RAAGs in Ham Misha Kapovich UC Davis June 30, 2011 Motivation M - - PowerPoint PPT Presentation

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RAAGs in Ham Misha Kapovich UC Davis June 30, 2011 Motivation M - - PowerPoint PPT Presentation

RAAGs in Ham Misha Kapovich UC Davis June 30, 2011 Motivation M is a compact surface, is area form on M . Diff ( M , ) is the group of area-preserving diffeomorphisms of M . Motivation M is a compact surface, is area form on M


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RAAGs in Ham

Misha Kapovich UC Davis June 30, 2011

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Motivation

◮ M is a compact surface, ω is area form on M. Diff (M, ω) is

the group of area-preserving diffeomorphisms of M.

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Motivation

◮ M is a compact surface, ω is area form on M. Diff (M, ω) is

the group of area-preserving diffeomorphisms of M.

◮ Zimmer’s Program (prediction): If Λ is a lattice of rank ≥ 2

(e.g. SL(3, Z)) then Λ cannot embed in Diff (M, ω).

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Motivation

◮ M is a compact surface, ω is area form on M. Diff (M, ω) is

the group of area-preserving diffeomorphisms of M.

◮ Zimmer’s Program (prediction): If Λ is a lattice of rank ≥ 2

(e.g. SL(3, Z)) then Λ cannot embed in Diff (M, ω).

◮ Note: SL(3, Z) embeds in Diff (S2).

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Motivation

◮ M is a compact surface, ω is area form on M. Diff (M, ω) is

the group of area-preserving diffeomorphisms of M.

◮ Zimmer’s Program (prediction): If Λ is a lattice of rank ≥ 2

(e.g. SL(3, Z)) then Λ cannot embed in Diff (M, ω).

◮ Note: SL(3, Z) embeds in Diff (S2). ◮ Negative results: L. Polterovich; Franks and Handel: A

non-uniform lattice of rank ≥ 2 cannot embed in Diff (M, ω). A non-uniform (irreducible) lattice in a Lie group (different from O(n, 1)) cannot embed in Diff (M, ω) if χ(M) ≤ 0.

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SLIDE 6

Motivation

◮ M is a compact surface, ω is area form on M. Diff (M, ω) is

the group of area-preserving diffeomorphisms of M.

◮ Zimmer’s Program (prediction): If Λ is a lattice of rank ≥ 2

(e.g. SL(3, Z)) then Λ cannot embed in Diff (M, ω).

◮ Note: SL(3, Z) embeds in Diff (S2). ◮ Negative results: L. Polterovich; Franks and Handel: A

non-uniform lattice of rank ≥ 2 cannot embed in Diff (M, ω). A non-uniform (irreducible) lattice in a Lie group (different from O(n, 1)) cannot embed in Diff (M, ω) if χ(M) ≤ 0.

◮ Question: What happens with lattices in O(n, 1)?

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Ham

◮ ω is a symplectic form on a manifold M (a closed,

nondegenerate 2-form, e.g., area form on a surface). H = Ht : M → R is a time-dependent smooth function. XH is the Hamiltonian vector field of H:

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Ham

◮ ω is a symplectic form on a manifold M (a closed,

nondegenerate 2-form, e.g., area form on a surface). H = Ht : M → R is a time-dependent smooth function. XH is the Hamiltonian vector field of H:

◮ dH(ξ) = ω(XH, ξ), i.e., XH is the “symplectic gradient.”

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Ham

◮ ω is a symplectic form on a manifold M (a closed,

nondegenerate 2-form, e.g., area form on a surface). H = Ht : M → R is a time-dependent smooth function. XH is the Hamiltonian vector field of H:

◮ dH(ξ) = ω(XH, ξ), i.e., XH is the “symplectic gradient.” ◮ ∂ ∂t ft = XH is the Hamiltonian flow of H. Maps ft are

Hamiltonian symplectomorphisms of (M, ω).

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Ham

◮ ω is a symplectic form on a manifold M (a closed,

nondegenerate 2-form, e.g., area form on a surface). H = Ht : M → R is a time-dependent smooth function. XH is the Hamiltonian vector field of H:

◮ dH(ξ) = ω(XH, ξ), i.e., XH is the “symplectic gradient.” ◮ ∂ ∂t ft = XH is the Hamiltonian flow of H. Maps ft are

Hamiltonian symplectomorphisms of (M, ω).

◮ Ham(M, ω) is the group of Hamiltonian symplectomorphisms.

If M is a surface, Ham(M, ω) ⊂ Diff (M, ω).

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Ham

◮ ω is a symplectic form on a manifold M (a closed,

nondegenerate 2-form, e.g., area form on a surface). H = Ht : M → R is a time-dependent smooth function. XH is the Hamiltonian vector field of H:

◮ dH(ξ) = ω(XH, ξ), i.e., XH is the “symplectic gradient.” ◮ ∂ ∂t ft = XH is the Hamiltonian flow of H. Maps ft are

Hamiltonian symplectomorphisms of (M, ω).

◮ Ham(M, ω) is the group of Hamiltonian symplectomorphisms.

If M is a surface, Ham(M, ω) ⊂ Diff (M, ω).

◮ Note: If M is a surface, then, as a group, Ham(M, ω) is

independent of ω (Mozer); thus, Ham(M, ω) = Ham(M).

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RAAGs

◮ Warning: Our convention is opposite to the standard (but is

consistent with Dynkin diagrams).

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RAAGs

◮ Warning: Our convention is opposite to the standard (but is

consistent with Dynkin diagrams).

◮ Γ is a finite graph (1-dimensional simplicial complex), V (Γ) is

the vertex set, E(Γ) is the edge set.

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RAAGs

◮ Warning: Our convention is opposite to the standard (but is

consistent with Dynkin diagrams).

◮ Γ is a finite graph (1-dimensional simplicial complex), V (Γ) is

the vertex set, E(Γ) is the edge set.

◮ Right-Angled Artin Group (RAAG)

GΓ = gv, v ∈ V (Γ)|[gv, gw] = 1, [v, w] / ∈ E(Γ).

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RAAGs

◮ Warning: Our convention is opposite to the standard (but is

consistent with Dynkin diagrams).

◮ Γ is a finite graph (1-dimensional simplicial complex), V (Γ) is

the vertex set, E(Γ) is the edge set.

◮ Right-Angled Artin Group (RAAG)

GΓ = gv, v ∈ V (Γ)|[gv, gw] = 1, [v, w] / ∈ E(Γ).

◮ Examples: Free groups, free abelian groups,...

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RAAGs

◮ Warning: Our convention is opposite to the standard (but is

consistent with Dynkin diagrams).

◮ Γ is a finite graph (1-dimensional simplicial complex), V (Γ) is

the vertex set, E(Γ) is the edge set.

◮ Right-Angled Artin Group (RAAG)

GΓ = gv, v ∈ V (Γ)|[gv, gw] = 1, [v, w] / ∈ E(Γ).

◮ Examples: Free groups, free abelian groups,... ◮ Theorem (Bergeron, Haglind, Wise): If Γ is an arithmetic

lattice in O(n, 1) of the simplest type then a finite-index subgroup in Γ embeds in some RAAG.

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RAAGs in Ham

◮ Main Theorem. Every RAAG embeds in every Ham: For

every symplectic manifold (M, ω) and every RAAG GΓ, there exists an embedding GΓ ֒ → Ham(M, ω).

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RAAGs in Ham

◮ Main Theorem. Every RAAG embeds in every Ham: For

every symplectic manifold (M, ω) and every RAAG GΓ, there exists an embedding GΓ ֒ → Ham(M, ω).

◮ Corollary. For every n there exist finite volume hyperbolic

n-manifolds N (compact and not) so that π1(N) embeds in every Ham.

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RAAGs in Ham

◮ Main Theorem. Every RAAG embeds in every Ham: For

every symplectic manifold (M, ω) and every RAAG GΓ, there exists an embedding GΓ ֒ → Ham(M, ω).

◮ Corollary. For every n there exist finite volume hyperbolic

n-manifolds N (compact and not) so that π1(N) embeds in every Ham.

◮ The most difficult case is M = S2.

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Outline of the proof

◮ Step 1. Embed given G = GΓ in Ham(M) for some surface

M of genus depending on Γ.

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Outline of the proof

◮ Step 1. Embed given G = GΓ in Ham(M) for some surface

M of genus depending on Γ.

◮ Step 2. Lift the action of G to the universal cover of M

(hyperbolic plane H2). The (faithful) action of G extends (topologically) to the rest of S2 by the identity.

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Outline of the proof

◮ Step 1. Embed given G = GΓ in Ham(M) for some surface

M of genus depending on Γ.

◮ Step 2. Lift the action of G to the universal cover of M

(hyperbolic plane H2). The (faithful) action of G extends (topologically) to the rest of S2 by the identity.

◮ Replace the hyperbolic area form with spherical, modify the

action of G so that it extends to a Lipschitz, faithful, area-preserving action on S2. The action fixes the exterior of H2.

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Outline of the proof

◮ Step 1. Embed given G = GΓ in Ham(M) for some surface

M of genus depending on Γ.

◮ Step 2. Lift the action of G to the universal cover of M

(hyperbolic plane H2). The (faithful) action of G extends (topologically) to the rest of S2 by the identity.

◮ Replace the hyperbolic area form with spherical, modify the

action of G so that it extends to a Lipschitz, faithful, area-preserving action on S2. The action fixes the exterior of H2.

◮ Step 3. Smooth out the action preserving faithfulness.

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Step 1 (topology)

◮ Embed the graph Γ in M for some surface M of genus = 1.

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Step 1 (topology)

◮ Embed the graph Γ in M for some surface M of genus = 1. ◮ Thicken Γ ⊂ M: Replace each vertex v by a domain Dv so

that the nerve of the collection {Dv} is Γ.

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Step 1 (topology)

◮ Embed the graph Γ in M for some surface M of genus = 1. ◮ Thicken Γ ⊂ M: Replace each vertex v by a domain Dv so

that the nerve of the collection {Dv} is Γ.

◮ Pick functions Hv supported on Dv and let fv be the time-1

maps of the associated Hamiltonian flows. Then each fv is also supported in Dv.

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Step 1 (topology)

◮ Embed the graph Γ in M for some surface M of genus = 1. ◮ Thicken Γ ⊂ M: Replace each vertex v by a domain Dv so

that the nerve of the collection {Dv} is Γ.

◮ Pick functions Hv supported on Dv and let fv be the time-1

maps of the associated Hamiltonian flows. Then each fv is also supported in Dv.

◮ Since Dv ∩ Dw = ∅ whenever [v, w] /

∈ E(Γ), [fv, fw] = 1 and we get a homomorphism GΓ → Ham(M),

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Step 1 (topology)

◮ Embed the graph Γ in M for some surface M of genus = 1. ◮ Thicken Γ ⊂ M: Replace each vertex v by a domain Dv so

that the nerve of the collection {Dv} is Γ.

◮ Pick functions Hv supported on Dv and let fv be the time-1

maps of the associated Hamiltonian flows. Then each fv is also supported in Dv.

◮ Since Dv ∩ Dw = ∅ whenever [v, w] /

∈ E(Γ), [fv, fw] = 1 and we get a homomorphism GΓ → Ham(M),

◮ given by ρ(gv) = fv.

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Step 1 (topology)

◮ Embed the graph Γ in M for some surface M of genus = 1. ◮ Thicken Γ ⊂ M: Replace each vertex v by a domain Dv so

that the nerve of the collection {Dv} is Γ.

◮ Pick functions Hv supported on Dv and let fv be the time-1

maps of the associated Hamiltonian flows. Then each fv is also supported in Dv.

◮ Since Dv ∩ Dw = ∅ whenever [v, w] /

∈ E(Γ), [fv, fw] = 1 and we get a homomorphism GΓ → Ham(M),

◮ given by ρ(gv) = fv. ◮ Such ρ is probably faithful for “generic” functions Hv, but I

do not know how to prove it!

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Step 1: Cntd

◮ Instead of “generic” Hv’s we will use non-generic ones.

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Step 1: Cntd

◮ Instead of “generic” Hv’s we will use non-generic ones. ◮ Take Dv = A(v) to be homotopically trivial annuli in M which

intersect in pairs of squares.

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Step 1: Cntd

◮ Instead of “generic” Hv’s we will use non-generic ones. ◮ Take Dv = A(v) to be homotopically trivial annuli in M which

intersect in pairs of squares.

◮ q

2

P2 P2 P2 P1 P1 A(v) A(w) P

Figure: Points pi, q are punctures to be removed from the surface.

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Step 1: Cntd

◮ On each annulus A(v) = S1 × [−1, 1] take Hv to be a height

function h(τ) so that h′(0) = 2π, h vanishes at −1, 1 with all its derivaives.

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Step 1: Cntd

◮ On each annulus A(v) = S1 × [−1, 1] take Hv to be a height

function h(τ) so that h′(0) = 2π, h vanishes at −1, 1 with all its derivaives.

◮ Then the time-1 Hamiltonian map f is a “double Dehn twist”

  • r “point-pushing map” rotating the circle S1 × 0 by 2π.
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Step 1: Cntd

◮ On each annulus A(v) = S1 × [−1, 1] take Hv to be a height

function h(τ) so that h′(0) = 2π, h vanishes at −1, 1 with all its derivaives.

◮ Then the time-1 Hamiltonian map f is a “double Dehn twist”

  • r “point-pushing map” rotating the circle S1 × 0 by 2π.

A α f( ) α

Figure: Point-pushing map (up to C 0 relative isotopy).

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End of Step 1

◮ Then the maps fv fix middle circles of the annuli A(v) (and

points outside the annuli) and, hence, induce elements of the mapping class group Map(M′) of the punctured surface M′ = M − {pi, q}.

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End of Step 1

◮ Then the maps fv fix middle circles of the annuli A(v) (and

points outside the annuli) and, hence, induce elements of the mapping class group Map(M′) of the punctured surface M′ = M − {pi, q}.

◮ I’d like to claim that the homomorphism GΓ → Map(M′) is

1-1. But this is still unclear. Nevertheless

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End of Step 1

◮ Then the maps fv fix middle circles of the annuli A(v) (and

points outside the annuli) and, hence, induce elements of the mapping class group Map(M′) of the punctured surface M′ = M − {pi, q}.

◮ I’d like to claim that the homomorphism GΓ → Map(M′) is

1-1. But this is still unclear. Nevertheless

◮ (Corollary of) a Theorem by Funar (c.f. Koberda;

Clay, Leininger and Mangahas) is that if we use for fv time-2 Hamiltonian maps, then ρ : GΓ → Map(M′) is 1-1.

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End of Step 1

◮ Then the maps fv fix middle circles of the annuli A(v) (and

points outside the annuli) and, hence, induce elements of the mapping class group Map(M′) of the punctured surface M′ = M − {pi, q}.

◮ I’d like to claim that the homomorphism GΓ → Map(M′) is

1-1. But this is still unclear. Nevertheless

◮ (Corollary of) a Theorem by Funar (c.f. Koberda;

Clay, Leininger and Mangahas) is that if we use for fv time-2 Hamiltonian maps, then ρ : GΓ → Map(M′) is 1-1.

◮ This does the job if M is S2.

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End of Step 1

◮ Then the maps fv fix middle circles of the annuli A(v) (and

points outside the annuli) and, hence, induce elements of the mapping class group Map(M′) of the punctured surface M′ = M − {pi, q}.

◮ I’d like to claim that the homomorphism GΓ → Map(M′) is

1-1. But this is still unclear. Nevertheless

◮ (Corollary of) a Theorem by Funar (c.f. Koberda;

Clay, Leininger and Mangahas) is that if we use for fv time-2 Hamiltonian maps, then ρ : GΓ → Map(M′) is 1-1.

◮ This does the job if M is S2. ◮ But Γ need not be planar.

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End of Step 1

◮ Then the maps fv fix middle circles of the annuli A(v) (and

points outside the annuli) and, hence, induce elements of the mapping class group Map(M′) of the punctured surface M′ = M − {pi, q}.

◮ I’d like to claim that the homomorphism GΓ → Map(M′) is

1-1. But this is still unclear. Nevertheless

◮ (Corollary of) a Theorem by Funar (c.f. Koberda;

Clay, Leininger and Mangahas) is that if we use for fv time-2 Hamiltonian maps, then ρ : GΓ → Map(M′) is 1-1.

◮ This does the job if M is S2. ◮ But Γ need not be planar. ◮ One can show (with a bit of trickery) that if Γ admits a finite

planar orbi-cover Λ → Γ then GΓ ֒ → GΛ and we are again OK.

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Step 2 (hyperbolic geometry)

◮ Of course, the universal cover of every graph is planar.

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Step 2 (hyperbolic geometry)

◮ Of course, the universal cover of every graph is planar. ◮ Let unit disk D = H2 → M be the universal cover (recall that

χ(M) = 0). Use this cover to lift each fv to a product of infinitely many commuting twists.

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Step 2 (hyperbolic geometry)

◮ Of course, the universal cover of every graph is planar. ◮ Let unit disk D = H2 → M be the universal cover (recall that

χ(M) = 0). Use this cover to lift each fv to a product of infinitely many commuting twists.

◮ We get a (faithful) representation ˜

ρ : GΓ → Ham(H2) (with hyperbolic area form). Moreover, if D′ is the infinitely punctured disk covering M′ then G = GΓ → Map(D′) is still 1-1.

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Step 2 (hyperbolic geometry)

◮ Of course, the universal cover of every graph is planar. ◮ Let unit disk D = H2 → M be the universal cover (recall that

χ(M) = 0). Use this cover to lift each fv to a product of infinitely many commuting twists.

◮ We get a (faithful) representation ˜

ρ : GΓ → Ham(H2) (with hyperbolic area form). Moreover, if D′ is the infinitely punctured disk covering M′ then G = GΓ → Map(D′) is still 1-1.

◮ Since all elements of ρ(G) are homotopically trivial, ˜

ρ(G) extends by the identity to the rest of S2.

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Step 2 (hyperbolic geometry)

◮ Of course, the universal cover of every graph is planar. ◮ Let unit disk D = H2 → M be the universal cover (recall that

χ(M) = 0). Use this cover to lift each fv to a product of infinitely many commuting twists.

◮ We get a (faithful) representation ˜

ρ : GΓ → Ham(H2) (with hyperbolic area form). Moreover, if D′ is the infinitely punctured disk covering M′ then G = GΓ → Map(D′) is still 1-1.

◮ Since all elements of ρ(G) are homotopically trivial, ˜

ρ(G) extends by the identity to the rest of S2.

◮ Problem: 1) The extension is only Holder; 2) more

importantly, ˜ ρ(G) preserves wrong area form.

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Step 2 (hyperbolic geometry)

◮ Of course, the universal cover of every graph is planar. ◮ Let unit disk D = H2 → M be the universal cover (recall that

χ(M) = 0). Use this cover to lift each fv to a product of infinitely many commuting twists.

◮ We get a (faithful) representation ˜

ρ : GΓ → Ham(H2) (with hyperbolic area form). Moreover, if D′ is the infinitely punctured disk covering M′ then G = GΓ → Map(D′) is still 1-1.

◮ Since all elements of ρ(G) are homotopically trivial, ˜

ρ(G) extends by the identity to the rest of S2.

◮ Problem: 1) The extension is only Holder; 2) more

importantly, ˜ ρ(G) preserves wrong area form.

◮ Let ω0 be the spherical area form on S2.

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SLIDE 48

Step 2 (hyperbolic geometry)

◮ Of course, the universal cover of every graph is planar. ◮ Let unit disk D = H2 → M be the universal cover (recall that

χ(M) = 0). Use this cover to lift each fv to a product of infinitely many commuting twists.

◮ We get a (faithful) representation ˜

ρ : GΓ → Ham(H2) (with hyperbolic area form). Moreover, if D′ is the infinitely punctured disk covering M′ then G = GΓ → Map(D′) is still 1-1.

◮ Since all elements of ρ(G) are homotopically trivial, ˜

ρ(G) extends by the identity to the rest of S2.

◮ Problem: 1) The extension is only Holder; 2) more

importantly, ˜ ρ(G) preserves wrong area form.

◮ Let ω0 be the spherical area form on S2. ◮ We can lift functions Hv to D and try to use ω0 to define new

time-2 Hamiltonian maps using these functions. The resulting maps preserve ω0 on D, but ...

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Step 2: Cntd

◮ ... The lifted functions ˜

Hv do not extend continuously by 0 to the unit circle...

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Step 2: Cntd

◮ ... The lifted functions ˜

Hv do not extend continuously by 0 to the unit circle...

◮ Even worse, the new time-2 maps are not in the (relative)

isotopy class of the lifts of the maps fv (or may not even preserve D′), so we cannot be sure that the representation is 1-1.

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SLIDE 51

Step 2: Cntd

◮ ... The lifted functions ˜

Hv do not extend continuously by 0 to the unit circle...

◮ Even worse, the new time-2 maps are not in the (relative)

isotopy class of the lifts of the maps fv (or may not even preserve D′), so we cannot be sure that the representation is 1-1.

◮ If z ∈ D, then (1 − |z|)2ωhyp(z) ≍ ω0(z).

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SLIDE 52

Step 2: Cntd

◮ ... The lifted functions ˜

Hv do not extend continuously by 0 to the unit circle...

◮ Even worse, the new time-2 maps are not in the (relative)

isotopy class of the lifts of the maps fv (or may not even preserve D′), so we cannot be sure that the representation is 1-1.

◮ If z ∈ D, then (1 − |z|)2ωhyp(z) ≍ ω0(z). ◮ Hence, the Hamiltonian vector field (with respect to ω0) of

˜ Hv at z is about (1 − |z|)−2× what we need for a double Dehn twist.

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SLIDE 53

Step 2: Cntd

◮ ... The lifted functions ˜

Hv do not extend continuously by 0 to the unit circle...

◮ Even worse, the new time-2 maps are not in the (relative)

isotopy class of the lifts of the maps fv (or may not even preserve D′), so we cannot be sure that the representation is 1-1.

◮ If z ∈ D, then (1 − |z|)2ωhyp(z) ≍ ω0(z). ◮ Hence, the Hamiltonian vector field (with respect to ω0) of

˜ Hv at z is about (1 − |z|)−2× what we need for a double Dehn twist.

◮ Thus, we have to replace ˜

Hv with new functions ˆ Hv(z) ≍ (1 − |z|)2 ˜ Hv(z), so that

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SLIDE 54

Step 2: Cntd

◮ ... The lifted functions ˜

Hv do not extend continuously by 0 to the unit circle...

◮ Even worse, the new time-2 maps are not in the (relative)

isotopy class of the lifts of the maps fv (or may not even preserve D′), so we cannot be sure that the representation is 1-1.

◮ If z ∈ D, then (1 − |z|)2ωhyp(z) ≍ ω0(z). ◮ Hence, the Hamiltonian vector field (with respect to ω0) of

˜ Hv at z is about (1 − |z|)−2× what we need for a double Dehn twist.

◮ Thus, we have to replace ˜

Hv with new functions ˆ Hv(z) ≍ (1 − |z|)2 ˜ Hv(z), so that

◮ the resulting time-1 maps (with respect to ω0) are double

Dehn twists.

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SLIDE 55

Step 2: Cntd

◮ We then get a new representation ˆ

ρ : G → Ham(D) which preserves D′ and, moreover, has the same projection to Map(D′) as ˜ ρ.

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SLIDE 56

Step 2: Cntd

◮ We then get a new representation ˆ

ρ : G → Ham(D) which preserves D′ and, moreover, has the same projection to Map(D′) as ˜ ρ.

◮ In particular: ˆ

ρ is 1-1.

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SLIDE 57

Step 2: Cntd

◮ We then get a new representation ˆ

ρ : G → Ham(D) which preserves D′ and, moreover, has the same projection to Map(D′) as ˜ ρ.

◮ In particular: ˆ

ρ is 1-1.

◮ Now, there are good news and bad news.

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SLIDE 58

Step 2: Cntd

◮ We then get a new representation ˆ

ρ : G → Ham(D) which preserves D′ and, moreover, has the same projection to Map(D′) as ˜ ρ.

◮ In particular: ˆ

ρ is 1-1.

◮ Now, there are good news and bad news. ◮ Good: The new functions ˆ

Hv admit C 1,1 extension by 0 from D to the rest of S2.

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SLIDE 59

Step 2: Cntd

◮ We then get a new representation ˆ

ρ : G → Ham(D) which preserves D′ and, moreover, has the same projection to Map(D′) as ˜ ρ.

◮ In particular: ˆ

ρ is 1-1.

◮ Now, there are good news and bad news. ◮ Good: The new functions ˆ

Hv admit C 1,1 extension by 0 from D to the rest of S2.

◮ In particular, the action of the group ˆ

ρ(G) on D extends to a Lipschitz action on S2 (by the identity).

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SLIDE 60

Step 2: Cntd

◮ We then get a new representation ˆ

ρ : G → Ham(D) which preserves D′ and, moreover, has the same projection to Map(D′) as ˜ ρ.

◮ In particular: ˆ

ρ is 1-1.

◮ Now, there are good news and bad news. ◮ Good: The new functions ˆ

Hv admit C 1,1 extension by 0 from D to the rest of S2.

◮ In particular, the action of the group ˆ

ρ(G) on D extends to a Lipschitz action on S2 (by the identity).

◮ Bad: The 2-nd and higher derivatives of ˆ

Hv blow up on the boundary of D, while the 1st derivatives are only bounded, so we do not even get a C 1–action on S2.

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SLIDE 61

Step 2: Cntd

◮ We then get a new representation ˆ

ρ : G → Ham(D) which preserves D′ and, moreover, has the same projection to Map(D′) as ˜ ρ.

◮ In particular: ˆ

ρ is 1-1.

◮ Now, there are good news and bad news. ◮ Good: The new functions ˆ

Hv admit C 1,1 extension by 0 from D to the rest of S2.

◮ In particular, the action of the group ˆ

ρ(G) on D extends to a Lipschitz action on S2 (by the identity).

◮ Bad: The 2-nd and higher derivatives of ˆ

Hv blow up on the boundary of D, while the 1st derivatives are only bounded, so we do not even get a C 1–action on S2.

◮ Good: The blow-up is only polynomial in z.

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SLIDE 62

Step 3 (analysis: mollification)

◮ The idea is to smooth out the action ˆ

ρ of G on S2 preserving faithfulness.

slide-63
SLIDE 63

Step 3 (analysis: mollification)

◮ The idea is to smooth out the action ˆ

ρ of G on S2 preserving faithfulness.

◮ Let ηǫ(z), ǫ ∈ (0, 1] be a real-analytic family of

bump-functions (“mollifiers”) on D which vanish (exponentially fast with derivatives of all orders) on the boundary circle, so that ηǫ → η0 = 1 (uniformly on compacts in D).

slide-64
SLIDE 64

Step 3 (analysis: mollification)

◮ The idea is to smooth out the action ˆ

ρ of G on S2 preserving faithfulness.

◮ Let ηǫ(z), ǫ ∈ (0, 1] be a real-analytic family of

bump-functions (“mollifiers”) on D which vanish (exponentially fast with derivatives of all orders) on the boundary circle, so that ηǫ → η0 = 1 (uniformly on compacts in D).

◮ Then, replace each ˆ

Hv with ηǫ ˆ

  • Hv. Now, these functions

extends to C ∞ on S2 for ǫ > 0.

slide-65
SLIDE 65

Step 3 (analysis: mollification)

◮ The idea is to smooth out the action ˆ

ρ of G on S2 preserving faithfulness.

◮ Let ηǫ(z), ǫ ∈ (0, 1] be a real-analytic family of

bump-functions (“mollifiers”) on D which vanish (exponentially fast with derivatives of all orders) on the boundary circle, so that ηǫ → η0 = 1 (uniformly on compacts in D).

◮ Then, replace each ˆ

Hv with ηǫ ˆ

  • Hv. Now, these functions

extends to C ∞ on S2 for ǫ > 0.

◮ Obtain new (C ∞) time-2 maps ˆ

fv,ǫ using the functions ηǫ ˆ Hv.

slide-66
SLIDE 66

Step 3 (analysis: mollification)

◮ The idea is to smooth out the action ˆ

ρ of G on S2 preserving faithfulness.

◮ Let ηǫ(z), ǫ ∈ (0, 1] be a real-analytic family of

bump-functions (“mollifiers”) on D which vanish (exponentially fast with derivatives of all orders) on the boundary circle, so that ηǫ → η0 = 1 (uniformly on compacts in D).

◮ Then, replace each ˆ

Hv with ηǫ ˆ

  • Hv. Now, these functions

extends to C ∞ on S2 for ǫ > 0.

◮ Obtain new (C ∞) time-2 maps ˆ

fv,ǫ using the functions ηǫ ˆ Hv.

◮ The result is again a family of representations

ˆ ρǫ : G → Ham(S2), gv → ˆ fv,ǫ.

slide-67
SLIDE 67

Step 3 (analysis: mollification)

◮ The idea is to smooth out the action ˆ

ρ of G on S2 preserving faithfulness.

◮ Let ηǫ(z), ǫ ∈ (0, 1] be a real-analytic family of

bump-functions (“mollifiers”) on D which vanish (exponentially fast with derivatives of all orders) on the boundary circle, so that ηǫ → η0 = 1 (uniformly on compacts in D).

◮ Then, replace each ˆ

Hv with ηǫ ˆ

  • Hv. Now, these functions

extends to C ∞ on S2 for ǫ > 0.

◮ Obtain new (C ∞) time-2 maps ˆ

fv,ǫ using the functions ηǫ ˆ Hv.

◮ The result is again a family of representations

ˆ ρǫ : G → Ham(S2), gv → ˆ fv,ǫ.

◮ Why would these ˆ

ρǫ be faithful for small ǫ?

slide-68
SLIDE 68

Step 3 (analysis: mollification)

◮ The idea is to smooth out the action ˆ

ρ of G on S2 preserving faithfulness.

◮ Let ηǫ(z), ǫ ∈ (0, 1] be a real-analytic family of

bump-functions (“mollifiers”) on D which vanish (exponentially fast with derivatives of all orders) on the boundary circle, so that ηǫ → η0 = 1 (uniformly on compacts in D).

◮ Then, replace each ˆ

Hv with ηǫ ˆ

  • Hv. Now, these functions

extends to C ∞ on S2 for ǫ > 0.

◮ Obtain new (C ∞) time-2 maps ˆ

fv,ǫ using the functions ηǫ ˆ Hv.

◮ The result is again a family of representations

ˆ ρǫ : G → Ham(S2), gv → ˆ fv,ǫ.

◮ Why would these ˆ

ρǫ be faithful for small ǫ?

◮ I have no idea...

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SLIDE 69

Step 3: Cntd

◮ The point however, is that ˆ

fv,ǫ|D depends real-analytically on ǫ for ǫ > 0.

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SLIDE 70

Step 3: Cntd

◮ The point however, is that ˆ

fv,ǫ|D depends real-analytically on ǫ for ǫ > 0.

◮ Therefore, for each g ∈ G − 1 the set Eg := {ǫ : ˆ

ρǫ(g) = 1} is either at most countable or Eg = [0, 1].

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SLIDE 71

Step 3: Cntd

◮ The point however, is that ˆ

fv,ǫ|D depends real-analytically on ǫ for ǫ > 0.

◮ Therefore, for each g ∈ G − 1 the set Eg := {ǫ : ˆ

ρǫ(g) = 1} is either at most countable or Eg = [0, 1].

◮ But the latter is impossible since ˆ

ρ = ˆ ρ0 is faithful.

slide-72
SLIDE 72

Step 3: Cntd

◮ The point however, is that ˆ

fv,ǫ|D depends real-analytically on ǫ for ǫ > 0.

◮ Therefore, for each g ∈ G − 1 the set Eg := {ǫ : ˆ

ρǫ(g) = 1} is either at most countable or Eg = [0, 1].

◮ But the latter is impossible since ˆ

ρ = ˆ ρ0 is faithful.

◮ Since G is countable, for generic ǫ, ˆ

ρǫ is faithful.

slide-73
SLIDE 73

Step 3: Cntd

◮ The point however, is that ˆ

fv,ǫ|D depends real-analytically on ǫ for ǫ > 0.

◮ Therefore, for each g ∈ G − 1 the set Eg := {ǫ : ˆ

ρǫ(g) = 1} is either at most countable or Eg = [0, 1].

◮ But the latter is impossible since ˆ

ρ = ˆ ρ0 is faithful.

◮ Since G is countable, for generic ǫ, ˆ

ρǫ is faithful.

◮ I do not know what happens for non-generic ǫ, even those

close to 0.

slide-74
SLIDE 74

Getting to Ham(M, ω) for an arbitrary symplectic manifold

◮ Hence, we obtain embeddings G ֒

→ Ham(S2) which are supported in ¯ D.

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SLIDE 75

Getting to Ham(M, ω) for an arbitrary symplectic manifold

◮ Hence, we obtain embeddings G ֒

→ Ham(S2) which are supported in ¯ D.

◮ Therefore, we can promote these embeddings to embeddings

G ֒ → Ham(M) for any surface M (by identity outside of a small disk D ⊂ M).

slide-76
SLIDE 76

Getting to Ham(M, ω) for an arbitrary symplectic manifold

◮ Hence, we obtain embeddings G ֒

→ Ham(S2) which are supported in ¯ D.

◮ Therefore, we can promote these embeddings to embeddings

G ֒ → Ham(M) for any surface M (by identity outside of a small disk D ⊂ M).

◮ Let M have dimension 2n. Consider a small polydisk

Dn = B2n ⊂ M.

slide-77
SLIDE 77

Getting to Ham(M, ω) for an arbitrary symplectic manifold

◮ Hence, we obtain embeddings G ֒

→ Ham(S2) which are supported in ¯ D.

◮ Therefore, we can promote these embeddings to embeddings

G ֒ → Ham(M) for any surface M (by identity outside of a small disk D ⊂ M).

◮ Let M have dimension 2n. Consider a small polydisk

Dn = B2n ⊂ M.

◮ Extend the faithful Hamiltonian action GΓ D diagonally to

Dn.

slide-78
SLIDE 78

Getting to Ham(M, ω) for an arbitrary symplectic manifold

◮ Hence, we obtain embeddings G ֒

→ Ham(S2) which are supported in ¯ D.

◮ Therefore, we can promote these embeddings to embeddings

G ֒ → Ham(M) for any surface M (by identity outside of a small disk D ⊂ M).

◮ Let M have dimension 2n. Consider a small polydisk

Dn = B2n ⊂ M.

◮ Extend the faithful Hamiltonian action GΓ D diagonally to

Dn.

◮ Then extend the diagonal action by the identity to the rest of

M.

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SLIDE 79

Generalizations

◮ Question 1. Can one improve the main theorem to an

embedding GΓ ֒ → Diff (S1)?

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SLIDE 80

Generalizations

◮ Question 1. Can one improve the main theorem to an

embedding GΓ ֒ → Diff (S1)?

◮ For example: Take Λ which is a connected linear graph on n

  • vertices. Is it true that for every finite graph Γ there exists an

embedding GΓ → GΛ?

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SLIDE 81

Generalizations

◮ Question 1. Can one improve the main theorem to an

embedding GΓ ֒ → Diff (S1)?

◮ For example: Take Λ which is a connected linear graph on n

  • vertices. Is it true that for every finite graph Γ there exists an

embedding GΓ → GΛ?

◮ If this is the case, then, since Λ embeds in S1, GΛ ֒

→ Diff (S1), so we should also get an embedding GΓ ֒ → Diff (S1).

slide-82
SLIDE 82

Generalizations

◮ Question 2. Do non-right angled Artin groups embed in

Diff (S2, ω)?

slide-83
SLIDE 83

Generalizations

◮ Question 2. Do non-right angled Artin groups embed in

Diff (S2, ω)?

◮ Unclear even for the braid groups.

slide-84
SLIDE 84

Generalizations

◮ Question 2. Do non-right angled Artin groups embed in

Diff (S2, ω)?

◮ Unclear even for the braid groups. ◮ Question 3. Suppose that Λ is a uniform lattice in SU(2, 1).

Can Λ embed in some RAAG?

slide-85
SLIDE 85

Generalizations

◮ Question 2. Do non-right angled Artin groups embed in

Diff (S2, ω)?

◮ Unclear even for the braid groups. ◮ Question 3. Suppose that Λ is a uniform lattice in SU(2, 1).

Can Λ embed in some RAAG?

◮ Not a single example is known.

slide-86
SLIDE 86

Generalizations

◮ Question 2. Do non-right angled Artin groups embed in

Diff (S2, ω)?

◮ Unclear even for the braid groups. ◮ Question 3. Suppose that Λ is a uniform lattice in SU(2, 1).

Can Λ embed in some RAAG?

◮ Not a single example is known. ◮ Note: All RAAGs are locally indicable (every f.g. subgroup

has infinite abelianization). On the other hand, there are uniform lattices in SU(2, 1) which are not known to have virtually positive b1.