Measurement of the fission mass yields of Am242 at the Lohengrin - - PowerPoint PPT Presentation

measurement of the fission mass yields of am242 at the
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Measurement of the fission mass yields of Am242 at the Lohengrin - - PowerPoint PPT Presentation

Measurement of the fission mass yields of Am242 at the Lohengrin Spectrometer Charlotte AMOUROUX 1 A. Bidaud 2 , N. Capellan 2 , S. Chabod 2 , H. Faust 3 , G. Kessedjian 2 , U. Kster 3 , A. Letourneau 1 , F. Martin 2 , T. Materna 1 , S.


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SLIDE 1

Charlotte AMOUROUX1

Measurement of the fission mass yields of Am242 at the Lohengrin Spectrometer

  • A. Bidaud2, N. Capellan2, S. Chabod2,
  • H. Faust3, G. Kessedjian2, U. Köster3,
  • A. Letourneau1, F. Martin2, T. Materna1,
  • S. Panebianco1, Ch. Sage2, O. Serot4

1CEA, DSM‐Saclay, France 2LPSC Grenoble, CNRS/IN2P3, France 3Institut Laue Langevin, France 4CEA, DEN‐Cadarache, France

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SLIDE 2

242Am(Z=95)

241Am : 90% of the radiotoxicity of the nuclear waste (without plutonium) between 200 and 1000 years ‐> Transmutation of 241Am

n+ 241 Am

242 Am

FP1 FP2 242Am : two long‐lived states Z=95 (odd charge)

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Charlotte AMOUROUX‐WONDER ‐25/09/2012

141 Y 16.02 H

1‐ 5‐ 48.6 keV

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SLIDE 3

PLAN

  • Experimental Set‐up & Analysis Method
  • Energy and Charge Distributions
  • Uncertainties Determination
  • Results

Charlotte AMOUROUX‐WONDER ‐25/09/2012

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SLIDE 4

High neutron flux Reactor Target Magnet: Selection A/q Condenser: Selection: E/q Detector: E

Experimental setup

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Charlotte AMOUROUX‐WONDER ‐25/09/2012

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SLIDE 5

How do we measure the energy of the fragment ?

E‐> E/q‐>A/q‐>A

* A.Bail thesis

=>Y(A,E,q)

Charlotte AMOUROUX‐WONDER ‐25/09/2012

ΔE‐E Ionisation Chamber

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SLIDE 6

Energy Distribution for a given q Charge Distribution for a given E N(A,q,E) according to q and E Valid if no correlation between E and q

How to calculate the fission yields ?

In reality we have a correlation but its influence on Y(A) in less than 3%

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Charlotte AMOUROUX‐WONDER ‐25/09/2012

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SLIDE 7

Example of Q‐distribution : two differents cases Measured Charge is determined at the last crossed material (Nickel)

With nanosecond isomer Without nanosecond isomer

Q‐Distribution

A=105 A=136

Target Target Nickel Foil Nickel Foil

Magnet Magnet

Q~21‐22 Q~24‐25

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Charlotte AMOUROUX‐WONDER ‐25/09/2012

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SLIDE 8

E‐Distribution

A=105 Q=21

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Charlotte AMOUROUX‐WONDER ‐25/09/2012

0.6 MeV for determination of KE 0.6 MeV for (q,E) correlation

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SLIDE 9

Kinetic energy as a fonction of the fragment mass

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Charlotte AMOUROUX‐WONDER ‐25/09/2012

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SLIDE 10

E‐Distribution

Statistic errors: ‐ ~ 1% Amplitude [a.u] Energy [MeV]

~1,5% of the total area _ maximal fluctuation of 1,5 % between 2 E‐ distribution ~0,8% of the total area _ maximal fluctuation of 1,0 % between 2 E‐ distribution

A=105 Q=21 Systematics errors: ‐ 1,5% low energy part ‐ 1,0% high energy part

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Charlotte AMOUROUX‐WONDER ‐25/09/2012

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SLIDE 11

Determination of the systematic error

This point is known twice

For the same mass as a function of time: For all masses: σ ~ 3%

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Charlotte AMOUROUX‐WONDER ‐25/09/2012

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SLIDE 12

Source Contribution Statistical ~1 % Extrapolation of the low part

  • f the energy distribution

1.5 % Extrapolation of the high part

  • f the energy distribution

1% Discrepancies between the two measurements of the common point 3% Normalisation ? Total of the systematic error 3.5%

Sources of relative uncertainties and their respective contributions.

Charlotte AMOUROUX‐WONDER ‐25/09/2012

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SLIDE 13

n+ 241 Am

242m Am 242

Am

Y Y’

σfission=2644(±281)barn*

91,4% 8,6% Y=Y’ ? Objectives of the experiment : ‐ Fission Mass Yields from Am‐241(2n,f) ‐ Is there any difference between the fission yields of Am‐242(n,f) and Am‐242m(n,f) ?

Fission Yields of Am‐242

(141 y) (16h)

σfission=6856(±656)barn*

* G.Fioni et al,Nucl Phys.A693(2001) 546 O.Bringer,Ph.D Thesis,INP Grenoble, October 2007

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Charlotte AMOUROUX‐WONDER ‐25/09/2012

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SLIDE 14

How do we proceed to observe a possible difference ?

B: vaccum problem A: Strong evolution of the properties

  • f the target (large energy shift)

A

Shut‐down of the reactor

B

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Charlotte AMOUROUX‐WONDER ‐25/09/2012

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SLIDE 15

Hypothesis: X=0. for X’=0 (0,04 for all σY and 0,07 for σYm ) General case : Γ~1

What is the maximum possible difference ?

n+ 241 Am

242m Am 242

Am

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Charlotte AMOUROUX‐WONDER ‐25/09/2012

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SLIDE 16

Conclusions

No difference between the yields: quantification on‐going. If you assume they are equal … Normalisation Y105=6,5% Only statistical error

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Charlotte AMOUROUX‐WONDER ‐25/09/2012

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SLIDE 17

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Charlotte AMOUROUX‐WONDER ‐25/09/2012

Isotopic fission yields

Future

239Pu 233U * A.Bail Thesis * Meeting GEDEPEON Jan 2011 G.Kessedjian (F.Martin thesis (on‐going)) 241Pu

242Am

Thank you for your attention

235U

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SLIDE 18

Back‐up

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SLIDE 19

Comparaison with the GEF code(June 2012)

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SLIDE 20

Number of fissions

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SLIDE 21

Evolution of the kinetic energy as a function of time

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SLIDE 22

FWHM of the energy distribution as a function of time

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