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List coloring and crossings Zden ek Dvo rk, Bernard Lidick and - PowerPoint PPT Presentation

List coloring and crossings Zden ek Dvo rk, Bernard Lidick and Riste krekovski Charles University University of Ljubljana CanaDAM 2011 - Victoria List coloring and crossings List coloring - quick reminder Let G be a graph and C set


  1. List coloring and crossings Zdenˇ ek Dvoˇ rák, Bernard Lidický and Riste Škrekovski Charles University University of Ljubljana CanaDAM 2011 - Victoria

  2. List coloring and crossings List coloring - quick reminder Let G be a graph and C set of colors. • coloring is a mapping c : V ( G ) → C . • coloring is proper if adjacent vertices have distinct colors • chromatic number χ ( G ) is minimum k such that G can be properly colored using k colors. • list assignment is a mapping L : V ( G ) → 2 C • list coloring ( L -coloring) is a coloring c such that c ( v ) ∈ L ( v ) for all v ∈ V ( G ) • choosability ch ( G ) is minimum k such that if | L ( v ) | ≥ k for all v ∈ V ( G ) then G can be properly L -colored

  3. List coloring and crossings Chromatic number vs. Choosability • χ ( G ) ≤ ch ( G ) • χ ( G ) ≤ ∆( G ) + 1 and also ch ( G ) ≤ ∆( G ) + 1 • Exists graph G: χ ( G ) < ch ( G )

  4. List coloring and crossings Chromatic number vs. Choosability • χ ( G ) ≤ ch ( G ) • χ ( G ) ≤ ∆( G ) + 1 and also ch ( G ) ≤ ∆( G ) + 1 • Exists graph G: χ ( G ) < ch ( G )

  5. List coloring and crossings Chromatic number vs. Choosability • χ ( G ) ≤ ch ( G ) • χ ( G ) ≤ ∆( G ) + 1 and also ch ( G ) ≤ ∆( G ) + 1 • Exists graph G: χ ( G ) < ch ( G )

  6. List coloring and crossings List coloring - motivation to our problem Theorem (Thomassen, 1994) Every planar graph is 5-choosable. Theorem (Voigt, 1994) There exists a planar graph which is not 4-choosable Is it possible to strengthen the theorem of Thomassen to allow some crossings?

  7. List coloring and crossings List coloring - Thomassen’s details Corollary (Thomassen, 1994) Every planar graph is 5-choosable. Theorem (Thomassen, 1994) Let G be a plane graph, F vertices of the outer face and u 1 , u 2 ∈ V ( F ) adjacent. Let L be a list assignment such that for every v ∈ V ( G ) :  1 v ∈ { u 1 , u 2 }   3 | L ( v ) | ≥ v ∈ V ( F ) \ { u 1 , u 2 }  5 otherwise  If | L ( u 1 ) ∪ L ( u 2 ) | ≥ 2 then G is L-colorable. u 1 , u 2 are precolored

  8. List coloring and crossings List coloring - Thomassen’s details Corollary 5 5 5 5 5 5 5 5 5 5 5 5 Theorem 3 3 1 1 3 5 5 5 5 3 3 3

  9. List coloring and crossings Crossings and 5-coloring graphs Crossing number of G , cr ( G ) is the minimum number of crossings edges in a drawing of G . Theorem (Oporowski and Zhao, 2005) Every graph with crossing number at most two is 5-colorable.

  10. List coloring and crossings Crossings and 5-coloring graphs Crossing number of G , cr ( G ) is the minimum number of crossings edges in a drawing of G . Theorem (Oporowski and Zhao, 2005) Every graph with crossing number at most two is 5-colorable. Observation (Erman et al., 2010) Every graph with crossing number at most one is 5-choosable.

  11. List coloring and crossings Our result Theorem (Oporowski and Zhao, 2005) Every graph with crossing number at most two is 5-colorable. Observation (Erman et al., 2010) Every graph with crossing number at most one is 5-choosable. Theorem Every graph with crossing number at most two is 5-choosable. Independently obtained by Campos and Havet.

  12. List coloring and crossings What we really proved Theorem (original) Let G be a graph and L a list assignment such that • cr ( G ) ≤ 2 and | L ( v ) | ≥ 5 for every v ∈ V ( G ) . Then G is L-choosable. Theorem (stronger) Let G be a graph and L a list assignment such that either • cr ( G ) ≤ 2 and | L ( v ) | ≥ 5 for every v ∈ V ( G ) , or • cr ( G ) ≤ 1 , G contains a triangle T, L ( v ) = 1 for all v ∈ V ( T ) , L ( u ) � = L ( v ) if u and v are two distinct vertices of T and | L ( v ) | ≥ 5 for all v ∈ V ( G ) \ V ( T ) . Then G is L-choosable.

  13. List coloring and crossings What we really proved Original 5 5 5 5 5 5 5 5 5 5 5 5 Stronger 5 5 5 5 5 5 5 5 1 5 5 1 5 5 5 5 1 5 5 or 5 5 5 5

  14. List coloring and crossings Proof idea • deal with small cases (one edge crossed twice,...) 5 5 1 5 5 5 1 5 5 1 5 • restrict to the case with precolored triangle • use Thomassen’s result

  15. List coloring and crossings Proof idea • deal with small cases (one edge crossed twice,...) • restrict to the case with precolored triangle a, b, c, d, e a, b, c, d, e 5 5 5 5 a, b, c, d, e a, b, c, d, e • use Thomassen’s result

  16. List coloring and crossings Proof idea • deal with small cases (one edge crossed twice,...) • restrict to the case with precolored triangle a, b, c, d, e a, b, c, d, e 5 5 1 x 5 5 a, b, c, d, e a, b, c, d, e • use Thomassen’s result

  17. List coloring and crossings Proof idea • deal with small cases (one edge crossed twice,...) • restrict to the case with precolored triangle x , b, c, d, e b 1 5 1 x 1 5 a a, x , c, d, e • use Thomassen’s result

  18. List coloring and crossings Proof idea • deal with small cases (one edge crossed twice,...) • restrict to the case with precolored triangle • use Thomassen’s result 1 5 5 1 1 5 5

  19. List coloring and crossings Proof idea • deal with small cases (one edge crossed twice,...) • restrict to the case with precolored triangle • use Thomassen’s result 1 5 5 1 5 5 5 1 5 5

  20. List coloring and crossings Proof idea • deal with small cases (one edge crossed twice,...) • restrict to the case with precolored triangle • use Thomassen’s result 5 5 5 1 5 5 1 5 5 5 1 5 5 5 5

  21. List coloring and crossings Proof idea • deal with small cases (one edge crossed twice,...) • restrict to the case with precolored triangle • use Thomassen’s result 3 3 3 1 1 5 1 5 3 1 1 5 1 5 1 1 5 1 1 5 1 3 5 3 3

  22. List coloring and crossings Proof idea • deal with small cases (one edge crossed twice,...) • restrict to the case with precolored triangle • use Thomassen’s result 3 3 3 1 3 1 3 3 3

  23. List coloring and crossings What about more crossings? Not for three crossings 6 = χ ( K 6 ) ≤ ch ( K 6 )

  24. List coloring and crossings What about more crossings and 5-coloring? Theorem (Král’ and Stacho, 2008) If a graph G has a drawing in the plane in which no two crossings are dependent, then χ ( G ) ≤ 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 5 Crossings are not too close to each other.

  25. List coloring and crossings More crossings and list coloring Theorem (Dvoˇ rák, L. and Mohar) If a graph G has a drawing in the plane in which distance between every two crossings is at least 19, then ch ( G ) ≤ 5 . 5 5 5 5 ≥ 19 ≥ 19 ≥ 19 5 5 5 5 5 5 5 5

  26. List coloring and crossings More crossings and list coloring Theorem (Dvoˇ rák, L. and Mohar) Let G be a graph, N ⊂ V ( G ) and L a list assignment such that L ( v ) ≥ 4 for v ∈ N and L ( v ) ≥ 5 otherwise. If G has a drawing in the plane in which distance between every two crossings, crossing and a vertex of N and two vertices of N is at least 19, then G is L-colorable. ≥ 19 ≥ 19 4 4 ≥ 19 ≥ 19 ≥ 19 ≥ 19 5 5 5 5 5 5 5 5

  27. List coloring and crossings More crossings and list coloring Theorem (Dvoˇ rák, L. and Mohar) Let G be a graph, N ⊂ V ( G ) and L a list assignment such that L ( v ) ≥ 4 for v ∈ N and L ( v ) ≥ 5 otherwise. Let G has a drawing in the plane in which distance between every crossings and vertices of N is large. Let L be more restricted for the outer face. If G is not one of 16 exceptions then G is L-colorable. 4 3 ≥ 15 4 1 ≥ 11 1 4 4 ≥ 5 5 1 1 1 ≥ ≥ 1 5 ≥ 19 3 5 5 5 5 4 5 5 5 5

  28. List coloring and crossings More crossings and list coloring Theorem (Dvoˇ rák, L. and Mohar) Let G be a graph, N ⊂ V ( G ) and L a list assignment such that L ( v ) ≥ 4 for v ∈ N and L ( v ) ≥ 5 otherwise. Let G has a drawing in the plane in which distance between every crossings and vertices of N is large. Let L be more restricted for the outer face. If G is not one of 16 exceptions then G is L-colorable. b 1 4 3 5 4 1 ≥ 1 ≥ 11 a, b, c, x 1 4 4 c 1 a ≥ 15 ≥ 15 ≥ 15 1 4 1 ≥ 19 3 5 5 5 5 3 4 5 5 5 5 c, x, a

  29. List coloring and crossings Thank you for your attention Special thanks to Robert Šámal for all the chocolate yesterday.

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