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On the strength of Hindmans Theorem for bounded sums of unions Lorenzo Carlucci Department of Computer Science University of Rome I September 2017 Wormshop 2017 Moscow, Steklov Institute Lorenzo Carlucci (Rome I) Moscow, September 2017 1


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On the strength of Hindman’s Theorem for bounded sums of unions

Lorenzo Carlucci

Department of Computer Science University of Rome I

September 2017 Wormshop 2017 Moscow, Steklov Institute

Lorenzo Carlucci (Rome I) Moscow, September 2017 1 / 22

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Outline

1

Hindman’s Finite Sums Theorem

2

Bounded Sums

3

Weak Yet Strong Principles

4

From Hindman to Ramsey

5

Other variants

Lorenzo Carlucci (Rome I) Moscow, September 2017 2 / 22

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Hindman’s Finite Sums Theorem

Theorem (Hindman, 1972)

Whenever the positive integers are colored in finitely many colors there is an infinite set such that all non-empty finite sums of distinct elements drawn from that set have the same color. Original proof is combinatorial but intricate. Later proofs are simpler but use strong methods (ultrafilters or ergodic theory). Question, ’80s What is the strength of Hindman’s Theorem?

Lorenzo Carlucci (Rome I) Moscow, September 2017 3 / 22

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Measures of Strength

HTk = ∀ c : N → k

  • instance

∃ X ⊆ N

solution

(|X| = ℵ0 and FS(X) is mono) HT = ∀kHTk

Reverse Mathematics: provability in the systems RCA0, WKL0, ACA0, ACA′

0, ACA+ 0 , . . .

  • r (mutual) implications over the base theory RCA0.

Computable Mathematics: complexity of solutions for computable instances. RM and CM: computable reducibility to/from other principles.

Lorenzo Carlucci (Rome I) Moscow, September 2017 4 / 22

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Lower Bound on Hindman’s Theorem HT ≥ ∅(1), RT3

2, ACA0

Theorem (Blass, Hirst, Simpson 1987)

1

Some computable (resp. computable in X) 2-coloring of N admits

  • nly solutions to HT2 that compute ∅(1) (resp. X ′ – the jump of X).

2

RCA0 + HT2 ⊢ ACA0. Proof is by coding of the Halting Set and formalizes in RCA0. Uses the notion of gap, the interval between two successive exponents of a number in base 2.

Lorenzo Carlucci (Rome I) Moscow, September 2017 5 / 22

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Upper Bound on Hindman’s Theorem ACA+

0 , ∅(ω+1) ≥ HT

Theorem (Blass, Hirst, Simpson 1987)

1

Any finite computable (resp. computable in X) coloring of N admits a solution to HT computable in ∅(ω+1) (resp. in X (ω+1)).

2

ACA+

0 ⊢ HT.

ACA+

0 is ACA0 plus ∀X∃Y(Y = X (ω)).

Proof is by analyzing the original proof by Hindman. Ultrafilter and ergodic proofs give worse bounds (so far).

Lorenzo Carlucci (Rome I) Moscow, September 2017 6 / 22

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Bounded Sums

Question (Blass, 2005) Does the complexity of HT grow with the length of the sums? Is it the case that longer sums require more jumps? FS(X) = sums of finitely many distinct elements of X. FS≤n(X) = sums of 1, 2, . . . , n distinct elements of X. HT≤n

k

= the restriction of HT to k colors and sums of length ≤ n.

HT≤n

k , HT≤n

Lorenzo Carlucci (Rome I) Moscow, September 2017 7 / 22

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Lower Bounds for bounded sums HT≤3 ≥ ∅(1), RT3

2, ACA0

Theorem (Dzhafarov, Jockusch, Solomon, Westrick, 2017)

1

RCA0 + HT≤3

3

⊢ ACA0.

2

RCA0 HT≤2

2 , and RCA0 + RT1 + HT≤2 2

⊢ SRT2

2.

SRT2

2 is the Stable Ramsey’s Theorem (WKL0 SRT2 2).

Proof of (1): modification of Blass-Hirst-Simpson’s argument. Proof of (2): Given a ∆0

2-set A define a coloring all of whose

solutions compute an infinite subset of A or an infinite set disjoint from A. Formalization requires RT1 (eq. BΣ0

2).

Lorenzo Carlucci (Rome I) Moscow, September 2017 8 / 22

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Upper bounds for bounded sums?

Question (Hindman, Leader and Strauss, 2003) Is there a proof that whenever N is finitely coloured there is a sequence x1, x2, . . . such that all xi and all xi + xj (i = j) have the same colour, that does not also prove the Finite Sums Theorem? Does HT≤2 imply HT over RCA0? Can we upper bound HT≤2 below ACA+

0 ?

Are there natural Hindman-type principles with:

1

Non-trivial lower bounds, and

2

Upper bounds strictly below HT?

We call such principles Weak Yet Strong.

Lorenzo Carlucci (Rome I) Moscow, September 2017 9 / 22

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A brute force proof using Ramsey

Given c : N → 2,

  • 1. Use RT1

2 on N wrt c to get an infinite homset H1.

  • 2. Use RT2

2 on H1 wrt f2(x, y) := c(x + y) to fix the color of sums of

length 2 on an infinite H2 ⊆ H1. . . .

  • k. Use RTk

2 on Hk−1 wrt fk(x1, . . . , xk) := c(x1 + · · · + xk) to fix the

color of sums of length k on an infinite Hk ⊆ Hk−1. This induces a coloring d : [1, k] → 2, where d(i) is the c-color of sums

  • f length i from Hk.

If k is large, then d has some interesting homogeneous set! E.g. if k ≥ 6 then by Schur’s Theorem there exists a, b > 0 such that d(a) = d(b) = d(a + b).

Lorenzo Carlucci (Rome I) Moscow, September 2017 10 / 22

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Hindman-Schur Theorem

FSA(X): sums of j-many distinct elements of X for any j ∈ A. Hindman-Schur Theorem: Whenever the positive integers are colored in two colors there exist positive integers a, b and an infinite set H such that FS{a,b,a+b}(H) is monochromatic.

Theorem (C., 2017)

Hindman-Schur Theorem is provable in ACA0. A host of similar Hindman-type theorems based on different finite combinatorial principles (e.g., Van Der Waerden, Folkman, etc.). All provable in ACA0. What about lower bounds?

Lorenzo Carlucci (Rome I) Moscow, September 2017 11 / 22

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Hindman-Schur with apartness

The Blass-Hirst-Simpson’s lower bound proof works, if we impose that the solution set satisfies the following Apartness Condition, for t = 2.

Definition (t-Apartness)

Fix a base t ≥ 2. A set X ⊆ N satisfies the t-apartness condition if x < x′ ⇒ µt(x) < λt(x′). λt(x) = least exponent in base t representation of n. µt(x) = maximal exponent in base t representation of n. P with t-apartness = P with t-apartness on the solution set.

Theorem (C., Kołodziejczyk, Lepore, Zdanowski, 2017)

Hindman-Schur with 2-apartness is equivalent to ACA0 (over RCA0).

Lorenzo Carlucci (Rome I) Moscow, September 2017 12 / 22

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The Apartness Condition

Imposing apartness is a self-strenghtening of Hindman’s Theorem: RCA0 ⊢ HT ≡ HT with apartness. For restricted versions we have the following:

Proposition (C., Kołodziejczyk, Lepore, Zdanowski, 2017)

RCA0 + HT≤n

2k ⊢ HT≤n k

with 3-apartness. Proof: Give c : N → 2, let d : N → 4: d(n) :=

  • c(n)

if n = 3t + . . . , 2 + c(n) if n = 2 · 3t + . . . . If FS≤2(H) is monochromatic for d then:

1

all elements have same first coefficient. Then:

2

no two elements of H can have the same first exponent.

Lorenzo Carlucci (Rome I) Moscow, September 2017 13 / 22

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Bounded Unions

Let FUT≤n

k

and FUT=n

k

the versions of Hindman’s Theorem in terms of unions instead of sums.

Proposition

For each n, kt ≥ 2, HT≤n

k

with t-apartness is equivalent to FUT≤n

k

  • ver
  • RCA0. Moreover, these principles are mutually strongly computably
  • reducible. The same equivalences hold for HT=n

k

with t-apartness and FUT=n

k .

Lorenzo Carlucci (Rome I) Moscow, September 2017 14 / 22

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Restricted Hindman and Polarized Ramsey

Recall that Dzhafarov et alii proved RCA0 + HT≤2 + RT1 ⊢ SRT2

2

We improve by showing that RCA0 + HT≤2 ⊢ IPT2

2

Definition (Dzhafarov and Hirst, 2011)

IPT2

2: For all f : [N]2 → 2 there exists a pair of infinite sets (H1, H2)

such that all increasing pairs {x1, x2} with xi ∈ Hi get the same f-color. RT2

2 ≥ IPT2 2 > SRT2 2

Lorenzo Carlucci (Rome I) Moscow, September 2017 15 / 22

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Restricted Hindman and Polarized Ramsey

In fact we get that IPT2

2 is strongly computably reducible to HT≤2 4 :

any f : [N]2 → 2 of IPT2

2 computes an instance c : N → 2 of HT≤2 4

s.t. any solution to HT≤2

4

for c computes a solution to IPT2

2 for f.

Theorem (C., 2017)

RCA0 + HT≤2

4

⊢ IPT2

  • 2. Moreover, IPT2

2 ≤sc HT≤2 4 .

HT=n

k

= restriction of HTk to sums of exactly n elements. In fact we show:

Theorem (C., 2017)

RCA0 + HT=2

2

with t-apartness ⊢ IPT2

  • 2. Moreover, IPT2

2 ≤sc HT=2 2

with t-apartness. N.B. RT2

2 proves HT=2 2

with t-apartness.

Lorenzo Carlucci (Rome I) Moscow, September 2017 16 / 22

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IPT2

2 ≤sc HT=2 2

with 2-apartness

Given f : [N]2 → 2, let g : N → 2: g(n) :=

  • if n = 2t,

f(λ(n), µ(n))

  • therwise.

Let H = {h1 < h2 < h3 < . . . } be an infinite and 2-apart set such that g is constant on FS=2(H). Then λ(h1) ≤ µ(h1) < λ(h2) ≤ µ(h2) < λ(h3) ≤ µ(h3) < . . . So if H1 := {λ(h1), λ(h3), λ(h5), . . . , } H2 := {µ(h2), µ(h4), µ(h6), . . . , } Then (H1, H2) is a solution to IPT2

2 for f.

Lorenzo Carlucci (Rome I) Moscow, September 2017 17 / 22

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Sums of length 2 and ACA0 HT≤2 ≥ ∅(1), RT3

2, ACA0

Recall that Dzhafarov et alii proved RCA0 + HT≤3 ⊢ ACA0.

Theorem (C., Kołodziejczyk, Lepore, Zdanowski, 2017)

RCA0 + HT≤2 ⊢ ACA0.

Proposition (C., Kołodziejczyk, Lepore, Zdanowski, 2017)

For t ≥ 2, RCA0 + HT≤2

2

with t-apartness ⊢ ACA0.

Lorenzo Carlucci (Rome I) Moscow, September 2017 18 / 22

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HT≤2

2

with apartness implies ACA0

Let f : N → N be 1:1. Let n = 2n0 + · · · + 2nr , (n0 < · · · < nr). Consider f ↾ [0, n0), f ↾ [n0, n1), . . . , f ↾ [nr−1, nr). Call j ≤ r important in n iff some value of f ↾ [nj−1, nj) is below n0. (n−1 := 0). c(n) := parity of the number of important js in n. Let H be infinite, 2-apart and FS≤2(H) mono. Claim: for each n ∈ H and each x < λ(n), x ∈ rg(f) if and only if x ∈ rg(f ↾ µ(n)). Gives a computable definition of rg(f): given x, find the smallest n ∈ H such that x < λ(n) and check whether x is in rg(f ↾ µ(n)).

Lorenzo Carlucci (Rome I) Moscow, September 2017 19 / 22

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HT=n

k

with apartness and ACA0

By improving the proof we get the following:

Proposition (C., Kołodziejczyk, Lepore, Zdanowski, 2017)

For every t ≥ 2, RCA0 + HT=3

2

with t-apartness ⊢ ACA0. Therefore {HT=n

k

with 2-apartness ; n ≥ 3, k ≥ 2} is a weak yet strong family.

Corollary (C., Kołodziejczyk, Lepore, Zdanowski, 2017)

For every n ≥ 3 and k ≥ 2, HT=n

k

with 2-apartness ≡ ACA0

  • ver RCA0.

Lorenzo Carlucci (Rome I) Moscow, September 2017 20 / 22

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Open Problems

Can we upper bound HT≤2

2

strictly below ACA+

0 ?

Is HT≤2

2

provable in ACA0? Do colors matter? How? Does apartness increase strength in the bounded cases? Which implications are witnessed by reductions? E.g. Does IPT3

2 ≤sc HT≤3 2 ?

Lorenzo Carlucci (Rome I) Moscow, September 2017 21 / 22

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Bibliography

1

  • A. Blass. Some questions arising from Hindman’s Theorem. Sci. Math. Jpn., 62 (2005),

331–334.

2

  • A. R. Blass, J.L. Hirst, S. G. Simpson. Logical analysis of some theorems of combinatorics

and topological dynamics. In: Logic and combinatorics, Contemp. Math., vol. 65, pp. 125–156. AMS, 1987.

3

  • L. Carlucci. A weak variant of Hindman’s Theorem stronger than Hilbert’s Theorem. To

appear in Archive for Mathematical Logic.

4

  • L. Carlucci. Weak Yet Strong restrictions of Hindman’s Finite Sums Theorem. To appear in

Proceedings of the AMS.

5

  • L. Carlucci, L. A. Kołodziewczyk, F. Lepore, K. Zdanowski, New bounds on restrictions of

Hindman’s Finite Sums Theorem, arXiv:1701.06095.

6

  • D. Dzhafarov, C. Jockusch, R. Solomon, L. B. Westrick. Effectiveness of Hindman’s

Theorem for bounded sums. In Proceedings of the International Symposium on Computability and Complexity, 2017.

7

  • N. Hindman. Finite sums from sequences within cells of a partition of N. Journal of

Combinatorial Theory Series A 17 (1974), 1–11.

8

  • N. Hindman, I. Leader, and D. Strauss. Open problems in partition regularity.

Combinatorics Probability and Computing 12 (2003), 571–583.

Lorenzo Carlucci (Rome I) Moscow, September 2017 22 / 22