SLIDE 19 2.
j,k ||ajk − δjk||0,1,1 + ||bk||1,0,1 < ǫ
3.
j,k ||ajk||0,1,N+1 + ||bk||1,0,N+1 ≤ M.
This result follows by tracking the uniform dependence on the coefficients of P in the proofs
- f [22]. We simply point out that the smallness of ||ajk − δjk||0,1,1 and ||bk||1,0,1 guarantees the
positive commutator estimate χ(P)i[P, A]χ(P) ≥ inf supp(χ) 2 χ2(P), for any χ ∈ C∞
0 (R+), which follows from (2.21). The other ingredient is the uniform P boundedness
estimate (2.23). In the sequel, we shall use the notation aτ(x) := a(eτx), τ ∈ R, x ∈ Rd, (5.1) namely aτ = eiτAae−iτA. Here is the main property of the spaces So,r−o,N. Proposition 5.2 (Scaling homogeneity). Let o ∈ {0, 1} and o ≤ r ≤ ¯ r(d). For all a ∈ So,r−o,N and τ ∈ R, eoτ||aτ||o,r−o,N = ||a||o,r−o,N.
- Proof. Observe first that
((x · ∇)na)τ = (x · ∇)n(aτ), (5.2) either by a trivial direct computation, or by remarking that dilations commute with their generator. Then (x · ∇)n(∂βaτ) = eτ|β| (x · ∇)n∂βa
and we see that eτo||(x · ∇)n∂β(aτ)||
L
d |β|+o = ||(x · ∇)n∂βa||
L
d |β|+o ,
by an elementary change of variable in the integral when |β| + o = 0, and trivially if |β| + o = 0. We are now ready to prove the following theorem which is our main technical result. Theorem 5.3. Let N := ¯ r(d) + 1. Fix a constant M > 0. Then, there exist ǫ > 0 and κ > 0 such that, for all ajk ∈ S0,¯
r(d),N+1, bk ∈ S1,¯ r(d)−1,N+1 such that
2.
j,k ||ajk − δjk||0,1,1 + ||bk||1,0,1 < ǫ,
3.
j,k ||ajk − δjk||0,¯ r(d),0 + ||bk||1,¯ r(d)−1,0 < ǫ,
4.
j,k ||ajk||0,¯ r(d),N+1 + ||bk||1,¯ r(d)−1,N+1 < M,
we have the following estimates, 19