Quadrangulation of a Triangulation Kenta Ozeki (Yokohama National - - PowerPoint PPT Presentation

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Quadrangulation of a Triangulation Kenta Ozeki (Yokohama National - - PowerPoint PPT Presentation

A spanning Bipartite Quadrangulation of a Triangulation Kenta Ozeki (Yokohama National University, Japan) Joint work with A. Nakamoto (YNU), and K. Noguchi (Tokyo U. of Science) Spanning bipartite quadrangulation (folklore) G :


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A spanning Bipartite Quadrangulation of a Triangulation

Kenta Ozeki

(Yokohama National University, Japan)

Joint work with

  • A. Nakamoto (YNU), and K. Noguchi (Tokyo U. of Science)
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Spanning bipartite quadrangulation

17th August, 2018 Bucharest Graph Theory Workshop 2 ✓ (folklore) G : triangulation (of any surface)

4-coloring in G 2 spanning bipartite quadrangulations covering (0,1) (1,1) (0,0) (0,1) (1,0) (0,1) (1,1) (0,0) (0,1) (1,0) (0,1) (1,1) (0,0) (0,1) (1,0)

Find a sp. bip. quad. in triangulations

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Spanning bipartite quadrangulation

17th August, 2018 Bucharest Graph Theory Workshop 3

G : triangulation of a surface a spanning quadragulation

Prop.

Bipartite or non-bipartite? Any PM gives a sp. quad. of G G : triangulation The dual has a perfect matching

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Spanning bipartite quadrangulation

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G : triangulation of a surface a spanning quadragulation

Prop.

Bipartite or non-bipartite? G : triangulation of the plane a spanning bipartite quadragulation

Cor.

Note: Any quadrangulation of the plane is bipartite. What about the case of non-spherical surfaces?

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Spanning bipartite quadrangulation

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The general cases seem difficult. Eulerian triangulation → Our target : ( vertex has even degree) Not all (Eulerian) triangulations have a sp. bip. quadrangulation

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The toroidal case

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  • n the torus has NO sp. bip. quadrangulation
  • n the torus has 7 vertices,

21 edges, and 14 faces But, bip. graph on 7 vertices and 21 – 7 = 14 edges. To obtain a sp. bip. quad., we delete exactly 14/2 = 7 edges

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The toroidal case

17th August, 2018 Bucharest Graph Theory Workshop 7

  • n the torus has NO sp. bip. quadrangulation

✓ Kundgen & Thomassen (`17) gave a weaker sufficient condition ✓ Later, I will show an idea of the proof.

G : Eulerian triangulation of the torus a sp. bip. quadrangulation in G

Main Thm.

G does NOT have as a subgraph

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The existence of sp. bip. quad.

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Plane Torus

✓ Eulerian triangulation

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The projective planar case

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G : Eulerian triangulation of the projective plane a sp. bip. quadrangulation in G

Main Thm. 2

✓ Kundgen & Thomassen (`17) proved the same,

Furthermore, if G : 3-colorable, ALL sp. quadrangulations in G are bipartite but our proof is shorter

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The projective planar case

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G : Eulerian triangulation of the projective plane a sp. bip. quadrangulation in G

Main Thm. 2

Eulerian triangulation of the projective plane is the face subdivision of an even embedding facial cycle is even length (Mohar `02)

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The projective planar case

17th August, 2018 Bucharest Graph Theory Workshop 11

G : Eulerian triangulation of the projective plane a sp. bip. quadrangulation in G

Main Thm. 2

Eulerian triangulation of the projective plane is the face subdivision of an even embedding facial cycle is even length Delete all edges in the even embedding (Mohar `02)

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The projective planar case

17th August, 2018 Bucharest Graph Theory Workshop 12

G : Eulerian triangulation of the projective plane

Main Thm. 2

If G : 3-colorable, ALL sp. quadrangulations in G are bipartite either bipartite or non-3-colorable (3-chromatic is impossible) (Youngs `96) quadrangulation of the projective plane is If G : 3-colorable, then all sp. quad.s are 3-colorable, so bipartite

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The projective planar case

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G : Eulerian triangulation of the projective plane a sp. bip. quadrangulation in G

Main Thm. 2

✓ Kundgen & Thomassen (`17) proved the same,

Furthermore, if G : 3-colorable, ALL sp. quadrangulations in G are bipartite but our proof is shorter

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The existence of sp. bip. quad.

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Plane Projective plane Torus

✓ Eulerian triangulation

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The case of other surfaces

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G : Eulerian triangulation of non-spherical surface a sp. bip. quadrangulation in G

Main Thm. 3

✓ Edge-width : the length of shortest essential cycle

If edge-width of G is large enough,

✓ Shown by using the following result;

(Hutchinson, Richter, and Seymour `02) (Archdeacon, Hutchinson, Nakamoto, Negami, and Ota `99)

Eulerian triangulation G with large edge-width is 4-colorable, unless G is the face subdivision of an even embedding

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The existence of sp. bip. quad.

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Plane Projective plane Torus Others if edge-width large

✓ Eulerian triangulation ✓ General triangulation

Only little is known: Plane ``Dense’’ triangulations

e.g. complete graph

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The toroidal case

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is an easy part, while we need some arguments

G : Eulerian triangulation of the torus a sp. bip. quadrangulation in G

Main Thm.

G does NOT have as a subgraph

is the main part

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The toroidal case

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✓ Use generating thm., allowing multiple edges

Eulerian multi-triangulation of the torus is generated from 27 base graphs or 6-regular ones

  • Thm. (Matsumoto, Nakamoto, and Yamaguchi, `18)

by a sequence of 4-splittings and 2-vertex additions

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4-splittings and 2-vertex-addition

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4-splittings and 2-vertex-addition

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2-vertex-addition 4-splitting

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27 base graphs

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6-regular triangulations

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6-reguler multi-triangulation of the torus is represented as follows:

  • Thm. (Altschuler, `73)

(Yeh and Zhu, `03) Characterize by p, q, r, all non-4-colorable triangulations on the torus

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The toroidal case

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G : Eulerian triangulation of the torus G does NOT have as a subgraph Eulerian multi-triangulation of the torus is generated from 27 base graphs or 6-regular ones

  • Thm. (Matsumoto, Nakamoto, and Yamaguchi, `18)

by a sequence of 4-splittings and 2-vertex additions a sp. bip. quad. in G

Main Thm.

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The toroidal case

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G : Eulerian triangulation of the torus G does NOT have as a subgraph a sp. bip. quad. in G

Main Thm.

✓ Show that for all the 27 base graphs and 6-regular ones. ✓ Suppose H’ is obtained from a triangulation H ➢ If H has a sp. bip. quad., then so is H’.

Then show that

➢ If H has as a subgraph,

then either so does H’ or H’ has a sp. bip. quad. by 4-splitting and 2-vertex addition.

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The existence of sp. bip. quad.

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Plane Projective plane Torus Others if edge-width large

✓ Eulerian triangulation ✓ General triangulation

Only little is known: Plane ``Dense’’ triangulations

e.g. complete graph

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The existence of sp. bip. quad.

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Plane Projective plane Torus Others if edge-width large

✓ Eulerian triangulation

Plane Projective plane Torus Others if edge-width large Not 3-colorable For the existence of sp. NON-bip. quadrangulation

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Thank you for your attention