SLIDE 1
Measuring tail dependence for collateral losses using bivariate L´ evy process
Jiwook Jang Actuarial Studies Faculty of Commerce and Economics University of New South Wales Sydney, AUSTRALIA
Actuarial Studies Research Symposium 11 November 2005
SLIDE 2 Overview
- Collateral losses : In worldwide, once a storm or earthquake arrives, it
brings about damages in properties, motors and interruption of busi- nesses. It occurred a couple of losses simultaneously from the World Trade Centre (WTC) catastrophe.
evy process with a copula, i.e. bivariate compound Pois- son process with a member of Farlie-Gumbel-Morgenstern copula for dependence between losses.
- Calculation of the coefficient of (upper) tail dependence using Fast
Fourier transform.
SLIDE 3 Bivariate aggregate losses
- Insurance companies are experiencing dependent losses from one spe-
cific event such as flood, windstorm, hail, earthquake and terrorist attack. So for bivariate risk case, we can model L(1)
t
=
Nt
X
i=1
Xi, L(2)
t
=
Nt
X
i=1
Yi,
SLIDE 4
where L(1)
t
is the total losses arising from risk type 1, L(2)
t
is the total losses arising from risk type 2 and Nt is the total number of collateral losses up to time t. Xi and Yi, i = 1, 2, · · · , are the loss amounts, which are to be dependent each other, where H(x) be the identically distribution function of X and H(y) be the identically distribution function of Y .
SLIDE 5 A point process and a copula
- We assume that the collateral loss arrival process, Nt follows a Pois-
son process with loss frequency rate µ. It is also assumed that is independent of Xi and Yi.
- We employ the Farlie-Gumbel-Morgenstern family copula, that is given
by C(u, v) = uv + θuv(1 − u)(1 − v), where u ∈ [0, 1], v ∈ [0, 1] and θ ∈ [−1, 1] , to capture the dependence of collateral losses of X and Y .
SLIDE 6 Copula
- A general approach to model dependence between random variables is
to specify the joint distribution of the variables using copulas.
- Dependence between random variables is usually completely described
by their multivariate distribution function, To define a copula more formally, consider
u = (u1, · · · , un)
belongs to the n-cube [0, 1]n. A copula, C(u), is a function,with support [0, 1]n and range [0, 1], that is multivariate cumulative distribution function whose univariate marginals are uniform U(0, 1).
SLIDE 7
- As a consequence of this definition, we see that
C
¡u1, · · · , uk−1, 0, uk+1, · · · , un ¢ = 0
and C (1, · · · , 1, uk, 1, · · · , 1) = uk for all k = 1, 2, · · · n. Any copula C is therefore the distribution of a multivariate uniform random vector.
SLIDE 8 Sklar theorem
- Let F be a two-dimensional distribution function with margins, F1,
F2. Then there exists a two-dimensional copula C such that for all x ∈
−
R
2
, F(x1, x2) = C(F1(x1), F2(x2)). (1)
- If F1 and F2 are continuous then C is unique, i.e.
C(u1, u2) = F(F −1
1
(u1), F −1
2
(u2)),
SLIDE 9 where F −1
1
, F −1
2
denote the quantile functions of the univariate margins F1, F2. Otherwise C is uniquely determined on Ran F1× Ran F2.
- Conversely, if C is a copula and F1 and F2 are distribution functions,
then the function F defined by (1) is a two-dimensional distribution function with margins F1 and F2.
SLIDE 10 Farlie-Gumbel-Morgenstern family copula with exponential margins
- In order to obtain the explicit expression of the function F(x, y), that is
a two-dimensional distribution function with margins H (x) and H(y), we let X and Y be exponential random variables, i.e. H (x) = 1−e−αx (α > 0, x > 0) and H(y) = 1 − e−βy (β > 0, y > 0), then the joint distribution function F(x, y) is given by F(x, y) = C(1 − e−αx, 1 − e−βy) = 1 − e−βy − e−αx + e−αx−βy + θe−αx−βy −θe−αx−2βy − θe−2αx−βy + θe−2αx−2βy.
SLIDE 11
- And its derivative is given by
dF(x, y) = dC(1 − e−αx, 1 − e−βy) = (1 + θ) αβe−αx−βy −2θαβe−αx−2βy − 2θαβe−2αx−βy +4θαβe−2αx−2βy. (2)
SLIDE 12 Upper tail dependence of collateral losses
- We examine upper tail dependence of collateral losses X and Y as
insurance companies’ concerns are on extreme losses in practice.
- we adopt the coefficient of upper tail dependence, λU, used by Em-
brechts, Lindskog and McNeil (2003), lim
u%1P
(
L(2)
t
> G−1
L(2)
t
(u) | L(1)
t
> G−1
L(1)
t
(u)
)
= λU provided that the limit λU ∈ [0, 1] exists, where GL(1)
t
and GL(2)
t
are marginal distribution functions for L(1)
t
and L(2)
t
.
SLIDE 13 The generator of the process
µ
L(1)
t
, L(2)
t
, t
¶
- The generator of the process
µ
L(1)
t
, L(2)
t
, t
¶
acting on a function f
³
l(1), l(2), t
´
belonging to its domain is given by A f
³
l(1), l(2), t
´
= ∂f ∂t +µ
⎡ ⎢ ⎣
∞
Z
∞
Z
f
³
l(1) + x, l(2) + y, t
´
dC(H (x) , H (y)) − f
³
l(1), l(2), t
´ ⎤ ⎥ ⎦ .
SLIDE 14 A suitable martingale
- Considering constants ν ≥ 0 and ξ ≥ 0,
exp
µ
−νL(1)
t
¶
exp
µ
−ξL(2)
t
¶
exp
⎡ ⎢ ⎣µ
t
Z
{1 − ˆ c (ν, ξ)} ds
⎤ ⎥ ⎦
is a martingale where ˆ c (ν, ξ) =
∞
R
∞
R
e−νxe−ξydC(H (x) , H (y)).
SLIDE 15 The joint Laplace transform of the distribution of L(1)
t
and L(2)
t
- Using the martingale obtained above, the joint Laplace transform of
the distribution of L(1)
t
and L(2)
t
at time t is given by E
½
e−νL(1)
t e−ξL(2) t |L(1)
0 , L(2)
¾
= exp
µ
−νL(1)
¶
exp
µ
−ξL(2)
¶
× exp
⎡ ⎢ ⎣−µ
t
Z
{1 − ˆ c (ν, ξ)} ds
⎤ ⎥ ⎦ .
SLIDE 16
- For simplicity, we assume that L(1)
= 0 and L(2) = 0, then it is given by E
½
e−νL(1)
t e−ξL(2) t
¾
= exp
⎡ ⎢ ⎣−µ
t
Z
{1 − ˆ c (ν, ξ)} ds
⎤ ⎥ ⎦ ,
where ˆ c (ν, ξ) =
∞
R
∞
R
e−νxe−ξydC(H (x) , H (y)).
SLIDE 17
- In order to obtain the explicit expression of the joint Laplace transform
- f the distribution of L(1)
t
and L(2)
t
at time t, let us use the joint density function f(x, y) driven by (2), then it is given by E
½
e−νL(1)
t e−ξL(2) t
¾
= exp
"
−µ
(
(αξ + βν + νξ) (2α + ν) (2β + ξ) − θαβ νξ (α + ν) (β + ξ) (2α + ν) (2β + ξ)
)
t
#
. (3)
SLIDE 18
- If we set ξ = 0, then the Laplace transform of the distribution of L(1)
t
is given by E
½
e−νL(1)
t
¾
= exp
½
−µ
µ
ν α + ν
¶
t
¾
(4) and if we set ν = 0, then the Laplace transform of the distribution of L(2)
t
is given by E
½
e−ξL(2)
t
¾
= exp
(
−µ
Ã
ξ β + ξ
!
t
)
, (5)
SLIDE 19 which are the Laplace transform of the distribution of the compound Pois- son process with exponential loss sizes. Due to the dependence of col- lateral losses of X and Y with sharing loss frequency rate µ, it is obvious that E
½
e−νL(1)
t e−ξL(2) t
¾
6= E
½
e−νL(1)
t
¾
E
½
e−ξL(2)
t
¾
.
SLIDE 20 When θ = 0,.i.e. no dependence in loss sizes
E
½
e−νL(1)
t e−ξL(2) t
¾
= exp
"
−µ
(
(αξ + βν + νξ) (α + ν) (β + ξ)
)
t
#
, (6) which is the case that two losses X and Y occur at the same time from a sharing loss frequency rate µ, but their sizes are independent each other.
- If loss X occurs with its frequency rate µ(x) and loss Y occurs with
its frequency rate µ(y) respectively and everything is independent each
SLIDE 21
- ther, we can easily derive the explicit expression of the joint Laplace
transform of the distribution of L(1)
t
and L(2)
t
at time t, i.e. E
½
e−νL(1)
t e−ξL(2) t
¾
= E
½
e−νL(1)
t
¾
E
½
e−ξL(2)
t
¾
= exp
½
−µ(x)
µ
ν α + ν
¶
t
¾
exp
(
−µ(y)
Ã
ξ β + ξ
!
t
)
. (7)
SLIDE 22
- If we set µ = µ(x) = µ(y), i.e. frequency rate for loss X and Y are
just the same, then (7) becomes E
½
e−νL(1)
t e−ξL(2) t
¾
= E
½
e−νL(1)
t
¾
E
½
e−ξL(2)
t
¾
= exp
½
−µ
µ
ν α + ν
¶
t
¾
exp
(
−µ
Ã
ξ β + ξ
!
t
)
= exp
"
−µ
(
(αξ + βν + 2νξ) (α + ν) (β + ξ)
)
t
#
. (8) Equation (8) looks similar to (6) as loss size X and Y are independent and their frequency rates are the same. However the joint Laplace transform
- f the distribution of L(1)
t
and L(2)
t
at time t expressed by (8) are the case that they are occurring independently, not collaterally like (6).
SLIDE 23 Covariance and linear correlation of collateral losses
- Differentiating (3) w.r.t. ν and ξ and set ν = 0 and ξ = 0, then we
can easily derive the joint expectation of L(1)
t
and L(2)
t
at time t, i.e. E
½
L(1)
t
L(2)
t
¾
= µ2
αβt2 + µ αβ
³
1 + θ
4
´
t.
- Also from (4) and (5) we can easily derive the expectation of L(1)
t
and L(2)
t
at time t, i.e. E
½
L(1)
t
¾
= µ
αt
and E
½
L(2)
t
¾
= µ
βt.
SLIDE 24
- The higher moments of L(1)
t
and L(2)
t
at time t can be obtained by differentiating it further, i.e. V ar
½
L(1)
t
¾
= 2µ α2t and V ar
½
L(2)
t
¾
= 2µ β2t.
- The covariance between L(1)
t
and L(2)
t
at time t is given by Cov(L(1)
t
, L(2)
t
) = E
½
L(1)
t
L(2)
t
¾
− E
½
L(1)
t
¾
E
½
L(2)
t
¾
= µ αβ
µ
1 + θ 4
¶
t. (9)
SLIDE 25
- As linear correlation (or Pearson’s correlation) has been most popularly
used in practice as a measure of dependence, we present the expression
- f the linear correlation coefficient for L(1)
t
and L(2)
t
at time t, denoted by ρ
µ
L(1)
t
, L(2)
t
¶
, ρ
µ
L(1)
t
, L(2)
t
¶
= Cov(L(1)
t
, L(2)
t
)
∙
V ar
½
L(1)
t
¾¸1
2 ∙
V ar
½
L(2)
t
¾¸1
2
=
µ αβ
³
1 + θ
4
´
t
³2µ
α2t
´1
2
µ
2µ β2t
¶1
2
= 4 + θ 8 . (10)
SLIDE 26 Example 1
- The parameter values used to calculate the covariance and linear cor-
relation using (9) and (10) are µ = 4, α = 1, β = 0.5, t = 1. From (9) and (10), the calculations of covariance and linear correlation between L(1)
t
and L(2)
t
at time t are shown in Table 1 and Table 2 respectively.
SLIDE 27
Table 1. θ Cov(L(1)
t
, L(2)
t
) −1 6 −0.5 7 8 0.5 9 1 10 Table 2. θ ρ
µ
L(1)
t
, L(2)
t
¶
−1 0.375 −0.5 0.4375 0.5 0.5 0.562 5 1 0.625
SLIDE 28 The coefficient of upper tail dependence, λU
- As it is not possible for us to obtain the joint distribution of L(1)
t
and L(2)
t
explicitly, we invert the joint Fast Fourier transform obtained from the joint Laplace transform of collateral losses to approximate the coefficient of (upper) tail dependence (Castleman 1996; Gonzalez and Woods 2002 and Gonzalez et al. 2004), i.e. F(u, v) =
1 MN M−1
P
x=0 N−1
P
y=0
f(x, y)e−j2π(ux
M +vy N ) and
f(x, y) =
M−1
P
u=0 N−1
P
v=0
F(u, v)ej2π(ux
M +vy N )
for x = 0, 1, 2, · · · , M − 1 and y = 0, 1, 2, · · · , N − 1.
SLIDE 29
- The below figures are the joint distribution of collateral losses and
their contours at each value of θ.
SLIDE 30
The joint distribution of collateral losses with θ = 1
SLIDE 31
The contour of the joint distribution of collateral losses with θ = 1
SLIDE 32
The joint distribution of collateral losses with θ = 0.5
SLIDE 33
The contour of the joint distribution of collateral losses with θ = 0.5
SLIDE 34
The joint distribution of collateral losses with θ = 0
SLIDE 35
The contour of the joint distribution of collateral losses with θ = 0
SLIDE 36
The joint distribution of collateral losses with θ = −0.5
SLIDE 37
The contour of the joint distribution of collateral losses with θ = −0.5
SLIDE 38
The joint distribution of collateral losses with θ = −1
SLIDE 39
The contour of the joint distribution of collateral losses with θ = −1
SLIDE 40
- Using Matlab, the calculations of the coefficients of (upper) tail de-
pendence for collateral losses are shown in Table 3, Table 4, Table 5 and Table 6 using the different VaR at 90%, 95%, 99% and 99.9%.
SLIDE 41
Table 3. θ
P
½
L(1)
t
> 7.84, L(2)
t
> 15.68
¾
P
½
L(1)
t
> 7.84 | L(2)
t
> 15.68
¾
= P
½
L(2)
t
> 15.68 | L(1)
t
> 7.84
¾
1 0.038425 0.38425 0.5 0.034221 0.34221 0.030239 0.30239 −0.5 0.026450 0.26450 −1 0.022831 0.22831 where P
½
L(1)
t
> 7.84
¾
= P
½
L(2)
t
> 15.68
¾
= 0.1
SLIDE 42
Table 4. θ
P
½
L(1)
t
> 9.37, L(2)
t
> 18.74
¾
P
½
L(1)
t
> 9.37 | L(2)
t
> 18.74
¾
= P
½
L(2)
t
> 18.74 | L(1)
t
> 9.37
¾
1 0.014593 0.29187 0.5 0.012565 0.25129 0.010681 0.21363 −0.5 0.0089309 0.17862 −1 0.0073023 0.14605 where P
½
L(1)
t
> 9.37
¾
= P
½
L(2)
t
> 18.74
¾
= 0.05
SLIDE 43
Table 5. θ
P
½
L(1)
t
> 12.61, L(2)
t
> 25.22
¾
P
½
L(1)
t
> 12.61 | L(2)
t
> 25.22
¾
= P
½
L(2)
t
> 25.22 | L(1)
t
> 12.61
¾
1 0.0015290 0.15290 0.5 0.0012168 0.12168 0.00094405 0.094405 −0.5 0.00070781 0.070781 −1 0.00050554 0.050554 where P
½
L(1)
t
> 12.61
¾
= P
½
L(2)
t
> 25.22
¾
= 0.01
SLIDE 44
Table 6. θ
P
½
L(1)
t
> 16.81, L(2)
t
> 33.62
¾
P
½
L(1)
t
> 16.81 | L(2)
t
> 33.62
¾
= P
½
L(2)
t
> 33.62 | L(1)
t
> 16.81
¾
1 0.000059365 0.059365 0.5 0.000042203 0.042203 0.000028667 0.028667 −0.5 0.000018274 0.018274 −1 0.000010590 0.010590 where P
½
L(1)
t
> 16.81
¾
= P
½
L(2)
t
> 33.62
¾
= 0.001
SLIDE 45 Further Research
- Dependence in interarival time of losses.
- In practice, we might need to employ one of the heavy-tailed distrib-
utions for jump sizes, H (x) and H(y) to deal with extreme losses.
- Employing other copulars.
- Nt can be the Cox process, rather than the Poisson process, that has
stochastic jump frequency rate µ(t).