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Plan 2 Outline: Basic definitions and facts Relation between L p , - - PowerPoint PPT Presentation
Plan 2 Outline: Basic definitions and facts Relation between L p , - - PowerPoint PPT Presentation
Function spaces L p Updated April 22, 2020 Plan 2 Outline: Basic definitions and facts Relation between L p , interpolation of norms Uniform convexity of L p with 1 p 8 Projections on closed convex sets Peculiarities of L p -spaces with
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Definition
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Definition Given measure space pX, F, µq, for p P p0, 8q let LppX, F, µq :“ ! f : X Ñ R: F-measurable ^ ż |f|pdµ ă 8 ) . For p :“ 0 we set L0pX F, µq :“
- f : X Ñ R: F-measurable
( and for p :“ 8 we let L8pX F, µq :“ ! f P L0 : ` DM P r0, 8q: µp|f| ą Mq “ 0q ˘) Alternative notations: Lp, Lppµq or LppXq When X is countable and µ is the counting measure: ℓppXq
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Vector space
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Lemma For each p P r0, 8s and each a, b P R, f, g P Lp ñ af ` bg P Lp. In particular, Lp is a vector space over R. Integrability condition: use |f ` g|p ď 2p|f|p ` 2p|g|p
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Lp-norm
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Lemma For f P L0 and for p P r1, 8q let }f}p :“ ´ ż |f|pdµ ¯1{p and for p :“ 8 set }f}8 :“ inf
- M P r0, 8q: µp|f| ą Mq “ 0
( Then } ¨ }p is a seminorm on Lp such that }f}p “ 0 ñ f “ 0 µ-a.e. In particular, } ¨ } is the norm on trfs: f P Lpu where rfs :“ tg P Lp : g “ f µ-a.e.u and }rfs}p :“ }f}p.
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Proof
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Homogeneity checked directly. For triangle inequality, we proceed by showing: Young’s inequality: @α P r0, 1s @x, y P r0, 8q: xαy1´α ď αx ` p1 ´ αqy H¨
- lder’s inequality: @f, g P L0 @p, q P r1, 8s:
1 p ` 1 q “ 1 ñ ż |fg|dµ ď }f}p}g}q. Minkowski’s inequality: @p P r1, 8q @f, g P Lp : } f ` g}p ď }f}p ` }g}p The case of p “ 8 is checked directly or via limits using @f P L0 : lim
pÑ8 }f}p “ }f}8
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Banach space structure
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Theorem (Completeness of Lp-spaces) For each p P r1, 8s and any tfnuně1 Ď Lp that is Cauchy in the sense lim
NÑ8 sup m,něN
}fn ´ fm}p “ 0 there exists f P Lp such that lim
nÑ8 }fn ´ f}p “ 0.
Moreover, we then have }f}p “ lim
nÑ8 }fn}p
where the limit on the right exists.
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Proof
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Assume p ă 8, pick tnkukě1 with supm,něnk }fn ´ fm}p ď 2´k. Define Fn :“
n
ÿ
k“1
|fnk`1 ´ fnk| ^ F :“ ÿ
kě1
|fnk`1 ´ fnk| Then }Fn}p ď 1 and, by Fatou’s lemma, }F}p ď 1. So F ă 8 µ-a.e. and so f :“ fn1 ` ÿ
kě1
` fnk`1 ´ fnk ˘ absolutely convergent µ-a.e. Telescoping: fnk Ñ f µ-a.e. and so, by Fatou again, }fnk}p Ñ }f}p and }f ´ fnk}p ď lim sup
jÑ8
}fnj ´ fnk}p ď 2´k This gives fn Ñ f in Lp. The case p “ 8 checked directly.
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Two corollaries
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Corollary If fn Ñ f in Lppµq then there exists a subsequence tnkukě1 such that sup
kě1
|fnk| P Lppµq and fnk Ý Ñ
kÑ8 f µ-a.e.
Corollary For each p P r1, 8s, the space trfs: f P Lpu endowed with norm } ¨ }p is a complete normed vector space a.k.a. Banach space.
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Relations between Lp-spaces
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Lemma Let Lp “ LppX, F, µq. (1) If µ is finite then p ÞÑ Lp is non-increasing, @p, r P r0, 8s: p ă r ñ Lr Ď Lp (2) If X is countable and µ is the counting measure, then p ÞÑ ℓppXq is non-decreasing, @p, r P r0, 8s: p ă r ñ ℓppXq Ď ℓrpXq Neither of these hold in general measure spaces but we have @p, q, r P p0, 8s: q ă p ă r ñ Lp Ď Lq ` Lr where Lq ` Lr :“ tf ` g: f P Lq ^ g P Lru.
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Proof
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If µ finite, @p ą q ą 0: }f}q ď µpXq1{q´1{p }f}p so p ÞÑ Lp is non-increasing. For X countable and µ the counting measure, @r ą p ą 0: }f}r ď }f}1´p{r
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}f}p{r
p
so p ÞÑ ℓppXq is non-decreasing. For general case: f “ f1t|f|ě1u ` f1t|f|ď1u and use above for the parts.
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Interpolation of p-norms
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Lemma For any q, p, r P p0, 8s with q ă p ă r we have }f}p ď }f}α
q}f}1´α r
where α P p0, 1q is the unique number such that 1 p “ α q ` 1 ´ α r . In particular, Lq X Lr Ď Lp. Proof: ż |f|pdµ “ ż |f|αp |f|p1´αqpdµ ď }f αp} q
αp }f p1´αqp} r p1´αqp
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Uniform convexity
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Definition A normed linear space V is uniformly convex if for each ǫ ą 0 there is δ ą 0 such that for all x, y P V with }x} “ 1 “ }y}, }x ´ y} ě ǫ ñ › › ›x ` y 2 › › › ď 1 ´ δ Says that unit ball is strictly convex and “uniformly curved”. Fails in L1 and L8, but: Theorem (Clarkson 1936) For each p P p1, 8q, the normed linear space Lp is uniformly convex. Proof based on Clarkson’s inequalities. We will follow the proof by O. Hanner (1956)
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Hanner’s inequalities
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Lemma For all p P r1, 2s and all f, g P Lp, we have }f ` g}p
p ` }f ´ g}p p ě
` }f}p ` }g}p ˘p ` ˇ ˇ}f}p ´ }g}p ˇ ˇp and 2p` }f}p
p ` }g}p p
˘ ě ` }f ` g}p ` }f ´ g}p ˘p ` ˇ ˇ}f ` g}p ´ }f ´ g}p ˇ ˇp The inequalities are reversed for p P r2, 8q. Note: 2nd inequality obtained from 1st by subs f Ñ f ` g ^ g Ñ f ´ g Generalize parallogram law for p “ 2
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Proof: main steps
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Suppose p P r1, 2s (for p P r2, 8q all inequalities reversed). Key identity: @t P r0, 1s @u, v P R: |u ` v|p ` |u ´ v|p ě aptq|u|p ` bptq|v|p where aptq :“ p1 ` tqp´1 ` p1 ´ tqp´1 and bptq :“ “ p1 ` tqp´1 ´ p1 ´ tqp´1‰ t1´p Proved by calculus. Apply to u “ fpxq and v “ gpxq and integrate: }f ` g}p
p ` }f ´ g}p p ě aptq}f}p p ` bptq}g}p p
As aptq ` bptqtp “ p1 ` tqp ` p1 ´ tqp, setting t :“ }g}p{}f}p we then get the result.
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Proof of uniform convexity
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Suppose p P r2, 8q. For }f}p “ }g}p “ 1, the 1st inequality gives › › ›f ` g 2 › › ›
p ď
ˆ 1 ´ }f ´ g}p
p
2p ˙1{p so claim holds with δ :“ 1 ´ p1 ´ pǫ{2qpq1{p For p P r1, 2s assume WLOG }f ` g}p ě }f ´ g}p. The 2nd inequality gives 2p`1 ě }f ` g}p
p h
´}f ´ g}p }f ` g}p ¯ where hpxq :“ p1 ` xqp ` p1 ´ xqp. Calculus shows hpxq ě 2 ` cppqx2 where cppq :“ ppp ´ 1q This gives › › ›f ` g 2 › › ›
p ď
´ 1 ` cppq 8 }f ´ g}2
p
¯´1 and claim follows with δ :“ 1 ´ p1 ´ 1
8cppqǫ2q´1.
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Projections on closed convex sets
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Proposition (Projection on closed convex subsets) Let p P p1, 8q and let C Ď Lp be non-empty and convex, i.e., @f, g P C @α P r0, 1s: αf ` p1 ´ αqg P C and closed (i.e., with all Lp-Cauchy sequences in C convergent in C). Let f P Lp C. Then C contains an element that is closest to f, Dh P C: }f ´ h}p “ inf
gPC }f ´ g}p
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Proof of Proposition
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By shift suppose f “ 0 and C Ď Lp closed convex with 0 R C. Let thnuně1 be s.t. lim
nÑ8 }hn}p “ inf gPC }g}p
Convexity of C ensures }hn}p ` }hm}p 2 ě › › ›hn ` hm 2 › › ›
pě inf gPC }g}p
So lim
NÑ8
sup
m,něN
› › ›hn ` hm 2 › › ›
p“ inf gPC }g}p
For normalized functions h1
n :“ hn{}hn}p this implies
lim
NÑ8 sup m,něN
› › ›h1
n ` h1 m
2 › › ›
p“ 1
Uniform convexity: th1
nuně1 Cauchy and thus convergent in Lp.
Then: thnuně1 convergent to some h P C, }h}p “ infgPC }g}p.
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Lp-spaces with 0 ă p ă 1
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Lemma (Reverse Minkowski inequality) For each p P p0, 1q, we have @f, g P Lp : › ›|f| ` |g| › ›
p ě }f}p ` }g}p
The inequality is strict whenever µpf ¨ g ‰ 0q ą 0. Proof: As x ÞÑ xp concave, so for a, b ě 0, t P p0, 1q: pa ` bqp “ ´ ta t ` p1 ´ tq b 1 ´ t ¯p ě t1´pap ` p1 ´ tq1´tbp True for t “ 0, 1 by continuity, strict if a, b ą 0 and t P p0, 1q. Now set a :“ |fpxq|, b :“ |gpxq| and integrate to get }|f| ` |g|}p
p ě t1´p}f}p p ` p1 ´ tq1´p}g}p
Finally, take t :“ }f}p{p}f}p ` }g}pq.
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Lp (still) a complete metric space
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Lemma For p P p0, 1q and f, g P Lppµq, define ̺ppf, gq :“ }f ´ g}p
p “
ż |f ´ g|pdµ Then ̺p is a pseudometric with ̺ppf, gq “ 0 ô f “ g µ-a.e. In particular, ̺p is a metric on the factor space trfs: f P Lpu and the resulting metric space is complete. Proof: Triangle inequality because @a, b ě 0: pa ` bqp ď ap ` bp Completness: same argument as for p ě 1.
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Convexity curse
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Ball in Lp, 0 ă p ă 1, not convex! Proposition Let p P p0, 1q and consider the Lp space over pX, F, µq such that for each δ ą 0 there are disjoint tAnuně1 Ď F such that X “ ď
ně1
An ^ sup
ně1
µpAnq ă δ Then every open, convex subset of pLp, ̺pq is either empty or Lp itself Convexity = algebra, open = topology so: Lp cannot be remetrized to a locally-convex vector space (let alone Banach space)
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Proof
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U Ď Lp non-empty, convex, 0 P U by shift. As U open, there is r ą 0 s.t. Bp0, rq Ď U. Let f P Lp non-zero. Set θ :“ 1{}f}p
- p. Integrability of |f|p +
assumption on measure space ñ DtAnuně1 partition s.t. @n ě 1: ż
An
|f|pdµ ă 1 θ prθq
1 1´p
Dominated Convergence: DN ě 1 ż
Ť
něN An
|f|p dµ ă 1 θ prθq
1 1´p
Set A1
n :“ An for n ă N and A1 N :“ Ť něN An and . . .
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Proof continued
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. . . let αn :“ θ ż
A1
n
|f|pdµ, and set hn :“ # α´1
n 1A1
n f,
if αn ‰ 0, 0, else. Then řN
n“1 αn “ 1 and αn ă prθq
1 1´p . Now
̺pp0, hnq “ 1 αp
n
ż
A1
n
|f|pdµ “ α1´p
n
θ ă rθ θ “ r and so hn P Bp0, rq Ď U. But U is convex and f “
N
ÿ
n“1
αnhn. so f P U as well. Hence U “ Lp.
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No continuous linear functions on Lp!
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Corollary Let p P p0, 1q. Under the condition on pX, F, µq in Proposition, LppX, F, µq admits no non-constant continuous convex (and, in particular, linear) functional. Proof: If φ: Lp Ñ R is a convex continuous map then tf P Lp : φpfq ă au is open and convex. Analysis without continuous linear function hard . . . On ℓppNq continuous linear functionals exist but they are (unique) extensions of those on ℓ1pNq, which is dense in ℓppNq.
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Space L0
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Endow with convergence in measure defined by µp|fn ´ f| ą ǫq Ñ 0 @ǫ ą 0. For µ finite, topology defined by neighborhoods:
- h P L0 : µp|h ´ f| ą ǫq ă ǫ
( indexed by f P L0 and ǫ ą 0. Metrized by Ky Fan metric: ̺0pf, gq :“ inf
- ǫ ě 0: µp|f ´ g| ą ǫq ď ǫ
( Lemma Suppose µ is finite. Then ̺0 is a pseudo-metric on L0 and is a metric
- n the factor space trfs: f P L0u. The factor space is complete.
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Special role of L2
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Norm } ¨ }2 arises from inner product xf, gy :“ ż fg dµ. via }f}2 “ xf, fy1{2. (Conjugate g if over C.) Paralellogram law (p “ 2 version of Hanner’s inequality): @f, g P L2 : }f ` g}2
2 ` }f ´ g}2 2 “ 2}f}2 2 ` 2}g}2 2
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Special role of L2 continued ...
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Inner product reconstructed from norm: Lemma (Polarization identity) In L2-spaces over R, for all f, g P L2 we have xf, gy “ 1 2}f ` g}2
2 ´ 1
2}f ´ g}2
2
In L2-spaces over C, we instead have xf, gy “ 1 4}f ` g}2
2 ´ 1
4}f ´ g}2
2 ` i
4}f ` ig}2
2 ´ i
4}f ´ ig}2
2
Proof: Plug in formula for norm using inner product
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