Products of compact lines Gonzalo Mart nez Cervantes University of - - PowerPoint PPT Presentation

products of compact lines
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Products of compact lines Gonzalo Mart nez Cervantes University of - - PowerPoint PPT Presentation

Products of compact lines Gonzalo Mart nez Cervantes University of Murcia, Spain joint work with Grzegorz Plebanek (University of Wroc law) Workshop on Banach spaces and Banach lattices September 12th, 2019 Research supported by


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Products of compact lines

Gonzalo Mart´ ınez Cervantes

University of Murcia, Spain

joint work with Grzegorz Plebanek (University of Wroc law)

Workshop on Banach spaces and Banach lattices

September 12th, 2019

Research supported by project MTM2017-86182-P (Government of Spain, AEI/FEDER, EU) and project 20797/PI/18 by Fundaci´

  • n S´

eneca, ACyT Regi´

  • n de Murcia.
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Yes

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  • Yes. It’s true.
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There are curves which fill the plane.

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The first curve filling the plane was discovered in 1890 by Giuseppe Peano.

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The first curve filling the plane was discovered in 1890 by Giuseppe Peano. Peano’s construction implies that the unit interval can be mapped onto its square

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The first curve filling the plane was discovered in 1890 by Giuseppe Peano. Peano’s construction implies that the unit interval can be mapped onto its square, i.e. there exists a continuous surjection f : [0, 1] → [0, 1]2.

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The first curve filling the plane was discovered in 1890 by Giuseppe Peano. Peano’s construction implies that the unit interval can be mapped onto its square, i.e. there exists a continuous surjection f : [0, 1] → [0, 1]2. Moreover, the unit interval can be mapped onto the cube [0, 1]3

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The first curve filling the plane was discovered in 1890 by Giuseppe Peano. Peano’s construction implies that the unit interval can be mapped onto its square, i.e. there exists a continuous surjection f : [0, 1] → [0, 1]2. Moreover, the unit interval can be mapped onto the cube [0, 1]3, onto

the tesseract [0, 1]4

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The first curve filling the plane was discovered in 1890 by Giuseppe Peano. Peano’s construction implies that the unit interval can be mapped onto its square, i.e. there exists a continuous surjection f : [0, 1] → [0, 1]2. Moreover, the unit interval can be mapped onto the cube [0, 1]3, onto

the tesseract [0, 1]4, and even onto the

Hilbert Cube [0, 1]N

.

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Hans Hahn in Vienna and Stefan Mazurkiewicz in Warsaw (independently) characterized continuous images of the unit interval as metric connected locally connected compact spaces.

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Hans Hahn in Vienna and Stefan Mazurkiewicz in Warsaw (independently) characterized continuous images of the unit interval as metric connected locally connected compact spaces. In 2001 Mary Ellen Rudin characterized continous images of compact lines as compact monotonically normal spaces.

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What is a compact line?

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What is a compact line?

A compact topological space whose topology is induced by a linear order.

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What is a compact line?

A compact topological space whose topology is induced by a linear order.

For example, the unit interval [0, 1], the long interval [0, ω1] and the split interval.

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In 1964 Treybig proved that if a product of two infinite compact spaces is a continuous image of a compact line then such a product is necessarily metrizable

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In 1964 Treybig proved that if a product of two infinite compact spaces is a continuous image of a compact line then such a product is necessarily metrizable i.e. if a compact line L maps onto a product K1 × K2, then

K1 and K2 are both metrizable .

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In 1964 Treybig proved that if a product of two infinite compact spaces is a continuous image of a compact line then such a product is necessarily metrizable i.e. if a compact line L maps onto a product K1 × K2, then

K1 and K2 are both metrizable .

In particular, a nonmetrizable compact line L cannot be mapped onto its square L2.

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Continuous images of products of compact lines

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Continuous images of products of compact lines

Suppose that L1, . . . , Ld are compact lines and that K1, K2, . . . , Kd+1 are infinite compact spaces.

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Continuous images of products of compact lines

Suppose that L1, . . . , Ld are compact lines and that K1, K2, . . . , Kd+1 are infinite compact spaces. Moreover, suppose that there is a continuous surjection f : L1 × . . . × Ld → K1 × . . . × Kd+1.

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Continuous images of products of compact lines

Suppose that L1, . . . , Ld are compact lines and that K1, K2, . . . , Kd+1 are infinite compact spaces. Moreover, suppose that there is a continuous surjection f : L1 × . . . × Ld → K1 × . . . × Kd+1. In 1970 Mardesic proved that, if all Ki are separable, there must be Ki and Kj metrizable.

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Continuous images of products of compact lines

Suppose that L1, . . . , Ld are compact lines and that K1, K2, . . . , Kd+1 are infinite compact spaces. Moreover, suppose that there is a continuous surjection f : L1 × . . . × Ld → K1 × . . . × Kd+1. In 1970 Mardesic proved that, if all Ki are separable, there must be Ki and Kj metrizable.

Moreover, he conjectured that indeed there are always Ki and Kj metrizable (with no separability assumption).

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Continuous images of products of compact lines

Suppose that L1, . . . , Ld are compact lines and that K1, K2, . . . , Kd+1 are infinite compact spaces. Moreover, suppose that there is a continuous surjection f : L1 × . . . × Ld → K1 × . . . × Kd+1. In 1970 Mardesic proved that, if all Ki are separable, there must be Ki and Kj metrizable.

Moreover, he conjectured that indeed there are always Ki and Kj metrizable (with no separability assumption).

In 2009 Avil´ es proved that there are always Ki and Kj separable.

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Continuous images of products of compact lines

Suppose that L1, . . . , Ld are compact lines and that K1, K2, . . . , Kd+1 are infinite compact spaces. Moreover, suppose that there is a continuous surjection f : L1 × . . . × Ld → K1 × . . . × Kd+1. In 1970 Mardesic proved that, if all Ki are separable, there must be Ki and Kj metrizable.

Moreover, he conjectured that indeed there are always Ki and Kj metrizable (with no separability assumption).

In 2009 Avil´ es proved that there are always Ki and Kj separable.

Last year Plebanek and I proved the conjecture!

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Free dimension of a compact space

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Free dimension of a compact space

Given a compact space K, we define free-dim(K) ∈ N ∪ {∞} so that

1 free-dim(K1) ≤ free-dim(K2) if K1 ⊆ K2.

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Free dimension of a compact space

Given a compact space K, we define free-dim(K) ∈ N ∪ {∞} so that

1 free-dim(K1) ≤ free-dim(K2) if K1 ⊆ K2. 2 free-dim(K1) ≤ free-dim(K2) if K1 is a continuous image of K2.

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Free dimension of a compact space

Given a compact space K, we define free-dim(K) ∈ N ∪ {∞} so that

1 free-dim(K1) ≤ free-dim(K2) if K1 ⊆ K2. 2 free-dim(K1) ≤ free-dim(K2) if K1 is a continuous image of K2. 3 free-dim(K) ≤ 1 if K is a metric compact space.

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Free dimension of a compact space

Given a compact space K, we define free-dim(K) ∈ N ∪ {∞} so that

1 free-dim(K1) ≤ free-dim(K2) if K1 ⊆ K2. 2 free-dim(K1) ≤ free-dim(K2) if K1 is a continuous image of K2. 3 free-dim(K) ≤ 1 if K is a metric compact space. 4 free-dim(L) ≤ 1 if L is a compact line.

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Free dimension of a compact space

Given a compact space K, we define free-dim(K) ∈ N ∪ {∞} so that

1 free-dim(K1) ≤ free-dim(K2) if K1 ⊆ K2. 2 free-dim(K1) ≤ free-dim(K2) if K1 is a continuous image of K2. 3 free-dim(K) ≤ 1 if K is a metric compact space. 4 free-dim(L) ≤ 1 if L is a compact line. 5 free-dim(K1 × . . . × Kd) ≤ free-dim(K1) + . . . + free-dim(Kd).

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Free dimension of a compact space

Given a compact space K, we define free-dim(K) ∈ N ∪ {∞} so that

1 free-dim(K1) ≤ free-dim(K2) if K1 ⊆ K2. 2 free-dim(K1) ≤ free-dim(K2) if K1 is a continuous image of K2. 3 free-dim(K) ≤ 1 if K is a metric compact space. 4 free-dim(L) ≤ 1 if L is a compact line. 5 free-dim(K1 × . . . × Kd) ≤ free-dim(K1) + . . . + free-dim(Kd).

Thus, the conjecture follows from the previous points and the following fact:

If K1, . . . , Kd are nonmetrizable compact spaces and Kd+1 is an infinite compact space, then free-dim(K1 × . . . × Kd+1) ≥ d + 1.

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Free dimension of a compact space

Given a compact space K, we define free-dim(K) ∈ N ∪ {∞} so that

1 free-dim(K1) ≤ free-dim(K2) if K1 ⊆ K2. 2 free-dim(K1) ≤ free-dim(K2) if K1 is a continuous image of K2. 3 free-dim(K) ≤ 1 if K is a metric compact space. 4 free-dim(L) ≤ 1 if L is a compact line. 5 free-dim(K1 × . . . × Kd) ≤ free-dim(K1) + . . . + free-dim(Kd).

Thus, the conjecture follows from the previous points and the following fact:

If K1, . . . , Kd are nonmetrizable compact spaces and Kd+1 is an infinite compact space, then free-dim(K1 × . . . × Kd+1) ≥ d + 1.

Notice that free-dim(L1 × . . . × Ld) ≤ d whenever L1, . . . , Ld are compact lines.

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What differences L1 and L1 × L2 when L1 and L2 are compact lines?

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What differences L1 and L1 × L2 when L1 and L2 are compact lines?

A basis for the topology of L1 is given by intervals.

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What differences L1 and L1 × L2 when L1 and L2 are compact lines?

A basis for the topology of L1 is given by intervals. A basis for the topology of L1 × L2 is given by rectangles.

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How do intervals and rectangles differ?

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How do intervals and rectangles differ?

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How do intervals and rectangles differ?

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How do intervals and rectangles differ?

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How do intervals and rectangles differ?

The blue cover has 3 intervals.

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How do intervals and rectangles differ?

The blue cover has 3 intervals. The red cover also has 3 intervals.

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How do intervals and rectangles differ?

The blue cover has 3 intervals. The red cover also has 3 intervals. We can find a finer cover which has 5 intervals.

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How do intervals and rectangles differ?

The blue cover has 3 intervals. The red cover also has 3 intervals. We can find a finer cover which has 5 intervals.

In general, if we have C1, . . . , Ck different covers of a compact line (made with intervals) then we can always find a finer cover C such that |C| ≤ 2(|C1| + . . . + |Ck|).

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How do intervals and rectangles differ?

The blue cover has 3 intervals. The red cover also has 3 intervals. We can find a finer cover which has 5 intervals.

In general, if we have C1, . . . , Ck different covers of a compact line (made with intervals) then we can always find a finer cover C such that |C| ≤ 2(|C1| + . . . + |Ck|).

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How do intervals and rectangles differ?

The blue cover has 3 intervals. The red cover also has 3 intervals. We can find a finer cover which has 5 intervals.

In general, if we have C1, . . . , Ck different covers of a compact line (made with intervals) then we can always find a finer cover C such that |C| ≤ 2(|C1| + . . . + |Ck|).

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How do intervals and rectangles differ?

The blue cover has 3 intervals. The red cover also has 3 intervals. We can find a finer cover which has 5 intervals.

In general, if we have C1, . . . , Ck different covers of a compact line (made with intervals) then we can always find a finer cover C such that |C| ≤ 2(|C1| + . . . + |Ck|).

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How do intervals and rectangles differ?

The blue cover has 3 intervals. The red cover also has 3 intervals. We can find a finer cover which has 5 intervals.

In general, if we have C1, . . . , Ck different covers of a compact line (made with intervals) then we can always find a finer cover C such that |C| ≤ 2(|C1| + . . . + |Ck|).

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How do intervals and rectangles differ?

The blue cover has 3 intervals. The red cover also has 3 intervals. We can find a finer cover which has 5 intervals.

In general, if we have C1, . . . , Ck different covers of a compact line (made with intervals) then we can always find a finer cover C such that |C| ≤ 2(|C1| + . . . + |Ck|).

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How do intervals and rectangles differ?

The blue cover has 3 intervals. The red cover also has 3 intervals. We can find a finer cover which has 5 intervals.

In general, if we have C1, . . . , Ck different covers of a compact line (made with intervals) then we can always find a finer cover C such that |C| ≤ 2(|C1| + . . . + |Ck|).

The blue cover has 3 rectangles.

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How do intervals and rectangles differ?

The blue cover has 3 intervals. The red cover also has 3 intervals. We can find a finer cover which has 5 intervals.

In general, if we have C1, . . . , Ck different covers of a compact line (made with intervals) then we can always find a finer cover C such that |C| ≤ 2(|C1| + . . . + |Ck|).

The blue cover has 3 rectangles. The red cover also has 3 rectangles.

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How do intervals and rectangles differ?

The blue cover has 3 intervals. The red cover also has 3 intervals. We can find a finer cover which has 5 intervals.

In general, if we have C1, . . . , Ck different covers of a compact line (made with intervals) then we can always find a finer cover C such that |C| ≤ 2(|C1| + . . . + |Ck|).

The blue cover has 3 rectangles. The red cover also has 3 rectangles. We can find a finer cover which has 9 rectangles.

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How do intervals and rectangles differ?

The blue cover has 3 intervals. The red cover also has 3 intervals. We can find a finer cover which has 5 intervals.

In general, if we have C1, . . . , Ck different covers of a compact line (made with intervals) then we can always find a finer cover C such that |C| ≤ 2(|C1| + . . . + |Ck|).

The blue cover has 3 rectangles. The red cover also has 3 rectangles. We can find a finer cover which has 9 rectangles.

In general, if you have C1, . . . , Ck different covers (made with rectangles) then we can always find a finer cover C such that |C| ≤ (2(|C1| + . . . + |Ck|))2.

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We define the free-dimension of a compact space K using families C of finite covers C consisting of closed sets. We say that C is topologically cofinal if for every open cover of K there is a finer cover in C.

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We define the free-dimension of a compact space K using families C of finite covers C consisting of closed sets. We say that C is topologically cofinal if for every open cover of K there is a finer cover in C.

Definition (G.M.C. and G. Plebanek, 2018)

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We define the free-dimension of a compact space K using families C of finite covers C consisting of closed sets. We say that C is topologically cofinal if for every open cover of K there is a finer cover in C.

Definition (G.M.C. and G. Plebanek, 2018)

Let d ∈ N ∪ {0}.

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We define the free-dimension of a compact space K using families C of finite covers C consisting of closed sets. We say that C is topologically cofinal if for every open cover of K there is a finer cover in C.

Definition (G.M.C. and G. Plebanek, 2018)

Let d ∈ N ∪ {0}. We say that a compact space K has free dimension ≤ d

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We define the free-dimension of a compact space K using families C of finite covers C consisting of closed sets. We say that C is topologically cofinal if for every open cover of K there is a finer cover in C.

Definition (G.M.C. and G. Plebanek, 2018)

Let d ∈ N ∪ {0}. We say that a compact space K has free dimension ≤ d (free-dim(K) ≤ d)

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We define the free-dimension of a compact space K using families C of finite covers C consisting of closed sets. We say that C is topologically cofinal if for every open cover of K there is a finer cover in C.

Definition (G.M.C. and G. Plebanek, 2018)

Let d ∈ N ∪ {0}. We say that a compact space K has free dimension ≤ d (free-dim(K) ≤ d) if there are

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We define the free-dimension of a compact space K using families C of finite covers C consisting of closed sets. We say that C is topologically cofinal if for every open cover of K there is a finer cover in C.

Definition (G.M.C. and G. Plebanek, 2018)

Let d ∈ N ∪ {0}. We say that a compact space K has free dimension ≤ d (free-dim(K) ≤ d) if there are a topologically cofinal family C of finite closed covers, a constant M > 0

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We define the free-dimension of a compact space K using families C of finite covers C consisting of closed sets. We say that C is topologically cofinal if for every open cover of K there is a finer cover in C.

Definition (G.M.C. and G. Plebanek, 2018)

Let d ∈ N ∪ {0}. We say that a compact space K has free dimension ≤ d (free-dim(K) ≤ d) if there are a topologically cofinal family C of finite closed covers, a constant M > 0 and a function χ : C → N

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We define the free-dimension of a compact space K using families C of finite covers C consisting of closed sets. We say that C is topologically cofinal if for every open cover of K there is a finer cover in C.

Definition (G.M.C. and G. Plebanek, 2018)

Let d ∈ N ∪ {0}. We say that a compact space K has free dimension ≤ d (free-dim(K) ≤ d) if there are a topologically cofinal family C of finite closed covers, a constant M > 0 and a function χ : C → N such that for every k ∈ N and every C1, . . . , Ck ∈ C there is a finer cover C such that |C| ≤ M (χ(C1) + . . . + χ(Ck))d .

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We define the free-dimension of a compact space K using families C of finite covers C consisting of closed sets. We say that C is topologically cofinal if for every open cover of K there is a finer cover in C.

Definition (G.M.C. and G. Plebanek, 2018)

Let d ∈ N ∪ {0}. We say that a compact space K has free dimension ≤ d (free-dim(K) ≤ d) if there are a topologically cofinal family C of finite closed covers, a constant M > 0 and a function χ : C → N such that for every k ∈ N and every C1, . . . , Ck ∈ C there is a finer cover C such that |C| ≤ M (χ(C1) + . . . + χ(Ck))d . With this definition it is easy to check that free-dim(L) ≤ 1 if L is a compact line,

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We define the free-dimension of a compact space K using families C of finite covers C consisting of closed sets. We say that C is topologically cofinal if for every open cover of K there is a finer cover in C.

Definition (G.M.C. and G. Plebanek, 2018)

Let d ∈ N ∪ {0}. We say that a compact space K has free dimension ≤ d (free-dim(K) ≤ d) if there are a topologically cofinal family C of finite closed covers, a constant M > 0 and a function χ : C → N such that for every k ∈ N and every C1, . . . , Ck ∈ C there is a finer cover C such that |C| ≤ M (χ(C1) + . . . + χ(Ck))d . With this definition it is easy to check that free-dim(L) ≤ 1 if L is a compact line, that free-dim(K1) ≤ free-dim(K2) if K1 ⊆ K2 or if K1 is a continuous image of K2,

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We define the free-dimension of a compact space K using families C of finite covers C consisting of closed sets. We say that C is topologically cofinal if for every open cover of K there is a finer cover in C.

Definition (G.M.C. and G. Plebanek, 2018)

Let d ∈ N ∪ {0}. We say that a compact space K has free dimension ≤ d (free-dim(K) ≤ d) if there are a topologically cofinal family C of finite closed covers, a constant M > 0 and a function χ : C → N such that for every k ∈ N and every C1, . . . , Ck ∈ C there is a finer cover C such that |C| ≤ M (χ(C1) + . . . + χ(Ck))d . With this definition it is easy to check that free-dim(L) ≤ 1 if L is a compact line, that free-dim(K1) ≤ free-dim(K2) if K1 ⊆ K2 or if K1 is a continuous image of K2, that free-dim(K) ≤ 1 if K is a metric compact space

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We define the free-dimension of a compact space K using families C of finite covers C consisting of closed sets. We say that C is topologically cofinal if for every open cover of K there is a finer cover in C.

Definition (G.M.C. and G. Plebanek, 2018)

Let d ∈ N ∪ {0}. We say that a compact space K has free dimension ≤ d (free-dim(K) ≤ d) if there are a topologically cofinal family C of finite closed covers, a constant M > 0 and a function χ : C → N such that for every k ∈ N and every C1, . . . , Ck ∈ C there is a finer cover C such that |C| ≤ M (χ(C1) + . . . + χ(Ck))d . With this definition it is easy to check that free-dim(L) ≤ 1 if L is a compact line, that free-dim(K1) ≤ free-dim(K2) if K1 ⊆ K2 or if K1 is a continuous image of K2, that free-dim(K) ≤ 1 if K is a metric compact space and that free-dim(K1 × . . . × Kd) ≤ free-dim(K1) + . . . + free-dim(Kd).

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Theorem (G.M.C. and G. Plebanek,2018)

If K1, . . . , Kd are nonmetrizable compact spaces and Kd+1 is an infinite compact space, then free-dim(K1 × . . . × Kd+1) ≥ d + 1.

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Theorem (G.M.C. and G. Plebanek,2018)

If K1, . . . , Kd are nonmetrizable compact spaces and Kd+1 is an infinite compact space, then free-dim(K1 × . . . × Kd+1) ≥ d + 1.

Lemma (Key Lemma)

If K is a nonmetrizable compact space

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Theorem (G.M.C. and G. Plebanek,2018)

If K1, . . . , Kd are nonmetrizable compact spaces and Kd+1 is an infinite compact space, then free-dim(K1 × . . . × Kd+1) ≥ d + 1.

Lemma (Key Lemma)

If K is a nonmetrizable compact space, then there is an uncountable family F of continuous functions f : K → [0, 1]

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Theorem (G.M.C. and G. Plebanek,2018)

If K1, . . . , Kd are nonmetrizable compact spaces and Kd+1 is an infinite compact space, then free-dim(K1 × . . . × Kd+1) ≥ d + 1.

Lemma (Key Lemma)

If K is a nonmetrizable compact space, then there is an uncountable family F of continuous functions f : K → [0, 1] such that for every infinite family F′ ⊆ F

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Theorem (G.M.C. and G. Plebanek,2018)

If K1, . . . , Kd are nonmetrizable compact spaces and Kd+1 is an infinite compact space, then free-dim(K1 × . . . × Kd+1) ≥ d + 1.

Lemma (Key Lemma)

If K is a nonmetrizable compact space, then there is an uncountable family F of continuous functions f : K → [0, 1] such that for every infinite family F′ ⊆ Fand for every n ∈ N there are functions f1, . . . , fn ∈ F′

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Theorem (G.M.C. and G. Plebanek,2018)

If K1, . . . , Kd are nonmetrizable compact spaces and Kd+1 is an infinite compact space, then free-dim(K1 × . . . × Kd+1) ≥ d + 1.

Lemma (Key Lemma)

If K is a nonmetrizable compact space, then there is an uncountable family F of continuous functions f : K → [0, 1] such that for every infinite family F′ ⊆ Fand for every n ∈ N there are functions f1, . . . , fn ∈ F′ and points x1, . . . , xn+1 ∈ K

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Theorem (G.M.C. and G. Plebanek,2018)

If K1, . . . , Kd are nonmetrizable compact spaces and Kd+1 is an infinite compact space, then free-dim(K1 × . . . × Kd+1) ≥ d + 1.

Lemma (Key Lemma)

If K is a nonmetrizable compact space, then there is an uncountable family F of continuous functions f : K → [0, 1] such that for every infinite family F′ ⊆ Fand for every n ∈ N there are functions f1, . . . , fn ∈ F′ and points x1, . . . , xn+1 ∈ K such that for every xj = xj′ there is k ≤ n such that |fk(xj) − fk(xj′)| ≥ 1

2.

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Theorem (G.M.C. and G. Plebanek,2018)

If K1, . . . , Kd are nonmetrizable compact spaces and Kd+1 is an infinite compact space, then free-dim(K1 × . . . × Kd+1) ≥ d + 1.

Lemma (Key Lemma)

If K is a nonmetrizable compact space, then there is an uncountable family F of continuous functions f : K → [0, 1] such that for every infinite family F′ ⊆ Fand for every n ∈ N there are functions f1, . . . , fn ∈ F′ and points x1, . . . , xn+1 ∈ K such that for every xj = xj′ there is k ≤ n such that |fk(xj) − fk(xj′)| ≥ 1

2.

Main ingredients.

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Theorem (G.M.C. and G. Plebanek,2018)

If K1, . . . , Kd are nonmetrizable compact spaces and Kd+1 is an infinite compact space, then free-dim(K1 × . . . × Kd+1) ≥ d + 1.

Lemma (Key Lemma)

If K is a nonmetrizable compact space, then there is an uncountable family F of continuous functions f : K → [0, 1] such that for every infinite family F′ ⊆ Fand for every n ∈ N there are functions f1, . . . , fn ∈ F′ and points x1, . . . , xn+1 ∈ K such that for every xj = xj′ there is k ≤ n such that |fk(xj) − fk(xj′)| ≥ 1

2.

Main ingredients. Since K is not metrizable, no countable family of functions separates points.

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SLIDE 80

Theorem (G.M.C. and G. Plebanek,2018)

If K1, . . . , Kd are nonmetrizable compact spaces and Kd+1 is an infinite compact space, then free-dim(K1 × . . . × Kd+1) ≥ d + 1.

Lemma (Key Lemma)

If K is a nonmetrizable compact space, then there is an uncountable family F of continuous functions f : K → [0, 1] such that for every infinite family F′ ⊆ Fand for every n ∈ N there are functions f1, . . . , fn ∈ F′ and points x1, . . . , xn+1 ∈ K such that for every xj = xj′ there is k ≤ n such that |fk(xj) − fk(xj′)| ≥ 1

2.

Main ingredients. Since K is not metrizable, no countable family of functions separates points. Using this fact we can construct a family F = {fα : α < ω1} of continuous functions and points x0

α, x1 α ∈ K such

that

slide-81
SLIDE 81

Theorem (G.M.C. and G. Plebanek,2018)

If K1, . . . , Kd are nonmetrizable compact spaces and Kd+1 is an infinite compact space, then free-dim(K1 × . . . × Kd+1) ≥ d + 1.

Lemma (Key Lemma)

If K is a nonmetrizable compact space, then there is an uncountable family F of continuous functions f : K → [0, 1] such that for every infinite family F′ ⊆ Fand for every n ∈ N there are functions f1, . . . , fn ∈ F′ and points x1, . . . , xn+1 ∈ K such that for every xj = xj′ there is k ≤ n such that |fk(xj) − fk(xj′)| ≥ 1

2.

Main ingredients. Since K is not metrizable, no countable family of functions separates points. Using this fact we can construct a family F = {fα : α < ω1} of continuous functions and points x0

α, x1 α ∈ K such

that

1 fα(x0

α) = 0 and fα(x1 α) = 1 for every α < ω1;

slide-82
SLIDE 82

Theorem (G.M.C. and G. Plebanek,2018)

If K1, . . . , Kd are nonmetrizable compact spaces and Kd+1 is an infinite compact space, then free-dim(K1 × . . . × Kd+1) ≥ d + 1.

Lemma (Key Lemma)

If K is a nonmetrizable compact space, then there is an uncountable family F of continuous functions f : K → [0, 1] such that for every infinite family F′ ⊆ Fand for every n ∈ N there are functions f1, . . . , fn ∈ F′ and points x1, . . . , xn+1 ∈ K such that for every xj = xj′ there is k ≤ n such that |fk(xj) − fk(xj′)| ≥ 1

2.

Main ingredients. Since K is not metrizable, no countable family of functions separates points. Using this fact we can construct a family F = {fα : α < ω1} of continuous functions and points x0

α, x1 α ∈ K such

that

1 fα(x0

α) = 0 and fα(x1 α) = 1 for every α < ω1;

2 fβ(x0

α) = fβ(x1 α) for every β < α < ω1.

slide-83
SLIDE 83

Theorem (G.M.C. and G. Plebanek,2018)

If K1, . . . , Kd are nonmetrizable compact spaces and Kd+1 is an infinite compact space, then free-dim(K1 × . . . × Kd+1) ≥ d + 1.

Lemma (Key Lemma)

If K is a nonmetrizable compact space, then there is an uncountable family F of continuous functions f : K → [0, 1] such that for every infinite family F′ ⊆ Fand for every n ∈ N there are functions f1, . . . , fn ∈ F′ and points x1, . . . , xn+1 ∈ K such that for every xj = xj′ there is k ≤ n such that |fk(xj) − fk(xj′)| ≥ 1

2.

Main ingredients. Since K is not metrizable, no countable family of functions separates points. Using this fact we can construct a family F = {fα : α < ω1} of continuous functions and points x0

α, x1 α ∈ K such

that

1 fα(x0

α) = 0 and fα(x1 α) = 1 for every α < ω1;

2 fβ(x0

α) = fβ(x1 α) for every β < α < ω1.

To prove the property stated in the Lemma use Ramsey.

slide-84
SLIDE 84

Theorem (G.M.C. and G. Plebanek,2018)

If K1, . . . , Kd are nonmetrizable compact spaces and Kd+1 is an infinite compact space, then free-dim(K1 × . . . × Kd+1) ≥ d + 1.

Lemma (Key Lemma)

If K is a nonmetrizable compact space, then there is an uncountable family F of continuous functions f : K → [0, 1] such that for every infinite family F′ ⊆ F and for every n ∈ N there are functions f1, . . . , fn ∈ F′ and points x1, . . . , xn+1 ∈ K such that for every xj = xj′ there is k ≤ n such that |fk(xj) − fk(xj′)| ≥ 1

2.

slide-85
SLIDE 85

Theorem (G.M.C. and G. Plebanek,2018)

If K1, . . . , Kd are nonmetrizable compact spaces and Kd+1 is an infinite compact space, then free-dim(K1 × . . . × Kd+1) ≥ d + 1.

Lemma (Key Lemma)

If K is a nonmetrizable compact space, then there is an uncountable family F of continuous functions f : K → [0, 1] such that for every infinite family F′ ⊆ F and for every n ∈ N there are functions f1, . . . , fn ∈ F′ and points x1, . . . , xn+1 ∈ K such that for every xj = xj′ there is k ≤ n such that |fk(xj) − fk(xj′)| ≥ 1

2.

Sketch of the proof. Set K = K1 × . . . × Kd+1. Suppose free-dim(K) ≤ d. Set C a topologically cofinal family of finite closed covers and χ : C → N such that for every C1, . . . , Ck ∈ C there is a finer cover C with |C| ≤ (χ(C1) + . . . + χ(Ck))d.

slide-86
SLIDE 86

Theorem (G.M.C. and G. Plebanek,2018)

If K1, . . . , Kd are nonmetrizable compact spaces and Kd+1 is an infinite compact space, then free-dim(K1 × . . . × Kd+1) ≥ d + 1.

Lemma (Key Lemma)

If K is a nonmetrizable compact space, then there is an uncountable family F of continuous functions f : K → [0, 1] such that for every infinite family F′ ⊆ F and for every n ∈ N there are functions f1, . . . , fn ∈ F′ and points x1, . . . , xn+1 ∈ K such that for every xj = xj′ there is k ≤ n such that |fk(xj) − fk(xj′)| ≥ 1

2.

Sketch of the proof. Set K = K1 × . . . × Kd+1. Suppose free-dim(K) ≤ d. Set C a topologically cofinal family of finite closed covers and χ : C → N such that for every C1, . . . , Ck ∈ C there is a finer cover C with |C| ≤ (χ(C1) + . . . + χ(Ck))d. Notice that for every continuous function f ∈ C(K) there is a cover Cf ∈ C such that Osc(f , C) ≤ 1

3 for every C ∈ Cf .

slide-87
SLIDE 87

Theorem (G.M.C. and G. Plebanek,2018)

If K1, . . . , Kd are nonmetrizable compact spaces and Kd+1 is an infinite compact space, then free-dim(K1 × . . . × Kd+1) ≥ d + 1.

Lemma (Key Lemma)

If K is a nonmetrizable compact space, then there is an uncountable family F of continuous functions f : K → [0, 1] such that for every infinite family F′ ⊆ F and for every n ∈ N there are functions f1, . . . , fn ∈ F′ and points x1, . . . , xn+1 ∈ K such that for every xj = xj′ there is k ≤ n such that |fk(xj) − fk(xj′)| ≥ 1

2.

Sketch of the proof. Set K = K1 × . . . × Kd+1. Suppose free-dim(K) ≤ d. Set C a topologically cofinal family of finite closed covers and χ : C → N such that for every C1, . . . , Ck ∈ C there is a finer cover C with |C| ≤ (χ(C1) + . . . + χ(Ck))d. Notice that for every continuous function f ∈ C(K) there is a cover Cf ∈ C such that Osc(f , C) ≤ 1

3 for every C ∈ Cf . Take families Fi ⊂ C(Ki) as in the

Lemma for every i ≤ d.

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SLIDE 88

Theorem (G.M.C. and G. Plebanek,2018)

If K1, . . . , Kd are nonmetrizable compact spaces and Kd+1 is an infinite compact space, then free-dim(K1 × . . . × Kd+1) ≥ d + 1.

Lemma (Key Lemma)

If K is a nonmetrizable compact space, then there is an uncountable family F of continuous functions f : K → [0, 1] such that for every infinite family F′ ⊆ F and for every n ∈ N there are functions f1, . . . , fn ∈ F′ and points x1, . . . , xn+1 ∈ K such that for every xj = xj′ there is k ≤ n such that |fk(xj) − fk(xj′)| ≥ 1

2.

Sketch of the proof. Set K = K1 × . . . × Kd+1. Suppose free-dim(K) ≤ d. Set C a topologically cofinal family of finite closed covers and χ : C → N such that for every C1, . . . , Ck ∈ C there is a finer cover C with |C| ≤ (χ(C1) + . . . + χ(Ck))d. Notice that for every continuous function f ∈ C(K) there is a cover Cf ∈ C such that Osc(f , C) ≤ 1

3 for every C ∈ Cf . Take families Fi ⊂ C(Ki) as in the

Lemma for every i ≤ d. WLOG, there is m ∈ N such that χ(Cf ) ≤ m for every f ∈ F1 ∪ . . . Fd.

slide-89
SLIDE 89

Theorem (G.M.C. and G. Plebanek,2018)

If K1, . . . , Kd are nonmetrizable compact spaces and Kd+1 is an infinite compact space, then free-dim(K1 × . . . × Kd+1) ≥ d + 1.

Lemma (Key Lemma)

If K is a nonmetrizable compact space, then there is an uncountable family F of continuous functions f : K → [0, 1] such that for every infinite family F′ ⊆ F and for every n ∈ N there are functions f1, . . . , fn ∈ F′ and points x1, . . . , xn+1 ∈ K such that for every xj = xj′ there is k ≤ n such that |fk(xj) − fk(xj′)| ≥ 1

2.

Sketch of the proof. Set K = K1 × . . . × Kd+1. Suppose free-dim(K) ≤ d. Set C a topologically cofinal family of finite closed covers and χ : C → N such that for every C1, . . . , Ck ∈ C there is a finer cover C with |C| ≤ (χ(C1) + . . . + χ(Ck))d. Notice that for every continuous function f ∈ C(K) there is a cover Cf ∈ C such that Osc(f , C) ≤ 1

3 for every C ∈ Cf . Take families Fi ⊂ C(Ki) as in the

Lemma for every i ≤ d. WLOG, there is m ∈ N such that χ(Cf ) ≤ m for every f ∈ F1 ∪ . . . Fd. Now notice that for any finite families G ⊂ F1 ∪ . . . Fd and H ⊂ C(Kd+1) there is a finite closed cover C such that |C| ≤

  • f ∈G χ(Cf ) +

f ∈H χ(Cf )

d ≤

  • |G|m +

f ∈H χ(Cf )

d , with

slide-90
SLIDE 90

Theorem (G.M.C. and G. Plebanek,2018)

If K1, . . . , Kd are nonmetrizable compact spaces and Kd+1 is an infinite compact space, then free-dim(K1 × . . . × Kd+1) ≥ d + 1.

Lemma (Key Lemma)

If K is a nonmetrizable compact space, then there is an uncountable family F of continuous functions f : K → [0, 1] such that for every infinite family F′ ⊆ F and for every n ∈ N there are functions f1, . . . , fn ∈ F′ and points x1, . . . , xn+1 ∈ K such that for every xj = xj′ there is k ≤ n such that |fk(xj) − fk(xj′)| ≥ 1

2.

Sketch of the proof. Set K = K1 × . . . × Kd+1. Suppose free-dim(K) ≤ d. Set C a topologically cofinal family of finite closed covers and χ : C → N such that for every C1, . . . , Ck ∈ C there is a finer cover C with |C| ≤ (χ(C1) + . . . + χ(Ck))d . Notice that for every continuous function f ∈ C(K) there is a cover Cf ∈ C such that Osc(f , C) ≤ 1

3 for every C ∈ Cf . Take families Fi ⊂ C(Ki) as in the

Lemma for every i ≤ d. WLOG, there is m ∈ N such that χ(Cf ) ≤ m for every f ∈ F1 ∪ . . . Fd. Now notice that for any finite families G ⊂ F1 ∪ . . . Fd and H ⊂ C(Kd+1) there is a finite closed cover C such that |C| ≤

  • f ∈G χ(Cf ) +

f ∈H χ(Cf )

d ≤

  • |G|m +

f ∈H χ(Cf )

d , with C finer than every Cf with f ∈ G ∪ H. This yields to a contradiction.

slide-91
SLIDE 91

Theorem (G.M.C. and G. Plebanek,2018)

If K1, . . . , Kd are nonmetrizable compact spaces and Kd+1 is an infinite compact space, then free-dim(K1 × . . . × Kd+1) ≥ d + 1.

Lemma (Key Lemma)

If K is a nonmetrizable compact space, then there is an uncountable family F of continuous functions f : K → [0, 1] such that for every infinite family F′ ⊆ F and for every n ∈ N there are functions f1, . . . , fn ∈ F′ and points x1, . . . , xn+1 ∈ K such that for every xj = xj′ there is k ≤ n such that |fk(xj) − fk(xj′)| ≥ 1

2.

Sketch of the proof. Set K = K1 × . . . × Kd+1. Suppose free-dim(K) ≤ d. Set C a topologically cofinal family of finite closed covers and χ : C → N such that for every C1, . . . , Ck ∈ C there is a finer cover C with |C| ≤ (χ(C1) + . . . + χ(Ck))d . Notice that for every continuous function f ∈ C(K) there is a cover Cf ∈ C such that Osc(f , C) ≤ 1

3 for every C ∈ Cf . Take families Fi ⊂ C(Ki) as in the

Lemma for every i ≤ d. WLOG, there is m ∈ N such that χ(Cf ) ≤ m for every f ∈ F1 ∪ . . . Fd. Now notice that for any finite families G ⊂ F1 ∪ . . . Fd and H ⊂ C(Kd+1) there is a finite closed cover C such that |C| ≤

  • f ∈G χ(Cf ) +

f ∈H χ(Cf )

d ≤

  • |G|m +

f ∈H χ(Cf )

d , with C finer than every Cf with f ∈ G ∪ H. This yields to a contradiction.

slide-92
SLIDE 92

Theorem (G.M.C. and G. Plebanek,2018)

If K1, . . . , Kd are nonmetrizable compact spaces and Kd+1 is an infinite compact space, then free-dim(K1 × . . . × Kd+1) ≥ d + 1.

Lemma (Key Lemma)

If K is a nonmetrizable compact space, then there is an uncountable family F of continuous functions f : K → [0, 1] such that for every infinite family F′ ⊆ F and for every n ∈ N there are functions f1, . . . , fn ∈ F′ and points x1, . . . , xn+1 ∈ K such that for every xj = xj′ there is k ≤ n such that |fk(xj) − fk(xj′)| ≥ 1

2.

Sketch of the proof. Set K = K1 × . . . × Kd+1. Suppose free-dim(K) ≤ d. Set C a topologically cofinal family of finite closed covers and χ : C → N such that for every C1, . . . , Ck ∈ C there is a finer cover C with |C| ≤ (χ(C1) + . . . + χ(Ck))d . Notice that for every continuous function f ∈ C(K) there is a cover Cf ∈ C such that Osc(f , C) ≤ 1

3 for every C ∈ Cf . Take families Fi ⊂ C(Ki) as in the

Lemma for every i ≤ d. WLOG, there is m ∈ N such that χ(Cf ) ≤ m for every f ∈ F1 ∪ . . . Fd. Now notice that for any finite families G ⊂ F1 ∪ . . . Fd and H ⊂ C(Kd+1) there is a finite closed cover C such that |C| ≤

  • f ∈G χ(Cf ) +

f ∈H χ(Cf )

d ≤

  • |G|m +

f ∈H χ(Cf )

d , with C finer than every Cf with f ∈ G ∪ H. This yields to a contradiction.

slide-93
SLIDE 93

Theorem (G.M.C. and G. Plebanek,2018)

If K1, . . . , Kd are nonmetrizable compact spaces and Kd+1 is an infinite compact space, then free-dim(K1 × . . . × Kd+1) ≥ d + 1.

Lemma (Key Lemma)

If K is a nonmetrizable compact space, then there is an uncountable family F of continuous functions f : K → [0, 1] such that for every infinite family F′ ⊆ F and for every n ∈ N there are functions f1, . . . , fn ∈ F′ and points x1, . . . , xn+1 ∈ K such that for every xj = xj′ there is k ≤ n such that |fk(xj) − fk(xj′)| ≥ 1

2.

Sketch of the proof. Set K = K1 × . . . × Kd+1. Suppose free-dim(K) ≤ d. Set C a topologically cofinal family of finite closed covers and χ : C → N such that for every C1, . . . , Ck ∈ C there is a finer cover C with |C| ≤ (χ(C1) + . . . + χ(Ck))d . Notice that for every continuous function f ∈ C(K) there is a cover Cf ∈ C such that Osc(f , C) ≤ 1

3 for every C ∈ Cf . Take families Fi ⊂ C(Ki) as in the

Lemma for every i ≤ d. WLOG, there is m ∈ N such that χ(Cf ) ≤ m for every f ∈ F1 ∪ . . . Fd. Now notice that for any finite families G ⊂ F1 ∪ . . . Fd and H ⊂ C(Kd+1) there is a finite closed cover C such that |C| ≤

  • f ∈G χ(Cf ) +

f ∈H χ(Cf )

d ≤

  • |G|m +

f ∈H χ(Cf )

d , with C finer than every Cf with f ∈ G ∪ H. This yields to a contradiction.

slide-94
SLIDE 94

Theorem (G.M.C. and G. Plebanek,2018)

If K1, . . . , Kd are nonmetrizable compact spaces and Kd+1 is an infinite compact space, then free-dim(K1 × . . . × Kd+1) ≥ d + 1.

Lemma (Key Lemma)

If K is a nonmetrizable compact space, then there is an uncountable family F of continuous functions f : K → [0, 1] such that for every infinite family F′ ⊆ F and for every n ∈ N there are functions f1, . . . , fn ∈ F′ and points x1, . . . , xn+1 ∈ K such that for every xj = xj′ there is k ≤ n such that |fk(xj) − fk(xj′)| ≥ 1

2.

Sketch of the proof. Set K = K1 × . . . × Kd+1. Suppose free-dim(K) ≤ d. Set C a topologically cofinal family of finite closed covers and χ : C → N such that for every C1, . . . , Ck ∈ C there is a finer cover C with |C| ≤ (χ(C1) + . . . + χ(Ck))d . Notice that for every continuous function f ∈ C(K) there is a cover Cf ∈ C such that Osc(f , C) ≤ 1

3 for every C ∈ Cf . Take families Fi ⊂ C(Ki) as in the

Lemma for every i ≤ d. WLOG, there is m ∈ N such that χ(Cf ) ≤ m for every f ∈ F1 ∪ . . . Fd. Now notice that for any finite families G ⊂ F1 ∪ . . . Fd and H ⊂ C(Kd+1) there is a finite closed cover C such that |C| ≤

  • f ∈G χ(Cf ) +

f ∈H χ(Cf )

d ≤

  • |G|m +

f ∈H χ(Cf )

d , with C finer than every Cf with f ∈ G ∪ H. This yields to a contradiction.

slide-95
SLIDE 95

Theorem (G.M.C. and G. Plebanek,2018)

If K1, . . . , Kd are nonmetrizable compact spaces and Kd+1 is an infinite compact space, then free-dim(K1 × . . . × Kd+1) ≥ d + 1.

Lemma (Key Lemma)

If K is a nonmetrizable compact space, then there is an uncountable family F of continuous functions f : K → [0, 1] such that for every infinite family F′ ⊆ F and for every n ∈ N there are functions f1, . . . , fn ∈ F′ and points x1, . . . , xn+1 ∈ K such that for every xj = xj′ there is k ≤ n such that |fk(xj) − fk(xj′)| ≥ 1

2.

Sketch of the proof. Set K = K1 × . . . × Kd+1. Suppose free-dim(K) ≤ d. Set C a topologically cofinal family of finite closed covers and χ : C → N such that for every C1, . . . , Ck ∈ C there is a finer cover C with |C| ≤ (χ(C1) + . . . + χ(Ck))d . Notice that for every continuous function f ∈ C(K) there is a cover Cf ∈ C such that Osc(f , C) ≤ 1

3 for every C ∈ Cf . Take families Fi ⊂ C(Ki) as in the

Lemma for every i ≤ d. WLOG, there is m ∈ N such that χ(Cf ) ≤ m for every f ∈ F1 ∪ . . . Fd. Now notice that for any finite families G ⊂ F1 ∪ . . . Fd and H ⊂ C(Kd+1) there is a finite closed cover C such that |C| ≤

  • f ∈G χ(Cf ) +

f ∈H χ(Cf )

d ≤

  • |G|m +

f ∈H χ(Cf )

d , with C finer than every Cf with f ∈ G ∪ H. This yields to a contradiction.

slide-96
SLIDE 96

Theorem (G.M.C. and G. Plebanek,2018)

If K1, . . . , Kd are nonmetrizable compact spaces and Kd+1 is an infinite compact space, then free-dim(K1 × . . . × Kd+1) ≥ d + 1.

Lemma (Key Lemma)

If K is a nonmetrizable compact space, then there is an uncountable family F of continuous functions f : K → [0, 1] such that for every infinite family F′ ⊆ F and for every n ∈ N there are functions f1, . . . , fn ∈ F′ and points x1, . . . , xn+1 ∈ K such that for every xj = xj′ there is k ≤ n such that |fk(xj) − fk(xj′)| ≥ 1

2.

Sketch of the proof. Set K = K1 × . . . × Kd+1. Suppose free-dim(K) ≤ d. Set C a topologically cofinal family of finite closed covers and χ : C → N such that for every C1, . . . , Ck ∈ C there is a finer cover C with |C| ≤ (χ(C1) + . . . + χ(Ck))d . Notice that for every continuous function f ∈ C(K) there is a cover Cf ∈ C such that Osc(f , C) ≤ 1

3 for every C ∈ Cf . Take families Fi ⊂ C(Ki) as in the

Lemma for every i ≤ d. WLOG, there is m ∈ N such that χ(Cf ) ≤ m for every f ∈ F1 ∪ . . . Fd. Now notice that for any finite families G ⊂ F1 ∪ . . . Fd and H ⊂ C(Kd+1) there is a finite closed cover C such that |C| ≤

  • f ∈G χ(Cf ) +

f ∈H χ(Cf )

d ≤

  • |G|m +

f ∈H χ(Cf )

d , with C finer than every Cf with f ∈ G ∪ H. This yields to a contradiction.

slide-97
SLIDE 97

Looking for the free dimension of a Banach Space

slide-98
SLIDE 98

Is it possible to define the free dimension of a Banach space in such a way that

1 free-dim(Y ) ≤ free-dim(X) whenever Y is a subspace of X

slide-99
SLIDE 99

Is it possible to define the free dimension of a Banach space in such a way that

1 free-dim(Y ) ≤ free-dim(X) whenever Y is a subspace of X or Y

is a quotient of X;

slide-100
SLIDE 100

Is it possible to define the free dimension of a Banach space in such a way that

1 free-dim(Y ) ≤ free-dim(X) whenever Y is a subspace of X or Y

is a quotient of X;

2 free-dim(C(L1 × . . . × Ld)) ≤ d for every compact lines L1, . . . , Ld;

slide-101
SLIDE 101

Is it possible to define the free dimension of a Banach space in such a way that

1 free-dim(Y ) ≤ free-dim(X) whenever Y is a subspace of X or Y

is a quotient of X;

2 free-dim(C(L1 × . . . × Ld)) ≤ d for every compact lines L1, . . . , Ld; 3 free-dim(C(K1 × . . . × Kd)) ≥ d whenever K1, . . . , Kd are

nonmetrizable compact spaces.

slide-102
SLIDE 102

Motivation

1 A. Michalak in 2018 proved that if L1, . . . , Ld and K1, . . . , Kd+1 are

nonmetrizable separable compact lines then C(K1 × . . . Kd+1) is not isomorphic to a subspace neither a quotient of C(L1 × . . . × Ld).

slide-103
SLIDE 103

Motivation

1 A. Michalak in 2018 proved that if L1, . . . , Ld and K1, . . . , Kd+1 are

nonmetrizable separable compact lines then C(K1 × . . . Kd+1) is not isomorphic to a subspace neither a quotient of C(L1 × . . . × Ld). Can the separability assumption be dropped?

slide-104
SLIDE 104

Motivation

1 A. Michalak in 2018 proved that if L1, . . . , Ld and K1, . . . , Kd+1 are

nonmetrizable separable compact lines then C(K1 × . . . Kd+1) is not isomorphic to a subspace neither a quotient of C(L1 × . . . × Ld). Can the separability assumption be dropped?

2 S. Banach suggested that “natural” spaces of functions of different

numbers of variables should be nonisomorphic.

slide-105
SLIDE 105

Motivation

1 A. Michalak in 2018 proved that if L1, . . . , Ld and K1, . . . , Kd+1 are

nonmetrizable separable compact lines then C(K1 × . . . Kd+1) is not isomorphic to a subspace neither a quotient of C(L1 × . . . × Ld). Can the separability assumption be dropped?

2 S. Banach suggested that “natural” spaces of functions of different

numbers of variables should be nonisomorphic.

It is known that the spaces C1([0, 1]) and C1([0, 1]d) are nonisomorphic whenever d ≥ 2.

slide-106
SLIDE 106

Motivation

1 A. Michalak in 2018 proved that if L1, . . . , Ld and K1, . . . , Kd+1 are

nonmetrizable separable compact lines then C(K1 × . . . Kd+1) is not isomorphic to a subspace neither a quotient of C(L1 × . . . × Ld). Can the separability assumption be dropped?

2 S. Banach suggested that “natural” spaces of functions of different

numbers of variables should be nonisomorphic.

It is known that the spaces C1([0, 1]) and C1([0, 1]d) are nonisomorphic whenever d ≥ 2. Nevertheless, it is an open problem if C1([0, 1]2) and C1([0, 1]d) are isomorphic for some d > 2.

slide-107
SLIDE 107

Motivation

1 A. Michalak in 2018 proved that if L1, . . . , Ld and K1, . . . , Kd+1 are

nonmetrizable separable compact lines then C(K1 × . . . Kd+1) is not isomorphic to a subspace neither a quotient of C(L1 × . . . × Ld). Can the separability assumption be dropped?

2 S. Banach suggested that “natural” spaces of functions of different

numbers of variables should be nonisomorphic.

It is known that the spaces C1([0, 1]) and C1([0, 1]d) are nonisomorphic whenever d ≥ 2. Nevertheless, it is an open problem if C1([0, 1]2) and C1([0, 1]d) are isomorphic for some d > 2. It is known that the spaces A(D) and A(Dd) are nonisomorphic whenever d ≥ 2.

slide-108
SLIDE 108

Motivation

1 A. Michalak in 2018 proved that if L1, . . . , Ld and K1, . . . , Kd+1 are

nonmetrizable separable compact lines then C(K1 × . . . Kd+1) is not isomorphic to a subspace neither a quotient of C(L1 × . . . × Ld). Can the separability assumption be dropped?

2 S. Banach suggested that “natural” spaces of functions of different

numbers of variables should be nonisomorphic.

It is known that the spaces C1([0, 1]) and C1([0, 1]d) are nonisomorphic whenever d ≥ 2. Nevertheless, it is an open problem if C1([0, 1]2) and C1([0, 1]d) are isomorphic for some d > 2. It is known that the spaces A(D) and A(Dd) are nonisomorphic whenever d ≥ 2.

slide-109
SLIDE 109

Motivation

1 A. Michalak in 2018 proved that if L1, . . . , Ld and K1, . . . , Kd+1 are

nonmetrizable separable compact lines then C(K1 × . . . Kd+1) is not isomorphic to a subspace neither a quotient of C(L1 × . . . × Ld). Can the separability assumption be dropped?

2 S. Banach suggested that “natural” spaces of functions of different

numbers of variables should be nonisomorphic.

It is known that the spaces C1([0, 1]) and C1([0, 1]d) are nonisomorphic whenever d ≥ 2. Nevertheless, it is an open problem if C1([0, 1]2) and C1([0, 1]d) are isomorphic for some d > 2. It is known that the spaces A(D) and A(Dd) are nonisomorphic whenever d ≥ 2. Nevertheless, it is an open problem if A(D2) and A(Dd) are isomorphic for some d > 2.

slide-110
SLIDE 110

Motivation

1 A. Michalak in 2018 proved that if L1, . . . , Ld and K1, . . . , Kd+1 are

nonmetrizable separable compact lines then C(K1 × . . . Kd+1) is not isomorphic to a subspace neither a quotient of C(L1 × . . . × Ld). Can the separability assumption be dropped?

2 S. Banach suggested that “natural” spaces of functions of different

numbers of variables should be nonisomorphic.

It is known that the spaces C1([0, 1]) and C1([0, 1]d) are nonisomorphic whenever d ≥ 2. Nevertheless, it is an open problem if C1([0, 1]2) and C1([0, 1]d) are isomorphic for some d > 2. It is known that the spaces A(D) and A(Dd) are nonisomorphic whenever d ≥ 2. Nevertheless, it is an open problem if A(D2) and A(Dd) are isomorphic for some d > 2. It is known that the spaces F(R) and F(Rd) are nonisomorphic whenever d ≥ 2.

slide-111
SLIDE 111

Motivation

1 A. Michalak in 2018 proved that if L1, . . . , Ld and K1, . . . , Kd+1 are

nonmetrizable separable compact lines then C(K1 × . . . Kd+1) is not isomorphic to a subspace neither a quotient of C(L1 × . . . × Ld). Can the separability assumption be dropped?

2 S. Banach suggested that “natural” spaces of functions of different

numbers of variables should be nonisomorphic.

It is known that the spaces C1([0, 1]) and C1([0, 1]d) are nonisomorphic whenever d ≥ 2. Nevertheless, it is an open problem if C1([0, 1]2) and C1([0, 1]d) are isomorphic for some d > 2. It is known that the spaces A(D) and A(Dd) are nonisomorphic whenever d ≥ 2. Nevertheless, it is an open problem if A(D2) and A(Dd) are isomorphic for some d > 2. It is known that the spaces F(R) and F(Rd) are nonisomorphic whenever d ≥ 2. Nevertheless, it is an open problem if F(R2) and F(Rd) are isomorphic for some d > 2.

slide-112
SLIDE 112

References

G.M.C., G. Plebanek, The Mardeˇ si´ c Conjecture and Free Products of Boolean Algebras.

  • Proc. Amer. Math. Soc. 147 (4) (2019), 1763–1772.