Lecture 3.5: Damped and forced harmonic motion Matthew Macauley - - PowerPoint PPT Presentation

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Lecture 3.5: Damped and forced harmonic motion Matthew Macauley - - PowerPoint PPT Presentation

Lecture 3.5: Damped and forced harmonic motion Matthew Macauley Department of Mathematical Sciences Clemson University http://www.math.clemson.edu/~macaule/ Math 2080, Differential Equations M. Macauley (Clemson) Lecture 3.5: Damped &


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Lecture 3.5: Damped and forced harmonic motion

Matthew Macauley Department of Mathematical Sciences Clemson University http://www.math.clemson.edu/~macaule/ Math 2080, Differential Equations

  • M. Macauley (Clemson)

Lecture 3.5: Damped & forced harmonic motion Differential Equations 1 / 7

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Introduction

Harmonic motion

Recall that if x(t) is the displacement of a mass m on a spring, then x(t) satsifies mx′′ + 2cx′ + ω2

0x = f (t) ,

where c is the damping constant ω0 is frequency f (t) is the external driving force In this lecture, we will analyze the cases when c = 0 and when f (t) is sinusoidal.

  • M. Macauley (Clemson)

Lecture 3.5: Damped & forced harmonic motion Differential Equations 2 / 7

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Damped harmonic motion

The homogeneous case

Divide through by the mass m and we get a 2nd order constant coefficient ODE: x′′ + 2cx′ + ω2

0x = 0

  • M. Macauley (Clemson)

Lecture 3.5: Damped & forced harmonic motion Differential Equations 3 / 7

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Forced harmonic motion: f (t) = 0

An example

When the driving frequency is sinusoidal, the ODE for x(t) is x′′ + 2cx′ + ω2

0x = A cos ωt ,

where c is the damping coefficient; ω0 is the natural frequency; ω is the driving frequency. In this lecture, we will analyze the case when c = 0. Case 1: ω = ω0.

  • M. Macauley (Clemson)

Lecture 3.5: Damped & forced harmonic motion Differential Equations 4 / 7

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Forced harmonic motion: f (t) = 0

Summary so far

The general solution to x′′ + ω2

0x = A cos ωt, ω = ω0 is

x(t) = xh(t) + xp(t) = C1 cos ω0t + C2 sin ω0t + A ω2

0 − ω2 cos ωt .

  • M. Macauley (Clemson)

Lecture 3.5: Damped & forced harmonic motion Differential Equations 5 / 7

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Case 2: ω = ω0

We need to solve x′′ + ω2

0x = A cos ω0t.

  • M. Macauley (Clemson)

Lecture 3.5: Damped & forced harmonic motion Differential Equations 6 / 7

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Case 2: ω = ω0

Summary so far

The general solution to x′′ + ω2

0x = A cos ω0t is

x(t) = xh(t) + xp(t) = C1 cos ω0t + C2 sin ω0t + At 2ω0 sin ω0t .

  • M. Macauley (Clemson)

Lecture 3.5: Damped & forced harmonic motion Differential Equations 7 / 7