Radiative EWSB in a Little Higgs Model
Carl Schmidt
Michigan State University May 11, 2010 PHENO 2010 arXiv:1001.0584, R. Foadi, J. T. Laverty, CS, and J.-H. Yu
Radiative EWSB in a Little Higgs Model Carl Schmidt Michigan State - - PowerPoint PPT Presentation
Radiative EWSB in a Little Higgs Model Carl Schmidt Michigan State University arXiv:1001.0584, R. Foadi, J. T. Laverty, CS, and J.-H. Yu May 11, 2010 PHENO 2010 Motivation Little Hierarchy: v 2 << f 2 << 2 (0.25 TeV) 2 (~1 TeV)
Michigan State University May 11, 2010 PHENO 2010 arXiv:1001.0584, R. Foadi, J. T. Laverty, CS, and J.-H. Yu
(0.25 TeV)2 (~1 TeV)2 (~10 TeV)2
Collective Symmetry Breaking: If g1= 0 or g2= 0, H is a Goldstone Boson. => Quadratic divergences ~ Λ2 vanish at one loop
If potential is purely radiative, expect m2~g4f2, λ~g4 => v2 ~ -m2/λ2 ~ f2 => Too big! Typically, LH models introduce new operators to make λ larger. Plaquettes, mass terms, quartic terms
Good: Gives negative contribution to m2. Necessary for symmetry breaking. Bad: Since mH
2 ~ -2m2, it gives contribution to Higgs mass
Still must have cancellation to get light Higgs.
m2 = 3t
2
8 2 MT
2 ln 2
MT
2
→ SU(2)L x U(1)Y
Collective Symmetry Breaking: If (g0L = g0R = 0) or (g1L = g1R = 0), H is a Goldstone Boson. => Quadratic divergences vanish at one loop
Gauge Sector (Barbieri, Bellazzini, Rychkov, Varagnolo)
MZ R
2 1 2 g0R 2 + g1R 2
MWR
2
1
2 g1R 2 f 2
MZ L
2 1 2 g0L 2 + g1L 2
MWL
2
1
2 g0L 2 + g1L 2
WR ZR ZL WL g1L
2 = g1R 2 = 6
f =1 TeV
(Also SM W and Z)
A =
A
A =
A
B =
B
B =
B
L AR A B f L BR B 1 f L AEE R B + h.c.
Breaks SO(5)0 Preserves SO(5)1 Preserves SO(5)0 Breaks SO(5)1 Collective Symmetry Breaking => SO(5)1-breaking spurion E =
1
MTA
2 A 2 + 1 2
MTB
2 B 2 f 2
Mt
2 t 2v 2 /2
TA A = 1 = 2t B = 0.981t f =1 TeV TB t
1 t
2 = 1
1
2 + 1
A
2
m2 31
2
8 2 2B
2 A 2
MTA
2
21
2A 2 f 2
1
2 1 2 3A 2 + 2B 2
f =10 TeV
g1L
2 = g1R 2 = 0.5, 2, 4
f =1 TeV
sint = 1 1
2 + A 2
m2 31
2
8 2 2B
2 ln B 2
MTA
2 A 2 ln A 2
MTA
2
L AQR A Bt L B
R B + h.c.
L A
R B
Compare to SUSY
g1L
2 = g1R 2 = 2
f =1 TeV
sint = 1 1
2 + A 2
A 4f , B 4f
2 2v 2
3t
4
4 2 1 4 ln MTA
2
Mt
2
+ F sint , MTA
2
MTB
2
g1 = g1L = g1R