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Normalized Polish Expression Draw slicing floorplan based on: - PowerPoint PPT Presentation

Normalized Polish Expression Draw slicing floorplan based on: Initial PE: P 1 = 25V1H374VH6V8VH Dimensions: (2,4), (1,3), (3,3), (3,5), (3,2), (5,3), (1,2), (2,4) Practical Problems in VLSI Physical Design Polish Expression (1/8) M1


  1. Normalized Polish Expression � Draw slicing floorplan based on: � Initial PE: P 1 = 25V1H374VH6V8VH � Dimensions: (2,4), (1,3), (3,3), (3,5), (3,2), (5,3), (1,2), (2,4) Practical Problems in VLSI Physical Design Polish Expression (1/8)

  2. M1 Move � Swap module 3 and 7 in P 1 = 25V1H374VH6V8VH � We get: P 2 = 25V1H734VH6V8VH � Area changed from 11 × 15 to 13 × 14 Practical Problems in VLSI Physical Design Polish Expression (2/8)

  3. Change on Floorplan Practical Problems in VLSI Physical Design Polish Expression (3/8)

  4. M2 Move � Complement last chain in P 2 = 25V1H734VH6V8VH � We get: P 3 = 25V1H734VH6V8HV � Area changed from 13 × 14 to 15 × 11 Practical Problems in VLSI Physical Design Polish Expression (4/8)

  5. Change on Floorplan Practical Problems in VLSI Physical Design Polish Expression (5/8)

  6. M3 Move � Swaps 6 and V in P 3 = 25V1H734VH6V8HV � We get: P 4 = 25V1H734VHV68HV � Area changed from 15 × 11 to 15 × 7 Practical Problems in VLSI Physical Design Polish Expression (6/8)

  7. Change on Floorplan Practical Problems in VLSI Physical Design Polish Expression (7/8)

  8. Initial Temperature Calculation � What is average change on cost function? � Initial temperature with acceptance probability 0.9? Practical Problems in VLSI Physical Design Polish Expression (8/8)

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