MATH 20: PROBABILITY Variance of Discrete Random Variables - - PowerPoint PPT Presentation

โ–ถ
math 20 probability
SMART_READER_LITE
LIVE PREVIEW

MATH 20: PROBABILITY Variance of Discrete Random Variables - - PowerPoint PPT Presentation

MATH 20: PROBABILITY Variance of Discrete Random Variables Xingru Chen xingru.chen.gr@dartmouth.edu XC 2020 Important Distributions Hypergeometric Discrete Uniform Distribution Distribution = 1 $ &"$ % !"%


slide-1
SLIDE 1

MATH 20: PROBABILITY

Variance

  • f

Discrete Random Variables Xingru Chen xingru.chen.gr@dartmouth.edu

XC 2020

slide-2
SLIDE 2

Important Distributions

๐‘› ๐œ• = 1 ๐‘œ

Discrete Uniform Distribution

๐‘„ ๐‘ˆ = ๐‘œ = ๐‘Ÿ!"#๐‘ž

Geometric Distribution

๐‘ ๐‘œ, ๐‘ž, ๐‘™ = ๐‘œ ๐‘™ ๐‘ž$๐‘Ÿ!"$

Binomial Distribution

โ„Ž ๐‘‚, ๐‘™, ๐‘œ, ๐‘ฆ =

$ % &"$ !"% & !

Hypergeometric Distribution

๐‘ฃ ๐‘ฆ, ๐‘™, ๐‘ž = ๐‘ฆ โˆ’ 1 ๐‘™ โˆ’ 1 ๐‘ž$๐‘Ÿ%"$

Negative Binomial Distribution

๐‘„ ๐‘Œ = ๐‘™ = ๐œ‡$ ๐‘™! ๐‘“"'

Poisson Distribution

XC 2020

slide-3
SLIDE 3

Bin Binomia ial ๐น ๐‘Œ = ๐‘œ๐‘ž ๐น ๐‘Œ = 1 ๐‘ž ๐น ๐‘Œ = ๐œ‡ ๐น ๐‘Œ = ๐‘™ ๐‘Ÿ ๐‘ž Ge Geometric Po Poisson Ne Negative binomi

  • mial

๐‘ ๐‘œ, ๐‘ž, ๐‘™ = ๐‘œ ๐‘™ ๐‘ž!๐‘Ÿ"#! ๐‘„ ๐‘ˆ = ๐‘œ = ๐‘Ÿ"#$๐‘ž ๐‘„ ๐‘Œ = ๐‘™ = ๐œ‡! ๐‘™! ๐‘“#% ๐‘ฃ ๐‘ฆ, ๐‘™, ๐‘ž = ๐‘ฆ โˆ’ 1 ๐‘™ โˆ’ 1 ๐‘ž!๐‘Ÿ&#! ๐น ๐‘Œ = ๐‘œ ๐‘™ ๐‘‚ Hy Hyper ergeo eomet etric ic โ„Ž ๐‘‚, ๐‘™, ๐‘œ, ๐‘ฆ =

! & '#! "#& ' "

XC 2020

slide-4
SLIDE 4

How Much Does a Hershey Kiss Weight?

ยง A single standard Hershey's Kiss weighs 0.16

  • unces.

XC 2020

slide-5
SLIDE 5

?

Ho How t to m mea easu sure t the q qualit ity

  • f

prod

  • duct

cts? Same ๐œˆ, different ๐œ.

XC 2020

slide-6
SLIDE 6

Home Made Versus Factory Made

XC 2020

slide-7
SLIDE 7

Variance of Discrete Random Variables

ยง Let ๐‘Œ be a numerically-valued random variable with expected value ๐œˆ = ๐น(๐‘Œ). Then the variance

  • f

๐‘Œ, denoted by ๐‘Š(๐‘Œ), is ๐‘Š ๐‘Œ = ๐น((๐‘Œ โˆ’ ๐œˆ)().

Ex Expected value ๐‘ญ(๐’€) :

%โˆˆ)

๐‘ฆ๐‘›(๐‘ฆ) Ex Expected value ๐‘ญ ๐”(๐’€) :

%โˆˆ)

๐œš(๐‘ฆ)๐‘›(๐‘ฆ) Va Variance ๐‘Š ๐‘Œ :

%โˆˆ)

(๐‘ฆ โˆ’ ๐œˆ)*๐‘›(๐‘ฆ)

XC 2020

slide-8
SLIDE 8

Variance of Discrete Random Variables

ยง Let ๐‘Œ be a numerically-valued random variable with expected value ๐œˆ = ๐น(๐‘Œ). Then the variance

  • f

๐‘Œ, denoted by ๐‘Š(๐‘Œ), is ๐‘Š ๐‘Œ = ๐น((๐‘Œ โˆ’ ๐œˆ)(). ยง Standard deviation

  • f

๐‘Œ, denoted by ๐ธ(๐‘Œ), is ๐ธ ๐‘Œ = ๐‘Š(๐‘Œ). ยง We

  • ften

write ๐œ for ๐ธ(๐‘Œ) and ๐œ( for ๐‘Š ๐‘Œ .

Va Variance ๐‘Š ๐‘Œ :

%โˆˆ)

(๐‘ฆ โˆ’ ๐œˆ)*๐‘›(๐‘ฆ)

XC 2020

slide-9
SLIDE 9

Variance of Discrete Random Variables

ยง Let ๐‘Œ be a numerically-valued random variable with expected value ๐œˆ = ๐น(๐‘Œ). Then the variance

  • f

๐‘Œ, denoted by ๐‘Š(๐‘Œ), is ๐‘Š ๐‘Œ = ๐น((๐‘Œ โˆ’ ๐œˆ)(). ยง If ๐‘Œ is any random variable with ๐œˆ = ๐น(๐‘Œ), then ๐‘Š ๐‘Œ = ๐น ๐‘Œ( โˆ’ ๐œˆ(.

Va Variance ๐‘Š ๐‘Œ :

%โˆˆ)

(๐‘ฆ โˆ’ ๐œˆ)*๐‘›(๐‘ฆ) :

%โˆˆ)

๐‘ฆ*๐‘›(๐‘ฆ) โˆ’ :

%โˆˆ)

๐‘ฆ๐‘›(๐‘ฆ)

XC 2020

slide-10
SLIDE 10

Let ๐‘Œ be a numerically-valued random variable with expected value ๐œˆ = ๐น(๐‘Œ). ๐‘Š ๐‘Œ = :

%โˆˆ)

(๐‘ฆ โˆ’ ๐œˆ)*๐‘›(๐‘ฆ) = :

%โˆˆ)

(๐‘ฆ* โˆ’ 2๐œˆ๐‘ฆ + ๐œˆ*)๐‘›(๐‘ฆ) = :

%โˆˆ)

๐‘ฆ*๐‘›(๐‘ฆ) โˆ’ 2๐œˆ :

%โˆˆ)

๐‘ฆ๐‘› ๐‘ฆ + ๐œˆ* :

%โˆˆ)

๐œˆ*๐‘› ๐‘ฆ

Proof

๐‘Š ๐‘Œ = $

!โˆˆ#

(๐‘ฆ โˆ’ ๐œˆ)$๐‘›(๐‘ฆ)

:

%โˆˆ)

๐‘ฆ๐‘› ๐‘ฆ = ๐œˆ

$

!โˆˆ#

๐‘› ๐‘ฆ = 1

๐‘Š ๐‘Œ = :

%โˆˆ)

๐‘ฆ*๐‘›(๐‘ฆ) โˆ’ 2๐œˆ :

%โˆˆ)

๐‘ฆ๐‘› ๐‘ฆ + ๐œˆ* :

%โˆˆ)

๐œˆ*๐‘› ๐‘ฆ = ๐น ๐‘Œ* โˆ’ 2๐œˆ* + ๐œˆ* = ๐น ๐‘Œ* โˆ’ ๐œˆ* :

%โˆˆ)

๐‘ฆ*๐‘›(๐‘ฆ) = ๐น(๐‘Œ*)

XC 2020

slide-11
SLIDE 11

Example 1

Tos

  • ss

a coi coin head

  • r

tail 1 or ๐‘› ๐‘ฆ = 1 2 ๐œˆ = ๐น ๐‘Œ = 1 2 ๐œ( = ๐‘Š ๐‘Œ = โ‹ฏ

XC 2020

slide-12
SLIDE 12

Example 1

Tos

  • ss

a coi coin head

  • r

tail 1 or ๐‘› ๐‘ฆ = 1 2 ๐œˆ = ๐น ๐‘Œ = 1 2 ๐œ( = ๐‘Š ๐‘Œ = 1 4

XC 2020

slide-13
SLIDE 13

Example 2

Rol

  • ll

a dice ce 1, 2, 3, 4, 5,

  • r

6 ๐‘› ๐‘ฆ = 1 6 ๐œˆ = ๐น ๐‘Œ = 7 2 ๐œ( = ๐‘Š ๐‘Œ = โ‹ฏ

XC 2020

slide-14
SLIDE 14

Example 2

Rol

  • ll

a dice ce 1, 2, 3, 4, 5,

  • r

6 ๐‘› ๐‘ฆ = 1 6 ๐œˆ = ๐น ๐‘Œ = 7 2 ๐œ( = ๐‘Š ๐‘Œ = 91 6 โˆ’ 49 4 = 35 12

XC 2020

slide-15
SLIDE 15

Quiz 9

What is the expected number

  • f

dice tosses needed to get two consecutive six's?

Number

  • f

tosses 2, 3, 4, โ€ฆ ๐น ๐‘Œ = ๐น ๐‘Œ 1 ๐‘„ 1 + ๐น ๐‘Œ 2 + ๐น ๐‘Œ 3 ๐‘„ 3 + ๐น ๐‘Œ 4 ๐‘„ 4 + ๐น ๐‘Œ 5 ๐‘„ 5 + ๐น ๐‘Œ 6 ๐‘„(6) ๐น ๐‘Œ = 5 6 ๐น ๐‘Œ 1 + 1 6 ๐น ๐‘Œ 6 = 5 6 1 + ๐น ๐‘Œ + 1 6 (5 6 ๐น ๐‘Œ 61 + 1 6 ๐น(๐‘Œ|66)) ๐น ๐‘Œ = 5 6 1 + ๐น ๐‘Œ + 1 6 [5 6 2 + ๐น ๐‘Œ + 2 6]

XC 2020

slide-16
SLIDE 16

Is the distribution function a must for calculating expectation?

๐‘ญ ๐’€

๐‘ญ ๐’€ ๐‘ฎ๐Ÿ ๐‘ธ(๐‘ฎ๐Ÿ) ๐‘ญ ๐’€ ๐‘ฎ๐Ÿ• ๐‘ธ(๐‘ฎ๐Ÿ•) ๐‘ญ ๐’€ ๐‘ฎ๐Ÿ” ๐‘ธ(๐‘ฎ๐Ÿ”) ๐‘ญ ๐’€ ๐‘ฎ๐Ÿ‘ ๐‘ธ(๐‘ฎ๐Ÿ‘) ๐‘ญ ๐’€ ๐‘ฎ๐Ÿ“ ๐‘ธ(๐‘ฎ๐Ÿ“) ๐‘ญ ๐’€ ๐‘ฎ๐Ÿ’ ๐‘ธ(๐‘ฎ๐Ÿ’)

XC 2020

slide-17
SLIDE 17

Example 3

Consider the general Bernoulli trial

  • process. As

usual, we let ๐‘Œ = 1 if the

  • utcome

is a success and 0 if it is a failure. Expect cted value ๐‘ญ(๐’€) M

&โˆˆ0

๐‘ฆ๐‘›(๐‘ฆ) = 1ร—๐‘ž + 0ร— 1 โˆ’ ๐‘ž = ๐‘ž Ber Bernoulli t tria ial ๐‘› ๐‘ฆ = O ๐‘ž, ๐‘Œ = 1 1 โˆ’ ๐‘ž, ๐‘Œ = 0 Variance ce ๐‘Š ๐‘Œ ๐น ๐‘Œ( โˆ’ ๐œˆ( = โ‹ฏ

XC 2020

slide-18
SLIDE 18

Example 3

Consider the general Bernoulli trial

  • process. As

usual, we let ๐‘Œ = 1 if the

  • utcome

is a success and 0 if it is a failure. Expect cted value ๐‘ญ(๐’€) M

&โˆˆ0

๐‘ฆ๐‘›(๐‘ฆ) = 1ร—๐‘ž + 0ร— 1 โˆ’ ๐‘ž = ๐‘ž Ber Bernoulli t tria ial ๐‘› ๐‘ฆ = O ๐‘ž, ๐‘Œ = 1 1 โˆ’ ๐‘ž, ๐‘Œ = 0 Variance ce ๐‘Š ๐‘Œ ๐น ๐‘Œ( โˆ’ ๐œˆ( = ๐‘ž โˆ’ ๐‘ž(

XC 2020

slide-19
SLIDE 19

Bin Binomia ial ๐น ๐‘Œ = ๐‘œ๐‘ž, ๐‘Š ๐‘Œ = ๐‘œ๐‘ž๐‘Ÿ ๐น ๐‘Œ = $

1,

๐‘Š ๐‘Œ = $#1

1%

๐น ๐‘Œ = ๐œ‡, ๐‘Š ๐‘Œ = ๐œ‡ ๐น ๐‘Œ = ๐‘™ 2

1,

๐‘Š ๐‘Œ = ๐‘™ 2

1%

Ge Geometric Po Poisson Ne Negative binomi

  • mial

๐‘ ๐‘œ, ๐‘ž, ๐‘™ = ๐‘œ ๐‘™ ๐‘ž!๐‘Ÿ"#! ๐‘„ ๐‘ˆ = ๐‘œ = ๐‘Ÿ"#$๐‘ž ๐‘„ ๐‘Œ = ๐‘™ = ๐œ‡! ๐‘™! ๐‘“#% ๐‘ฃ ๐‘ฆ, ๐‘™, ๐‘ž = ๐‘ฆ โˆ’ 1 ๐‘™ โˆ’ 1 ๐‘ž!๐‘Ÿ&#! ๐น ๐‘Œ = ๐‘œ !

',

๐‘Š ๐‘Œ = "! '#! ('#")

'%('#$)

Hy Hyper ergeo eomet etric ic โ„Ž ๐‘‚, ๐‘™, ๐‘œ, ๐‘ฆ =

! & '#! "#& ' "

XC 2020

slide-20
SLIDE 20

Binomial Distribution and Poisson Distribution

Po Poisson Distribution ๐‘„ ๐‘Œ = ๐‘™ = ๐œ‡$ ๐‘™! ๐‘“"' ๐น ๐‘Œ = ๐œ‡, ๐‘Š ๐‘Œ = ๐œ‡ Bi Binomial Dist stribution ๐‘ ๐‘œ, ๐‘ž, ๐‘™ = ๐‘œ ๐‘™ ๐‘ž$๐‘Ÿ!"$ ๐น ๐‘Œ = ๐‘œ๐‘ž, ๐‘Š ๐‘Œ = ๐‘œ๐‘ž๐‘Ÿ

=

๐‘ž = %5

",

๐‘ข = 1, ๐‘œ โ†’ โˆž, ๐‘ž โ†’ 0

XC 2020

slide-21
SLIDE 21

Bin Binomia ial ๐น ๐‘Œ = ๐‘œ๐‘ž ๐‘ ๐‘œ, ๐‘ž, ๐‘™ = ๐‘œ ๐‘™ ๐‘ž!๐‘Ÿ"#! Variance ce ๐‘Š ๐‘Œ ๐น ๐‘Œ( โˆ’ ๐œˆ( = M

&โˆˆ0

๐‘ฆ(๐‘› ๐‘ฆ โˆ’ ๐œˆ( M

&โˆˆ0

๐‘ฆ(๐‘› ๐‘ฆ = M

!67 "

๐‘™( ๐‘œ ๐‘™ ๐‘ž!๐‘Ÿ"#! = M

!6$ "

๐‘™( ๐‘œ ๐‘™ ๐‘ž!๐‘Ÿ"#! = M

!6$ "

๐‘™( ๐‘œ! ๐‘™! ๐‘œ โˆ’ ๐‘™ ! ๐‘ž!๐‘Ÿ"#! = M

!6$ "

๐‘œ๐‘ž๐‘™ (๐‘œ โˆ’ 1)! (๐‘™ โˆ’ 1)! ๐‘œ โˆ’ ๐‘™ ! ๐‘ž!#$๐‘Ÿ"#! = ๐‘œ๐‘ž M

!6$ "

(๐‘™ โˆ’ 1 + 1) ๐‘œ โˆ’ 1 ๐‘™ โˆ’ 1 ๐‘ž!#$๐‘Ÿ"#! = ๐‘œ๐‘ž M

867 "#$

๐‘š ๐‘œ โˆ’ 1 ๐‘š ๐‘ž8๐‘Ÿ"#$#8 + ๐‘œ๐‘ž M

867 "#$ ๐‘œ โˆ’ 1

๐‘š ๐‘ž8๐‘Ÿ"#$#8

XC 2020

slide-22
SLIDE 22

Bin Binomia ial ๐น ๐‘Œ = ๐‘œ๐‘ž ๐‘ ๐‘œ, ๐‘ž, ๐‘™ = ๐‘œ ๐‘™ ๐‘ž!๐‘Ÿ"#! Variance ce ๐‘Š ๐‘Œ ๐น ๐‘Œ( โˆ’ ๐œˆ( = M

&โˆˆ0

๐‘ฆ(๐‘› ๐‘ฆ โˆ’ ๐œˆ( ยง โˆ‘&โˆˆ0 ๐‘ฆ(๐‘› ๐‘ฆ = ๐‘œ ๐‘œ โˆ’ 1 ๐‘ž( โˆ‘86$

"#$ "#( 8#$ ๐‘ž8#$๐‘Ÿ"#$#8 + ๐‘œ๐‘ž = ๐‘œ ๐‘œ โˆ’ 1 ๐‘ž( + ๐‘œ๐‘ž

ยง ๐œˆ( = ๐‘œ(๐‘ž( ยง โˆ‘&โˆˆ0 ๐‘ฆ(๐‘› ๐‘ฆ โˆ’ ๐œˆ( = ๐‘œ ๐‘œ โˆ’ 1 ๐‘ž( + ๐‘œ๐‘ž โˆ’ ๐‘œ(๐‘ž( = ๐‘œ๐‘ž(1 โˆ’ ๐‘ž)

XC 2020

slide-23
SLIDE 23

๐น ๐‘Œ = ๐œ‡ Po Poisson ๐‘„ ๐‘Œ = ๐‘™ = ๐œ‡! ๐‘™! ๐‘“#% Variance ce ๐‘Š ๐‘Œ ๐น ๐‘Œ( โˆ’ ๐œˆ( = M

&โˆˆ0

๐‘ฆ(๐‘› ๐‘ฆ โˆ’ ๐œˆ( M

&โˆˆ0

๐‘ฆ(๐‘› ๐‘ฆ = M

!67 9:

๐‘™( ๐œ‡! ๐‘™! ๐‘“#% = M

!6$ 9:

๐‘™ ๐œ‡! ๐‘™! ๐‘“#% = M

!6$ 9:

๐œ‡๐‘™ ๐œ‡!#$ (๐‘™ โˆ’ 1)! ๐‘“#% = M

!6$ 9:

๐œ‡(๐‘™ โˆ’ 1 + 1) ๐œ‡!#$ (๐‘™ โˆ’ 1)! ๐‘“#% = ๐œ‡ M

867 9:

๐‘š ๐œ‡8 ๐‘š! ๐‘“#% + ๐œ‡ M

867 9: ๐œ‡8

๐‘š! ๐‘“#%

XC 2020

slide-24
SLIDE 24

๐น ๐‘Œ = ๐œ‡ Po Poisson ๐‘„ ๐‘Œ = ๐‘™ = ๐œ‡! ๐‘™! ๐‘“#% Variance ce ๐‘Š ๐‘Œ ๐น ๐‘Œ( โˆ’ ๐œˆ( = M

&โˆˆ0

๐‘ฆ(๐‘› ๐‘ฆ โˆ’ ๐œˆ( ยง โˆ‘&โˆˆ0 ๐‘ฆ(๐‘› ๐‘ฆ = ๐œ‡ โˆ‘867

9: ๐‘š %& 8! ๐‘“#% + ๐œ‡ โˆ‘867 9: %& 8! ๐‘“#% = ๐œ‡( โˆ‘86$ 9: %&'( (8#$)! ๐‘“#% + ๐œ‡ = ๐œ‡( + ๐œ‡

ยง ๐œˆ( = ๐œ‡( ยง โˆ‘&โˆˆ0 ๐‘ฆ(๐‘› ๐‘ฆ โˆ’ ๐œˆ( = ๐œ‡( + ๐œ‡ โˆ’ ๐œ‡( = ๐œ‡

XC 2020

slide-25
SLIDE 25

Linearity

๐น(๐‘Œ + ๐‘) = ๐น(๐‘Œ) + ๐น(๐‘) ๐น(๐‘‘๐‘Œ) = ๐‘‘๐น(๐‘Œ). ๐น(๐‘๐‘Œ + ๐‘) = ๐‘๐น(๐‘Œ) + ๐‘

XC 2020

slide-26
SLIDE 26

Properties of Variance

ยง If ๐‘Œ is any random variable and ๐‘‘ is any constant, then ๐‘Š ๐‘‘๐‘Œ = ๐‘‘(๐‘Š(๐‘Œ), ๐‘Š ๐‘Œ + ๐‘‘ = ๐‘Š(๐‘Œ). Variance ce ๐‘Š ๐‘Œ = ๐น ๐‘Œ( โˆ’ ๐œˆ( = ๐น ๐‘Œ( โˆ’ [๐น ๐‘Œ ]( ๐‘Š ๐‘‘๐‘Œ = ๐น (๐‘‘๐‘Œ)( โˆ’ [๐น ๐‘‘๐‘Œ ]( ๐น(๐‘๐‘Œ + ๐‘) = ๐‘๐น(๐‘Œ) + ๐‘

XC 2020

slide-27
SLIDE 27

Properties of Variance

ยง If ๐‘Œ is any random variable and ๐‘‘ is any constant, then ๐‘Š ๐‘‘๐‘Œ = ๐‘‘(๐‘Š(๐‘Œ), ๐‘Š ๐‘Œ + ๐‘‘ = ๐‘Š(๐‘Œ). Variance ce ๐‘Š ๐‘Œ = ๐น ๐‘Œ( โˆ’ ๐œˆ( = ๐น ๐‘Œ( โˆ’ [๐น ๐‘Œ ]( ๐‘Š ๐‘‘๐‘Œ = ๐น (๐‘‘๐‘Œ)( โˆ’ ๐น ๐‘‘๐‘Œ

( = ๐น ๐‘‘(๐‘Œ( โˆ’ ๐‘‘๐น ๐‘Œ (

= ๐‘‘(๐น ๐‘Œ( โˆ’ ๐‘‘( ๐น ๐‘Œ

( = ๐‘‘( ๐น ๐‘Œ( โˆ’ ๐น ๐‘Œ (

= ๐‘‘(๐‘Š ๐‘Œ ๐น(๐‘๐‘Œ + ๐‘) = ๐‘๐น(๐‘Œ) + ๐‘

XC 2020

slide-28
SLIDE 28

Properties of Variance

ยง If ๐‘Œ is any random variable and ๐‘‘ is any constant, then ๐‘Š ๐‘‘๐‘Œ = ๐‘‘(๐‘Š(๐‘Œ), ๐‘Š ๐‘Œ + ๐‘‘ = ๐‘Š(๐‘Œ). Variance ce ๐‘Š ๐‘Œ = ๐น ๐‘Œ โˆ’ ๐œˆ ( = ๐น ๐‘Œ โˆ’ ๐น(๐‘Œ) ( ๐‘Š ๐‘Œ + ๐‘‘ = ๐น ๐‘Œ + ๐‘‘ โˆ’ ๐น(๐‘Œ + ๐‘‘) ( ๐น(๐‘๐‘Œ + ๐‘) = ๐‘๐น(๐‘Œ) + ๐‘

XC 2020

slide-29
SLIDE 29

Properties of Variance

ยง If ๐‘Œ is any random variable and ๐‘‘ is any constant, then ๐‘Š ๐‘‘๐‘Œ = ๐‘‘(๐‘Š(๐‘Œ), ๐‘Š ๐‘Œ + ๐‘‘ = ๐‘Š(๐‘Œ). Variance ce ๐‘Š ๐‘Œ = ๐น ๐‘Œ โˆ’ ๐œˆ ( = ๐น ๐‘Œ โˆ’ ๐น(๐‘Œ) ( ๐‘Š ๐‘Œ + ๐‘‘ = ๐น ๐‘Œ + ๐‘‘ โˆ’ ๐น(๐‘Œ + ๐‘‘) ( = ๐น ๐‘Œ + ๐‘‘ โˆ’ ๐น ๐‘Œ โˆ’ ๐‘‘ ( = ๐น ๐‘Œ โˆ’ ๐น ๐‘Œ

(

= ๐‘Š(๐‘Œ). ๐น(๐‘๐‘Œ + ๐‘) = ๐‘๐น(๐‘Œ) + ๐‘

XC 2020

slide-30
SLIDE 30

Non-linearity

๐‘Š ๐‘‘๐‘Œ = ๐‘‘(๐‘Š(๐‘Œ) ๐‘Š ๐‘Œ + ๐‘‘ = ๐‘Š(๐‘Œ) ๐‘Š(๐‘๐‘Œ + ๐‘) = ๐‘(๐‘Š(๐‘Œ)

XC 2020

slide-31
SLIDE 31

When do we need independence?

๐‘Œ + ๐‘ ๐‘Œ๐‘ Ne Need

๐น(๐‘Œ๐‘) = ๐น(๐‘Œ)๐น(๐‘) โ€ฆ

Do Do not need

๐น(๐‘Œ + ๐‘) = ๐น(๐‘Œ) + ๐น(๐‘) โ€ฆ โ€ฆ ๐‘พ(๐’€ + ๐’) = ๐‘พ(๐’€) + ๐‘พ(๐’)

XC 2020

slide-32
SLIDE 32

When do we need independence?

๐‘Œ + ๐‘ ๐‘Œ๐‘ Ne Need

๐น(๐‘Œ๐‘) = ๐น(๐‘Œ)๐น(๐‘) ๐‘Š(๐‘Œ + ๐‘) = ๐‘Š(๐‘Œ) + ๐‘Š(๐‘) โ€ฆ

Do Do not need

๐น(๐‘Œ + ๐‘) = ๐น(๐‘Œ) + ๐น(๐‘) โ€ฆ โ€ฆ

XC 2020

slide-33
SLIDE 33

Let ๐‘Œ and ๐‘ be random variables with finite expected values. And ๐‘Œ and ๐‘ are independent random variables.

๐‘Š ๐‘Œ + ๐‘ = ๐น ๐‘Œ + ๐‘ ( โˆ’ ๐‘ + ๐‘ ( = ๐น ๐‘Œ( + 2๐‘Œ๐‘ + ๐‘( โˆ’ ๐‘ + ๐‘ ( = ๐น ๐‘Œ( + 2๐น ๐‘Œ๐‘ + ๐น ๐‘( โˆ’ ๐‘( โˆ’ 2๐‘๐‘ โˆ’ ๐‘(

Proof

๐‘Š ๐‘Œ = ๐น ๐‘Œ( โˆ’ ๐œˆ(

๐น ๐‘ = ๐‘

๐น(๐‘Œ๐‘) = ๐น(๐‘Œ)๐น(๐‘)

๐‘Š ๐‘Œ + ๐‘ = ๐น ๐‘Œ* + 2๐น ๐‘Œ ๐น ๐‘ + ๐น ๐‘* โˆ’ ๐‘* โˆ’ 2๐‘๐‘ โˆ’ ๐‘* = ๐น ๐‘Œ* + 2๐‘๐‘ + ๐น ๐‘* โˆ’ ๐‘* โˆ’ 2๐‘๐‘ โˆ’ ๐‘* = ๐น ๐‘Œ* โˆ’ ๐‘* + ๐น ๐‘* โˆ’ ๐‘* = ๐‘Š ๐‘Œ + ๐‘Š(๐‘) ๐น ๐‘Œ = ๐‘ ๐น ๐‘Œ + ๐‘ = ๐‘ + ๐‘

XC 2020

slide-34
SLIDE 34

Properties of Variance

ยง If ๐‘Œ is any random variable and ๐‘‘ is any constant, then ๐‘Š ๐‘‘๐‘Œ = ๐‘‘(๐‘Š(๐‘Œ), ๐‘Š ๐‘Œ + ๐‘‘ = ๐‘Š(๐‘Œ). ยง Let ๐‘Œ and ๐‘ be two in independent random

  • variables. Then

๐‘Š(๐‘Œ + ๐‘) = ๐‘Š(๐‘Œ) + ๐‘Š(๐‘). ยง It can be shown that the variance

  • f

the sum

  • f

any number

  • f

mutually independent random variables is the sum

  • f

the individual variances.

XC 2020

slide-35
SLIDE 35

Properties of Variance

ยง Let ๐‘Œ$, ๐‘Œ(, โ‹ฏ , ๐‘Œ" be an independent trials process with ๐น ๐‘Œ

< = ๐œˆ and

๐‘Š ๐‘Œ

< = ๐œ(.

Let ๐‘‡" = ๐‘Œ$ + ๐‘Œ( + โ‹ฏ + ๐‘Œ" be the sum, and ๐ต" = =)

" be

the

  • average. Then

๐‘Š ๐‘‘๐‘Œ = ๐‘‘*๐‘Š(๐‘Œ) independent ๐‘Š(๐‘Œ + ๐‘) = ๐‘Š(๐‘Œ) + ๐‘Š(๐‘).

?

๐น ๐‘‡" = โ‹ฏ

?

๐‘Š ๐‘‡" = โ‹ฏ

XC 2020

slide-36
SLIDE 36

Properties of Variance

ยง Let ๐‘Œ$, ๐‘Œ(, โ‹ฏ , ๐‘Œ" be an independent trials process with ๐น ๐‘Œ

< = ๐œˆ and

๐‘Š ๐‘Œ

< = ๐œ(.

Let ๐‘‡" = ๐‘Œ$ + ๐‘Œ( + โ‹ฏ + ๐‘Œ" be the sum, and ๐ต" = =)

" be

the

  • average. Then

๐‘Š ๐‘‘๐‘Œ = ๐‘‘$๐‘Š(๐‘Œ) independent ๐‘Š(๐‘Œ + ๐‘) = ๐‘Š(๐‘Œ) + ๐‘Š(๐‘).

= ๐น ๐‘‡" = ๐‘œ๐œˆ = ๐‘Š ๐‘‡" = ๐‘œ๐œ(

?

๐น ๐ต" = โ‹ฏ

?

๐‘Š ๐ต" = โ‹ฏ, ๐ธ ๐ต" = โ‹ฏ

XC 2020

slide-37
SLIDE 37

Properties of Variance

ยง Let ๐‘Œ$, ๐‘Œ(, โ‹ฏ , ๐‘Œ" be an independent trials process with ๐น ๐‘Œ

< = ๐œˆ and

๐‘Š ๐‘Œ

< = ๐œ(.

Let ๐‘‡" = ๐‘Œ$ + ๐‘Œ( + โ‹ฏ + ๐‘Œ" be the sum, and ๐ต" = =)

" be

the

  • average. Then

= ๐น ๐‘‡" = ๐‘œ๐œˆ = ๐‘Š ๐‘‡" = ๐‘œ๐œ(

=

๐น ๐ต" = ๐œˆ

=

๐‘Š ๐ต" = >%

" ,

๐ธ ๐ต" = >

"

XC 2020

slide-38
SLIDE 38

Ber Bernoulli t tria ial ๐‘› ๐‘ฆ = O ๐‘ž, ๐‘Œ = 1 1 โˆ’ ๐‘ž, ๐‘Œ = 0 ๐‘ญ ๐’€ = ๐‘ž ๐‘Š ๐‘Œ = ๐‘ž โˆ’ ๐‘ž(

Example

Bin Binomia ial n independent Bernoulli trials = ๐น ๐‘‡" = ๐‘œ๐œˆ = ๐‘Š ๐‘‡" = ๐‘œ๐œ(

XC 2020

slide-39
SLIDE 39

Law of Large Numbers

ยง Let ๐‘Œ$, ๐‘Œ(, โ‹ฏ , ๐‘Œ" be an independent trials process with ๐น ๐‘Œ

< = ๐œˆ and

๐‘Š ๐‘Œ

< = ๐œ(.

ยง Let ๐‘‡" = ๐‘Œ$ + ๐‘Œ( + โ‹ฏ + ๐‘Œ" be the sum, and ๐ต" = =)

" be

the

  • average. Then

=

๐น ๐ต" = ๐œˆ

=

๐‘Š ๐ต" = >%

" ,

๐ธ ๐ต" = >

"

๐‘œ โ†’ +โˆž ๐‘Š ๐ต" โ†’ โ‹ฏ ๐ธ ๐ต" โ†’ โ‹ฏ

XC 2020