D periodic, undamped forced by Kolmogorov forcing. Inverse cascade. Numerical, “semi-analytical”.

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SLIDE 72

Long time, undamped

Gallet-Young (’13): “Condensate” in 2D periodic, undamped forced by Kolmogorov forcing. Inverse cascade. Numerical, “semi-analytical”. And wrong for some solutions.

slide-73
SLIDE 73

Long time, undamped

Gallet-Young (’13): “Condensate” in 2D periodic, undamped forced by Kolmogorov forcing. Inverse cascade. Numerical, “semi-analytical”. And wrong for some solutions. Kolmogorov forcing: Af = λf.

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SLIDE 74

Long time, undamped

Gallet-Young (’13): “Condensate” in 2D periodic, undamped forced by Kolmogorov forcing. Inverse cascade. Numerical, “semi-analytical”. And wrong for some solutions. Kolmogorov forcing: Af = λf. Exact solutions u(t) = y(t)f. Navier-Stokes: y(t) = y0e−νλt + 1 νλ

  • 1 − e−νλt
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SLIDE 75

Long time, undamped

Gallet-Young (’13): “Condensate” in 2D periodic, undamped forced by Kolmogorov forcing. Inverse cascade. Numerical, “semi-analytical”. And wrong for some solutions. Kolmogorov forcing: Af = λf. Exact solutions u(t) = y(t)f. Navier-Stokes: y(t) = y0e−νλt + 1 νλ

  • 1 − e−νλt

Euler: y(t) = y0 + t

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SLIDE 76

Long time, undamped

Gallet-Young (’13): “Condensate” in 2D periodic, undamped forced by Kolmogorov forcing. Inverse cascade. Numerical, “semi-analytical”. And wrong for some solutions. Kolmogorov forcing: Af = λf. Exact solutions u(t) = y(t)f. Navier-Stokes: y(t) = y0e−νλt + 1 νλ

  • 1 − e−νλt

Euler: y(t) = y0 + t Any finite t:

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SLIDE 77

Long time, undamped

Gallet-Young (’13): “Condensate” in 2D periodic, undamped forced by Kolmogorov forcing. Inverse cascade. Numerical, “semi-analytical”. And wrong for some solutions. Kolmogorov forcing: Af = λf. Exact solutions u(t) = y(t)f. Navier-Stokes: y(t) = y0e−νλt + 1 νλ

  • 1 − e−νλt

Euler: y(t) = y0 + t Any finite t: SNS(t)u0 → SE(t)u0.

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SLIDE 78

Long time, undamped

Gallet-Young (’13): “Condensate” in 2D periodic, undamped forced by Kolmogorov forcing. Inverse cascade. Numerical, “semi-analytical”. And wrong for some solutions. Kolmogorov forcing: Af = λf. Exact solutions u(t) = y(t)f. Navier-Stokes: y(t) = y0e−νλt + 1 νλ

  • 1 − e−νλt

Euler: y(t) = y0 + t Any finite t: SNS(t)u0 → SE(t)u0. Solution bounded in ν, locally in time.

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SLIDE 79

Long time, undamped

Gallet-Young (’13): “Condensate” in 2D periodic, undamped forced by Kolmogorov forcing. Inverse cascade. Numerical, “semi-analytical”. And wrong for some solutions. Kolmogorov forcing: Af = λf. Exact solutions u(t) = y(t)f. Navier-Stokes: y(t) = y0e−νλt + 1 νλ

  • 1 − e−νλt

Euler: y(t) = y0 + t Any finite t: SNS(t)u0 → SE(t)u0. Solution bounded in ν, locally in

  • time. But: t → ∞: u(t) → uf =

1 νλf

νAuf = f, B(uf, uf) = 0 Unbounded.

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SLIDE 80

Long time, undamped

Gallet-Young (’13): “Condensate” in 2D periodic, undamped forced by Kolmogorov forcing. Inverse cascade. Numerical, “semi-analytical”. And wrong for some solutions. Kolmogorov forcing: Af = λf. Exact solutions u(t) = y(t)f. Navier-Stokes: y(t) = y0e−νλt + 1 νλ

  • 1 − e−νλt

Euler: y(t) = y0 + t Any finite t: SNS(t)u0 → SE(t)u0. Solution bounded in ν, locally in

  • time. But: t → ∞: u(t) → uf =

1 νλf

νAuf = f, B(uf, uf) = 0

  • Unbounded. Forgets initial data.
slide-81
SLIDE 81

Long time, undamped

Gallet-Young (’13): “Condensate” in 2D periodic, undamped forced by Kolmogorov forcing. Inverse cascade. Numerical, “semi-analytical”. And wrong for some solutions. Kolmogorov forcing: Af = λf. Exact solutions u(t) = y(t)f. Navier-Stokes: y(t) = y0e−νλt + 1 νλ

  • 1 − e−νλt

Euler: y(t) = y0 + t Any finite t: SNS(t)u0 → SE(t)u0. Solution bounded in ν, locally in

  • time. But: t → ∞: u(t) → uf =

1 νλf

νAuf = f, B(uf, uf) = 0

  • Unbounded. Forgets initial data.

Same true with Dirichlet BC (f = sin nx sin my).

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SLIDE 82

Long time, undamped

Gallet-Young (’13): “Condensate” in 2D periodic, undamped forced by Kolmogorov forcing. Inverse cascade. Numerical, “semi-analytical”. And wrong for some solutions. Kolmogorov forcing: Af = λf. Exact solutions u(t) = y(t)f. Navier-Stokes: y(t) = y0e−νλt + 1 νλ

  • 1 − e−νλt

Euler: y(t) = y0 + t Any finite t: SNS(t)u0 → SE(t)u0. Solution bounded in ν, locally in

  • time. But: t → ∞: u(t) → uf =

1 νλf

νAuf = f, B(uf, uf) = 0

  • Unbounded. Forgets initial data.

Same true with Dirichlet BC (f = sin nx sin my). Open problem: construct example of f so that a stationary condensate exists.

slide-83
SLIDE 83

Long time, undamped

Gallet-Young (’13): “Condensate” in 2D periodic, undamped forced by Kolmogorov forcing. Inverse cascade. Numerical, “semi-analytical”. And wrong for some solutions. Kolmogorov forcing: Af = λf. Exact solutions u(t) = y(t)f. Navier-Stokes: y(t) = y0e−νλt + 1 νλ

  • 1 − e−νλt

Euler: y(t) = y0 + t Any finite t: SNS(t)u0 → SE(t)u0. Solution bounded in ν, locally in

  • time. But: t → ∞: u(t) → uf =

1 νλf

νAuf = f, B(uf, uf) = 0

  • Unbounded. Forgets initial data.

Same true with Dirichlet BC (f = sin nx sin my). Open problem: construct example of f so that a stationary condensate exists. B(uE, uE) = f is easily solvable.

slide-84
SLIDE 84

Long time, undamped

Gallet-Young (’13): “Condensate” in 2D periodic, undamped forced by Kolmogorov forcing. Inverse cascade. Numerical, “semi-analytical”. And wrong for some solutions. Kolmogorov forcing: Af = λf. Exact solutions u(t) = y(t)f. Navier-Stokes: y(t) = y0e−νλt + 1 νλ

  • 1 − e−νλt

Euler: y(t) = y0 + t Any finite t: SNS(t)u0 → SE(t)u0. Solution bounded in ν, locally in

  • time. But: t → ∞: u(t) → uf =

1 νλf

νAuf = f, B(uf, uf) = 0

  • Unbounded. Forgets initial data.

Same true with Dirichlet BC (f = sin nx sin my). Open problem: construct example of f so that a stationary condensate exists. B(uE, uE) = f is easily solvable. Can any steadily forced undamped Navier-Stokes solutions remain bounded for all time as viscosity is removed?

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SLIDE 85

Basic Questions

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SLIDE 86

Basic Questions

◮ How does the 2D inverse cascade work? Does deterministic 3D

eddy diffusity exist? (i.e. can B(u, u) provide average friction at low wave numbers in 2D, at high wave numbers in 3D?).

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SLIDE 87

Basic Questions

◮ How does the 2D inverse cascade work? Does deterministic 3D

eddy diffusity exist? (i.e. can B(u, u) provide average friction at low wave numbers in 2D, at high wave numbers in 3D?).

◮ Is there a well defined (weak) inviscid limit, when energy

dissipation rate does not necessarily vanish?

slide-88
SLIDE 88

Finite time, with boundaries: known results

Inviscid limit: same initial data, fixed time, smooth domain. uNS → uE inside the domain.

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SLIDE 89

Finite time, with boundaries: known results

Inviscid limit: same initial data, fixed time, smooth domain. uNS → uE inside the domain. Weakly.

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SLIDE 90

Finite time, with boundaries: known results

Inviscid limit: same initial data, fixed time, smooth domain. uNS → uE inside the domain. Weakly. Or better.

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SLIDE 91

Finite time, with boundaries: known results

Inviscid limit: same initial data, fixed time, smooth domain. uNS → uE inside the domain. Weakly. Or better. Kato 84: If (and oly if) dissipation ν ˆ

BL(ν)

|∇u|2dx → 0 then the finite time inviscid limit holds in strong L2.

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SLIDE 92

Finite time, with boundaries: known results

Inviscid limit: same initial data, fixed time, smooth domain. uNS → uE inside the domain. Weakly. Or better. Kato 84: If (and oly if) dissipation ν ˆ

BL(ν)

|∇u|2dx → 0 then the finite time inviscid limit holds in strong L2. Energy dissipation rate ν ´ T ´

Ω |∇u|2dxdt vanishes

slide-93
SLIDE 93

Finite time, with boundaries: known results

Inviscid limit: same initial data, fixed time, smooth domain. uNS → uE inside the domain. Weakly. Or better. Kato 84: If (and oly if) dissipation ν ˆ

BL(ν)

|∇u|2dx → 0 then the finite time inviscid limit holds in strong L2. Energy dissipation rate ν ´ T ´

Ω |∇u|2dxdt vanishes

Here BL : {x ∈ Ω | dist(x, ∂Ω) ≤ O(ν)} Assumed: smooth regime, smooth boundary. Method: corrector.

slide-94
SLIDE 94

Finite time, with boundaries: known results

Inviscid limit: same initial data, fixed time, smooth domain. uNS → uE inside the domain. Weakly. Or better. Kato 84: If (and oly if) dissipation ν ˆ

BL(ν)

|∇u|2dx → 0 then the finite time inviscid limit holds in strong L2. Energy dissipation rate ν ´ T ´

Ω |∇u|2dxdt vanishes

Here BL : {x ∈ Ω | dist(x, ∂Ω) ≤ O(ν)} Assumed: smooth regime, smooth boundary. Method: corrector. Improvements: only tangential gradient in slightly thicker boundary layer (Temam-Wang ’97, Wang ’01).

slide-95
SLIDE 95

Finite time, with boundaries: known results

Inviscid limit: same initial data, fixed time, smooth domain. uNS → uE inside the domain. Weakly. Or better. Kato 84: If (and oly if) dissipation ν ˆ

BL(ν)

|∇u|2dx → 0 then the finite time inviscid limit holds in strong L2. Energy dissipation rate ν ´ T ´

Ω |∇u|2dxdt vanishes

Here BL : {x ∈ Ω | dist(x, ∂Ω) ≤ O(ν)} Assumed: smooth regime, smooth boundary. Method: corrector. Improvements: only tangential gradient in slightly thicker boundary layer (Temam-Wang ’97, Wang ’01). Inviscid unconditionally: only for very short time and real analytic data (Caflisch-Sammartino ’98), vorticity supported away from the boundary ( Maekawa ’14) and restrictive symmetries (Lopes Filho-Mazzucato-Nussenzveig-Lopes-M. Taylor,’08, Kelliher ’09).

slide-96
SLIDE 96

Finite time, with boundaries: known results

Inviscid limit: same initial data, fixed time, smooth domain. uNS → uE inside the domain. Weakly. Or better. Kato 84: If (and oly if) dissipation ν ˆ

BL(ν)

|∇u|2dx → 0 then the finite time inviscid limit holds in strong L2. Energy dissipation rate ν ´ T ´

Ω |∇u|2dxdt vanishes

Here BL : {x ∈ Ω | dist(x, ∂Ω) ≤ O(ν)} Assumed: smooth regime, smooth boundary. Method: corrector. Improvements: only tangential gradient in slightly thicker boundary layer (Temam-Wang ’97, Wang ’01). Inviscid unconditionally: only for very short time and real analytic data (Caflisch-Sammartino ’98), vorticity supported away from the boundary ( Maekawa ’14) and restrictive symmetries (Lopes Filho-Mazzucato-Nussenzveig-Lopes-M. Taylor,’08, Kelliher ’09). All results: rate of dissipation vanishes.

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SLIDE 97

Prandtl

Prandtl: u(x) = v(x)1{dist(x,∂Ω)>√ν} + uP1{dist(x,∂Ω)<√ν} + O(√ν). and uP solves Prandtl equations. Note that Kato’s BL is much smaller.

slide-98
SLIDE 98

Prandtl

Prandtl: u(x) = v(x)1{dist(x,∂Ω)>√ν} + uP1{dist(x,∂Ω)<√ν} + O(√ν). and uP solves Prandtl equations. Note that Kato’s BL is much smaller. Prandtl are ill posed (Gerard-Varet-Dormy ’10, Guo-Nguyen ’11, Gerard-Varet-Nguyen ’12),

slide-99
SLIDE 99

Prandtl

Prandtl: u(x) = v(x)1{dist(x,∂Ω)>√ν} + uP1{dist(x,∂Ω)<√ν} + O(√ν). and uP solves Prandtl equations. Note that Kato’s BL is much smaller. Prandtl are ill posed (Gerard-Varet-Dormy ’10, Guo-Nguyen ’11, Gerard-Varet-Nguyen ’12), the expansion is not valid (Grenier ’00, Grenier-Guo-Nguyen ’14)

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SLIDE 100

Prandtl

Prandtl: u(x) = v(x)1{dist(x,∂Ω)>√ν} + uP1{dist(x,∂Ω)<√ν} + O(√ν). and uP solves Prandtl equations. Note that Kato’s BL is much smaller. Prandtl are ill posed (Gerard-Varet-Dormy ’10, Guo-Nguyen ’11, Gerard-Varet-Nguyen ’12), the expansion is not valid (Grenier ’00, Grenier-Guo-Nguyen ’14) and the equations blow up (E-Engquist ’97, Kukavica-Vicol-Wang ’16).

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SLIDE 101

Prandtl

Prandtl: u(x) = v(x)1{dist(x,∂Ω)>√ν} + uP1{dist(x,∂Ω)<√ν} + O(√ν). and uP solves Prandtl equations. Note that Kato’s BL is much smaller. Prandtl are ill posed (Gerard-Varet-Dormy ’10, Guo-Nguyen ’11, Gerard-Varet-Nguyen ’12), the expansion is not valid (Grenier ’00, Grenier-Guo-Nguyen ’14) and the equations blow up (E-Engquist ’97, Kukavica-Vicol-Wang ’16). Prandtl are well posed if

◮ If there is no turning point of the Euler flow on the boundary, and

if the initial vorticity is bounded below by a positive constant. Oleinik ’66, Masmoudi-Wong in Sobolev space, ’12.

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SLIDE 102

Prandtl

Prandtl: u(x) = v(x)1{dist(x,∂Ω)>√ν} + uP1{dist(x,∂Ω)<√ν} + O(√ν). and uP solves Prandtl equations. Note that Kato’s BL is much smaller. Prandtl are ill posed (Gerard-Varet-Dormy ’10, Guo-Nguyen ’11, Gerard-Varet-Nguyen ’12), the expansion is not valid (Grenier ’00, Grenier-Guo-Nguyen ’14) and the equations blow up (E-Engquist ’97, Kukavica-Vicol-Wang ’16). Prandtl are well posed if

◮ If there is no turning point of the Euler flow on the boundary, and

if the initial vorticity is bounded below by a positive constant. Oleinik ’66, Masmoudi-Wong in Sobolev space, ’12.

◮ If the initial velocity is real analytic in all variables.

Sammartino-Caflisch ’98.

slide-103
SLIDE 103

Prandtl

Prandtl: u(x) = v(x)1{dist(x,∂Ω)>√ν} + uP1{dist(x,∂Ω)<√ν} + O(√ν). and uP solves Prandtl equations. Note that Kato’s BL is much smaller. Prandtl are ill posed (Gerard-Varet-Dormy ’10, Guo-Nguyen ’11, Gerard-Varet-Nguyen ’12), the expansion is not valid (Grenier ’00, Grenier-Guo-Nguyen ’14) and the equations blow up (E-Engquist ’97, Kukavica-Vicol-Wang ’16). Prandtl are well posed if

◮ If there is no turning point of the Euler flow on the boundary, and

if the initial vorticity is bounded below by a positive constant. Oleinik ’66, Masmoudi-Wong in Sobolev space, ’12.

◮ If the initial velocity is real analytic in all variables.

Sammartino-Caflisch ’98.

◮ If the initial velocity is real analytic with respect to tangential

variables, smooth transversally. Cannone, Lombardo, Sammartino ’01, Kukavica, Vicol ’13.

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SLIDE 104

Prandtl

Prandtl: u(x) = v(x)1{dist(x,∂Ω)>√ν} + uP1{dist(x,∂Ω)<√ν} + O(√ν). and uP solves Prandtl equations. Note that Kato’s BL is much smaller. Prandtl are ill posed (Gerard-Varet-Dormy ’10, Guo-Nguyen ’11, Gerard-Varet-Nguyen ’12), the expansion is not valid (Grenier ’00, Grenier-Guo-Nguyen ’14) and the equations blow up (E-Engquist ’97, Kukavica-Vicol-Wang ’16). Prandtl are well posed if

◮ If there is no turning point of the Euler flow on the boundary, and

if the initial vorticity is bounded below by a positive constant. Oleinik ’66, Masmoudi-Wong in Sobolev space, ’12.

◮ If the initial velocity is real analytic in all variables.

Sammartino-Caflisch ’98.

◮ If the initial velocity is real analytic with respect to tangential

variables, smooth transversally. Cannone, Lombardo, Sammartino ’01, Kukavica, Vicol ’13.

◮ If the initial vorticity has a single curve of nondegenerate critical

points and it is Gevrey 7

4 in the tangential directions, smooth

  • transversally. G´

erard-Varet, Masmoudi ’13.

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SLIDE 105

Set up, half space

The domain Ω = {(x1, x2) | x1 ∈ R, x2 > 0}. The Euler solution v = v(x1, x2, t) is assumed to be smooth, bounded and Hs, s > 2.

slide-106
SLIDE 106

Set up, half space

The domain Ω = {(x1, x2) | x1 ∈ R, x2 > 0}. The Euler solution v = v(x1, x2, t) is assumed to be smooth, bounded and Hs, s > 2. The restriction of the tangential component

  • f the Euler solution to the boundary is denoted U:

v1(x1, x2, t) = U(x1, t).

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SLIDE 107

Set up, half space

The domain Ω = {(x1, x2) | x1 ∈ R, x2 > 0}. The Euler solution v = v(x1, x2, t) is assumed to be smooth, bounded and Hs, s > 2. The restriction of the tangential component

  • f the Euler solution to the boundary is denoted U:

v1(x1, x2, t) = U(x1, t). The Navier-Stokes solution is u ∈ Hs. Vorticity of the NS solution is ω: ω(x1, x2, t) = ∂1u2(x1, x2, t) − ∂2u1(x1, x2, t)

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SLIDE 108

Set up, half space

The domain Ω = {(x1, x2) | x1 ∈ R, x2 > 0}. The Euler solution v = v(x1, x2, t) is assumed to be smooth, bounded and Hs, s > 2. The restriction of the tangential component

  • f the Euler solution to the boundary is denoted U:

v1(x1, x2, t) = U(x1, t). The Navier-Stokes solution is u ∈ Hs. Vorticity of the NS solution is ω: ω(x1, x2, t) = ∂1u2(x1, x2, t) − ∂2u1(x1, x2, t) The initial data for both u and v are the same: u(x1, x2, 0) = v(x1, x2, 0) = u0(x1, x2).

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SLIDE 109

Set up, half space

The domain Ω = {(x1, x2) | x1 ∈ R, x2 > 0}. The Euler solution v = v(x1, x2, t) is assumed to be smooth, bounded and Hs, s > 2. The restriction of the tangential component

  • f the Euler solution to the boundary is denoted U:

v1(x1, x2, t) = U(x1, t). The Navier-Stokes solution is u ∈ Hs. Vorticity of the NS solution is ω: ω(x1, x2, t) = ∂1u2(x1, x2, t) − ∂2u1(x1, x2, t) The initial data for both u and v are the same: u(x1, x2, 0) = v(x1, x2, 0) = u0(x1, x2). The boundary conditions are thus u| x2=0 = 0, v2| x2=0 = 0, v1| x2=0 = U(x1, t)

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SLIDE 110

Result CKV (Kukavica, Vicol, C)

Theorem

(CKV ’14) Asume: U(x1, t) ≥ 0,

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SLIDE 111

Result CKV (Kukavica, Vicol, C)

Theorem

(CKV ’14) Asume: U(x1, t) ≥ 0, and lim

ν→0

ˆ T Dτ,βdt = 0,

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SLIDE 112

Result CKV (Kukavica, Vicol, C)

Theorem

(CKV ’14) Asume: U(x1, t) ≥ 0, and lim

ν→0

ˆ T Dτ,βdt = 0, with Dτ,β = ν ˆ

x2<β

|ωτ|2dx,

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SLIDE 113

Result CKV (Kukavica, Vicol, C)

Theorem

(CKV ’14) Asume: U(x1, t) ≥ 0, and lim

ν→0

ˆ T Dτ,βdt = 0, with Dτ,β = ν ˆ

x2<β

|ωτ|2dx, ωτ = min{ω + 1 τ ; 0}

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SLIDE 114

Result CKV (Kukavica, Vicol, C)

Theorem

(CKV ’14) Asume: U(x1, t) ≥ 0, and lim

ν→0

ˆ T Dτ,βdt = 0, with Dτ,β = ν ˆ

x2<β

|ωτ|2dx, ωτ = min{ω + 1 τ ; 0} and lim

ν→0 ν

ˆ T 1 τ dt = 0, lim

ν→0

β ν = ∞.

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SLIDE 115

Result CKV (Kukavica, Vicol, C)

Theorem

(CKV ’14) Asume: U(x1, t) ≥ 0, and lim

ν→0

ˆ T Dτ,βdt = 0, with Dτ,β = ν ˆ

x2<β

|ωτ|2dx, ωτ = min{ω + 1 τ ; 0} and lim

ν→0 ν

ˆ T 1 τ dt = 0, lim

ν→0

β ν = ∞. Then lim

ν→0 sup t≤T

u(t) − v(t)L2 = 0.

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SLIDE 116

Remarks

◮ Motivation: Oleinik’s sign condition, to give a one-sided Kato

condition for inviscid limit when Prandtl is well-posed.

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SLIDE 117

Remarks

◮ Motivation: Oleinik’s sign condition, to give a one-sided Kato

condition for inviscid limit when Prandtl is well-posed.

◮ Result works in bounded domains with smooth boundaries.

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SLIDE 118

Remarks

◮ Motivation: Oleinik’s sign condition, to give a one-sided Kato

condition for inviscid limit when Prandtl is well-posed.

◮ Result works in bounded domains with smooth boundaries. ◮ Uses better corrector, with sign condition.

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SLIDE 119

Remarks

◮ Motivation: Oleinik’s sign condition, to give a one-sided Kato

condition for inviscid limit when Prandtl is well-posed.

◮ Result works in bounded domains with smooth boundaries. ◮ Uses better corrector, with sign condition. ◮ Condition on viscous flow is satisfied by viscous shear flow,

(eνt∂yy v(y), 0), v(0) = 0, v′(y) ≤ 0.

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SLIDE 120

Remarks

◮ Motivation: Oleinik’s sign condition, to give a one-sided Kato

condition for inviscid limit when Prandtl is well-posed.

◮ Result works in bounded domains with smooth boundaries. ◮ Uses better corrector, with sign condition. ◮ Condition on viscous flow is satisfied by viscous shear flow,

(eνt∂yy v(y), 0), v(0) = 0, v′(y) ≤ 0.

◮ Condition U ≥ 0 persists for short time from ID.

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SLIDE 121

Remarks

◮ Motivation: Oleinik’s sign condition, to give a one-sided Kato

condition for inviscid limit when Prandtl is well-posed.

◮ Result works in bounded domains with smooth boundaries. ◮ Uses better corrector, with sign condition. ◮ Condition on viscous flow is satisfied by viscous shear flow,

(eνt∂yy v(y), 0), v(0) = 0, v′(y) ≤ 0.

◮ Condition U ≥ 0 persists for short time from ID. ◮ In particular, U ≥ 0, ω ≥ − 1 ν1−0 in x2 < ν1−0 implies

u − vL2 → 0.

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SLIDE 122

Remarks

◮ Motivation: Oleinik’s sign condition, to give a one-sided Kato

condition for inviscid limit when Prandtl is well-posed.

◮ Result works in bounded domains with smooth boundaries. ◮ Uses better corrector, with sign condition. ◮ Condition on viscous flow is satisfied by viscous shear flow,

(eνt∂yy v(y), 0), v(0) = 0, v′(y) ≤ 0.

◮ Condition U ≥ 0 persists for short time from ID. ◮ In particular, U ≥ 0, ω ≥ − 1 ν1−0 in x2 < ν1−0 implies

u − vL2 → 0.

◮ Bardos-Titi (’13) : if νωNS = ν∂2u1 → 0 on boundary.

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SLIDE 123

Result CEIV (Elgindi, Ignatova, Vicol, C)

Theorem

(CEIV ’15) Assume u1u2 equicontinuous at x2 = 0: ∃γ(x1, t) ∈ L1(dx1dt), such that

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SLIDE 124

Result CEIV (Elgindi, Ignatova, Vicol, C)

Theorem

(CEIV ’15) Assume u1u2 equicontinuous at x2 = 0: ∃γ(x1, t) ∈ L1(dx1dt), such that ∀ǫ > 0 ∃ρ(ǫ) > 0, |u1(x1, y, t)u2(x1, y, t)| ≤ ǫγ(x1, t), ∀|y| ≤ ρ(ǫ), x1, t.

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SLIDE 125

Result CEIV (Elgindi, Ignatova, Vicol, C)

Theorem

(CEIV ’15) Assume u1u2 equicontinuous at x2 = 0: ∃γ(x1, t) ∈ L1(dx1dt), such that ∀ǫ > 0 ∃ρ(ǫ) > 0, |u1(x1, y, t)u2(x1, y, t)| ≤ ǫγ(x1, t), ∀|y| ≤ ρ(ǫ), x1, t. Then lim

ν→0 sup 0≤t≤T

u(t) − v(t)L2 = 0.

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SLIDE 126

Corollary CEIV

Corollary

Assume sup

0<ν≤ν0

ˆ T u2

L∞dt ≤ C

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SLIDE 127

Corollary CEIV

Corollary

Assume sup

0<ν≤ν0

ˆ T u2

L∞dt ≤ C

and ∂1u1 uniformly integrable near x2 = 0:

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SLIDE 128

Corollary CEIV

Corollary

Assume sup

0<ν≤ν0

ˆ T u2

L∞dt ≤ C

and ∂1u1 uniformly integrable near x2 = 0: ∀ǫ > 0, ∀L > 0,

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SLIDE 129

Corollary CEIV

Corollary

Assume sup

0<ν≤ν0

ˆ T u2

L∞dt ≤ C

and ∂1u1 uniformly integrable near x2 = 0: ∀ǫ > 0, ∀L > 0, ∃ρ(ǫ, L) > 0 such that

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SLIDE 130

Corollary CEIV

Corollary

Assume sup

0<ν≤ν0

ˆ T u2

L∞dt ≤ C

and ∂1u1 uniformly integrable near x2 = 0: ∀ǫ > 0, ∀L > 0, ∃ρ(ǫ, L) > 0 such that

  • ˆ

x2≤ρ

ˆ

|x1|≤L

|∂1u1(x1, x2, t)| dx1dx2

  • L2(dt)

≤ ǫ

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SLIDE 131

Corollary CEIV

Corollary

Assume sup

0<ν≤ν0

ˆ T u2

L∞dt ≤ C

and ∂1u1 uniformly integrable near x2 = 0: ∀ǫ > 0, ∀L > 0, ∃ρ(ǫ, L) > 0 such that

  • ˆ

x2≤ρ

ˆ

|x1|≤L

|∂1u1(x1, x2, t)| dx1dx2

  • L2(dt)

≤ ǫ Then lim

ν→0 sup 0≤t≤T

u(t) − v(t)L2 = 0.

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SLIDE 132

New 3D result

Theorem

Let un be a sequence of weak solutions of the Navier-Stokes equations ∂tun + un · ∇un − νn∆un + ∇pn = fn in Ω ⊂ R3 bounded, with ∇ · un = 0, fn bounded in L2(0, T; L2(Ω)), converging weakly to f, un(0) divergence-free and bounded in L2(Ω) and νn → 0. We assume that for any K ⊂⊂ Ω there exists a constant EK, a constant ǫ > 0 and a constant ζ2 > 0 such that sup

n

ˆ T ˆ

K

|un(x + y, t) − un(x, t)|2dxdt ≤ EK|y|ζ2 holds for |y| < dist(K, ∂Ω) in the inertial range |y| ≥ ǫ− 1

4 ν 3 4

n = η(n)

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SLIDE 133

New 3D result

Theorem

Let un be a sequence of weak solutions of the Navier-Stokes equations ∂tun + un · ∇un − νn∆un + ∇pn = fn in Ω ⊂ R3 bounded, with ∇ · un = 0, fn bounded in L2(0, T; L2(Ω)), converging weakly to f, un(0) divergence-free and bounded in L2(Ω) and νn → 0. We assume that for any K ⊂⊂ Ω there exists a constant EK, a constant ǫ > 0 and a constant ζ2 > 0 such that sup

n

ˆ T ˆ

K

|un(x + y, t) − un(x, t)|2dxdt ≤ EK|y|ζ2 holds for |y| < dist(K, ∂Ω) in the inertial range |y| ≥ ǫ− 1

4 ν 3 4

n = η(n)

Assume that un(t) converge weakly in L2(Ω) to u∞(t) for almost all t ∈ (0, T). Then u∞ is a weak solution of the Euler equations.

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SLIDE 134

Remarks

  • 1. The result can be proved for suitable weak solutions in exterior

domains as well.

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SLIDE 135

Remarks

  • 1. The result can be proved for suitable weak solutions in exterior

domains as well.

  • 2. Obviously, the scaling assumption does not imply regularity,

because it is L2 and also limited to y bounded away from zero. Also, the exact Kolmogorov form of η(n) is not needed. All that is used is that η(n) converges to zero as n → ∞.

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SLIDE 136

Remarks

  • 1. The result can be proved for suitable weak solutions in exterior

domains as well.

  • 2. Obviously, the scaling assumption does not imply regularity,

because it is L2 and also limited to y bounded away from zero. Also, the exact Kolmogorov form of η(n) is not needed. All that is used is that η(n) converges to zero as n → ∞.

  • 3. It is possible to remove the assumption of almost all time L2(Ω)

convergence, and replace it with the weak convergence in L2(0, T; L2(Ω)), at the price of demanding space-time second order structure function scaling. ˆ T ˆ

K

|un(x + y, t + s) − un(x, t)|2dxdt ≤ EK(|y|ζ2 + |s|β) for η(n) ≤ |y| < dist(K; ∂Ω), t + s ∈ [0, T], |s| ≥ τ(n), τ(n) → 0, and β > 0. If τ(n) = 0 the requirement is strong, it implies the sequence bounded in Cβ(0, T; L2(Ω)), and in particular the L2(Ω) convergence

  • n each time slice.
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SLIDE 137

New 2D Result

Theorem

Let Ω ⊂ R2 be a bounded open set with smooth boundary. Let un be a sequence of solutions of Navier-Stokes equations with viscosities νn → 0. We assume that the solutions are driven by forces fn ∈ H1(Ω) that are uniformly bounded in H1(Ω) and converge weakly in H1(Ω) to

  • f. We assume that the initial data un(0) are divergence-free and are

in H1

0(Ω) and uniformly bounded in L2(Ω). Moreover, we assume that

for any K ⊂⊂ Ω, sup

0≤t≤T

ˆ

K

|ωn|2dx ≤ EK uniformly in n.

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SLIDE 138

New 2D Result

Theorem

Let Ω ⊂ R2 be a bounded open set with smooth boundary. Let un be a sequence of solutions of Navier-Stokes equations with viscosities νn → 0. We assume that the solutions are driven by forces fn ∈ H1(Ω) that are uniformly bounded in H1(Ω) and converge weakly in H1(Ω) to

  • f. We assume that the initial data un(0) are divergence-free and are

in H1

0(Ω) and uniformly bounded in L2(Ω). Moreover, we assume that

for any K ⊂⊂ Ω, sup

0≤t≤T

ˆ

K

|ωn|2dx ≤ EK uniformly in n. Then any weak limit in L2(0, T; L2(Ω)) of the sequence un, u∞, is a weak solution of the Euler equations ∂tω∞ + u∞ · ∇ω∞ = g = ∇⊥ · f with ω∞ = ∇⊥ · u∞.

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SLIDE 139

2D result, continued

The solution has bounded energy, u∞ ∈ L∞(0, T; L2(Ω)). and for any compact K ⊂⊂ Ω, sup

t∈[0,T]

ˆ

K

|ω∞(x, t)|2dx ≤ EK holds.

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SLIDE 140

2D result, continued

The solution has bounded energy, u∞ ∈ L∞(0, T; L2(Ω)). and for any compact K ⊂⊂ Ω, sup

t∈[0,T]

ˆ

K

|ω∞(x, t)|2dx ≤ EK holds.

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SLIDE 141

Idea of Proof for 3D result

Smooth function j(z) supported in the annulus 1 < |z| < 2, with ´

R3 j(z)dz = 1, j(−z) = j(z). We fix a compact K ⊂⊂ Ω and denote,

for a function u, for x ∈ K and 2r < dist(K, ∂Ω), ur(x) = ˆ

1≤|z|≤2

u(x − rz)j(z)dz.

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SLIDE 142

Idea of Proof for 3D result

Smooth function j(z) supported in the annulus 1 < |z| < 2, with ´

R3 j(z)dz = 1, j(−z) = j(z). We fix a compact K ⊂⊂ Ω and denote,

for a function u, for x ∈ K and 2r < dist(K, ∂Ω), ur(x) = ˆ

1≤|z|≤2

u(x − rz)j(z)dz. From CET (uv)r(x) − ur(x)vr(x) = ρr(u, v)(x) is good.

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SLIDE 143

Idea of Proof for 3D result

Smooth function j(z) supported in the annulus 1 < |z| < 2, with ´

R3 j(z)dz = 1, j(−z) = j(z). We fix a compact K ⊂⊂ Ω and denote,

for a function u, for x ∈ K and 2r < dist(K, ∂Ω), ur(x) = ˆ

1≤|z|≤2

u(x − rz)j(z)dz. From CET (uv)r(x) − ur(x)vr(x) = ρr(u, v)(x) is good. NΦ(n) = ˆ T ˆ

(un ⊗ un) : ∇Φ dxdt

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SLIDE 144

Idea of Proof for 3D result

Smooth function j(z) supported in the annulus 1 < |z| < 2, with ´

R3 j(z)dz = 1, j(−z) = j(z). We fix a compact K ⊂⊂ Ω and denote,

for a function u, for x ∈ K and 2r < dist(K, ∂Ω), ur(x) = ˆ

1≤|z|≤2

u(x − rz)j(z)dz. From CET (uv)r(x) − ur(x)vr(x) = ρr(u, v)(x) is good. NΦ(n) = ˆ T ˆ

(un ⊗ un) : ∇Φ dxdt

  • NΦ(n) −

ˆ T ˆ

(un)r ⊗ (un)r : ∇Φ dxdt

  • ≤ CΦ(EKr ζ2 + Er)
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SLIDE 145

Idea of Proof for 3D result

Smooth function j(z) supported in the annulus 1 < |z| < 2, with ´

R3 j(z)dz = 1, j(−z) = j(z). We fix a compact K ⊂⊂ Ω and denote,

for a function u, for x ∈ K and 2r < dist(K, ∂Ω), ur(x) = ˆ

1≤|z|≤2

u(x − rz)j(z)dz. From CET (uv)r(x) − ur(x)vr(x) = ρr(u, v)(x) is good. NΦ(n) = ˆ T ˆ

(un ⊗ un) : ∇Φ dxdt

  • NΦ(n) −

ˆ T ˆ

(un)r ⊗ (un)r : ∇Φ dxdt

  • ≤ CΦ(EKr ζ2 + Er)

(un)r converges pointwise.

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SLIDE 146

Idea of Proof for 3D result

Smooth function j(z) supported in the annulus 1 < |z| < 2, with ´

R3 j(z)dz = 1, j(−z) = j(z). We fix a compact K ⊂⊂ Ω and denote,

for a function u, for x ∈ K and 2r < dist(K, ∂Ω), ur(x) = ˆ

1≤|z|≤2

u(x − rz)j(z)dz. From CET (uv)r(x) − ur(x)vr(x) = ρr(u, v)(x) is good. NΦ(n) = ˆ T ˆ

(un ⊗ un) : ∇Φ dxdt

  • NΦ(n) −

ˆ T ˆ

(un)r ⊗ (un)r : ∇Φ dxdt

  • ≤ CΦ(EKr ζ2 + Er)

(un)r converges pointwise. Lebegue dominated, and continuity of translation: lim

n→∞ NΦ(n) =

ˆ T ˆ

(u∞) ⊗ (u∞) : ∇Φ dxdt

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SLIDE 147

Idea of proof or 2D result

Localize with cutoff χ: ∇ · (χun) ∈ L2(Ω), ∇⊥ · (χun) ∈ L2(Ω) ⇒ χun ∈ H1

0(Ω)

bounded uniformly in time and n.

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SLIDE 148

Idea of proof or 2D result

Localize with cutoff χ: ∇ · (χun) ∈ L2(Ω), ∇⊥ · (χun) ∈ L2(Ω) ⇒ χun ∈ H1

0(Ω)

bounded uniformly in time and n. Localize vorticity equation:

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SLIDE 149

Idea of proof or 2D result

Localize with cutoff χ: ∇ · (χun) ∈ L2(Ω), ∇⊥ · (χun) ∈ L2(Ω) ⇒ χun ∈ H1

0(Ω)

bounded uniformly in time and n. Localize vorticity equation: ∂t(χωn) ∈ L∞(0, T; H−2(Ω)).

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SLIDE 150

Idea of proof or 2D result

Localize with cutoff χ: ∇ · (χun) ∈ L2(Ω), ∇⊥ · (χun) ∈ L2(Ω) ⇒ χun ∈ H1

0(Ω)

bounded uniformly in time and n. Localize vorticity equation: ∂t(χωn) ∈ L∞(0, T; H−2(Ω)). Aubin-Lions: χωn converge strongly in L2(0, T; H−1(Ω)).

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SLIDE 151

Idea of proof or 2D result

Localize with cutoff χ: ∇ · (χun) ∈ L2(Ω), ∇⊥ · (χun) ∈ L2(Ω) ⇒ χun ∈ H1

0(Ω)

bounded uniformly in time and n. Localize vorticity equation: ∂t(χωn) ∈ L∞(0, T; H−2(Ω)). Aubin-Lions: χωn converge strongly in L2(0, T; H−1(Ω)). NΦ(n) = ˆ T ˆ

(un · ∇Φ)ωndxdt

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SLIDE 152

Idea of proof or 2D result

Localize with cutoff χ: ∇ · (χun) ∈ L2(Ω), ∇⊥ · (χun) ∈ L2(Ω) ⇒ χun ∈ H1

0(Ω)

bounded uniformly in time and n. Localize vorticity equation: ∂t(χωn) ∈ L∞(0, T; H−2(Ω)). Aubin-Lions: χωn converge strongly in L2(0, T; H−1(Ω)). NΦ(n) = ˆ T ˆ

(un · ∇Φ)ωndxdt NΦ(n) = ˆ T ˆ

ΛD(χun · ∇Φ)Λ−1

D (χωn)dxdt.

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SLIDE 153

Corrector CEIV

φ1 = −U(x1, t)

  • 2

ˆ ∞

x2

gσ(t)(z)dz − 2δ(t)η(x2)

  • ,

with gσ(z) = 1 √ 2πσ e− z2

2σ ,

σ(t) = δ(t)2 = 2νt,

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SLIDE 154

Corrector CEIV

φ1 = −U(x1, t)

  • 2

ˆ ∞

x2

gσ(t)(z)dz − 2δ(t)η(x2)

  • ,

with gσ(z) = 1 √ 2πσ e− z2

2σ ,

σ(t) = δ(t)2 = 2νt, and η ∈ C∞

0 (R+), supported in [1, 2] and with integral equal to 1 √ 2π.

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SLIDE 155

Corrector CEIV

φ1 = −U(x1, t)

  • 2

ˆ ∞

x2

gσ(t)(z)dz − 2δ(t)η(x2)

  • ,

with gσ(z) = 1 √ 2πσ e− z2

2σ ,

σ(t) = δ(t)2 = 2νt, and η ∈ C∞

0 (R+), supported in [1, 2] and with integral equal to 1 √ 2π.

φ2 = − ˆ x2 ∂1φ1(x1, z)dz

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SLIDE 156

Corrector CEIV

φ1 = −U(x1, t)

  • 2

ˆ ∞

x2

gσ(t)(z)dz − 2δ(t)η(x2)

  • ,

with gσ(z) = 1 √ 2πσ e− z2

2σ ,

σ(t) = δ(t)2 = 2νt, and η ∈ C∞

0 (R+), supported in [1, 2] and with integral equal to 1 √ 2π.

φ2 = − ˆ x2 ∂1φ1(x1, z)dz Properties:

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SLIDE 157

Corrector CEIV

φ1 = −U(x1, t)

  • 2

ˆ ∞

x2

gσ(t)(z)dz − 2δ(t)η(x2)

  • ,

with gσ(z) = 1 √ 2πσ e− z2

2σ ,

σ(t) = δ(t)2 = 2νt, and η ∈ C∞

0 (R+), supported in [1, 2] and with integral equal to 1 √ 2π.

φ2 = − ˆ x2 ∂1φ1(x1, z)dz Properties: ∇ · φ = 0, (φ + v)| x2=0 = 0, (∂t − ν∆)φ = small and

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SLIDE 158

Corrector CEIV

φ1 = −U(x1, t)

  • 2

ˆ ∞

x2

gσ(t)(z)dz − 2δ(t)η(x2)

  • ,

with gσ(z) = 1 √ 2πσ e− z2

2σ ,

σ(t) = δ(t)2 = 2νt, and η ∈ C∞

0 (R+), supported in [1, 2] and with integral equal to 1 √ 2π.

φ2 = − ˆ x2 ∂1φ1(x1, z)dz Properties: ∇ · φ = 0, (φ + v)| x2=0 = 0, (∂t − ν∆)φ = small and φ1Lp + ∂1φ1Lp ≤ Cδ

1 p

φ2Lp + ∂1φ2Lp ≤ Cδ ∂2φ1Lp ≤ Cδ

1 p −1

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SLIDE 159

Ideea of proof of CEIV result

w = u − v − φ

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SLIDE 160

Ideea of proof of CEIV result

w = u − v − φ Note w| x2=0 = 0.

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SLIDE 161

Ideea of proof of CEIV result

w = u − v − φ Note w| x2=0 = 0. d dt w2

L2 + 2ν∇w2 L2 ≤ C∇vL∞w2 L2 + T1 + T2 + T3

with

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SLIDE 162

Ideea of proof of CEIV result

w = u − v − φ Note w| x2=0 = 0. d dt w2

L2 + 2ν∇w2 L2 ≤ C∇vL∞w2 L2 + T1 + T2 + T3

with T1 =

  • ˆ

v(∂t − ν∆)φdx

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SLIDE 163

Ideea of proof of CEIV result

w = u − v − φ Note w| x2=0 = 0. d dt w2

L2 + 2ν∇w2 L2 ≤ C∇vL∞w2 L2 + T1 + T2 + T3

with T1 =

  • ˆ

v(∂t − ν∆)φdx

  • T2 =
  • ˆ

(u · ∇φ)udx

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SLIDE 164

Ideea of proof of CEIV result

w = u − v − φ Note w| x2=0 = 0. d dt w2

L2 + 2ν∇w2 L2 ≤ C∇vL∞w2 L2 + T1 + T2 + T3

with T1 =

  • ˆ

v(∂t − ν∆)φdx

  • T2 =
  • ˆ

(u · ∇φ)udx

  • and

T3 =

  • ˆ

[(u · ∇v)φ + (φ · ∇v)w]dx

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SLIDE 165

Ideea of proof of CEIV result

w = u − v − φ Note w| x2=0 = 0. d dt w2

L2 + 2ν∇w2 L2 ≤ C∇vL∞w2 L2 + T1 + T2 + T3

with T1 =

  • ˆ

v(∂t − ν∆)φdx

  • T2 =
  • ˆ

(u · ∇φ)udx

  • and

T3 =

  • ˆ

[(u · ∇v)φ + (φ · ∇v)w]dx

  • T3 is ok.
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SLIDE 166

Ideea of proof of CEIV result

w = u − v − φ Note w| x2=0 = 0. d dt w2

L2 + 2ν∇w2 L2 ≤ C∇vL∞w2 L2 + T1 + T2 + T3

with T1 =

  • ˆ

v(∂t − ν∆)φdx

  • T2 =
  • ˆ

(u · ∇φ)udx

  • and

T3 =

  • ˆ

[(u · ∇v)φ + (φ · ∇v)w]dx

  • T3 is ok.

Recall: v smooth, φ small, u bounded in L2.

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SLIDE 167

Bound of T1

The corrector was designed so that (∂t − ν∆)φL2 ≤ C[δ

1 2 + ˙

δ]

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SLIDE 168

Bound of T1

The corrector was designed so that (∂t − ν∆)φL2 ≤ C[δ

1 2 + ˙

δ] which is due to the fact that (∂t − ν(∂x2)2)gσ = 0, and bounds on U, Ut.

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SLIDE 169

Bound of T1

The corrector was designed so that (∂t − ν∆)φL2 ≤ C[δ

1 2 + ˙

δ] which is due to the fact that (∂t − ν(∂x2)2)gσ = 0, and bounds on U, Ut. Recall: δ = √ 2νt.

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SLIDE 170

Bound of T1

The corrector was designed so that (∂t − ν∆)φL2 ≤ C[δ

1 2 + ˙

δ] which is due to the fact that (∂t − ν(∂x2)2)gσ = 0, and bounds on U, Ut. Recall: δ = √ 2νt. and thus ˆ t T1dt = O(νt)

1 4

for 0 ≤ t ≤ T.

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SLIDE 171

Behavior of T2

  • (j,i)=(2,1)

ˆ uj∂jφiuidx

  • ≤ Cu2

L∞δ(t)

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SLIDE 172

Behavior of T2

  • (j,i)=(2,1)

ˆ uj∂jφiuidx

  • ≤ Cu2

L∞δ(t)

because of properties of φ.

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SLIDE 173

Behavior of T2

  • (j,i)=(2,1)

ˆ uj∂jφiuidx

  • ≤ Cu2

L∞δ(t)

because of properties of φ. Main contribution is from

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SLIDE 174

Behavior of T2

  • (j,i)=(2,1)

ˆ uj∂jφiuidx

  • ≤ Cu2

L∞δ(t)

because of properties of φ. Main contribution is from

  • ˆ

u2∂2φ1u1dx

  • .
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SLIDE 175

Behavior of T2

  • (j,i)=(2,1)

ˆ uj∂jφiuidx

  • ≤ Cu2

L∞δ(t)

because of properties of φ. Main contribution is from

  • ˆ

u2∂2φ1u1dx

  • .

The integral for x2 ≥ ρ(ǫ) is bounded using the Gaussian gσ(ρ) and L2 bounds on u. Its time integarl rapidly vanishes.

slide-176
SLIDE 176

Behavior of T2

  • (j,i)=(2,1)

ˆ uj∂jφiuidx

  • ≤ Cu2

L∞δ(t)

because of properties of φ. Main contribution is from

  • ˆ

u2∂2φ1u1dx

  • .

The integral for x2 ≥ ρ(ǫ) is bounded using the Gaussian gσ(ρ) and L2 bounds on u. Its time integarl rapidly vanishes. The integral for x2 ≤ ρ(ǫ) is essentially (ignoring the small term due to η) and rescaling in x2

slide-177
SLIDE 177

Behavior of T2

  • (j,i)=(2,1)

ˆ uj∂jφiuidx

  • ≤ Cu2

L∞δ(t)

because of properties of φ. Main contribution is from

  • ˆ

u2∂2φ1u1dx

  • .

The integral for x2 ≥ ρ(ǫ) is bounded using the Gaussian gσ(ρ) and L2 bounds on u. Its time integarl rapidly vanishes. The integral for x2 ≤ ρ(ǫ) is essentially (ignoring the small term due to η) and rescaling in x2

  • 2

ˆ U(x1, t)u1(x1, δx2, t)u2(x1, δx2, t)g1(x2)dx1dx2

slide-178
SLIDE 178

Behavior of T2

  • (j,i)=(2,1)

ˆ uj∂jφiuidx

  • ≤ Cu2

L∞δ(t)

because of properties of φ. Main contribution is from

  • ˆ

u2∂2φ1u1dx

  • .

The integral for x2 ≥ ρ(ǫ) is bounded using the Gaussian gσ(ρ) and L2 bounds on u. Its time integarl rapidly vanishes. The integral for x2 ≤ ρ(ǫ) is essentially (ignoring the small term due to η) and rescaling in x2

  • 2

ˆ U(x1, t)u1(x1, δx2, t)u2(x1, δx2, t)g1(x2)dx1dx2

  • which is bounded uniformly by
slide-179
SLIDE 179

Behavior of T2

  • (j,i)=(2,1)

ˆ uj∂jφiuidx

  • ≤ Cu2

L∞δ(t)

because of properties of φ. Main contribution is from

  • ˆ

u2∂2φ1u1dx

  • .

The integral for x2 ≥ ρ(ǫ) is bounded using the Gaussian gσ(ρ) and L2 bounds on u. Its time integarl rapidly vanishes. The integral for x2 ≤ ρ(ǫ) is essentially (ignoring the small term due to η) and rescaling in x2

  • 2

ˆ U(x1, t)u1(x1, δx2, t)u2(x1, δx2, t)g1(x2)dx1dx2

  • which is bounded uniformly by

2ǫ ˆ

ρ(ǫ) δ

ˆ

R

g1(x2)|U(x1, t)|γ(x1, t)dx1dx2

slide-180
SLIDE 180

Ideea of proof of Corollary CEIV

We have the same problem term:

slide-181
SLIDE 181

Ideea of proof of Corollary CEIV

We have the same problem term: B(t) =

  • 2

ˆ U(x1, t)u1(x1, δx2, t)u2(x1, δx2, t)g1(x2)dx1dx2

slide-182
SLIDE 182

Ideea of proof of Corollary CEIV

We have the same problem term: B(t) =

  • 2

ˆ U(x1, t)u1(x1, δx2, t)u2(x1, δx2, t)g1(x2)dx1dx2

  • For given ǫ there exists L > 0 such that
slide-183
SLIDE 183

Ideea of proof of Corollary CEIV

We have the same problem term: B(t) =

  • 2

ˆ U(x1, t)u1(x1, δx2, t)u2(x1, δx2, t)g1(x2)dx1dx2

  • For given ǫ there exists L > 0 such that

u(t)2

L∞

ˆ

|x1|≥Lor x2≥L

|U(x1, t)|g1(x2)dx1dx2 ≤ ǫu(t)2

L∞.

slide-184
SLIDE 184

Ideea of proof of Corollary CEIV

We have the same problem term: B(t) =

  • 2

ˆ U(x1, t)u1(x1, δx2, t)u2(x1, δx2, t)g1(x2)dx1dx2

  • For given ǫ there exists L > 0 such that

u(t)2

L∞

ˆ

|x1|≥Lor x2≥L

|U(x1, t)|g1(x2)dx1dx2 ≤ ǫu(t)2

L∞.

On the other hand

slide-185
SLIDE 185

Ideea of proof of Corollary CEIV

We have the same problem term: B(t) =

  • 2

ˆ U(x1, t)u1(x1, δx2, t)u2(x1, δx2, t)g1(x2)dx1dx2

  • For given ǫ there exists L > 0 such that

u(t)2

L∞

ˆ

|x1|≥Lor x2≥L

|U(x1, t)|g1(x2)dx1dx2 ≤ ǫu(t)2

L∞.

On the other hand 2 ˆ

|x1|≤L,x2≤L

dx1dx2U(x1)g1(x2)u1(x1, δx2, t) ˆ δx2 (−∂1u1(x1, z, t))dz

slide-186
SLIDE 186

Ideea of proof of Corollary CEIV

We have the same problem term: B(t) =

  • 2

ˆ U(x1, t)u1(x1, δx2, t)u2(x1, δx2, t)g1(x2)dx1dx2

  • For given ǫ there exists L > 0 such that

u(t)2

L∞

ˆ

|x1|≥Lor x2≥L

|U(x1, t)|g1(x2)dx1dx2 ≤ ǫu(t)2

L∞.

On the other hand 2 ˆ

|x1|≤L,x2≤L

dx1dx2U(x1)g1(x2)u1(x1, δx2, t) ˆ δx2 (−∂1u1(x1, z, t))dz is bounded by

slide-187
SLIDE 187

Ideea of proof of Corollary CEIV

We have the same problem term: B(t) =

  • 2

ˆ U(x1, t)u1(x1, δx2, t)u2(x1, δx2, t)g1(x2)dx1dx2

  • For given ǫ there exists L > 0 such that

u(t)2

L∞

ˆ

|x1|≥Lor x2≥L

|U(x1, t)|g1(x2)dx1dx2 ≤ ǫu(t)2

L∞.

On the other hand 2 ˆ

|x1|≤L,x2≤L

dx1dx2U(x1)g1(x2)u1(x1, δx2, t) ˆ δx2 (−∂1u1(x1, z, t))dz is bounded by 2UL∞u1(t)L∞ ˆ

|x1|≤L

ˆ δL |∂1u1(x1, z, t)|dx1dz,

slide-188
SLIDE 188

Ideea of proof of Corollary CEIV

We have the same problem term: B(t) =

  • 2

ˆ U(x1, t)u1(x1, δx2, t)u2(x1, δx2, t)g1(x2)dx1dx2

  • For given ǫ there exists L > 0 such that

u(t)2

L∞

ˆ

|x1|≥Lor x2≥L

|U(x1, t)|g1(x2)dx1dx2 ≤ ǫu(t)2

L∞.

On the other hand 2 ˆ

|x1|≤L,x2≤L

dx1dx2U(x1)g1(x2)u1(x1, δx2, t) ˆ δx2 (−∂1u1(x1, z, t))dz is bounded by 2UL∞u1(t)L∞ ˆ

|x1|≤L

ˆ δL |∂1u1(x1, z, t)|dx1dz, and so, if δL ≤ ρ(ǫ, L)

slide-189
SLIDE 189

Ideea of proof of Corollary CEIV

We have the same problem term: B(t) =

  • 2

ˆ U(x1, t)u1(x1, δx2, t)u2(x1, δx2, t)g1(x2)dx1dx2

  • For given ǫ there exists L > 0 such that

u(t)2

L∞

ˆ

|x1|≥Lor x2≥L

|U(x1, t)|g1(x2)dx1dx2 ≤ ǫu(t)2

L∞.

On the other hand 2 ˆ

|x1|≤L,x2≤L

dx1dx2U(x1)g1(x2)u1(x1, δx2, t) ˆ δx2 (−∂1u1(x1, z, t))dz is bounded by 2UL∞u1(t)L∞ ˆ

|x1|≤L

ˆ δL |∂1u1(x1, z, t)|dx1dz, and so, if δL ≤ ρ(ǫ, L) ˆ T B(t)dt ≤ 2ǫ  UL∞ ˆ T u1(t)2

L∞dt +

ˆ T u2

L∞dt

 

slide-190
SLIDE 190

Discussion

◮ All previous results require some uniform assumptions of

gradients of Navier-Stokes solutions at the boundary.

slide-191
SLIDE 191

Discussion

◮ All previous results require some uniform assumptions of

gradients of Navier-Stokes solutions at the boundary.

◮ All but the new results require regular Euler solutions and derive

strong L2 convergence

slide-192
SLIDE 192

Discussion

◮ All previous results require some uniform assumptions of

gradients of Navier-Stokes solutions at the boundary.

◮ All but the new results require regular Euler solutions and derive

strong L2 convergence

◮ The strong stability and the regularity of the Euler solution imply

the vanishing of the energy dissipation rate in the zero viscosity limit.

slide-193
SLIDE 193

Discussion

◮ All previous results require some uniform assumptions of

gradients of Navier-Stokes solutions at the boundary.

◮ All but the new results require regular Euler solutions and derive

strong L2 convergence

◮ The strong stability and the regularity of the Euler solution imply

the vanishing of the energy dissipation rate in the zero viscosity limit.

◮ The vanishing of the dissipation rate follows from weak

convergence in L2(Ω) for all times only if the Euler equation is

  • conservative. We proved results of emergence of weak, possibly

dissipative solutions of Euler equations in 3D if the ensemble of Navier-Stokes solutions obeys a local-in-space but uniform in the ensemble second order structure function scaling from above. In two dimensions, we proved the emergence of weak solutions form arbitrary families of strong solutions of Navier-Stokes equations with uniform interior (local) enstrophy bounds. There might be dissipative solutions among them, although an example is not available at this time.