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Neutron-Antineutron Oscillation: Theoretical Status and Experimental Prospects Bhupal Dev First Nuclear and Particle Theory Meeting Washington University in St. Louis March 12, 2019 Too crazy? But neutral meson |qq states oscillate - 2 nd


  1. Neutron-Antineutron Oscillation: Theoretical Status and Experimental Prospects Bhupal Dev First Nuclear and Particle Theory Meeting Washington University in St. Louis March 12, 2019

  2. Too crazy? But neutral meson |qq 〉 states oscillate - 2 nd order weak interactions K 0 , B 0 K 0 , B 0 2

  3. Too crazy? But neutral meson |qq 〉 states oscillate - 2 nd order weak interactions K 0 , B 0 K 0 , B 0 And neutral fermions can oscillate too - … ν µ ν τ 2

  4. Too crazy? But neutral meson |qq 〉 states oscillate - 2 nd order weak interactions K 0 , B 0 K 0 , B 0 And neutral fermions can oscillate too - … ν µ ν τ So why not - New ? n n physics 2

  5. Conservation of Baryon Number In the Standard Model (SM), conservation of baryon number forbids a neutron ( B = 1 ) from transforming into an antineutron ( B = − 1 ). Also forbids the decay of the lightest baryon, i.e. proton. Just like the conservation of electric charge forbids the decay of electron. 3

  6. Conservation of Baryon Number In the Standard Model (SM), conservation of baryon number forbids a neutron ( B = 1 ) from transforming into an antineutron ( B = − 1 ). Also forbids the decay of the lightest baryon, i.e. proton. Just like the conservation of electric charge forbids the decay of electron. But conservation of electric charge is closely connected with U (1) em gauge symmetry (Noether’s theorem). If same idea worked for B , we expect conservation of “baryonic” charge to be associated with a new long-range force coupled to B . No experimental evidence so far! Strong constraints on any new long-range force coupled to B . [Schlamminger et al. (PRL ’08); Cowsik et al. ’18; Agarwalla, Bustamante (PRL ’18)] 3

  7. Baryon Number Violation From the SM point of view, both B and L are “accidental” global symmetries. No special reason why they should be conserved beyond SM. Even in the SM, B + L is violated by non-perturbative sphaleron processes, and it’s only the B − L combination that is conserved. Sphalerons play an important role in explaining the primordial baryon asymmetry (baryogenesis). However, the sphaleron-induced B -violation is negligible for T ≪ v EW to have any observable effects in lab. 4

  8. Selection Rules Conservation of angular momentum requires that spin of nucleon should be transferred to another fermion (lepton or baryon). Leads to the selection rule ∆ B = ± ∆ L , or | ∆( B − L ) | = 0 , 2 . 5

  9. Selection Rules Conservation of angular momentum requires that spin of nucleon should be transferred to another fermion (lepton or baryon). Leads to the selection rule ∆ B = ± ∆ L , or | ∆( B − L ) | = 0 , 2 . In the SM, ∆( B − L ) = 0 , or ∆ B = +∆ L = 0 (e.g. neutron decay). Second possibility: | ∆( B − L ) | = 2 , which can be realized in three ways: ∆ B = − ∆ L = 1 (e.g. proton decay) | ∆ B | = 2 (e.g. dinucleon decay, n − ¯ n oscillation) – This talk | ∆ L | = 2 (e.g. Majorana mass for neutrino, 0 νββ ) – Talk by E. Mereghetti Conservation or violation of B − L determines the mechanism of baryon instability. Connected with the Majorana nature of neutrino mass. [Mohapatra, Marshak (PRL ’80)] 5

  10. ∆ B = 1 versus ∆ B = 2 ∆ B = 1 ∆ B = 2 Proton decay Di-nucleon decay and n − ¯ n Induced by dimension-6 operator Induced by dimension-9 operator QQQL . QQQQQQ . Amplitude ∝ Λ − 2 . Amplitude ∝ Λ − 5 . τ p � 10 34 yr implies Λ � 10 15 GeV. Λ � 100 TeV enough to satisfy experimental constraints. Proton decay requires GUT-scale physics. n − ¯ n oscillation (and conversion) could come from a TeV-scale new [Nath, Perez (Phys. Rep. ’07)] physics. u e + [Phillips et al. (Phys. Rep ’16)] u d p u u π 0 d d d d n n d d (c) 6

  11. General Formalism of n − ¯ n Oscillation Start with the Schr¨ odinger equation � � � � � � i ∂ | n � M 11 δm | n � = ∂t | ¯ n � δm M 22 | ¯ n � � �� � H eff with Im( M jj ) = − iλ/ 2 , where λ − 1 = τ n ≃ 880 sec is the mean lifetime of a free neutron. 7

  12. General Formalism of n − ¯ n Oscillation Start with the Schr¨ odinger equation � � � � � � i ∂ | n � M 11 δm | n � = ∂t | ¯ n � δm M 22 | ¯ n � � �� � H eff with Im( M jj ) = − iλ/ 2 , where λ − 1 = τ n ≃ 880 sec is the mean lifetime of a free neutron. The difference ∆ M ≡ M 11 − M 22 incorporates any interaction effects that distinguish neutron and antineutron (e.g. ambient external magnetic field). 7

  13. General Formalism of n − ¯ n Oscillation Start with the Schr¨ odinger equation � � � � � � i ∂ | n � M 11 δm | n � = ∂t | ¯ n � δm M 22 | ¯ n � � �� � H eff with Im( M jj ) = − iλ/ 2 , where λ − 1 = τ n ≃ 880 sec is the mean lifetime of a free neutron. The difference ∆ M ≡ M 11 − M 22 incorporates any interaction effects that distinguish neutron and antineutron (e.g. ambient external magnetic field). Mass eigenstates � � � � � � | n 1 � cos θ sin θ | n � with tan(2 θ ) = 2 δm = | n 2 � − sin θ cos θ | ¯ n � ∆ M 7

  14. General Formalism of n − ¯ n Oscillation Start with the Schr¨ odinger equation � � � � � � i ∂ | n � M 11 δm | n � = ∂t | ¯ n � δm M 22 | ¯ n � � �� � H eff with Im( M jj ) = − iλ/ 2 , where λ − 1 = τ n ≃ 880 sec is the mean lifetime of a free neutron. The difference ∆ M ≡ M 11 − M 22 incorporates any interaction effects that distinguish neutron and antineutron (e.g. ambient external magnetic field). Mass eigenstates � � � � � � | n 1 � cos θ sin θ | n � with tan(2 θ ) = 2 δm = | n 2 � − sin θ cos θ | ¯ n � ∆ M Real energy eigenvalues:   E 1 , 2 = 1 � (∆ M ) 2 + 4( δm ) 2  M 11 + M 22 ±  2 � �� � ∆ E 7

  15. Transition Probability Starting with a pure | n � state at t = 0 , the probability to evolve into the | ¯ n � state at a later time t is � � ∆ E t n | n ( t ) �| 2 = sin 2 (2 θ ) sin 2 e − λt P ¯ n ( t ) = |� ¯ 2 � � � � 4( δm ) 2 ∆ E t sin 2 e − λt = (∆ E ) 2 2 Quasi-free limit ∆ E t ≪ 1 : � t � 2 n ( t ) ∼ ( δm t ) 2 e − λt = e − λt P ¯ τ n ¯ n where τ n ¯ n = 1 / | δm | is the oscillation lifetime. n � 10 8 sec (or | δm | � 10 − 29 MeV), so Current experimental limits give τ n ¯ τ n ¯ n ≫ τ n . 8

  16. In Field-Free Vacuum In this case, ∆ M = 0 and � � m n − iλ/ 2 δm H eff = δm m n − iλ/ 2 √ Leads to the mass eigenstates | n ± � = ( | n � ± | ¯ n � ) / 2 with eigenvalues ( m n ± δm ) − iλ/ 2 and maximal mixing θ = π/ 4 . The oscillation probability is simply n ( t ) = sin 2 � t � e − λt P ¯ τ n ¯ n Never realized in practice. 9

  17. In a Static Ambient Magnetic Field n interact with the external � The n and ¯ B field via their magnetic dipole moments n = − 1 . 91 µ N and µ N = e/ (2 m N ) = 3 . 15 × 10 − 14 MeV/T. � µ n, ¯ n , where µ n = − µ ¯ � � µ n · � m n − � B − iλ/ 2 δm H eff = µ n · � δm m n + � B − iλ/ 2 µ n · � B ≫ δm , even for a reduced magnetic field of | � B | ∼ 10 − 8 Leads to ∆ M = − 2 � B | ≃ 10 − 21 MeV, as opposed to µ n · � T (as in the ILL experiment), for which | � | δm | � 10 − 29 MeV. 10

  18. In a Static Ambient Magnetic Field n interact with the external � The n and ¯ B field via their magnetic dipole moments n = − 1 . 91 µ N and µ N = e/ (2 m N ) = 3 . 15 × 10 − 14 MeV/T. � µ n, ¯ n , where µ n = − µ ¯ � � µ n · � m n − � B − iλ/ 2 δm H eff = µ n · � δm m n + � B − iλ/ 2 µ n · � B ≫ δm , even for a reduced magnetic field of | � B | ∼ 10 − 8 Leads to ∆ M = − 2 � B | ≃ 10 − 21 MeV, as opposed to µ n · � T (as in the ILL experiment), for which | � | δm | � 10 − 29 MeV. µ n · � ∆ E ≃ 2 | � B | and to realize the quasi-free limit, need to arrange an observation µ n · � time t such that | � B | t ≪ 1 and also t ≪ τ n . The transition probability reduces to � t � 2 P ¯ n ( t ) ≃ τ n ¯ n Number of ¯ n ’s produced by n − ¯ n oscillation is essentially N ¯ n = P ¯ n ( t ) N n = P ¯ n ( t ) φ n T run Main challenge: Need to establish smaller magnetic fields. 10

  19. ILL/Grenoble n − ¯ n Oscillation Search Experiment Bent n-guide 58 Ni coated, L ~ 63 m, 6 � 12 cm 2 v ~ 600 m/s n 11

  20. In Bound Nuclei � � � � m n + V n δm m n, eff δm H eff = ≡ δm m n + V ¯ δm m ¯ n n, eff The nuclear potential is practically real, V n = V nR , but V ¯ n has a large imaginary part V ¯ n = V ¯ nR − iV ¯ nI with V nR , V ¯ nR , V ¯ nI ∼ O (100) MeV. [Dover, Gal, Richard (PRC ’85); Friedman, Gal (PRD ’08)] 12

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