SLIDE 12 The model A->2A, 2A->A and random walk has two remarkable symmetries
- Let Q1(x,t) and P1(x,t) be a solution obeying the BCs.
Then Q2= P1(x,-t)+1 and P2=Q1(x,-t) -1 is also a solution with the same BCs.
In old variables this is invariance of q(x,t) with respect to time reversal: consequence of detailed balance of underlying microscopic model.
- Let Q1(x,t) and P1(x,t) be a solution obeying the BCs.
Then Q2= -P1(-x,-t) and P2=-Q1(-x,-t) is also a solution with the same BCs. Once the Hamilton’s equations are solved, we can calculate the action along the “activation trajectory” q(x,t), p(x,t) and evaluate P(c):
]} ) , ( ) , ( [ { ] ) , ( ) , ( [ ) ( ln W t x Q t x P dt F dx N w t x q t x p dt dx N S K c
t t
− ∂ + Δ = − ∂ = ≈ −
∫ ∫ ∫ ∫
∞ ∞ − ∞ ∞ − τ τ
P
N=Kld /h>>1 is the number of particles in the front region