MHD in a Cylindrical Shearing Box Takeru K. Suzuki School of Arts - - PowerPoint PPT Presentation
MHD in a Cylindrical Shearing Box Takeru K. Suzuki School of Arts - - PowerPoint PPT Presentation
MHD in a Cylindrical Shearing Box Takeru K. Suzuki School of Arts & Science, U. Tokyo September 6th, 2018 Thanks to XC40@YITP & ATERUI@CfCA/NaOJ Accretion Disks Some Examples Accretion Disks around Black Holes Active Galactic
Accretion Disks
Some Examples
- Accretion Disks around Black Holes
- Active Galactic Nuclei (SMBH)
- Galactic Disks
- Protoplanetary Disks
credit: NASA
- Ang. Mom. Transport & Mass Accretion
GM/r2 rΩ
2
r,Ω r0,Ω0 Central Star
- Ang. Mom. Transport & Mass Accretion
GM/r2 rΩ
2
r,Ω r0,Ω0 Central Star
- If Ang. Mom. conserved:
Ω = Ω0( r0
r )2
- Ang. Mom. Transport & Mass Accretion
GM/r2 rΩ
2
r,Ω r0,Ω0 Central Star
- If Ang. Mom. conserved:
Ω = Ω0( r0
r )2
- Centrifugal force at r :
rΩ2 = r0Ω2
0( r0 r )3
- Ang. Mom. Transport & Mass Accretion
GM/r2 rΩ
2
r,Ω r0,Ω0 Central Star
- If Ang. Mom. conserved:
Ω = Ω0( r0
r )2
- Centrifugal force at r :
rΩ2 = r0Ω2
0( r0 r )3
- Gravity at r :
GM r2
( r0
r )2
- Ang. Mom. Transport & Mass Accretion
GM/r2 rΩ
2
r,Ω r0,Ω0 Central Star
- If Ang. Mom. conserved:
Ω = Ω0( r0
r )2
- Centrifugal force at r :
rΩ2 = r0Ω2
0( r0 r )3
- Gravity at r :
GM r2
( r0
r )2
- If r0Ω2
0 = GM/r2 0,
⇒ rΩ2 > GM/r2
- Ang. Mom. Transport & Mass Accretion
GM/r2 rΩ
2
r,Ω r0,Ω0 Central Star
- If Ang. Mom. conserved:
Ω = Ω0( r0
r )2
- Centrifugal force at r :
rΩ2 = r0Ω2
0( r0 r )3
- Gravity at r :
GM r2
( r0
r )2
- If r0Ω2
0 = GM/r2 0,
⇒ rΩ2 > GM/r2
- Mass does NOT accrete.
(Rayleigh Criterion)
Turbulence in Accretion Disks
Turbulence ⇒ Macroscopic (effective) Viscosity
- Outward Transport of Angular Momentum
- Inward Accretion of Matters
Exchange fluid elements by ‘‘stirring with a spoon’’
MHD in an Accretion Disk
Suzuki & Inutsuka 2014
Magneto-Rotational Instability (MRI) –linear analyses–
Balbus & Hawley 1991
∂ρ ∂t + ∇ · (ρ) = 0 d dt + 1 ρ∇(p+ B2 8π) − (B·∇)B 4πρ
+ ∇Φ = 0
∂B ∂t = ∇ × ( × B − η∇ × B)
ρ de
dt = −p∇ · + η 4π|∇ × B|2
- axisymmetric perturbation: ∝ exp(−iωt + ikrr + ikzz)
- Gravity by a central star ∇Φ ≈ (GM
r2 ,0, GMz r3 )
- Assuming B0 = (0,0, Bz,0), ideal MHD (η = 0),
& incompressive (krδr + kzδz = 0) Dispersion relation :
ω4 − (22
A,zk2 z + κ2 k2
z
k2)ω2 + 4 A,zk4 z + (κ2 − 4Ω2)2 A,z k4
z
k2 = 0 where κ : epicycle frequency (= Ω for Kepler rotation)
A,z = Bz,0/
- 4πρ
MRI –Dispersion Relation–
Sano & Miyama 1999
- Always unstable for the weak B (β = 8πp
B2 1)
- The growth rate ∼ Ω−1
Magneto-Rotational Instability (MRI)
Center The Fluid element rotates faster than A.M. conservation Centrifugal F. > Gravity (Connection through B-field) A fluid element moves outward (Unstable)
Unstable under
- Weak B-fields
- (inner-fast) Differential Rotation
Velikov (1959); Chandrasekhar (1960); Balbus & Hawley (1991)
MHD in Cartesian Shearing Box (CaSB)
Hawley, Gammie, & Balbus 1995
MHD in Cartesian Shearing Box (CaSB)
- Local Cartesian coordinate with co-rotating with Ω0.
(neglect curvature)
Hawley, Gammie, & Balbus 1995
MHD in Cartesian Shearing Box (CaSB)
- Local Cartesian coordinate with co-rotating with Ω0.
(neglect curvature)
- x = r − r0; y ↔ φ-direction
Hawley, Gammie, & Balbus 1995
MHD in Cartesian Shearing Box (CaSB)
- Local Cartesian coordinate with co-rotating with Ω0.
(neglect curvature)
- x = r − r0; y ↔ φ-direction
- Basic equations for Keplerian rotation (Ω0 =
- GM/r3)
∂ρ ∂t + ∇ · (ρ) = 0 ∂x ∂t = − 1 ρ∇x(p+ B2 8π ) + (B·∇)Bx 4πρ
+ 2Ω0y + 3Ω2
0x ∂y ∂t = − 1 ρ∇y(p+ B2 8π ) + (B·∇)By 4πρ
− 2Ω0x
∂z ∂t = − 1 ρ∇z(p+ B2 8π ) + (B·∇)Bz 4πρ
− Ω2
0z ∂B ∂t = ∇ × ( × B − η∇ × B)
∇ · B = 0
Hawley, Gammie, & Balbus 1995
MHD in Cartesian Shearing Box (CaSB)
- Local Cartesian coordinate with co-rotating with Ω0.
(neglect curvature)
- x = r − r0; y ↔ φ-direction
- Basic equations for Keplerian rotation (Ω0 =
- GM/r3)
∂ρ ∂t + ∇ · (ρ) = 0 ∂x ∂t = − 1 ρ∇x(p+ B2 8π ) + (B·∇)Bx 4πρ
+ 2Ω0y + 3Ω2
0x ∂y ∂t = − 1 ρ∇y(p+ B2 8π ) + (B·∇)By 4πρ
− 2Ω0x
∂z ∂t = − 1 ρ∇z(p+ B2 8π ) + (B·∇)Bz 4πρ
− Ω2
0z ∂B ∂t = ∇ × ( × B − η∇ × B)
∇ · B = 0
- An Isothermal Equation of State
Hawley, Gammie, & Balbus 1995
MHD in Cartesian Shearing Box (CaSB)
- Local Cartesian coordinate with co-rotating with Ω0.
(neglect curvature)
- x = r − r0; y ↔ φ-direction
- Basic equations for Keplerian rotation (Ω0 =
- GM/r3)
∂ρ ∂t + ∇ · (ρ) = 0 ∂x ∂t = − 1 ρ∇x(p+ B2 8π ) + (B·∇)Bx 4πρ
+ 2Ω0y + 3Ω2
0x ∂y ∂t = − 1 ρ∇y(p+ B2 8π ) + (B·∇)By 4πρ
− 2Ω0x
∂z ∂t = − 1 ρ∇z(p+ B2 8π ) + (B·∇)Bz 4πρ
− Ω2
0z ∂B ∂t = ∇ × ( × B − η∇ × B)
∇ · B = 0
- An Isothermal Equation of State
- Steady-state solution
- B = (0, By, Bz) & = (0,−3
2Ω0x,0)
- ρ = ρ0 exp(−z2/H2) (H2 ≡ 2c2
s/Ω2 0):
hydrostatic equilibrium
Hawley, Gammie, & Balbus 1995
Cartesian Shearing Box Simulations
Hawley et al. 1995; Matsumoto & Tajima 1995; ...
Suzuki & Inutsuka 2009
Applications of CaSB
- PIC simulation in CaSB
Hoshino 2013; 2015; Shirakawa & Hoshino 2014
- MHD + non-thermal particles Kimura+ 2016
Some Disadvantages of CaSB
Some Disadvantages of CaSB
- Neglect the Curvature
Some Disadvantages of CaSB
- Neglect the Curvature
- Symmetry to the ±x direction
The central star can be located
- n either left or right side
Some Disadvantages of CaSB
- Neglect the Curvature
- Symmetry to the ±x direction
The central star can be located
- n either left or right side
- No Gas Accretion
A New Aproach
A New Aproach
- Break the Symmetry
A New Aproach
- Break the Symmetry
- Introduce the Curvature
A New Aproach
- Break the Symmetry
- Introduce the Curvature
⇒ can handle the net accretion ?
A New Aproach
- Break the Symmetry
- Introduce the Curvature
⇒ can handle the net accretion ? ⇒ Let’s try “Cylindrical Shearing Box (CySB)”
Cylindrical Shearing Box (CySB)
Cylindrical Shearing Box (CySB)
Key : Boundary Condition at R±
Cylindrical Shearing Box (CySB)
Key : Boundary Condition at R± Radial Boundary Condition
⇐ Conservation Laws
- f Mass+Momentum+(Energy)+B
Equations
Equations
- Mass:
∂tρ + R−1∂R(ρRR) + ∂φ(···) + ∂z(···) = 0
Equations
- Mass:
∂tρ + R−1∂R(ρRR) + ∂φ(···) + ∂z(···) = 0
- Momentum– R:
∂t(ρR) + R−1∂R(ρ2
RR) + ··· = 0
Equations
- Mass:
∂tρ + R−1∂R(ρRR) + ∂φ(···) + ∂z(···) = 0
- Momentum– R:
∂t(ρR) + R−1∂R(ρ2
RR) + ··· = 0
- Momentum– φ (Angular Momentum):
∂t(ρφR)+∂R[(ρRφ + BRBφ/4π)R2]+··· = 0
Equations
- Mass:
∂tρ + R−1∂R(ρRR) + ∂φ(···) + ∂z(···) = 0
- Momentum– R:
∂t(ρR) + R−1∂R(ρ2
RR) + ··· = 0
- Momentum– φ (Angular Momentum):
∂t(ρφR)+∂R[(ρRφ + BRBφ/4π)R2]+··· = 0
- Momentum– z:
∂t(ρz) + R−1∂R(ρRzR) + ··· = 0
Equations
- Mass:
∂tρ + R−1∂R(ρRR) + ∂φ(···) + ∂z(···) = 0
- Momentum– R:
∂t(ρR) + R−1∂R(ρ2
RR) + ··· = 0
- Momentum– φ (Angular Momentum):
∂t(ρφR)+∂R[(ρRφ + BRBφ/4π)R2]+··· = 0
- Momentum– z:
∂t(ρz) + R−1∂R(ρRzR) + ··· = 0
- Induction eq.– φ
∂tBφ = ∂z(···) − ∂R(RBφ − φBR)
Equations
- Mass:
∂tρ + R−1∂R(ρRR) + ∂φ(···) + ∂z(···) = 0
- Momentum– R:
∂t(ρR) + R−1∂R(ρ2
RR) + ··· = 0
- Momentum– φ (Angular Momentum):
∂t(ρφR)+∂R[(ρRφ + BRBφ/4π)R2]+··· = 0
- Momentum– z:
∂t(ρz) + R−1∂R(ρRzR) + ··· = 0
- Induction eq.– φ
∂tBφ = ∂z(···) − ∂R(RBφ − φBR)
- Induction eq.– z
∂tBz = R−1∂R[(zBR − RBz)R] − ∂φ(···)
Equations
- Mass:
∂tρ + R−1∂R(ρRR) + ∂φ(···) + ∂z(···) = 0
- Momentum– R:
∂t(ρR) + R−1∂R(ρ2
RR) + ··· = 0
- Momentum– φ (Angular Momentum):
∂t(ρφR)+∂R[(ρRφ + BRBφ/4π)R2]+··· = 0
- Momentum– z:
∂t(ρz) + R−1∂R(ρRzR) + ··· = 0
- Induction eq.– φ
∂tBφ = ∂z(···) − ∂R(RBφ − φBR)
- Induction eq.– z
∂tBz = R−1∂R[(zBR − RBz)R] − ∂φ(···)
- ∇ · B = 0
R−1∂R(BRR) + R−1∂φBφ + ∂zBz = 0
Cylindrical Shearing Condition
Cylindrical Shearing Condition
- Shear: A(R±,φ, z) = A(R∓,φ ± ∆Ωeqt, z)
where ∆Ωeq = Ωeq,− − Ωeq,+
Cylindrical Shearing Condition
- Shear: A(R±,φ, z) = A(R∓,φ ± ∆Ωeqt, z)
where ∆Ωeq = Ωeq,− − Ωeq,+
- Conserved quantities, A, at R− & R+
A = ⎧ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎩ ρRR ρ2
RR
(ρRφ + BφBR/4π)R2 ρRzR RBφ − φBR (zBR − RBz)R BRR
Cylindrical Shearing Box (CySB)
Cylindrical Shearing Box (CySB)
Time Evolution
(βz,0 = 103, T ∝ R−1/2, initial ρ ∝ R−1)
(LR, Lφ, Lz) = (0.4,π/6,0.1) ≈(4H,4H,H) resolved by (256,256,64)
αB = BRBφ/4πp
0.05 0.1 0.15 0.2 0.25 20 40 60 80 100 120 140 160 180 200 α t (rotation) αB at R0=1
Angular Momentum Flows
Under the steady-state condition:
∂ ∂R
- R2
ρRRΩeq + ρRδφ − BRBφ/4π
- = 0
Accretion & Bz Advection
∂ ∂t(RBz) = ∂ ∂R
R(zBR − RBz) ⇒ ⟨R,Bz⟩ = ⟨R(RBz − zBR)⟩/⟨RBz⟩
Zonal Flow
a long-lived ρ bump
Johansen+ 2009
- Physical ?
- Numerical Artifact ?
Summary
Cylindrical Shearing Box
Summary
Cylindrical Shearing Box Advantage to Cartesian SB
- can handle net mass accretion
Summary
Cylindrical Shearing Box Advantage to Cartesian SB
- can handle net mass accretion
Advantage to Global Simulations
- can resolve fine-scale turbulence
- can perform long-time simulations
Summary
Cylindrical Shearing Box Advantage to Cartesian SB
- can handle net mass accretion
Advantage to Global Simulations
- can resolve fine-scale turbulence
- can perform long-time simulations
Various potential applications
Summary
Cylindrical Shearing Box Advantage to Cartesian SB
- can handle net mass accretion
Advantage to Global Simulations
- can resolve fine-scale turbulence
- can perform long-time simulations
Various potential applications
- Accretion vs. Bz advection
Summary
Cylindrical Shearing Box Advantage to Cartesian SB
- can handle net mass accretion
Advantage to Global Simulations
- can resolve fine-scale turbulence
- can perform long-time simulations
Various potential applications
- Accretion vs. Bz advection
- Particle Acceleration
Summary
Cylindrical Shearing Box Advantage to Cartesian SB
- can handle net mass accretion
Advantage to Global Simulations
- can resolve fine-scale turbulence
- can perform long-time simulations
Various potential applications
- Accretion vs. Bz advection
- Particle Acceleration
- Dust grains in Prtoplanetary Disks
Summary
Cylindrical Shearing Box Advantage to Cartesian SB
- can handle net mass accretion
Advantage to Global Simulations
- can resolve fine-scale turbulence
- can perform long-time simulations
Various potential applications
- Accretion vs. Bz advection
- Particle Acceleration
- Dust grains in Prtoplanetary Disks
- ......