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Method of summation of some slowly convergent series Pawe Wony - - PowerPoint PPT Presentation

Method of summation of some slowly convergent series Pawe Wony Rafa Nowak e-mail: rafal.nowak@cs.uni.wroc.pl Institute of Computer Science University of Wrocaw, ul. Joliot-Curie 15, 50-383 Wrocaw, Poland Approximation and


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SLIDE 1

Method of summation of some slowly convergent series

Paweł Woźny Rafał Nowak

e-mail: rafal.nowak@cs.uni.wroc.pl Institute of Computer Science University of Wrocław,

  • ul. Joliot-Curie 15, 50-383 Wrocław, Poland

Approximation and extrapolation of convergent and divergent sequences and series CIRM Luminy, France September 28 – October 2, 2009

  • P. Woźny, R. Nowak (UWr)

Method of summation Luminy ’09 1 / 29

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SLIDE 2

Motivation

Outline

1

Motivation Annihilation by Linear Difference Operators Approach

2

Method Recurrent construction Algorithm

3

Results Relation to ε-algorithm Generalized hypergeometric series Basic hypergeometric series Orthogonal polynomials

  • P. Woźny, R. Nowak (UWr)

Method of summation Luminy ’09 2 / 29

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SLIDE 3

Motivation Annihilation by Linear Difference Operators

Notations and definitions

Series, partial sums, remainders

Consider an infinite series s =

  • n=0

an with terms an, partial sums sn =

n−1

  • j=0

an, n ∈ ◆, and remainders rn =

  • j=0

an+j, n ∈ ◆ ∪ {0}. Thus s = sn + rn

  • P. Woźny, R. Nowak (UWr)

Method of summation Luminy ’09 3 / 29

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SLIDE 4

Motivation Annihilation by Linear Difference Operators

Notations and definitions

Linear Difference Operators

Identity operator ■ xn = xn Shift operator ❊ xn = xn+1, ❊k xn = xn+k, k ∈ ❩ Linear difference operator ▲ of order ord ▲ = ℓ ▲ =

k0+ℓ

  • k=k0

λk(n) · ❊k, λk0(n), λk0+ℓ(n) = 0 Example — forward difference operator: ∆ := ❊ − ■, ∆ sn = sn+1 − sn = an (1)

  • P. Woźny, R. Nowak (UWr)

Method of summation Luminy ’09 4 / 29

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SLIDE 5

Motivation Annihilation by Linear Difference Operators

Notations and definitions

Linear Difference Operators

Identity operator ■ xn = xn Shift operator ❊ xn = xn+1, ❊k xn = xn+k, k ∈ ❩ Linear difference operator ▲ of order ord ▲ = ℓ ▲ =

k0+ℓ

  • k=k0

λk(n) · ❊k, λk0(n), λk0+ℓ(n) = 0 Example — forward difference operator: ∆ := ❊ − ■, ∆ sn = sn+1 − sn = an (1)

  • P. Woźny, R. Nowak (UWr)

Method of summation Luminy ’09 4 / 29

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SLIDE 6

Motivation Annihilation by Linear Difference Operators

Notations and definitions

Multiplication Pxn = yn, ◗yn = zn = ⇒ (◗ · P) xn = zn Powers ▲0 := ■, ▲k+1 := ▲ · ▲k Operator ▲ annihilates the sequence xn, if ▲xn = 0

Example

If xn is a polynomial in n of degree k, then ∆k+1 xn = 0.

  • P. Woźny, R. Nowak (UWr)

Method of summation Luminy ’09 5 / 29

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SLIDE 7

Motivation Annihilation by Linear Difference Operators

Notations and definitions

Multiplication Pxn = yn, ◗yn = zn = ⇒ (◗ · P) xn = zn Powers ▲0 := ■, ▲k+1 := ▲ · ▲k Operator ▲ annihilates the sequence xn, if ▲xn = 0

Example

If xn is a polynomial in n of degree k, then ∆k+1 xn = 0.

  • P. Woźny, R. Nowak (UWr)

Method of summation Luminy ’09 5 / 29

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SLIDE 8

Motivation Annihilation by Linear Difference Operators

Notations and definitions

Multiplication Pxn = yn, ◗yn = zn = ⇒ (◗ · P) xn = zn Powers ▲0 := ■, ▲k+1 := ▲ · ▲k Operator ▲ annihilates the sequence xn, if ▲xn = 0

Example

If xn is a polynomial in n of degree k, then ∆k+1 xn = 0.

  • P. Woźny, R. Nowak (UWr)

Method of summation Luminy ’09 5 / 29

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SLIDE 9

Motivation Annihilation by Linear Difference Operators

Motivation

We have s = sn + rn. (2) Let the linear difference operator ▲(∞) annihilate the remainder rn. Then ▲(∞)(s) = ▲(∞)(sn) + ▲(∞)(rn), s · ▲(∞)(1) = ▲(∞)(sn), and consequently s = ▲(∞)(sn) ▲(∞)(1) , (3) if ▲(∞)(1) = 0.

Problems

Does ▲(∞) exist? How to find annihilator ▲(∞)?

  • P. Woźny, R. Nowak (UWr)

Method of summation Luminy ’09 6 / 29

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SLIDE 10

Motivation Annihilation by Linear Difference Operators

Motivation

We have s = sn + rn. (2) Let the linear difference operator ▲(∞) annihilate the remainder rn. Then ▲(∞)(s) = ▲(∞)(sn) + ▲(∞)(rn), s · ▲(∞)(1) = ▲(∞)(sn), and consequently s = ▲(∞)(sn) ▲(∞)(1) , (3) if ▲(∞)(1) = 0.

Problems

Does ▲(∞) exist? How to find annihilator ▲(∞)?

  • P. Woźny, R. Nowak (UWr)

Method of summation Luminy ’09 6 / 29

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SLIDE 11

Motivation Approach

Levin-Type Sequence Transformation

Let ▲(m), m ∈ ◆, be an approximation of ▲(∞) in the sense that

  • ▲(m)(r(m)

n

) = 0, ▲(m)(1) = 0, (4) where r(m)

n

= rn − rn+m = an + an+1 + · · · + an+m−1. Since s ≈ sn + r(m)

n

, we can expect that Q(m)

n

:= ▲(m)(sn) ▲(m)(1) (5) gives an approximation of s, of accuracy growing when m → ∞.

  • P. Woźny, R. Nowak (UWr)

Method of summation Luminy ’09 7 / 29

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SLIDE 12

Motivation Approach

Levin-Type Sequence Transformation

Let ▲(m), m ∈ ◆, be an approximation of ▲(∞) in the sense that

  • ▲(m)(r(m)

n

) = 0, ▲(m)(1) = 0, (4) where r(m)

n

= rn − rn+m = an + an+1 + · · · + an+m−1. Since s ≈ sn + r(m)

n

, we can expect that Q(m)

n

:= ▲(m)(sn) ▲(m)(1) (5) gives an approximation of s, of accuracy growing when m → ∞.

  • P. Woźny, R. Nowak (UWr)

Method of summation Luminy ’09 7 / 29

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SLIDE 13

Method

Outline

1

Motivation Annihilation by Linear Difference Operators Approach

2

Method Recurrent construction Algorithm

3

Results Relation to ε-algorithm Generalized hypergeometric series Basic hypergeometric series Orthogonal polynomials

  • P. Woźny, R. Nowak (UWr)

Method of summation Luminy ’09 8 / 29

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SLIDE 14

Method Recurrent construction

Method Of Obtaining The Annihilators ▲(m)

Recurrent Construction

  • P. Wozny, R. Nowak,

Method of summation of some slowly convergent, Applied Mathematics and Computation (2009), accepted. According to ▲(m)(an + an+1 + . . . + an+m−1

  • r(m)

n

) = 0, (6)

  • perator ▲(1) should annihilate an.

A possible choice is the first-order operator ▲(1) := ∆ · 1 an ■

  • =

1 an+1 ❊ − 1 an ■ . (7) The operators ▲(2), ▲(3), . . . are constructed recursively by ▲(m) = P(m)▲(m−1), m 2. (8)

  • P. Woźny, R. Nowak (UWr)

Method of summation Luminy ’09 9 / 29

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SLIDE 15

Method Recurrent construction

Method Of Obtaining The Annihilators ▲(m)

Recurrent Construction

  • P. Wozny, R. Nowak,

Method of summation of some slowly convergent, Applied Mathematics and Computation (2009), accepted. According to ▲(m)(an + an+1 + . . . + an+m−1

  • r(m)

n

) = 0, (6)

  • perator ▲(1) should annihilate an.

A possible choice is the first-order operator ▲(1) := ∆ · 1 an ■

  • =

1 an+1 ❊ − 1 an ■ . (7) The operators ▲(2), ▲(3), . . . are constructed recursively by ▲(m) = P(m)▲(m−1), m 2. (8)

  • P. Woźny, R. Nowak (UWr)

Method of summation Luminy ’09 9 / 29

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SLIDE 16

Method Recurrent construction

Method Of Obtaining The Annihilators ▲(m)

Recurrent Construction

  • P. Wozny, R. Nowak,

Method of summation of some slowly convergent, Applied Mathematics and Computation (2009), accepted. According to ▲(m)(an + an+1 + . . . + an+m−1

  • r(m)

n

) = 0, (6)

  • perator ▲(1) should annihilate an.

A possible choice is the first-order operator ▲(1) := ∆ · 1 an ■

  • =

1 an+1 ❊ − 1 an ■ . (7) The operators ▲(2), ▲(3), . . . are constructed recursively by ▲(m) = P(m)▲(m−1), m 2. (8)

  • P. Woźny, R. Nowak (UWr)

Method of summation Luminy ’09 9 / 29

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SLIDE 17

Method Recurrent construction

Method Of Obtaining The Annihilators ▲(m)

Recurrent Construction

  • P. Wozny, R. Nowak,

Method of summation of some slowly convergent, Applied Mathematics and Computation (2009), accepted. According to ▲(m)(an + an+1 + . . . + an+m−1

  • r(m)

n

) = 0, (6)

  • perator ▲(1) should annihilate an.

A possible choice is the first-order operator ▲(1) := ∆ · 1 an ■

  • =

1 an+1 ❊ − 1 an ■ . (7) The operators ▲(2), ▲(3), . . . are constructed recursively by ▲(m) = P(m)▲(m−1), m 2. (8)

  • P. Woźny, R. Nowak (UWr)

Method of summation Luminy ’09 9 / 29

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SLIDE 18

Method Recurrent construction

Step Of Construction

r(m)

n

= r(m−1)

n

+ an+m−1 ▲(m−1)(r(m−1)

n

) = 0

  • ▲(m−1) := ❊m−1 ▲(1) ❊−m+1

= ⇒

  • ▲(m−1)(an+m−1) = 0.

Assume that operators P(m) and ❘(m) are such that P(m)▲(m−1) = ❘(m) ▲(m−1). (9) Then ▲(m) := P(m)▲(m−1), ▲(m)(r(m)

n

) = 0 Proof:

▲(m)(r(m)

n

) = ▲(m)(r(m−1)

n

) + ▲(m) (an+m−1) = P(m)▲(m−1)(r(m−1)

n

) + ❘(m) ▲(m−1) (an+m−1) = P(m)(0) + ❘(m)(0) = 0,

  • P. Woźny, R. Nowak (UWr)

Method of summation Luminy ’09 10 / 29

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SLIDE 19

Method Recurrent construction

Step Of Construction

r(m)

n

= r(m−1)

n

+ an+m−1 ▲(m−1)(r(m−1)

n

) = 0

  • ▲(m−1) := ❊m−1 ▲(1) ❊−m+1

= ⇒

  • ▲(m−1)(an+m−1) = 0.

Assume that operators P(m) and ❘(m) are such that P(m)▲(m−1) = ❘(m) ▲(m−1). (9) Then ▲(m) := P(m)▲(m−1), ▲(m)(r(m)

n

) = 0 Proof:

▲(m)(r(m)

n

) = ▲(m)(r(m−1)

n

) + ▲(m) (an+m−1) = P(m)▲(m−1)(r(m−1)

n

) + ❘(m) ▲(m−1) (an+m−1) = P(m)(0) + ❘(m)(0) = 0,

  • P. Woźny, R. Nowak (UWr)

Method of summation Luminy ’09 10 / 29

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SLIDE 20

Method Recurrent construction

Step Of Construction

r(m)

n

= r(m−1)

n

+ an+m−1 ▲(m−1)(r(m−1)

n

) = 0

  • ▲(m−1) := ❊m−1 ▲(1) ❊−m+1

= ⇒

  • ▲(m−1)(an+m−1) = 0.

Assume that operators P(m) and ❘(m) are such that P(m)▲(m−1) = ❘(m) ▲(m−1). (9) Then ▲(m) := P(m)▲(m−1), ▲(m)(r(m)

n

) = 0 Proof:

▲(m)(r(m)

n

) = ▲(m)(r(m−1)

n

) + ▲(m) (an+m−1) = P(m)▲(m−1)(r(m−1)

n

) + ❘(m) ▲(m−1) (an+m−1) = P(m)(0) + ❘(m)(0) = 0,

  • P. Woźny, R. Nowak (UWr)

Method of summation Luminy ’09 10 / 29

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SLIDE 21

Method Recurrent construction

Step Of Construction

r(m)

n

= r(m−1)

n

+ an+m−1 ▲(m−1)(r(m−1)

n

) = 0

  • ▲(m−1) := ❊m−1 ▲(1) ❊−m+1

= ⇒

  • ▲(m−1)(an+m−1) = 0.

Assume that operators P(m) and ❘(m) are such that P(m)▲(m−1) = ❘(m) ▲(m−1). (9) Then ▲(m) := P(m)▲(m−1), ▲(m)(r(m)

n

) = 0 Proof:

▲(m)(r(m)

n

) = ▲(m)(r(m−1)

n

) + ▲(m) (an+m−1) = P(m)▲(m−1)(r(m−1)

n

) + ❘(m) ▲(m−1) (an+m−1) = P(m)(0) + ❘(m)(0) = 0,

  • P. Woźny, R. Nowak (UWr)

Method of summation Luminy ’09 10 / 29

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SLIDE 22

Method Recurrent construction

Step Of Construction

r(m)

n

= r(m−1)

n

+ an+m−1 ▲(m−1)(r(m−1)

n

) = 0

  • ▲(m−1) := ❊m−1 ▲(1) ❊−m+1

= ⇒

  • ▲(m−1)(an+m−1) = 0.

Assume that operators P(m) and ❘(m) are such that P(m)▲(m−1) = ❘(m) ▲(m−1). (9) Then ▲(m) := P(m)▲(m−1), ▲(m)(r(m)

n

) = 0 Proof:

▲(m)(r(m)

n

) = ▲(m)(r(m−1)

n

) + ▲(m) (an+m−1) = P(m)▲(m−1)(r(m−1)

n

) + ❘(m) ▲(m−1) (an+m−1) = P(m)(0) + ❘(m)(0) = 0,

  • P. Woźny, R. Nowak (UWr)

Method of summation Luminy ’09 10 / 29

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SLIDE 23

Method Recurrent construction

Step Of Construction

r(m)

n

= r(m−1)

n

+ an+m−1 ▲(m−1)(r(m−1)

n

) = 0

  • ▲(m−1) := ❊m−1 ▲(1) ❊−m+1

= ⇒

  • ▲(m−1)(an+m−1) = 0.

Assume that operators P(m) and ❘(m) are such that P(m)▲(m−1) = ❘(m) ▲(m−1). (9) Then ▲(m) := P(m)▲(m−1), ▲(m)(r(m)

n

) = 0 Proof:

▲(m)(r(m)

n

) = ▲(m)(r(m−1)

n

) + ▲(m) (an+m−1) = P(m)▲(m−1)(r(m−1)

n

) + ❘(m) ▲(m−1) (an+m−1) = P(m)(0) + ❘(m)(0) = 0,

  • P. Woźny, R. Nowak (UWr)

Method of summation Luminy ’09 10 / 29

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SLIDE 24

Method Recurrent construction

Example (A)

2 ln 2 =

  • n=0

an, an := 1 (n + 1) 2n (10) ▲(1) := (n + 1) ■ −(2n + 4) ❊ = ⇒ ▲(1)(an) = 0 (11)

  • ▲(1) = ❊ ▲(1) ❊−1 = (n + 2) ■ −(2n + 6) ❊

= ⇒

  • ▲(1)(an+1) = 0

P(2)▲(1) = ❘(2) ▲(1) (12) P(2) = π(2)

0 (n) ■ +π(2) 1 (n) ❊,

❘(2) = ρ(2)

0 (n) ■ +ρ(2) 1 (n) ❊

P(2)▲(1) = ⊞ ■ + ⊟ ❊ + ⊠ ❊2, ❘(2) ▲(1) = ⊞ ■ + ⊟ ❊ + ⊠ ❊2 P(2) = (n + 2) ■ −(2n + 8) ❊, ❘(2) = (n + 1) ■ −(2n + 6) ❊, ▲(2) := P(2)▲(1) = (n + 1)(n + 2) ■ −4 (n + 2)(n + 3) ❊ +4 (n + 3)(n + 4) ❊2 .

  • P. Woźny, R. Nowak (UWr)

Method of summation Luminy ’09 11 / 29

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SLIDE 25

Method Recurrent construction

Example (A)

2 ln 2 =

  • n=0

an, an := 1 (n + 1) 2n (10) ▲(1) := (n + 1) ■ −(2n + 4) ❊ = ⇒ ▲(1)(an) = 0 (11)

  • ▲(1) = ❊ ▲(1) ❊−1 = (n + 2) ■ −(2n + 6) ❊

= ⇒

  • ▲(1)(an+1) = 0

P(2)▲(1) = ❘(2) ▲(1) (12) P(2) = π(2)

0 (n) ■ +π(2) 1 (n) ❊,

❘(2) = ρ(2)

0 (n) ■ +ρ(2) 1 (n) ❊

P(2)▲(1) = ⊞ ■ + ⊟ ❊ + ⊠ ❊2, ❘(2) ▲(1) = ⊞ ■ + ⊟ ❊ + ⊠ ❊2 P(2) = (n + 2) ■ −(2n + 8) ❊, ❘(2) = (n + 1) ■ −(2n + 6) ❊, ▲(2) := P(2)▲(1) = (n + 1)(n + 2) ■ −4 (n + 2)(n + 3) ❊ +4 (n + 3)(n + 4) ❊2 .

  • P. Woźny, R. Nowak (UWr)

Method of summation Luminy ’09 11 / 29

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SLIDE 26

Method Recurrent construction

Example (A)

2 ln 2 =

  • n=0

an, an := 1 (n + 1) 2n (10) ▲(1) := (n + 1) ■ −(2n + 4) ❊ = ⇒ ▲(1)(an) = 0 (11)

  • ▲(1) = ❊ ▲(1) ❊−1 = (n + 2) ■ −(2n + 6) ❊

= ⇒

  • ▲(1)(an+1) = 0

P(2)▲(1) = ❘(2) ▲(1) (12) P(2) = π(2)

0 (n) ■ +π(2) 1 (n) ❊,

❘(2) = ρ(2)

0 (n) ■ +ρ(2) 1 (n) ❊

P(2)▲(1) = ⊞ ■ + ⊟ ❊ + ⊠ ❊2, ❘(2) ▲(1) = ⊞ ■ + ⊟ ❊ + ⊠ ❊2 P(2) = (n + 2) ■ −(2n + 8) ❊, ❘(2) = (n + 1) ■ −(2n + 6) ❊, ▲(2) := P(2)▲(1) = (n + 1)(n + 2) ■ −4 (n + 2)(n + 3) ❊ +4 (n + 3)(n + 4) ❊2 .

  • P. Woźny, R. Nowak (UWr)

Method of summation Luminy ’09 11 / 29

slide-27
SLIDE 27

Method Recurrent construction

Example (A)

2 ln 2 =

  • n=0

an, an := 1 (n + 1) 2n (10) ▲(1) := (n + 1) ■ −(2n + 4) ❊ = ⇒ ▲(1)(an) = 0 (11)

  • ▲(1) = ❊ ▲(1) ❊−1 = (n + 2) ■ −(2n + 6) ❊

= ⇒

  • ▲(1)(an+1) = 0

P(2)▲(1) = ❘(2) ▲(1) (12) P(2) = π(2)

0 (n) ■ +π(2) 1 (n) ❊,

❘(2) = ρ(2)

0 (n) ■ +ρ(2) 1 (n) ❊

P(2)▲(1) = ⊞ ■ + ⊟ ❊ + ⊠ ❊2, ❘(2) ▲(1) = ⊞ ■ + ⊟ ❊ + ⊠ ❊2 P(2) = (n + 2) ■ −(2n + 8) ❊, ❘(2) = (n + 1) ■ −(2n + 6) ❊, ▲(2) := P(2)▲(1) = (n + 1)(n + 2) ■ −4 (n + 2)(n + 3) ❊ +4 (n + 3)(n + 4) ❊2 .

  • P. Woźny, R. Nowak (UWr)

Method of summation Luminy ’09 11 / 29

slide-28
SLIDE 28

Method Recurrent construction

Example (A (cont.))

▲(2) = ⊞ ■ + ⊟ ❊ + ⊠ ❊2, ▲(2)(an + an+1) = 0

  • ▲(2) = ❊2 ▲(1) ❊−2 = (n + 3) ■ −(2n + 8) ❊

P(3)▲(2) = ❘(3) ▲(2) (13) P(3) = π(3)

0 (n) ■ +π(3) 1 (n) ❊,

❘(3) = ρ(3)

0 (n) ■ +ρ(3) 1 (n) ❊ +ρ(3) 2 (n) ❊2,

▲(3) := P(3)▲(2) = ⊞ ■ + ⊟ ❊ + ⊠ ❊2 + ⊡ ❊3 . . . ⇓ P(m) = (n + m) ■ −(2n + 4m) ❊, m ∈ ◆ ? ▲(m) = P(m)P(m−1) · · · P(1)

  • P. Woźny, R. Nowak (UWr)

Method of summation Luminy ’09 12 / 29

slide-29
SLIDE 29

Method Recurrent construction

Example (A (cont.))

▲(2) = ⊞ ■ + ⊟ ❊ + ⊠ ❊2, ▲(2)(an + an+1) = 0

  • ▲(2) = ❊2 ▲(1) ❊−2 = (n + 3) ■ −(2n + 8) ❊

P(3)▲(2) = ❘(3) ▲(2) (13) P(3) = π(3)

0 (n) ■ +π(3) 1 (n) ❊,

❘(3) = ρ(3)

0 (n) ■ +ρ(3) 1 (n) ❊ +ρ(3) 2 (n) ❊2,

▲(3) := P(3)▲(2) = ⊞ ■ + ⊟ ❊ + ⊠ ❊2 + ⊡ ❊3 . . . ⇓ P(m) = (n + m) ■ −(2n + 4m) ❊, m ∈ ◆ ? ▲(m) = P(m)P(m−1) · · · P(1)

  • P. Woźny, R. Nowak (UWr)

Method of summation Luminy ’09 12 / 29

slide-30
SLIDE 30

Method Recurrent construction

Example (A (cont.))

▲(2) = ⊞ ■ + ⊟ ❊ + ⊠ ❊2, ▲(2)(an + an+1) = 0

  • ▲(2) = ❊2 ▲(1) ❊−2 = (n + 3) ■ −(2n + 8) ❊

P(3)▲(2) = ❘(3) ▲(2) (13) P(3) = (n + 3) ■ −(2n + 12) ❊, ❘(3) = ρ(3)

0 (n) ■ +ρ(3) 1 (n) ❊ +ρ(3) 2 (n) ❊2,

▲(3) := P(3)▲(2) = ⊞ ■ + ⊟ ❊ + ⊠ ❊2 + ⊡ ❊3 . . . ⇓ P(m) = (n + m) ■ −(2n + 4m) ❊, m ∈ ◆ ? ▲(m) = P(m)P(m−1) · · · P(1)

  • P. Woźny, R. Nowak (UWr)

Method of summation Luminy ’09 12 / 29

slide-31
SLIDE 31

Method Recurrent construction

Example (A (cont.))

▲(2) = ⊞ ■ + ⊟ ❊ + ⊠ ❊2, ▲(2)(an + an+1) = 0

  • ▲(2) = ❊2 ▲(1) ❊−2 = (n + 3) ■ −(2n + 8) ❊

P(3)▲(2) = ❘(3) ▲(2) (13) P(3) = (n + 3) ■ −(2n + 12) ❊, ❘(3) = ρ(3)

0 (n) ■ +ρ(3) 1 (n) ❊ +ρ(3) 2 (n) ❊2,

▲(3) := P(3)▲(2) = ⊞ ■ + ⊟ ❊ + ⊠ ❊2 + ⊡ ❊3 . . . ⇓ P(m) = (n + m) ■ −(2n + 4m) ❊, m ∈ ◆ ? ▲(m) = P(m)P(m−1) · · · P(1)

  • P. Woźny, R. Nowak (UWr)

Method of summation Luminy ’09 12 / 29

slide-32
SLIDE 32

Method Recurrent construction

Transformation Q(m)

n ▲(m)(an + an+1 + · · · + an+m−1) = 0, m ∈ ◆ ▲(m) = P(m)▲(m−1) = P(m)P(m−1) · · · P(1) Q(m)

n

:= ▲(m)(sn) ▲(m)(1) =: N(m)

n

D(m)

n

(14) N(m)

n

= P(m)(N(m−1)

n

), D(m)

n

= P(m)(D(m−1)

n

) P(m) = ? for m ∈ ◆

  • P. Woźny, R. Nowak (UWr)

Method of summation Luminy ’09 13 / 29

slide-33
SLIDE 33

Method Recurrent construction

Transformation Q(m)

n ▲(m)(an + an+1 + · · · + an+m−1) = 0, m ∈ ◆ ▲(m) = P(m)▲(m−1) = P(m)P(m−1) · · · P(1) Q(m)

n

:= ▲(m)(sn) ▲(m)(1) =: N(m)

n

D(m)

n

(14) N(m)

n

= P(m)(N(m−1)

n

), D(m)

n

= P(m)(D(m−1)

n

) P(m) = ? for m ∈ ◆

  • P. Woźny, R. Nowak (UWr)

Method of summation Luminy ’09 13 / 29

slide-34
SLIDE 34

Method Recurrent construction

Transformation Q(m)

n ▲(m)(an + an+1 + · · · + an+m−1) = 0, m ∈ ◆ ▲(m) = P(m)▲(m−1) = P(m)P(m−1) · · · P(1) Q(m)

n

:= ▲(m)(sn) ▲(m)(1) =: N(m)

n

D(m)

n

(14) N(m)

n

= P(m)(N(m−1)

n

), D(m)

n

= P(m)(D(m−1)

n

) P(m) = ? for m ∈ ◆

  • P. Woźny, R. Nowak (UWr)

Method of summation Luminy ’09 13 / 29

slide-35
SLIDE 35

Method Recurrent construction

Transformation Q(m)

n ▲(m)(an + an+1 + · · · + an+m−1) = 0, m ∈ ◆ ▲(m) = P(m)▲(m−1) = P(m)P(m−1) · · · P(1) Q(m)

n

:= ▲(m)(sn) ▲(m)(1) =: N(m)

n

D(m)

n

(14) N(m)

n

= P(m)(N(m−1)

n

), D(m)

n

= P(m)(D(m−1)

n

) P(m) = ? for m ∈ ◆

  • P. Woźny, R. Nowak (UWr)

Method of summation Luminy ’09 13 / 29

slide-36
SLIDE 36

Method Algorithm

Algorithm

Let ▲(0) := ■, ▲(1)(an) = 0, P(1) := ▲(1), N(0)

n

:= sn, D(0)

n

:= 1. For k = 1, 2, . . . do

1

If k 2, then determine such operators P(k) and ❘(k) that P(k)▲(k−1) = ❘(k) ▲(k−1), (15) where ▲(k−1) = P(k−1)P(k−2) · · · P(1),

  • ▲(k−1) = ❊k−1 ▲(1) ❊1−k

2

Compute N(k)

n

:= P(k)(N(k−1)

n

), D(k)

n

:= P(k)(D(k−1)

n

) Q(k)

n

:= N(k)

n

D(k)

n

  • P. Woźny, R. Nowak (UWr)

Method of summation Luminy ’09 14 / 29

slide-37
SLIDE 37

Method Algorithm

Example A ...

sn =

n−1

  • j=0

an, an = 1 (n + 1)2n P(m) = (n + m) ■ −(2n + 4m) ❊, m ∈ ◆ N(0)

n

:= sn =

n−1

  • j=0

aj, D(0)

n

:= 1, N(m)

n

:= P(m)(N(m−1)

n

) = (n + m)N(m−1)

n

− (2n + 4m)N(m−1)

n+1

, m 1, D(m)

n

:= P(m)(D(m−1)

n

) = (n + m)D(m−1)

n

− (2n + 4m)D(m−1)

n+1

, m 1, Q(m)

n

:= N(m)

n

D(m)

n

.

  • P. Woźny, R. Nowak (UWr)

Method of summation Luminy ’09 15 / 29

slide-38
SLIDE 38

Results

Outline

1

Motivation Annihilation by Linear Difference Operators Approach

2

Method Recurrent construction Algorithm

3

Results Relation to ε-algorithm Generalized hypergeometric series Basic hypergeometric series Orthogonal polynomials

  • P. Woźny, R. Nowak (UWr)

Method of summation Luminy ’09 16 / 29

slide-39
SLIDE 39

Results Relation to ε-algorithm

Theorem

If ord P(m) = 1, then Q(m)

n

= ε(n)

2m,

m ∈ ◆.

Example A ...

Given the partial sums s1, s2, . . . , s5, one can obtain the following array of quantities Q(m)

n

(underlined digits are exact):

Q(0)

1

= 1.000 Q(1)

1

= 1.3750 Q(2)

1

= 1.38596 Q(3)

1

= 1.386285 Q(4)

1

= 1.38629408 Q(0)

2

= 1.250 Q(1)

2

= 1.3833 Q(2)

2

= 1.38622 Q(3)

2

= 1.386292 Q(0)

3

= 1.333 Q(1)

3

= 1.3854 Q(2)

3

= 1.38627 Q(0)

4

= 1.365 Q(1)

4

= 1.3860 Q(0)

5

= 1.377

Using Wynn’s ε algorithm and Aitken’s iterated ∆2 process one obtains ε(1)

4

= 1.38596, A(1)

2

= 1.38611.

  • P. Woźny, R. Nowak (UWr)

Method of summation Luminy ’09 17 / 29

slide-40
SLIDE 40

Results Relation to ε-algorithm

Theorem

If ord P(m) = 1, then Q(m)

n

= ε(n)

2m,

m ∈ ◆.

Example A ...

Given the partial sums s1, s2, . . . , s5, one can obtain the following array of quantities Q(m)

n

(underlined digits are exact):

Q(0)

1

= 1.000 Q(1)

1

= 1.3750 Q(2)

1

= 1.38596 Q(3)

1

= 1.386285 Q(4)

1

= 1.38629408 Q(0)

2

= 1.250 Q(1)

2

= 1.3833 Q(2)

2

= 1.38622 Q(3)

2

= 1.386292 Q(0)

3

= 1.333 Q(1)

3

= 1.3854 Q(2)

3

= 1.38627 Q(0)

4

= 1.365 Q(1)

4

= 1.3860 Q(0)

5

= 1.377

Using Wynn’s ε algorithm and Aitken’s iterated ∆2 process one obtains ε(1)

4

= 1.38596, A(1)

2

= 1.38611.

  • P. Woźny, R. Nowak (UWr)

Method of summation Luminy ’09 17 / 29

slide-41
SLIDE 41

Results Generalized hypergeometric series

Series p+1Fp(1, α; β; x), p 1

p+1F p

  • 1, α1, α2, . . . , αp

β1, β2, . . . , βp x

  • =

  • n=0

an with an := (α1)n(α2)n · · · (αp)n (β1)n(β2)n · · · (βp)n xn.

Operators P(m)

P(1) := ∆p 1 an ■

  • =

⇒ P(1)(an) = 0, P(m) :=

p

  • j=0

mp j ∆j p

  • i=1

(βi + n + m(p + 1) − j − 2)

  • ∆p−j,

m = 2, 3 . . . ▲(m) := P(m)P(m−1) · · · P(1) = ⇒ ▲(m) = ∆mp p

  • i=1

(βi)n+m−1 (αi)n · x−n ■

  • ▲(m) (an + an+1 + . . . + an+m−1) = 0
  • P. Woźny, R. Nowak (UWr)

Method of summation Luminy ’09 18 / 29

slide-42
SLIDE 42

Results Generalized hypergeometric series

Series p+1Fp(1, α; β; x), p 1

p+1F p

  • 1, α1, α2, . . . , αp

β1, β2, . . . , βp x

  • =

  • n=0

an with an := (α1)n(α2)n · · · (αp)n (β1)n(β2)n · · · (βp)n xn.

Operators P(m)

P(1) := ∆p 1 an ■

  • =

⇒ P(1)(an) = 0, P(m) :=

p

  • j=0

mp j ∆j p

  • i=1

(βi + n + m(p + 1) − j − 2)

  • ∆p−j,

m = 2, 3 . . . ▲(m) := P(m)P(m−1) · · · P(1) = ⇒ ▲(m) = ∆mp p

  • i=1

(βi)n+m−1 (αi)n · x−n ■

  • ▲(m) (an + an+1 + . . . + an+m−1) = 0
  • P. Woźny, R. Nowak (UWr)

Method of summation Luminy ’09 18 / 29

slide-43
SLIDE 43

Results Generalized hypergeometric series

Series p+1Fp(1, α; β; x), p 1

p+1F p

  • 1, α1, α2, . . . , αp

β1, β2, . . . , βp x

  • =

  • n=0

an with an := (α1)n(α2)n · · · (αp)n (β1)n(β2)n · · · (βp)n xn.

Operators P(m)

P(1) := ∆p 1 an ■

  • =

⇒ P(1)(an) = 0, P(m) :=

p

  • j=0

mp j ∆j p

  • i=1

(βi + n + m(p + 1) − j − 2)

  • ∆p−j,

m = 2, 3 . . . ▲(m) := P(m)P(m−1) · · · P(1) = ⇒ ▲(m) = ∆mp p

  • i=1

(βi)n+m−1 (αi)n · x−n ■

  • ▲(m) (an + an+1 + . . . + an+m−1) = 0
  • P. Woźny, R. Nowak (UWr)

Method of summation Luminy ’09 18 / 29

slide-44
SLIDE 44

Results Generalized hypergeometric series

Example (Lemniscate constant)

A := 2F

1

1

4, 1 2 5 4

1

  • = 3F

2

  • 1, 1

4, 1 2

1, 5

4

1

  • =

  • n=0

an, an := ( 1

4)n ( 1 2)n

(1)n ( 5

4)n

acc(σ) := − log10

  • σ

s − 1

accuracy of σ, acc(s15) = 1.25, acc(s103) = 2.17, acc(s106) = 3.67 acc(ε(1)

14 ) = 1.61

acc(

uL (14) 1

(1, { {sn} })) = 11.50 acc(Q(7)

1 ) = 13.03

  • P. Woźny, R. Nowak (UWr)

Method of summation Luminy ’09 19 / 29

slide-45
SLIDE 45

Results Generalized hypergeometric series

Example (Lemniscate constant)

A := 2F

1

1

4, 1 2 5 4

1

  • = 3F

2

  • 1, 1

4, 1 2

1, 5

4

1

  • =

  • n=0

an, an := ( 1

4)n ( 1 2)n

(1)n ( 5

4)n

acc(σ) := − log10

  • σ

s − 1

accuracy of σ, acc(s15) = 1.25, acc(s103) = 2.17, acc(s106) = 3.67 acc(ε(1)

14 ) = 1.61

acc(

uL (14) 1

(1, { {sn} })) = 11.50 acc(Q(7)

1 ) = 13.03

  • P. Woźny, R. Nowak (UWr)

Method of summation Luminy ’09 19 / 29

slide-46
SLIDE 46

Results Generalized hypergeometric series

Example (Lemniscate constant)

A := 2F

1

1

4, 1 2 5 4

1

  • = 3F

2

  • 1, 1

4, 1 2

1, 5

4

1

  • =

  • n=0

an, an := ( 1

4)n ( 1 2)n

(1)n ( 5

4)n

acc(σ) := − log10

  • σ

s − 1

accuracy of σ, acc(s15) = 1.25, acc(s103) = 2.17, acc(s106) = 3.67 acc(ε(1)

14 ) = 1.61

acc(

uL (14) 1

(1, { {sn} })) = 11.50 acc(Q(7)

1 ) = 13.03

  • P. Woźny, R. Nowak (UWr)

Method of summation Luminy ’09 19 / 29

slide-47
SLIDE 47

Results Generalized hypergeometric series

Example (Lemniscate constant)

A := 2F

1

1

4, 1 2 5 4

1

  • = 3F

2

  • 1, 1

4, 1 2

1, 5

4

1

  • =

  • n=0

an, an := ( 1

4)n ( 1 2)n

(1)n ( 5

4)n

acc(σ) := − log10

  • σ

s − 1

accuracy of σ, acc(s15) = 1.25, acc(s103) = 2.17, acc(s106) = 3.67 acc(ε(1)

14 ) = 1.61

acc(

uL (14) 1

(1, { {sn} })) = 11.50 acc(Q(7)

1 ) = 13.03

  • P. Woźny, R. Nowak (UWr)

Method of summation Luminy ’09 19 / 29

slide-48
SLIDE 48

Results Generalized hypergeometric series

Example (Lemniscate constant)

A := 2F

1

1

4, 1 2 5 4

1

  • = 3F

2

  • 1, 1

4, 1 2

1, 5

4

1

  • =

  • n=0

an, an := ( 1

4)n ( 1 2)n

(1)n ( 5

4)n

acc(σ) := − log10

  • σ

s − 1

accuracy of σ, acc(s15) = 1.25, acc(s103) = 2.17, acc(s106) = 3.67 acc(ε(1)

14 ) = 1.61

acc(

uL (14) 1

(1, { {sn} })) = 11.50 acc(Q(7)

1 ) = 13.03

  • P. Woźny, R. Nowak (UWr)

Method of summation Luminy ’09 19 / 29

slide-49
SLIDE 49

Results Generalized hypergeometric series

Some Theoretical Results

Theorem

The Q transformation, applied to the series p+1Fp(1, α; β; x) with x = 1, is regular, i.e., lim

n→∞ Q(m) n

(sn) = p+1F

p

  • 1, α1, α2, . . . , αp

β1, β2, . . . , βp x

  • for all m ∈ ◆.

Theorem

p+1F p

  • 1, α1, α2, . . . , αp

β1, β2, . . . , βp x

  • − Q(m)

n

(sn) = O

  • xn+m(p+1)

, x → 0.

  • P. Woźny, R. Nowak (UWr)

Method of summation Luminy ’09 20 / 29

slide-50
SLIDE 50

Results Generalized hypergeometric series

C´ ıˇ zek, Zamastil and Sk´ ala transformation G (m)

n G (m)

n

  • {

{qk} }m−1

k=1 , {

{sn} }, { {ωn} } := ∆m m−1

  • k=1

(n + qk) sn ωn

  • ∆m

m−1

  • k=1

(n + qk) 1 ωn

  • (16)

{ {qk} }m−1

k=1

set of parameters, { {ωn} } remainder estimates (see [1] or [4, (2.13)])

Theorem

Q(m)

n

= G (m∗)

n

  • {

{q∗

k}

}m∗−1

k=1 , {

{sn} }, { {ω∗

n}

}

  • ,

m∗ := mp, ω∗

n := (n + 1)p−1an,

{ {q∗

k}

}m∗−1

k=1

:=

  • 1, 1, . . . , 1
  • p−1 times

; β1, β2, . . . , βp; β1 + 1, β2 + 1, . . . , βp + 1; . . . ; β1 + m − 2, β2 + m − 2, . . . , βp + m − 2

  • .

(17)

  • P. Woźny, R. Nowak (UWr)

Method of summation Luminy ’09 21 / 29

slide-51
SLIDE 51

Results Generalized hypergeometric series

C´ ıˇ zek, Zamastil and Sk´ ala transformation G (m)

n G (m)

n

  • {

{qk} }m−1

k=1 , {

{sn} }, { {ωn} } := ∆m m−1

  • k=1

(n + qk) sn ωn

  • ∆m

m−1

  • k=1

(n + qk) 1 ωn

  • (16)

{ {qk} }m−1

k=1

set of parameters, { {ωn} } remainder estimates (see [1] or [4, (2.13)]) qk ≡ 1 = ⇒ Levin L transformation qk = k = ⇒ Weniger S transformation (see [4, §8.2])

Theorem

Q(m)

n

= G (m∗)

n

  • {

{q∗

k}

}m∗−1

k=1 , {

{sn} }, { {ω∗

n}

}

  • ,

m∗ := mp, ω∗

n := (n + 1)p−1an,

{ {q∗

k}

}m∗−1

k=1

:=

  • 1, 1, . . . , 1
  • p−1 times

; β1, β2, . . . , βp; β1 + 1, β2 + 1, . . . , βp + 1; . . . ; β1 + m − 2, β2 + m − 2, . . . , βp + m − 2

  • .

(17)

  • P. Woźny, R. Nowak (UWr)

Method of summation Luminy ’09 21 / 29

slide-52
SLIDE 52

Results Generalized hypergeometric series

C´ ıˇ zek, Zamastil and Sk´ ala transformation G (m)

n G (m)

n

  • {

{qk} }m−1

k=1 , {

{sn} }, { {ωn} } := ∆m m−1

  • k=1

(n + qk) sn ωn

  • ∆m

m−1

  • k=1

(n + qk) 1 ωn

  • (16)

Theorem

Q(m)

n

= G (m∗)

n

  • {

{q∗

k}

}m∗−1

k=1 , {

{sn} }, { {ω∗

n}

}

  • ,

m∗ := mp, ω∗

n := (n + 1)p−1an,

{ {q∗

k}

}m∗−1

k=1

:=

  • 1, 1, . . . , 1
  • p−1 times

; β1, β2, . . . , βp; β1 + 1, β2 + 1, . . . , βp + 1; . . . ; β1 + m − 2, β2 + m − 2, . . . , βp + m − 2

  • .

(17)

  • P. Woźny, R. Nowak (UWr)

Method of summation Luminy ’09 21 / 29

slide-53
SLIDE 53

Results Generalized hypergeometric series

Example

s = 5F

4

  • 1, 1, 2, 2, 7

3, 5, 6, 9 99 100

  • ≈ 1.0376328566238592296948,

Q(5)

1

= G (20)

1

({ {q∗

k}

}, { {sn} }, { {ω∗

n}

} ≈ 1.03763285662385922975208,

acc(G (m)

n

  • {

{qk} }m−1

k=1 , {

{sn} }, { {ωn} }

  • ) :

remainder estimates ωn parameters qk ω∗

n

t-variant u-variant v-variant q∗

k

19.26 15.46 16.78 17.67 1 (Levin L [4, (7.1-7), β = 1]) 18.44 14.46 15.83 16.69 k (Weniger S [4, (8.2-7), β = 1]) 14.20 16.04 17.33 18.24 k2 (cf. [1, Tab. 1, 2]) 1.51 10.60 8.39 9.73

  • P. Woźny, R. Nowak (UWr)

Method of summation Luminy ’09 22 / 29

slide-54
SLIDE 54

Results Basic hypergeometric series

q-hypergeometric series

Consider the series

p+1φ p

  • q, α1, . . . , αp

β1, β2, . . . , βp q; x

  • =

  • n=0

an with an := (α1; q)n(α2; q)n · · · (αp; q)n (β1; q)n(β2; q)n · · · (βp; q)n xn, (18) where (z; q)k is a q-Pochhammer symbol defined by: (z; q)k :=                    1, k = 0,

k−1

  • j=0

(1 − zqj), k > 0,

  • j=0

(1 − zqj), k = ∞,

  • P. Woźny, R. Nowak (UWr)

Method of summation Luminy ’09 23 / 29

slide-55
SLIDE 55

Results Basic hypergeometric series

Notations

△q

(0; i) := ■,

△q

(m; i) :=

  • ❊ −qm+i−1 ■
  • △q

(m−1; i),

m ∈ ◆, i ∈ ❩

Operators P(m)

P(1) := △q

(p; 0)

1 an ■

  • ,

P(m) :=

p

  • j=0

mp j

  • q

·

  • △q

(j; 0)

p

  • i=1

(1 − βi qn+m(p+1)−j−2)

  • △q

(p−j; mp−m),

m 2 where r j

  • q

:= (q; q)r (q; q)j (q; q)r−j , r, j ∈ ◆0, j r.

  • P. Woźny, R. Nowak (UWr)

Method of summation Luminy ’09 24 / 29

slide-56
SLIDE 56

Results Basic hypergeometric series

Notations

△q

(0; i) := ■,

△q

(m; i) :=

  • ❊ −qm+i−1 ■
  • △q

(m−1; i),

m ∈ ◆, i ∈ ❩

Operators P(m)

P(1) := △q

(p; 0)

1 an ■

  • ,

P(m) :=

p

  • j=0

mp j

  • q

·

  • △q

(j; 0)

p

  • i=1

(1 − βi qn+m(p+1)−j−2)

  • △q

(p−j; mp−m),

m 2 where r j

  • q

:= (q; q)r (q; q)j (q; q)r−j , r, j ∈ ◆0, j r.

  • P. Woźny, R. Nowak (UWr)

Method of summation Luminy ’09 24 / 29

slide-57
SLIDE 57

Results Basic hypergeometric series

Notations

△q

(0; i) := ■,

△q

(m; i) :=

  • ❊ −qm+i−1 ■
  • △q

(m−1; i),

m ∈ ◆, i ∈ ❩

Operators P(m)

P(1) := △q

(p; 0)

1 an ■

  • ,

P(m) :=

p

  • j=0

mp j

  • q

·

  • △q

(j; 0)

p

  • i=1

(1 − βi qn+m(p+1)−j−2)

  • △q

(p−j; mp−m),

m 2 where r j

  • q

:= (q; q)r (q; q)j (q; q)r−j , r, j ∈ ◆0, j r.

  • P. Woźny, R. Nowak (UWr)

Method of summation Luminy ’09 24 / 29

slide-58
SLIDE 58

Results Basic hypergeometric series

Example

3φ 2

  • q, a, b

q, c q; c/ab

  • = 2φ

1

  • a, b

c q; c/ab

  • = (c/a; q)∞(c/b; q)∞

(c; q)∞(c/ab; q)∞

Table: Values of acc(Q(m)

n

) with a = 9/10, b = 5/8, c = 1/2 and q = 1/5. nm 1 2 3 4 5 6 1 0.42 3.18 8.75 14.77 22.17 30.97 41.15 2 0.48 4.67 11.64 18.36 26.46 35.96 3 0.53 6.13 14.50 21.92 30.72 40.91 4 0.59 7.58 17.35 25.47 34.97 5 0.64 9.03 20.19 29.01 39.21 6 0.69 10.48 23.04 32.56 7 0.74 11.93 25.89 36.11 8 0.79 13.38 28.73 9 0.84 14.83 31.58 10 0.89 16.28 11 0.94 17.73 (z; q)∞ = ∞

j=0(1 − zqj)

12 1.00 13 1.05

  • P. Woźny, R. Nowak (UWr)

Method of summation Luminy ’09 25 / 29

slide-59
SLIDE 59

Results Orthogonal polynomials

Chebyshev polynomials

s =

  • n=1

an, an := 1 zn (n + t)v fn, fn ∈ {Tn(x), Un(x)} ˆ P(m) := (n+m+t+v−2) ■ −2zx(n+2m+t+v−2) ❊ +z2(n+3m+t+v−2) ❊2 ▲(m) := ˆ P(m) ˆ P(m−1) · · · ˆ P(1) ((n + t)v−1 ■) ⇓ ▲(m)(an + an+1 + . . . + an+m−1

  • r(m)

n

) = 0 = ⇒ Q(m)

n

:= ▲(m)(sn) ▲(m)(1)

Example

− 2 − π 2 √ 2 + 2x =

  • n=0

bnTn(x)

  • an

, bn := (−1)n n2 − 1/4 (19) ˆ P(m) := (n + m − 1/2) ■ +2x(n + 2m − 1/2) ❊ +(n + 3m − 1/2) ❊2,

  • P. Woźny, R. Nowak (UWr)

Method of summation Luminy ’09 26 / 29

slide-60
SLIDE 60

Results Orthogonal polynomials

Chebyshev polynomials

s =

  • n=1

an, an := 1 zn (n + t)v fn, fn ∈ {Tn(x), Un(x)} ˆ P(m) := (n+m+t+v−2) ■ −2zx(n+2m+t+v−2) ❊ +z2(n+3m+t+v−2) ❊2 ▲(m) := ˆ P(m) ˆ P(m−1) · · · ˆ P(1) ((n + t)v−1 ■) ⇓ ▲(m)(an + an+1 + . . . + an+m−1

  • r(m)

n

) = 0 = ⇒ Q(m)

n

:= ▲(m)(sn) ▲(m)(1)

Example

− 2 − π 2 √ 2 + 2x =

  • n=0

bnTn(x)

  • an

, bn := (−1)n n2 − 1/4 (19) ˆ P(m) := (n + m − 1/2) ■ +2x(n + 2m − 1/2) ❊ +(n + 3m − 1/2) ❊2,

  • P. Woźny, R. Nowak (UWr)

Method of summation Luminy ’09 26 / 29

slide-61
SLIDE 61

Results Orthogonal polynomials

Chebyshev polynomials

s =

  • n=1

an, an := 1 zn (n + t)v fn, fn ∈ {Tn(x), Un(x)} ˆ P(m) := (n+m+t+v−2) ■ −2zx(n+2m+t+v−2) ❊ +z2(n+3m+t+v−2) ❊2 ▲(m) := ˆ P(m) ˆ P(m−1) · · · ˆ P(1) ((n + t)v−1 ■) ⇓ ▲(m)(an + an+1 + . . . + an+m−1

  • r(m)

n

) = 0 = ⇒ Q(m)

n

:= ▲(m)(sn) ▲(m)(1)

Example

− 2 − π 2 √ 2 + 2x =

  • n=0

bnTn(x)

  • an

, bn := (−1)n n2 − 1/4 (19) ˆ P(m) := (n + m − 1/2) ■ +2x(n + 2m − 1/2) ❊ +(n + 3m − 1/2) ❊2,

  • P. Woźny, R. Nowak (UWr)

Method of summation Luminy ’09 26 / 29

slide-62
SLIDE 62

Results Orthogonal polynomials

Figure: Accuracy of the summation of the series (19) for x = −0.95, −0.9, . . . , 1.

x K 0,8 K 0,6 K 0,4 K 0,2 0,0 0,2 0,4 0,6 0,8 1,0 Accuracy 10 20 30 40 50

⋆ acc(s(50)

1

)

  • acc(Q(24)

1

)

  • acc(H (24)

1

)

  • acc(K (24)

1

)

  • acc(ε(1)

48 ) +

acc(s50)

  • P. Woźny, R. Nowak (UWr)

Method of summation Luminy ’09 27 / 29

slide-63
SLIDE 63

Summary

Summary

The method for summation of some slowly convergent series was proposed Method may be successfully applied to the summation of generalized and basic hypergeometric series, as well as some classical orthogonal polynomial series expansions In some special cases, our algorithm is equivalent to Wynn’s epsilon algorithm, Weniger S transformation or the technique recently introduced by ˇ C´ ıˇ zek, Zamastil and Sk´ ala [1]. In the case of trigonometric series, our method is very similar to the Homeier’s H transformation, while in the case of orthogonal series — to the K transformation.

  • P. Woźny, R. Nowak (UWr)

Method of summation Luminy ’09 28 / 29

slide-64
SLIDE 64

Summary

Summary

The method for summation of some slowly convergent series was proposed Method may be successfully applied to the summation of generalized and basic hypergeometric series, as well as some classical orthogonal polynomial series expansions In some special cases, our algorithm is equivalent to Wynn’s epsilon algorithm, Weniger S transformation or the technique recently introduced by ˇ C´ ıˇ zek, Zamastil and Sk´ ala [1]. In the case of trigonometric series, our method is very similar to the Homeier’s H transformation, while in the case of orthogonal series — to the K transformation.

  • P. Woźny, R. Nowak (UWr)

Method of summation Luminy ’09 28 / 29

slide-65
SLIDE 65

Summary

Summary

The method for summation of some slowly convergent series was proposed Method may be successfully applied to the summation of generalized and basic hypergeometric series, as well as some classical orthogonal polynomial series expansions In some special cases, our algorithm is equivalent to Wynn’s epsilon algorithm, Weniger S transformation or the technique recently introduced by ˇ C´ ıˇ zek, Zamastil and Sk´ ala [1]. In the case of trigonometric series, our method is very similar to the Homeier’s H transformation, while in the case of orthogonal series — to the K transformation.

  • P. Woźny, R. Nowak (UWr)

Method of summation Luminy ’09 28 / 29

slide-66
SLIDE 66

Summary

Summary

The method for summation of some slowly convergent series was proposed Method may be successfully applied to the summation of generalized and basic hypergeometric series, as well as some classical orthogonal polynomial series expansions In some special cases, our algorithm is equivalent to Wynn’s epsilon algorithm, Weniger S transformation or the technique recently introduced by ˇ C´ ıˇ zek, Zamastil and Sk´ ala [1]. In the case of trigonometric series, our method is very similar to the Homeier’s H transformation, while in the case of orthogonal series — to the K transformation.

  • P. Woźny, R. Nowak (UWr)

Method of summation Luminy ’09 28 / 29

slide-67
SLIDE 67

Summary

For Further Reading

  • J. ˇ

C´ ıˇ zek, J. Zamastil, L. Sk´ ala, New summation technique for rapidly divergent perturbation series. Hydrogen atom in magnetic field,

  • J. Math. Phys. 44, (2003) 962–968.
  • S. Lewanowicz, S. Paszkowski,

An analytic method for convergence acceleration of certain hypergeometric series,

  • Math. Comput. 64 (1995) 691–713.
  • S. Paszkowski,

Convergence acceleration of orthogonal series,

  • Numer. Algorithms 47 (2008) 35–62.

E.J. Weniger, Nonlinear sequence transformations for the acceleration of convergence and the summation of divergent series,

  • Comput. Phys. Rep. 10 (1989) 189–371.
  • P. Woźny, R. Nowak (UWr)

Method of summation Luminy ’09 29 / 29