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Modified gravity and the cosmological constant problem Based on - - PowerPoint PPT Presentation

Introduction-Why modify General Relativity Modification of gravity Horndeskis theory The self-tuning filter The Fab Four Conclusions Modified gravity and the cosmological constant problem Based on arxiv:1106.2000 [hep-th] published in PRL


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Introduction-Why modify General Relativity Modification of gravity Horndeski’s theory The self-tuning filter The Fab Four Conclusions

Modified gravity and the cosmological constant problem

Based on arxiv:1106.2000 [hep-th] published in PRL and hep-th/1112.4866 PRD

CC, Ed Copeland, Tony Padilla and Paul M Saffin

Laboratoire de Physique Théorique d’Orsay, CNRS UMR 8627, LMPT, Tours

  • C. Charmousis

Modified gravity and the cosmological constant problemBased on a

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Introduction-Why modify General Relativity Modification of gravity Horndeski’s theory The self-tuning filter The Fab Four Conclusions To modify or not?

1

Introduction-Why modify General Relativity To modify or not?

2

Modification of gravity Self-tuning

3

Horndeski’s theory

4

The self-tuning filter

5

The Fab Four

6

Conclusions

  • C. Charmousis

Modified gravity and the cosmological constant problemBased on a

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Introduction-Why modify General Relativity Modification of gravity Horndeski’s theory The self-tuning filter The Fab Four Conclusions To modify or not?

Question: Why we should not modify GR

Theoretical consistency: In 4 dimensions, consider L = L(M, g, ∇g, ∇∇g). Then Lovelock’s theorem in D = 4 states that GR with cosmological constant is the unique metric theory emerging from, S(4) =

  • M

d4x

  • −g(4) [R − 2Λ]

giving,

Equations of motion of 2nd-order given by a symmetric two-tensor, Gµν + Λgµν and admitting Bianchi identities.

Under these hypotheses GR is the unique massless-tensorial 4 dimensional theory of gravity

  • C. Charmousis

Modified gravity and the cosmological constant problemBased on a

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Introduction-Why modify General Relativity Modification of gravity Horndeski’s theory The self-tuning filter The Fab Four Conclusions To modify or not?

Experimental and observational data

Experimental consistency:

  • Excellent agreement with solar system tests
  • Strong gravity tests on binary pulsars
  • Laboratory tests of Newton’s law (tests on extra dimensions)

Time delay of light Planetary tajectories ... C. Charmousis

Modified gravity and the cosmological constant problemBased on a

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Introduction-Why modify General Relativity Modification of gravity Horndeski’s theory The self-tuning filter The Fab Four Conclusions To modify or not?

Q: What is the matter content of the Universe today?

Assuming homogeinity-isotropy and GR Gµν = 8πGTµν cosmological and astrophysical observations dictate the matter content of the Universe today: A: -Only a 4% of matter has been discovered in the laboratory. We hope to see more at LHC. But even then...

If we assume only ordinary sources of matter (DM included) there is disagreement between local, astrophysical and cosmological data.

  • C. Charmousis

Modified gravity and the cosmological constant problemBased on a

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Introduction-Why modify General Relativity Modification of gravity Horndeski’s theory The self-tuning filter The Fab Four Conclusions To modify or not?

Universe is accelerating → Enter the cosmological constant

Easiest way out: Assume a tiny cosmological constant ρΛ =

Λ 8πG = (10−3eV )4,

ie modify Einstein’s equation by, Gµν + Λgµν = 8πGTµν Cosmological constant introduces √ Λ and generates a cosmological horizon √ Λ is as tiny as the inverse size of the Universe today, r0 = H−1 Note that

Solar system scales Cosmological Scales ∼ 10 A.U. H−1

= 10−14

But things get worse... Theoretically, the size of the Universe would not even include the moon!

Cosmological constant problem

  • C. Charmousis

Modified gravity and the cosmological constant problemBased on a

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Introduction-Why modify General Relativity Modification of gravity Horndeski’s theory The self-tuning filter The Fab Four Conclusions To modify or not?

Cosmological constant problem, [S Weinberg Rev.

Mod. Phys. 1989]

Cosmological constant behaves as vacuum energy which according to the strong equivalence principle gravitates, Vacuum energy fluctuations are at the UV cutoff of the QFT Λvac/8πG ∼ m4

Pl...

Vacuum potential energy from spontaneous symmetry breaking ΛEW ∼ (200GeV )4 Bare gravitational cosmological constant Λbare Λobs ∼ Λvac+ Λpot+Λbare Enormous Fine-tuning inbetween theoretical and observational value Why such a discrepancy between theory and observation? Weinberg no-go theorembig CC Why is Λobs so small and not exactly zero? small cc Why do we observe it now ?

  • C. Charmousis

Modified gravity and the cosmological constant problemBased on a

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Introduction-Why modify General Relativity Modification of gravity Horndeski’s theory The self-tuning filter The Fab Four Conclusions Self-tuning

1

Introduction-Why modify General Relativity To modify or not?

2

Modification of gravity Self-tuning

3

Horndeski’s theory

4

The self-tuning filter

5

The Fab Four

6

Conclusions

  • C. Charmousis

Modified gravity and the cosmological constant problemBased on a

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Introduction-Why modify General Relativity Modification of gravity Horndeski’s theory The self-tuning filter The Fab Four Conclusions Self-tuning

Gravitational theories

Extra dimensions : Extension of GR to Lovelock theory with modified yet second order field equations. Braneworlds: In general relevant as UV modifications, problematic in the IR (ghosts, strong coupling problems etc). 4-dimensional modification of GR: Scalar-tensor galileon or f(R), Einstein-Aether, Hoˆ rava gravity: Tension with local and strong gravity tests, some theoretical problems/questions with Lorentz breaking and flowing back to GR in the IR. Massive gravity: Is there a Higgs mechanism for gravity? Not as yet a robust covariant theory, only perturbative windows available, often dressed with stability problems. Some recent progress We will consider the simplest of cases, namely scalar tensor theory. Generically these theories can result as IR endpoints of more complex theories of gravity or from higher dimensional theories by KK reduction.

  • C. Charmousis

Modified gravity and the cosmological constant problemBased on a

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Introduction-Why modify General Relativity Modification of gravity Horndeski’s theory The self-tuning filter The Fab Four Conclusions Self-tuning

Weinberg no-go theorem

Assume an effective, conserved and covariant 4 dimensional theory Consider gravity action including all contributions of cosmological constant in the scalar potential term, S[π1, ..., πN, gµν] =

  • d4x√−gR + L(π1, ..., πN, gµν, ∂m) + Matter

If gµν = ηµν, πi = constant. Then Λ = 0 It is impossible to find trivial solutions to Einstein’s field equations without fine tuning the cosmological constant to zero. Let us consider a self − tuning, or, non-trivial scalar field...

  • C. Charmousis

Modified gravity and the cosmological constant problemBased on a

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Introduction-Why modify General Relativity Modification of gravity Horndeski’s theory The self-tuning filter The Fab Four Conclusions Self-tuning

Self-Tuning: general idea

Question: What if we break Poincaré invariance at the level of the scalar field? Keep gµν = ηµν locally but allow for φ = constant. Can we have a portion of flat spacetime whatever the value of the cosmological constant and without fine-tuning any of the parameters of the theory? Toy model theory of self-adjusting scalar field. Solving this problem classically means that vacuum energy does not gravitate and we break SEP not EEP. Beyond leading order O(Λ4), radiative corrections O(Λ6/MPl2) may spoil self-tuning. We need:

1

A cosmological background

2

A sufficiently general theory to work with

  • C. Charmousis

Modified gravity and the cosmological constant problemBased on a

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Introduction-Why modify General Relativity Modification of gravity Horndeski’s theory The self-tuning filter The Fab Four Conclusions

1

Introduction-Why modify General Relativity To modify or not?

2

Modification of gravity Self-tuning

3

Horndeski’s theory

4

The self-tuning filter

5

The Fab Four

6

Conclusions

  • C. Charmousis

Modified gravity and the cosmological constant problemBased on a

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Introduction-Why modify General Relativity Modification of gravity Horndeski’s theory The self-tuning filter The Fab Four Conclusions

A general scalar tensor theory

Consider φ and gµν as gravitational DoF. Consider L = L(gµν, gµν,i1, ..., gµν,i1...ip, φ, φ,i1, ..., φ,i1...iq) with p, q ≥ 2 but finite L has higher than second derivatives What is the most general scalar-tensor theory giving second order field equations? Similar to Lovelock’s theorem but for the presence of higher derivatives in L. Here second order field equations in principle protect vacua from ghost instabilities.

  • C. Charmousis

Modified gravity and the cosmological constant problemBased on a

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Introduction-Why modify General Relativity Modification of gravity Horndeski’s theory The self-tuning filter The Fab Four Conclusions

Horndeski’s theory

rather complex... loads of derivatives, Kronecker δ’s K-essence terms free functions of scalar and kinetic term but just what we need and it gets simpler as we go on...

  • C. Charmousis

Modified gravity and the cosmological constant problemBased on a

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The Horndeski action [Horndeski 1974, Int.

  • J. Theor.

Phys.], [Deffayet et al.]

L = κ1(φ, ρ)δijk

µνσ∇µ∇iφR νσ jk

− 4 3κ1,ρ(φ, ρ)δijk

µνσ∇µ∇iφ∇ν∇jφ∇σ∇kφ

+κ3(φ, ρ)δijk

µνσ∇iφ∇µφR νσ jk

− 4κ3,ρ(φ, ρ)δijk

µνσ∇iφ∇µφ∇ν∇jφ∇σ∇kφ

+F(φ, ρ)δij

µνR µν ij

− 4F(φ, ρ),ρδij

µν∇iφ∇µφ∇ν∇jφ

−3[2F(φ, ρ),φ + ρκ8(φ, ρ)]∇µ∇µφ + 2κ8(φ, ρ)δij

µν∇iφ∇µφ∇ν∇jφ

+κ9(φ, ρ), ρ = ∇µφ∇µφ, where κi(φ, ρ), i = 1, 3, 8, 9 are 4 arbitrary functions of the scalar field φ and its kinetic term denoted as ρ and F,ρ = κ1,φ − κ3 − 2ρκ3,ρ δi1...ih

j1...jh = h!δi1 [j1...δih jh]

Field equations are second order in metric gµν and φ and theory is unique. Most general galileon theory

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Introduction-Why modify General Relativity Modification of gravity Horndeski’s theory The self-tuning filter The Fab Four Conclusions

Horndeski cosmology

Consider cosmological background: Assume, ds2 = −dt2 + a2(t)

  • dr2

1−kr2 + r 2(dθ2 + sin2 θ dφ2)

  • , φ = φ(t)

Insert into action or use EoM, Cosmological Langrangian L(a, ˙ a, φ, ˙ φ) = a3 3

n=0(Xn − Yn κ a2 )Hn

X0 = −˜ Q7,φ ˙ φ + κ9, X1 = −12F,φ ˙ φ + 3(Q7 ˙ φ − ˜ Q7) + 6κ8 ˙ φ3 X2 = 12F,ρρ − 12F, X3 = 8κ1,ρ ˙ φ3 Y0 = ˜ Q1,φ ˙ φ + 12κ3 ˙ φ2 − 12F, Y1 = ˜ Q1 − Q1 ˙ φ, Y2 = Y3 = 0 With, −12κ1 = Q1 := ∂ ˜

Q1 ∂ ˙ φ , and 6F,φ − 3 ˙

φ2κ8 = Q7 := ∂ ˜

Q7 ∂ ˙ φ

and H = ˙

a

  • a. L polynomial of third order in H.
  • C. Charmousis

Modified gravity and the cosmological constant problemBased on a

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Introduction-Why modify General Relativity Modification of gravity Horndeski’s theory The self-tuning filter The Fab Four Conclusions

Cosmological field equations

1

Cosmological Langrangian density L(a, ˙ a, φ, ˙ φ) = a3

3

  • n=0

(Xn − Yn κ a2 )Hn

2

Modified Friedmann eq (with some matter source). H(a, ˙ a, φ, ˙ φ) = 1 a3 (∂L ∂ ˙ a ˙ a + ∂L ∂ ˙ φ ˙ φ − L) = −ρm

3

Scalar eq. E(a, ˙ a, ¨ a, φ, ˙ φ, ¨ φ) = − d dt (∂L/∂ ˙ φ) + ∂L/∂φ = 0 = ¨ φf (φ, ˙ φ, a, ˙ a) + g(φ, ˙ φ, a, ˙ a, ¨ a) = 0 Linear in ¨ φ and ¨ a. Also have 2nd Friedmann equation or usual energy conservation.

  • C. Charmousis

Modified gravity and the cosmological constant problemBased on a

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Introduction-Why modify General Relativity Modification of gravity Horndeski’s theory The self-tuning filter The Fab Four Conclusions

1

Introduction-Why modify General Relativity To modify or not?

2

Modification of gravity Self-tuning

3

Horndeski’s theory

4

The self-tuning filter

5

The Fab Four

6

Conclusions

  • C. Charmousis

Modified gravity and the cosmological constant problemBased on a

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Introduction-Why modify General Relativity Modification of gravity Horndeski’s theory The self-tuning filter The Fab Four Conclusions

Main Assumptions

Vacuum energy does not gravitate. Assume that ρm = ρΛ, a piecewise discontinuous step function of time t. Discontinuous points, t = t⋆, are phase transitions which are point like and arbitrary in time. x = time, and y = ρΛ. Assume that spacetime is flat or a flat portion for all t H2 + κ

a2 = 0, with κ = 0, or κ = −1 Milne spacetime (a(t) = t)

φ not constant but in principle a function of time t!

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Modified gravity and the cosmological constant problemBased on a

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Introduction-Why modify General Relativity Modification of gravity Horndeski’s theory The self-tuning filter The Fab Four Conclusions

The self tuning filter

Mathematical regularity imposed by a distributional source

1

We are going to set H2 + κ

a2 =0, with ρ(Λ) piecewise discontinuous. Then 2

H(a, φ, ˙ φ) = 1 a3 (∂L ∂ ˙ a ˙ a + ∂L ∂ ˙ φ ˙ φ − L) = −ρΛ a(t), ˙ a and φ(t) are continuous whereas ˙ φ is discontinuous at t = t⋆. H has to depend on ˙ φ

3

Scalar eq. on shell is E(a, φ, ˙ φ, ¨ φ) = ¨ φf (φ, ˙ φ, a) + g(φ, ˙ φ, a) = 0 φ has a δ(t − t⋆) singularity at t = t⋆ Hence f (φ, ˙ φ, a) = 0, g(φ, ˙ φ, a) = 0 Since t = t⋆ is arbitrary we finally get ¨ φΛf (a) + g(a) = 0

4

Hence on shell, E has no dependance on φ. φ fixed by Friedmann eq.

5

In the presence of matter cosmology must be non trivial. Hence E must depend on ¨ a

  • C. Charmousis

Modified gravity and the cosmological constant problemBased on a

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Introduction-Why modify General Relativity Modification of gravity Horndeski’s theory The self-tuning filter The Fab Four Conclusions

Applying self-tuning filter to cosmological Horndesky

Using the form of Horndeski cosmological equations:

  • linearity of second order terms in a and φ
  • polynomial form of H

We obtain

κ1 = 1 8 Vringo

′(φ)

  • 1 +

1 2 ln |ρ|

  • +

1 4 Vpaul (φ)ρ − 1 12 B(φ) κ3 = 1 16 Vringo

′′(φ) ln |ρ| +

1 12 V ′

paul (φ)ρ −

1 12 B′(φ) + p(φ) − 1 2 Vjohn(φ)(1 − ln |ρ|) κ8 = 2p′(φ) + V ′

john(φ) ln |ρ| − λ(φ)

κ9 = c0 + 1 2 V ′′

george(φ)ρ + λ′(φ)ρ2

F = − 1 12 Vgeorge(φ) − p(φ)ρ − 1 2 Vjohn(φ)ρ ln |ρ|

All ρ dependance integrated out. Free functions Vfab4, c0 cosmological constant , B, p, λ B, p, λ total derivatives

  • C. Charmousis

Modified gravity and the cosmological constant problemBased on a

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Introduction-Why modify General Relativity Modification of gravity Horndeski’s theory The self-tuning filter The Fab Four Conclusions

1

Introduction-Why modify General Relativity To modify or not?

2

Modification of gravity Self-tuning

3

Horndeski’s theory

4

The self-tuning filter

5

The Fab Four

6

Conclusions

  • C. Charmousis

Modified gravity and the cosmological constant problemBased on a

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Relevant and irelevant terms

Remember the Horndeski action L = κ1(φ, ρ)δijk

µνσ∇µ∇iφR νσ jk

− 4 3κ1,ρ(φ, ρ)δijk

µνσ∇µ∇iφ∇ν∇jφ∇σ∇kφ

+κ3(φ, ρ)δijk

µνσ∇iφ∇µφR νσ jk

− 4κ3,ρ(φ, ρ)δijk

µνσ∇iφ∇µφ∇ν∇jφ∇σ∇kφ

+F(φ, ρ)δij

µνR µν ij

− 4F(φ, ρ),ρδij

µν∇iφ∇µφ∇ν∇jφ

−3[2F(φ, ρ),φ + ρκ8(φ ρ)]∇µ∇µφ + 2κ8δij

µν∇iφ∇µφ∇ν∇jφ

+κ9(φ, ρ) The self-tuning filter gave, κ1 = 1 8V ′

ringo(φ)

  • 1 + 1

2 ln |ρ|

  • + 1

4Vpaul(φ)ρ κ3 = 1 16V ′′

ringo(φ) ln |ρ| + 1

12V ′

paul(φ)ρ − 1

2Vjohn(φ)(1 − ln |ρ|) κ8 = V ′

john(φ) ln |ρ|

κ9 = 1 2V ′′

george(φ)ρ

F = − 1 12Vgeorge(φ) − 1 2Vjohn(φ)ρ ln |ρ| Are these terms recognisable geometric quantities?

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Introduction-Why modify General Relativity Modification of gravity Horndeski’s theory The self-tuning filter The Fab Four Conclusions

George is easy

Start with LGeorge Set everybody else to zero κ9 = 1 2V ′′

georgeρ,

F = − 1 12Vgeorge Lgeorge = −1 6Vgeorge(φ)R + 1 2∇µ

  • V ′

george∂µφ

. ∼ = −1 6Vgeorge(φ)R Einstein-Hilbert non-minimally coupled with a free scalar field

  • C. Charmousis

Modified gravity and the cosmological constant problemBased on a

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Introduction-Why modify General Relativity Modification of gravity Horndeski’s theory The self-tuning filter The Fab Four Conclusions

EoM help for Ringo and John

Switch on only VRingo in EoM. We find, K1 = 1 16 V ′

ringo,

K3 = 1 16 V ′′

ringo

The equation of motion reads, Eik

ringo

=

  • −gK1(φ, ρ)δaijk

λµνσgλb∇µ∇i φR νσ jk

+ K3(φ, ρ)δaijk

λµνσgλb∇i φ∇µφR νσ jk

=

  • −g(∗R∗)ijkl

4K1∇l ∇j φ + 4K3∇l φ∇j φ = 1 4

  • −g(∗R∗)ijkl ∇l ∇j Vringo(φ)

While at the same time we have, δ

  • M

d4x −g V (φ) ˆ G

  • =
  • M

d4x −g δgij 2φHij + 4(∗R∗)ikjl ∇l ∇kV (φ) + δφ[∂φV (φ) ˆ G] Hence LRingo = VRingo(φ) ˆ G Similarly LJohn = VjohnGij ∇i φ∇j φ. All three LGeorge, LRingo, LJohn are KK Lovelock densities

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Modified gravity and the cosmological constant problemBased on a

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The double dual tensor

In 4 dimensions we can define a dual of the curvature tensor by dualising each pair of indices much like the Faraday tensor in EM ∗F ab = 1 2εabcd Fcd Double Dual (∗R∗) (∗R∗)µνσλ = −1 4ε

ij µν Rijkl ε kl σλ = 1 4δijkl µνσλ Rijkl

As appearing in the Horndeski action

1

Same index properties as R-tensor

2

Divergence free: ∇i(∗R∗)

i jkl

= 0

3

Simple trace is Einstein (∗R∗)ik

jk = −Gi j ,

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Introduction-Why modify General Relativity Modification of gravity Horndeski’s theory The self-tuning filter The Fab Four Conclusions

Paul

Last term is not recognisable. However, numerous Padilla tricks bring it to the form, Lpaul = √−gVPaul(φ) Rµναβ∇µφ∇αφ∇ν∇βφ+ +Gµν(∇µφ∇αφ − gµα(∇φ)2)∇α∇νφ +Rµν(∇µ∇αφ − gµαφ)∇αφ∇νφ] ???However, (∗R∗)µναβ = Rµναβ + 2Rν[αgβ]µ − 2Rµ[αgβ]ν + Rgµ[αgβ]ν , Therefore Lpaul = √−gVpaul(φ)(∗R∗)µναβ∇µφ∇αφ∇ν∇βφ Also a higher KK Lovelock density [K V Akoleyen]

  • C. Charmousis

Modified gravity and the cosmological constant problemBased on a

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Introduction-Why modify General Relativity Modification of gravity Horndeski’s theory The self-tuning filter The Fab Four Conclusions

Fab 4

Putting it all together from Horndeski s general action,

L = κ1(φ, ρ)δijk

µνσ∇µ∇i φR νσ jk

− 4 3 κ1,ρ(φ, ρ)δijk

µνσ∇µ∇i φ∇ν∇j φ∇σ∇kφ

+κ3(φ, ρ)δijk

µνσ∇i φ∇µφR νσ jk

− 4κ3,ρ(φ, ρ)δijk

µνσ∇i φ∇µφ∇ν∇j φ∇σ∇kφ

+F(φ, ρ)δij

µνR µν ij

− 4F(φ, ρ),ρδij

µν∇i φ∇µφ∇ν∇j φ

−3[2F(φ, ρ),φ + ρκ8(φ ρ)]∇µ∇µφ + 2κ8δij

µν∇i φ∇µφ∇ν∇j φ

+κ9(φ, ρ)

Self-tuning filter Ljohn = √−gVjohn(φ)Gµν∇µφ∇νφ Lpaul = √−gVpaul(φ)(∗R∗)µναβ∇µφ∇αφ∇ν∇βφ Lgeorge = √−gVgeorge(φ)R Lringo = √−gVringo(φ)ˆ G All are scalar-tensor interaction terms. No kinetic or potential scalar terms

  • C. Charmousis

Modified gravity and the cosmological constant problemBased on a

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Introduction-Why modify General Relativity Modification of gravity Horndeski’s theory The self-tuning filter The Fab Four Conclusions

Cosmology equations and self tuning

Friedmann equation reads H = −ρΛ Hjohn = 3Vjohn(φ) ˙ φ2 H2 + κ a2

  • + 6Vjohn(φ) ˙

φ2H2 Hpaul = − 9Vpaul(φ) ˙ φ3H

  • H2 + κ

a2

  • − 6Vpaul(φ) ˙

φ3H3 Hgeorge = −6Vgeorge(φ) H2 + κ a2

  • + H ˙

φV ′

george

Vgeorge

  • Hringo

= − 24V ′

ringo(φ) ˙

φH

  • H2 + κ

a2

  • First find self tuning vacuum setting H2 + κ

a2 = 0

Algebraic equation with respect to ˙ φ. Hence φ is a function of time t with discontinuous first derivatives at t = t∗ Ringo cannot self-tune without a little help from his friends.

  • C. Charmousis

Modified gravity and the cosmological constant problemBased on a

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Introduction-Why modify General Relativity Modification of gravity Horndeski’s theory The self-tuning filter The Fab Four Conclusions

Cosmology equations and self tuning

Scalar equation, Eφ = Ejohn + Epaul + Egeorge + Eringo = 0 Ejohn = 6 d dt

  • a3Vjohn(φ) ˙

φ∆2

  • − 3a3V ′

john(φ) ˙

φ2∆2 Epaul = −9 d dt

  • a3Vpaul(φ) ˙

φ2H∆2

  • + 3a3V ′

paul(φ) ˙

φ3H∆2 Egeorge = −6 d dt

  • a3V ′

george(φ)∆1

  • + 6a3V ′′

george(φ) ˙

φ∆1 + 6a3V ′

george(φ)∆2 1

Eringo = −24V ′

ringo(φ) d

dt

  • a3 κ

a2 ∆1 + 1 3∆3

  • where

∆n = Hn −

√−κ

a

n

which vanishes on shell as it should For non trivial cosmology need {Vjohn, Vpaul, Vgeorge, Vringo} = {0, 0, constant, constant}

  • C. Charmousis

Modified gravity and the cosmological constant problemBased on a

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Introduction-Why modify General Relativity Modification of gravity Horndeski’s theory The self-tuning filter The Fab Four Conclusions

1

Introduction-Why modify General Relativity To modify or not?

2

Modification of gravity Self-tuning

3

Horndeski’s theory

4

The self-tuning filter

5

The Fab Four

6

Conclusions

  • C. Charmousis

Modified gravity and the cosmological constant problemBased on a

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Introduction-Why modify General Relativity Modification of gravity Horndeski’s theory The self-tuning filter The Fab Four Conclusions

Conclusions

Starting from a general scalar tensor theory (Horndeski) We have filtered out the theory with self-tuning properties Theory has enchanting geometrical properties which we need to understand Still have 4 free functions which parametrise the theory. These need to be fixed by cosmology, stability and local constraints. Many questions unanswered:

1

What is the Fab 4 cosmology? In other words for which of the potentials do we get usual Hot Big Bang cosmology?

2

Usually to escape solar system constraints we take refuge in Veinshtein of chameleon mechanisms...

3

Maybe we can do better by redoing solar system tests from scratch for the self-tuned background in the spirit of [gr-qc/08014339]

4

Black hole solutions of such theories could really help. Also self tuning in different backgrounds.

  • C. Charmousis

Modified gravity and the cosmological constant problemBased on a

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Sketch of proof

Consider gravity action including all contributions of cosmological constant in the scalar potential term V , S[π, gµν] =

  • d4x√−gR + L(π, gµν, ∂m, V )

Assume gµν = ηµν, π = constant. Then On-shell L0 = −V0 √−g where L0 = L(ηµν, constant, Λ) with EoM,

∂L ∂gµν |0 = ∂L ∂π |0 = 0

scalar EoM is related to the trace of gravity equation Then Lagrangian has remnant symmetry, δgµν = ǫgµν and δπ = −ǫ and hence L = √−ˆ gL(ˆ gµν, ∂) with ˆ gµν = eπgµν All dependance in π has dropped out. So,on-shell for vacuum we have

∂L ∂gµν |0 = 1 2gµνL0

Hence V0(Λ) = 0 and thus the cosmological constant is fine tuned

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Introduction-Why modify General Relativity Modification of gravity Horndeski’s theory The self-tuning filter The Fab Four Conclusions

George is easy

Start with LGeorge Set everybody else to zero κ9 = 1 2V ′′

georgeρ,

F = − 1 12Vgeorge Lgeorge = −1 6Vgeorge(φ)R + 1 2∇µ

  • V ′

george∂µφ

. ∼ = −1 6Vgeorge(φ)R Einstein-Hilbert non-minimally coupled with a free scalar field The remaining terms need more work. Back to classical GR

  • C. Charmousis

Modified gravity and the cosmological constant problemBased on a

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SLIDE 35

The double dual tensor and Lovelock theory

In 4 dimensions we can define a dual of the curvature tensor by dualising each pair of indices much like the Faraday tensor in EM ∗F ab = 1 2 εabcd Fcd Double Dual (∗R∗) (∗R∗)µνσλ = − 1 4 ε

ij µν Rijkl ε kl σλ = 1 4 δijkl µνσλ Rijkl

As appearing in the Horndeski action 1 Same index properties as R-tensor 2 Divergence free: ∇i (∗R∗)

i jkl

= 0 3 Simple trace is Einstein (∗R∗)ik

jk = −Gi j ,

4 Hence

1 4 δijk µνσ R µν jk

= −Gi

µ

5 (∗R∗)µναβ = Rµναβ + 2Rν[αgβ]µ − 2Rµ[αgβ]ν + Rgµ[αgβ]ν , 6 Finally the 2nd order Lovelock tensor originating from variation of ˆ G is: Hij = (∗R∗)i

klmRjklm −

1 4 gij ˆ G . In D = 4 Hij = 0 hence (∗R∗)i klmRjklm = 1

4 gij ˆ

G

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SLIDE 36

Introduction-Why modify General Relativity Modification of gravity Horndeski’s theory The self-tuning filter The Fab Four Conclusions

With a little help from my friends

Switch on only VRingo in EoM. We find, K1 = 1 16 V ′

ringo,

K3 = 1 16 V ′′

ringo

Note the absence of ˙ φ; Ringo cannot self-tune without a little help from his friends. The equation of motion reads, Eik

ringo

=

  • −gK1(φ, ρ)δaijk

λµνσgλb∇µ∇i φR νσ jk

+ K3(φ, ρ)δaijk

λµνσgλb∇i φ∇µφR νσ jk

=

  • −g(∗R∗)ijkl

4K1∇l ∇j φ + 4K3∇l φ∇j φ = 1 4

  • −g(∗R∗)ijkl ∇l ∇j Vringo(φ)

While at the same time we have, δ

  • M

d4x −g V (φ) ˆ G

  • =
  • M

d4x −g δgij 2φHij + 4(∗R∗)ikjl ∇l ∇kV (φ) + δφ[∂φV (φ) ˆ G] Hence LRingo = VRingo(φ) ˆ G Similarly LJohn = VjohnGij ∇i φ∇j φ. All three are KK Lovelock densities

  • C. Charmousis

Modified gravity and the cosmological constant problemBased on a

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SLIDE 37

Introduction-Why modify General Relativity Modification of gravity Horndeski’s theory The self-tuning filter The Fab Four Conclusions

Paul

Last term is not recognisable. However, numerous Padilla tricks bring it to the form, Lpaul = √−gVPaul(φ) Rµναβ∇µφ∇αφ∇ν∇βφ+ +Gµν(∇µφ∇αφ − gµα(∇φ)2)∇α∇νφ +Rµν(∇µ∇αφ − gµαφ)∇αφ∇νφ] ???However remember, (∗R∗)µναβ = Rµναβ + 2Rν[αgβ]µ − 2Rµ[αgβ]ν + Rgµ[αgβ]ν , Therefore Lpaul = √−gVpaul(φ)(∗R∗)µναβ∇µφ∇αφ∇ν∇βφ

  • C. Charmousis

Modified gravity and the cosmological constant problemBased on a